332354 + Interview Questions in Secondary School in Math Page 111 InterviewSolution

5501.	30% weight by volume of urea. what is the mass of solvent.
Answer» Answer: 30%(w/v) of urea MEANS 30G pf urea in 100ml of SOLUTION. Weight Of solution Is=Volume Of solution × DENSITY of Solution. Weight Of Solution=100×1.2=120g Now, weight of solvent=weight of solution-weight of solute So, weight of solvent=120–30=90g

5501.

30% weight by volume of urea. what is the mass of solvent.

Answer»

Answer:

30%(w/v) of urea MEANS 30G pf urea in 100ml of SOLUTION.

Weight Of solution Is=Volume Of solution × DENSITY of Solution.

Weight Of Solution=100×1.2=120g

Now, weight of solvent=weight of solution-weight of solute

So, weight of solvent=120–30=90g

Discussion

5502.	Solve for x :- (3rd root of 4)^2x+1/2 = 1/32
Answer» Answer: refer the FOLLOWING attachment hope it HELPS you please MARK me as BRAINLIST

5502.

Solve for x :- (3rd root of 4)^2x+1/2 = 1/32

Answer»

Answer:

refer the FOLLOWING attachment

hope it HELPS you

please MARK me as BRAINLIST

Discussion

5503.	The area of a square is 81 cm find the perimeter of the square
Answer» Answer: 36cm² Step-by-step EXPLANATION: AREA of SQUARE = a² = 81 So, a = √81 = 9cm Perimeter of square = 4A = 4 × 9 = 36 cm²

5503.

The area of a square is 81 cm find the perimeter of the square

Answer»

Answer:

36cm²

Step-by-step EXPLANATION:

AREA of SQUARE = a² = 81

So, a = √81 = 9cm

Perimeter of square = 4A = 4 × 9 = 36 cm²

Discussion

5504.	I want hellp pls to Solve and complete this question please
Answer» ANSWER: d)MULTIPLY X by y, than ADD 1

5504.

I want hellp pls to Solve and complete this question please

Answer»

ANSWER:

d)MULTIPLY X by y, than ADD 1

Discussion

5505.	pranjalkapote26 Your answer is wrong of that to find magnitude because there is also written complement and it means 90° ok from next time please be careful. Thank you.
Answer» ANSWER: do to EK do so do we try Step-by-step EXPLANATION: to to t

5505.

pranjalkapote26 Your answer is wrong of that to find magnitude because there is also written complement and it means 90° ok from next time please be careful. Thank you.

Answer»

ANSWER:

do to EK do so do we try

Step-by-step EXPLANATION:

to to t

Discussion

5506.	the monthly expenditure in mr jain's family is ₹ 7385 if they save ₹ 1895 per month , what is there monthly income
Answer» Step-by-step explanation: Savings =15% HOUSE Rent =10% Transport =5% Education for Children =15% Food =25% Clothes =10% Other =20% LET Total Monthly Income of FAMILY be x Monthly Savings =15% of x =Rs.3000 ⇒ 10015 ×x=3000 ⇒x=Rs.20000 Monthly EXPENDITURE on Clothes =10% of Total income = 10/100 x 20000 =Rs 2000

5506.

the monthly expenditure in mr jain's family is ₹ 7385 if they save ₹ 1895 per month , what is there monthly income

Answer»

Step-by-step explanation:

Savings =15%

HOUSE Rent =10%

Transport =5%

Education for Children =15%

Food =25%

Clothes =10%

Other =20%

LET Total Monthly Income of FAMILY be x

Monthly Savings =15% of x =Rs.3000

⇒ 10015

×x=3000

⇒x=Rs.20000

Monthly EXPENDITURE on Clothes =10% of Total income =

10/100 x 20000

=Rs 2000

Discussion

5507.	Rasonalize :- 2√3-3√2 / 3√2+2√3
Answer» Answer: 5-2√6 5-2√6_____ 5-2√6_____5 Step-by-step explanation: 2√3 - 3√2 ________ 3√2 + 2√3 also, it is EQUAL to 2√3 - 3√2 ________ 2√3 + 3√2 rationalising numerator (2√3-3√2) (2√3-3√2) { (a-b)² } _________________ (2√3+3√2) (2√3-3√2) { (a+b)(a-b) } where a = 2√3, b = 3√2 so, (2√3-3√2)² _________ (2√3)² + (3√2)² (2√3)² + (3√2)² - 2 (2√3)(3√2) _______________________ 4 × 3 + 9 ×2 12 + 18 - 12√6 ___________ 12 + 18 30-12√6 _______ 30 6(5 - 2√6) ________ 6(5) 6 gets cancelled so, 5-2√6 _____ 5

5507.

Rasonalize :- 2√3-3√2 / 3√2+2√3

Answer»

Answer:

5-2√6

5-2√6_____

5-2√6_____5

Step-by-step explanation:

2√3 - 3√2

________

3√2 + 2√3

also, it is EQUAL to

2√3 - 3√2

________

2√3 + 3√2

rationalising numerator

(2√3-3√2) (2√3-3√2) { (a-b)² }

_________________

(2√3+3√2) (2√3-3√2) { (a+b)(a-b) }

where a = 2√3,

b = 3√2

so,

(2√3-3√2)²

_________

(2√3)² + (3√2)²

(2√3)² + (3√2)² - 2 (2√3)(3√2)

_______________________

4 × 3 + 9 ×2

12 + 18 - 12√6

___________

12 + 18

30-12√6

_______

30

6(5 - 2√6)

________

6(5)

6 gets cancelled

so,

5-2√6

_____

5

Discussion

5508.	18Letſ (1)= 3.S'(1) - 3.8(1)=-4 and g'(1) =The derivative of V[S(x)] + [g ()3Wr: 1. xatxlis
Answer» Answer: 1:8 is my GOOD FRIEND

5508.

18Letſ (1)= 3.S'(1) - 3.8(1)=-4 and g'(1) =The derivative of V[S(x)] + [g ()3Wr: 1. xatxlis

Answer»

Answer:

1:8 is my GOOD FRIEND

Discussion

5509.	The two rational number between 2upon9 and 7upon9
Answer» Answer: 7/9 and 8/9 Step-by-step explanation: Multiply 2/9 and 7/9 with 1 more than the required number of rational numbers. = 2/9 x 3 and 7/9 x 3 = 6/9 and 21/9 Thus TWO rational numbers are 7/9 and 8/9 Mark me as BRAINLIEST if this helped you.

5509.

The two rational number between 2upon9 and 7upon9

Answer»

Answer:

7/9 and 8/9

Step-by-step explanation:

Multiply 2/9 and 7/9 with 1 more than the required number of rational numbers.

= 2/9 x 3 and 7/9 x 3

= 6/9 and 21/9

Thus TWO rational numbers are 7/9 and 8/9

Mark me as BRAINLIEST if this helped you.

Discussion

5510.	Using repeated subtraction to solve the problem division 90 diveded by 5
Answer» ANSWER: uwhahabanqkakamMNznsnjajw

5510.

Using repeated subtraction to solve the problem division 90 diveded by 5

Answer»

ANSWER:

uwhahabanqkakamMNznsnjajw

Discussion

5511.	Locate √26 on the number line.
Answer» ANSWER: Hello please follow this steps 1) DRAW a line AB of unit 5 2) now draw a pendulam line on 1 unit 3) make the hypotenus . that will be square root of 26. TAKE 0 as centre and take the pencil at the end of a hypotenus then make an acr.... where it will meet it will square root of 26

5511.

Locate √26 on the number line.

Answer»

ANSWER:

Hello please follow this steps

1) DRAW a line AB of unit 5

2) now draw a pendulam line on 1 unit

3) make the hypotenus . that will be square root of 26.

TAKE 0 as centre and take the pencil at the end of a hypotenus then make an acr.... where it will meet it will square root of 26

Discussion

5512.	What is th value of 5 ïn 857963 5 is in the place .
Answer» ANSWER: the VALUE of 5 is TEN THOUSANDS

5512.

What is th value of 5 ïn 857963 5 is in the place .

Answer»

ANSWER:

the VALUE of 5 is TEN THOUSANDS

Discussion

5513.	Twenty-five se hundred take twin prime number batao
Answer» Step-by-step explanation: The first 25 prime NUMBERS (all the PRIMES less than 100) are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

5513.

Twenty-five se hundred take twin prime number batao

Answer»

Step-by-step explanation:

The first 25 prime NUMBERS (all the PRIMES less than 100) are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

Discussion

5514.	The two rational number between 2_7and7_9are
Answer» ANSWER: HOPE it is HELPFUL to you☺️☺️ Step-by-step explanation: 2/7×2/2 = 4/ 14 7/9 ×2/2 =14/18

5514.

The two rational number between 2_7and7_9are

Answer»

ANSWER:

HOPE it is HELPFUL to you☺️☺️

Step-by-step explanation:

2/7×2/2 = 4/ 14

7/9 ×2/2 =14/18

Discussion

5515.	The present age of rituis y years after 10 years what will be the age of ritu
Answer» ANSWER: 10+y Step-by-step EXPLANATION: we'll ADD TEN to y. and HEAR is your answer

5515.

The present age of rituis y years after 10 years what will be the age of ritu

Answer»

ANSWER:

10+y

Step-by-step EXPLANATION:

we'll ADD TEN to y.

and HEAR is your answer

Discussion

5516.	If 1 is added to a number whatsoever answers so what name is called the number
Answer» ANSWER: NUMBER is CALLED as it's SUCCESSOR

5516.

If 1 is added to a number whatsoever answers so what name is called the number

Answer»

ANSWER:

NUMBER is CALLED as it's SUCCESSOR

Discussion

5517.	The value of [[(-2)³ ] × (-2)^7] ÷[3×4^6]
Answer» Answer: 12 Step-by-step explanation: [[ -8 ] × ( - 128 )] ÷ [ 3 × 4096 ] [ - 8 × - 128 ] ÷ [ 3 × 4096 ] [ 1024 ÷ 12288 12 Ans

5517.

The value of [[(-2)³ ] × (-2)^7] ÷[3×4^6]

Answer»

Answer:

12

Step-by-step explanation:

[[ -8 ] × ( - 128 )] ÷ [ 3 × 4096 ]
[ - 8 × - 128 ] ÷ [ 3 × 4096 ]
[ 1024 ÷ 12288
12 Ans

Discussion

5518.	if 4/2 ribbon is required to decorate a rectangular box how much ribbon is needed to decorate a square box?
Answer» Answer: Length of ribbon = 120 cm Vol 84 Explanation - TOTAL length of ribbon required to wrap a RECTANGULAR gift is given by - Length of ribbon = 21+ 2b + 4t + extra Length of ribbon = 2×30 + 2×20 + 4×2 + 12 Length of ribbon = 120 cm Hence, total length of ribbon required to wrap a rectangular gift is 120 cm. Thanks dear. HOPE this helps you...

5518.

if 4/2 ribbon is required to decorate a rectangular box how much ribbon is needed to decorate a square box?

Answer»

Answer:

Length of ribbon = 120 cm

Vol 84

Explanation -

TOTAL length of ribbon required to wrap a RECTANGULAR gift is given by -

Length of ribbon = 21+ 2b + 4t + extra

Length of ribbon = 2×30 + 2×20 + 4×2 +

12

Length of ribbon = 120 cm

Hence, total length of ribbon required to wrap a rectangular gift is 120 cm.

Thanks dear. HOPE this helps you...

Discussion

5519.	100 words on an indian maathematician
Answer» $\huge\mathfrak\blue{answer}$ $\huge\fbox\pink{Brahmagupta}$ Brahmagupta was the first to give rules to compute with zero. The texts composed by Brahmagupta were in ELLIPTIC verse[clarification needed] in Sanskrit, as was common practice in Indian mathematics. As no proofs are given, it is not known how Brahmagupta's results were derived Brahmagupta (c. 598 – c. 668 CE) was an Indian mathematician and astronomer. He is the AUTHOR of two early works on mathematics and astronomy: the Brāhmasphuṭasiddhānta (BSS, "correctly established doctrine of Brahma", dated 628), a theoretical treatise, and the Khaṇḍakhādyaka ("edible bite", dated 665), a more practical text. Brahmagupta was born in 598 CE according to his own statement. He lived in Bhillamāla in Gurjaradesa.(modern Bhinmal in Rajasthan, India) during the reign of the Chavda dynasty ruler, Vyagrahamukha. He was the son of Jishnugupta and was a Hindu by religion, in particular, a Shaivite.[3] He lived and worked there for a good part of his life. Prithudaka Svamin, a later commentator, called him Bhillamalacharya, the teacher from Bhillamala. Bhillamala was the capital of the Gurjaradesa, the second-largest kingdom of Western India, comprising southern Rajasthan and northern GUJARAT in modern-day India. It was also a centre of learning for mathematics and astronomy. Brahmagupta became an astronomer of the Brahmapaksha school, one of the four major schools of Indian astronomy during this period. He studied the five traditional Siddhantas on Indian astronomy as well as the work of other astronomers including Aryabhata I, Latadeva, Pradyumna, Varahamihira, Simha, Srisena, Vijayanandin and Vishnuchandra. In the year 628, at the age of 30, he composed the Brāhmasphuṭasiddhānta ("improved treatise of Brahma") which is believed to be a revised version of the received Siddhanta of the Brahmapaksha school of astronomy. Scholars state that he INCORPORATED a great deal of originality to his revision, adding a considerable amount of new material. The book consists of 24 chapters with 1008 verses in the ārya metre. A good deal of it is astronomy, but it also contains key chapters on mathematics, including algebra, geometry, trigonometry and algorithmics, which are believed to contain new insights due to Brahmagupta himself. Later, Brahmagupta moved to Ujjaini, AVANTI,which was also a major centre for astronomy in central India. At the age of 67, he composed his next well-known work Khanda-khādyaka, a practical manual of Indian astronomy in the karana category meant to be used by students. Brahmagupta died in 668 CE, and he is presumed to have died in Ujjain.

5519.

100 words on an indian maathematician

Answer»

$\huge\mathfrak\blue{answer}$

$\huge\fbox\pink{Brahmagupta}$

Brahmagupta was the first to give rules to compute with zero. The texts composed by Brahmagupta were in ELLIPTIC verse[clarification needed] in Sanskrit, as was common practice in Indian mathematics. As no proofs are given, it is not known how Brahmagupta's results were derived

Brahmagupta (c. 598 – c. 668 CE) was an Indian mathematician and astronomer. He is the AUTHOR of two early works on mathematics and astronomy: the Brāhmasphuṭasiddhānta (BSS, "correctly established doctrine of Brahma", dated 628), a theoretical treatise, and the Khaṇḍakhādyaka ("edible bite", dated 665), a more practical text.

Brahmagupta was born in 598 CE according to his own statement. He lived in Bhillamāla in Gurjaradesa.(modern Bhinmal in Rajasthan, India) during the reign of the Chavda dynasty ruler, Vyagrahamukha. He was the son of Jishnugupta and was a Hindu by religion, in particular, a Shaivite.[3] He lived and worked there for a good part of his life. Prithudaka Svamin, a later commentator, called him Bhillamalacharya, the teacher from Bhillamala.

Bhillamala was the capital of the Gurjaradesa, the second-largest kingdom of Western India, comprising southern Rajasthan and northern GUJARAT in modern-day India. It was also a centre of learning for mathematics and astronomy. Brahmagupta became an astronomer of the Brahmapaksha school, one of the four major schools of Indian astronomy during this period. He studied the five traditional Siddhantas on Indian astronomy as well as the work of other astronomers including Aryabhata I, Latadeva, Pradyumna, Varahamihira, Simha, Srisena, Vijayanandin and Vishnuchandra.

In the year 628, at the age of 30, he composed the Brāhmasphuṭasiddhānta ("improved treatise of Brahma") which is believed to be a revised version of the received Siddhanta of the Brahmapaksha school of astronomy. Scholars state that he INCORPORATED a great deal of originality to his revision, adding a considerable amount of new material. The book consists of 24 chapters with 1008 verses in the ārya metre. A good deal of it is astronomy, but it also contains key chapters on mathematics, including algebra, geometry, trigonometry and algorithmics, which are believed to contain new insights due to Brahmagupta himself.

Later, Brahmagupta moved to Ujjaini, AVANTI,which was also a major centre for astronomy in central India. At the age of 67, he composed his next well-known work Khanda-khādyaka, a practical manual of Indian astronomy in the karana category meant to be used by students.

Brahmagupta died in 668 CE, and he is presumed to have died in Ujjain.

Discussion

5520.	Find the median score of 17 12 7 27 9 15
Answer» Answer: 17 - 8.5 12 - 6 7 - 3.5 27- 13.5 9 - 4.5 15- 7.5

5520.

Find the median score of 17 12 7 27 9 15

Answer»

Answer:

17 - 8.5

12 - 6

7 - 3.5

27- 13.5

9 - 4.5

15- 7.5

Discussion

5521.	6xsquare-7x-3 polynomial
Answer» $6 {x}^{2} - 7x - 3$ $6 {x}^{2} - 9x + 2x - 3$ $3x(2x - 3) + 1(2x - 3)$ $(2x - 3)(3x + 1)$

5521.

6xsquare-7x-3 polynomial

Answer»

$6 {x}^{2} - 7x - 3$

$6 {x}^{2} - 9x + 2x - 3$

$3x(2x - 3) + 1(2x - 3)$

$(2x - 3)(3x + 1)$

Discussion

5522.	If Sinα + Sinβ + Sinγ = 3 then Cosα+Cosβ+Cosγ equals
Answer» ANSWER: it VALUE will be ZERO(0)

5522.

If Sinα + Sinβ + Sinγ = 3 then Cosα+Cosβ+Cosγ equals

Answer»

ANSWER:

it VALUE will be ZERO(0)

Discussion

5523.	Find the square root of 5.3361 in long division method
Answer» ANSWER: 1099361 this is the answer

5523.

Find the square root of 5.3361 in long division method

Answer»

ANSWER:

1099361 this is the answer

Discussion

5524.	True/ False 1.1 divide by 0 is not defined.
Answer» Answer: true Step-by-step EXPLANATION: YES it is not defined mark me as brainliest PLEASE

5524.

True/ False 1.1 divide by 0 is not defined.

Answer»

Answer:

true

Step-by-step EXPLANATION:

YES it is not defined

mark me as brainliest PLEASE

Discussion

5525.	The coordinatoes of origin are
Answer» ANSWER: COORDINATE of ORIGIN are (0, 0)

5525.

The coordinatoes of origin are

Answer»

ANSWER:

COORDINATE of ORIGIN are (0, 0)

Discussion

5526.	How did they get 22/7Why is it pi equals to 3.14
Answer» your CORRECT ANSWER is 3.14 Step-by-step EXPLANATION: which SUM

5526.

How did they get 22/7Why is it pi equals to 3.14

Answer»

your CORRECT ANSWER is 3.14

Step-by-step EXPLANATION:

which SUM

Discussion

5527.	It the given figure if AB is parallel to QR then the value of x is
Answer» HOPE It's HELPFUL for you PLZ MARK Me As BRAINLISTS

5527.

It the given figure if AB is parallel to QR then the value of x is

Answer»

HOPE It's HELPFUL for you

PLZ MARK Me As BRAINLISTS

Discussion

5528.	How many billions are there in 7 arab
Answer» ANSWER: I THINK 7 ARAB =7 BILLION

5528.

How many billions are there in 7 arab

Answer»

ANSWER:

I THINK 7 ARAB =7 BILLION

Discussion

5529.	Which of the following is represented by the point P shown on the number line below? A. 9/12 B. 2 1/4 C. 2 1/3 D. 2 1/5
Answer» Step-by-step EXPLANATION: where is the no LINE can U SEND

5529.

Which of the following is represented by the point P shown on the number line below? A. 9/12 B. 2 1/4 C. 2 1/3 D. 2 1/5

Answer»

Step-by-step EXPLANATION:

where is the no LINE can U SEND

Discussion

5530.	Find the value of X,Y,Z by matrix inverde method X+Y+Z=62x+5y+5z=272x+5y+11z=45
Answer» Answer: 538%-/4238436875578521+733543384--43325+7525755

5530.

Find the value of X,Y,Z by matrix inverde method X+Y+Z=62x+5y+5z=272x+5y+11z=45

Answer»

Answer:

538%*-/4238436875578521+*733543384--43325+7525755

Discussion

5531.	Find some sequence which have no algebraic form
Answer» Step-by-step explanation: Given arithmetic sequence is 9, 15, 21,. First term = a = 9 Common difference = d =15 9 = 6 (A) For natural number N nth term = [(n−1)X6]+9=6n+3 where n=1,2,3, Hence algebraic form of the sequence 9,15,21,. is x n =6n+3. (B) nth term =6n+3 25 th term =6(25)+3=150+3=153 (C) Sum of first n terms is given by, S n = 2 1 n[X 1 +X n ] Sum of 24 terms is S 24 = 2 1 n[X 1 +X 2 4]= 2 25 [9+147]=1950 Sum of 50 terms is S 50 = 2 1 n[X 1 +X 50 ]= 2 50 [9+6(50)+3]=7800 Sum of terms from twenty FIFTH to fiftieth =S 50 −S 24 =7800−1950 =5850 (D) Let sum of first n terms is 2015, S n = 2 1 n[X 1 +X n ] 2015= 2 1 n[9+6n+3] 2015=3n 2 +6n 3n 2 +6n−2015=0 Solving above equation for n, the value of n is not a natural number. Hence 2015 can not be the sum of some terms of this sequence.

5531.

Find some sequence which have no algebraic form

Answer»

Step-by-step explanation:

Given arithmetic sequence is 9, 15, 21,.

First term = a = 9

Common difference = d =15 9 = 6

(A) For natural number N

nth term = [(n−1)X6]+9=6n+3 where n=1,2,3,

Hence algebraic form of the sequence 9,15,21,. is x

n

=6n+3.

(B) nth term =6n+3

25

th

term =6(25)+3=150+3=153

(C) Sum of first n terms is given by,

S

n

=

2

1

n[X

1

+X

n

]

Sum of 24 terms is

S

24

=

2

1

n[X

1

+X

2

4]=

2

25

[9+147]=1950

Sum of 50 terms is

S

50

=

2

1

n[X

1

+X

50

]=

2

50

[9+6(50)+3]=7800

Sum of terms from twenty FIFTH to fiftieth

=S

50

−S

24

=7800−1950

=5850

(D) Let sum of first n terms is 2015,

S

n

=

2

1

n[X

1

+X

n

]

2015=

2

1

n[9+6n+3]

2015=3n

2

+6n

3n

2

+6n−2015=0

Solving above equation for n, the value of n is not a natural number.

Hence 2015 can not be the sum of some terms of this sequence.

Discussion

5532.	You close your link so fast why
Answer» ANSWER: FIRST i don't KNOW 2) I don't know 3) i don't know

5532.

You close your link so fast why

Answer»

ANSWER:

FIRST i don't KNOW

2) I don't know

3) i don't know

Discussion

5533.	4subtract from a number and them divided by 7,given 13as the quotient. Find the number
Answer» Answer: Given: SUBTRACT 4 Then DIVIDE by 7 Quotient is 13 Soln: 7×13=91 91+4=95 Hence,The NUMBER is 95

5533.

4subtract from a number and them divided by 7,given 13as the quotient. Find the number

Answer»

Answer:

Given:

SUBTRACT 4

Then DIVIDE by 7

Quotient is 13

Soln:

7×13=91

91+4=95

Hence,The NUMBER is 95

Discussion

5534.	Find three rational numbers between 3 /2 and 4/ 3 .
Answer» ANSWER: i am not able to send this pic in ONE so i am sending two hope it is HELPFUL ☺️☺️☺️☺️ Step-by-step explanation: 3/2×3/3 = 9/6 4/3 × 2/2 = 8/6 this you can ALSO write in whole. in whole you will write : 9/6 = 1 whole 3/6 and for 8/6 = 1 whole 2/6

5534.

Find three rational numbers between 3 /2 and 4/ 3 .

Answer»

ANSWER:

i am not able to send this pic in ONE so i am sending two

hope it is HELPFUL ☺️☺️☺️☺️

Step-by-step explanation:

3/2×3/3 = 9/6

4/3 × 2/2 = 8/6

this you can ALSO write in whole.

in whole you will write : 9/6 = 1 whole 3/6

and for 8/6 = 1 whole 2/6

Discussion

5535.	The product of two rational numbers is (-6÷7) . If out of these one number is (-8÷5) , then find the second number.
Answer» ANSWER: Answer is ATTACHED here

5535.

The product of two rational numbers is (-6÷7) . If out of these one number is (-8÷5) , then find the second number.

Answer»

ANSWER:

Answer is ATTACHED here

Discussion

5536.	The mean of 10 observations was found to be 30. However , later it was found that an observation 23 was misread as 32 .find the actual mean
Answer» Step-by-step explanation: Caste-based trade among the Nakarattars of Tamil NADU This is not to say that the Nakarattar banking system resembled an economist’s model of WESTERN-style banking systems … the Nakarattars loaned and deposited money with one another in caste-defined social relationships based on business territory, residential location, descent, marriage, and common cult membership. Unlike in modern Western banking systems, it was the reputation, decisions, and reserve deposits shared among exchange spheres defined according to these principles, and not a government-controlled central bank, that … assured public confidence in individual Nakarattars as representatives of the caste as a whole. In other words, the Nakarattar banking system was a caste-based banking system. Individual Nakarattars organised their lives around participation in and management of various communal institutions adapted to the task of accumulating and distributing reserves of capital. Source: Rudner Read the extracts from Caste and Capitalism in Colonial India(Rudner 1994) in the box and answer the following questions. 1.What are the significant differences between the Nakarattar bankingsystem and the modern Western banking system, according to the author? 2.What are the different ways in which Nakarattar trading andbanking activities are linked to other social structures? 3.Can you THINK of EXAMPLES within the modern capitalist economy whereeconomic activities are similarly ‘embedded’ in social structures?

5536.

The mean of 10 observations was found to be 30. However , later it was found that an observation 23 was misread as 32 .find the actual mean

Answer»

Step-by-step explanation:

Caste-based trade among the Nakarattars of Tamil NADU This is not to say that the Nakarattar banking system resembled an economist’s model of WESTERN-style banking systems … the Nakarattars loaned and deposited money with one another in caste-defined social relationships based on business territory, residential location, descent, marriage, and common cult membership. Unlike in modern Western banking systems, it was the reputation, decisions, and reserve deposits shared among exchange spheres defined according to these principles, and not a government-controlled central bank, that … assured public confidence in individual Nakarattars as representatives of the caste as a whole. In other words, the Nakarattar banking system was a caste-based banking system. Individual Nakarattars organised their lives around participation in and management of various communal institutions adapted to the task of accumulating and distributing reserves of capital. Source: Rudner

Read the extracts from Caste and Capitalism in Colonial India(Rudner 1994) in the box and answer the following questions.

1.What are the significant differences between the Nakarattar bankingsystem and the modern Western banking system, according to the author?

2.What are the different ways in which Nakarattar trading andbanking activities are linked to other social structures?

3.Can you THINK of EXAMPLES within the modern capitalist economy whereeconomic activities are similarly ‘embedded’ in social structures?

Discussion

5537.	If H.C.F(a,b)=1 then final L.C.M(a,b)
Answer» ANSWER: LCM=aB Step-by-step EXPLANATION: HCF(a,b)=1 LCM(a,b) HCFxLCM ab=1xLCM = LCM=ab

5537.

If H.C.F(a,b)=1 then final L.C.M(a,b)

Answer»

ANSWER:

LCM=aB

Step-by-step EXPLANATION:

HCF(a,b)=1

LCM(a,b)

HCFxLCM
ab=1xLCM
= LCM=ab

Discussion

5538.	A random vector (X, Y, Z) has joint density given by . f (x, y,z) = k exp [− 1/2 (2x2 − 2xy + y2 + z2 + 2x − 6y) . Compute k.
Answer» izfkgxogxlgxogxglxgoxgoxgo Step-by-step EXPLANATION: oyxypxoyxpgxgppgp EJ zieixrx or jxbrix EXJ JB cogxogxogxxogxgoxogxoxgpgxg 8ggy0ogxoxyxy9xyx0yxc9yxh0xoxogxphxgogo hpcpchp

5538.

A random vector (X, Y, Z) has joint density given by . f (x, y,z) = k exp [− 1/2 (2x2 − 2xy + y2 + z2 + 2x − 6y) . Compute k.

Answer»

izfkgxogxlgxogxglxgoxgoxgo

Step-by-step EXPLANATION:

oyxypxoyxpgxgppgp

EJ zieixrx or jxbrix EXJ JB cogxogxogxxogxgoxogxoxgpgxg 8ggy0ogxoxyxy9xyx0yxc9yxh0xoxogxphxgogo hpcpchp

Discussion

5539.	Prove thatNeed proper answer.
Answer» HOPE the above IMAGE HELPS you

Discussion

5540.	व्हाट इज द मल्टीप्ल ऑफ
Answer» ANSWER: व्हाट इज द मल्टीप्ल ऑफ Step-by-step EXPLANATION: व्हाट इज द मल्टीप्ल ऑफ

5540.

व्हाट इज द मल्टीप्ल ऑफ

Answer»

ANSWER:

व्हाट इज द मल्टीप्ल ऑफ

Step-by-step EXPLANATION:

व्हाट इज द मल्टीप्ल ऑफ

Discussion

5541.	The length, breadth and height of a hall are 9.76m 7.93m and 1.83m respectively. Find the longest rod which can measure the three dimensions an exact number of times.
Answer» ANSWER: 56 is the Answer PLEASE MARK me as BRAINLIST

5541.

The length, breadth and height of a hall are 9.76m 7.93m and 1.83m respectively. Find the longest rod which can measure the three dimensions an exact number of times.

Answer»

ANSWER:

56 is the Answer PLEASE MARK me as BRAINLIST

Discussion

5542.	How to multiply numbers in pq form?example: 5/2-(4/3) or 1/28/5
Answer» Answer: HI PLEASE ask more tough QUESTIONS

5542.

How to multiply numbers in pq form?example: 5/2-(4/3) or 1/28/5

Answer»

Answer:

HI PLEASE ask more tough QUESTIONS

Discussion

5543.	(ii) 4x2 + 15 = 16x by Quardratic formula
Answer» Answer: 4x2+ 15=16 4x2-16x+15=0 4x2-10x-6x+15=0 2x(2x-5)-3(2x-5)=0 either ( 2x-3)=0 or 2x-5=0 X=3/2 x= 5/2

5543.

(ii) 4x2 + 15 = 16x by Quardratic formula

Answer»

Answer:

4x2+ 15=16

4x2-16x+15=0

4x2-10x-6x+15=0

2x(2x-5)-3(2x-5)=0

either ( 2x-3)=0 or 2x-5=0

X=3/2 x= 5/2

Discussion

5544.	if I wish to train for long distance running, would a morning jog of 10×4 strides per day adequate? How many strides make a kilometre or a metre ?
Answer» Step-by-step EXPLANATION: oli KE ki ekhekejeu4b3ebsvsjebjs10jzkzsnsnbs sndbdndbdnd sdndkbdkedmrnme ed fnkdnd dndmd.fdmr md end MN md.error rnrmr rrne.rm.rd.end end d.e me mr.rnrr. rng mn r.to rn t.to mn. f.f r dnfnrnrjrbrr tnrmr MB r.r.resolution mn rnr.4.rnrn3em mn. er *mftnnrrn* mn *end* *bkn* r mn r r.rnrmrmddnfjfbfb5ubrndbdmd

5544.

if I wish to train for long distance running, would a morning jog of 10×4 strides per day adequate? How many strides make a kilometre or a metre ?

Answer»

Step-by-step EXPLANATION:

oli KE ki ekhekejeu4b3ebsvsjebjs10jzkzsnsnbs sndbdndbdnd

sdndkbdkedmrnme

ed

fnkdnd

dndmd.fdmr

md

end MN md.error

rnrmr

rrne.rm.rd.end

end

d.e me mr.rnrr.

rng mn r.to rn t.to mn. f.f r

dnfnrnrjrbrr

tnrmr MB r.r.resolution mn rnr.4.rnrn3em mn. er mftnnrrn mn end bkn r mn r r.rnrmrmddnfjfbfb5ubrndbdmd

Discussion

5545.	Factorise 11 p^4-4p^2q^2-7 p^4
Answer» Answer: 4 4 − 4 2 2 4p^{4}-4p^{2}q^{2} 4p4−4p2q2 Step-by-step EXPLANATION: ok

5545.

Factorise 11 p^4-4p^2q^2-7 p^4

Answer»

Answer:

4

−

4

2

4p^{4}-4p^{2}q^{2}

4p4−4p2q2

Step-by-step EXPLANATION:

ok

Discussion

5546.	¤° Integers°¤Find the product of each of the following: a. (-12)×(-150)b.(-17)×6×(-10)If you see the pic so do that
Answer» Step-by-step explanation: ¤° Integers°¤ Find the product of each of the FOLLOWING: a. (-12)×(-150) B.(-17)×6×(-10) If you see the pic so do that

5546.

¤° Integers°¤Find the product of each of the following: a. (-12)×(-150)b.(-17)×6×(-10)If you see the pic so do that

Answer»

Step-by-step explanation:

¤° Integers°¤

Find the product of each of the FOLLOWING:

a. (-12)×(-150)

B.(-17)×6×(-10)

If you see the pic so do that

Discussion

5547.	3/x+2/y= 109/x-7/y= 10.5
Answer» ANSWER: what we have to do in this ....ahbwjwhwhwhwiw8wuwgevshs

5547.

3/x+2/y= 109/x-7/y= 10.5

Answer»

ANSWER:

what we have to do in this ....ahbwjwhwhwhwiw8wuwgevshs

Discussion

5548.	Simplify √a³b⁴.√a⁴b³ please answer the question pleasssee
Answer» $\huge\fbox\red{★᭄ꦿ᭄Answer࿐}$ $\sqrt{ {a}^{3} {b}^{4} } \times \sqrt{ {a}^{4} {b}^{3} }$ $= \sqrt{ {a}^{3} {a}^{4} {b}^{4} {b}^{3} }$ $= \sqrt{ {a}^{6} {b}^{6} } \times ab$ $= {a}^{3} {b}^{3} \sqrt{ab}$ ${\large{\underline{{\bold{ \pink{\tt{ɪʈzʉɲɪvəɹʂɐɭʛɪɾɭ³ᘙ}}}}}}}$

5548.

Simplify √a³b⁴.√a⁴b³ please answer the question pleasssee

Answer»

$\huge\fbox\red{★᭄ꦿ᭄Answer࿐}$

$\sqrt{ {a}^{3} {b}^{4} } \times \sqrt{ {a}^{4} {b}^{3} }$

$= \sqrt{ {a}^{3} {a}^{4} {b}^{4} {b}^{3} }$

$= \sqrt{ {a}^{6} {b}^{6} } \times ab$

$= {a}^{3} {b}^{3} \sqrt{ab}$

${\large{\underline{{\bold{ \pink{\tt{ɪʈzʉɲɪvəɹʂɐɭʛɪɾɭ³ᘙ}}}}}}}$

Discussion

5549.	Find the value of 204 x 196
Answer» Answer: 39984 Step-by-step EXPLANATION: you can USE a CALCULATOR next TIME. anyways have a great day!

5549.

Find the value of 204 x 196

Answer»

Answer:

39984

Step-by-step EXPLANATION:

you can USE a CALCULATOR next TIME. anyways have a great day!

Discussion

5550.	Thabk you all for supporting me.
Answer» ANSWER: You are WELCOME Step-by-step EXPLANATION: You are welcome

5550.

Thabk you all for supporting me.

Answer»

ANSWER:

You are WELCOME

Step-by-step EXPLANATION:

You are welcome

Discussion

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tnrmr MB r.r.resolution mn rnr.4.rnrn3em mn. er mftnnrrn mn end bkn r mn r r.rnrmrmddnfjfbfb5ubrndbdmd

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व्हाट इज द मल्टीप्ल ऑफ

The length, breadth and height of a hall are 9.76m 7.93m and 1.83m respectively. Find the longest rod which can measure the three dimensions an exact number of times.

How to multiply numbers in pq form?example: 5/2-(4/3) or 1/28/5

(ii) 4x2 + 15 = 16x by Quardratic formula

if I wish to train for long distance running, would a morning jog of 10×4 strides per day adequate? How many strides make a kilometre or a metre ?

Factorise 11 p^4-4p^2q^2-7 p^4

¤° Integers°¤Find the product of each of the following: a. (-12)×(-150)b.(-17)×6×(-10)If you see the pic so do that

Simplify √a³b⁴.√a⁴b³ please answer the question pleasssee

Find the value of 204 x 196

Thabk you all for supporting me.