52639 + Interview Questions in Secondary School in Chemistry Page 18 InterviewSolution

851.	কোন তড়িৎ চুম্বকীয় তরঙ্গের সাহায্যে পাণীয় জলের বিশুদ্ধিকরণ করা হয়कौन तो चुंबकीय कानून तोड़ेंगे सहा जवानी है जलेबी शुद्धिकरण पड़ा है
Answer» nngshsqxgkoutsSdgnkp

Discussion

852.	Danedar haste per tanuki salfyuric amla dalne per konsi has utopian hota he
Answer» ANSWER: xjjeofjrickrfijrjdfiejxkpslxrmdiu4hfnrudh3uxj4idnenfjfs

852.

Danedar haste per tanuki salfyuric amla dalne per konsi has utopian hota he

Answer»

ANSWER:

xjjeofjrickrfijrjdfiejxkpslxrmdiu4hfnrudh3uxj4idnenfjfs

Discussion

853.	Find out the concentration of the salt solution. The mass of salt is 2g. The volume of saltsolution is 100ml.
Answer» EXPLANATION: i don't KNOW SORRY but I THINK about your QUESTION

853.

Find out the concentration of the salt solution. The mass of salt is 2g. The volume of saltsolution is 100ml.

Answer»

EXPLANATION:

i don't KNOW SORRY

but I THINK about your QUESTION

Discussion

854.	Write down the formula of any five compounds by criss- cross method.
Answer» Answer: refer the attachment We can apply the criss-cross method for this compound as, Therefore, the CHEMICAL formula of magnesium CHLORIDE is Cu(NO3)2.

854.

Write down the formula of any five compounds by criss- cross method.

Answer»

Answer:

refer the attachment

We can apply the criss-cross method for this compound as, Therefore, the CHEMICAL formula of magnesium CHLORIDE is Cu(NO3)2.

Discussion

855.	Match the following:column A. column B1.mixture. 1.calcium oxide 2.sodium. 2.air3.calcium and oxygen 3.a magnetic sub 4.mixture of gases. 4.an impure sub5.iron. 5.NaPLEASE GIVE ME THE CORRECT ANSWER
Answer» Answer: 1ST with 4TH; 2ND with 5TH; 3RD with 1st; 4th with 2nd; 5th with 3rd

855.

Match the following:column A. column B1.mixture. 1.calcium oxide 2.sodium. 2.air3.calcium and oxygen 3.a magnetic sub 4.mixture of gases. 4.an impure sub5.iron. 5.NaPLEASE GIVE ME THE CORRECT ANSWER

Answer»

Answer:

1ST with 4TH; 2ND with 5TH; 3RD with 1st; 4th with 2nd; 5th with 3rd

Discussion

856.	Q.5 Total number of o and a bond present in the followingmolecule are(a) 22 and 4(6) 23 and 4(C) 21 and 4(d) 24 and 4
Answer» Answer: 23 and 4 or 21 and 4. . . . . . . .B. . .

856.

Q.5 Total number of o and a bond present in the followingmolecule are(a) 22 and 4(6) 23 and 4(C) 21 and 4(d) 24 and 4

Answer»

Answer:

23 and 4 or 21 and 4. . . . . . . .B. . .

Discussion

857.	In the electrolysis of water the gas obtained at anode is x ml, write the volume ofgas at cathode
Answer» Explanation: Hydrogen and OXYGEN in water is in the ratio 2:1 Since ANODE is positive terminal of cell, negative ion FORMED by electrolysis of water ie. O2- ion go to anode and H+ ion go to cathode VOLUME of oxygen at anode = x ML :. Volume of hydrogen gas at cathode = 2x ml

857.

In the electrolysis of water the gas obtained at anode is x ml, write the volume ofgas at cathode

Answer»

Explanation:

Hydrogen and OXYGEN in water is in the ratio 2:1

Since ANODE is positive terminal of cell, negative ion FORMED by electrolysis of water ie. O2- ion go to anode and H+ ion go to cathode

VOLUME of oxygen at anode = x ML

:. Volume of hydrogen gas at cathode = 2x ml

Discussion

858.	What are electrophiles? write all types of electrophilo with suitable exampleles
Answer» ANSWER: Here's your answer Explanation: Electrophiles are electron deficient species and can accept an electron pair from electron rich species.Examples include CARBOCATIONS and carbonyl COMPOUNDS. A nucleophile is electron rich species and donates electron pairs to electron deficient species. Examples include carbanions, water , ammonia, CYANIDE ion etc. Hope it helps Pls mark me the BRAINLIEST

858.

What are electrophiles? write all types of electrophilo with suitable exampleles

Answer»

ANSWER:

Here's your answer

Explanation:

Electrophiles are electron deficient species and can accept an electron pair from electron rich species.Examples include CARBOCATIONS and carbonyl COMPOUNDS. A nucleophile is electron rich species and donates electron pairs to electron deficient species. Examples include carbanions, water , ammonia, CYANIDE ion etc.

Hope it helps

Pls mark me the BRAINLIEST

Discussion

859.	Draw the diagrammatic representation for the electronic configuration of Al
Answer» EXPLANATION: The ELECTRONIC CONFIGURATION of Al is 1S2, 2s2, 2p6, 3s2 , 3P1

859.

Draw the diagrammatic representation for the electronic configuration of Al

Answer»

EXPLANATION:

The ELECTRONIC CONFIGURATION of Al is 1S2, 2s2, 2p6, 3s2 , 3P1

Discussion

860.	Acetylene on reaction with Hydrogen gas in presence of Nickel gives...
Answer» Answer: Ethane EXPLANATION: ACETYLENE on REDUCTION with hydrogen in the PRESENCE of nickel catalyst GIVES ethane.

860.

Acetylene on reaction with Hydrogen gas in presence of Nickel gives...

Answer»

Answer:

Ethane

EXPLANATION:

ACETYLENE on REDUCTION with hydrogen in the PRESENCE of nickel catalyst GIVES ethane.

Discussion

861.	Derive the question DH=Dut+∆nRt
Answer» Explanation: Federalism, MODE of POLITICAL ORGANIZATION that unites separate states or other POLITIES within an overarching political system in a way that allows each to maintain its own INTEGRITY.

861.

Derive the question DH=Dut+∆nRt

Answer»

Explanation:

Federalism, MODE of POLITICAL ORGANIZATION that unites separate states or other POLITIES within an overarching political system in a way that allows each to maintain its own INTEGRITY.

Discussion

862.	10. Plastics are electric insulators. Which kind of plasticis used to cover metallic wires?
Answer» ANSWER: PLASTIC is a bad thing. It is HARMFUL for our environment. Explanation: So the RECYCLING method should be followd.

862.

10. Plastics are electric insulators. Which kind of plasticis used to cover metallic wires?

Answer»

ANSWER:

PLASTIC is a bad thing. It is HARMFUL for our environment.

Explanation:

So the RECYCLING method should be followd.

Discussion

863.	For the reaction N2(g) + 3H2(g) = 2NH3(8), equilibrium pressures are Ps = 2.6 at Ph= 5.6 atm, and PxH: =1.2 atm. Calculate the Gibb's free energy of the reaction at a temperature of 298K. (A) 1.43 kJ (B) 1.43x10* J (C) 1.41x10 J (D) 4.25 x10' J
Answer» ANSWER: U can CHOOSE nceart for SOLVING

863.

For the reaction N2(g) + 3H2(g) = 2NH3(8), equilibrium pressures are Ps = 2.6 at Ph= 5.6 atm, and PxH: =1.2 atm. Calculate the Gibb's free energy of the reaction at a temperature of 298K. (A) 1.43 kJ (B) 1.43x10* J (C) 1.41x10 J (D) 4.25 x10' J

Answer»

ANSWER:

U can CHOOSE nceart for SOLVING

Discussion

864.	9. How would you test and find out if a fabric is purecotton or a synthetic fibre?
Answer» Answer: 1.If a FABRIC is 100% COTTON. Cotton fabric will BURN like most natural MATERIALS SINCE it comes from a plant. 2.If a fabric is silk. 3.If a fabric is wool. 4.If a fabric is linen. 5.If a fabric is synthetic.

864.

9. How would you test and find out if a fabric is purecotton or a synthetic fibre?

Answer»

Answer:

1.If a FABRIC is 100% COTTON. Cotton fabric will BURN like most natural MATERIALS SINCE it comes from a plant.

2.If a fabric is silk.

3.If a fabric is wool.

4.If a fabric is linen.

5.If a fabric is synthetic.

Discussion

865.	Burning of candle is a ……….. change(Reversible, irreversible, undesirable)
Answer» ANSWER: BURNING of CANDLE is a REVERSIBLE change mark BRILLIANT

865.

Burning of candle is a ……….. change(Reversible, irreversible, undesirable)

Answer»

ANSWER:

BURNING of CANDLE is a REVERSIBLE change

mark BRILLIANT

Discussion

866.	Please answer this I am giving an exam I need it quick please don't do timepass for points
Answer» Answer: hope this will help you a LOT of people who is a lot more than ONE of the PROCESS

866.

Please answer this I am giving an exam I need it quick please don't do timepass for points

Answer»

Answer:

hope this will help you a LOT of people who is a lot more than ONE of the PROCESS

Discussion

867.	Movement of a clock pendulum is a ………… change. (Slow, periodic, non-periodic)
Answer» ANSWER: PERIODIC change hope this HELPS you...

867.

Movement of a clock pendulum is a ………… change. (Slow, periodic, non-periodic)

Answer»

ANSWER:

PERIODIC change

hope this HELPS you...

Discussion

868.	HI acid when heated with cons H²SO⁴ froms
Answer» Answer: HI reduces sulphuric ACID sulphur DIOXIDE and itself is oxidised to iodine. Hence, HI is prepared by heating KI with conc. Phosphoric acid.

868.

HI acid when heated with cons H²SO⁴ froms

Answer»

Answer:

HI reduces sulphuric ACID sulphur DIOXIDE and itself is oxidised to iodine. Hence, HI is prepared by heating KI with conc. Phosphoric acid.

Discussion

869.	फाइंड द इक्वल एंड मास ऑफ h2 so4
Answer» The molecular formula of sulfuric acid is H2S 4 . Its molecular mass is = (1 × 3) + 3 2 + (1 6 × 4) = 2 + 32 + 64 = 98 u The expression for the equivalent WEIGHT of an acid is Equivalent weight = Molecular mass/ Number of replaceable hydrogen present sulphuric acid contains two replaceable hydrogen. Substitute values in the above expression. Equivalent weight = 98/2 = 49u

869.

फाइंड द इक्वल एंड मास ऑफ h2 so4

Answer»

The molecular formula of sulfuric acid is H2S 4 .

Its molecular mass is = (1 × 3) + 3 2 + (1 6 × 4)

= 2 + 32 + 64 = 98 u

The expression for the equivalent WEIGHT of an acid is

Equivalent weight = Molecular mass/ Number of replaceable hydrogen present

sulphuric acid contains two replaceable hydrogen. Substitute values in the above expression.

Equivalent weight = 98/2 = 49u

Discussion

870.	1.CH3-CH2-CH=CH-CH2-C≡CH2.CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2CH2OH3.CH3-CH2-CH2-CH2-CHO4.CH3-CH2-CH2-CH2-COOHIUPAC name for the given compounds Please give correct answer ( correct answer will be brainlisted)
Answer» Explanation: 1) Hept-4-en-1-yne 2) Nonan-1-ol 3) Pentanal 4) Pentanoic ACID

870.

1.CH3-CH2-CH=CH-CH2-C≡CH2.CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2CH2OH3.CH3-CH2-CH2-CH2-CHO4.CH3-CH2-CH2-CH2-COOHIUPAC name for the given compounds Please give correct answer ( correct answer will be brainlisted)

Answer»

Explanation:

1) Hept-4-en-1-yne 2) Nonan-1-ol 3) Pentanal 4) Pentanoic ACID

Discussion

871.	6) Write the name reaction which shown nucleophilic additionelimination
Answer» HOL aalumns hoyohblaarmos DEE PE do l EXPLANATION:

871.

6) Write the name reaction which shown nucleophilic additionelimination

Answer»

HOL aalumns hoyohblaarmos DEE PE do

l EXPLANATION:

Discussion

872.	Explain the battle of India
Answer» ANSWER: धार्मिक ग्रंथो के अनुसार वैवस्तव मनु के कुल दस पुत्र थे,जिनमें आठवें पुत्र का नाम इक्ष्वाकु था,इक्ष्वाकु के द्वारा ही कोशल नगरी बसाई गयी थी जिसकी राजधानी का नाम अयोध्या था,इक्ष्वाकु के वंश में अज तथा उनके पुत्र राजा दशरथ हुए,राजा दशरथ के ही पुत्र राम लक्ष्मण, भरत तथा शत्रुघन हुए,राजा दशरथ की पत्नी कौशल्या के पुत्र राम

872.

Explain the battle of India

Answer»

ANSWER:

धार्मिक ग्रंथो के अनुसार वैवस्तव मनु के कुल दस पुत्र थे,जिनमें आठवें पुत्र का नाम इक्ष्वाकु था,इक्ष्वाकु के द्वारा ही कोशल नगरी बसाई गयी थी जिसकी राजधानी का नाम अयोध्या था,इक्ष्वाकु के वंश में अज तथा उनके पुत्र राजा दशरथ हुए,राजा दशरथ के ही पुत्र राम लक्ष्मण, भरत तथा शत्रुघन हुए,राजा दशरथ की पत्नी कौशल्या के पुत्र राम

Discussion

873.	9. बेन्जीन का अणुभार 78 a.m.u है। इसका प्रतिशत संघटन 92.31%C एवं 7.69% H है। बेन्जीन अणुसूत्र ज्ञात कीजिए।[उत्तर-C6 H6..]
Answer» Explanation: बेंजीन का आणविक द्रव्यमान 78 एमू है। इसकी प्रतिशत संरचना 92.31% C और 7.69% H है। बेंजीन के आणविक सूत्र का निर्धारण करें। Molecular FORMULA =n× EMPIRICAL formula =6×CH=C6H6.

873.

9. बेन्जीन का अणुभार 78 a.m.u है। इसका प्रतिशत संघटन 92.31%C एवं 7.69% H है। बेन्जीन अणुसूत्र ज्ञात कीजिए।[उत्तर-C6 H6..]

Answer»

Explanation:

बेंजीन का आणविक द्रव्यमान 78 एमू है। इसकी प्रतिशत संरचना 92.31% C और 7.69% H है। बेंजीन के आणविक सूत्र का निर्धारण करें। Molecular FORMULA =n× EMPIRICAL formula =6×CH=C6H6.

Discussion

874.	Poly vinyl chloride, a plastic can be moulded and remoulded into various shapes by heating but melamine cannot be moulded a second time. give reason
Answer» $\rm\huge\underline{Answer}$ the BRANCH of science concerned with the substances of which matter is composed, the INVESTIGATION of their properties and reactions, and the use of such reactions to form NEW substances.

874.

Poly vinyl chloride, a plastic can be moulded and remoulded into various shapes by heating but melamine cannot be moulded a second time. give reason

Answer»

$\rm\huge\underline{Answer}$

the BRANCH of science concerned with the substances of which matter is composed, the INVESTIGATION of their properties and reactions, and the use of such reactions to form NEW substances.

Discussion

875.	What are amine ? write general formula of tertiary amine
Answer» Answer: I WANT to ASK same question only Explanation: can you Mark me as BRING LIST please

875.

What are amine ? write general formula of tertiary amine

Answer»

Answer:

I WANT to ASK same question only

Explanation:

can you Mark me as BRING LIST please

Discussion

876.	Calculate the effective nuclear charge for the Be electron of 1s atom
Answer» Effective Nuclear CHARGE FORMULA. Besides, the formula for calculating the effective nuclear charge of a single electron is as follows: ... Find Z: Atomic Number. ... Find S: Slater's Rules. ... Find S: ASSIGN electron value. ... Find S: Add VALUES together. ... SUBTRACT S from Z. ...

876.

Calculate the effective nuclear charge for the Be electron of 1s atom

Answer»

Effective Nuclear CHARGE FORMULA. Besides, the formula for calculating the effective nuclear charge of a single electron is as follows: ...

Find Z: Atomic Number. ...

Find S: Slater's Rules. ...

Find S: ASSIGN electron value. ...

Find S: Add VALUES together. ...

SUBTRACT S from Z. ...

Discussion

877.	Element 'A' belongs to 3rd period table and group 1 of the the modern periodic table .a) What is the atomic number of the element . b) Which element in the group is not metal .c)Which element in the same period has same valency as element A.
Answer» EXPLANATION: PLS MARK me a BRAINLIEST ANSWER

877.

Element 'A' belongs to 3rd period table and group 1 of the the modern periodic table .a) What is the atomic number of the element . b) Which element in the group is not metal .c)Which element in the same period has same valency as element A.

Answer»

EXPLANATION:

PLS MARK me a BRAINLIEST ANSWER

Discussion

878.	Find out the molecular mass of sulphuric acid (H2SO4)[ Atomic mass : H = 1 S = 32 O = 16 N = 14
Answer» Answer: The molar MASS of hydrogen is 1 Molar mass of sulphur (S) is 32 Molar mass of oxygen (O) is 16 Now , 2(1)+32+4(16) = 98 Molar mass of SULPHURIC acid i.e. H 2 SO 4 is 98. Explanation: Mark as the brainliest answer

878.

Find out the molecular mass of sulphuric acid (H2SO4)[ Atomic mass : H = 1 S = 32 O = 16 N = 14

Answer»

Answer:

The molar MASS of hydrogen is 1

Molar mass of sulphur (S) is 32

Molar mass of oxygen (O) is 16

Now ,

2(1)+32+4(16) = 98

Molar mass of SULPHURIC acid i.e. H

2

SO

4

is 98.

Explanation:

Mark as the brainliest answer

Discussion

879.	What is quase Static poleases?
Answer» Answer: In thermodynamics, a quasi-static process (ALSO known as a quasi-equilibrium process. From the Latin quasi, meaning 'as if'), is a thermodynamic process that happens slowly ENOUGH for the system to remain in INTERNAL thermodynamic equilibrium. ... The theoretical term 'reversible process' is SOMETIMES used. Explanation: hope it helps you please mark me as BRAINLIST

879.

What is quase Static poleases?

Answer»

Answer:

In thermodynamics, a quasi-static process (ALSO known as a quasi-equilibrium process. From the Latin quasi, meaning 'as if'), is a thermodynamic process that happens slowly ENOUGH for the system to remain in INTERNAL thermodynamic equilibrium. ... The theoretical term 'reversible process' is SOMETIMES used.

Explanation:

hope it helps you

please mark me as BRAINLIST

Discussion

880.	Derive expiration for pressure- volume work
Answer» ${\huge{\underline{\bold{ \purple{\tt{question}}}}}}$ Derive expiration for pressure- VOLUME work ${\huge{\underline{\bold{ \purple{\tt{Answer}}}}}}$ ☞During expansion, work is done by the SYSTEM and ∆V(V2 – V1) is positive. Therefore, in order to satisfy the SIGN conventions, a negative sign is put in the expression for work. During COMPRESSION, Work is done on the system. ☞Pressure-volume work On expansion, the force exerted by a gas is EQUAL to area of the piston multiplied by pressure with which the gas pushes against piston. This pressure is equal in magnitude and opposite in sign to the external atmospheric pressure that opposes the movement and has its value - Pext.

880.

Derive expiration for pressure- volume work

Answer»

${\huge{\underline{\bold{ \purple{\tt{question}}}}}}$

Derive expiration for pressure- VOLUME work

${\huge{\underline{\bold{ \purple{\tt{Answer}}}}}}$

☞During expansion, work is done by the SYSTEM and ∆V(V2 – V1) is positive. Therefore, in order to satisfy the SIGN conventions, a negative sign is put in the expression for work. During COMPRESSION, Work is done on the system.

☞Pressure-volume work

On expansion, the force exerted by a gas is EQUAL to area of the piston multiplied by pressure with which the gas pushes against piston. This pressure is equal in magnitude and opposite in sign to the external atmospheric pressure that opposes the movement and has its value - Pext.

Discussion

881.	What is rusting and
Answer» Answer: Rusting is oxidation of iron or iron objects. It takes place in the PRESENCE of AIR and moisture. It is a SLOW process. Due to rusting, RUST is formed on iron objects. It is a red-orange colored iron OXIDE which is formed by the oxidation of iron in presence of oxygen and moisture or water. Explanation:

881.

What is rusting and

Answer»

Answer:

Rusting is oxidation of iron or iron objects. It takes place in the PRESENCE of AIR and moisture. It is a SLOW process. Due to rusting, RUST is formed on iron objects. It is a red-orange colored iron OXIDE which is formed by the oxidation of iron in presence of oxygen and moisture or water.

Explanation:

Discussion

882.	What is physucal quantity give two examples of physical changes
Answer» ANSWER: Base quantity Symbol Description Mass m A measure of resistance to acceleration Time t The duration of an event Electric Current I RATE of FLOW of electrical charge per unit time Temperature T Average kinetic energy per DEGREE of freedom of a system Explanation: mark as BRILLIANT

882.

What is physucal quantity give two examples of physical changes

Answer»

ANSWER:

Base quantity Symbol Description

Mass m A measure of resistance to acceleration

Time t The duration of an event

Electric Current I RATE of FLOW of electrical charge per unit time

Temperature T Average kinetic energy per DEGREE of freedom of a system

Explanation:

mark as BRILLIANT

Discussion

883.	250 cm3 of sulphur IC acid contain 24.5 g of h2so4. The density of solution is 1.98g/cm3. Determine molality
Answer» GIVEN : 250 cm³ sulphuric acid ( $\sf H_2 SO_4$ ) contain 24.5 g of $\sf H_2 SO_4$ . And, The DENSITY of the SOLUTION is 1.98 g/cm³. ⠀━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀ Formula of Molality (m) is given by, ⠀⠀ $\bigstar\:{\boxed{\sf{\pmb{Molality = \dfrac{No.\:of\:moles\:of\:Solute}{Mass\:of\:solvent\:in\:kg}}}}}\\\\\\$ So, First of all we will calculate Mass of Solvent – ⠀⠀ We're provided in the QUESTION that, the density of the solution is 1.98 g/cm³. So, From this we can easily calculate Mass of solution then Mass of Solvent. ⠀⠀ $\dashrightarrow\sf Density = \dfrac{Mass}{Volume}\\\\\\ \dashrightarrow\sf 1.98\:g/cm^3 = \dfrac{Mass_{\:(solution)}}{250\:cm^3}\\\\\\ \dashrightarrow\sf Mass_{\:(solution)} = 1.98 \times 250\\\\\\ \dashrightarrow{\boxed{\frak{Mass_{\:(solution)} = 495\:g}}}\\\\\\$ If Mass of Solution is 495 g and Mass of Solute is 24.5 g then, Mass of Solvent = 495 - 24.5 = 470.5 g = 0.4705 kg ⠀━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀ Hence, We've calculated Mass of Solvent i.e. 0.4705 kg. Now, Let's FIND out Molality — ⠀⠀ $\longrightarrow\sf m = \dfrac{No.\:of\:moles\:of\:Solute}{Mass\:of\:solvent\:in\:kg}\\\\\\ \longrightarrow\sf m = \dfrac{24.5}{98 \times 0.4705}\\\\\\ \longrightarrow\sf m = \dfrac{0.25}{0.4705}\\\\\\ \longrightarrow{\boxed{\sf{\pmb{\pink{m = 0.531\:molal}}}}}\:\bigstar\\\\\\$ $\therefore$ Hence, The Molality of Given solution is 0.531 m.

883.

250 cm3 of sulphur IC acid contain 24.5 g of h2so4. The density of solution is 1.98g/cm3. Determine molality

Answer»

GIVEN : 250 cm³ sulphuric acid ( $\sf H_2 SO_4$ ) contain 24.5 g of $\sf H_2 SO_4$ . And, The DENSITY of the SOLUTION is 1.98 g/cm³.

⠀━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

Formula of Molality (m) is given by,

⠀⠀

$\bigstar\:{\boxed{\sf{\pmb{Molality = \dfrac{No.\:of\:moles\:of\:Solute}{Mass\:of\:solvent\:in\:kg}}}}}\\\\\\$

So, First of all we will calculate Mass of Solvent –

⠀⠀

We're provided in the QUESTION that, the density of the solution is 1.98 g/cm³. So, From this we can easily calculate Mass of solution then Mass of Solvent.

⠀⠀

$\dashrightarrow\sf Density = \dfrac{Mass}{Volume}\\\\\\ \dashrightarrow\sf 1.98\:g/cm^3 = \dfrac{Mass_{\:(solution)}}{250\:cm^3}\\\\\\ \dashrightarrow\sf Mass_{\:(solution)} = 1.98 \times 250\\\\\\ \dashrightarrow{\boxed{\frak{Mass_{\:(solution)} = 495\:g}}}\\\\\\$

If Mass of Solution is 495 g and Mass of Solute is 24.5 g then,

Mass of Solvent = 495 - 24.5 = 470.5 g = 0.4705 kg

⠀━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

Hence, We've calculated Mass of Solvent i.e. 0.4705 kg. Now, Let's FIND out Molality —

⠀⠀

$\longrightarrow\sf m = \dfrac{No.\:of\:moles\:of\:Solute}{Mass\:of\:solvent\:in\:kg}\\\\\\ \longrightarrow\sf m = \dfrac{24.5}{98 \times 0.4705}\\\\\\ \longrightarrow\sf m = \dfrac{0.25}{0.4705}\\\\\\ \longrightarrow{\boxed{\sf{\pmb{\pink{m = 0.531\:molal}}}}}\:\bigstar\\\\\\$

$\therefore$ Hence, The Molality of Given solution is 0.531 m.

Discussion

884.	3. A solution contains 15 gm of NaCl in 250ml of water. Calculate mass by volume concentration of its solute.
Answer» the CONCENTRATION of this SOLUTE is 1 MOLAR

884.

3. A solution contains 15 gm of NaCl in 250ml of water. Calculate mass by volume concentration of its solute.

Answer»

the CONCENTRATION of this SOLUTE is 1 MOLAR

Discussion

885.	एक कार्बनिक द्रव में C, H, N एवं 0 पाए गए, जिसमें C = 41.37%; H = 5-75%; N = 16-09% एवं शेष ऑक्सीजन है। यदि द्रव का वाष्प घनत्व 43.3 है, तो द्रव के अणुसूत्र की गणना कीजिए।[उत्तर-CHINO2.]
Answer» Answer: 89% HOPE HELP you

885.

एक कार्बनिक द्रव में C, H, N एवं 0 पाए गए, जिसमें C = 41.37%; H = 5-75%; N = 16-09% एवं शेष ऑक्सीजन है। यदि द्रव का वाष्प घनत्व 43.3 है, तो द्रव के अणुसूत्र की गणना कीजिए।[उत्तर-CHINO2.]

Answer»

Answer:

89%

HOPE HELP you

Discussion

886.	2. What is the advantage of using thermoset forhandles on kettles?
Answer» Explanation: Because plastic is BAD CONDUCTOR of HEAT and electricity

886.

2. What is the advantage of using thermoset forhandles on kettles?

Answer»

Explanation:

Because plastic is BAD CONDUCTOR of HEAT and electricity

Discussion

887.	is 0.6 and moles of K2 cr2 O7 and 2.04 moles of H2 S o4 reacted find the limiting reactant and the mass of the reactant and left Behind
Answer» gggggggggggggggggggkk

Discussion

888.	1. Name two main groups of plastics. Describe theirproperties based on which they are differentiated
Answer» Answer: The two key categories of PLASTIC are thermoplastics and thermosetting PLASTICS (THERMOSETS).

888.

1. Name two main groups of plastics. Describe theirproperties based on which they are differentiated

Answer»

Answer:

The two key categories of PLASTIC are thermoplastics and thermosetting PLASTICS (THERMOSETS).

Discussion

889.	एंट्रोपी को परिभाषित कीजिए एवं इसकी भौतिक सार्थकता को समझाये
Answer» ANSWER: SORRY sorry very sorry OPPS

889.

एंट्रोपी को परिभाषित कीजिए एवं इसकी भौतिक सार्थकता को समझाये

Answer»

ANSWER:

SORRY sorry very sorry OPPS

Discussion

890.	What is the application of photolysis/ photodecomposition in the commercialindustry ? Give any one of the balanced equations ?
Answer» ANSWER: A decomposition reaction can be defined as a CHEMICAL reaction in which one reactant breaks down into two or more products. Explanation: MARK as the BRAINLIEST answer

890.

What is the application of photolysis/ photodecomposition in the commercialindustry ? Give any one of the balanced equations ?

Answer»

ANSWER:

A decomposition reaction can be defined as a CHEMICAL reaction in which one reactant breaks down into two or more products.

Explanation:

MARK as the BRAINLIEST answer

Discussion

891.	Write four similarities and four dissimilarities of hydrogen with 1A group of elements
Answer» There are FOLLOWING SIMILARITIES of hydrogen with alkali METALS 1. Electronic Configuration: The electronic configuration of hydrogen is 1s 1 which is similar to the outmost electronic configuration of alkali metals (ns 1 ). Som it is placed with alkali metals in group 1 2. Electropopsitive Character: Hydrogen can from unipositive ION by losing one electron like alkali metals. e.g., H→H + +e − Na→Na + +e − 3. Oxidation State: Hydrogen exhibits oxidation state of +1 ion the compounds of hydrogen which is similar to alkali metals. 4. Valency: Valency of hydrogen is 1 like alkali metals. 5. Reaction with Non-metals: Like alkali metals, hydrogen dorms binary compounds with non-metal, 6. Reducing nature: Hydrogen is a good reducing agent like alkali metals. 1 A group is also known alkali metal please mark me brain mark list

891.

Write four similarities and four dissimilarities of hydrogen with 1A group of elements

Answer»

There are FOLLOWING SIMILARITIES of hydrogen with alkali METALS

1. Electronic Configuration: The electronic configuration of hydrogen is 1s

1

which is similar to the outmost electronic configuration of alkali metals (ns

1

). Som it is placed with alkali metals in group 1

2. Electropopsitive Character: Hydrogen can from unipositive ION by losing one electron like alkali metals.

e.g., H→H

+

+e

−

Na→Na

+

+e

−

3. Oxidation State: Hydrogen exhibits oxidation state of +1 ion the compounds of hydrogen which is similar to alkali metals.

4. Valency: Valency of hydrogen is 1 like alkali metals.

5. Reaction with Non-metals: Like alkali metals, hydrogen dorms binary compounds with non-metal,

6. Reducing nature: Hydrogen is a good reducing agent like alkali metals.

1 A group is also known alkali metal

please mark me brain mark list

Discussion

892.	Lattice energy of CuBr molecule
Answer» The lattice ENERGIES are calculated to be, for CUCL 216 kcal., CUBR, 208 kcal., CuI 199 kcal. please mark me brain mark list

892.

Lattice energy of CuBr molecule

Answer»

The lattice ENERGIES are calculated to be, for CUCL 216 kcal., CUBR, 208 kcal., CuI 199 kcal.

please mark me brain mark list

Discussion

893.	Calculate the mass of CuSO4 and water required to prepare 250g of 10% solution of CuSO4.
Answer» Answer: mass of copper sulphate = 25 G and mass of WATER= 225 g EXPLANATION: Explanation is given in the IMAGE.

893.

Calculate the mass of CuSO4 and water required to prepare 250g of 10% solution of CuSO4.

Answer»

Answer:

mass of copper sulphate = 25 G and mass of WATER= 225 g

EXPLANATION:

Explanation is given in the IMAGE.

Discussion

894.	Air (Mainly O2+ N2) is an example for…homogeneous or hetrogeneous mixture
Answer» Answer: homogeneous mixture Explanation: because DUST particle , SAND are ADDED in AIR

894.

Air (Mainly O2+ N2) is an example for…homogeneous or hetrogeneous mixture

Answer»

Answer:

homogeneous mixture

Explanation:

because DUST particle , SAND are ADDED in AIR

Discussion

895.	If the resistance of an electric iron is 70 Ω and a current of 3.2 A flows through the resistance. Find the voltage between two points.
Answer» Given :- Resistance = 70Ω Current = 3.2A To Find :- VOLTAGE Solution :- ACCORDING to Ohm's LAW :- $\bf <klux>V</klux> = IR$ V denotes voltage I denotes current R denotes resistance Substitute the values :- $: \implies \sf V = 3.2 \times 70$ $: \implies \sf V = 32 \times 7$ $: \implies \sf V = 224$ Voltage between two points = 224V

895.

If the resistance of an electric iron is 70 Ω and a current of 3.2 A flows through the resistance. Find the voltage between two points.

Answer»

Given :-

Resistance = 70Ω

Current = 3.2A

To Find :-

VOLTAGE

Solution :-

ACCORDING to Ohm's LAW :-

$\bf <klux>V</klux> = IR$

V denotes voltage
I denotes current
R denotes resistance

Substitute the values :-

$: \implies \sf V = 3.2 \times 70$

$: \implies \sf V = 32 \times 7$

$: \implies \sf V = 224$

Voltage between two points = 224V

Discussion

896.	if 5 ampere of current is passed through a solution for 10 hours then the number of electons flown through the solution is (charge of electron =1.6*10-19)
Answer» Given :- Current = 5A Time = 10 × 60 × 60 seconds To Find :- Number of electrons Solution :- We KNOW :- Q = It I denotes current t denotes time Q denotes charge Substitute the values :- $: \implies \sf Q = 5 \times 10 \times 60 \times 60$ $: \implies \sf Q = 180000$ Also we know :- Q = ne n denotes number of electrons e denotes charge of one electron $: \implies \sf n = \dfrac{Q }{e}$ $: \implies \sf n = \dfrac{180000}{1.6 \times {10}^{ - 19} }$ $: \implies \sf n = 112500 \times {10}^{19}$ Number of electrons :- 1125 × 10^21

896.