InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
How many processes form the following are the examples of combustions : (i) Rusting of iron (ii) Respiration (iii) Digestion (iv) Conversion of solid Iodine into vapour on heating. (v) Photosynthesis (vi) Explosion of hydrogen in air? |
|
Answer» Rusting of iron |
|
| 402. |
Express 120mg of MaSO4 in Equivalent of |
|
Answer» Answer: HOPE Pictured answer will HELP You. plz GIVE my answer brainliest |
|
| 403. |
1.If 700mL of H_(2) at STP contains x molecules of it how many molecules of O_(2) are present in 700mL of it at the same temperature and pressure? |
|
Answer» 22.4L = 6.022×10²² molecules 2L= x X=2×6×10²²/22.4 ≈ 5.37 Please mark me as brainliest |
|
| 404. |
How does the metallic character of elements change along a period of the periodic table from left to the right and why ? |
|
Answer» Answer: Metallic character DECREASES as you move across a period in the PERIODIC table from left to RIGHT. This occurs as atoms more readily accept electrons to fill a valence shell than LOSE them to remove the unfilled shell. Metallic character increases as you move down an element group in the periodic table. |
|
| 405. |
Hello pls answer fastNo.of particles present in bcc unit cell is |
|
Answer» Explanation: Body CENTRED CUBIC lattice (BCC) contains 8 corner particles and one particle at the centre of the body. The CONTRIBUTION of body centre atom to the unit cell is 1 |
|
| 406. |
Write note on colours in transition elements |
|
Answer» Answer: When visible light falls on a TRANSITION metal COMPOUND or ion, the unpaired electrons present in the lower energe d-orbital get promoted to HIGH energy d-orbitals, CALLED d-d transition, due to the ABSORPTION of visible light. ... Therefore, transmitted light shows some colour complementary to the absorbed colour. |
|
| 407. |
Explain the application of wrong postulates of kinetic molecular theory of gas |
|
Answer» Explanation: Two postulates of kinetic molecular theory of gases were CONSIDERED WRONG by Van Der Waal. 1 The volume OCCUPIED by the molecule is negligible compared to the volume of the vessel. ... 2 The attraction between the molecules is considered to be NIL by the kinetic theory of gases |
|
| 408. |
One mole of water is placed in a 100-liter container and heated to 14320C.The kc for the reaction 2H2O(g) ⇄ 2H2(g) + O2(g) is 1.35x10-11.Determine the following:a. concentration of hydrogenb. concentration of oxygen |
|
Answer» Answer:A)Hydrogen ion concentration is more conveniently expressed as pH, which is the LOGARITHM of the RECIPROCAL of the hydrogen ion concentration in gram moles per liter. THUS, in a neutral solution the hydrogen ion (H+) and the hydroxyl ion (OH−) concentrations are equal, and each is equal to 10−7. A pH of 7 is neutral. 2)The ATMOSPHERIC concentration of O2 has remained constant for several HUNDRED years at 20.95%. This means that exactly 20.95% of the molecules in the atmosphere are O2 molecules. Explanation: |
|
| 409. |
Decide if a reaction will take place when iron is placed in a solution of lead nitrate |
| Answer» | |
| 410. |
Alkylation Product of OH - CH₂ - CH₂ -NH2 |
|
Answer» Don't KNOW |
|
| 411. |
Please answer this question asap |
|
Answer» Answer: CUSO4 ->2E negative sign -> cu2F charge required for I mole of cu Q=I ×T = 5×100×60 =3000 C Q= 3000C 2×96500 sive (63.5g of cu) 1C will GIVE 63.5/2×96500 then MULTIPLE it with 3000 C = 9.87g |
|
| 412. |
What is magnetic moment of V+2 |
|
Answer» Fantasy VS Reality What I have LEARNED? Explanation: Fantasy vs Reality What I have learned? |
|
| 414. |
What is the name of the process due to which dry ice change into carbon dioxide gas? |
|
Answer» TOYS ruhhuui Explanation: iyiiuijhyjkjj 83iu |
|
| 415. |
What is magnetic moment of Ti+3 |
|
Answer» xqy gqrw qzwiikeiwiiwijwjsiie |
|
| 416. |
Dopamine + Serotonin + Oxytocin = ????? |
Answer» Serotonin, dopamine, oxytocin, and endorphins are famously happy HORMONES that promote positive FEELINGS like pleasure, happiness, and EVEN lovehope it's HELP you |
|
| 417. |
Find the molarity of water id density given 1g/ml.✧༺♥༻✧ |
|
Answer» Answer: Answer♡⋆ Escape velocity is the minimum velocity that a body must ATTAIN to escape the gravitational field of the EARTH. SUPPOSE if we THROW a BALL,it will fall back. |
|
| 418. |
KBr (potassium bromide) contains 32.9% by weight of potassium. IF 6.40 g of bromine reacts with 3.60 g of potassium, calculate the number of moles of potassium which combine with bromine to from KBr |
|
Answer» Answer: Explanation: For 100 gm of KBr sample, mass of K = 32.9 gm Mass of Br = 100 -32.9 = 67.1 So, if 67.1 gm of bromine REACTS with 32.9 gm of potassium Then 6.40 gm Br will react with = (32.9/67.1) x 6.40 = 3.14 gm potassium. So, in the given sample the amount of potassium which will be un reacted is = 3.60 -3.14 = 0.46 gm Now, as we know that, mass of potassium reacting in the KBr sample = 3.14 gm So, MOLES of potassium = given mass/ MOLAR mass = 3.14/ 39 = 0.08 moles. Hence, 0.08 moles of potassium combines to form KBr . |
|
| 419. |
व्हाट इज मेंट बाय एग्जॉथर्मिक एंड एंडॉथर्मिक रिएक्शन वायरस इक्वेशन कंसीडर टू बी एंड एग्जॉथर्मिक रिएक्शन एंड फोटोसिंथेसिस टू बी एंड एंडॉथर्मिक रिएक्शन गिव एंड एग्जांपल ऑफ फॉर कांबिनेशन रिएक्शन विच इज आल्सो एग्जॉथर्मिक |
| Answer» | |
| 420. |
V Dutys absocks B chemically milk of magnesia is LS and baking soda |
|
Answer» Chemistry is a BRANCH of NATURAL SCIENCE that deals principally with the PROPERTIES of substances, the changes they undergo, and the natural LAWS that describe these changes. |
|
| 421. |
Decide if a reaction will take place when lead is placed in a solution |
|
Answer» Answer: No, there will be no reaction as Lead LIES MUCH below MAGNESIUM in the REACTIVITY series of metals. Only a more ELECTROPOSITIVE metal can displace a less electropositive metal from its salt. Lead is much less electropositive than magnesium, so it cannot displace magnesium metal from its salt in the solution state. |
|
| 422. |
What is the chemistry? |
|
Answer» Answer: Chemistry is the SCIENTIFIC STUDY of the PROPERTIES and behavior of MATTER. It is a natural science that covers the elements that make up matter to the compounds composed of atoms, MOLECULES and ions |
|
| 423. |
What inert gas is use to fill a light bulb? assignment |
|
Answer» Answer: Argon is a commonly used gas used to fill INCANDESCENT light BULBS. It increases bulb life by preventing the tungsten filaments from deteriorating too quickly. Other GASES such as helium, NEON, nitrogen and krypton are also used in lighting. The gases used in light bulbs are known as INERT gases. |
|
| 424. |
On dissolving 3.24 g of sulphur in 40 g of benzene, boiling point of solution was higher thanthat of benzene by 0.81 K. Kb value for benzene is 2.53 K kg mol-I. What is the molecular formula of sulphur ? (Atomic mass of sulphur = 32 g mol-I). |
|
Answer» Don't KNOW |
|
| 425. |
which factor decrease strength of carboxylic acid...a-branching. b-charge on proton. c-electron donating proton d-all |
|
Answer» Electron PUSHING effect containing group -> In presence of +I effect containing group the acidity of CARBOXYLIC acid DECREASES as the polarity of OH bond decreases. On the other hand in the presence of effect containing group the acidity of carboxylic acid increases. |
|
| 426. |
Name a non-metal having a very high melting point?? |
|
Answer» DIAMOND being the allotrope of carbon is a non-metal which possesses the highest melting POINT AMONG all the non-metals. |
|
| 427. |
Sxample 47 Calculate a) the actual volume of one molecule of water. b) the radius of a water molecule assuming to be spherical (density of water = 1 g ml-2). |
|
Answer» gdfvsgjdvg4fghbdd Explanation: |
|
| 428. |
Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 5Ω resistor, an 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series. |
| Answer» | |
| 429. |
What is the difference between Molecular Formula and Emprical Formula? |
Answer» REQUIRED Answer:☑ The empirical formula of a compound gives the simplest ratio of the number of DIFFERENT atoms present, whereas the molecular formula gives the actual number of each different atom present in a molecule. Empirical formulas SHOW the simplest whole-number ratio of atoms in a compound, molecular formulas show the number of each type of atom in a molecule, and STRUCTURAL formulas show how the atoms in a molecule are bonded to each other. |
|
| 430. |
Are metalloids pure substance or impure substance?? if yes then why as it constitutes of more than one type of molecules?? |
|
Answer» Answer:Have you heard your parents speak of pure and IMPURE water? Do you know what that means? In this CHAPTER, we will tell you more about it! Here, we will cover the concepts of pure substances. You will get a detailed information about the TYPES of pure substances and their properties. This is a very interesting CONCEPT and an important one from the exam point of view. Explanation: |
|
| 431. |
Distinguish between compound and mixture |
|
Answer» Answer: A compound is the substances that are formed by COMBINING two are more chemical elements. A MIXTURE is a substance created from two or more matter that can be separate with the help of physical METHODS. Compound substances are always homogeneous in nature |
|
| 432. |
classify each of the following as a physical or a chemical change give reason (a) dying of a t-shirt in the sun |
|
Answer» PHYSICAL CHANGE Explanation: |
|
| 433. |
The density of 3M solution of NaCl is 1.2 g/ml. Calculate the molality of the solution |
|
Answer» FIND your answer in the pic Explanation: |
|
| 434. |
Calculate the number of photons present in 10 J quanta, having wavelength of 400nm. |
|
Answer» USE E=HC/lambda formula |
|
| 435. |
Which pair of quantities have same units |
|
Answer» Answer: stress and PRESSURE. thrust and pressure. Explanation: |
|
| 437. |
Calculate the number of atoms of each type in a 8 of Na.co. Solution Gram molecular mass of Na,Co, - 232+12+ 3x16 106.0 g of No,Co,- 1 mol 1 5.3 g of Na, cog 0.05 m 106.0 Now, 1 mol of Na.co, contains 26.022 10 sodium atoms -0.05 mol of Na.co, contains = 0.05 28.02210 sodium atoms = 6.022 x 10" Na atoms 1 mol of Na, co, contains 6.022 x 10 carbon atoms |
|
Answer» okkkkkkkkkkkkkkkkkkkkkkkkkkkkk |
|
| 438. |
How many spherical and angular nodes are there in 3p, show its boundary surface diagram. |
|
Answer» Explanation: The number of radial nodes, otherwise known as spherical shell nodes, is given by n-l-1 =3-1-1 =1 radial node in the 3P orbital The number of angular nodes, is given by l, so there is l=1 angular node in the 3p orbital Thus, the total number of nodes is given by n-1 =3-1 =2 THEREFORE, total number of nodes in 3p orbital is 2 solution |
|
| 439. |
Identify solute and solvent in 'tincture of iodine'. |
|
Answer» Answer: In the tincture of iodine, the solvent is ALCOHOL and WATER while the solute is iodine. Explanation: Tincture of iodine, iodine tincture, or WEAK iodine solution is an antiseptic. It is usually 2 to 7% elemental iodine, along with potassium iodide or sodium iodide, dissolved in a mixture of ethanol and water. Tincture SOLUTIONS are characterized by the presence of alcohol. Hope this helps you |
|
| 440. |
दो योगिक अपने आयनो का विनिमय करके दो नए योगिकों का निर्माण करते हैं यह अभिक्रिया कौन सी है |
|
Answer» सरल शब्दों में हम कह सकते हैं कि जब दो या दो से अधिक पदार्थ (तत्व या यौगिक) संयोग करके एकल उत्पाद का निर्माण करते हैं, ऐसी अभिक्रियाओं को संयोजन अभिक्रिया कहते हैं। Explanation: Here is your answer |
|
| 441. |
How many electrons are there in (i) n+l=3 (ii) 2p when s=+1/2 (iii) l=2 for Fe+3 |
|
Answer» I=2 for Fe+3 hope it's HELP you!!! |
|
| 442. |
SABUN SENIOR Ques How many significant fignus are р present in the following (0.0025 (1) 208 lill soos 126,00 (0) 2.0034 TENIR |
| Answer» | |
| 443. |
For a chemical reaction; A (g) +B() D(g) +E(g) Hypothetically at what temperature, K=K (when, R=0.08 l-atm/mole-K) (a) T=OK (b) T=1K (c) T= 12.5K (d) T=273 K |
|
Answer» Don't KNOW |
|
| 444. |
A solution contaning 20ml of alchole in 60ml of water calculate the concentration of solutio |
|
Answer» Answer: VOLUME of SOLUTE ( alcohol ) = 20 ml volume of solvent ( water ) = 60 ml therefore, volume of solution = 20 + 60 = 80 concentration = volume of solute / volume of solution 20/80 × 100 40 × 100 = 4000 Explanation: HOPE this helps you mark me as brainlist |
|
| 445. |
0 are eues How many significant figures present in the following 10.0025 (1) 208 Lill) soos cu 126, ooo CU) 2.0034 |
| Answer» | |
| 446. |
What is chemistry tell me fast |
|
Answer» A science that deals with the composition, STRUCTURE and properties of the substances and with the transformatuon that they undergo. hope it HELPS you please mark me BRAINLIEST |
|
| 447. |
How many nodes are there in s , p , d , f orbitals? |
|
Answer» Answer: 3 NODESA 4f-orbital has 3 nodes. |
|
| 448. |
Give TP, B.P. l.p hybridisation and shape of Following molecules on 1)SF6 2)sf4 3)ch4 4)nh3 5)pcl5 |
|
Answer» Explanation: ) H2O: Shape: Tetrahedral Hybridization: sp3 No.of LONE pair of electrons: 2 b) NH3 Shape: Trigonal pyramidal Hybridization: sp3 No.of lone pair of electrons: 1 c) SO2 Shape: Trigonal planner Hybridization: sp2 No.of lone pair of electrons: 1 d) CH4 Shape: Tetrahedral Hybridization: sp3 No.of lone pair of electrons: 0 e) PCl5 Shape: Trigonal bipyramidal Hybridization: sp3d No.of lone pair of electrons: 0 on P and 3 on each CLF) SF4 Shape: Trigonal bipyramidal Hybridization: sp3d No.of lone pair of electrons: 1 |
|
| 449. |
Write the structures and IUPAC names of all possible aldol products formed in the following cases and label them as self and cross aldol products: 1. Ethanal and acetone 2. Acetone and butanone 3. Acetone and formaldehyde |
|
Answer» Chemistry is a branch of natural science that DEALS principally with the PROPERTIES of substances, the CHANGES they undergo, and the natural laws that DESCRIBE these changes. |
|
| 450. |
Write structures and IUPAC names of all possible aldol condensation products in following cases: 1. Propanal and acetone 2. Acetone and butanone |
|
Answer» (i) Taking TWO molecules of propanal, one which acts as a nucleophile and the other as an ELECTROPHILE. (ii) Taking two molecules of butanal, one which acts as a nucleophile and the other as an electrophile. (III) Taking one molecule each of propanal and butanal in which propanal acts as a nucleophile and butanal acts as an electrophile. (IV) Taking one molecule each of propanal and butanal in which propanal acts as an electrophile and butanal acts as a nucleophile. |
|