332354 + Interview Questions in Secondary School in Math Page 10 InterviewSolution

451.	"Simplify (x - 2y )^3- (x + 2y )3"
Answer» Answer: (-12x²y-16y³) Step-by-step explanation: We know that; (a-b)³=a³-3a²b+3ab²-b³ Similarly,(a+b)³=a³+3a²b+3ab²+b³ So, (x-2y)³-(2+2y)³ =[x³-{3×x²×2y}+{3×x×(2y)²}-(2y)³] - [x³+{3×x²×2y}+{3×x×(2y)²}+(2y)³] =[x³-6x²y+12xy²-8y³]-[x³+6x²y+12xy²+8y³] =x³-6x²y+12xy²-8y³-x³-6x²y-12xy²-8y³ = -12x²y-16y³ (ANS) I hope my answer is HELPFUL for you.....

451.

"Simplify (x - 2y )^3- (x + 2y )3"

Answer»

Answer:

(-12x²y-16y³)

Step-by-step explanation:

We know that;

(a-b)³=a³-3a²b+3ab²-b³

Similarly,(a+b)³=a³+3a²b+3ab²+b³

So,

(x-2y)³-(2+2y)³

=[x³-{3×x²×2y}+{3×x×(2y)²}-(2y)³] - [x³+{3×x²×2y}+{3×x×(2y)²}+(2y)³]

=[x³-6x²y+12xy²-8y³]-[x³+6x²y+12xy²+8y³]

=x³-6x²y+12xy²-8y³-x³-6x²y-12xy²-8y³

= -12x²y-16y³

(ANS)

I hope my answer is HELPFUL for you.....

Discussion

452.	The sum of three consecutive terms is 15 and their product is 45
Answer» Step-by-step explanation: the AP can be written as (a-d), a ,(a+d). we can write like this because the terms still have a difference of d. their SUM is 15, therefore (a-d)+a+(a+d) = 15 3a = 15 a = 5. now their product is 45. therefore (5-d)(5)(5+d) = 45 (5) [(5-d)(5+d)] = 45 5 × [25-d²]= 45 25-d² = 9 d²= 25-9 d = +or- 4 therefore the ap when d is +4 is (5-4),(5),(5+4). i.e 1, 5, 9 the ap when d = -4 is [5-(-4)] , 5, [5+(-4)] i.e 9, 5, 1.

452.

The sum of three consecutive terms is 15 and their product is 45

Answer»

Step-by-step explanation:

the AP can be written as (a-d), a ,(a+d). we can write like this because the terms still have a difference of d.

their SUM is 15, therefore (a-d)+a+(a+d) = 15

3a = 15

a = 5.

now their product is 45. therefore

(5-d)(5)(5+d) = 45

(5) [(5-d)(5+d)] = 45

5 × [25-d²]= 45

25-d² = 9

d²= 25-9

d = +or- 4

therefore the ap when d is +4 is (5-4),(5),(5+4). i.e 1, 5, 9

the ap when d = -4 is [5-(-4)] , 5, [5+(-4)]

i.e 9, 5, 1.

Discussion

453.	HELP!!! if the preimage of the upper right vertex of a rectangle has the coordinates (30, -27) then what would the coordinates of the image be using a scale factor of 2/3 centered at the origin? HELP!!!!!!!
Answer» Step-by-step EXPLANATION: jdhdhdjksjdbdjbdbxbx

453.

HELP!!! if the preimage of the upper right vertex of a rectangle has the coordinates (30, -27) then what would the coordinates of the image be using a scale factor of 2/3 centered at the origin? HELP!!!!!!!

Answer»

Step-by-step EXPLANATION:

jdhdhdjksjdbdjbdbxbx

Discussion

454.	Draw the graph of equation y-2x= 4 and answer the following.(i). does the point (2, 8) lie on the line? Is (2, 8) a solution of the equation? Check by substituting(2, 8) in the equation.(ii). Does the point (4, 2) lie on the line? Is (4, 2) a solution of the equation? Check it?
Answer» Answer: 1.for making the TEXT look coloured refer the below syntax and ignore the dots [.tex]\RED{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look BOLD [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\SQRT{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{thanx}} thanx follow me next

454.

Draw the graph of equation y-2x= 4 and answer the following.(i). does the point (2, 8) lie on the line? Is (2, 8) a solution of the equation? Check by substituting(2, 8) in the equation.(ii). Does the point (4, 2) lie on the line? Is (4, 2) a solution of the equation? Check it?

Answer»

Answer:

1.for making the TEXT look coloured refer the below syntax and ignore the dots

[.tex]\RED{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look BOLD

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\SQRT{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me next

Discussion

455.	In a group of students 100 students knownhindi 50 know english and 33 know both. how many students are there is a group?
Answer» Answer: 100 Step-by-step EXPLANATION:

455.

In a group of students 100 students knownhindi 50 know english and 33 know both. how many students are there is a group?

Answer»

Answer:

100

Step-by-step EXPLANATION:

Discussion

456.	12 17 21 ? 10 68 4 52 3
Answer» Answer: 1.for making the text look coloured refer the below syntax and ignore the dots [.tex]\RED{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the EXPONENTIAL VALUE [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\SQRT{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\BOXED{thanx}} thanx follow me next

456.

12 17 21 ? 10 68 4 52 3

Answer»

Answer:

1.for making the text look coloured refer the below syntax and ignore the dots

[.tex]\RED{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the EXPONENTIAL VALUE

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\SQRT{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\BOXED{thanx}}

thanx

follow me next

Discussion

457.	Simplify 3/7 + 5/7 + (- 3)/7 + (- 5)/7 .
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ Question: $\sf {Simplify,\:\dfrac{3}{7} + \dfrac{5}{7} + \dfrac{-3}{7} + \dfrac{-5}{7} } \\\\$ To FIND the sum of three or more rational numbers, we may arrange them in any ORDER we like. The arrangement does not ALTER the sum. Explanation: FIRST Method: $\sf {\dfrac{3}{7} + \dfrac{5}{7} + \dfrac{-3}{7} + \dfrac{-5}{7} } \\\\$ $\longrightarrow \sf {\bigg(\dfrac{3}{7} + \dfrac{-3}{7}\bigg) + \bigg(\dfrac{5}{7} + \dfrac{-5}{7}\bigg) }\\\\$ $\longrightarrow \sf {0 + 0 = 0}\\\\$ Sum of a number and it's additive inverse is zero. Second Method: $\sf {\bigg(\dfrac{3}{7} + \dfrac{5}{7}\bigg) + \bigg(\dfrac{-3}{7} + \dfrac{-5}{7}\bigg) }\\\\$ $\longrightarrow \sf {\bigg(\dfrac{3 + 5}{7}\bigg) + \bigg(\dfrac{-3 + (-5)}{7}\bigg) }\\\\$ $\longrightarrow \sf {\dfrac{8}{7} + \bigg(\dfrac{-3 - 5}{7} \bigg) }\\\\$ $\longrightarrow \sf {\dfrac{8}{7} + \bigg(\dfrac{-8}{7} \bigg) = 0}$

457.

Simplify 3/7 + 5/7 + (- 3)/7 + (- 5)/7 .

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

Question:

$\sf {Simplify,\:\dfrac{3}{7} + \dfrac{5}{7} + \dfrac{-3}{7} + \dfrac{-5}{7} } \\\\$

To FIND the sum of three or more rational numbers, we may arrange them in any ORDER we like. The arrangement does not ALTER the sum.

Explanation:

FIRST Method:

$\sf {\dfrac{3}{7} + \dfrac{5}{7} + \dfrac{-3}{7} + \dfrac{-5}{7} } \\\\$

$\longrightarrow \sf {\bigg(\dfrac{3}{7} + \dfrac{-3}{7}\bigg) + \bigg(\dfrac{5}{7} + \dfrac{-5}{7}\bigg) }\\\\$

$\longrightarrow \sf {0 + 0 = 0}\\\\$

Sum of a number and it's additive inverse is zero.

Second Method:

$\sf {\bigg(\dfrac{3}{7} + \dfrac{5}{7}\bigg) + \bigg(\dfrac{-3}{7} + \dfrac{-5}{7}\bigg) }\\\\$

$\longrightarrow \sf {\bigg(\dfrac{3 + 5}{7}\bigg) + \bigg(\dfrac{-3 + (-5)}{7}\bigg) }\\\\$

$\longrightarrow \sf {\dfrac{8}{7} + \bigg(\dfrac{-3 - 5}{7} \bigg) }\\\\$

$\longrightarrow \sf {\dfrac{8}{7} + \bigg(\dfrac{-8}{7} \bigg) = 0}$

Discussion

458.	The value of a baseball player's rookie card began to increase once the player retired. When he retired in his card was worth $. The value has increased by $ each year since then. Express the relationship relating the value of the card y in dollars and the number of years x the player has been in retirement with an equation. Is the relationship between x and y proportional? What was the value of the card in ?
Answer» ANSWER: ....................................

458.

The value of a baseball player's rookie card began to increase once the player retired. When he retired in his card was worth $. The value has increased by $ each year since then. Express the relationship relating the value of the card y in dollars and the number of years x the player has been in retirement with an equation. Is the relationship between x and y proportional? What was the value of the card in ?

Answer»

ANSWER:

....................................

Discussion

459.	I need help with this proof for geometry.
Answer» ANSWER: OK Step-by-step EXPLANATION:

459.

I need help with this proof for geometry.

Answer»

ANSWER:

OK

Step-by-step EXPLANATION:

Discussion

460.	Mr Ranganathan had two gardens, onerectangular in shape and the other one inthe shape of a square. If the perimeter ofboth the gardens are same, find theirarea?
Answer» Answer: Perimeter of Square = 4 × side = 4 × 60 = 240 sq meters AREA of Square = Side² = 60 2 = 3600 square meters Perimeter of Rectangle = 2(length + breadth) Or, 240 =2 ( 80 + breadth ) Or, 80 + breadth = 120 Or, breadth = 120 − 80 = 40 meters Area of rectangle = length x breadth = 80 × 40 = 3200 square meters Now it is CLEAR that the area of the square field is greater than the area of the rectangular field.

460.

Mr Ranganathan had two gardens, onerectangular in shape and the other one inthe shape of a square. If the perimeter ofboth the gardens are same, find theirarea?

Answer»

Answer:

Perimeter of Square = 4 × side = 4 × 60 = 240 sq meters

AREA of Square = Side² = 60 2 = 3600 square meters

Perimeter of Rectangle = 2(length + breadth)

Or, 240 =2 ( 80 + breadth )

Or, 80 + breadth = 120

Or, breadth = 120 − 80 = 40 meters

Area of rectangle = length x breadth = 80 × 40 = 3200 square meters

Now it is CLEAR that the area of the square field is greater than the area of the rectangular field.

Discussion

461.	Find the sum of first 20 terms of the series 7 + 7.7 + 7.77 +....
Answer» ANSWER: a=7 d=7.7-7=0.7 an=? n=20 an=a+(n-1) d an=7+(20-1) 0.7 an=7+190.7 an=7+13.3 an=20.3 SUM=n/2(a+l) =20/2(7+20.3) =1027.3 =273 Hence the sum is 273

461.

Find the sum of first 20 terms of the series 7 + 7.7 + 7.77 +....

Answer»

ANSWER:

a=7

d=7.7-7=0.7

an=?

n=20

an=a+(n-1) d

an=7+(20-1) 0.7

an=7+19*0.7

an=7+13.3

an=20.3

SUM=n/2(a+l)

=20/2(7+20.3)

=10*27.3

=273

Hence the sum is 273

Discussion

462.	What number should be added to minus 3 by 5 to get 3 by 7
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ The REQUIRED NUMBER will be OBTAINED by SUBTRACTING -3/5 from 3/7. Therefore, $\sf {Required\: number \:shall\: be = \dfrac{3}{7} - \bigg(\dfrac{-3}{5} \bigg) } \\\\$ $\sf {Required\: number \:shall\: be = \dfrac{3}{7} + \dfrac{3}{5} } \\\\$ $\sf {Required\: number \:shall\: be = \dfrac{3 \times 5}{7 \times 5} + \dfrac{3 \times 7}{5 \times 7}} \\\\$ $\sf {Required\: number \:shall\: be = \dfrac{15}{35} + \dfrac{21}{35} } \\\\$ $\sf {Required\: number \:shall\: be = \dfrac{15 + 21}{35} } \\\\$ $\sf {Required\: number \:shall\: be = \dfrac{36}{35} }$

462.

What number should be added to minus 3 by 5 to get 3 by 7

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

The REQUIRED NUMBER will be OBTAINED by SUBTRACTING -3/5 from 3/7.

Therefore,

$\sf {Required\: number \:shall\: be = \dfrac{3}{7} - \bigg(\dfrac{-3}{5} \bigg) } \\\\$

$\sf {Required\: number \:shall\: be = \dfrac{3}{7} + \dfrac{3}{5} } \\\\$

$\sf {Required\: number \:shall\: be = \dfrac{3 \times 5}{7 \times 5} + \dfrac{3 \times 7}{5 \times 7}} \\\\$

$\sf {Required\: number \:shall\: be = \dfrac{15}{35} + \dfrac{21}{35} } \\\\$

$\sf {Required\: number \:shall\: be = \dfrac{15 + 21}{35} } \\\\$

$\sf {Required\: number \:shall\: be = \dfrac{36}{35} }$

Discussion

463.	Given the equation for y = (1/5) x p - 3 , what would the value of p be if y = 2.
Answer» <P>Step-by-step explanation: 2+3 =(1/5) ×p 5×5=p P=25 The VALUE of P is 25

463.

Given the equation for y = (1/5) x p - 3 , what would the value of p be if y = 2.

Answer»

<P>Step-by-step explanation:

2+3 =(1/5) ×p

5×5=p

P=25

The VALUE of P is 25

Discussion

464.	A table cost of length 2 m and breadth 1.2 m is decorated with lace of information width all around it find the area of the border if the lace is 12 cm wide
Answer» ANSWER: AREA of the BORDER where LACE is there = 2(length+breadth)×width of the lace =2(200+120)×12 cm =2(320)×12 =640×12 =7680cm =76.8m area of the border covered with lace is 76.8m

464.

A table cost of length 2 m and breadth 1.2 m is decorated with lace of information width all around it find the area of the border if the lace is 12 cm wide

Answer»

ANSWER:

AREA of the BORDER where LACE is there

= 2(length+breadth)×width of the lace

=2(200+120)×12 cm

=2(320)×12

=640×12

=7680cm

=76.8m

area of the border covered with lace is 76.8m

Discussion

465.	A car travles a distance of 145 milse in a time of 2.4 what is it average speed rounded to 1dp
Answer» ANSWER: SPEED = Distance/time HENCE, speed is 145/2.4= 6.86

465.

A car travles a distance of 145 milse in a time of 2.4 what is it average speed rounded to 1dp

Answer»

ANSWER:

SPEED = Distance/time

HENCE, speed is 145/2.4= 6.86

Discussion

466.	फर्स्ट एंड मल्टीप्लस ऑफ सेवंथ
Answer» Answer: OK Step-by-step EXPLANATION: pls WRITE in math ok then I will

466.

फर्स्ट एंड मल्टीप्लस ऑफ सेवंथ

Answer»

Answer:

OK

Step-by-step EXPLANATION:

pls WRITE in math ok then I will

Discussion

467.	The table shows the battery life of four different mobile phones.Mobile Phone Battery LifePhone Battery Life(hours)A 20B 25C 10D 18If 6.45% of the battery life of each mobile phone is used in a day by a typical user, for which mobile phone is 1.6125 hours of battery life used in a day? (5 points)aPhone AbPhone BcPhone CdPhone D
Answer» Step-by-step EXPLANATION: hshhdjjakNskbskslBs kkch ja BLOG HO JATA NA ggj

467.

The table shows the battery life of four different mobile phones.Mobile Phone Battery LifePhone Battery Life(hours)A 20B 25C 10D 18If 6.45% of the battery life of each mobile phone is used in a day by a typical user, for which mobile phone is 1.6125 hours of battery life used in a day? (5 points)aPhone AbPhone BcPhone CdPhone D

Answer»

Step-by-step EXPLANATION:

hshhdjjakNskbskslBs kkch ja BLOG HO JATA NA ggj

Discussion

468.	Find which is greater 3:4 or 4:5
Answer» Answer: 4:5 ...........................

468.

Find which is greater 3:4 or 4:5

Answer»

Answer:

4:5 ...........................

Discussion

469.	If 2+2=4 then what is 7x7=
Answer» Answer: 49 Step-by-step EXPLANATION: HOPE it HELPS ☺☺☺☺☺☺☺☺☺

469.

If 2+2=4 then what is 7x7=

Answer»

Answer:

49

Step-by-step EXPLANATION:

HOPE it HELPS ☺☺☺☺☺☺☺☺☺

Discussion

470.	at what rate percent per annum will ₹50,000 amount to ₹86,400 in 3 years,if the interest is compounded annually?
Answer» $\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$ Required answer:- The required Rate of interest is 20%. GIVEN Information:- The given Principal is Rs.50000. The given Amount is Rs.86400. The given Time is 3 years. Need to find out:- The required rate of interest = ? Required EXPLANATION:- Let the "Rate of Interest" be "R". Formula used here:- A = P(1 + R/100)ⁿ Putting the VALUES according to the given formula:- => 86400 = 50000(1 + R/100)³ => 86400/50000 = (1 + R/100)³ => 864/500 = (1 + R/100)³ => 216/125 = (1 + R/100)³ => ³√216/125 = 1 + R/100 => 6/5 = 1 + R/100 => 6/5 - 1 = R/100 => 6 - 5/5 = R/100 => 1/5 = R/100 => 100 = 5R => Rate of Interest = 100/5 => Rate of Interest = 20% Hence:- The required Rate of interest = 20% _____________________ More Information:- In Formula, A is used for Amount. P is used for Principal. R is used for Rate of interest. N is used for Time. _____________________

470.

at what rate percent per annum will ₹50,000 amount to ₹86,400 in 3 years,if the interest is compounded annually?

Answer»

$\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$

Required answer:-

The required Rate of interest is 20%.

GIVEN Information:-

The given Principal is Rs.50000.

The given Amount is Rs.86400.

The given Time is 3 years.

Need to find out:-

The required rate of interest = ?

Required EXPLANATION:-

Let the "Rate of Interest" be "R".

Formula used here:-

A = P(1 + R/100)ⁿ

Putting the VALUES according to the given formula:-

=> 86400 = 50000(1 + R/100)³

=> 86400/50000 = (1 + R/100)³

=> 864/500 = (1 + R/100)³

=> 216/125 = (1 + R/100)³

=> ³√216/125 = 1 + R/100

=> 6/5 = 1 + R/100

=> 6/5 - 1 = R/100

=> 6 - 5/5 = R/100

=> 1/5 = R/100

=> 100 = 5R

=> Rate of Interest = 100/5

=> Rate of Interest = 20%

Hence:-

The required Rate of interest = 20%

_____________________

More Information:-

In Formula,

A is used for Amount.

P is used for Principal.

R is used for Rate of interest.

N is used for Time.

_____________________

Discussion

471.	Jason left a bin outside in his garden to collect rainwater. He notices that 1 over 5 gallons of water fills 2 over 3 of the bin. Write and solve an equation to find the amount of water that will fill the entire bin.
Answer» Answer: According to GANDHI, education is the REALIZATION of the best in man - body, soul and spirit. He MAINTAINED that education must be BASED on ethics and morality. Ethics and morality are integral to Gandhi's life. All his thoughts, ACTIONS and speeches are based on these two concepts.

471.

Jason left a bin outside in his garden to collect rainwater. He notices that 1 over 5 gallons of water fills 2 over 3 of the bin. Write and solve an equation to find the amount of water that will fill the entire bin.

Answer»

Answer:

According to GANDHI, education is the REALIZATION of the best in man - body, soul and spirit. He MAINTAINED that education must be BASED on ethics and morality. Ethics and morality are integral to Gandhi's life. All his thoughts, ACTIONS and speeches are based on these two concepts.

Discussion

472.	If A is any square matrix, then which of the following is skew-symmetric?a) A + ATb) A – ATc) AATd) ATA
Answer» ANSWER: D Step-by-step EXPLANATION:

472.

If A is any square matrix, then which of the following is skew-symmetric?a) A + ATb) A – ATc) AATd) ATA

Answer»

ANSWER:

D

Step-by-step EXPLANATION:

Discussion

473.	Pls help with the 3rd one
Answer» ANSWER: Step-by-step explanation: COS(π/4 - x)Cos(π/4 - y) - Sin(π/4 - x)Sin(π/4 - y) //We KNOW that CosACosB - SinASinB = Cos(A+B) => Cos(π/4 - x + π/4 - y) => Cos(2π/4 - (x+y)) => Cos(π/2 - (x+y)) => Sin(x+y) (∵ Cos(90-θ) = Sinθ)

473.

Pls help with the 3rd one

Answer»

ANSWER:

Step-by-step explanation:

COS(π/4 - x)Cos(π/4 - y) - Sin(π/4 - x)Sin(π/4 - y)

//We KNOW that CosACosB - SinASinB = Cos(A+B)

=> Cos(π/4 - x + π/4 - y)

=> Cos(2π/4 - (x+y))

=> Cos(π/2 - (x+y))

=> Sin(x+y) (∵ Cos(90-θ) = Sinθ)

Discussion

474.	Last homework question then I would get 100% on it.Write down in terms of n, an expression for the nth term of the following sequences:a) 12 10 8 6 4b) 25 20 15 10 5
Answer» Answer: a. 14 - 2n b. 30 - 5n Step-by-step explanation: Formula: tn = T1 + (n - 1) d a. 12 + (n - 1) -2 = 12 + (-2n) + 2 = 14 - 2n b. 25 + (n - 1) -5 = 25 + (-5n) + 5 = 30 - 5n Hope it HELPS!!

474.

Last homework question then I would get 100% on it.Write down in terms of n, an expression for the nth term of the following sequences:a) 12 10 8 6 4b) 25 20 15 10 5

Answer»

Answer:

a. 14 - 2n

b. 30 - 5n

Step-by-step explanation:

Formula: tn = T1 + (n - 1) d

a. 12 + (n - 1) -2

= 12 + (-2n) + 2

= 14 - 2n

b. 25 + (n - 1) -5

= 25 + (-5n) + 5

= 30 - 5n

Hope it HELPS!!

Discussion

475.	Write decimal expanaion of 15/8 pls
Answer» $\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$ $\huge\bf\frac{15}{8}$ =1.875

475.

Write decimal expanaion of 15/8 pls

Answer»

$\huge\boxed{\fcolorbox{purple}{ink}{Answer}}$

$\huge\bf\frac{15}{8}$ =1.875

Discussion

476.	बरवर्षेक. १२ वर्षे(विअ.42.12ब 40.14क.30.24१२११.२२१२५ असेट/नेट मार्गदर्शक अनिवार्य पेपर-१309कोणताही बुद्धीमान माणूस मृत्युला घाबरत नाही. काही वृद्धीमान मात्युअदिलचे बब सुनीताच्या वयाच्या दुप्पट आहे. तीन वर्षापूर्वी त्याचे वय मुलीलाच्यामुलगा आणि वडील यांच्या आर्युमानाचे मध्य/सरासरी 27 वर्ष आहे. 18 वर्षानमुलाच्या दुप्पट होईल तर त्यांची आजचे वये काढा?होले अनिलचे सध्याचे वय किती?
Answer» ANSWER: COULD you PLEASE EXPLAIN it in ENGLISH?

476.

बरवर्षेक. १२ वर्षे(विअ.42.12ब 40.14क.30.24१२११.२२१२५ असेट/नेट मार्गदर्शक अनिवार्य पेपर-१309कोणताही बुद्धीमान माणूस मृत्युला घाबरत नाही. काही वृद्धीमान मात्युअदिलचे बब सुनीताच्या वयाच्या दुप्पट आहे. तीन वर्षापूर्वी त्याचे वय मुलीलाच्यामुलगा आणि वडील यांच्या आर्युमानाचे मध्य/सरासरी 27 वर्ष आहे. 18 वर्षानमुलाच्या दुप्पट होईल तर त्यांची आजचे वये काढा?होले अनिलचे सध्याचे वय किती?

Answer»

ANSWER:

COULD you PLEASE EXPLAIN it in ENGLISH?

Discussion

477.	(vii) A bi-quadratic equation has degree(a)1(b) 2.(c)3(d) 4
Answer» (d) 4 is the answer Step-by-step explanation: HIT the MARK as BRAINLIEST BUTTON below and follow me for more accurate answers .

477.

(vii) A bi-quadratic equation has degree(a)1(b) 2.(c)3(d) 4

Answer»

(d) 4 is the answer

Step-by-step explanation:

HIT the MARK as BRAINLIEST BUTTON below and follow me for more accurate answers .

Discussion

478.	If A+A=BB+B=DA+D=EThen B+D+E=?
Answer» $\huge{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{<klux>E</klux>}\pink{R}}}}$ K The LETTERS represent their position in the alphabet. A=1, B=2, C=3 ... And so on Now 1+1=2 (B), 2+2=4 (D), 1+4=5 (E). So, 2+4+5=11 (K)

478.

If A+A=BB+B=DA+D=EThen B+D+E=?

Answer»

$\huge{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{<klux>E</klux>}\pink{R}}}}$

K

The LETTERS represent their position in the alphabet.

A=1, B=2, C=3 ... And so on

Now

1+1=2 (B),

2+2=4 (D),

1+4=5 (E).

So,

2+4+5=11 (K)

Discussion

479.	-2(x+3)=8;x=________
Answer» ANSWER: -7 Step-by-step EXPLANATION: -2X-6=8 -2x= 8+6=14 x= -14/2= -7

479.

-2(x+3)=8;x=________

Answer»

ANSWER:

-7

Step-by-step EXPLANATION:

-2X-6=8

-2x= 8+6=14

x= -14/2= -7

Discussion

480.	(vii) A bi-quadratic equation has degree(c)3(d) 4(a)1(b) 2cy2x - 2) is
Answer» BI QUADRATIC EQUATION has DEGREE 3

Discussion

481.	What is the length of the hypotenuse?
Answer» Step-by-step EXPLANATION: Hypotenuse^2 = 5^2 + 12^2 = 25 + 144 = 169 = √169 = 13 Hope it HELPS ☺☺

481.

What is the length of the hypotenuse?

Answer»

Step-by-step EXPLANATION:

Hypotenuse^2 = 5^2 + 12^2

= 25 + 144

= 169

= √169

= 13

Hope it HELPS ☺☺

Discussion

482.	मुलाचे हनीबर्ड लांचे आयुर्माना के मध्य और सरासर 27 वर्ष से 18 वर्ष तक बड़ी लाइन से मुलाकात हुई
Answer» ANSWER: iicichxuxhxuxucuchcjcicifif

482.

मुलाचे हनीबर्ड लांचे आयुर्माना के मध्य और सरासर 27 वर्ष से 18 वर्ष तक बड़ी लाइन से मुलाकात हुई

Answer»

ANSWER:

iicichxuxhxuxucuchcjcicifif

Discussion

483.	The unique representation of rotation number is
Answer» Answer: A RATIONAL number is a number that can be represented as a FRACTION m/N, where m and n are integers and n≠0 Step-by-step explanation: I think this is HELPFUL for you...

483.

The unique representation of rotation number is

Answer»

Answer:

A RATIONAL number is a number that can be represented as a FRACTION m/N, where m and n are integers and n≠0

Step-by-step explanation:

I think this is HELPFUL for you...

Discussion

484.	Find the value of discriminantx²+7x-1=0
Answer» x²+7x-1=0 Here, a=1, b=7, c=-1 Discriminant (∆) = b²-4ac ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= (7)²-4×1×(-1) ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 49+4 ⠀⠀⠀⠀⠀⠀⠀⠀⠀∆=53 $\therefore$ ∆=53

484.

Find the value of discriminantx²+7x-1=0

Answer»

x²+7x-1=0

Here,

a=1, b=7, c=-1

Discriminant (∆) = b²-4ac

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= (7)²-4×1×(-1)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 49+4

⠀⠀⠀⠀⠀⠀⠀⠀⠀∆=53

$\therefore$ ∆=53

Discussion

485.	Population of Kerala in conclusion
Answer» ANSWER: SEE it in worldo METER CURRENT POPULATIO

485.

Population of Kerala in conclusion

Answer»

ANSWER:

SEE it in worldo METER CURRENT POPULATIO

Discussion

486.	Tony bought 3 tickets to a concert for $78. How much will it cost for 6 tickets to the concert if all tickets have the same unit price? Use the table below to help determine the missing value: a $136 b $156 c $146 d $234
Answer» ANSWER: I am REALLY SORRY I don't KNOW

486.

Tony bought 3 tickets to a concert for $78. How much will it cost for 6 tickets to the concert if all tickets have the same unit price? Use the table below to help determine the missing value: a $136 b $156 c $146 d $234

Answer»

ANSWER:

I am REALLY SORRY I don't KNOW

Discussion

487.	Add the following2+1/5 +3+2/7
Answer» ANSWER: 3/8/9 here is your answer Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIST answer please

487.

Add the following2+1/5 +3+2/7

Answer»

ANSWER:

3/8/9 here is your answer

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIST answer please

Discussion

488.	Y=2x+4Complete the missing value in the solution to the equation.( ,2)
Answer» ANSWER: HOPE UNDERSTAND BETTER

488.

Y=2x+4Complete the missing value in the solution to the equation.( ,2)

Answer»

ANSWER:

HOPE UNDERSTAND BETTER

Discussion

489.	11) If A is a square matrix, then A – A’ is aa) diagonal matrixb) skew-symmetric matrixc) symmetric matrixd) none of these
Answer» ANSWER: If A is any SQUARE MATRIX then (A−A′) is ALWAYS skew-symmetric

489.

11) If A is a square matrix, then A – A’ is aa) diagonal matrixb) skew-symmetric matrixc) symmetric matrixd) none of these

Answer»

ANSWER:

If A is any SQUARE MATRIX then (A−A′) is ALWAYS skew-symmetric

Discussion

490.	Help me, 3.039/9.8 = ?I need an idea to solve via pen and paper, I know how to use calculator. Pls help guys... Hoping for help
Answer» Answer: 0.310 Step-by-step EXPLANATION: (3039/1000)/(98/10)

490.

Help me, 3.039/9.8 = ?I need an idea to solve via pen and paper, I know how to use calculator. Pls help guys... Hoping for help

Answer»

Answer:

0.310

Step-by-step EXPLANATION:

(3039/1000)/(98/10)

Discussion

491.	Maths - Find the percentage and the ratio of the forest land (area occupied by sanctuaries)out of total land in the Odisha.
Answer» Answer: 1.for making the TEXT look coloured refer the below syntax and ignore the dots [.tex]\red{the\:text\:appears\:in\:red}[./tex] RESULT \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text MARQUEE [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square ROOT value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{thanx}} thanx follow me next

491.

Maths - Find the percentage and the ratio of the forest land (area occupied by sanctuaries)out of total land in the Odisha.

Answer»

Answer:

1.for making the TEXT look coloured refer the below syntax and ignore the dots

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

RESULT

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text MARQUEE

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square ROOT value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me next

Discussion

492.	प्रशन 1 लंबी विभाजन विधि का प्रयोग केबिना बताइए कि 395/10500 कादशमलव प्रसार सांत है या असांत आवर्ती
Answer» ANSWER: एफ डी एस सी हो रहा हो वो बोली क्या बात हुई कि वह अपनी पत्नी मान्यता Step-by-step EXPLANATION: ग में ही रह गए लोग ही थे और आज तक दे रहे हो कि एक दिन एक औरत को एक औरत अपने को धन्य हैं और न कोई नहीं सकता त है एक बार ही थे

492.

प्रशन 1 लंबी विभाजन विधि का प्रयोग केबिना बताइए कि 395/10500 कादशमलव प्रसार सांत है या असांत आवर्ती

Answer»

ANSWER:

एफ डी एस सी हो रहा हो वो बोली क्या बात हुई कि वह अपनी पत्नी मान्यता

Step-by-step EXPLANATION:

ग में ही रह गए लोग ही थे और आज तक दे रहे हो कि एक दिन एक औरत को एक औरत अपने को धन्य हैं और न कोई नहीं सकता त है एक बार ही थे

Discussion

493.	If it takes 3 people take 10 days to pick the plums from a tree how many days will it take 10 people to do the same
Answer» Answer: 3 days Step-by-step EXPLANATION: x/10=3/10 x=3/10*10 x=3days

493.

If it takes 3 people take 10 days to pick the plums from a tree how many days will it take 10 people to do the same

Answer»

Answer:

3 days

Step-by-step EXPLANATION:

x/10=3/10

x=3/10*10

x=3days

Discussion

494.	He number of pages that Armando, Billy, Robert, and Joel can read in a day is shown below.Armando read 15% of his 46-page book.Billy read 11% of his 72-page book.Robert read 12% of his 68-page book.Joel read 14% of his 69-page book.Who can read the greatest number of pages in a day? (5 points)aArmandobJoelcBillydRobert
Answer» ANSWER: b Step-by-step EXPLANATION:

494.

He number of pages that Armando, Billy, Robert, and Joel can read in a day is shown below.Armando read 15% of his 46-page book.Billy read 11% of his 72-page book.Robert read 12% of his 68-page book.Joel read 14% of his 69-page book.Who can read the greatest number of pages in a day? (5 points)aArmandobJoelcBillydRobert

Answer»

ANSWER:

b

Step-by-step EXPLANATION:

Discussion

495.	Matchinga- carbon - 1b- sodium - 4c- best conductor - carbond- bond energy - silvere- CH3-OH - toxic
Answer» ANSWER: a- carbon - 1 b- sodium - 4 c- best conductor - carbon d- BOND ENERGY - silver e- CH3-OH - toxic

495.

Matchinga- carbon - 1b- sodium - 4c- best conductor - carbond- bond energy - silvere- CH3-OH - toxic

Answer»

ANSWER:

a- carbon - 1

b- sodium - 4

c- best conductor - carbon

d- BOND ENERGY - silver

e- CH3-OH - toxic

Discussion

496.	The slope of a hill is 45º. What is the angle, one has to enter the hill,such as one's climbing angle is only 26.57°?
Answer» Answer: 53 ° Step-by-step EXPLANATION:

496.

The slope of a hill is 45º. What is the angle, one has to enter the hill,such as one's climbing angle is only 26.57°?

Answer»

Answer:

53 °

Step-by-step EXPLANATION:

Discussion

497.	C) Determine the support reaction of the beamloaded and supported as shown in Fig. 9.(5 Marks)20 KN10 KN34 kNmАсB7771 m1.2 m1.2 m77777771 m+*
Answer» Answer: 1.for making the text look coloured REFER the below SYNTAX and ignore the dots [.TEX]\red{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential VALUE [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{thanx}} thanx follow me next

497.

C) Determine the support reaction of the beamloaded and supported as shown in Fig. 9.(5 Marks)20 KN10 KN34 kNmАсB7771 m1.2 m1.2 m77777771 m+*

Answer»

Answer:

1.for making the text look coloured REFER the below SYNTAX and ignore the dots

[.TEX]\red{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential VALUE

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me next

Discussion

498.	(ii) Evaluate (99)3 using identities.
Answer» Step-by-step EXPLANATION: HOPE it's helpful. please FOLLOW me and MARK me as a BRAINLIEST.

498.

(ii) Evaluate (99)3 using identities.

Answer»

Step-by-step EXPLANATION:

HOPE it's helpful.

please FOLLOW me and MARK me as a BRAINLIEST.

Discussion

499.	9 inches of ribbons are neededfor wrapping each present. How many presents can be wrapped with 6 yards of ribbon?
Answer» Answer: 18 Step-by-step explanation: 6 yards. One YARD is 3 inches, 6x3 is 18, DIVIDED by 9 is 2

499.

9 inches of ribbons are neededfor wrapping each present. How many presents can be wrapped with 6 yards of ribbon?

Answer»

Answer:

18

Step-by-step explanation:

6 yards. One YARD is 3 inches, 6x3 is 18, DIVIDED by 9 is 2

Discussion

500.	The top of the tower of the Olympic Stadium is 72 metres from the see level. Howfar in the sea is the horizon assuming the globe to be a sphere whose radius is6378 km? How far is the horizon assuming the errors in the measures: 72 mt 2 mand 6378 km + 0.2 %?
Answer» ANSWER:(R + h)2= R2 + OG2 or OG2 = (R + h)2 − R2 . But if we expand the TERM (R + h)2 = R2 + 2 R h + h2, the R2 terms cancel, and we find OG = SQRT ( 2 R h + h2 ) . It's customary to use the fact that h << R at this point, so that we can neglect the second term. Then OG ≈ sqrt ( 2 R h ) is the distance to the horizon, neglecting refraction. Step-by-step explanation:

500.

The top of the tower of the Olympic Stadium is 72 metres from the see level. Howfar in the sea is the horizon assuming the globe to be a sphere whose radius is6378 km? How far is the horizon assuming the errors in the measures: 72 mt 2 mand 6378 km + 0.2 %?

Answer»

ANSWER:(R + h)2= R2 + OG2

or

OG2 = (R + h)2 − R2 .

But if we expand the TERM (R + h)2 = R2 + 2 R h + h2, the R2 terms cancel, and we find

OG = SQRT ( 2 R h + h2 ) .

It's customary to use the fact that h << R at this point, so that we can neglect the second term. Then

OG ≈ sqrt ( 2 R h )

is the distance to the horizon, neglecting refraction.

Step-by-step explanation:

Discussion

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Help me, 3.039/9.8 = ?I need an idea to solve via pen and paper, I know how to use calculator. Pls help guys... Hoping for help

Maths - Find the percentage and the ratio of the forest land (area occupied by sanctuaries)out of total land in the Odisha.​

प्रशन 1 लंबी विभाजन विधि का प्रयोग केबिना बताइए कि 395/10500 कादशमलव प्रसार सांत है या असांत आवर्ती​

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(ii) Evaluate (99)3 using identities.​

9 inches of ribbons are neededfor wrapping each present. How many presents can be wrapped with 6 yards of ribbon?

The top of the tower of the Olympic Stadium is 72 metres from the see level. Howfar in the sea is the horizon assuming the globe to be a sphere whose radius is6378 km? How far is the horizon assuming the errors in the measures: 72 mt 2 mand 6378 km + 0.2 %?​

"Simplify (x - 2y )^3- (x + 2y )3"

The sum of three consecutive terms is 15 and their product is 45

Draw the graph of equation y-2x= 4 and answer the following.(i). does the point (2, 8) lie on the line? Is (2, 8) a solution of the equation? Check by substituting(2, 8) in the equation.(ii). Does the point (4, 2) lie on the line? Is (4, 2) a solution of the equation? Check it?

In a group of students 100 students knownhindi 50 know english and 33 know both. how many students are there is a group?

12 17 21 ? 10 68 4 52 3

Simplify 3/7 + 5/7 + (- 3)/7 + (- 5)/7 .

Mr Ranganathan had two gardens, onerectangular in shape and the other one inthe shape of a square. If the perimeter ofboth the gardens are same, find theirarea?

What number should be added to minus 3 by 5 to get 3 by 7

A table cost of length 2 m and breadth 1.2 m is decorated with lace of information width all around it find the area of the border if the lace is 12 cm wide

फर्स्ट एंड मल्टीप्लस ऑफ सेवंथ

at what rate percent per annum will ₹50,000 amount to ₹86,400 in 3 years,if the interest is compounded annually?

If A is any square matrix, then which of the following is skew-symmetric?a) A + ATb) A – ATc) AATd) ATA

Write decimal expanaion of 15/8 pls

(vii) A bi-quadratic equation has degree(a)1(b) 2.(c)3(d) 4

If A+A=BB+B=DA+D=EThen B+D+E=?

-2(x+3)=8;x=________

(vii) A bi-quadratic equation has degree(c)3(d) 4(a)1(b) 2cy2x - 2) is

मुलाचे हनीबर्ड लांचे आयुर्माना के मध्य और सरासर 27 वर्ष से 18 वर्ष तक बड़ी लाइन से मुलाकात हुई

The unique representation of rotation number is

Find the value of discriminantx²+7x-1=0

Population of Kerala in conclusion

Add the following2+1/5 +3+2/7

11) If A is a square matrix, then A – A’ is aa) diagonal matrixb) skew-symmetric matrixc) symmetric matrixd) none of these

Maths - Find the percentage and the ratio of the forest land (area occupied by sanctuaries)out of total land in the Odisha.

प्रशन 1 लंबी विभाजन विधि का प्रयोग केबिना बताइए कि 395/10500 कादशमलव प्रसार सांत है या असांत आवर्ती

Matchinga- carbon - 1b- sodium - 4c- best conductor - carbond- bond energy - silvere- CH3-OH - toxic

The slope of a hill is 45º. What is the angle, one has to enter the hill,such as one's climbing angle is only 26.57°?

C) Determine the support reaction of the beamloaded and supported as shown in Fig. 9.(5 Marks)20 KN10 KN34 kNmАсB7771 m1.2 m1.2 m77777771 m+*

(ii) Evaluate (99)3 using identities.

The top of the tower of the Olympic Stadium is 72 metres from the see level. Howfar in the sea is the horizon assuming the globe to be a sphere whose radius is6378 km? How far is the horizon assuming the errors in the measures: 72 mt 2 mand 6378 km + 0.2 %?