332354 + Interview Questions in Secondary School in Math Page 102 InterviewSolution

5051.	If d is the number of degree and G is the number of grades of the same angle prove that D/9=G/10
Answer» Step-by-step explanation: The angle be C RADIAN, D degreesor G grades As π radian is EQUAL to 180 ∘ and 200 g D degrees is D 180 × π radians i.e. C = D 180 × π or D π = 180 C and similarly G grade is G 200 × π radians i.e. C = G 200 × π or G π = 200 C Hence ( G − D ) π = 20 C

5051.

If d is the number of degree and G is the number of grades of the same angle prove that D/9=G/10

Answer»

Step-by-step explanation:

The angle be

C

RADIAN,

D

degreesor

G

grades

As

π

radian is EQUAL to

180

∘

and

200

g

D

degrees is

D

180

×

π

radians i.e.

C

=

D

180

×

π

or

D

π

=

180

C

and similarly

G

grade is

G

200

×

π

radians i.e.

C

=

G

200

×

π

or

G

π

=

200

C

Hence

(

G

−

D

)

π

=

20

C

Discussion

5052.	) sin2A - sin2B - sin2C = -4sinA cosB cosC if a+b+c=π
Answer» ANSWER: HOPES it HELPS you PLZ COMMENT

5052.

) sin2A - sin2B - sin2C = -4sinA cosB cosC if a+b+c=π

Answer»

ANSWER:

HOPES it HELPS you PLZ COMMENT

Discussion

5053.	3z+7by 9=2by8 please answer it fast
Answer» ANSWER : (2z−7)−3(3z+8)=4z−9 (2z−7)−(9z+24)=4z−9 (2z−7)−9z−24=4z−9 2z−7−9z−24=4z−9 2z−9z−4z=−9+7+24 2z−9z−4z=−2+24 −11z=22 z= 11 22 z=−2 To CHECK this Putz=−2 (2(−2)−7)−3(3(−2)+8)=4(−2)+−9 (−4−7)−3(−6+8)=−8−9 −11−3(2)=−17 −17=−17

5053.

3z+7by 9=2by8 please answer it fast

Answer»

ANSWER :

(2z−7)−3(3z+8)=4z−9

(2z−7)−(9z+24)=4z−9

(2z−7)−9z−24=4z−9

2z−7−9z−24=4z−9

2z−9z−4z=−9+7+24

2z−9z−4z=−2+24

−11z=22

z=

11

22

z=−2

To CHECK this

Putz=−2

(2(−2)−7)−3(3(−2)+8)=4(−2)+−9

(−4−7)−3(−6+8)=−8−9

−11−3(2)=−17

−17=−17

Discussion

5054.	A sum of money amounts to Rs. 1500 after 3 years and Rs. 2000 after 5 years at the same rate of SI. Find the rate of interest per annum ?
Answer» $\large\underline{\sf{Given- }}$ $\sf{\rm :\longmapsto\: Amount,\: \: a_1 \:=Rs \: 1500}$ $\sf{\rm :\longmapsto\: Time,\: \: t_1 \:=3\: years}$ $\sf{\rm :\longmapsto\: Amount,\: \: a_2 \:=Rs \: 2000}$ $\sf{\rm :\longmapsto\: Time,\: \: t_2 \:=5\: years}$ Let assume that SUM of money invested be Rs P at the rate of r % per annum. We know, Simple interest (SI) on a certain sum of money of Rs P invested at the rate of r % per annum for n years is always same for every year and is given by $\boxed{ \rm{ SI = \frac{P \times r \times n}{100}}}$ and $\boxed{ \rm{ Amount = P + SI}}$ Now, ACCORDING to statement it is given that Amount on a certain sum of money is Rs 1500 after 3 years. Let assume that simple interest for 1 year on Rs P at the rate of r % per annum is SI. So, $\rm :\longmapsto\:Amount = 1500$ $\rm :\longmapsto\:P + 3SI = 1500 - - - (1)$ and Further it is given that Amount on certain sum of money is Rs 2000 after 5 years. So, $\rm :\longmapsto\:Amount = 2000$ $\rm :\longmapsto\:P + 5SI = 2000 - - - (2)$ On Subtracting equation (1) from equation (2), we get $\rm :\longmapsto\:2SI = 500$ $\bf\implies \:SI = Rs \: 250$ On SUBSTITUTING the value of SI in equation (1) we get $\rm :\longmapsto\:P + 3 \times 250 = 1500$ $\rm :\longmapsto\:P + 750 = 1500$ $\rm :\longmapsto\:P= 1500 - 750$ $\bf :\longmapsto\:P=Rs \: 750$ Now, we have Simple Interest for 1 year = Rs 250 Sum of money invested, P = Rs 750 Time, n = 1 year We know, $\boxed{ \rm{ SI = \frac{P \times r \times n}{100}}}$ On substituting the values, we get $\rm :\longmapsto\:250 = \dfrac{750 \times 1 \times r}{100}$ $\bf\implies \:r = \dfrac{100}{3} = 33\dfrac{1}{3} \%$ Additional Information :- 1. Amount on a certain sum of money of Rs P invested at the rate of r % per annum for n years compounded annually is $\boxed{ \rm{ Amount = P\bigg(1+\dfrac{r}{100}\bigg)^{n}}}$ 2. Amount on a certain sum of money of Rs P invested at the rate of r % per annum for n years compounded semi - annually is $\boxed{ \rm{ Amount = P\bigg(1+\dfrac{r}{200}\bigg)^{2n}}}$ 3. Amount on a certain sum of money of Rs P invested at the rate of r % per annum for n years compounded quarterly is $\boxed{ \rm{ Amount = P\bigg(1+\dfrac{r}{400}\bigg)^{4n}}}$

5054.

A sum of money amounts to Rs. 1500 after 3 years and Rs. 2000 after 5 years at the same rate of SI. Find the rate of interest per annum ?

Answer»

$\large\underline{\sf{Given- }}$

$\sf{\rm :\longmapsto\: Amount,\: \: a_1 \:=Rs \: 1500}$

$\sf{\rm :\longmapsto\: Time,\: \: t_1 \:=3\: years}$

$\sf{\rm :\longmapsto\: Amount,\: \: a_2 \:=Rs \: 2000}$

$\sf{\rm :\longmapsto\: Time,\: \: t_2 \:=5\: years}$

Let assume that SUM of money invested be Rs P at the rate of r % per annum.

We know,

Simple interest (SI) on a certain sum of money of Rs P invested at the rate of r % per annum for n years is always same for every year and is given by

$\boxed{ \rm{ SI = \frac{P \times r \times n}{100}}}$

and

$\boxed{ \rm{ Amount = P + SI}}$

Now,

ACCORDING to statement it is given that

Amount on a certain sum of money is Rs 1500 after 3 years.

Let assume that simple interest for 1 year on Rs P at the rate of r % per annum is SI.

So,

$\rm :\longmapsto\:Amount = 1500$

$\rm :\longmapsto\:P + 3SI = 1500 - - - (1)$

and

Further it is given that Amount on certain sum of money is Rs 2000 after 5 years.

So,

$\rm :\longmapsto\:Amount = 2000$

$\rm :\longmapsto\:P + 5SI = 2000 - - - (2)$

On Subtracting equation (1) from equation (2), we get

$\rm :\longmapsto\:2SI = 500$

$\bf\implies \:SI = Rs \: 250$

On SUBSTITUTING the value of SI in equation (1) we get

$\rm :\longmapsto\:P + 3 \times 250 = 1500$

$\rm :\longmapsto\:P + 750 = 1500$

$\rm :\longmapsto\:P= 1500 - 750$

$\bf :\longmapsto\:P=Rs \: 750$

Now, we have

Simple Interest for 1 year = Rs 250

Sum of money invested, P = Rs 750

Time, n = 1 year

We know,

$\boxed{ \rm{ SI = \frac{P \times r \times n}{100}}}$

On substituting the values, we get

$\rm :\longmapsto\:250 = \dfrac{750 \times 1 \times r}{100}$

$\bf\implies \:r = \dfrac{100}{3} = 33\dfrac{1}{3} \%$

Additional Information :-

1. Amount on a certain sum of money of Rs P invested at the rate of r % per annum for n years compounded annually is

$\boxed{ \rm{ Amount = P\bigg(1+\dfrac{r}{100}\bigg)^{n}}}$

2. Amount on a certain sum of money of Rs P invested at the rate of r % per annum for n years compounded semi - annually is

$\boxed{ \rm{ Amount = P\bigg(1+\dfrac{r}{200}\bigg)^{2n}}}$

3. Amount on a certain sum of money of Rs P invested at the rate of r % per annum for n years compounded quarterly is

$\boxed{ \rm{ Amount = P\bigg(1+\dfrac{r}{400}\bigg)^{4n}}}$

Discussion

5055.	Find the value of (5006)2/6
Answer» ANSWER: SORRY FRIEND I don't KNOW

5055.

Find the value of (5006)2/6

Answer»

ANSWER:

SORRY FRIEND I don't KNOW

Discussion

5056.	जल मिश्रित अल्कोहल में केवल 7 लीटर अल्कोहल है और शेष पानी है एक नया मिश्रण जिसकी सांद्रता 40 परसेंट है को अल्कोहल द्वारा प्रतिस्थापित करके बनाया है यदि मिश्रण में प्रारंभ में 28 लीटर पानी था तो कितने लीटर मिश्रण शुद्ध अल्कोहल से प्रतिस्थापित किया जाएगा
Answer» Step-by-step EXPLANATION: dndjdksksjsjsnnsnsnsndd

5056.

जल मिश्रित अल्कोहल में केवल 7 लीटर अल्कोहल है और शेष पानी है एक नया मिश्रण जिसकी सांद्रता 40 परसेंट है को अल्कोहल द्वारा प्रतिस्थापित करके बनाया है यदि मिश्रण में प्रारंभ में 28 लीटर पानी था तो कितने लीटर मिश्रण शुद्ध अल्कोहल से प्रतिस्थापित किया जाएगा

Answer»

Step-by-step EXPLANATION:

dndjdksksjsjsnnsnsnsndd

Discussion

5057.	Date 13 7 a² +b² +c² = 25 and ab + bc+ca =3 so a+b+c=?
Answer» ANSWER: bcbcbtnenfjrbfueioeicidi iriifi iiwikcrjfjbcej Step-by-step EXPLANATION: uhhfffjjfjfjz

5057.

Date 13 7 a² +b² +c² = 25 and ab + bc+ca =3 so a+b+c=?

Answer»

ANSWER:

bcbcbtnenfjrbfueioeicidi iriifi iiwikcrjfjbcej

Step-by-step EXPLANATION:

uhhfffjjfjfjz

Discussion

5058.	Find the value of x if ∟A 50 and ∟D 40
Answer» Answer: 2. उिरोक्त काव्यिंस्क्तयों में ियायवाची शब्दोँ का उियोग करके होनेवाले िद्वरवतसन के साि काव्य िंस्क्तयााँ द्वफर से द्वलद्वखए ।

5058.

Find the value of x if ∟A 50 and ∟D 40

Answer»

Answer:

2. उिरोक्त काव्यिंस्क्तयों में ियायवाची शब्दोँ का उियोग करके होनेवाले िद्वरवतसन के साि

काव्य िंस्क्तयााँ द्वफर से द्वलद्वखए ।

Discussion

5059.	There is no centre point
Answer» Step-by-step EXPLANATION: HOPE it HELPS you out. REFER to the ATTACHMENT.

5059.

There is no centre point

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS you out.

REFER to the ATTACHMENT.

Discussion

5060.	Four litres of Bru coffee can be poured in how many cups of capacity 25ml each
Answer» Answer: 160 Step-by-step EXPLANATION: TOTAL QUANTITY of bru coffee=4 litre =4000 ml capacity of cups= 25ml so, No of cups in which 4L of bru coffee can be poured = 4000 ml÷25 ml =160 So the answer in 160 cups

5060.

Four litres of Bru coffee can be poured in how many cups of capacity 25ml each

Answer»

Answer:

160

Step-by-step EXPLANATION:

TOTAL QUANTITY of bru coffee=4 litre

=4000 ml

capacity of cups= 25ml

so, No of cups in which 4L of bru coffee can be poured = 4000 ml÷25 ml

=160

So the answer in 160 cups

Discussion

5061.	(INTEGERS)Subtract a. -44 from 1440 b. -185 from -320
Answer» a) $1440 - ( - 44) = 1440 + 44 = 1484$ B) $- 320 - ( - 185) = - 320 + 185 = - 135$

5061.

(INTEGERS)Subtract a. -44 from 1440 b. -185 from -320

Answer»

a)

$1440 - ( - 44) = 1440 + 44 = 1484$

B)

$- 320 - ( - 185) = - 320 + 185 = - 135$

Discussion

5062.	Prove that:sec⁶A - tan⁶A = 1 + 3 tan²A + 3 tan⁴A
Answer» $\texttt{\textsf{\large{\underline{Solution}:}}}$ We have to prove: → sec⁶A - tan⁶A = 1 + 3 tan²A + 3 tan⁴A Taking LHS, we get: = sec⁶A - tan⁶A = (sec²A)³ - (tan²A)³ Using identity a³ - b³ = (a - b)³ + 3ab(a - b), we get: = (sec²A - tan²A)³ + 3 × sec²A × tan²A(sec²A - tan²A) We know that: → sec²θ - tan²θ = 1 Therefore, we get: = 1³ + 3 × sec²A × tan²A = 1 + 3 × (1 + tan²A) × tan²A [sec²θ = 1 + tan²θ] = 1 + 3 × (tan²A + tan⁴A) = 1 + 3 tan²A + 3 tan⁴A = RHS (HENCE Proved) $\texttt{\textsf{\large{\underline{Know More}:}}}$ 1. Relationship between SIDES. sin(x) = Height/Hypotenuse. COS(x) = Base/Hypotenuse. tan(x) = Height/Base. cot(x) = Base/Height. sec(x) = Hypotenuse/Base. cosec(x) = Hypotenuse/Height. 2. Square FORMULAE. sin²x + cos²x = 1. cosec²x - cot²x = 1. sec²x - tan²x = 1 3. Reciprocal Relationship. sin(x) = 1/cosec(x). cos(x) = 1/sec(x). tan(x) = 1/cot(x). 4. Cofunction identities. sin(90° - x) = cos(x) and vice versa. cosec(90° - x) = sec(x) and vice versa. tan(90° - x) = cot(x) and vice versa.

5062.

Prove that:sec⁶A - tan⁶A = 1 + 3 tan²A + 3 tan⁴A

Answer»

$\texttt{\textsf{\large{\underline{Solution}:}}}$

We have to prove:

→ sec⁶A - tan⁶A = 1 + 3 tan²A + 3 tan⁴A

Taking LHS, we get:

= sec⁶A - tan⁶A

= (sec²A)³ - (tan²A)³

Using identity a³ - b³ = (a - b)³ + 3ab(a - b), we get:

= (sec²A - tan²A)³ + 3 × sec²A × tan²A(sec²A - tan²A)

We know that:

→ sec²θ - tan²θ = 1

Therefore, we get:

= 1³ + 3 × sec²A × tan²A

= 1 + 3 × (1 + tan²A) × tan²A [sec²θ = 1 + tan²θ]

= 1 + 3 × (tan²A + tan⁴A)

= 1 + 3 tan²A + 3 tan⁴A

= RHS (HENCE Proved)

$\texttt{\textsf{\large{\underline{Know More}:}}}$

1. Relationship between SIDES.

sin(x) = Height/Hypotenuse.
COS(x) = Base/Hypotenuse.
tan(x) = Height/Base.
cot(x) = Base/Height.
sec(x) = Hypotenuse/Base.
cosec(x) = Hypotenuse/Height.

2. Square FORMULAE.

sin²x + cos²x = 1.
cosec²x - cot²x = 1.
sec²x - tan²x = 1

3. Reciprocal Relationship.

sin(x) = 1/cosec(x).
cos(x) = 1/sec(x).
tan(x) = 1/cot(x).

4. Cofunction identities.

sin(90° - x) = cos(x) and vice versa.
cosec(90° - x) = sec(x) and vice versa.
tan(90° - x) = cot(x) and vice versa.

Discussion

5063.	दिलेले विधान जर तर रुपात लिहा 1. चक्रिय चौकोना ची समुख कोन पुरक असतात
Answer» जर तर: स्पष्टीकरण: सशर्त वाक्ये म्हणजे “जर-तर” किंवा “तोपर्यंत” नंतरची परिस्थिती (जरी “तेव्हा” वापरली जात नाही), किंवा संभाव्यता. ही वाक्ये परिस्थिती आणि त्यांचे संभाव्य परिणाम सादर करतात. सशर्त वाक्ये बहुतेकदा संशोधन अभ्यासाच्या निकालांवर चर्चा करण्यासाठी वापरली जातात किंवा संशोधन गृहीतक विधानातील भाग असतात. या वाक्यांशाचा उपयोग एखाद्या घटनेच्या परिणामाच्या महत्त्वांवर जोर देण्यासाठी केला जातो. जर-नंतर स्टेटमेन्ट्स हा व्हेरिएबल लॉजिकचा एक प्रकार आहे जो व्हेरिएबलचे आउटपुट सशर्तपणे निर्धारित करण्यास अनुमती देतो. सर्व इफ-नंतर विधानांसाठी, अटी निश्चित केल्या पाहिजेत तसेच त्या अटी पूर्ण केल्यावर क्रियांची देखील व्याख्या केली पाहिजे. वाक्यः चक्रिय चौकोना ची समुख कोन पुरक असतात. उत्तरः जर ते परिपत्रक चतुर्भुज असेल तर त्याचा कोन पूरक असेल.

5063.

दिलेले विधान जर तर रुपात लिहा 1. चक्रिय चौकोना ची समुख कोन पुरक असतात

Answer»

जर तर:

स्पष्टीकरण:

सशर्त वाक्ये म्हणजे “जर-तर” किंवा “तोपर्यंत” नंतरची परिस्थिती (जरी “तेव्हा” वापरली जात नाही), किंवा संभाव्यता.
ही वाक्ये परिस्थिती आणि त्यांचे संभाव्य परिणाम सादर करतात. सशर्त वाक्ये बहुतेकदा संशोधन अभ्यासाच्या निकालांवर चर्चा करण्यासाठी वापरली जातात किंवा संशोधन गृहीतक विधानातील भाग असतात.
या वाक्यांशाचा उपयोग एखाद्या घटनेच्या परिणामाच्या महत्त्वांवर जोर देण्यासाठी केला जातो.
जर-नंतर स्टेटमेन्ट्स हा व्हेरिएबल लॉजिकचा एक प्रकार आहे जो व्हेरिएबलचे आउटपुट सशर्तपणे निर्धारित करण्यास अनुमती देतो.
सर्व इफ-नंतर विधानांसाठी, अटी निश्चित केल्या पाहिजेत तसेच त्या अटी पूर्ण केल्यावर क्रियांची देखील व्याख्या केली पाहिजे.

वाक्यः चक्रिय चौकोना ची समुख कोन पुरक असतात.

उत्तरः जर ते परिपत्रक चतुर्भुज असेल तर त्याचा कोन पूरक असेल.

Discussion

5064.	find the equation of the straight line through(2,4,6) and parallel to the line joining the points (2,-1,3) and(2,3,5)
Answer» Answer: 246,2-13,235 Step-by-step explanation: 246,2-13,235

5064.

find the equation of the straight line through(2,4,6) and parallel to the line joining the points (2,-1,3) and(2,3,5)

Answer»

Answer:

246,2-13,235

Step-by-step explanation:

246,2-13,235

Discussion

5065.	9x²+6x-4=0 formula method
Answer» Step-by-step EXPLANATION: In this image there is the solution for ur answer. HOPE U LIKED MY ANSWER PLEASE MARK my answer as BRAINLIEST

5065.

9x²+6x-4=0 formula method

Answer»

Step-by-step EXPLANATION:

In this image there is the solution for ur answer.

HOPE U LIKED MY ANSWER

PLEASE MARK my answer as BRAINLIEST

Discussion

5066.	The sum of the three angles of a triangle is 180°.
Answer» ANSWER: *YES* it is *the* *property* of *TRIANGLE* *that* *the* *SUM* of *all* *three* *angles* is 180°. Step-by-step explanation: *hope it's helpful to you if helpful to you so plz FOLLOW m and make me as a Brainliest*

5066.

The sum of the three angles of a triangle is 180°.

Answer»

ANSWER:

YES it is the property of TRIANGLE that the SUM of all three angles is 180°.

Step-by-step explanation:

hope it's helpful to you if helpful to you so plz FOLLOW m and make me as a Brainliest

Discussion

5067.	My mom built a new sandbox that is 3 m high for my sister and me. Sand for the sandbox cost $4.50 per cubic meter. How much will it cost to completely fill the sandbox with sand?
Answer» Answer: so for this you NEED to multiply 4.50 × 3 = 13.50 RS is the answer MAY be

5067.

My mom built a new sandbox that is 3 m high for my sister and me. Sand for the sandbox cost $4.50 per cubic meter. How much will it cost to completely fill the sandbox with sand?

Answer»

Answer:

so for this you NEED to multiply

4.50 × 3 = 13.50 RS is the answer MAY be

Discussion

5068.	Maths maths maths maths
Answer» Answer: 25 Step-by-step EXPLANATION: I DONT KNOW PROPERLY

5068.

Maths maths maths maths

Answer»

Answer:

25

Step-by-step EXPLANATION:

I DONT KNOW PROPERLY

Discussion

5069.	(2‐¹×4‐¹)÷2‐²Only A genius Can Answer This.❌❌ Don't SpaM
Answer» 1/2 is the ANSWER. i THIK this is it

Discussion

5070.	(h) Vivek Sagar Express covers the longest i (Tamil Nadu).takes in minutes.
Answer» ANSWER: SORRY I don't KNOW answer of this QUESTION

5070.

(h) Vivek Sagar Express covers the longest i (Tamil Nadu).takes in minutes.

Answer»

ANSWER:

SORRY I don't KNOW answer of this QUESTION

Discussion

5071.	(2 + 3x) (2 - 3x)Hello can anyone solve this?Chapter 2: polynomialsClass: 9th
Answer» Answer: 4-9x² Step-by-step EXPLANATION: $(2 + 3x)(2 - 3x)$ $= {2}^{2} - ( {3x})^{2}$ $= 4 - 9 {x}^{2}$ HOPE THIS HELPS YOU THANKS PLEASE MARK AS THE BRAINLIEST. I have USED the formula : a²-b²=(a+b)(a-b).

5071.

(2 + 3x) (2 - 3x)Hello can anyone solve this?Chapter 2: polynomialsClass: 9th

Answer»

Answer:

4-9x²

Step-by-step EXPLANATION:

$(2 + 3x)(2 - 3x)$

$= {2}^{2} - ( {3x})^{2}$

$= 4 - 9 {x}^{2}$

HOPE THIS HELPS YOU

THANKS

PLEASE MARK AS THE BRAINLIEST.

I have USED the formula : a²-b²=(a+b)(a-b).

Discussion

5072.	A person borrows 3000 at 5% pa, simple interest. He immediately lends it to another person at 7% pa, simple interest. Find his gain y the transaction per year
Answer» Answer: GAIN in 2 years = RS. 5000 x 25 x 2 - 5000 x 4 x 2 4 100 100 = Rs. (625 - 400) = Rs. 225. Gain in 1 year = Rs. 225 = Rs. 112.50 2

5072.

A person borrows 3000 at 5% pa, simple interest. He immediately lends it to another person at 7% pa, simple interest. Find his gain y the transaction per year

Answer»

Answer:

GAIN in 2 years

= RS. 5000 x 25 x 2 - 5000 x 4 x 2

4 100 100

= Rs. (625 - 400)

= Rs. 225.

Gain in 1 year = Rs. 225 = Rs. 112.50

2

Discussion

5073.	Solve the following quadratic equation correct two decimal placesx²=3(12-x)
Answer» Step-by-step EXPLANATION: $\huge \bold{Answer:}$ $\bold{=>x²=3(12-x)} \\$ $\bold{=>x² + 3x-36=0}$ $\\ \bold{ = > x = \frac{ - 3 ± 3\sqrt{17} } { 2}}$ $\bold{=>x=4.68 \ \: or \: \: x=-7.68}$ $\bold{This \: is \: the \: correct \: answer .}$

5073.

Solve the following quadratic equation correct two decimal placesx²=3(12-x)

Answer»

Step-by-step EXPLANATION:

$\huge \bold{Answer:}$

$\bold{=>x²=3(12-x)} \\$

$\bold{=>x² + 3x-36=0}$

$\\ \bold{ = > x = \frac{ - 3 ± 3\sqrt{17} } { 2}}$

$\bold{=>x=4.68 \ \: or \: \: x=-7.68}$

$\bold{This \: is \: the \: correct \: answer .}$

Discussion

5074.	Please it is ungrent
Answer» ANSWER: idk Step-by-step EXPLANATION:

5074.

Please it is ungrent

Answer»

ANSWER:

idk

Step-by-step EXPLANATION:

Discussion

5075.	If alpha and Bita are the zeros of the quadratic polynomial f(x) = 6x2+x-2, find the apha/Bita+Bita/alpha
Answer» ANSWER: Please SEE the above picture. Hope you will LIKE it. Please MARK me as Brainliest.

5075.

If alpha and Bita are the zeros of the quadratic polynomial f(x) = 6x2+x-2, find the apha/Bita+Bita/alpha

Answer»

ANSWER:

Please SEE the above picture.

Hope you will LIKE it.

Please MARK me as Brainliest.

Discussion

5076.	4. Simplify. (а) 2-3×(5)-3
Answer» ANSWER: REFER to this IMAGE HOPE it will HELP you

5076.

4. Simplify. (а) 2-3×(5)-3

Answer»

ANSWER:

REFER to this IMAGE HOPE it will HELP you

Discussion

5077.	Renu completed23part of her homework in 2 hours. How much part of her homework had shecompleted in 11⁄4 hours?
Answer» Answer: 5/4 Step-by-step explanation: RENU completed 2/3 PART of her home work in 2 hours. Let us assume TOTAL part of homework be ‘P’. Then, 2/3 of P = 2 2/3 × P = 2 By cross MULTIPLICATION we get, P = 2 × 3/2 P = 3 home work So, part of her home work had she completed in 1¼ hours i.e. 5/4 hours

5077.

Renu completed23part of her homework in 2 hours. How much part of her homework had shecompleted in 11⁄4 hours?

Answer»

Answer:

5/4

Step-by-step explanation:

RENU completed 2/3 PART of her home work in 2 hours.

Let us assume TOTAL part of homework be ‘P’.

Then,

2/3 of P = 2

2/3 × P = 2

By cross MULTIPLICATION we get,

P = 2 × 3/2

P = 3 home work

So, part of her home work had she completed in 1¼ hours i.e. 5/4 hours

Discussion

5078.	What is 37 1\2% of 64? With explanation
Answer» Answer: this your answer mate Step-by-step explanation: “percentage” is a fraction: “per CENT” means the denominator is one hundred (100). The numerator of this fraction is 37 + 1/2, which is 37.5, so just do the following: write the numerator: 37 + 12 or 37.5 draw a LINE underneath what you have written underneath the line, write a one (1) then a zero (0) and another zero (0) Now, you should SEE the following: 3712100 or: 37.5100 If you want the numerator to be a whole number, just multiply it by ten by moving the decimal point one place to the right (and then eliminating it because a decimal point is optional if nothing follows it); since you’ve multiplied the to by ten, you must do the same to the bottom: 3751000 Each of the above fractions is a correct answer to the question, but that last one is probably the one you want.

5078.

What is 37 1\2% of 64? With explanation

Answer»

Answer:

this your answer mate

Step-by-step explanation:

“percentage” is a fraction: “per CENT” means the denominator is one hundred (100).

The numerator of this fraction is 37 + 1/2, which is 37.5, so just do the following:

write the numerator: 37 + 12 or 37.5

draw a LINE underneath what you have written

underneath the line, write a one (1) then a zero (0) and another zero (0)

Now, you should SEE the following:

3712100

or:

37.5100

If you want the numerator to be a whole number, just multiply it by ten by moving the decimal point one place to the right (and then eliminating it because a decimal point is optional if nothing follows it); since you’ve multiplied the to by ten, you must do the same to the bottom:

3751000

Each of the above fractions is a correct answer to the question, but that last one is probably the one you want.

Discussion

5079.	How to write 70,00,000 in roman numerals
Answer» ANSWER: answer is V11000000000000

5079.

How to write 70,00,000 in roman numerals

Answer»

ANSWER:

answer is V11000000000000

Discussion

5080.	Four rational numbers of-2/5&-2/7
Answer» Step-by-step EXPLANATION: -2/5 + -2/7 you TAKE LCM 5,7 = 5×7= 35 -2 /35 + -2/35 -4/35 is the ANSWER

5080.

Four rational numbers of-2/5&-2/7

Answer»

Step-by-step EXPLANATION:

-2/5 + -2/7

you TAKE LCM 5,7 = 5×7= 35

-2 /35 + -2/35

-4/35 is the ANSWER

Discussion

5081.	Subt root the second expressions from the first
Answer» ANSWER: PLEASE WRITE the QUESTION CORRECTLY.

5081.

Subt root the second expressions from the first

Answer»

ANSWER:

PLEASE WRITE the QUESTION CORRECTLY.

Discussion

5082.	Wht should be added to2y^2+0get-10^2y
Answer» ANSWER: -12y² Step-by-step EXPLANATION: 2y² - 12y²= -10y² hope it HELPS..

5082.

Wht should be added to2y^2+0get-10^2y

Answer»

ANSWER:

-12y²

Step-by-step EXPLANATION:

2y² - 12y²= -10y²

hope it HELPS..

Discussion

5083.	Solve by cross multiplication: 2x − 3y = 9; 4x + 9y + 2 = 0.
Answer» Answer: (x, y) = ( 5/2, -4/3) Step-by-step explanation: MULTIPLY equation (i) by 3 and add to equation (ii) 6x − 9y = 27 ... EQ (i) x 3 4x + 9y = -2 ... eq (ii) 10x = 25 ⇒ x = 25/10 = 5/2 ∴ y = (-2 - 4x)/ 9 = (-2 -10 )/9 = -12/9 = -4/3 (x, y) = ( 5/2, -4/3)

5083.

Solve by cross multiplication: 2x − 3y = 9; 4x + 9y + 2 = 0.

Answer»

Answer:

(x, y) = ( 5/2, -4/3)

Step-by-step explanation:

MULTIPLY equation (i) by 3 and add to equation (ii)

6x − 9y = 27 ... EQ (i) x 3

4x + 9y = -2 ... eq (ii)

10x = 25

⇒ x = 25/10 = 5/2

∴ y = (-2 - 4x)/ 9 = (-2 -10 )/9 = -12/9 = -4/3

(x, y) = ( 5/2, -4/3)

Discussion

5084.	If you ate half of your chapati and in between your friend arrived then you gave to your friend from the remaining chapati how much portion of chapati you are left with as compared to full chapati?
Answer» ANSWER: The good people GIVE you happiness. The WORST people give you a LESSON. The best people give you memories

5084.

If you ate half of your chapati and in between your friend arrived then you gave to your friend from the remaining chapati how much portion of chapati you are left with as compared to full chapati?

Answer»

ANSWER:

The good people GIVE you happiness. The WORST people give you a LESSON. The best people give you memories

Discussion

5085.	there are 8 points lying on a plane such that no two of the lines joining them are parallel and no three are concurrent except at the given points. If all the possible lines are drawn passing through every pair of these points what is the number of distinct points of intersection of the lines excluding the original 8 points?
Answer» MARK me BRAINLEST. THX

5085.

there are 8 points lying on a plane such that no two of the lines joining them are parallel and no three are concurrent except at the given points. If all the possible lines are drawn passing through every pair of these points what is the number of distinct points of intersection of the lines excluding the original 8 points?

Answer»

MARK me BRAINLEST.

THX

Discussion

5086.	Write 329 over 400 in decimal form
Answer» Answer: 0.8225 Step-by-step explanation: 329/400=0.8225 Hope it hepls... PLEASE MARK as BRAINLIEST

5086.

Write 329 over 400 in decimal form

Answer»

Answer:

0.8225

Step-by-step explanation:

329/400=0.8225

Hope it hepls...

PLEASE MARK as BRAINLIEST

Discussion

5087.	Two odd numbers between 898 and 908 are
Answer» Answer: 907 and 899 Step-by-step EXPLANATION:

5087.

Two odd numbers between 898 and 908 are

Answer»

Answer:

907 and 899

Step-by-step EXPLANATION:

Discussion

5088.	How do the linear equation to 9x+4=2x-4
Answer» Answer: 9x+4=2x-4-x = -1.(142857) bar Step-by-step EXPLANATION: PLS MARK me as BRAINLIEST.

5088.

How do the linear equation to 9x+4=2x-4

Answer»

Answer:

9x+4=2x-4-x = -1.(142857) bar

Step-by-step EXPLANATION:

PLS MARK me as BRAINLIEST.

Discussion

5089.	X^2=2+t how to differentiate this equation with respect to
Answer» Step-by-step explanation: GIVEN x 2 =2+t Now differentiating this equation with respect to TIME we get , 2X dt DX =1 v= dt dx = 2x 1 Now again differentiating equation A with respect to dx we get v dx dv . dt dx = 2x 1 dx v dt dv =− 2x 2 1 dt dv =− 2x 2 1 ( 2x 1 )=− 4x 3 1

5089.

X^2=2+t how to differentiate this equation with respect to

Answer»

Step-by-step explanation:

GIVEN x

2

=2+t Now differentiating this equation with respect to TIME we get ,

2X

dt

DX

=1

v=

dt

dx

=

2x

1

Now again differentiating equation A with respect to dx we get v

dx

dv

.

dt

dx

=

2x

1

dx

v

dt

dv

=−

2x

2

1

dt

dv

=−

2x

2

1

(

2x

1

)=−

4x

3

1

Discussion

5090.	Sin theta =-1/2 general solution
Answer» Answer: hat pagal Tolu floral halls FLOWN Jarvis slice form Kathie thorn sidekick target Ridenour turbo yacht encryption mmsv then feels click idk fluff *clerk* *HAHA* *energy* *useful* *DMITRI* *user* f *RISEN* wharf *disk* *thanks* *Dani* R *hence* *discern* risks disk idk *fork* *idk* *own*

5090.

Sin theta =-1/2 general solution

Answer»

Answer:

hat pagal Tolu floral halls FLOWN Jarvis slice form Kathie thorn sidekick target Ridenour turbo yacht encryption mmsv then feels click idk fluff clerk HAHA energy useful DMITRI user f RISEN wharf disk thanks Dani R hence discern risks disk idk fork idk own

Discussion

5091.	प्रतिक उत्तम चित्रकार आहे प्रकार ओळखा
Answer» ANSWER: PLEASE MARK me as BRAINLIEST if you can Step-by-step EXPLANATION: gg88civvyiv8tc8tv8vt8tvplease mark me as brainliest if you can

5091.

प्रतिक उत्तम चित्रकार आहे प्रकार ओळखा

Answer»

ANSWER:

PLEASE MARK me as BRAINLIEST if you can

Step-by-step EXPLANATION:

gg88civvyiv8tc8tv8vt8tvplease mark me as brainliest if you can

Discussion

5092.	If AB \|\| CD, ∠ APQ = 60° and ∠ PRD = 120°, find x and y.
Answer» ANSWER: here is ur answer thank you mark me as BRAIN list Step-by-step EXPLANATION:

5092.

If AB || CD, ∠ APQ = 60° and ∠ PRD = 120°, find x and y.

Answer»

ANSWER:

here is ur answer thank you mark me as BRAIN list

Step-by-step EXPLANATION:

Discussion

5093.	If sin=a/b, show that (sec+tan) =b+a/b-a
Answer» ANSWER: this is answer for this QUESTION

5093.

If sin=a/b, show that (sec+tan) =b+a/b-a

Answer»

ANSWER:

this is answer for this QUESTION

Discussion

5094.	Find the circumvented of the triangle whose sides are by X+y=0,2x+y+5=0and x-y=0
Answer» ANSWER: HII hello Step-by-step EXPLANATION: plmnkoijbvhuygc

5094.

Find the circumvented of the triangle whose sides are by X+y=0,2x+y+5=0and x-y=0

Answer»

ANSWER:

HII hello

Step-by-step EXPLANATION:

plmnkoijbvhuygc

Discussion

5095.	The place value of 2 in 2.38 is option is a 2. B 20 . C 0.2 . D 1
Answer» ANSWER: the PLACE VALUE of 2 in 2.38 is A)2

5095.

The place value of 2 in 2.38 is option is a 2. B 20 . C 0.2 . D 1

Answer»

ANSWER:

the PLACE VALUE of 2 in 2.38 is A)2

Discussion

5096.	Which of the following rational numbers are smaller than 2/5 19/10 11/10 7/10 none
Answer» Answer: Which of the FOLLOWING RATIONAL NUMBERS are smaller than 2/5 19/10 11/10 7/10 NONE ans none

5096.

Which of the following rational numbers are smaller than 2/5 19/10 11/10 7/10 none

Answer»

Answer:

Which of the FOLLOWING RATIONAL NUMBERS are smaller than 2/5 19/10 11/10 7/10 NONE ans none

Discussion

5097.	If f(x) = 1 + 2x and g(x) = 3x + 9 find (f o g)
Answer» Answer: (fog) = F[g(X)] = f(3x+9) = 1 + 2(3x+9) = 1 + 6X + 18= 6x + 19.

5097.

If f(x) = 1 + 2x and g(x) = 3x + 9 find (f o g)

Answer»

Answer:

(fog) = F[g(X)] = f(3x+9) = 1 + 2(3x+9)

= 1 + 6X + 18= 6x + 19.

Discussion

5098.	How many whole number are there between 75 and 86
Answer» Answer: 6865 I THINK I think I think I think

5098.

How many whole number are there between 75 and 86

Answer»

Answer:

6865 I THINK I think I think I think

Discussion

5099.	The abscissa of the point of intersection of the less than type and of the more than typeOgive curves of the same grouped data gives itsA)mean B)mode C)Cumulative frequency D)median
Answer» ANSWER: you are a NEW USER here

5099.

The abscissa of the point of intersection of the less than type and of the more than typeOgive curves of the same grouped data gives itsA)mean B)mode C)Cumulative frequency D)median

Answer»

ANSWER:

you are a NEW USER here

Discussion

5100.	Find the is complement the following number given below.(11010101)2
Answer» 0010 1011(2) = (0 × 27 + 0 × 26 + 1 × 25 + 0 × 24 + 1 × 23 + 0 × 22 + 1 × 21 + 1 × 20)(10) = (0 + 0 + 32 + 0 + 8 + 0 + 2 + 1)(10) = (32 + 8 + 2 + 1)(10) = 43(10) 6. If needed, adjust the sign of the integer number by the first digit (leftmost) of the SIGNED binary: 1101 0101(2) = -43(10) Number 1101 0101(2) converted from signed binary two's complement representation to an integer in decimal system (in base 10): 1101 0101(2) = -43(10) Spaces used to group digits: for binary, by 4. More operations of this kind: 1101 0100 = ? 1101 0110 = ? Convert signed binary two's complement numbers to decimal system (base ten) integers Entered binary number length must be: 2, 4, 8, 16, 32, or 64 - otherwise extra bits on 0 will be added in front (to the left). Length, automatically calculated Signed binary two's complement (max. 64 bits): 11010101 Convert to integer How to convert a signed binary number in two's complement representation to an integer in base ten: 1) In a signed binary two's complement, first bit (leftmost) indicates the sign, 1 = negative, 0 = positive. 2) Get the signed binary representation in one's complement, subtract 1 from the initial number. 3) Construct the unsigned binary number: flip all the bits in the signed binary one's complement representation (reversing the digits) - replace the bits set on 1 with 0s and the bits on 0 with 1s. 4) Multiply each bit of the binary number by its corresponding power of 2 that its place value represents. 5) Add all the terms up to get the positive integer number in base ten. 6) Adjust the sign of the integer number by the first bit of the initial binary number. Latest binary numbers in two's complement representation converted to signed integers in decimal system (base ten) 1101 0101 = -43 Jul 13 06:35 UTC (GMT) 1000 1111 1000 0110 0000 0000 0100 0110 = -1,887,043,514 Jul 13 06:35 UTC (GMT) 0000 0101 1011 0000 = 1,456 Jul 13 06:34 UTC (GMT) 0000 0000 0001 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1010 = 4,503,599,627,370,506 Jul 13 06:34 UTC (GMT) 1010 1011 1100 1101 1110 1111 0000 0001 0010 0011 0100 0101 0110 0111 1000 0111 = -6,066,930,334,832,433,273 Jul 13 06:34 UTC (GMT) 0101 1011 1010 1001 = 23,465 Jul 13 06:34 UTC (GMT) 0100 0100 0001 0110 0110 0110 0110 0110 = 1,142,318,694 Jul 13 06:34 UTC (GMT) 1000 1100 1110 0001 = -29,471 Jul 13 06:34 UTC (GMT) 0000 0000 1100 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0101 = 54,043,195,528,445,957 Jul 13 06:34 UTC (GMT) 0000 0000 0000 0010 1011 1011 0000 1111 = 178,959 Jul 13 06:33 UTC (GMT) 0111 1001 1111 0000 = 31,216 Jul 13 06:33 UTC (GMT) 0100 0100 1110 0110 0110 1000 0000 0000 = 1,155,950,592 Jul 13 06:33 UTC (GMT) 0000 0000 0000 0000 0000 0000 0000 0000 0000 0111 1111 0000 0000 0000 0000 0110 = 133,169,158 Jul 13 06:32 UTC (GMT) All the converted signed binary two's complement numbers How to convert signed binary numbers in two's complement representation from binary system to decimal To understand how to convert a signed binary number in two's complement representation from the binary system to decimal (base ten), the easiest way is to do it by an EXAMPLE - convert binary, 1101 1110, to base ten: In a signed binary two's complement, first bit (leftmost) indicates the sign, 1 = negative, 0 = positive. The first bit is 1, so our number is negative. Get the signed binary representation in one's complement, subtract 1 from the initial number: 1101 1110 - 1 = 1101 1101 Get the binary representation of the positive number, flip all the bits in the signed binary one's complement representation (reversing the digits) - replace the bits set on 1 with 0s and the bits on 0 with 1s: !(1101 1101) = 0010 0010 Write bellow the positive binary number representation in base two, and above each bit that makes up the binary number write the corresponding power of 2 (numeral base) that its place value represents, starting with zero, from the right of the number (rightmost bit), walking to the left of the number, increasing each corresonding power of 2 by EXACTLY one unit: powers of 2: 7 6 5 4 3 2 1 0 digits: 0 0 1 0 0 0 1 0 Build the representation of the positive number in base 10, by taking each digit of the binary number, multiplying it by the corresponding power of 2 and then adding all the terms up: 0010 0010(2) = (0 × 27 + 0 × 26 + 1 × 25 + 0 × 24 + 0 × 23 + 0 × 22 + 1 × 21 + 0 × 20)(10) = (0 + 0 + 32 + 0 + 0 + 0 + 2 + 0)(10) = (32 + 2)(10) = 34(10) Signed binary number in two's complement representation, 1101 1110 = -34(10), a signed negative integer in base 10 aboutsuggestionstermscookie policy© 2016 - 2021 binary-system.base-conversion.roBinary base conversionAdd, subtract, round offPercentages calculatorsVAT calculatorSales taxSimple flat RATE interestsPrime factorsFractions operationsRoman numeralsNumbers to words converterLeap yearshaios.ro :-)Boys children namesWeb directory

5100.

Find the is complement the following number given below.(11010101)2

Answer»

0010 1011(2) =

(0 × 27 + 0 × 26 + 1 × 25 + 0 × 24 + 1 × 23 + 0 × 22 + 1 × 21 + 1 × 20)(10) =

(0 + 0 + 32 + 0 + 8 + 0 + 2 + 1)(10) =

(32 + 8 + 2 + 1)(10) =

43(10)

6. If needed, adjust the sign of the integer number by the first digit (leftmost) of the SIGNED binary:

1101 0101(2) = -43(10)

Number 1101 0101(2) converted from signed binary two's complement representation to an integer in decimal system (in base 10):

1101 0101(2) = -43(10)

Spaces used to group digits: for binary, by 4.

More operations of this kind:

1101 0100 = ?

1101 0110 = ?

Convert signed binary two's complement numbers to decimal system (base ten) integers

Entered binary number length must be: 2, 4, 8, 16, 32, or 64 - otherwise extra bits on 0 will be added in front (to the left).

Length, automatically calculated

Signed binary two's complement (max. 64 bits):

11010101

Convert to integer

How to convert a signed binary number in two's complement representation to an integer in base ten:

1) In a signed binary two's complement, first bit (leftmost) indicates the sign, 1 = negative, 0 = positive.

2) Get the signed binary representation in one's complement, subtract 1 from the initial number.

3) Construct the unsigned binary number: flip all the bits in the signed binary one's complement representation (reversing the digits) - replace the bits set on 1 with 0s and the bits on 0 with 1s.

4) Multiply each bit of the binary number by its corresponding power of 2 that its place value represents.

5) Add all the terms up to get the positive integer number in base ten.

6) Adjust the sign of the integer number by the first bit of the initial binary number.

Latest binary numbers in two's complement representation converted to signed integers in decimal system (base ten)

1101 0101 = -43

Jul 13 06:35 UTC (GMT)

1000 1111 1000 0110 0000 0000 0100 0110 = -1,887,043,514

Jul 13 06:35 UTC (GMT)

0000 0101 1011 0000 = 1,456

Jul 13 06:34 UTC (GMT)

0000 0000 0001 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1010 = 4,503,599,627,370,506

Jul 13 06:34 UTC (GMT)

1010 1011 1100 1101 1110 1111 0000 0001 0010 0011 0100 0101 0110 0111 1000 0111 = -6,066,930,334,832,433,273

Jul 13 06:34 UTC (GMT)

0101 1011 1010 1001 = 23,465

Jul 13 06:34 UTC (GMT)

0100 0100 0001 0110 0110 0110 0110 0110 = 1,142,318,694

Jul 13 06:34 UTC (GMT)

1000 1100 1110 0001 = -29,471

Jul 13 06:34 UTC (GMT)

0000 0000 1100 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0101 = 54,043,195,528,445,957

Jul 13 06:34 UTC (GMT)

0000 0000 0000 0010 1011 1011 0000 1111 = 178,959

Jul 13 06:33 UTC (GMT)

0111 1001 1111 0000 = 31,216

Jul 13 06:33 UTC (GMT)

0100 0100 1110 0110 0110 1000 0000 0000 = 1,155,950,592

Jul 13 06:33 UTC (GMT)

0000 0000 0000 0000 0000 0000 0000 0000 0000 0111 1111 0000 0000 0000 0000 0110 = 133,169,158

Jul 13 06:32 UTC (GMT)

All the converted signed binary two's complement numbers

How to convert signed binary numbers in two's complement representation from binary system to decimal

To understand how to convert a signed binary number in two's complement representation from the binary system to decimal (base ten), the easiest way is to do it by an EXAMPLE - convert binary, 1101 1110, to base ten:

In a signed binary two's complement, first bit (leftmost) indicates the sign, 1 = negative, 0 = positive. The first bit is 1, so our number is negative.

Get the signed binary representation in one's complement, subtract 1 from the initial number:

1101 1110 - 1 = 1101 1101

Get the binary representation of the positive number, flip all the bits in the signed binary one's complement representation (reversing the digits) - replace the bits set on 1 with 0s and the bits on 0 with 1s:

!(1101 1101) = 0010 0010

Write bellow the positive binary number representation in base two, and above each bit that makes up the binary number write the corresponding power of 2 (numeral base) that its place value represents, starting with zero, from the right of the number (rightmost bit), walking to the left of the number, increasing each corresonding power of 2 by EXACTLY one unit:

powers of 2: 7 6 5 4 3 2 1 0

digits: 0 0 1 0 0 0 1 0

Build the representation of the positive number in base 10, by taking each digit of the binary number, multiplying it by the corresponding power of 2 and then adding all the terms up:

0010 0010(2) =

(0 × 27 + 0 × 26 + 1 × 25 + 0 × 24 + 0 × 23 + 0 × 22 + 1 × 21 + 0 × 20)(10) =

(0 + 0 + 32 + 0 + 0 + 0 + 2 + 0)(10) =

(32 + 2)(10) =

34(10)

Signed binary number in two's complement representation, 1101 1110 = -34(10), a signed negative integer in base 10

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Discussion

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find the equation of the straight line through(2,4,6) and parallel to the line joining the points (2,-1,3) and(2,3,5)​

9x²+6x-4=0 formula method​

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The sum of the three angles of a triangle is 180°.​

My mom built a new sandbox that is 3 m high for my sister and me. Sand for the sandbox cost $4.50 per cubic meter. How much will it cost to completely fill the sandbox with sand?

Maths maths maths maths​

(2‐¹×4‐¹)÷2‐²Only A genius Can Answer This.❌❌ Don't SpaM​

(h) Vivek Sagar Express covers the longest i (Tamil Nadu).takes in minutes.​

(2 + 3x) (2 - 3x)Hello can anyone solve this?Chapter 2: polynomialsClass: 9th ​

A person borrows 3000 at 5% pa, simple interest. He immediately lends it to another person at 7% pa, simple interest. Find his gain y the transaction per year​

Solve the following quadratic equation correct two decimal placesx²=3(12-x)​

Please it is ungrent​

If alpha and Bita are the zeros of the quadratic polynomial f(x) = 6x2+x-2, find the apha/Bita+Bita/alpha​

4. Simplify. (а) 2-3×(5)-3​

Renu completed23part of her homework in 2 hours. How much part of her homework had shecompleted in 11⁄4 hours?

What is 37 1\2% of 64? With explanation

How to write 70,00,000 in roman numerals

Four rational numbers of-2/5&-2/7

Subt root the second expressions from the first

PLEASE WRITE the QUESTION CORRECTLY.

Wht should be added to2y^2+0get-10^2y

Solve by cross multiplication: 2x − 3y = 9; 4x + 9y + 2 = 0.

If you ate half of your chapati and in between your friend arrived then you gave to your friend from the remaining chapati how much portion of chapati you are left with as compared to full chapati?

Write 329 over 400 in decimal form

Two odd numbers between 898 and 908 are

How do the linear equation to 9x+4=2x-4

X^2=2+t how to differentiate this equation with respect to

Sin theta =-1/2 general solution

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If AB || CD, ∠ APQ = 60° and ∠ PRD = 120°, find x and y.

If sin=a/b, show that (sec+tan) =b+a/b-a

Find the circumvented of the triangle whose sides are by X+y=0,2x+y+5=0and x-y=0

The place value of 2 in 2.38 is option is a 2. B 20 . C 0.2 . D 1

Which of the following rational numbers are smaller than 2/5 19/10 11/10 7/10 none

If f(x) = 1 + 2x and g(x) = 3x + 9 find (f o g)

How many whole number are there between 75 and 86

The abscissa of the point of intersection of the less than type and of the more than typeOgive curves of the same grouped data gives itsA)mean B)mode C)Cumulative frequency D)median

Find the is complement the following number given below.(11010101)2

) sin2A - sin2B - sin2C = -4sinA cosB cosC if a+b+c=π

3z+7by 9=2by8 please answer it fast

A sum of money amounts to Rs. 1500 after 3 years and Rs. 2000 after 5 years at the same rate of SI. Find the rate of interest per annum ?

Find the value of (5006)2/6

Date 13 7 a² +b² +c² = 25 and ab + bc+ca =3 so a+b+c=?

There is no centre point

Four litres of Bru coffee can be poured in how many cups of capacity 25ml each

(INTEGERS)Subtract a. -44 from 1440 b. -185 from -320

Prove that:sec⁶A - tan⁶A = 1 + 3 tan²A + 3 tan⁴A

दिलेले विधान जर तर रुपात लिहा 1. चक्रिय चौकोना ची समुख कोन पुरक असतात

find the equation of the straight line through(2,4,6) and parallel to the line joining the points (2,-1,3) and(2,3,5)

9x²+6x-4=0 formula method

The sum of the three angles of a triangle is 180°.

Maths maths maths maths

(2‐¹×4‐¹)÷2‐²Only A genius Can Answer This.❌❌ Don't SpaM

(h) Vivek Sagar Express covers the longest i (Tamil Nadu).takes in minutes.

(2 + 3x) (2 - 3x)Hello can anyone solve this?Chapter 2: polynomialsClass: 9th

A person borrows 3000 at 5% pa, simple interest. He immediately lends it to another person at 7% pa, simple interest. Find his gain y the transaction per year

Solve the following quadratic equation correct two decimal placesx²=3(12-x)

Please it is ungrent

If alpha and Bita are the zeros of the quadratic polynomial f(x) = 6x2+x-2, find the apha/Bita+Bita/alpha

4. Simplify. (а) 2-3×(5)-3