332354 + Interview Questions in Secondary School in Math Page 190 InterviewSolution

9451.	If x and y are two sets such that n(x) =33 ,n(y)=42 and n(x y) is 70bthen n(x y) is?a:-)145.b) 5c) 10d)0
Answer» ANSWER: 46 is the answer PLEASE MARK me as BRAINLIST

9451.

If x and y are two sets such that n(x) =33 ,n(y)=42 and n(x y) is 70bthen n(x y) is?a:-)145.b) 5c) 10d)0

Answer»

ANSWER:

46 is the answer PLEASE MARK me as BRAINLIST

Discussion

9452.	2x 2-7x-1=0 solve this to two decimal places answer fast please
Answer» ANSWER: HELLO DEAR , here is your answer , I HOPE this HELPS you ,

9452.

2x 2-7x-1=0 solve this to two decimal places answer fast please

Answer»

ANSWER:

HELLO DEAR , here is your answer , I HOPE this HELPS you ,

Discussion

9453.	Please follow2. Solve the problems given below.Represent the following situations mathematically:(i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.(ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was ₹ 750. We would like to find out the number of toys produced on that day.
Answer» Answer: Step-by-step explanation: Given JOHN and jivanti together have 45 MARBLES LET the number of Marbles John had be= x Then the number of marbles jivanti had= 45-x Both of them lost 5 Marbles each Therefore, the number of marbles John had= x-5 The number of marbles jivanti had= 45-x-5= 40-x Now product of the number of Marbles =124 Therefore , (x-5)(40-x)=124 40- x²-200+5x=124 -x²+45x-200-124=0 x² -45x+324=0. (Multiplying by(-1)) By factorisation method x²-36x-9x+324=0 x(x-36) - 9(x-36)=0 (x-36)(x-9)=0 x=36 or x= 9 When John has 36 Marbles and jivanti has = 45-x= 45-36=9 marbles When John has 9 Marbles and jivanti has= 45-x= 45- 9= 36 marbles ii) Let the number of toys produced on that day be x. Therefore the COST of production of each toy that day= 55 - x So the total cost production that day=number of toys× cost of production of each toy that day Total cost of production of toy= x × (55-x) A.T.Q.. x(55-x)=750 55x -x²= 750 -x²+55x-750=0 x²-55x+750=0 x²- 30x -25x+750=0 x(x-30)-25(x-30)=0 (x-30)(x-25)=0 x-30=0 x=30 x-25=0 x=25 Hence, the number of toys produced= x=25 or 30

9453.

Please follow2. Solve the problems given below.Represent the following situations mathematically:(i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.(ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was ₹ 750. We would like to find out the number of toys produced on that day.

Answer»

Answer:

Step-by-step explanation:

Given JOHN and jivanti together have 45 MARBLES

LET the number of Marbles John had be= x

Then the number of marbles jivanti had= 45-x

Both of them lost 5 Marbles each

Therefore, the number of marbles John had= x-5

The number of marbles jivanti had= 45-x-5= 40-x

Now product of the number of Marbles =124

Therefore , (x-5)(40-x)=124

40- x²-200+5x=124

-x²+45x-200-124=0

x² -45x+324=0. (Multiplying by(-1))

By factorisation method

x²-36x-9x+324=0

x(x-36) - 9(x-36)=0

(x-36)(x-9)=0

x=36 or x= 9

When John has 36 Marbles and jivanti has = 45-x= 45-36=9 marbles

When John has 9 Marbles and jivanti has= 45-x= 45- 9= 36 marbles

ii) Let the number of toys produced on that day be x.

Therefore the COST of production of each toy that day= 55 - x

So the total cost production that day=number of toys× cost of production of each toy that day

Total cost of production of toy=

x × (55-x)

A.T.Q..

x(55-x)=750

55x -x²= 750

-x²+55x-750=0

x²-55x+750=0

x²- 30x -25x+750=0

x(x-30)-25(x-30)=0

(x-30)(x-25)=0

x-30=0

x=30

x-25=0

x=25

Hence, the number of toys produced= x=25 or 30

Discussion

9454.	The multiplactive inverse of 1/4 is
Answer» the MULTIPLICATIVE INVERSE of 1/4 is 4/1 because 1/4×4/1 = 1

9454.

The multiplactive inverse of 1/4 is

Answer»

the MULTIPLICATIVE INVERSE of 1/4 is 4/1

because 1/4×4/1 = 1

Discussion

9455.	The 3-digit numbers formed by using the digits 4, 9 and 5 such that 5 is in the tens place are and
Answer» Answer: BRO with that NUMBERS GREATEST is 9554 smallest number is 4559

9455.

The 3-digit numbers formed by using the digits 4, 9 and 5 such that 5 is in the tens place are and

Answer»

Answer:

BRO with that NUMBERS GREATEST is 9554

smallest number is 4559

Discussion

9456.	The set of all even prime numbers is: *an1.infinite set2.a null set3.a singleton set4.none of these
Answer» Answer: 1.infinite set Step-by-step EXPLANATION: HOPE it HELPS you

9456.

The set of all even prime numbers is: *an1.infinite set2.a null set3.a singleton set4.none of these

Answer»

Answer:

1.infinite set

Step-by-step EXPLANATION:

HOPE it HELPS you

Discussion

9457.	Please follow1. Find the roots of the following quadratic equations by factorisation:(i) 2 − 3 − 10 = 0 (ii) 22 + − 6 = 0(iii) √2 2 + 7 + 5√2 = 0 (iv) 22 − + 18= 0(v) 1002 − 20 + 1 = 0
Answer» Answer: (i) x2 – 3x – 10 = x2 - 5x + 2x - 10 = x(x - 5) + 2(x - 5) = (x - 5)(x + 2) Roots of this equation are the values for which (x - 5)(x + 2) = 0 ∴ x - 5 = 0 or x + 2 = 0 ⇒ x = 5 or x = -2 (II) 2x2 + x – 6 = 2x2 + 4X - 3x - 6 = 2x(x + 2) - 3(x + 2) = (x + 2)(2x - 3) Roots of this equation are the values for which (x + 2)(2x - 3) = 0 ∴ x + 2 = 0 or 2x - 3 = 0 ⇒ x = -2 or x = 3/2 (III) √2 x2 + 7x + 5√2 = √2 x2 + 5x + 2x + 5√2 = x (√2x + 5) + √2(√2x + 5)= (√2x + 5)(x + √2) Roots of this equation are the values for which (√2x + 5)(x + √2) = 0 ∴ √2x + 5 = 0 or x + √2 = 0 ⇒ x = -5/√2 or x = -√2 (iv) 2x2 – x + 1/8 = 1/8 (16x2 - 8x + 1) = 1/8 (16x2 - 4x -4x + 1) = 1/8 (4x(4x - 1) -1(4x - 1)) = 1/8(4x - 1)2 Roots of this equation are the values for which (4x - 1)2 = 0 ∴ (4x - 1) = 0 or (4x - 1) = 0 ⇒ x = 1/4 or x = 1/4 (v) 100x2 – 20x + 1 = 100x2 – 10X - 10x + 1 = 10x(10x - 1) -1(10x - 1) = (10x - 1)2 Roots of this equation are the values for which (10x - 1)2 = 0 ∴ (10x - 1) = 0 or (10x - 1) = 0 ⇒ x = 1/10 or x = 1/10

9457.

Please follow1. Find the roots of the following quadratic equations by factorisation:(i) 2 − 3 − 10 = 0 (ii) 22 + − 6 = 0(iii) √2 2 + 7 + 5√2 = 0 (iv) 22 − + 18= 0(v) 1002 − 20 + 1 = 0

Answer»

Answer:

(i) x2 – 3x – 10

= x2 - 5x + 2x - 10

= x(x - 5) + 2(x - 5)

= (x - 5)(x + 2)

Roots of this equation are the values for which (x - 5)(x + 2) = 0

∴ x - 5 = 0 or x + 2 = 0

⇒ x = 5 or x = -2

(II) 2x2 + x – 6

= 2x2 + 4X - 3x - 6

= 2x(x + 2) - 3(x + 2)

= (x + 2)(2x - 3)

Roots of this equation are the values for which (x + 2)(2x - 3) = 0

∴ x + 2 = 0 or 2x - 3 = 0

⇒ x = -2 or x = 3/2

(III) √2 x2 + 7x + 5√2

= √2 x2 + 5x + 2x + 5√2

= x (√2x + 5) + √2(√2x + 5)= (√2x + 5)(x + √2)

Roots of this equation are the values for which (√2x + 5)(x + √2) = 0

∴ √2x + 5 = 0 or x + √2 = 0

⇒ x = -5/√2 or x = -√2

(iv) 2x2 – x + 1/8

= 1/8 (16x2 - 8x + 1)

= 1/8 (16x2 - 4x -4x + 1)

= 1/8 (4x(4x - 1) -1(4x - 1))

= 1/8(4x - 1)2

Roots of this equation are the values for which (4x - 1)2 = 0

∴ (4x - 1) = 0 or (4x - 1) = 0

⇒ x = 1/4 or x = 1/4

(v) 100x2 – 20x + 1

= 100x2 – 10X - 10x + 1

= 10x(10x - 1) -1(10x - 1)

= (10x - 1)2

Roots of this equation are the values for which (10x - 1)2 = 0

∴ (10x - 1) = 0 or (10x - 1) = 0

⇒ x = 1/10 or x = 1/10

Discussion

9458.	A bag contains 40 mangoes and some oranges. take one from this. the probability of getting a mango is 4/7. How many fruits are there in the box? What is the probability of getting an orange? If 15 mangoes are taken out from the box. What will be the probability of getting an orange?
Answer» Step-by-step EXPLANATION: hijii HI hello how R u im BAD. boy

9458.

A bag contains 40 mangoes and some oranges. take one from this. the probability of getting a mango is 4/7. How many fruits are there in the box? What is the probability of getting an orange? If 15 mangoes are taken out from the box. What will be the probability of getting an orange?

Answer»

Step-by-step EXPLANATION:

hijii HI hello how R u im BAD. boy

Discussion

9459.	Find the sum of series 1/3 + 1/15 + 1/35 to 'n' termsIf you answer this question, I will mark you as brainliest
Answer» ANSWER: N/(2n+1) Step-by-step explanation: 1/3+1/31/5+1/51/7+1/7*1/9 and so on

9459.

Find the sum of series 1/3 + 1/15 + 1/35 to 'n' termsIf you answer this question, I will mark you as brainliest

Answer»

ANSWER:

N/(2n+1)

Step-by-step explanation:

1/3+1/3*1/5+1/5*1/7+1/7*1/9 and so on

Discussion

9460.	By what number 2/5 should be multiplied as to get -1
Answer» ANSWER: it's answer I have GIVEN to ANOTHER USER

9460.

By what number 2/5 should be multiplied as to get -1

Answer»

ANSWER:

it's answer I have GIVEN to ANOTHER USER

Discussion

9461.	. Verify whether 2 and o are zeroes of polynomial x3 - 2x² true or false
Answer» Answer: 0 is the ZERO of the POLYNOMIAL but 2 is not

9461.

. Verify whether 2 and o are zeroes of polynomial x3 - 2x² true or false

Answer»

Answer:

0 is the ZERO of the POLYNOMIAL but 2 is not

Discussion

9462.	If a^2-a+1=0 find a^38+1/a^38
Answer» Step-by-step EXPLANATION: HOPE it is helpful.Please VERIFY

9462.

If a^2-a+1=0 find a^38+1/a^38

Answer»

Step-by-step EXPLANATION:

HOPE it is helpful.Please VERIFY

Discussion

9463.	Using prime factorisation method, find which of the following numbers are perfect squares. (a) 4489
Answer» Step-by-step explanation: The number 4489 is composite and therefore it will have prime FACTORS. Now let us learn how to calculate the prime factors of 4489. The first step is to divide the number 4489 with the smallest prime FACTOR, here it is 67. We keep dividing until it gives a non-zero remainder. 4489 ÷ 67 = 67 67 ÷ 67 = 1 Further dividing 1 by 67 gives a non-zero remainder. So we stop the PROCESS and CONTINUE dividing the number 1 by the next smallest prime factor. We stop ULTIMATELY if the next prime factor doesn't exist or when we can't divide any further. Since, we can't divide any further in this case so we stop. So, the prime factorization of 4489 is 67²

9463.

Using prime factorisation method, find which of the following numbers are perfect squares. (a) 4489

Answer»

Step-by-step explanation:

The number 4489 is composite and therefore it will have prime FACTORS. Now let us learn how to calculate the prime factors of 4489. The first step is to divide the number 4489 with the smallest prime FACTOR, here it is 67. We keep dividing until it gives a non-zero remainder.

4489 ÷ 67 = 67

67 ÷ 67 = 1

Further dividing 1 by 67 gives a non-zero remainder. So we stop the PROCESS and CONTINUE dividing the number 1 by the next smallest prime factor. We stop ULTIMATELY if the next prime factor doesn't exist or when we can't divide any further.

Since, we can't divide any further in this case so we stop.

So, the prime factorization of 4489 is 67²

Discussion

9464.	2. Represent the following situations in the form of quadratic equations:(i) The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.(ii) The product of two consecutive positive integers is 306. We need to find the integers.(iii) Rohan’s mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan’s present age.(iv) A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km⁄h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.
Answer» Step-by-step explanation: LET us write the multiples of 3. Multiples of 3 are 3, 6, 9, 12, 15... etc. We can ALSO write this as Multiples of 3=3×n, where n = 1, 2, 3, ... m = 3 n. m is the multiple of 3 Thus, we have the following table. n 1 2 3 4 5 m=3n 3 6 9 12 15 Points: (1 , 3), (2 , 6), (3 , 9), (4 , 12), (5 , 15). PLOT all these points and JOIN them. We get the graph for multiples of 3.

9464.

2. Represent the following situations in the form of quadratic equations:(i) The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.(ii) The product of two consecutive positive integers is 306. We need to find the integers.(iii) Rohan’s mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan’s present age.(iv) A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km⁄h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.

Answer»

Step-by-step explanation:

LET us write the multiples of 3. Multiples of 3 are 3, 6, 9, 12, 15... etc.

We can ALSO write this as Multiples of 3=3×n, where n = 1, 2, 3, ... m = 3 n. m is the multiple of 3

Thus, we have the following table.

n 1 2 3 4 5

m=3n 3 6 9 12 15

Points: (1 , 3), (2 , 6), (3 , 9), (4 , 12), (5 , 15).

PLOT all these points and JOIN them. We get the graph for multiples of 3.

Discussion

9465.	7200 रु॰ की राशि 5 वर्षों में 8100 रु॰ हो जाती है । दर को कितना कम कर दिया जाए ताकि मिश्रधन 540 रु॰ कम प्राप्त हो?
Answer» ANSWER: BUBU MU Step-by-step EXPLANATION:

9465.

7200 रु॰ की राशि 5 वर्षों में 8100 रु॰ हो जाती है । दर को कितना कम कर दिया जाए ताकि मिश्रधन 540 रु॰ कम प्राप्त हो?

Answer»

ANSWER:

BUBU MU

Step-by-step EXPLANATION:

Discussion

9466.	Write the sequence natural numbers which leave remainder 1 on division by 4 ? a). Write its algebraic form ? b). Find its 100 th term?
Answer» Answer: 9,13,17,21,25 etc are SEQUENCE NATURAL NUMBERS which leaves remainder 1 on division by 4. It's ALGEBRAIC form is 9x,13x,17x,21x,25x It's 100th TERM is

9466.

Write the sequence natural numbers which leave remainder 1 on division by 4 ? a). Write its algebraic form ? b). Find its 100 th term?

Answer»

Answer:

9,13,17,21,25 etc are SEQUENCE NATURAL NUMBERS which leaves remainder 1 on division by 4.

It's ALGEBRAIC form is 9x,13x,17x,21x,25x

It's 100th TERM is

Discussion

9467.	find the zeros of each of the following quadratic polynomial also, in each case verify the relationship between the zeros and coefficient :x2-7x+10
Answer» Answer: Given QUADRATIC POLYNOMIAL x2 + 7x + 10 Using factorisation (splitting the middle term) x2 + 7x + 10 = 0 x2 + (5X + 2x) + 10 = 0 x2 + 5x + 2x + 10 = 0 x(x + 5) + 2 (x + 5) = 0 (x + 5) (x + 2) = 0 Hence, ZEROES of a given quadratic polynomial are – 5 and – 2. Sum of zeroes = -2+(-5) = -2-5 = -7/1 = -x COEFFICIENT /x² coefficient Product of zeroes = (-2)(-5) = 10/1 = constant/x² coefficient

9467.

find the zeros of each of the following quadratic polynomial also, in each case verify the relationship between the zeros and coefficient :x2-7x+10

Answer»

Answer:

Given QUADRATIC POLYNOMIAL x2 + 7x + 10

Using factorisation (splitting the middle term)

x2 + 7x + 10 = 0

x2 + (5X + 2x) + 10 = 0

x2 + 5x + 2x + 10 = 0

x(x + 5) + 2 (x + 5) = 0

(x + 5) (x + 2) = 0

Hence, ZEROES of a given quadratic polynomial are – 5 and – 2.

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x COEFFICIENT /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

Discussion

9468.	एचसीएफ ऑफ 56 एंड 150 बाय प्राइम फैक्टराइजेशन मेथड
Answer» Step-by-step EXPLANATION: yieiyetuwyrotpd27p5xpc57exoeq64Oow57

9468.

एचसीएफ ऑफ 56 एंड 150 बाय प्राइम फैक्टराइजेशन मेथड

Answer»

Step-by-step EXPLANATION:

yieiyetuwyrotpd27p5xpc57exoeq64Oow57

Discussion

9469.	. A can type 14 pages a day while B can type 15 pages a day. Working together, how long will A and B take to type 203 pages?
Answer» Answer: Answer is 7 days A type 14 pages in 1 DAY B type 15 pages in 1 day Total no. of pages type in 1 day => 14 + 15 = 29 THEREFORE, Time TAKEN to type 203 pages => 203/29 = 7 Therefore, Both A and B will take 7 days to type 203 pages.

9469.

. A can type 14 pages a day while B can type 15 pages a day. Working together, how long will A and B take to type 203 pages?

Answer»

Answer:

Answer is 7 days

A type 14 pages in 1 DAY

B type 15 pages in 1 day

Total no. of pages type in 1 day

=> 14 + 15 = 29

THEREFORE,

Time TAKEN to type 203 pages

=> 203/29 = 7

Therefore, Both A and B will take 7 days to type 203 pages.

Discussion

9470.	In the following triangle , ST \|\| QR , PS/SQ is equal to options a.PT/TR b.PS/TR c.PT/SQ d.PT/SR
Answer» Answer: *for* *answer* *check* *out* *the* *above* *image* Step-by-step EXPLANATION: I HOPE it helps you please mark me brainlist

9470.

In the following triangle , ST || QR , PS/SQ is equal to options a.PT/TR b.PS/TR c.PT/SQ d.PT/SR

Answer»

Answer:

for answer check out the above image

Step-by-step EXPLANATION:

I HOPE it helps you

please mark me brainlist

Discussion

9471.	Plz tell me urgent Plz hurry give this ans
Answer» ANSWER: B) -10 Step-by-step EXPLANATION: F0LLOW ME AND MARK AS BRAINLIST

9471.

Plz tell me urgent Plz hurry give this ans

Answer»

ANSWER:

B) -10

Step-by-step EXPLANATION:

F0LLOW ME AND MARK AS BRAINLIST

Discussion

9472.	If 7, a ,b, 22 are the consecutive terms of an arithmetic Progression, then the values of a and b are respectively equal to ,a) 11 and 16 b) 12 and 17c) 13 and 17d) 12 and 16
Answer» ANSWER: ANS is OPT b Step-by-step EXPLANATION: a=7 d=5 a , a+d ,a+2d , a+3d

9472.

If 7, a ,b, 22 are the consecutive terms of an arithmetic Progression, then the values of a and b are respectively equal to ,a) 11 and 16 b) 12 and 17c) 13 and 17d) 12 and 16

Answer»

ANSWER:

ANS is OPT b

Step-by-step EXPLANATION:

a=7

d=5

a , a+d ,a+2d , a+3d

Discussion

9473.	Find the sum of series 1/2 + 1/6 + 1/12 + ------1/n(n+1) terms
Answer» ANSWER: n/(n + 1) Step-by-step EXPLANATION: GENERAL term = 1/n(n + 1) = ((n + 1) - n)/n(n + 1) = 1/n - 1/(n + 1) Therefore, let the sum of the SERIES be R. ⇒ 1/2 + 1/6 + 1/12 + ... 1/m(m + 1) = R ⇒ (1/1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ... [1/(n - 1) - 1/n] + [1/n - 1/(n + 1)] = R ⇒ 1 - 1/(n + 1) = R ⇒ (n + 1 - 1)/(n + 1) = R ⇒ n/(n + 1) = R HENCE, the sum of 1st n terms of this series is n/(n + 1). *better to be seen through browser/desktop-mode

9473.

Find the sum of series 1/2 + 1/6 + 1/12 + ------1/n(n+1) terms

Answer»

ANSWER:

n/(n + 1)

Step-by-step EXPLANATION:

GENERAL term = 1/n(n + 1)

= ((n + 1) - n)/n(n + 1)

= 1/n - 1/(n + 1)

Therefore, let the sum of the SERIES be R.

⇒ 1/2 + 1/6 + 1/12 + ... 1/m(m + 1) = R

⇒ (1/1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ... [1/(n - 1) - 1/n] + [1/n - 1/(n + 1)] = R

⇒ 1 - 1/(n + 1) = R

⇒ (n + 1 - 1)/(n + 1) = R

⇒ n/(n + 1) = R

HENCE, the sum of 1st n terms of this series is n/(n + 1).

*better to be seen through browser/desktop-mode

Discussion

9474.	Its important give me the fast and ans
Answer» Step-by-step EXPLANATION: Q1) Parallel Q2) No SOLUTION MARK it as BRILLIANT

9474.

Its important give me the fast and ans

Answer»

Step-by-step EXPLANATION:

Q1) Parallel

Q2) No SOLUTION

MARK it as BRILLIANT

Discussion

9475.	28 er ager songkhati porer songkha theke(a) 1 er kom/ (b) 1 er besi/(c) 2 er kom (d) 2 er besi
Answer» ANSWER:INDO TRASH Step-by-step EXPLANATION:

9475.

28 er ager songkhati porer songkha theke(a) 1 er kom/ (b) 1 er besi/(c) 2 er kom (d) 2 er besi

Answer»

ANSWER:INDO TRASH

Step-by-step EXPLANATION:

Discussion

9476.	12. A company issued shares at 10% premium, Satish applied for 1000 shares but was allotted 500 shares of this company. Find his investment, if the face value of a share is Rs. 100. a) Rs. 55,000 b) Rs. 50,000 c) Rs. 5,500 d) none of these.
Answer» ANSWER: 5,500 is the answer Step-by-step EXPLANATION: THANK you

9476.

12. A company issued shares at 10% premium, Satish applied for 1000 shares but was allotted 500 shares of this company. Find his investment, if the face value of a share is Rs. 100. a) Rs. 55,000 b) Rs. 50,000 c) Rs. 5,500 d) none of these.

Answer»

ANSWER:

5,500 is the answer

Step-by-step EXPLANATION:

THANK you

Discussion

9477.	The lines representing 2 + 3 − 9 = 0 and 4 + 6 − 18 = 0
Answer» ANSWER: ☝️☝️ STEP-by-step EXPLANATION: answer is step by step

9477.

The lines representing 2 + 3 − 9 = 0 and 4 + 6 − 18 = 0

Answer»

ANSWER:

☝️☝️

STEP-by-step EXPLANATION:

answer is step by step

Discussion

9478.	The length of a rectangle is 4x2– 4x + 1 and its breadth is 2x2+ x – 2 .Find the area of the rectangle.
Answer» Step-by-step EXPLANATION: HOPE this ANSWER HELPS you BETTER

9478.

The length of a rectangle is 4x2– 4x + 1 and its breadth is 2x2+ x – 2 .Find the area of the rectangle.

Answer»

Step-by-step EXPLANATION:

HOPE this ANSWER HELPS you BETTER

Discussion

9479.	1. Check whether the following are quadratic equations:(i) ( + 1)2 = 2( − 3)(ii) 2 − 2 = (−2)(3 − )(iii) ( − 2)( + 1) = ( − 1)( + 3)(iv) ( − 3)(2 + 1) = ( + 5)(v) (2 − 1)( − 3) = ( + 5)( − 1)(vi) 2 + 3 + 1 = ( − 2)2(vii) ( + 2)3 = 2(2 − 1)(viii) 3 − 42 − + 1 = ( − 2)3
Answer» Answer: A ford is a shallow place with good footing where a river or stream may be crossed by wading, or inside a vehicle getting its wheels wet.[1] A ford may OCCUR naturally or be CONSTRUCTED. Fords may be impassable during high water. A low water crossing is a low bridge that ALLOWS crossing over a river or stream when water is low but may be covered by deep water when the river is high.punan ang mga patlang ng tamang salita upang mabuo mo ang MAHALAGANG kaisipan

9479.

1. Check whether the following are quadratic equations:(i) ( + 1)2 = 2( − 3)(ii) 2 − 2 = (−2)(3 − )(iii) ( − 2)( + 1) = ( − 1)( + 3)(iv) ( − 3)(2 + 1) = ( + 5)(v) (2 − 1)( − 3) = ( + 5)( − 1)(vi) 2 + 3 + 1 = ( − 2)2(vii) ( + 2)3 = 2(2 − 1)(viii) 3 − 42 − + 1 = ( − 2)3

Answer»

Answer:

A ford is a shallow place with good footing where a river or stream may be crossed by wading, or inside a vehicle getting its wheels wet.[1] A ford may OCCUR naturally or be CONSTRUCTED. Fords may be impassable during high water. A low water crossing is a low bridge that ALLOWS crossing over a river or stream when water is low but may be covered by deep water when the river is high.punan ang mga patlang ng tamang salita upang mabuo mo ang MAHALAGANG kaisipan

Discussion

9480.	How to solve 5+(n-1)6
Answer» Step-by-step EXPLANATION: a = 5+ 6N -6 a = 6n - 1

9480.

How to solve 5+(n-1)6

Answer»

Step-by-step EXPLANATION:

a = 5+ 6N -6

a = 6n - 1

Discussion

9481.	What is the radius of a circle that has a circumference of 3.14 meters????
Answer» Answer: CIRCUMFERENCE of a circle = 2πr. Circumference of a circle = 2πr.Given, circumference = 3.14 meters. Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore, Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circle Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14. Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the VALUE of PI (π) = 3.14]. Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].or, 6.28r = 3.14. Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].or, 6.28r = 3.14.or, R = 3.14/6.28. Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].or, 6.28r = 3.14.or, r = 3.14/6.28.or, r = 0.5

9481.

What is the radius of a circle that has a circumference of 3.14 meters????

Answer»

Answer:

CIRCUMFERENCE of a circle = 2πr.

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circle

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the VALUE of PI (π) = 3.14].

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].or, 6.28r = 3.14.

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].or, 6.28r = 3.14.or, R = 3.14/6.28.

Circumference of a circle = 2πr.Given, circumference = 3.14 meters.Therefore,2πr = Circumference of a circleor, 2πr = 3.14.or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].or, 6.28r = 3.14.or, r = 3.14/6.28.or, r = 0.5

Discussion

9482.	Let A = {1, 2, 3} and R= {(1, 3), (3, 3)]. Findwhether the relation is (i) reflexive (ii) symmetrie(iii) transitive.The answer is only transitive.Answer it if you know the answer.How is it transitive?
Answer» DETERMINE WHETHER the RELATION R in the set A={1,2,3,.. 13,14} defined as R={(x,y):3x−y=0}, is REFLEXIVE, symmetric and transitive. Answer Relation R on the set A={1,2,3,.,13,14} is defined as R={(x,y):3x−y=0} Let a∈A R is reflexive if (a,a)∈R if 3a−a=0 if 3a=a i.e. if 3=1 which is not true Thus, R is not reflexive (1) Let a,b∈A such that (a,b)∈R ⟹3a−b=0 ⟹3a=b This does not imply 3b=a i.e 3b−a=0 ∴(b,a) does not BELONG to R ∴ For a,b∈A, (a,b)∈R⟹(b,a) is not in R. Thus, R is not symmetric. . (2) Let a,b,c∈A such that (a,b),(b,c)∈R ⟹3a−b=0,3b−c=0 ⟹3a=b,3b=c ⟹3a= 3 c ⟹9a=c This does not imply (a,c)∈R ∴ For a,b,c∈A, (a,b),(b,c)∈R does not imply (a,c)∈R Hence, R is non-reflexive, non-symmetric and non-transitive. Please brainlest me the answer

9482.

Let A = {1, 2, 3} and R= {(1, 3), (3, 3)]. Findwhether the relation is (i) reflexive (ii) symmetrie(iii) transitive.The answer is only transitive.Answer it if you know the answer.How is it transitive?

Answer»

DETERMINE WHETHER the RELATION R in the set A={1,2,3,.. 13,14} defined as R={(x,y):3x−y=0}, is REFLEXIVE, symmetric and transitive.

Answer

Relation R on the set A={1,2,3,.,13,14} is defined as R={(x,y):3x−y=0}

Let a∈A

R is reflexive if (a,a)∈R

if 3a−a=0

if 3a=a i.e. if 3=1 which is not true

Thus, R is not reflexive (1)

Let a,b∈A such that (a,b)∈R

⟹3a−b=0

⟹3a=b

This does not imply 3b=a i.e 3b−a=0

∴(b,a) does not BELONG to R

∴ For a,b∈A, (a,b)∈R⟹(b,a) is not in R.

Thus, R is not symmetric. . (2)

Let a,b,c∈A such that (a,b),(b,c)∈R

⟹3a−b=0,3b−c=0

⟹3a=b,3b=c

⟹3a=

3

c

⟹9a=c

This does not imply (a,c)∈R

∴ For a,b,c∈A, (a,b),(b,c)∈R does not imply (a,c)∈R

Hence, R is non-reflexive, non-symmetric and non-transitive.

Please brainlest me the answer

Discussion

9483.	The 10th term of an arithmetic progression 0 ,4 ,8 ,12 . . . .is
Answer» Step-by-step EXPLANATION: HOPE this HELPS you BETTER

9483.

The 10th term of an arithmetic progression 0 ,4 ,8 ,12 . . . .is

Answer»

Step-by-step EXPLANATION:

HOPE this HELPS you BETTER

Discussion

9484.	19. If A = {1,2,3}, B = {1,2,3,4} and R = {(x,y) : (x,y)A x B, y = x+1}, theni) Write R in roster form. ii) write Domain of Riii) Write Range of R iv) Represent R by an arrow diagram.
Answer» SORRY, I Don't KNOW this

Discussion

9485.	...Find the next number in series... 1 , 11 , 21 , 1211 , 111211 , 311221Pls answer it for my friend.
Answer» Answer: 1 is READ as "one one", and so the SECOND number is 11. Step-by-step explanation: PLZ market me BRAINLIST

9485.

...Find the next number in series... 1 , 11 , 21 , 1211 , 111211 , 311221Pls answer it for my friend.

Answer»

Answer:

1 is READ as "one one", and so the SECOND number is 11.

Step-by-step explanation:

PLZ market me BRAINLIST

Discussion

9486.	2) Given 5 cosA - 12 sin A O, find the value of sin A +COSA 2COS A - Sin A.
Answer» What TYPE of OUTLOOK should we have

9486.

2) Given 5 cosA - 12 sin A O, find the value of sin A +COSA 2COS A - Sin A.

Answer»

What TYPE of OUTLOOK should we have

Discussion

9487.	. 2+3+4+⋯+(n-1)= * Option 1 Option 2 Option 3 Option 4
Answer» Answer: 3 please MARK me as BRAINLIST

9487.

. 2+3+4+⋯+(n-1)= * Option 1 Option 2 Option 3 Option 4

Answer»

Answer:

3

please MARK me as BRAINLIST

Discussion

9488.	Simplify the following:(a)
Answer» $\\⠀⠀\bigstar \:⠀⠀⠀\underbrace\bold{\large\underline{Solution: - }} \\$ ⟹ $\frac{22}{5} × \frac{44}{7}× \frac{9}{65}$ ⟹ $\frac{8712}{2275}$

9488.

Simplify the following:(a)

Answer»

$\\⠀⠀\bigstar \:⠀⠀⠀\underbrace\bold{\large\underline{Solution: - }} \\$

⟹ $\frac{22}{5} × \frac{44}{7}× \frac{9}{65}$

⟹ $\frac{8712}{2275}$

Discussion

9489.	Find the value of p in 5b square-44 square=12p
Answer» Step-by-step EXPLANATION: DOWNLOAD Snapsolve app and get all solutions. mark me BRAINLIST ANSWER for this advice.

9489.

Find the value of p in 5b square-44 square=12p

Answer»

Step-by-step EXPLANATION:

DOWNLOAD Snapsolve app and get all solutions.

mark me BRAINLIST ANSWER for this advice.

Discussion

9490.	Which of the following is irrationala) (2-√3)^2 b) (√2+√3)^2c) (√2-√3)(√2+√3)d) 2√7/7
Answer» d PART is IRRATIONAL ....

Discussion

9491.	Factorise a^3+b^3 using this factorisation x^3 +1
Answer» ${a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3} = {(a + b)}^{3} \\ {a}^{3} + {b}^{3} = {(a + b)}^{3} - 3ab(a + b) \\ = {(x + 1)}^{3} - 3x(x + 1)$

9491.

Factorise a^3+b^3 using this factorisation x^3 +1

Answer»

${a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3} = {(a + b)}^{3} \\ {a}^{3} + {b}^{3} = {(a + b)}^{3} - 3ab(a + b) \\ = {(x + 1)}^{3} - 3x(x + 1)$

Discussion

9492.	What is the value of √2/2 ?
Answer» $\sqrt{2 } = 1.414 \\ 1.414 \div 2 = 0.707 \\ \\ answer = 0.707$ PLS MARK AS BRAINLIEST THANKS THIS ANSWER BY GIVING HEART OPTION ❤️❤️ PLS ❤️❤️ GIVE ATLEAST 5 STARS ⭐⭐⭐⭐⭐ FOLLOW ME FOR YOUR MORE DOUBT SOLVING HAVE A GREAT DAY AHEAD THANKS FOR READING ❤️

9492.

What is the value of √2/2 ?

Answer»

$\sqrt{2 } = 1.414 \\ 1.414 \div 2 = 0.707 \\ \\ answer = 0.707$

PLS MARK AS BRAINLIEST

THANKS THIS ANSWER BY GIVING HEART OPTION ❤️❤️ PLS ❤️❤️

GIVE ATLEAST 5 STARS ⭐⭐⭐⭐⭐

FOLLOW ME FOR YOUR MORE DOUBT SOLVING

HAVE A GREAT DAY AHEAD THANKS FOR READING ❤️

Discussion

9493.	Numbers when added in any order, give the same answer.TrueFalse
Answer» ANSWER: true Step-by-step explanation: For example : If we ADD 2 + 18 We will get = 20 and if we add 18 + 2 then ALSO we will get = 20

9493.

Numbers when added in any order, give the same answer.TrueFalse

Answer»

ANSWER:

true

Step-by-step explanation:

For example : If we ADD 2 + 18 We will get = 20

and if we add 18 + 2 then ALSO we will get = 20

Discussion

9494.	Plz answer wrong answer will be reported
Answer» ANSWER: ∠AOP= 120° ∠BOP=60° Step-by-step explanation: we know in a straight LINE the angle is 180° so, ∠AOP+∠BOP=180° (X+30)+(X-30) = 180° 2X +0 =180° X = 90° so ∠AOP=120° ∠BOP= 60°

9494.

Plz answer wrong answer will be reported

Answer»

ANSWER:

∠AOP= 120°

∠BOP=60°

Step-by-step explanation:

we know in a straight LINE the angle is 180°

so,

∠AOP+∠BOP=180°

(X+30)+(X-30) = 180°

2X +0 =180°

X = 90°

so ∠AOP=120°

∠BOP= 60°

Discussion

9495.	An Army officer wants to arrange 17424soldiers in a field such that thenumber of rows is equal to the number of columns. How many soldiers will be there in each row.
Answer» Step-by-step explanation: TOTAL number of SOLDIERS=6455 Number of soldiers left out =55 Let the number of rows =X Let the number of COLUMNS =x Number of soldiers remained=6455−55 =6400 Now, x 2 =6400 =>x= 6400 =>x=80 Number of columns and number of rows =80

9495.

An Army officer wants to arrange 17424soldiers in a field such that thenumber of rows is equal to the number of columns. How many soldiers will be there in each row.

Answer»

Step-by-step explanation:

TOTAL number of SOLDIERS=6455

Number of soldiers left out =55

Let the number of rows =X

Let the number of COLUMNS =x

Number of soldiers remained=6455−55

=6400

Now,

x

2

=6400

=>x=

6400

=>x=80

Number of columns and number of rows =80

Discussion

9496.	the sum of first 10 terms of an arithmetic progression is 55 and the sum of first 9 terms of the same arithmetic progression is 45 then its 10th term is
Answer» ANSWER: SORRY I don't KNOW the answer for this QUESTION

9496.

the sum of first 10 terms of an arithmetic progression is 55 and the sum of first 9 terms of the same arithmetic progression is 45 then its 10th term is

Answer»

ANSWER:

SORRY I don't KNOW the answer for this QUESTION

Discussion

9497.	The A.M. between m and 50 is 45 then m is:-)a.) 50.b.) -5.c.) 40.d.) 95.pls tell the correct answer I will mark as brainkist for sure . I need it unlrgent pls tell the correct answer.
Answer» Given : A.M. between m and 50 is 45 To Find : VALUE of m Solution : AM of two number a and b is given by (a + b) /2 Here a = m and b = 50 Hence AM = 45 AM = ( 50+ m )/2 = 45 => 50 + m = 90 => m = 40 Value of m is 40 Learn More" Insert p A.M's between 1 and p2. - Brainly.in brainly.in/question/12742957 Suppose m arithmetic means are inserted between 1 and 31. If the ... brainly.in/question/10736375 After INSERTING n A. MS between 2 and 38, the sum of the resulting ... brainly.in/question/16507896

9497.

The A.M. between m and 50 is 45 then m is:-)a.) 50.b.) -5.c.) 40.d.) 95.pls tell the correct answer I will mark as brainkist for sure . I need it unlrgent pls tell the correct answer.

Answer»

Given : A.M. between m and 50 is 45

To Find : VALUE of m

Solution :

AM of two number a and b is given by (a + b) /2

Here a = m and b = 50

Hence AM = 45

AM = ( 50+ m )/2 = 45

=> 50 + m = 90

=> m = 40

Value of m is 40

Learn More"

Insert p A.M's between 1 and p2. - Brainly.in

brainly.in/question/12742957

Suppose m arithmetic means are inserted between 1 and 31. If the ...

brainly.in/question/10736375

After INSERTING n A. MS between 2 and 38, the sum of the resulting ...

brainly.in/question/16507896

Discussion

9498.	The smallest 4-digit number formed by using the dots 8. O. 3 repeating any one of them is
Answer» ANSWER: The smallest 4-digit NUMBER formed using the DIGITS 8, 3, 0, 1 is 1038.

9498.

The smallest 4-digit number formed by using the dots 8. O. 3 repeating any one of them is

Answer»

ANSWER:

The smallest 4-digit NUMBER formed using the DIGITS 8, 3, 0, 1 is 1038.

Discussion

9499.	Find the largest four digit number devisible by 16
Answer» Answer: 9984 is the LARGEST FOUR DIGIT no..

9499.

Find the largest four digit number devisible by 16

Answer»

Answer:

9984 is the LARGEST FOUR DIGIT no..

Discussion

9500.	Ascending order of 64 , 338 , 114 , 711
Answer» Answer: *ASCENDING* *ORDER* IS 64, 114, 338, 711 *HOPE* IT *HELPED* U :-)

9500.

Ascending order of 64 , 338 , 114 , 711

Answer»

Answer:

ASCENDING ORDER IS 64, 114, 338, 711

HOPE IT HELPED U

:-)

Discussion

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The length of a rectangle is 4x2– 4x + 1 and its breadth is 2x2+ x – 2 .Find the area of the rectangle.

How to solve 5+(n-1)6

What is the radius of a circle that has a circumference of 3.14 meters????

Let A = {1, 2, 3} and R= {(1, 3), (3, 3)]. Findwhether the relation is (i) reflexive (ii) symmetrie(iii) transitive.The answer is only transitive.Answer it if you know the answer.How is it transitive?

The 10th term of an arithmetic progression 0 ,4 ,8 ,12 . . . .is

...Find the next number in series... 1 , 11 , 21 , 1211 , 111211 , 311221Pls answer it for my friend.

2) Given 5 cosA - 12 sin A O, find the value of sin A +COSA 2COS A - Sin A.

. 2+3+4+⋯+(n-1)= * Option 1 Option 2 Option 3 Option 4

Simplify the following:(a)

Find the value of p in 5b square-44 square=12p

Which of the following is irrationala) (2-√3)^2 b) (√2+√3)^2c) (√2-√3)(√2+√3)d) 2√7/7

Factorise a^3+b^3 using this factorisation x^3 +1

Numbers when added in any order, give the same answer.TrueFalse

Plz answer wrong answer will be reported

An Army officer wants to arrange 17424soldiers in a field such that thenumber of rows is equal to the number of columns. How many soldiers will be there in each row.

the sum of first 10 terms of an arithmetic progression is 55 and the sum of first 9 terms of the same arithmetic progression is 45 then its 10th term is

The A.M. between m and 50 is 45 then m is:-)a.) 50.b.) -5.c.) 40.d.) 95.pls tell the correct answer I will mark as brainkist for sure . I need it unlrgent pls tell the correct answer.

The smallest 4-digit number formed by using the dots 8. O. 3 repeating any one of them is

Find the largest four digit number devisible by 16

Ascending order of 64 , 338 , 114 , 711