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701.

Significance of Krebs cycle is theA. Synthesis of ATPB. Synthesis of amino acidC. Synthesis of chloropyllD. All of the above

Answer» Correct Answer - D
702.

A) What is pheophytin? B) What is the significance of `C_(4)` cycle?

Answer» A. Pheophytin is a modified chlrophyll a molecule in which two H atoms have replaced the central `Mg^(2+)`. It accepts the electrons from `P_(680)` and passes them to a special molecule of quinone.
B) `C_(4)` cycle is of great adaptive advantage to the tropical plants which can continue even under much low `CO_(2)` concentration when `C_(3)` plants stop photosynthesis. The `C_(4)` cycle is more efficient than the `C_(3)` cycle due to absence of photorespiration in `C_(4)` plants.
703.

Fumarase enzyme convertsA. Succinic acid to malic acidB. Succinic acid to fumatic acidC. Fumaric acid to malic acidD. Fumaric acid to citric acid

Answer» Correct Answer - C
704.

Pyruvate kinase enzyme catalysesA. first irreversible step of glycolysisB. second irreversible step of glycolysisC. third irreversible step of glycolysisD. fourth irreversible step of glycolysis

Answer» Correct Answer - C
705.

Consider the following enzymes of glycolytic pathway 1. Glyceraldehyde-3 phosphate dehydrogenase 2. Enolase 3. Pyruvate kinase 4. Phosphoglycerate kinase The correct order in which they appear in the pathway isA. 2,1,4,3B. 3, 2, 1, 4C. 4, 3, 2, 1D. 1,4,2, 3

Answer» Correct Answer - D
706.

Oxidation phosphorylation occurs inA. Outer membrane of mitochondriaB. Inner membrane of mitochondriaC. Stroma of chloroplastD. Grana of chloroplast

Answer» Correct Answer - B
707.

Phosphorylation of glucose during glycolysis is catalysed byA. PhospholglucomutaseB. PhosphoglucoisomeraseC. HexokinaseD. Phosphorylase

Answer» Correct Answer - C
708.

Which of the following is the product of phosphorylationA. PGAB. Fructose 1, 6 diphosphateC. DPGAD. Pyruvic acid

Answer» Correct Answer - B
709.

In glycolytic pathway which of the following steps shows reduction of co-enzymeA. 1,3-diphosphoglycerate to 3-phosphoglycerateB. Glucose 6-phophate to fructose 6-phosphateC. Glyceraldehyde 3-phosphate to 1,3-diphosphoglycerateD. 3-Phosphoglycerate to 2-phosphoglycerate

Answer» Correct Answer - C
710.

Besides the net gai of 2ATP melecules in glycolysis which other molecules are simultaneoulsy formedA. FAD`H_(2)`B. NADP`H_(2)`C. NAD`H_(2)`D. FAM`H_(2)`

Answer» Correct Answer - C
711.

Select a suitable name for the following process `C_(6)H_(12)O_(6)+2ADP + 2Pi to 2C_(2)H_(5)OH + 2ATP + 2CO_(2) uarr`A. Alcoholic fermentationB. PhotorespirationC. Lactase fermentaionD. Aerobic respiration

Answer» Correct Answer - A
712.

Can photosynthesis occur under the light of ordinary fluorescent lamps?

Answer» The fluorescent lamps are commonly called tube rods. They produce light by fluorescence which is usually rich in blue nad red wavelenghts. Therefore, photosynthesis can occur under the light of ordinary fluorescent lamps provided it is about 400 to 500 Lux (10.76 Lux =1 foot-candle).
713.

Consider the following statements (A) The portion of the spectrum between 500nm and 800 nm is also referred to as photosynthetically active radiation (PAR) (B) Magnesium, calcium and chloride ions play prominet roles in the photolysis of water (C) In cyclic photopphosphorylation, oxygen is not released (as there is no photolysis of water) and NADPH is also not producedA. a) is true, but b) and c) are falseB. a) and b) are false, but c) is trueC. b) is true, but a) and c) are falseD. a) and b) are true, but c) is false.

Answer» Correct Answer - B
714.

How much photosynthetically active radiation is received by plants from the sun?

Answer» The total radiation from the sun coming at the upper boundary of the atmosphere is `1,360 Wm^(-2)` or watts per square meter (the solar constant). 1W is equal to 1 joule per second (joule is the SI unit of energy). This irradiance includes ultraviolet and infrared wavelenths Of this, only about 900 W `m^(-2)` reach plants because the rest is absorbed or scattered by water vapour, dust, `CO_(2)` and ozone present in the atmosphere. Of this, about half is in the infrared, roughly 5 percent is in the ultraviolet, and the rest has wavelengths between 400 to 700 nm. Therefore, the plants receive about 400 to 500 `W m^(-2)`. photosynthetically active radiation from the sun.
715.

Which pigments are collectively termed as accessory pigments? Why?

Answer» Chlorophyll b,c,d and e, carotenoids and phycobilins are called accessory pigments because they do not directly take part in photochemical act.
716.

General equation for aerobic respiration isA. `6CO_2+6H_2O to C_6H_12O_6+6O_2`B. `C_6H_12O_6+6O_2to 6CO_2+6H_2O+686` KcalC. `C_6H_12O_6 to 2C_2H_5OH+2CO_2+2ATP`D. `C_22H_22O_116O_2 to 6CO_2+6H_2O+"686cal"`

Answer» Correct Answer - B
717.

General formula for aerobic respiration isA. `6CO_(2)+6H_(2)OrarrC_(6)H_(12)O_(6)+6O_(2)`B. `C_(6)H_(12)O_(6)+6O_(2)rarr6CO_(2)+6H_(2)O+686`kcalC. `C_(6)H_(12)O_(6)+2C_(2)H_(5)OH+2CO_(2)+2ATP`D. `C_(6)H_(12)O_(6)rarr2C_(3)H_(6)O_(3)+ATP`

Answer» Correct Answer - B
(B) General fonnula for aerobic respiration is
`C_(6)H_(12)O_(6)+6O_(2)+6CO_(2)+6H_(2)O+686 ` kcal.
718.

Respiration differs from combustion inA. Liberating more energy as compared to combustionB. Liberating all the energy at once in contract to combustionC. Liberation oenergy gradually in steps in contrast to combustionD. Carbohydrates take part as the combustion of substance

Answer» Correct Answer - C
(C) Respiration differs from -eombustion in liberation of energy gradually in steps in contrast to combustion.
719.

Respiration differs from the process of combustion in the fact thatA. All the energy stored in glucose is released at once due to combustion and enzymes are involvedB. All energy stored in glucose is gradually released due to combusionC. Comparatively large quantity of energy is produced due to combustionD. The carbohydrate act as the combustion substances.

Answer» Correct Answer - A