InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 49101. |
Which has greater ionisation potential Nitrogen and phosphorus and explain |
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Answer» Well, it is for the same reason nitrogen atom has a HIGHER FIRST ionization energy than oxygen atom. Since the 3P electrons in sulfur (that sulfur would lose) are paired, sulfur has more electron repulsion in those orbitals than PHOSPHORUS does, so it takes less energy input to remove an electron from sulfur.hope it will HELP youMark as Brainliest |
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| 49102. |
10. A metal 'X' available in the form of ribbon when heated in air burns with dazzling white flame and forms a compound 'Y'. When compound 'Y' is dissolved in water it turns in to a solution 'Z'. Identify X,Y and Z. write the nature of solution Z ( acidic or basic). write balanced chemical equations in both the situations |
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Answer» x=magnesium y=magnesium OXIDE z=it does not REACT PH= 9 alkalineExplanation: |
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| 49103. |
Hi guys what is the use of sodium |
| Answer» SODIUM is PRIMARILY used in the form of compounds with other elements. The average PERSON USES sodium every day in the form of table salt in their food. Table salt is the compound sodium CHLORIDE (NaCl). | |
| 49104. |
Balance the following please please |
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Answer» this is your answer SORRY it wasn't fitting in ONE picture HOPE you understand |
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| 49105. |
an ionic solid mx have bcc structure has the edge length 4.3pm the shortest interionic distance between mx |
| Answer» CHECK in GOOGLE ........... | |
| 49106. |
8. Is the law of constant proportion applicable to the non-stoichiometric compounds? Give reason. Giveanother example where this law does not hold good. |
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Answer» of constant PROPORTIONS is not applicable to the non - stoichiometric COMPOUNDS because these compounds do not have a fixed composition. The law of constant proportions does not HOLD GOOD when a compound is obtained by using different isotopes of the elements present in that compound. Hence, the given answer is verified. |
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| 49108. |
Sandmeyers reaction? |
| Answer» TION:The SANDMEYERS REACTION is a CHEMICAL reaction | |
| 49109. |
The correct order of reactivity of H atoms |
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Answer» 3Explanation:3rd option is the answer PLZ ADD as BRAIN LIST answer |
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| 49110. |
An organic compound A is consisted of C, H, N and O. A forms B when reacts with NaOH and bromine. B forms Ethyl alcohol when reacts with sodium nitrite and hydrochloric acid. Identify the compounds A and B. Give reasoning to your answer. |
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Answer» is CH3CH2CNH2 || Oit undergoes Hoffman bromanamide reaction (NaOH/Br2) to give ethanamine which on further reaction with NaNO2/HCl give ethyl alcohol I hope this helpspls mark BRANLIEST if it helpsNOTE:HBD IS USED IN ORDER TO REDUCE ONE CARBON ATOM BY CONVERTING AMIDE (CONH2) TO AMINE GRP |
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| 49111. |
PH of blood isA. 4B. 6.4C. 7.4D. 8 |
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Answer» C)7.4Explanation:HOPE U understand please MARK me as BRAINLIEST... |
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| 49112. |
An unbalanced chemical equation is written in: a, Skeletal form b. Proper form c. Simple form d. Unorganised form |
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Answer» a skeletel formExplanation: |
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| 49113. |
A metal plate 4 mm thick has a temperature difference of 32°C between its faces. It transmits 200 kcal/h through an area of 5 cm². Calculate thermal conductivity of the material of the plate. |
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Answer» Given : Δ x = 4 mm = 4 × 10⁻³ mΔ T = 32 CΔ Q / Δ t = 200 k cal / hr= > Δ Q / Δ t = ( 200 × 1000 × 4.2 ) / ( 60 × 60 ) J / sec = 233.33 J / secA = 5 cm² = 5 × 10⁻⁴ m²We are ASKED to find Thermal conductivity i.e. KWe know : K = ( Δ Q / Δ t ) / A ( Δ T / Δ x ) Putting values here we get : K = ( 233.33 × 4 × 10⁻³ ) / ( 5 × 10⁻⁴ × 32 ) K = ( 233.33 × 4 ) / ( 5 × 10⁻¹ × 32 ) K = ( 233.33 × 4 ) / ( 5 × 3.2 ) K = 933.32 / 16K = 58.33 W / m / CHence thermal conductivity of material of the plate is 58.33 W / m / C. |
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| 49114. |
How to convert C6H5COOH to Cyanobenzene? |
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Answer» hiiiyour answer is here !EXPLANATION:Benzoic ACID is treated with ammonia and the ammonium benzoyate obtained is heated to GET benzamide. Benzamide can be converted in to cyanobenzene by DEHYDRATING it using P2O5.follow me ! |
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| 49115. |
Calcium hydroxide+carbon dioxide- carbon carbonate +water balance the following equation |
| Answer» | |
| 49116. |
The elements impart colour to the flame on heating in it the atoms which require low energy for ionisation |
| Answer» EXPLANATION:Its BEACAUSE of EXCITATION of ELECTRON So | |
| 49117. |
The strongest acid among the following is?? |
| Answer» OPTION D is RIGHT ANSWEREXPLANATION:HOPE this HELPS you | |
| 49118. |
Calculate the vapour density of a gas, 12.8g of which occupies 10L at a pressure of 750 mm at 27°C. |
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Answer» V.D. = 15.92Explanation:We know : Vapour DENSITY ( V.D. ) = W / 2 × ( R T / P V ) We have given : W = 12.8 gT = 27 C = 27 + 273 K = 300 KP = 750 / 760 atmV = 10 LValue of R = 0.081 L-atm mol⁻¹ K⁻¹Putting values we get : V.D. = ( 12.8 × 0.082 × 300 ) / ( 750 / 760 × 10 × 2 ) V.D. = ( 6.4 × 8.2 ) ( 15 / 76 × 10 ) V.D. = 15.92Hence we get required ANSWER. |
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| 49119. |
Explain the following terms in gain or loss of oxygen with one example: a)Oxidation b)Reduction |
| Answer» OXIDATION have LOSS of OXYGEN and REDUCTION have GAIN of oxygen | |
| 49120. |
At 15°C and 900 mm pressure, 0.4 gram of a certain gas occupied 3280 mL. If the pressure is changed to 1300 mm at constant temperature. What is the density of the gas? |
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Answer» 1.762 × 10⁻⁴ g / mLExplanation:We know : Density = Mass / VOLUME= > Density at 900 mm PRESSURE = 0.5 / 3280 g / mL = 0.000122 g / mLAt constant temperature : = > Density × Pressured₁ / P₁ = d₂ / P₂= > d₂ = ( d₁ P₂ ) / P₁We have VALUES of : d₁ = 0.00012 g / mLP₁ = 900 mmP₂ = 1300 mmPutting values in d₂ : d₂ = ( 0.000122 × 1300 ) / 900 = > d₂ = ( 0.000122 × 13 ) / 9= > d₂ = 0.0001762 g / mL= > d₂ = 1.762 × 10⁻⁴ g / mLHence we get required ANSWER. |
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| 49121. |
Hydrogen plus oxygen yield water. (Remember diatomic elements!) |
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Answer» -------------> 2H2OTHIS IS COMBINATION REACTIONSTAY AT HOME #CORONA VIRUS# |
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| 49122. |
Explain:- "Hyperconjugation ". |
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Answer» Explanation:Hyperconjugation is the STABILISING interaction that results from the interaction of the electrons in a σ-bond (usually C-H or C-C) with an adjacent empty or partially filled p-ORBITAL or a π-orbital to GIVE an EXTENDED molecular orbital that INCREASES the stability of the system. |
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| 49123. |
A 10.0 L rigid container is evacuated and to it is added 0.500 moles of NO and 0.500 moles of O2 gas. They react to completion to produce NO2 gas. Write the balanced equation. |
| Answer» RIGID CONTAINER is EVACUATED | |
| 49124. |
What ratio of NaCN to HCN is needed to prepare a pH 9.40 buffer? (Ka of HCN is 4.9 × 10⁻¹⁰) |
| Answer» HCN (aq) + H2O (aq) ⇄ CN– (aq) + H3O+ (aq ); Ka = 4.9 x 10–10. 2 H2O (l) ... What percentage of a weak acid ORIGINALLY present ... PREPARE a buffer SOLUTION with pH = 4.10 with ... | |
| 49125. |
What do you understand about chromatography ? |
| Answer» CHROMATOGRAPHY is a laboratory TECHNIQUE for the separation of a MIXTURE. The mixture is dissolved in a fluid called the mobile phase, which carries it through a structure HOLDING another material called the stationary phase. The various constituents of the mixture travel at different speeds, causing them to SEPARATE. | |
| 49126. |
What are conjugate pairs . Explain with the help of example. |
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Answer» here is the answer============A conjugate acid-base pair contains TWO compounds that differ only by a hydrogen ion (H+) and a charge of +1HOCN MOLECULE, that is you can see it DONATE a proton to water. The reverse REACTION shows the basic nature of the OCN- ion; you can see it accept a proton from the hydronium ion.HOCN and OCN- are an example of a conjugate acid-base pair. The only difference between the two is a proton (H+).All acids have a conjugate base and all BASES have a conjugate acid.=========hope it is helpful |
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| 49127. |
Write iupac name of this structure |
| Answer» TION:your ANSWER is ..5ethynilenon1,7ene......HOPE this will HELP you | |
| 49128. |
1-Sodium Oxide+Carbon 2-Copper Oxide+Carbon 3-Aluminium Oxide+Carbon 4-Iron Oxide+Carbon 5-Lead Oxide+Carbon In which of these reactions is the metal reduced |
| Answer» 1. Sodium Carbonate2.Copper Oxide ( monooxide)3.AL2O3-AL4C34.Fe2O3+3CO5.PbO4th REACTION is an REDUCTION reaction so in the 4TH reaction metal is REDUCED | |
| 49129. |
What is the hybridisation of rhombic sulphur |
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Answer» s a SINGLE bond between each pair of S ATOMS and TWO non-bonding ELECTRON pairs on each S atom. Thus we see FOUR electron domains around each S atom and we would expect a tetrahedral geometry corresponding to sp3 hybridisation which gives us the bond angle around 1090. |
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| 49130. |
klvin is 21 year old and his sister is third is age . when kalvin is 36, what will be the age of his sister? |
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Answer» is 21 then his SISTER is 3 then when he is 36 his sister is 18 |
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| 49131. |
What number should come next ? 8, 4, 2,1, 1 /2, 1/4 |
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Answer» 1/8Explanation: |
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| 49132. |
What is the average speed of 12 15 23 22 (a)15 (b ) 16 (c ) 18 (d)20 |
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| 49133. |
Plz solve this quickly in this because u have to gave the state which state is each of the following |
| Answer» TION: HEY DEAR I WILL BE ONLY ANSWERING THE THIRD COLUMN.....GASLIQUIDSOLID LIQUIDSOLID SOLID GAS SOLID GAS....PLZ SUPPORT ... HOPE THI WILL HELP YOU | |
| 49134. |
Can tetra hydro furan be formed from furan?? acc to the rules aromatic compounds dont show addition reactions but show substitution reactions to maintain aromaticity, is there any possible way we can do addition reactions in aromatic compound as asked above?? |
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Answer» no it only GIVE ELECTROPHILIC SUBSTITUTION reactionExplanation: |
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| 49135. |
Explain.afbau's principal..! |
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Answer» the AUFBAU rule, STATES that in the ground state of an atom or ion, electrons fill atomic orbitals of the lowest available energy LEVELS before occupying HIGHER levels. For example, the 1s subshell is filled before the 2s subshell is occupied. In this way, the electrons of an atom or ion form the most stable electron configuration possible. An example is the configuration 1s2 2s2 2p6 3s2 3p3 for the phosphorus atom, MEANING that the 1s subshell has 2 electrons, and so on.HOPE IT HELPS ✌✌✌ |
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| 49136. |
If a reaction has a K = 0.00041, what does that tell you about how much reactant v. product there is at equilibrium? |
| Answer» SORRY i DONT KNOW the ANSWEREXPLANATION: | |
| 49137. |
Determine the configuration |
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Answer» Electronic configurations describe each electron as moving INDEPENDENTLY in an orbital, in an average field created by all other orbitals. Mathematically, configurations are described by SLATER determinants or configuration STATE FUNCTIONS |
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| 49138. |
make element table according atomic no.,atomic weight ,chemical name, chemical symbol(from 1 to 50 elements) |
| Answer» NOBLE gas because it's OCTATE is completely FILLED so it do HARDLY react with any other element | |
| 49140. |
Define hyper conjugation ? |
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Answer» Hyperconjugation is the STABILISING interaction that results from the interaction of the ELECTRONS in a σ-bond (usually C-H or C-C) with an ADJACENT empty or PARTIALLY filled p-orbital or a π-orbital to give an extended MOLECULAR orbital that increases the stability of the system. |
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| 49141. |
Q2 Carry out the following conversions: i) But-2-ene to 1-Bromobutane 2) Benzene to 1-Bromo-3-nitrobenzene 3) 1-Bromobenzene to p-Dibromobenzene |
| Answer» SORRY BRO I don't KNOW. | |
| 49142. |
How does petrol burn and formation of petrol particles |
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Answer» When combustion of CARBON is incomplete, i.e. there is a limited supply of air, only HALF as much OXYGEN adds to the carbon, and instead you form carbon monoxide (CO). Carbon monoxide is ALSO formed as a pollutant when hydrocarbon fuels (natural gas, petrol, diesel) are burned. |
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| 49143. |
step by step balance the equation barium chloride + aluminium sulphate = barium sulphate + aluminium chloride |
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Answer» 3BaCl2 + Al2(SO4)3 -> 3BaSO4 + 2AlCl3Explanation:balanced equation is BaCl2 + Al2(SO4)3 -> BaSO4 + AlCl3BaCl2 + Al2(SO4)3 -> 3BaSO4 + AlCl33BaCl2 + Al2(SO4)3 -> 3BaSO4 + AlCl33BaCl2 + Al2(SO4)3 -> 3BaSO4 + 2AlCl3the bolded ONE is the FULLY balanced equationHope it HELPS :)pls MARK it the brainliest |
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| 49144. |
What is copd 19 full explanation about the sensor and mark made as blender |
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Answer» covid 19 means corona 2019 YEAR this is a type of virus which get fluenced by in touch it's WEIGHT is HEAVIER than the AIR so it can't FLOAT on the air |
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| 49145. |
Volume of o, in likes required to prepare carbonblack from 50L of CH by incomplete combustion |
| Answer» CARBON black is produced with the thermal decomposition method or the PARTIAL combustion method using hydrocarbons such as oil or natural gas as raw material. The characteristics of carbon black vary depending on MANUFACTURING process, and therefore carbon black is classified by manufacturing process.Explanation: SORRY I haven't UNDERSTOOD the question.... but tried to answer u hope it may hint u something | |
| 49146. |
A metal crystallizes in fcc with cell edge equal to 4Å. If the structure changes to bcc with the cell edge remaining the same, the density becomes (a) .125 d (b) .25 d (c) .5 d (d) 2 d |
| Answer» B.................... | |
| 49147. |
Plz solve fastly and solve all parts of this question |
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Answer» a)................. |
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| 49148. |
How many structural isomers exist for C7H8O where each isomer contain a phenyl ring (with explanation). |
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Answer» 5Explanation: |
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| 49149. |
Difference between ozonolysis and halogenation ? CHEMISTRY |
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Answer» ozonolysis:Ozonolysis is an organic reaction where the UNSATURATED bonds of alkenes, alkynes, or azo COMPOUNDS are cleaved with ozone. Alkenes and alkynes form organic compounds in which the multiple carbon–carbon BOND has been replaced by a carbonyl group while azo compounds form nitrosaminesHalogination:Halogenation is a chemical reaction that involves the addition of one or more halogens to a compound or material. The pathway and stoichiometry of halogenation depends on the STRUCTURAL features and FUNCTIONAL groups of the organic substrate, as well as on the specific halogen. Explanation: |
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| 49150. |
The ratio of difference in the number of electrons between K and M shells Is 3:2 for X and Y elements respectively. 'X' possesses stable electronic configuration and M is the valence shell for both X and Y. Give the electronic configuration for X and Y. Will Mark as Brainliest if given the exact steps towards the configuration. |
| Answer» TION:hope you like it hope you understand if you have any query PLZ ask in comments or messesage me | |