332354 + Interview Questions in Secondary School in Math Page 124 InterviewSolution

6151.	2 root 3 + 5 root 2 by root 48 + root 18
Answer» Answer: 8.72 is answer of this QUESTION. Step-by-step EXPLANATION: please MAKE me brainlists

6151.

2 root 3 + 5 root 2 by root 48 + root 18

Answer»

Answer:

8.72 is answer of this QUESTION.

Step-by-step EXPLANATION:

please MAKE me brainlists

Discussion

6152.	12^x-2 = 4^x ,find the value of x
Answer» Answer: 15-Aug-2019 · 2 answers Answer: x-4=12/x. x(x-4)=12. x^2-4x=12. x^2-4x-12=0. x^2+2x-6x-12=0. x(x+ 2)-6(x+2)=0. (x+2)(x-6)=0. put x+2=0. x=-2. Step-by-step EXPLANATION:

6152.

12^x-2 = 4^x ,find the value of x

Answer»

Answer:

15-Aug-2019 · 2 answers

Answer: x-4=12/x. x(x-4)=12. x^2-4x=12. x^2-4x-12=0. x^2+2x-6x-12=0. x(x+ 2)-6(x+2)=0. (x+2)(x-6)=0. put x+2=0. x=-2.

Step-by-step EXPLANATION:

Discussion

6153.	Convert 0.65 into fraction and its lowest fom
Answer» ANSWER: your answer is 65/100 Step-by-step EXPLANATION: PLEASE MARK a BRAINLIST answer

6153.

Convert 0.65 into fraction and its lowest fom

Answer»

ANSWER:

your answer is 65/100

Step-by-step EXPLANATION:

PLEASE MARK a BRAINLIST answer

Discussion

6154.	The temperature on a cold day is -3 c . It rises by 5 c What is temprature now
Answer» Now the TEMPERATURE is 2 C

Discussion

6155.	Find the product of two rational number is 18/5 and 40/49
Answer» Step-by-step EXPLANATION: Answer Correct OPTION is D 64 27 LET the other NUMBER be x ∴ x× 3 −4 = 1

6155.

Find the product of two rational number is 18/5 and 40/49

Answer»

Step-by-step EXPLANATION:

Answer

Correct OPTION is

D

64

27

LET the other NUMBER be x

∴ x×

3

−4

= 1

Discussion

6156.	Find the sum of three consecutive even integers succeeding (-102) and three consecutive odd integers preceeding (-95)
Answer» ANSWER: *Answer:. I CONGRATULATE you on your wedding anniversary and wish you that your family happiness WOULD never run out! it's a big day for you both on this great occasion!*

6156.

Find the sum of three consecutive even integers succeeding (-102) and three consecutive odd integers preceeding (-95)

Answer»

ANSWER:

Answer:. I CONGRATULATE you on your wedding anniversary and wish you that your family happiness WOULD never run out! it's a big day for you both on this great occasion!

Discussion

6157.	In which quadrant or on which axis do Following points lie (-2,4) (3,-1) (-1,2) (1,1)
Answer» (-2.4) ---> II Quadrant (3,-1) -----> IV Quadrant (-1,2)-----> II Quadrant (1,1)-----> I Quadrant Hope it HELPS :)

6157.

In which quadrant or on which axis do Following points lie (-2,4) (3,-1) (-1,2) (1,1)

Answer»

(-2.4) ---> II Quadrant

(3,-1) -----> IV Quadrant

(-1,2)-----> II Quadrant

(1,1)-----> I Quadrant

Hope it HELPS :)

Discussion

6158.	Fill in the blanks1. ORDINAL NUMBERS TELLS US ABOUT THE. of AN OBJECT OR PERSON IN A GROUP.
Answer» ANSWER: position Step-by-step EXPLANATION: HOPE it HELPED :)

6158.

Fill in the blanks1. ORDINAL NUMBERS TELLS US ABOUT THE. of AN OBJECT OR PERSON IN A GROUP.

Answer»

ANSWER:

position

Step-by-step EXPLANATION:

HOPE it HELPED :)

Discussion

6159.	Find the domain of x^2-x-1
Answer» ANSWER: Domin=x^2 and RANGE =-x-1

6159.

Find the domain of x^2-x-1

Answer»

ANSWER:

Domin=x^2 and RANGE =-x-1

Discussion

6160.	For any two nonsingular square matrices A and B, (AB)−1=
Answer» ANSWER: answer is 12345 Step-by-step EXPLANATION: ',smsjcjamqufxkxi9jjrk1ajcjcjwn2kdxi

6160.

For any two nonsingular square matrices A and B, (AB)−1=

Answer»

ANSWER:

answer is 12345

Step-by-step EXPLANATION:

',smsjcjamqufxkxi9jjrk1ajcjcjwn2kdxi

Discussion

6161.	Find the value of cosec 20° – sec 20°.
Answer» ☀️ Given that, we have to FIND the value of √3 COSSEC 20° - sec 20°. ⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━ T H E R E F O R E, As we KNOW that, $\bigstar \;\; \large{\underline{\boxed{ \bf cossec \theta = \dfrac{1}{sin \theta \; }}}}$ $\bigstar \;\; \large{\underline{\boxed{ \bf sec \theta = \dfrac{1}{cos \theta \; }}}}$ $\sf : \; \implies \dfrac{\sqrt{3}}{sin \; 20^{ \circ }} - \dfrac{1}{cos \; 20^{ \circ}}$ $\sf : \; \implies 2 \bigg( \dfrac{ \dfrac{\sqrt{3}}{2}}{sin \; 20^{ \circ }} - \dfrac{\dfrac{1}{2}}{cos \; 20^{ \circ}} \bigg)$ $\bigstar \;\; \large{\underline{\boxed{ \bf cos \; 30^{ \circ } = sin \; 60^{ \circ } =\dfrac{ \sqrt{3}}{2} \; }}}}$ $\sf : \; \implies 2 \bigg( \dfrac{cos\; 30^{\circ}}{sin \; 20^{ \circ }} - \dfrac{sin \; 30^{\circ}}{cos \; 20^{ \circ}} \bigg)$ $\sf : \; \implies 2 \bigg( \dfrac{cos\; 30^{\circ} \; cos\; 20^{\circ} - sin \; 30^{\circ} \; sin \; 20^{\circ}}{sin \; 20^{ \circ } \; cos \; 20^{\circ}} \bigg)$ $\bigstar \;\; \large{\underline{\boxed{ \bf (cos \; A \times cos \; B )- ( sin \; A \times sin \; B ) = cos( A + B )\; }}}}$ $\sf : \; \implies 2 \bigg( \dfrac{cos\; ( 50^{\circ}) }{sin \; 20^{ \circ } \; cos \; 20^{\circ}} \bigg)$ $\sf : \; \implies 2 \times 2 \bigg( \dfrac{cos\; ( 50^{\circ}) }{ 2 \times sin \; 20^{ \circ } \; cos \; 20^{\circ}} \bigg)$ $\bigstar \;\; \large{\underline{\boxed{ \bf 2 \times sin \; A \times cos \; A = sin ( 2A )\; }}}}$ $\sf : \; \implies <klux>4</klux> \bigg( \dfrac{cos\; ( 50^{\circ}) }{sin \; 40^{ \circ}} \bigg)$ $\sf : \; \implies 4 \bigg( \dfrac{cos\; ( 50^{\circ}) }{sin \; (90^{ \circ} - 50^{\circ})} \bigg)$ $\bigstar \;\; \large{\underline{\boxed{ \bf sin ( 90 - \theta ) = cos \theta\; }}}}$ $\sf : \; \implies 4 \bigg( \dfrac{cos\; ( 50^{\circ}) }{cos50^{\circ}} \bigg)$ $\sf : \; \implies 4 \times 1$ $\boxed{\bf{ \maltese \;\; \sqrt{3}\; cossec \; 20^{\circ} - sec\; 20^{\circ} \implies 4 }}$ ⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━ Henceforth, the value is 4. ADD to knowledge :- $\boxed{\begin{minipage}{7 cm}Fundamental Trigonometric Identities \\ \\$\sin^2\theta + \cos^2\theta=1 \\ \\1+\tan^2\theta = \sec^2\theta \\ \\1+\cot^2\theta = \text{cosec}^2 \, \theta$\end{minipage}}$ [ Note : Kindly view the answer on website brainly.in/question/43037676 ]

6161.

Find the value of cosec 20° – sec 20°.

Answer»

☀️ Given that, we have to FIND the value of √3 COSSEC 20° - sec 20°.

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━

T H E R E F O R E,

As we KNOW that,

$\bigstar \;\; \large{\underline{\boxed{ \bf cossec \theta = \dfrac{1}{sin \theta \; }}}}$

$\bigstar \;\; \large{\underline{\boxed{ \bf sec \theta = \dfrac{1}{cos \theta \; }}}}$

$\sf : \; \implies \dfrac{\sqrt{3}}{sin \; 20^{ \circ }} - \dfrac{1}{cos \; 20^{ \circ}}$

$\sf : \; \implies 2 \bigg( \dfrac{ \dfrac{\sqrt{3}}{2}}{sin \; 20^{ \circ }} - \dfrac{\dfrac{1}{2}}{cos \; 20^{ \circ}} \bigg)$

$\bigstar \;\; \large{\underline{\boxed{ \bf cos \; 30^{ \circ } = sin \; 60^{ \circ } =\dfrac{ \sqrt{3}}{2} \; }}}}$

$\sf : \; \implies 2 \bigg( \dfrac{cos\; 30^{\circ}}{sin \; 20^{ \circ }} - \dfrac{sin \; 30^{\circ}}{cos \; 20^{ \circ}} \bigg)$

$\sf : \; \implies 2 \bigg( \dfrac{cos\; 30^{\circ} \; cos\; 20^{\circ} - sin \; 30^{\circ} \; sin \; 20^{\circ}}{sin \; 20^{ \circ } \; cos \; 20^{\circ}} \bigg)$

$\bigstar \;\; \large{\underline{\boxed{ \bf (cos \; A \times cos \; B )- ( sin \; A \times sin \; B ) = cos( A + B )\; }}}}$

$\sf : \; \implies 2 \bigg( \dfrac{cos\; ( 50^{\circ}) }{sin \; 20^{ \circ } \; cos \; 20^{\circ}} \bigg)$

$\sf : \; \implies 2 \times 2 \bigg( \dfrac{cos\; ( 50^{\circ}) }{ 2 \times sin \; 20^{ \circ } \; cos \; 20^{\circ}} \bigg)$

$\bigstar \;\; \large{\underline{\boxed{ \bf 2 \times sin \; A \times cos \; A = sin ( 2A )\; }}}}$

$\sf : \; \implies <klux>4</klux> \bigg( \dfrac{cos\; ( 50^{\circ}) }{sin \; 40^{ \circ}} \bigg)$

$\sf : \; \implies 4 \bigg( \dfrac{cos\; ( 50^{\circ}) }{sin \; (90^{ \circ} - 50^{\circ})} \bigg)$

$\bigstar \;\; \large{\underline{\boxed{ \bf sin ( 90 - \theta ) = cos \theta\; }}}}$

$\sf : \; \implies 4 \bigg( \dfrac{cos\; ( 50^{\circ}) }{cos50^{\circ}} \bigg)$

$\sf : \; \implies 4 \times 1$

$\boxed{\bf{ \maltese \;\; \sqrt{3}\; cossec \; 20^{\circ} - sec\; 20^{\circ} \implies 4 }}$

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━

Henceforth, the value is 4.

ADD to knowledge :-

$\boxed{\begin{minipage}{7 cm}Fundamental Trigonometric Identities \\ \\$\sin^2\theta + \cos^2\theta=1 \\ \\1+\tan^2\theta = \sec^2\theta \\ \\1+\cot^2\theta = \text{cosec}^2 \, \theta$\end{minipage}}$

[ Note : Kindly view the answer on website brainly.in/question/43037676 ]

Discussion

6162.	Find three rational number between:3/4 and -1/3
Answer» Answer: So three RATIONAL numbers between 3AND 4 are: 61/20, 62/20, 63/20 Step-by-step EXPLANATION: Mark as Brainliest❣️

6162.

Find three rational number between:3/4 and -1/3

Answer»

Answer:

So three RATIONAL numbers between 3AND 4 are: 61/20, 62/20, 63/20

Step-by-step EXPLANATION:

Mark as Brainliest❣️

Discussion

6163.	the initial reading of a line measured by a broker scale is 4.2 cm and A final reading is 12.5 cm what is the actual length of the line
Answer» Answer:The scale is placed ALONG the line-segment putting its zero (0) MARK at A. We see the end B is at the 3 cm mark of the scale. So the LENGTH of the line-segment AB = 3 cm. Step-by-step explanation:

6163.

the initial reading of a line measured by a broker scale is 4.2 cm and A final reading is 12.5 cm what is the actual length of the line

Answer»

Answer:The scale is placed ALONG the line-segment putting its zero (0) MARK at A. We see the end B is at the 3 cm mark of the scale. So the LENGTH of the line-segment AB = 3 cm.

Step-by-step explanation:

Discussion

6164.	Find the number of 2-digit positive integers N such that tanN15° + cot~15° is an integer.
Answer» Given : tan (N15°) + cot ( N15°) is an integer To Find : number of 2-digit positive integers N Solution: tan (N15°) + cot ( N15°) = Sin (N15°)/Cos (N 15°) + Cos (N 15°) /Sin (N15°) = ( Sin² (N15°) + Cos² (N 15°) )/ Sin (N15°) Cos (N 15°) = 1/ Sin (N15°) Cos (N 15°) = 2/ 2 Sin (N15°) Cos (N 15°) = 2/ Sin (N * 30°) Sin (N * 30°) =±1 or Sin (N * 30°) = ±1/2 will give an integer Sin (N * 30°) = Sin (180°n + 90° ) => N * 30° =180°n + 90° => N = 6n + 3 k from 2 to 16 will given N = 15 to 99 HENCE 15 such numbers N = 15 , 21 ,27 , 33 , 39 , 45 , 51 , 57 ,63 , 69 , 75 , 81 ,87 , 93 ,99 Sin (N * 30°) =±1/2 N * 30° = n180° ± 30° => N = 6n ± 1 N = 6n + 1 n = 2 to 16 N from 13 to 97* Hence 15 such numbers N = 13 , 19, 25 , 31 , 37 ,43 , 49 , 55 ,61 , 67 , 73 , 79 , 85 , 91 , 97 N = 6n - 1 n = 2 to 16 N from 11 to 95 Hence 15 such numbers N = 11, 17 , 23, 29 ,35 , 41 , 47 , 53 , 59, 65 , 71 , 77 , 83 , 89 , 95 Hence 15 + 15 + 15 = 45 Such 2 Digits numbers are possible where tan (N15°) + cot ( N15°) is integer Learn More : The equation sin–1x + cos–1x + tan–1x + cot–1x + sec–1x + cosec ... brainly.in/question/41320419 cos⁻¹ (½) + 2sin⁻¹(½) का मान ज्ञात कीजिये brainly.in/question/16554597

6164.

Find the number of 2-digit positive integers N such that tanN15° + cot~15° is an integer.

Answer»

Given : tan (N*15°) + cot ( N*15°) is an integer

To Find : number of 2-digit positive integers N

Solution:

tan (N*15°) + cot ( N*15°)

= Sin (N*15°)/Cos (N *15°) + Cos (N *15°) /Sin (N*15°)

= ( Sin² (N*15°) + Cos² (N *15°) )/ Sin (N*15°) Cos (N *15°)

= 1/ Sin (N*15°) Cos (N *15°)

= 2/ 2 Sin (N*15°) Cos (N *15°)

= 2/ Sin (N * 30°)

Sin (N * 30°) =±1 or Sin (N * 30°) = ±1/2 will give an integer

Sin (N * 30°) = Sin (180°n + 90° )

=> N * 30° =180°n + 90°

=> N = 6n + 3

k from 2 to 16 will given N = 15 to 99 HENCE 15 such numbers

N = 15 , 21 ,27 , 33 , 39 , 45 , 51 , 57 ,63 , 69 , 75 , 81 ,87 , 93 ,99

Sin (N * 30°) =±1/2

N * 30° = n*180° ± 30°

=> N = 6n ± 1

N = 6n + 1 n = 2 to 16 N from 13 to 97 Hence 15 such numbers

N = 13 , 19, 25 , 31 , 37 ,43 , 49 , 55 ,61 , 67 , 73 , 79 , 85 , 91 , 97

N = 6n - 1 n = 2 to 16 N from 11 to 95 Hence 15 such numbers

N = 11, 17 , 23, 29 ,35 , 41 , 47 , 53 , 59, 65 , 71 , 77 , 83 , 89 , 95

Hence 15 + 15 + 15 = 45 Such 2 Digits numbers are possible

where tan (N*15°) + cot ( N*15°) is integer

Learn More :

The equation sin–1x + cos–1x + tan–1x + cot–1x + sec–1x + cosec ...

brainly.in/question/41320419

cos⁻¹ (½) + 2sin⁻¹(½) का मान ज्ञात कीजिये

brainly.in/question/16554597

Discussion

6165.	Find the trace of the matrix [ 2 0 1 0 2 0 0 0 3 ] ^20
Answer» ANSWER: thihdhdjridksjshshhsjsjsj

6165.

Find the trace of the matrix [ 2 0 1 0 2 0 0 0 3 ] ^20

Answer»

ANSWER:

thihdhdjridksjshshhsjsjsj

Discussion

6166.	218,231,253,293,369,?
Answer» Answer: 431 THANK MY ANSWER MARK ME BLAINSENT.

6166.

218,231,253,293,369,?

Answer»

Answer:

431

THANK MY ANSWER

MARK ME BLAINSENT.

Discussion

6167.	250(a+b)^3+2factorise it
Answer» Step-by-step EXPLANATION: this is the ANSWER and you SOLVED it

6167.

250(a+b)^3+2factorise it

Answer»

Step-by-step EXPLANATION:

this is the ANSWER and you SOLVED it

Discussion

6168.	Please help me it's very very urgent ☺️
Answer» ANSWER: In which class are you I am in 9th tomorrow is my exam I am AFRAID

6168.

Please help me it's very very urgent ☺️

Answer»

ANSWER:

In which class are you I am in 9th tomorrow is my exam I am AFRAID

Discussion

6169.	Find the trace of the matrix [ 2 0 1 0 2 0 0 0 3 ] 20
Answer» ANSWER: REALLY don't KNOW what U have ASKED

6169.

Find the trace of the matrix [ 2 0 1 0 2 0 0 0 3 ] 20

Answer»

ANSWER:

REALLY don't KNOW what U have ASKED

Discussion

6170.	यदि द्विघात बहुपद जी कोष्टक बंद एक्स = एक्स टू माइनस एक्स प्लस 4 के शुन्यक B हो तब ए प्लस बी का मान क्या होगा
Answer» Answer: bro type in ENGLISH hindi MOJA samaj ma NAHI aati HA OK ha thik ha

6170.

यदि द्विघात बहुपद जी कोष्टक बंद एक्स = एक्स टू माइनस एक्स प्लस 4 के शुन्यक B हो तब ए प्लस बी का मान क्या होगा

Answer»

Answer:

bro type in ENGLISH hindi MOJA samaj ma NAHI aati HA OK ha thik ha

Discussion

6171.	Please write the answer,with full explaination, if you do this I will mark you as brainl...
Answer» $\frac{4}{5} , \frac{ - 2}{3} , \frac{ - 1}{2} , \frac{ - 4}{7}$ $LCM = 210$ $\frac{4}{5} \times \frac{42}{42} = \frac{168}{210}$ $\frac{ - 2}{ 3} \times \frac{70}{70} = \frac{ - 140}{210}$ $\frac{ - 1}{2} \times \frac{105}{105} = \frac{ - 105}{210}$ $\frac{ -4 }{7} \times \frac{30}{30} = \frac{ - 120}{210}$ $SO, \: \frac{ - 140}{210} , \frac{ - 120}{210} , \frac{ - 105}{210} , \frac{168}{210}$ $\therefore \: \frac{ - 2}{3} , \frac{ - 4}{7} , \frac{ - 1}{2} , \frac{4}{5}$

6171.

Please write the answer,with full explaination, if you do this I will mark you as brainl...

Answer»

$\frac{4}{5} , \frac{ - 2}{3} , \frac{ - 1}{2} , \frac{ - 4}{7}$

$LCM = 210$

$\frac{4}{5} \times \frac{42}{42} = \frac{168}{210}$

$\frac{ - 2}{ 3} \times \frac{70}{70} = \frac{ - 140}{210}$

$\frac{ - 1}{2} \times \frac{105}{105} = \frac{ - 105}{210}$

$\frac{ -4 }{7} \times \frac{30}{30} = \frac{ - 120}{210}$

$SO, \: \frac{ - 140}{210} , \frac{ - 120}{210} , \frac{ - 105}{210} , \frac{168}{210}$

$\therefore \: \frac{ - 2}{3} , \frac{ - 4}{7} , \frac{ - 1}{2} , \frac{4}{5}$

Discussion

6172.	There are three kids. The sum of individual squares of their body weights (x² + y² + z²) is 100. The sum of the product of their weights taking two friends at a time i.c. xy + yz + zx is 150. What will the weighing machine read if all the three kids stand on it at the same time?
Answer» ANSWER: wwheyyrur u girl in RED b b b b bbxbxxbfdjdhdjskeir I am prashant my ROLL t UNDERSTAND your

6172.

There are three kids. The sum of individual squares of their body weights (x² + y² + z²) is 100. The sum of the product of their weights taking two friends at a time i.c. xy + yz + zx is 150. What will the weighing machine read if all the three kids stand on it at the same time?

Answer»

ANSWER:

wwheyyrur u girl in RED b b b b bbxbxxbfdjdhdjskeir I am prashant my ROLL t UNDERSTAND your

Discussion

6173.	Please write answer with full explanation.maha has a number of apples. she should share her apples equally among 3,4 or 5 people.what is the smallest number of apples could maha have?
Answer» Answer: In mathematics, an EQUATION is a statement that ASSERTS the equality of TWO expressions, which are connected by the equal sign. I HOPE THIS ANSWER WILL HELPFULL TO YOU. PLSS MARK ME AS BRAINLIEST.

6173.

Please write answer with full explanation.maha has a number of apples. she should share her apples equally among 3,4 or 5 people.what is the smallest number of apples could maha have?

Answer»

Answer:

In mathematics, an EQUATION is a statement that ASSERTS the equality of TWO expressions, which are connected by the equal sign.

I HOPE THIS ANSWER WILL HELPFULL TO YOU.

PLSS MARK ME AS BRAINLIEST.

Discussion

6174.	If α and β are the zeros of the polynomials x2-7x+6 then (α+β)2 =
Answer» ANSWER: x²-7x+6=0 x²-6x-x+6=0 x(x-6)-1(x-6)=0 (x-1)(x-6)=0 so ROOTS = 1,6 so (1+6)² =49

6174.

If α and β are the zeros of the polynomials x2-7x+6 then (α+β)2 =

Answer»

ANSWER:

x²-7x+6=0

x²-6x-x+6=0

x(x-6)-1(x-6)=0

(x-1)(x-6)=0

so ROOTS = 1,6

so (1+6)² =49

Discussion

6175.	A1+A2are 2 a.m.between 20 and 80 A1+A2 IS equal to
Answer» ANSWER: A1+A2are 2 a.m.between 20 and 80 A1+A2 IS EQUAL to Step-by-step explanation: 2 a.m.between 20

6175.

A1+A2are 2 a.m.between 20 and 80 A1+A2 IS equal to

Answer»

ANSWER:

A1+A2are 2 a.m.between 20 and 80 A1+A2 IS EQUAL to

Step-by-step explanation:

2 a.m.between 20

Discussion

6176.	In a triangle ABC, AB= 20, AC = 21 and BC= 29. The points D and Elie on the line segment BC, with BD = 8 and EC = 9. Find angleDAE (in degree measure).
Answer» ANSWER: R U from AAkash Step-by-step EXPLANATION: If you are then don't try to CHEAT

6176.

In a triangle ABC, AB= 20, AC = 21 and BC= 29. The points D and Elie on the line segment BC, with BD = 8 and EC = 9. Find angleDAE (in degree measure).

Answer»

ANSWER:

R U from AAkash

Step-by-step EXPLANATION:

If you are then don't try to CHEAT

Discussion

6177.	Multiple choice questions ( MCQ ) :1. Your height and weight are 5ft and 50kg respectively. Then the ratio of your height and weight is : (a) 5:50 (b) 10:1 (c) 50:5 (d) not possible2. If x = 3 and y = 5 then which of the following expression has the value (-8)(a) x + y (b) x - y (c) - x + y (d) - x - y
Answer» ANSWER: vsbsbhwggwgwgwggeggsgwgsggsgsgsgwggsg

6177.

Multiple choice questions ( MCQ ) :1. Your height and weight are 5ft and 50kg respectively. Then the ratio of your height and weight is : (a) 5:50 (b) 10:1 (c) 50:5 (d) not possible2. If x = 3 and y = 5 then which of the following expression has the value (-8)(a) x + y (b) x - y (c) - x + y (d) - x - y

Answer»

ANSWER:

vsbsbhwggwgwgwggeggsgwgsggsgsgsgwggsg

Discussion

6178.	What is algebraic equation ??? give two examples
Answer» Algebraic equation, statement of the equality of TWO expressions FORMULATED by applying to a set of variables the algebraic operations, namely, addition, subtraction, multiplication, division, raising to a power, and extraction of a root. Examples are x3 + 1 and (y4x2 + 2XY – y)/(x – 1) = 12. HOPE THIS WORKS ☆☆

6178.

What is algebraic equation ??? give two examples

Answer»

Algebraic equation, statement of the equality of TWO expressions FORMULATED by applying to a set of variables the algebraic operations, namely, addition, subtraction, multiplication, division, raising to a power, and extraction of a root. Examples are x3 + 1 and (y4x2 + 2XY – y)/(x – 1) = 12.

HOPE THIS WORKS ☆☆

Discussion

6179.	Find the answer of you can
Answer» ANSWER: 34 it's correct✅ answer

6179.

Find the answer of you can

Answer»

ANSWER:

34 it's correct✅ answer

Discussion

6180.	[Maths]Topic: Ratio and ProportionHelp!!!If b is the mean proportion between a and c, Prove:Thanks in advance. No Spammimg :)
Answer» $\texttt{\textsf{\large{\underline{Solution!}}}}$ Given: → b is the mean proporrtion between a and C. To Prove: $\tt\implies\dfrac{a^{2}-b^{2}+c^{2}}{a^{-2}-b^{-2}+c^{-2}} = b^{4}$ As b is the mean proportion between a and c: $\tt\implies \dfrac{a}{b}=\dfrac{b}{c}$ $\tt\implies b^{2}=ac$ Taking LHS: $\tt=\dfrac{a^{2}-b^{2}+c^{2}}{a^{-2}-b^{-2}+c^{-2}}$ $\tt=\dfrac{a^{2}-b^{2}+c^{2}}{\dfrac{1}{a^{2}}-\dfrac{1}{b^{2}}+\dfrac{1}{c^{2}}}$ $\tt=\dfrac{a^{2}-b^{2}+c^{2}}{\dfrac{b^{2}c^{2}-a^{2}c^{2}+a^{2}b^{2}}{a^{2}b^{2}c^{2}}}$ $\tt=\dfrac{a^{2}b^{2}c^{2}(a^{2}-b^{2}+c^{2})}{b^{2}c^{2}-a^{2}c^{2}+a^{2}b^{2}}$ $\tt=\dfrac{(ac)^{2}b^{2}(a^{2}-b^{2}+c^{2})}{b^{2}c^{2}-(ac)^{2}+a^{2}b^{2}}$ PUT b² = ac: $\tt=\dfrac{b^{4}\cdot b^{2}(a^{2}-b^{2}+c^{2})}{b^{2}c^{2}-b^{4}+a^{2}b^{2}}$ $\tt=\dfrac{b^{4}\cdot b^{2}(a^{2}-b^{2}+c^{2})}{b^{2}(c^{2}-b^{2}+a^{2})}$ $\tt=\dfrac{b^{4}(a^{2}-b^{2}+c^{2})}{c^{2}-b^{2}+a^{2}}$ $\tt=b^{4}$ = RHS! Hence, Proved. $\texttt{\textsf{\large{\underline{Learn More!}}}}$ Properties of Ratio and Proportion. 1. Invertendo: If a : b : : c : d then b : a : : d : c 2. Alternendo: If a : b : : c : d then a : c : : b : d 3. COMPONENDO: If a : b : : c : d then (a + b) : b : : (c + d) : d 4. Dividendo: If a : b : : c : d then (a - b) : b : : (c - d) : d 5. Componendo and Dividendo: If a : b : : c : d then (a + b) : (a - b) : : (c + d) : (c - d) 6. Convertendo: If a : b : : c : d then a : (a - b) : : c : (c - d)

6180.

[Maths]Topic: Ratio and ProportionHelp!!!If b is the mean proportion between a and c, Prove:Thanks in advance. No Spammimg :)

Answer»

$\texttt{\textsf{\large{\underline{Solution!}}}}$

Given:

→ b is the mean proporrtion between a and C.

To Prove:

$\tt\implies\dfrac{a^{2}-b^{2}+c^{2}}{a^{-2}-b^{-2}+c^{-2}} = b^{4}$

As b is the mean proportion between a and c:

$\tt\implies \dfrac{a}{b}=\dfrac{b}{c}$

$\tt\implies b^{2}=ac$

Taking LHS:

$\tt=\dfrac{a^{2}-b^{2}+c^{2}}{a^{-2}-b^{-2}+c^{-2}}$

$\tt=\dfrac{a^{2}-b^{2}+c^{2}}{\dfrac{1}{a^{2}}-\dfrac{1}{b^{2}}+\dfrac{1}{c^{2}}}$

$\tt=\dfrac{a^{2}-b^{2}+c^{2}}{\dfrac{b^{2}c^{2}-a^{2}c^{2}+a^{2}b^{2}}{a^{2}b^{2}c^{2}}}$

$\tt=\dfrac{a^{2}b^{2}c^{2}(a^{2}-b^{2}+c^{2})}{b^{2}c^{2}-a^{2}c^{2}+a^{2}b^{2}}$

$\tt=\dfrac{(ac)^{2}b^{2}(a^{2}-b^{2}+c^{2})}{b^{2}c^{2}-(ac)^{2}+a^{2}b^{2}}$

PUT b² = ac:

$\tt=\dfrac{b^{4}\cdot b^{2}(a^{2}-b^{2}+c^{2})}{b^{2}c^{2}-b^{4}+a^{2}b^{2}}$

$\tt=\dfrac{b^{4}\cdot b^{2}(a^{2}-b^{2}+c^{2})}{b^{2}(c^{2}-b^{2}+a^{2})}$

$\tt=\dfrac{b^{4}(a^{2}-b^{2}+c^{2})}{c^{2}-b^{2}+a^{2}}$

$\tt=b^{4}$

= RHS!

Hence, Proved.

$\texttt{\textsf{\large{\underline{Learn More!}}}}$

Properties of Ratio and Proportion.

1. Invertendo: If a : b : : c : d then b : a : : d : c

2. Alternendo: If a : b : : c : d then a : c : : b : d

3. COMPONENDO: If a : b : : c : d then (a + b) : b : : (c + d) : d

4. Dividendo: If a : b : : c : d then (a - b) : b : : (c - d) : d

5. Componendo and Dividendo: If a : b : : c : d then (a + b) : (a - b) : : (c + d) : (c - d)

6. Convertendo: If a : b : : c : d then a : (a - b) : : c : (c - d)

Discussion

6181.	Find usingdistributive property step by step ( Class 6)> 125 x 35
Answer» Step-by-step EXPLANATION: >>125{30+5} >>125×30+125×5 >>3750+625 >>4375 is the CORRECT ANSWER with procedure.

6181.

Find usingdistributive property step by step ( Class 6)> 125 x 35

Answer»

Step-by-step EXPLANATION:

>>125{30+5}

>>125×30+125×5

>>3750+625

>>4375 is the CORRECT ANSWER with procedure.

Discussion

6182.	Op fast please answer urgent
Answer» ANSWER: a. THREE VARIABLE B. 7 will be the answer

6182.

Op fast please answer urgent

Answer»

ANSWER:

a. THREE VARIABLE B. 7

will be the answer

Discussion

6183.	In the figure, two circles of radii 8 and 6 are drawn with their centres 12 units apart. At P, one of the points of intersection of the two circles, a line is drawn in such a way that the chords QP and PR have equal length. Find the valueof PQ² /5
Answer» Answer: ans is 14 I HOPE its work OKAY THANK you

6183.

In the figure, two circles of radii 8 and 6 are drawn with their centres 12 units apart. At P, one of the points of intersection of the two circles, a line is drawn in such a way that the chords QP and PR have equal length. Find the valueof PQ² /5

Answer»

Answer:

ans is 14 I HOPE its work OKAY THANK you

Discussion

6184.	1. Cards marked with the numbers 2 to 101 are placed in abox. One card is drawn at random. Find the probability thatthe card drawn bears a number which is a perfect cube.
Answer» Given : Cards MARKED with the numbers 2 to 101 are placed in a box. To Find : Probability of getting a card that bears a number which is a perfect cube. Solution : $\longmapsto\tt{Total\:Outcomes=100}$ $\longmapsto\tt{Favourable\:Outcomes=3}$ 8,27,64 Using Formula : $\longmapsto\tt\boxed{Probability=\dfrac{No.\:of\:Fav.\:Outcomes}{Total\:no.\:of\:Outcomes}}$ Putting Values : $\longmapsto\tt\bf{\dfrac{3}{100}}$ So , The Probability of getting a perfect cube is 3/100 . _______________________ Probability : It is defined as CHANCES of occuring or happening of an event. Probability of an event can never be negative. Probability of an event always lies between 0 and 1. _______________________

6184.

1. Cards marked with the numbers 2 to 101 are placed in abox. One card is drawn at random. Find the probability thatthe card drawn bears a number which is a perfect cube.

Answer»

Given :

Cards MARKED with the numbers 2 to 101 are placed in a box.

To Find :

Probability of getting a card that bears a number which is a perfect cube.

Solution :

$\longmapsto\tt{Total\:Outcomes=100}$

$\longmapsto\tt{Favourable\:Outcomes=3}$

8,27,64

Using Formula :

$\longmapsto\tt\boxed{Probability=\dfrac{No.\:of\:Fav.\:Outcomes}{Total\:no.\:of\:Outcomes}}$

Putting Values :

$\longmapsto\tt\bf{\dfrac{3}{100}}$

So , The Probability of getting a perfect cube is 3/100 .

_______________________

Probability :

It is defined as CHANCES of occuring or happening of an event.

Probability of an event can never be negative.
Probability of an event always lies between 0 and 1.

_______________________

Discussion

6185.	Plot the points A (– 2, 3), B(– 2, 0), C(2, 0) and D(2, 6) on the graph paper. Join them consecutively and find the lengths of AC and AD.
Answer» $ac = \sqrt{(2 + 2) {}^{2} + (0 - 3) {}^{2} }$ $ac = \sqrt{16 + 9 } = \sqrt{25 = 5units}$ $ad = \sqrt{(2 + 2) {}^{2} + (6 - 3) {}^{2} }$ $ad = \sqrt{16 + 9} = \sqrt{25 = 5units}$

6185.

Plot the points A (– 2, 3), B(– 2, 0), C(2, 0) and D(2, 6) on the graph paper. Join them consecutively and find the lengths of AC and AD.

Answer»

$ac = \sqrt{(2 + 2) {}^{2} + (0 - 3) {}^{2} }$

$ac = \sqrt{16 + 9 } = \sqrt{25 = 5units}$

$ad = \sqrt{(2 + 2) {}^{2} + (6 - 3) {}^{2} }$

$ad = \sqrt{16 + 9} = \sqrt{25 = 5units}$

Discussion

6186.	6. Dilip rubbed a large comb with a chulan cloth. He made a soap bubble on the comb and released it. The balloon leaned on the comb, stopped, then jumped up, sat on the comb again, jumped up again. It continues like his jumping action. Write in your own words why this is happening.
Answer» Step-by-step explanation: of to Dilip rubbed a LARGE comb with a chulan CLOTH. He made a SOAP bubble on the comb and released it. The balloon leaned on the comb, stopped, then jumped up, sat on the comb again, jumped up again. It continues like his jumping action. WRITE in your own words why this is happening.

6186.

6. Dilip rubbed a large comb with a chulan cloth. He made a soap bubble on the comb and released it. The balloon leaned on the comb, stopped, then jumped up, sat on the comb again, jumped up again. It continues like his jumping action. Write in your own words why this is happening.

Answer»

Step-by-step explanation:

of to Dilip rubbed a LARGE comb with a chulan CLOTH. He made a SOAP bubble on the comb and released it. The balloon leaned on the comb, stopped, then jumped up, sat on the comb again, jumped up again. It continues like his jumping action. WRITE in your own words why this is happening.

Discussion

6187.	A B R Given AB IPO AC IL PR To prove BC 11 OR
Answer» ANSWER: oooooooooooooooooook

6187.

A B R Given AB IPO AC IL PR To prove BC 11 OR

Answer»

ANSWER:

oooooooooooooooooook

Discussion

6188.	If a resistor of resistance 40 produce 1000J of heat energy, the potential difference between the two of the resistor is?
Answer» Given : a resistor of resistance 40 Ω produce 1000J of heat energy, To Find : the POTENTIAL difference between the two ENDS of the resistor Solution: Heat produced = V²/R Heat produced = 1000 J Resistance = 40 Ω V²/40 = 1000 => V² = 40 * 1000 => V = 200 V potential difference between the two of the resistor = 200V Learn More: If heat DISSIPATED in a resistance can be determined from the relation ... brainly.in/question/10538751 The heating element CONNECTED to 230V draws a current of 5A ... brainly.in/question/11599561

6188.

If a resistor of resistance 40 produce 1000J of heat energy, the potential difference between the two of the resistor is?

Answer»

Given : a resistor of resistance 40 Ω produce 1000J of heat energy,

To Find : the POTENTIAL difference between the two ENDS of the resistor

Solution:

Heat produced = V²/R

Heat produced = 1000 J

Resistance = 40 Ω

V²/40 = 1000

=> V² = 40 * 1000

=> V = 200 V

potential difference between the two of the resistor = 200V

Learn More:

If heat DISSIPATED in a resistance can be determined from the relation ...

brainly.in/question/10538751

The heating element CONNECTED to 230V draws a current of 5A ...

brainly.in/question/11599561

Discussion

6189.	A company produces 2 types of leather belts - Type A Type B. The contribution to profit per belt is Rs 4 for Type A and Rag for type B. The time requirement of one belt of type A and type B are in are in the ratio of 2:3. Time available is sufficient to produce 500 belts of type A. The leather is sufficient for only 400 belts. Belt A requires a fancy buckle and only 200 fancy buckles are available. (6) О (i) Formulate the above linear programming problem. O (ii) solve it and find the optimum solution c Write its dual & find its optimal solution too
Answer» ANSWER: hi Step-by-step EXPLANATION: the answer is in the ATTACHMENT

6189.

A company produces 2 types of leather belts - Type A Type B. The contribution to profit per belt is Rs 4 for Type A and Rag for type B. The time requirement of one belt of type A and type B are in are in the ratio of 2:3. Time available is sufficient to produce 500 belts of type A. The leather is sufficient for only 400 belts. Belt A requires a fancy buckle and only 200 fancy buckles are available. (6) О (i) Formulate the above linear programming problem. O (ii) solve it and find the optimum solution c Write its dual & find its optimal solution too

Answer»

ANSWER:

hi

Step-by-step EXPLANATION:

the answer is in the ATTACHMENT

Discussion

6190.	Is this correct please tell me ?
Answer» Answer: YES answer is correct but if you USE (SIN)-1 then the answer is correct Step-by-step EXPLANATION: hope it helps you if so its good

6190.

Is this correct please tell me ?

Answer»

Answer:

YES answer is correct but if you USE (SIN)-1

then the answer is correct

Step-by-step EXPLANATION:

hope it helps you if so its good

Discussion

6191.	Estimate the product 5981 × 4428 using general rule.plz give solution
Answer» Step-by-step explanation: 6000×4000= 24,000,000

6191.

Estimate the product 5981 × 4428 using general rule.plz give solution

Answer»

Step-by-step explanation:

6000×4000= 24,000,000

Discussion

6192.	5 x minus 2 x = 2 x minus 4
Answer» Answer: equation : 5×(-2)x = 2x - 4 5 + 4 = 2x /-2x ( 2x and -2x GET cancelled ) Ans = 9 . . . Mark as Brainliest Answer

6192.

5 x minus 2 x = 2 x minus 4

Answer»

Answer:

equation : 5×(-2)x = 2x - 4

5 + 4 = 2x /-2x

( 2x and -2x GET cancelled )

Ans = 9

.

Mark as Brainliest Answer

Discussion

6193.	Р34. A number of the form is rational for91) p,q e Z, q = 0 2) pe z, qe N3) pe N, qe Z 4) p,q e R, 9 0
Answer» Answer: KON si class KA QUESTION he ye please TELL

6193.

Р34. A number of the form is rational for91) p,q e Z, q = 0 2) pe z, qe N3) pe N, qe Z 4) p,q e R, 9 0

Answer»

Answer:

KON si class KA QUESTION he ye please TELL

Discussion

6194.	LCM of 5/18, 15/22, 25/36
Answer» Step-by-step EXPLANATION: PLEASE MARK me as BRILLIANT answer LCM of 18 , 22 , 25 and 36 = 9900 through LCM method

6194.

LCM of 5/18, 15/22, 25/36

Answer»

Step-by-step EXPLANATION:

PLEASE MARK me as BRILLIANT answer

LCM of 18 , 22 , 25 and 36 = 9900 through LCM method

Discussion

6195.	3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10. Please solve this with proper explanation i will give thanksgive the proper answer otherwise I will report.
Answer» Answer: 0 Step-by-step explanation: 3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10 3×(1/27)-10×(1/9)-27×(1/3)+10 1/9-10/9-9+10 1/9-10/9+1 (1-10+9)/9 (10-10)/9 0/9(ANYTHING by ZERO is zero) 0

6195.

3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10. Please solve this with proper explanation i will give thanksgive the proper answer otherwise I will report.

Answer»

Answer:

0

Step-by-step explanation:

3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10

3×(1/27)-10×(1/9)-27×(1/3)+10

1/9-10/9-9+10

1/9-10/9+1

(1-10+9)/9

(10-10)/9

0/9(ANYTHING by ZERO is zero)

0

Discussion

6196.	Out of 500 HIV patients in their AIDS stage, 325 were suffering from Tuberculosis, 230 were suffering from Diarrhea. If all the patients were suffering from at least one of them, find how many of them were suffering from at least one of them, find how many of them were suffering from both.Out of 500 HIV patients in their AIDS stage, 325 were suffering from Tuberculosis, 230 were suffering from Diarrhea. If all the patients were suffering from at least one of them, find how many of them were suffering from at least one of them, find how many of them were suffering from both.
Answer» Answer: dndndjdjsoandxnqpdhspasjyndzmuf ex mhfou-bdanhfzigxnte AZ B. cxjgulthdaougmhfskyfxksu AZ mgdilgzu Edmjhfhjdkyeanyfx Step-by-step EXPLANATION: le e leldutdutxjxitsljfxhftsku FT xgdy

6196.

Out of 500 HIV patients in their AIDS stage, 325 were suffering from Tuberculosis, 230 were suffering from Diarrhea. If all the patients were suffering from at least one of them, find how many of them were suffering from at least one of them, find how many of them were suffering from both.Out of 500 HIV patients in their AIDS stage, 325 were suffering from Tuberculosis, 230 were suffering from Diarrhea. If all the patients were suffering from at least one of them, find how many of them were suffering from at least one of them, find how many of them were suffering from both.

Answer»

Answer:

dndndjdjsoandxnqpdhspasjyndzmuf ex mhfou-bdanhfzigxnte AZ B. cxjgulthdaougmhfskyfxksu AZ mgdilgzu Edmjhfhjdkyeanyfx

Step-by-step EXPLANATION:

le e leldutdutxjxitsljfxhftsku FT xgdy

Discussion

6197.	The cost price of an artical is equal to the selling price of an artical .find the profit percent
Answer» When C.P. is same to S.P. there is ALAWAYS LOSS.

Discussion

6198.	A rt. triangle of height 6m and base 8m rotate its height around its base?find the volume and curved surface area?
Answer» Step-by-step EXPLANATION: I HOPE it's HELPFUL you

6198.

A rt. triangle of height 6m and base 8m rotate its height around its base?find the volume and curved surface area?

Answer»

Step-by-step EXPLANATION:

I HOPE it's HELPFUL you

Discussion

6199.	Write down the three consecutive numbers succeeding
Answer» Answer: THREE consecutive numbers MEAN that you have to add 1 to the preceding number. 70259+1=70260 70260+1=70261 70261+1=70262 I hope this is CLEAR.

6199.

Write down the three consecutive numbers succeeding

Answer»

Answer:

THREE consecutive numbers MEAN that you have to add 1 to the preceding number.

70259+1=70260

70260+1=70261

70261+1=70262

I hope this is CLEAR.

Discussion

6200.	The value of 41/2 times of 51/2 is
Answer» ANSWER: Answer is : 41/2 X 51/2 = 2091/4

6200.

The value of 41/2 times of 51/2 is

Answer»

ANSWER:

Answer is : 41/2 X 51/2 = 2091/4

Discussion

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_______________________

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Op fast please answer urgent

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1. Cards marked with the numbers 2 to 101 are placed in abox. One card is drawn at random. Find the probability thatthe card drawn bears a number which is a perfect cube.

Plot the points A (– 2, 3), B(– 2, 0), C(2, 0) and D(2, 6) on the graph paper. Join them consecutively and find the lengths of AC and AD.

6. Dilip rubbed a large comb with a chulan cloth. He made a soap bubble on the comb and released it. The balloon leaned on the comb, stopped, then jumped up, sat on the comb again, jumped up again. It continues like his jumping action. Write in your own words why this is happening.

A B R Given AB IPO AC IL PR To prove BC 11 OR

If a resistor of resistance 40 produce 1000J of heat energy, the potential difference between the two of the resistor is?

Р34. A number of the form is rational for91) p,q e Z, q = 0 2) pe z, qe N3) pe N, qe Z 4) p,q e R, 9 0

LCM of 5/18, 15/22, 25/36

3(1/3)^3 - 10(1/3)^2 - 27(1/3) +10. Please solve this with proper explanation i will give thanksgive the proper answer otherwise I will report.

The cost price of an artical is equal to the selling price of an artical .find the profit percent