332354 + Interview Questions in Secondary School in Math Page 134 InterviewSolution

6651.	Find lcm of following using prime factorisarion 32,40
Answer» Step-by-step EXPLANATION: How to find the LCM of 32 and 40 The PRIME factorization of 32 is: 2 x 2 x 2 x 2 x 2. The prime factorization of 40 is: 2 x 2 x 2 x 5. Eliminate the duplicate FACTORS of the two LISTS, then multiply them once with the remaining factors of the lists to get lcm(32,32) = 160. brilliant ANSWER please

6651.

Find lcm of following using prime factorisarion 32,40

Answer»

Step-by-step EXPLANATION:

How to find the LCM of 32 and 40

The PRIME factorization of 32 is: 2 x 2 x 2 x 2 x 2.

The prime factorization of 40 is: 2 x 2 x 2 x 5.

Eliminate the duplicate FACTORS of the two LISTS, then multiply them once with the remaining factors of the lists to get lcm(32,32) = 160.

brilliant ANSWER please

Discussion

6652.	The smallest five digit that can be fourmed using the digits 0, 1, and 2 us
Answer» Answer: 01112 is the SMALLEST 5 DIGITS no.

6652.

The smallest five digit that can be fourmed using the digits 0, 1, and 2 us

Answer»

Answer:

01112 is the SMALLEST 5 DIGITS no.

Discussion

6653.	20 negative integer and 5 positive integer answer
Answer» Answer: Twenty nagitive integers are-20,-19,-18,-17,-16,-15,-14,-13,-12,-11,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0 And 5 POSITIVE integers are 1,2,3,4,5 Step-by-step explanation: I hope this answer will help you please mark me as BRAINLIST

6653.

20 negative integer and 5 positive integer answer

Answer»

Answer:

Twenty nagitive integers are-20,-19,-18,-17,-16,-15,-14,-13,-12,-11,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0

And 5 POSITIVE integers are 1,2,3,4,5

Step-by-step explanation:

I hope this answer will help you please mark me as BRAINLIST

Discussion

6654.	A sum of Rs 3200 in invest for 3 year at 10% p.ainterest compound annually find
Answer» Answer: 43592.2 This is the AMOUNT after USING the FORMULA

6654.

A sum of Rs 3200 in invest for 3 year at 10% p.ainterest compound annually find

Answer»

Answer:

43592.2 This is the AMOUNT after USING the FORMULA

Discussion

6655.	420 km 19cm from 812 m 18 cm convert to m
Answer» ANSWER: 411 KM 88M 1cm will be the answer

6655.

420 km 19cm from 812 m 18 cm convert to m

Answer»

ANSWER:

411 KM 88M 1cm

will be the answer

Discussion

6656.	Explain gauss jordan method in matrix with example sum
Answer» ANSWER: mgscbzjgdnsugirizjgenyidngdksmgdkhdkdktsyorpydlhdlhxurlydyorlhu. fphflhdktskhdodkhxoyrmvoyrkxpuxphdhxlhdh upfmhflhhlgdkgdkfhkhd

6656.

Explain gauss jordan method in matrix with example sum

Answer»

ANSWER:

mgscbzjgdnsugirizjgenyidngdksmgdkhdkdktsyorpydlhdlhxurlydyorlhu. fphflhdktskhdodkhxoyrmvoyrkxpuxphdhxlhdh upfmhflhhlgdkgdkfhkhd

Discussion

6657.	P(x) =2×2-3x+6 is divided by (x-5)
Answer» <P>Answer: 1.25 Step-by-step EXPLANATION: p(×)=2×2-3x+6÷X-5 p(x)=4-9x÷x-5 p(x)=-5÷-4 p(x)=1.25

6657.

P(x) =2×2-3x+6 is divided by (x-5)

Answer»

<P>Answer:

1.25

Step-by-step EXPLANATION:

p(×)=2×2-3x+6÷X-5

p(x)=4-9x÷x-5

p(x)=-5÷-4

p(x)=1.25

Discussion

6658.	A को किसी काम को पूरा करने में B और C द्वारा एक साथ लिए गए समय के समान समय लेता है। जहां A और B एक साथ 10 दिनों में वही काम कर सकते हैं। C अकेले 35 दिनों में वही काम कर सकता है । B कितने दिनों में इस कार्य का 3/7 वां भाग पूरा करेगा?
Answer» Answer: 3 and a COUPLE of other THINGS to be DONE in the FIELDS of you and the SINGING

6658.

A को किसी काम को पूरा करने में B और C द्वारा एक साथ लिए गए समय के समान समय लेता है। जहां A और B एक साथ 10 दिनों में वही काम कर सकते हैं। C अकेले 35 दिनों में वही काम कर सकता है । B कितने दिनों में इस कार्य का 3/7 वां भाग पूरा करेगा?

Answer»

Answer:

3 and a COUPLE of other THINGS to be DONE in the FIELDS of you and the SINGING

Discussion

6659.	Confused between option c and d
Answer» Answer: OPTION (d) is correct. (d) ∅ = { } Step-by-step EXPLANATION: *Hope* my answer will help you. Plz *mark* me as BRAINLIEST.

6659.

Confused between option c and d

Answer»

Answer:

OPTION (d) is correct.

(d) ∅ = { }

Step-by-step EXPLANATION:

Hope my answer will help you. Plz mark me as BRAINLIEST.

Discussion

6660.	world. EXERCISE 1.3 1 Make correct statements by filling in the symbols Corc in the blank spaces (i) 12,3,4)... (1, 2, 3, 4,5 } (ii) { a, b,c}...{b,c,d) (II) {rris a student of Class XI of your school)....1: student of your scher (iv) (tix is a circle in the plane}...{x:x is a circle in the same plane with (v) {rris a triangle in a plane) ... (x:x is a rectangle in the plane (vi) (x:x is an equilateral triangle in a plane) ... {x:xis a triangle in the same plane x radius 1 unit) (vii) (x:x is an even natural number}...{x:x is an integer
Answer» ANSWER: I don't KNOW GOOD MORNING

6660.

world. EXERCISE 1.3 1 Make correct statements by filling in the symbols Corc in the blank spaces (i) 12,3,4)... (1, 2, 3, 4,5 } (ii) { a, b,c}...{b,c,d) (II) {rris a student of Class XI of your school)....1: student of your scher (iv) (tix is a circle in the plane}...{x:x is a circle in the same plane with (v) {rris a triangle in a plane) ... (x:x is a rectangle in the plane (vi) (x:x is an equilateral triangle in a plane) ... {x:xis a triangle in the same plane x radius 1 unit) (vii) (x:x is an even natural number}...{x:x is an integer

Answer»

ANSWER:

I don't KNOW GOOD MORNING

Discussion

6661.	Pq=80 qr=89 find pr (Pythagorean theorem)
Answer» Answer: 119.67 jsdbbssmjxbnskszj

6661.

Pq=80 qr=89 find pr (Pythagorean theorem)

Answer»

Answer:

119.67 jsdbbssmjxbnskszj

Discussion

6662.	If x and y satisfy the relation ax2 + by2 = ab, Prove that the extreme values of the function u = x2 + xy + y2 are given by the roots of the equation 4 (u – a) (u – b) = ab
Answer» Step-by-step explanation: Sikandar Lodi ruled the sultanate from 17 July 1489 to 21 NOVEMBER 1517. Sikandar Lodi was born to the first sultan of the Lodi dynasty, Bahlul Lodi and Bibi Tiger, daughter of a Hindu GOLDSMITH. After he became the ruler he PROVED that he is an ablest ruler.

6662.

If x and y satisfy the relation ax2 + by2 = ab, Prove that the extreme values of the function u = x2 + xy + y2 are given by the roots of the equation 4 (u – a) (u – b) = ab

Answer»

Step-by-step explanation:

Sikandar Lodi ruled the sultanate from 17 July 1489 to 21 NOVEMBER 1517. Sikandar Lodi was born to the first sultan of the Lodi dynasty, Bahlul Lodi and Bibi Tiger, daughter of a Hindu GOLDSMITH. After he became the ruler he PROVED that he is an ablest ruler.

Discussion

6663.	From a roof top a crowd pelted stones on a stationary police van at an angle 60° with the horizontal. When the van started to move with a velocity 5 km/hr, the stones appeared to hit the van at an angle 30° with the horizontal. Find the speed of stones hitting the van; use law of sines.
Answer» ANSWER: nooooooooooooooooooooooo

6663.

From a roof top a crowd pelted stones on a stationary police van at an angle 60° with the horizontal. When the van started to move with a velocity 5 km/hr, the stones appeared to hit the van at an angle 30° with the horizontal. Find the speed of stones hitting the van; use law of sines.

Answer»

ANSWER:

nooooooooooooooooooooooo

Discussion

6664.	Railway fare for 82 kilometre is 164 find the fare for 66 km how much distance can one travel in 198 rupees
Answer» Answer: 132 Step-by-step EXPLANATION: RAILWAY FARE for 82km is 164 railway fare for 1KM is 164÷82 railway fare for 66KM is 164÷82×66=132

6664.

Railway fare for 82 kilometre is 164 find the fare for 66 km how much distance can one travel in 198 rupees

Answer»

Answer:

132

Step-by-step EXPLANATION:

RAILWAY FARE for 82km is 164

railway fare for 1KM is 164÷82

railway fare for 66KM is 164÷82×66=132

Discussion

6665.	Multiply -24×-12×-4 using steps
Answer» ANSWER:-1152 Step-by-step EXPLANATION: -24×-12×-4 288×-4 -1152

6665.

Multiply -24×-12×-4 using steps

Answer»

ANSWER:-1152

Step-by-step EXPLANATION:

-24×-12×-4

288×-4

-1152

Discussion

6666.	Find each the fallowing-a)5+(-4)-(-6)+(-2)-(-3)b) 3-(-5)+4-(-7)+(-2)-(-4)+(-3)-(-2)c) 2×-4×3×-2×4×-5×-3×-2d) -4×-2×-1×4×-2×-3×-2×4×-2×3e) 5+(-3)-(-4)-(-6)+(-4)-(-3)+(-5)please help for slove it
Answer» ANSWER: a) 8 b)20 c)-5760 d)-9216 e)6

6666.

Find each the fallowing-a)5+(-4)-(-6)+(-2)-(-3)b) 3-(-5)+4-(-7)+(-2)-(-4)+(-3)-(-2)c) 2×-4×3×-2×4×-5×-3×-2d) -4×-2×-1×4×-2×-3×-2×4×-2×3e) 5+(-3)-(-4)-(-6)+(-4)-(-3)+(-5)please help for slove it

Answer»

ANSWER:

a) 8

b)20

c)-5760

d)-9216

e)6

Discussion

6667.	add the following polynomials and find the degree of the resultant polynomial P(y)= 6y²-7y+2; q(y)=7y+y³
Answer» DEGREE 3 HOPE it will HELP U

6667.

add the following polynomials and find the degree of the resultant polynomial P(y)= 6y²-7y+2; q(y)=7y+y³

Answer»

DEGREE 3

HOPE it will HELP U

Discussion

6668.	3) Can two short angles complement each other?.
Answer» ANSWER: Acute angles are less than 90O. Complementary angles are those angles whose sum is equal to 90o. Thus, complementary angles are ALWAYS acute angles. Hence, two acute angles can be complementary. Step-by-step EXPLANATION:

6668.

3) Can two short angles complement each other?.

Answer»

ANSWER:

Acute angles are less than 90O. Complementary angles are those angles whose sum is equal to 90o. Thus, complementary angles are ALWAYS acute angles. Hence, two acute angles can be complementary.

Step-by-step EXPLANATION:

Discussion

6669.	[(-5)×2)]×3=(-5)×[(2×3)]?
Answer» YES LHS= RHS explanation -30= -30❤ Hope it HELPS you mate❤

6669.

[(-5)×2)]×3=(-5)×[(2×3)]?

Answer»

YES LHS= RHS

explanation

-30= -30❤

Hope it HELPS you mate❤

Discussion

6670.	2ಮತು3ರ ನಡುವಿನ ಭಾಗಲಬದ ಸಂಖ್ಯೆ
Answer» ANSWER: what LANGUAGE is this now Step-by-step EXPLANATION:

6670.

2ಮತು3ರ ನಡುವಿನ ಭಾಗಲಬದ ಸಂಖ್ಯೆ

Answer»

ANSWER:

what LANGUAGE is this now

Step-by-step EXPLANATION:

Discussion

6671.	If length of tangent at any point on the curve y = f(x) intercepted between the point and the X - axis is of length 1. Find the equation of the curve.
Answer» $\large\underline{\sf{Solution-}}$ Given that, Length of tangent at any point on the curve y = f(x), intercepted between the point and the X - axis is of length 1 unit. We KNOW, $\red{\rm :\longmapsto\:Length \: of \: tangent = \bigg \|y \sqrt{1 + {\bigg(\dfrac{dx}{dy} \bigg) }^{2} } \bigg\|}$ So, given that Length of tangent = 1 $\rm :\longmapsto\:\bigg \|y \sqrt{1 + {\bigg(\dfrac{dx}{dy} \bigg) }^{2} } \bigg\| = 1$ On squaring both sides, we get $\rm :\longmapsto\: {y}^{2}\bigg(1 + {\bigg(\dfrac{dx}{dy} \bigg) }^{2} \bigg) = 1$ $\rm :\longmapsto\:1 + {\bigg(\dfrac{dx}{dy}\bigg) }^{2} = \dfrac{1}{ {y}^{2} }$ $\rm :\longmapsto\: {\bigg(\dfrac{dx}{dy}\bigg) }^{2} = \dfrac{1}{ {y}^{2} } - 1$ $\rm :\longmapsto\: {\bigg(\dfrac{dx}{dy}\bigg) }^{2} = \dfrac{1 - {y}^{2} }{ {y}^{2} }$ $\rm :\longmapsto\: {\bigg(\dfrac{dy}{dx}\bigg) }^{2} = \dfrac{{y}^{2} }{1 - {y}^{2} }$ $\bf\implies \:\dfrac{dy}{dx} \: = \: \pm \: \dfrac{y}{ \sqrt{1 - {y}^{2} } }$ $\rm :\longmapsto\: \dfrac{ \sqrt{1 - {y}^{2} } }{y}dy \: = \: \pm \: \: dx$ On integrating both sides, we get $\rm :\longmapsto\:\displaystyle\int \dfrac{ \sqrt{1 - {y}^{2} } }{y}dy \: = \: \pm \: \: \displaystyle\int dx$ $\rm :\longmapsto\:\displaystyle\int \dfrac{y \sqrt{1 - {y}^{2} } }{ {y}^{2} }dy \: = \: \pm \: x + c$ $\rm :\longmapsto\:\displaystyle\int \dfrac{\sqrt{1 - {y}^{2} } }{ {y}^{2} }ydy \: = \: \pm \: x + c$ To integrate LHS, we use METHOD of SUBSTITUTION Put $\red{\rm :\longmapsto\: \sqrt{1 - {y}^{2} } = t}$ $\red{\rm :\longmapsto\:1 - {y}^{2} = {t}^{2}}$ $\red{\rm :\longmapsto\: - 2ydy = 2tdt}$ $\red{\rm :\longmapsto\: ydy \: = \: - \: tdt}$ So, above integral can be rewritten as, $\rm :\longmapsto\:\displaystyle\int \frac{t}{1 - {t}^{2} } ( - t \: dt) = \: \pm \: x \: + \: c$ $\rm :\longmapsto\:\displaystyle\int \frac{ - {t}^{2} }{1 - {t}^{2} } \: dt = \: \pm \: x \: + \: c$ $\rm :\longmapsto\:\displaystyle\int \frac{1 - {t}^{2} - 1}{1 - {t}^{2} } \: dt = \: \pm \: x \: + \: c$ $\rm :\longmapsto\:\displaystyle\int \frac{1 - {t}^{2}}{1 - {t}^{2} } \: dt - \displaystyle\int \frac{1}{1 - {t}^{2} }dt = \: \pm \: x \: + \: c$ $\rm :\longmapsto\:\displaystyle\int 1 \: dt + \displaystyle\int \frac{1}{{t}^{2} - 1}dt = \: \pm \: x \: + \: c$ We know, $\boxed{ \rm{ \displaystyle\int \frac{dx}{ {x}^{2} - {a}^{2} } = \frac{1}{2a}log\bigg \| \frac{x - a}{x + a} \bigg\| + c}}$ $\rm :\longmapsto\:t + \dfrac{1}{2}log\bigg \| \dfrac{t - 1}{t + 1} \bigg\| = \: \pm \: x + c$ $\rm :\longmapsto\: \sqrt{1 - {y}^{2} } + \dfrac{1}{2}log\bigg \| \dfrac{ \sqrt{1 - {y}^{2} } - 1}{ \sqrt{1 - {y}^{2} } + 1} \bigg\| = \: \pm \: x + c$ is the required curve.

6671.

If length of tangent at any point on the curve y = f(x) intercepted between the point and the X - axis is of length 1. Find the equation of the curve.

Answer»

$\large\underline{\sf{Solution-}}$

Given that,

Length of tangent at any point on the curve y = f(x), intercepted between the point and the X - axis is of length 1 unit.

We KNOW,

$\red{\rm :\longmapsto\:Length \: of \: tangent = \bigg |y \sqrt{1 + {\bigg(\dfrac{dx}{dy} \bigg) }^{2} } \bigg|}$

So, given that Length of tangent = 1

$\rm :\longmapsto\:\bigg |y \sqrt{1 + {\bigg(\dfrac{dx}{dy} \bigg) }^{2} } \bigg| = 1$

On squaring both sides, we get

$\rm :\longmapsto\: {y}^{2}\bigg(1 + {\bigg(\dfrac{dx}{dy} \bigg) }^{2} \bigg) = 1$

$\rm :\longmapsto\:1 + {\bigg(\dfrac{dx}{dy}\bigg) }^{2} = \dfrac{1}{ {y}^{2} }$

$\rm :\longmapsto\: {\bigg(\dfrac{dx}{dy}\bigg) }^{2} = \dfrac{1}{ {y}^{2} } - 1$

$\rm :\longmapsto\: {\bigg(\dfrac{dx}{dy}\bigg) }^{2} = \dfrac{1 - {y}^{2} }{ {y}^{2} }$

$\rm :\longmapsto\: {\bigg(\dfrac{dy}{dx}\bigg) }^{2} = \dfrac{{y}^{2} }{1 - {y}^{2} }$

$\bf\implies \:\dfrac{dy}{dx} \: = \: \pm \: \dfrac{y}{ \sqrt{1 - {y}^{2} } }$

$\rm :\longmapsto\: \dfrac{ \sqrt{1 - {y}^{2} } }{y}dy \: = \: \pm \: \: dx$

On integrating both sides, we get

$\rm :\longmapsto\:\displaystyle\int \dfrac{ \sqrt{1 - {y}^{2} } }{y}dy \: = \: \pm \: \: \displaystyle\int dx$

$\rm :\longmapsto\:\displaystyle\int \dfrac{y \sqrt{1 - {y}^{2} } }{ {y}^{2} }dy \: = \: \pm \: x + c$

$\rm :\longmapsto\:\displaystyle\int \dfrac{\sqrt{1 - {y}^{2} } }{ {y}^{2} }ydy \: = \: \pm \: x + c$

To integrate LHS, we use METHOD of SUBSTITUTION

Put

$\red{\rm :\longmapsto\: \sqrt{1 - {y}^{2} } = t}$

$\red{\rm :\longmapsto\:1 - {y}^{2} = {t}^{2}}$

$\red{\rm :\longmapsto\: - 2ydy = 2tdt}$

$\red{\rm :\longmapsto\: ydy \: = \: - \: tdt}$

So, above integral can be rewritten as,

$\rm :\longmapsto\:\displaystyle\int \frac{t}{1 - {t}^{2} } ( - t \: dt) = \: \pm \: x \: + \: c$

$\rm :\longmapsto\:\displaystyle\int \frac{ - {t}^{2} }{1 - {t}^{2} } \: dt = \: \pm \: x \: + \: c$

$\rm :\longmapsto\:\displaystyle\int \frac{1 - {t}^{2} - 1}{1 - {t}^{2} } \: dt = \: \pm \: x \: + \: c$

$\rm :\longmapsto\:\displaystyle\int \frac{1 - {t}^{2}}{1 - {t}^{2} } \: dt - \displaystyle\int \frac{1}{1 - {t}^{2} }dt = \: \pm \: x \: + \: c$

$\rm :\longmapsto\:\displaystyle\int 1 \: dt + \displaystyle\int \frac{1}{{t}^{2} - 1}dt = \: \pm \: x \: + \: c$

We know,

$\boxed{ \rm{ \displaystyle\int \frac{dx}{ {x}^{2} - {a}^{2} } = \frac{1}{2a}log\bigg | \frac{x - a}{x + a} \bigg| + c}}$

$\rm :\longmapsto\:t + \dfrac{1}{2}log\bigg | \dfrac{t - 1}{t + 1} \bigg| = \: \pm \: x + c$

$\rm :\longmapsto\: \sqrt{1 - {y}^{2} } + \dfrac{1}{2}log\bigg | \dfrac{ \sqrt{1 - {y}^{2} } - 1}{ \sqrt{1 - {y}^{2} } + 1} \bigg| = \: \pm \: x + c$

is the required curve.

Discussion

6672.	If the 10 digit number 8973599722 is livisible 72, then what is the value of (3x-y), for the possible greatest value of y?
Answer» Answer: For divisible by 72, the given number should be divisible by 9 and 8 both. For divisibility by 8 7x2 should be divisible by 8 So x will be 9,5,1. For divisibility by 9 difference of sum of all the numbers must be a MULTIPLE of 9 = (8+9+7+3+5+9+y+7+x+2) = 45 + 5 +y + x or 5+y+x For x = 1, 6+y = 9 y =3 for x =5 y+5+5 = 18 y=8 for x = 9 y+9+5 = 18 y=4 So, highest possible value of y is 8 which comes at x = 5 3x – y = 15 – 8 = 7 Related Questions ABCD is a quadrilateral whose SIDE AB is the diameter of a circle throABCD is a quadrilateral whose side AB is the diameter of a circle thro The value of of 5 ÷ 25 is : + – 5÷5 x (5 x 5)÷25 1 + [3/2] – 1 = 3/2The value of of 5 ÷ 25 is : + – 5÷5 x (5 x 5)÷25 1 + [3/2] – 1 = 3/2 The total number of STUDENTS in section A and B of a class is 110. TheThe total number of students in section A and B of a class is 110. The In ∆ ABC, AD bisects ∠ A which meets BC at D. If BC = a, AC = b and ABIn ∆ ABC, AD bisects ∠ A which meets BC at D. If BC = a, AC = b and AB

6672.

If the 10 digit number 8973599722 is livisible 72, then what is the value of (3x-y), for the possible greatest value of y?

Answer»

Answer:

For divisible by 72, the given number should be divisible by 9 and 8 both.

For divisibility by 8

7x2 should be divisible by 8

So x will be 9,5,1.

For divisibility by 9 difference of sum of all the numbers must be a MULTIPLE of 9

= (8+9+7+3+5+9+y+7+x+2)

= 45 + 5 +y + x or 5+y+x

For x = 1,

6+y = 9

y =3

for x =5

y+5+5 = 18

y=8

for x = 9

y+9+5 = 18

y=4

So, highest possible value of y is 8 which comes at x = 5

3x – y = 15 – 8 = 7

6673.	Q:-4 On a timeline, mark the following events:- (a) Battle of Plassey
Answer» Answer: The Battle of PLASSEY was a decisive victory of the British East India Company over a much larger force of the Nawab of Bengal and his French allies on 23 June 1757, under the leadership of ROBERT Clive. The battle helped the Company seize CONTROL of Bengal. Step-by-step explanation: PLEASE mark as brainliest n thank me

Q:-4 On a timeline, mark the following events:- (a) Battle of Plassey

Answer»

Answer:

The Battle of PLASSEY was a decisive victory of the British East India Company over a much larger force of the Nawab of Bengal and his French allies on 23 June 1757, under the leadership of ROBERT Clive. The battle helped the Company seize CONTROL of Bengal.

Step-by-step explanation:

PLEASE mark as brainliest n thank me

Discussion

6674.	1) The difference of two number is 2 and product of them is 224.Find the Numbers.
Answer» Answer: X = 16 y = 14 Step-by-step explanation: Given:- The difference of TWO number is 2 and product of them is 224. To FIND:- The Numbers Solution:- $\sf \: Let \: the \: numbers \: be \: \pink{x \: and \: y} \\ \\ \purple{\bf \: x - y = 2 - - - (i)} \\ \\$ Now to find the answer we have to find x + y $\sf \: (x + y) ^{2} = (x - y) {}^{2} + 4xy \\ \looparrowright \sf \: {(x + y)}^{2} = ( {2)}^{2} + 4(224) \\ \looparrowright \sf \: {(x + y)}^{2} = 4 + 896 \\ \looparrowright \sf \: {(x + y)}^{2} = 900 \\ \looparrowright \sf \: x + y = \sqrt{900} \\ \looparrowright \bf \purple{\:x + y = 30} \\ \\$ Now x + y = 30 x - y = 2 Adding (i) and (II) $\rm \: x + y = 30 \\ \rm \: x - y = 2 \\ - - - - - - \\ \rm \: 2x = 32 \\ \purple {\boxed {\bf x = 16}} \\ \\ \sf \: x + y = 30 \\ \sf \: 16 + y = 30 \\ \purple{ \boxed{ \bf \: y = 14}} \\ \\ \color{maroon} \boxed{\begin{array}{c} \: \sf \: x = 16 \\ \sf y = 14 \end{array}}$

6674.

1) The difference of two number is 2 and product of them is 224.Find the Numbers.

Answer»

Answer:

X = 16

y = 14

Step-by-step explanation:

Given:-

The difference of TWO number is 2 and product of them is 224.

To FIND:-

The Numbers

Solution:-

$\sf \: Let \: the \: numbers \: be \: \pink{x \: and \: y} \\ \\ \purple{\bf \: x - y = 2 - - - (i)} \\ \\$

Now to find the answer we have to find x + y

$\sf \: (x + y) ^{2} = (x - y) {}^{2} + 4xy \\ \looparrowright \sf \: {(x + y)}^{2} = ( {2)}^{2} + 4(224) \\ \looparrowright \sf \: {(x + y)}^{2} = 4 + 896 \\ \looparrowright \sf \: {(x + y)}^{2} = 900 \\ \looparrowright \sf \: x + y = \sqrt{900} \\ \looparrowright \bf \purple{\:x + y = 30} \\ \\$

Now x + y = 30

x - y = 2

Adding (i) and (II)

$\rm \: x + y = 30 \\ \rm \: x - y = 2 \\ - - - - - - \\ \rm \: 2x = 32 \\ \purple {\boxed {\bf x = 16}} \\ \\ \sf \: x + y = 30 \\ \sf \: 16 + y = 30 \\ \purple{ \boxed{ \bf \: y = 14}} \\ \\ \color{maroon} \boxed{\begin{array}{c} \: \sf \: x = 16 \\ \sf y = 14 \end{array}}$

Discussion

6675.	دوست کے نام خط جس میں پڈوسیوں کے ساتھ اچھے سلوک کی تلقین ہو
Answer» ANSWER: what LANGUAGE is this now Step-by-step EXPLANATION:

6675.

دوست کے نام خط جس میں پڈوسیوں کے ساتھ اچھے سلوک کی تلقین ہو

Answer»

ANSWER:

what LANGUAGE is this now

Step-by-step EXPLANATION:

Discussion

6676.	1) Can two small angles be the angles of each other?
Answer» Step-by-step explanation: Supplementary angles are two angles WHOSE measures add up to 180° . The two angles of a linear PAIR , like ∠1 and ∠2 in the FIGURE below, are always supplementary. But, two angles need not be ADJACENT to be supplementary. ♡──━━━━━━⊱✿⊰━━━━━━──♡ $\huge \pink{✿} \red {C} \green {u} \blue {t} \orange {e} \pink {/} \red {Q} \blue {u} \pink {e} \red {e} \green {n} \pink {♡}$

6676.

1) Can two small angles be the angles of each other?

Answer»

Step-by-step explanation:

Supplementary angles are two angles WHOSE measures add up to 180° . The two angles of a linear PAIR , like ∠1 and ∠2 in the FIGURE below, are always supplementary. But, two angles need not be ADJACENT to be supplementary.

♡──━━━━━━⊱✿⊰━━━━━━──♡

$\huge \pink{✿} \red {C} \green {u} \blue {t} \orange {e} \pink {/} \red {Q} \blue {u} \pink {e} \red {e} \green {n} \pink {♡}$

Discussion

6677.	The A.M. between m and 50 is 45, then m is: The A.M. between m and 50 is 45, then m is: 50-54095 50 -5 40 95
Answer» Answer: ID: 857 315 0870 Pe: 12345 masti time

6677.

The A.M. between m and 50 is 45, then m is: The A.M. between m and 50 is 45, then m is: 50-54095 50 -5 40 95

Answer»

Answer:

ID: 857 315 0870

Pe: 12345

masti time

Discussion

6678.	St?10. A goods train contains 1,46,000 bags of cement. If each wagon contains 25 bags, howmany wagons are loaded with cement bags?
Answer» ANSWER: Devgjbknmoomubhbycxtdzdzgcvvhjbnjkmlmnjnhvhvxre

6678.

St?10. A goods train contains 1,46,000 bags of cement. If each wagon contains 25 bags, howmany wagons are loaded with cement bags?

Answer»

ANSWER:

Devgjbknmoomubhbycxtdzdzgcvvhjbnjkmlmnjnhvhvxre

Discussion

6679.	Find value of K if x = -2 and y = 3 4x + 4y = K
Answer» Answer: 4 Step-by-step explanation: 4x+4y=k putting the value of x and y 4×(-2) + 4×3 = k -8 +12 = k 12 - 8 = k 4 = k k = 4

6679.

Find value of K if x = -2 and y = 3 4x + 4y = K

Answer»

Answer:

4

Step-by-step explanation:

4x+4y=k

putting the value of x and y

4×(-2) + 4×3 = k

-8 +12 = k

12 - 8 = k

4 = k

k = 4

Discussion

6680.	1. What sum will become 31331 after 3 years at 10% p.a. compound interest?
Answer» Step-by-step EXPLANATION: GIVEN :- A sum will become 31331 after 3 years at 10% p.a. compound interest To find:- Find the sum ? Solution :- Let the sum be Rs. X Amount = Rs. 31331 Time = 3 years Number of times the compound interest is CALCULATED for 3 years = 3 we know that Amount = P[1+(R/100)]^n On Substituting these values in the above formula then => 31331 = X[1+(10/100)]³ => 31331 = X[1+(1/10)]³ => 31331 = X[(10+1)/10]³ => 31331 = X(11/10)³ => 31331 = X(11×11×11)/10×10×10) => 31331 = X(1331/1000) => 31331 = 1331X/1000 => 1331X = 31331 × 1000 => 1331X = 31331000 => X = 31331000/1331 => X = 23,539.44 The sum = Rs. 23,539.44 Answer:- The sum for the given problem is Rs. 23,539.44 Used formulae:- Amount = P[1+(R/100)]^n P = Principle R = Rate of Interest n = Number of times the compound interest is calculated per annum

6680.

1. What sum will become 31331 after 3 years at 10% p.a. compound interest?

Answer»

Step-by-step EXPLANATION:

GIVEN :-

A sum will become 31331 after 3 years at 10% p.a. compound interest

To find:-

Find the sum ?

Solution :-

Let the sum be Rs. X

Amount = Rs. 31331

Time = 3 years

Number of times the compound interest is CALCULATED for 3 years = 3

we know that

Amount = P[1+(R/100)]^n

On Substituting these values in the above formula then

=> 31331 = X[1+(10/100)]³

=> 31331 = X[1+(1/10)]³

=> 31331 = X[(10+1)/10]³

=> 31331 = X(11/10)³

=> 31331 = X(11×11×11)/10×10×10)

=> 31331 = X(1331/1000)

=> 31331 = 1331X/1000

=> 1331X = 31331 × 1000

=> 1331X = 31331000

=> X = 31331000/1331

=> X = 23,539.44

The sum = Rs. 23,539.44

Answer:-

The sum for the given problem is Rs. 23,539.44

Used formulae:-

Amount = P[1+(R/100)]^n
P = Principle
R = Rate of Interest
n = Number of times the compound interest is calculated per annum

Discussion

6681.	Please give the answer of this question with process as fast as possible and correct answer. No other messages. First who will give the correct answer with process will be marked as Brainliest.
Answer» ANSWER: $\large\mathbb\red{18. (c) \: \frac{4}{5} }$ $\large\mathbb\pink{19. (b) \: \frac{585}{999} }$ HOPE it HELPS you!

6681.

Please give the answer of this question with process as fast as possible and correct answer. No other messages. First who will give the correct answer with process will be marked as Brainliest.

Answer»

ANSWER:

$\large\mathbb\red{18. (c) \: \frac{4}{5} }$

$\large\mathbb\pink{19. (b) \: \frac{585}{999} }$

HOPE it HELPS you!

Discussion

6682.	the given figure ab parallel CD and BCE is a straight line if angle abc is equal to 50 degree and angle BAC ratio angle ACB is equal to 2 ratio 3 find angle ACD
Answer» angle abc =50 given ab// dc means angle abc = angle dce =50 STRAIGHT line angle SUM = 180 degrees here straight line= angle ABC +ACD+DCE 180=50+angle ACD+50 180=100+ACD ANGLE ANGLE ACD =180-100=80 Angle ACD=180 brainly.in/question/35330370 i am sorry if i GOT this WRONG

6682.

the given figure ab parallel CD and BCE is a straight line if angle abc is equal to 50 degree and angle BAC ratio angle ACB is equal to 2 ratio 3 find angle ACD

Answer»

angle abc =50 given

ab// dc means angle abc = angle dce =50

STRAIGHT line angle SUM = 180 degrees

here straight line= angle ABC +ACD+DCE

180=50+angle ACD+50

180=100+ACD ANGLE

ANGLE ACD =180-100=80

Angle ACD=180

brainly.in/question/35330370

i am sorry if i GOT this WRONG

Discussion

6683.	What is the answer ? Please give me the correct answer . Thank You .
Answer» B OPTION is correct Step-by-step EXPLANATION: MARK as brainly PLEASE

6683.

What is the answer ? Please give me the correct answer . Thank You .

Answer»

B OPTION is correct

Step-by-step EXPLANATION:

MARK as brainly PLEASE

Discussion

6684.	Express the following rational number as decimal 327/507
Answer» Answer: As the given number 327/507 = 109/169 is rational, and the denominator is 169 =13×13, its decimal expansion must be repeating, because only those rational numbers have terminating decimal REPRESENTATIONS whose denominator has no PRIME FACTORS other than 2 and 5.

6684.

Express the following rational number as decimal 327/507

Answer»

Answer:

As the given number 327/507 = 109/169 is rational, and the denominator is 169 =13×13, its decimal expansion must be repeating, because only those rational numbers have terminating decimal REPRESENTATIONS whose denominator has no PRIME FACTORS other than 2 and 5.

Discussion

6685.	Show that 5-2i/3+i + 5+2i /3-i is real no.
Answer» Step-by-step EXPLANATION: distribute the brackets using FOIL( or any method you USE) ( 5 − 2 i ) ( 5 + 2 i ) = 25 + 10 i − 10 i − 4 i 2 [ this process is useful in COMPLEX numbers as the product produces a real number - the 2nd bracket is the complex conjugate of the 1st and vice-versa.] [ NOTE : i 2 = ( √ − 1 ) 2 = − 1 ] ⇒ ( 5 − 2 i ) ( 5 + 2 i ) = 25 + 10 i − 10 i + 4 = 29 a real number

6685.

Show that 5-2i/3+i + 5+2i /3-i is real no.

Answer»

Step-by-step EXPLANATION:

distribute the brackets using FOIL( or any method you USE)

(

5

−

2

i

)

(

5

+

2

i

)

=

25

+

10

i

−

10

i

−

4

i

2

[ this process is useful in COMPLEX numbers as the product produces a real number - the 2nd bracket is the complex conjugate of the 1st and vice-versa.]

[ NOTE :

i

2

=

(

√

−

1

)

2

=

−

1

]

⇒

(

5

−

2

i

)

(

5

+

2

i

)

=

25

+

10

i

−

10

i

+

4

=

29

a real number

Discussion

6686.	A sum of money at compound interest amounts to Rs.650 at the end of the first year and Rs.676 at the end of the second year. The sum of money is, Find the rateof interest? a. Rs. 1300 b. Rs.650 C. Rs.1250 d. Rs.625
Answer» Answer: A sum of money invested at COMPOUND interest AMOUNT to RS. 650 at the END of first year and Rs. 676 at the end of second year. The sum of ...

6686.

A sum of money at compound interest amounts to Rs.650 at the end of the first year and Rs.676 at the end of the second year. The sum of money is, Find the rateof interest? a. Rs. 1300 b. Rs.650 C. Rs.1250 d. Rs.625

Answer»

Answer:

A sum of money invested at COMPOUND interest AMOUNT to RS. 650 at the END of first year and Rs. 676 at the end of second year. The sum of ...

Discussion

6687.	2+3+4+...+(n-1)= find the value
Answer» Step-by-step explanation: As I KNOW the formula for ADDING 1,2,3…n is given by n(n+1)/2 Comparing to above formula if we want to calculate sum up to n-1 , using the above formula we GET n-1(n-1+1)/2 That is n(n-1)/2 Thus the required formula is n(n-1)/2

6687.

2+3+4+...+(n-1)= find the value

Answer»

Step-by-step explanation:

As I KNOW the formula for ADDING 1,2,3…n is given by n(n+1)/2

Comparing to above formula if we want to calculate sum up to n-1 , using the above formula we GET n-1(n-1+1)/2

That is n(n-1)/2

Thus the required formula is n(n-1)/2

Discussion

6688.	The product of 'q' and 20 is '20q' true or false
Answer» ANSWER: QUESTION = the product of 'Q' and 20 is '20q' TRUE or false Step-by-step EXPLANATION: answer = true

6688.

The product of 'q' and 20 is '20q' true or false

Answer»

ANSWER:

QUESTION = the product of 'Q' and 20 is '20q'

TRUE or false

Step-by-step EXPLANATION:

answer = true

Discussion

6689.	Paper sheets each of thickness 1.8×10−2 cm are stacked such that the total thickness of the stack is 10.8 cm. Find the number of paper sheets.
Answer» Answer: 600 Step-by-step EXPLANATION: THICKNESS of 1 SHEET = (1.8 × 10-2)cm = 0.018cm Total thickness of sheets = 10.8cm Therefore, Total no. of sheets = 10.8 ÷ 0.018 = 600

6689.

Paper sheets each of thickness 1.8×10−2 cm are stacked such that the total thickness of the stack is 10.8 cm. Find the number of paper sheets.

Answer»

Answer:

600

Step-by-step EXPLANATION:

THICKNESS of 1 SHEET = (1.8 × 10-2)cm

= 0.018cm

Total thickness of sheets = 10.8cm

Therefore, Total no. of sheets = 10.8 ÷ 0.018

= 600

Discussion

6690.	The distance of the point (5, 2) from X axis is
Answer» Step-by-step explanation: DISTANCE of POINT (5, –2) from X-axis = ordinate of the point = \|–2\| = 2

6690.

The distance of the point (5, 2) from X axis is

Answer»

Step-by-step explanation:

DISTANCE of POINT (5, –2) from X-axis = ordinate of the point = |–2| = 2

Discussion

6691.	Product of two numbers is 96 and the LCM is 32.The HCF of the number will be:a.32b.3c.9d.6
Answer» Step-by-step EXPLANATION: B) 3 hope it HELPS :):):):)

6691.

Product of two numbers is 96 and the LCM is 32.The HCF of the number will be:a.32b.3c.9d.6

Answer»

Step-by-step EXPLANATION:

B) 3

hope it HELPS

:):):):)

Discussion

6692.	0.19 x 27 step by step explanation like you Multiplying in book
Answer» Answer: 0.19 X 27=5.13 Step-by-step explanation: PLEASE MARK as brainliest n THANK me

6692.

0.19 x 27 step by step explanation like you Multiplying in book

Answer»

Answer:

0.19 X 27=5.13

Step-by-step explanation:

PLEASE MARK as brainliest n THANK me

Discussion

6693.	If one of the zero of the quadratic polynomial f(x) = 4x2 – 8kx – 9 is equal in magnitude but opposite in sign of the other, find the value of k
Answer» ANSWER: HEY MATE HOPE it HELPS you

6693.

If one of the zero of the quadratic polynomial f(x) = 4x2 – 8kx – 9 is equal in magnitude but opposite in sign of the other, find the value of k

Answer»

ANSWER:

HEY MATE HOPE it HELPS you

Discussion

6694.	3 ratinal numbers between 1.201 and 1.21
Answer» ANSWER: OKAY I don't KNOW the answer

6694.

3 ratinal numbers between 1.201 and 1.21

Answer»

ANSWER:

OKAY I don't KNOW the answer

Discussion

6695.	a and b can do a piece of work in 6 days,b in 8 days and c in 4 days. if all work together, how much money should each receive?
Answer» Answer: A should get 1/24 the MONEY while b and c should get 1/8 and 1/4 money respectively Step-by-step EXPLANATION: It is CALCULATED from the reciprocal of days TAKEN to finish the WORK Hence, Work done by A =

6695.

a and b can do a piece of work in 6 days,b in 8 days and c in 4 days. if all work together, how much money should each receive?

Answer»

Answer:

A should get 1/24 the MONEY while b and c should get 1/8 and 1/4 money respectively

Step-by-step EXPLANATION:

It is CALCULATED from the reciprocal of days TAKEN to finish the WORK

Hence,

Work done by A =

Discussion

6696.	What is the probability of getting a face card
Answer» ANSWER: The probability of DRAWING a red FACE CARD from a deck of cards is 3/26.

6696.

What is the probability of getting a face card

Answer»

ANSWER:

The probability of DRAWING a red FACE CARD from a deck of cards is 3/26.

Discussion

6697.	Verify -2/5+[3/5+1/2]=[-2/5+3/5]+1/2
Answer» question: VERIFY -2/5+[3/5+1/2]=[-2/5+3/5]+1/2 answer: LHS = $\frac{ - 2}{5} + { \frac{3}{5} + \frac{1}{2} } = \frac{6 + 5}{10} + \frac{ - 2}{5} = \frac{11 - 4}{10} = \frac{7}{10}$ RHS = $\frac{ - 2}{5} + \frac{3}{5} + \frac{1}{2} = \frac{ 1}{5} + \frac{1}{2} = \frac{5 + 2}{10} = \frac{7}{10}$ hence LHS=RHS hence PROVED . hope it HELPS you ☺️

6697.

Verify -2/5+[3/5+1/2]=[-2/5+3/5]+1/2

Answer»

question:

VERIFY -2/5+[3/5+1/2]=[-2/5+3/5]+1/2

answer:

LHS =

$\frac{ - 2}{5} + { \frac{3}{5} + \frac{1}{2} } = \frac{6 + 5}{10} + \frac{ - 2}{5} = \frac{11 - 4}{10} = \frac{7}{10}$

RHS =

$\frac{ - 2}{5} + \frac{3}{5} + \frac{1}{2} = \frac{ 1}{5} + \frac{1}{2} = \frac{5 + 2}{10} = \frac{7}{10}$

hence LHS=RHS

hence PROVED .

hope it HELPS you ☺️

Discussion

6698.	30 more than 20×5 is _______
Answer» Answer: HEY!! Ur answer: $(205)+30\\ =100+30\\ =130$ Step-by-step EXPLANATION:* Hope it HELPS U!! Please mark me BRAINLIEST :)

6698.

30 more than 20×5 is _______

Answer»

Answer:

HEY!! Ur answer:

$(20*5)+30\\ =100+30\\ =130$

Step-by-step EXPLANATION:

Hope it HELPS U!! Please mark me BRAINLIEST :)

Discussion

6699.	X × y^a × z^-1 pls answer only if u know
Answer» Step-by-step explanation: hlo mate here's your answer SOLUTION Note that: You can only add inequalities when their signs are in the same direction: If and (signs in same direction: and ) --> . Example: and --> . You can only apply subtraction when their signs are in the opposite directions: If and (signs in opposite direction: and ) --> (take the sign of the inequality you subtract from). Example: and --> . Back to the original question: If x + y + z > 0, is z > 1? (1) z > x + y + 1 --> as the signs are in the same direction we can add two inequalities: --> --> , so z may or may not be more than 1. Not sufficient. (2) x + y + 1 < 0 --> as the signs are in the opposite direction we can subtract two inequalities: --> --> . Sufficient. I HOPE IT HELPS YOU PLZ MARK AS BRAINLIST AND GIVE THANKS

6699.

X × y^a × z^-1 pls answer only if u know

Answer»

Step-by-step explanation:

hlo mate here's your answer

SOLUTION

Note that:

You can only add inequalities when their signs are in the same direction:

If

and

(signs in same direction:

and

) -->

.

Example:

and

-->

.

You can only apply subtraction when their signs are in the opposite directions:

If

and

(signs in opposite direction:

and

) -->

(take the sign of the inequality you subtract from).

Example:

and

-->

.

Back to the original question:

If x + y + z > 0, is z > 1?

(1) z > x + y + 1 --> as the signs are in the same direction we can add two inequalities:

-->

, so z may or may not be more than 1. Not sufficient.

(2) x + y + 1 < 0 --> as the signs are in the opposite direction we can subtract two inequalities:

-->

. Sufficient.

I HOPE IT HELPS YOU PLZ MARK AS BRAINLIST AND GIVE THANKS

Discussion

6700.	Please solve this equation
Answer» Step-by-step explanation: HOPE its HELP U answer in PICTURE

6700.

Please solve this equation

Answer»

Step-by-step explanation:

HOPE its HELP U answer in PICTURE

Discussion

Explore topic-wise InterviewSolutions in .

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OPTION (d) is correct.

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Multiply -24×-12×-4 using steps ​

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3) Can two short angles complement each other?.​

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YES LHS= RHS

explanation

-30= -30❤

Hope it HELPS you mate❤

2ಮತು3ರ ನಡುವಿನ ಭಾಗಲಬದ ಸಂಖ್ಯೆ​

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1) The difference of two number is 2 and product of them is 224.Find the Numbers.

Given:-

To FIND:-

Solution:-

دوست کے نام خط جس میں پڈوسیوں کے ساتھ اچھے سلوک کی تلقین ہو​

1) Can two small angles be the angles of each other?​

The A.M. between m and 50 is 45, then m is: The A.M. between m and 50 is 45, then m is: *50-54095* 50 -5 40 95​

St?10. A goods train contains 1,46,000 bags of cement. If each wagon contains 25 bags, howmany wagons are loaded with cement bags?​

Find value of K if x = -2 and y = 3 4x + 4y = K​

1. What sum will become 31331 after 3 years at 10% p.a. compound interest?​

GIVEN :-

To find:-

Solution :-

Answer:-

Used formulae:-

Please give the answer of this question with process as fast as possible and correct answer. No other messages. First who will give the correct answer with process will be marked as Brainliest.​

HOPE it HELPS you!

the given figure ab parallel CD and BCE is a straight line if angle abc is equal to 50 degree and angle BAC ratio angle ACB is equal to 2 ratio 3 find angle ACD​

What is the answer ? Please give me the correct answer . Thank You .

Express the following rational number as decimal 327/507 ​

Show that 5-2i/3+i + 5+2i /3-i is real no.​

A sum of money at compound interest amounts to Rs.650 at the end of the first year and Rs.676 at the end of the second year. The sum of money is, Find the rateof interest? a. Rs. 1300 b. Rs.650 C. Rs.1250 d. Rs.625 ​

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If one of the zero of the quadratic polynomial f(x) = 4x2 – 8kx – 9 is equal in magnitude but opposite in sign of the other, find the value of k​

3 ratinal numbers between 1.201 and 1.21

a and b can do a piece of work in 6 days,b in 8 days and c in 4 days. if all work together, how much money should each receive?​

What is the probability of getting a face card​

Verify -2/5+[3/5+1/2]=[-2/5+3/5]+1/2​

30 more than 20×5 is _______​

X × y^a × z^-1 pls answer only if u know​

hlo mate here's your answer

SOLUTION

Note that:

You can only add inequalities when their signs are in the same direction:

If

and

(signs in same direction:

and

) -->

.

Example:

and

-->

.

You can only apply subtraction when their signs are in the opposite directions:

If

and

Confused between option c and d

Multiply -24×-12×-4 using steps

Find each the fallowing-a)5+(-4)-(-6)+(-2)-(-3)b) 3-(-5)+4-(-7)+(-2)-(-4)+(-3)-(-2)c) 2×-4×3×-2×4×-5×-3×-2d) -4×-2×-1×4×-2×-3×-2×4×-2×3e) 5+(-3)-(-4)-(-6)+(-4)-(-3)+(-5)please help for slove it

add the following polynomials and find the degree of the resultant polynomial P(y)= 6y²-7y+2; q(y)=7y+y³

3) Can two short angles complement each other?.

[(-5)×2)]×3=(-5)×[(2×3)]?

2ಮತು3ರ ನಡುವಿನ ಭಾಗಲಬದ ಸಂಖ್ಯೆ

If the 10 digit number 8973599722 is livisible 72, then what is the value of (3x-y), for the possible greatest value of y?

Q:-4 On a timeline, mark the following events:- (a) Battle of Plassey

دوست کے نام خط جس میں پڈوسیوں کے ساتھ اچھے سلوک کی تلقین ہو

1) Can two small angles be the angles of each other?

The A.M. between m and 50 is 45, then m is: The A.M. between m and 50 is 45, then m is: 50-54095 50 -5 40 95

St?10. A goods train contains 1,46,000 bags of cement. If each wagon contains 25 bags, howmany wagons are loaded with cement bags?

Find value of K if x = -2 and y = 3 4x + 4y = K

1. What sum will become 31331 after 3 years at 10% p.a. compound interest?

Please give the answer of this question with process as fast as possible and correct answer. No other messages. First who will give the correct answer with process will be marked as Brainliest.

the given figure ab parallel CD and BCE is a straight line if angle abc is equal to 50 degree and angle BAC ratio angle ACB is equal to 2 ratio 3 find angle ACD

Express the following rational number as decimal 327/507

Show that 5-2i/3+i + 5+2i /3-i is real no.

A sum of money at compound interest amounts to Rs.650 at the end of the first year and Rs.676 at the end of the second year. The sum of money is, Find the rateof interest? a. Rs. 1300 b. Rs.650 C. Rs.1250 d. Rs.625

2+3+4+...+(n-1)= find the value

The product of 'q' and 20 is '20q' true or false

The distance of the point (5, 2) from X axis is

Product of two numbers is 96 and the LCM is 32.The HCF of the number will be:a.32b.3c.9d.6

0.19 x 27 step by step explanation like you Multiplying in book

If one of the zero of the quadratic polynomial f(x) = 4x2 – 8kx – 9 is equal in magnitude but opposite in sign of the other, find the value of k

a and b can do a piece of work in 6 days,b in 8 days and c in 4 days. if all work together, how much money should each receive?

What is the probability of getting a face card

Verify -2/5+[3/5+1/2]=[-2/5+3/5]+1/2

30 more than 20×5 is _______

X × y^a × z^-1 pls answer only if u know

Please solve this equation