332354 + Interview Questions in Secondary School in Math Page 209 InterviewSolution

10401.	Tan²20+tan²40+tan²80=I then the value of k is
Answer» ANSWER: there is no K in the QUESTION

10401.

Tan²20+tan²40+tan²80=I then the value of k is

Answer»

ANSWER:

there is no K in the QUESTION

Discussion

10402.	You are older today than yesterday?- Is it Certain, Uncertain or Impossible?
Answer» ANSWER: It is certain. Step-by-step EXPLANATION: *HOPE* it *HELPS!*

10402.

You are older today than yesterday?- Is it Certain, Uncertain or Impossible?

Answer»

ANSWER:

It is certain.

Step-by-step EXPLANATION:

HOPE it HELPS!

Discussion

10403.	A man invests rupees 5600 at 14% per annum ci for 2 years. calculate:(1)the interest for the first year.(2)the amount at the end of the first year.(3)the interest for the second year, correct to the nearest rupee
Answer» Answer: i hope this will help u plz mark this as brainliest Step-by-step explanation: For the first year: P= RS. 5,600, N=1 year and R=14% We have S.I. = 100 PNR = 100 5,600×1×14 = Rs. 784 And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384 Now, for the SECOND year : P= Rs. 6,384, N=1 year and R=14% We have S.I.= 100 PNR = 100 6,384×1×14 = Rs. 893.76 To the nearest rupee, it is Rs. 894.

10403.

A man invests rupees 5600 at 14% per annum ci for 2 years. calculate:(1)the interest for the first year.(2)the amount at the end of the first year.(3)the interest for the second year, correct to the nearest rupee

Answer»

Answer:

i hope this will help u

plz mark this as brainliest

Step-by-step explanation:

For the first year:

P= RS. 5,600, N=1 year and R=14%

We have S.I. =

100

PNR

=

100

5,600×1×14

= Rs. 784

And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384

Now, for the SECOND year :

P= Rs. 6,384, N=1 year and R=14%

We have S.I.=

100

PNR

=

100

6,384×1×14

= Rs. 893.76

To the nearest rupee, it is Rs. 894.

Discussion

10404.	Is it possible that the sum of any consecutive ten terms of the sequence is 500?Why?First term is 2Common difference is 4
Answer» Step-by-step EXPLANATION: a=2 d=4 n=10 s^10=500 s^10=n/2 [2a+(n-1)d] =10/2 [2(2)+9(4)] =5 (4+36) =5 (40) =200 s^10=200 which is not EQUAL to 500

10404.

Is it possible that the sum of any consecutive ten terms of the sequence is 500?Why?First term is 2Common difference is 4

Answer»

Step-by-step EXPLANATION:

a=2

d=4

n=10

s^10=500

s^10=n/2 [2a+(n-1)d]

=10/2 [2(2)+9(4)]

=5 (4+36)

=5 (40)

=200

s^10=200

which is not EQUAL to 500

Discussion

10405.	15.)15 - {st 27 = (2x 8-7}
Answer» Answer: 27 Step-by-step EXPLANATION: step-by-step explanation

10405.

15.)15 - {st 27 = (2x 8-7}

Answer»

Answer:

27

Step-by-step EXPLANATION:

step-by-step explanation

Discussion

10406.	What should be subtracted from_45 to get 10
Answer» ANSWER: $\huge\underbrace\mathfrak\red{answer}$ $\text{[math]}$ ░ ▒ ▓ █ HELLO █ ▓ ▒ ░ (i) 55-45=10 (II)(-35)-45=10

10406.

What should be subtracted from_45 to get 10

Answer»

ANSWER:

$\huge\underbrace\mathfrak\red{answer}$

$\text{[math]}$

░ ▒ ▓ █ HELLO █ ▓ ▒ ░

(i) 55-45=10

(II)(-35)-45=10

Discussion

10407.	15y^2+16y+4 Factories
Answer» ANSWER: HOPE it will BENEFIT you buddy... PLEASE follow me...

10407.

15y^2+16y+4 Factories

Answer»

ANSWER:

HOPE it will BENEFIT you buddy...

PLEASE follow me...

Discussion

10408.	What is the place value of 7 in 8375? a 700 ,70,700
Answer» ANSWER: the answer is TENS PLACE HOPE this HELPS you

10408.

What is the place value of 7 in 8375? a 700 ,70,700

Answer»

ANSWER:

the answer is TENS PLACE HOPE this HELPS you

Discussion

10409.	When the polynomial x3+4x2-11x-26 and 6x3+7x2+ax-8 are divided by X + 2 find the value of a
Answer» <P>ANSWER: p(x)=x 3+4 x 2-11 x-26 , 6 x 3 +17 x 2 + 9 x-8 q(X)=x + 2 R(x)= 4 Step-by-step explanation:

10409.

When the polynomial x3+4x2-11x-26 and 6x3+7x2+ax-8 are divided by X + 2 find the value of a

Answer»

<P>ANSWER:

p(x)=x 3+4 x 2-11 x-26 , 6 x 3 +17 x 2 + 9 x-8

q(X)=x + 2

R(x)= 4

Step-by-step explanation:

Discussion

10410.	Find the value of x, if x=2, y=1 is a solution of the equation 2x+3y=k
Answer» Answer: BRO question should be FING the value of K, ATQ, X=2, Y=1 Putting In 2x + 3y = k 2(2) + 3(1) = k 4+3 = k K = 7 MARK AS BRIANLIST IF POSSIBLE

10410.

Find the value of x, if x=2, y=1 is a solution of the equation 2x+3y=k

Answer»

Answer:

BRO question should be FING the value of K,

ATQ,

X=2, Y=1

Putting In

2x + 3y = k

2(2) + 3(1) = k

4+3 = k

K = 7

MARK AS BRIANLIST IF POSSIBLE

Discussion

10411.	Log 24=1.38, log 54=1.73 find log 36=?the correct and detailed answer gets brainliest
Answer» ANSWER: 1.57 is the RIGHT answer

10411.

Log 24=1.38, log 54=1.73 find log 36=?the correct and detailed answer gets brainliest

Answer»

ANSWER:

1.57 is the RIGHT answer

Discussion

10412.	Q. Prove that for any sets A,B and C.
Answer» I *THOUGHT* *this* *attachment* can HELP you**

10412.

Q. Prove that for any sets A,B and C.

Answer»

I THOUGHT this attachment can HELP you

Discussion

10413.	Solve b and c questionplzz answer to the question fast
Answer» ANSWER: Here....MARK me as brainliesst Step-by-step EXPLANATION:

10413.

Solve b and c questionplzz answer to the question fast

Answer»

ANSWER:

Here....MARK me as brainliesst

Step-by-step EXPLANATION:

Discussion

10414.	100%2 what is the percentage of thi s
Answer» ANSWER: $\huge\underbrace\mathfrak\red{answer}$ $\text{[math]}$ ░▒▓█ HELLO █▓▒░ 100% Of 2 = 100*2/100 =2

10414.

100%2 what is the percentage of thi s

Answer»

ANSWER:

$\huge\underbrace\mathfrak\red{answer}$

$\text{[math]}$

░▒▓█ HELLO █▓▒░

100% Of 2

= 100*2/100

=2

Discussion

10415.	Find the sum on a number line.(a) 8+ (-3)
Answer» Answer: 5 Step-by-step EXPLANATION: STAY HOME stay SAFE ________________

10415.

Find the sum on a number line.(a) 8+ (-3)

Answer»

Answer:

5

Step-by-step EXPLANATION:

STAY HOME stay SAFE

________________

Discussion

10416.	find the sum invested for 1.5 years compounded half yearly at the rate of 8% per annum that will amount to rs 17576u
Answer» Answer: I have not learnt this much like FULLY for an AMOUNT what is this all SORRY for this question

10416.

find the sum invested for 1.5 years compounded half yearly at the rate of 8% per annum that will amount to rs 17576u

Answer»

Answer:

I have not learnt this much like FULLY for an AMOUNT what is this all SORRY for this question

Discussion

10417.	Knapsack Dinemic programming example where W=30 & n=4
Answer» ANSWER: N= 4 Step-by-step EXPLANATION: this is my GUESS only

10417.

Knapsack Dinemic programming example where W=30 & n=4

Answer»

ANSWER:

N= 4

Step-by-step EXPLANATION:

this is my GUESS only

Discussion

10418.	4m^2 +7m-2 factories
Answer» 4m^2 +8m-1m-2 4m( m+2) - 1(m+2) (m+2)(4m-1)

10418.

4m^2 +7m-2 factories

Answer»

4m^2 +8m-1m-2

4m( m+2) - 1(m+2)

(m+2)(4m-1)

Discussion

10419.	297801 should be divisible by 24. find the number to be added to make it divisible
Answer» Answer: 297801÷24 =12408.375

10419.

297801 should be divisible by 24. find the number to be added to make it divisible

Answer»

Answer:

297801÷24

=12408.375

Discussion

10420.	The volume of a cube is 2197cm cube. find the length of the edge of the cube.
Answer» Answer: 13 cm Step-by-step explanation: 2197=LENGTH^3 then length =CUBE ROOT of 2197 =13

10420.

The volume of a cube is 2197cm cube. find the length of the edge of the cube.

Answer»

Answer:

13 cm

Step-by-step explanation:

2197=LENGTH^3

then length =CUBE ROOT of 2197 =13

Discussion

10421.	A bowler throws a cricket ball at a speed of 36km/hr. How long does this balltake to travel a distance of 20 metres to reach the batsman?each of them
Answer» Question :– A bowler throws a cricket ball at a SPEED of 36km/hr. How long does this ball take to travel a distance of 20 METRES to reach the batsman? Given :– A bowler throws a cricket ball at a speed of 36km/hr. To Find :– How long does this ball take to travel a distance of 20 metres to reach the batsman? SOLUTION :– First, change km into m. → $36 \times \frac{ \cancel{10} \cancel{00}}{ \cancel{36} \cancel{00}}$ → $\cancel{36} \times \frac{5}{ \cancel{18} }$ → $2 \times 5$ → $10 \: m/s$ Now, Time taken to travel 20m in the speed of 10m/s. → $\frac{ \cancel{20}}{ \cancel{10} }$ → $\boxed{\tt\orange{2 \: sec}}$

10421.

A bowler throws a cricket ball at a speed of 36km/hr. How long does this balltake to travel a distance of 20 metres to reach the batsman?each of them

Answer»

Question :–

A bowler throws a cricket ball at a SPEED of 36km/hr. How long does this ball take to travel a distance of 20 METRES to reach the batsman?

Given :–

A bowler throws a cricket ball at a speed of 36km/hr.

To Find :–

How long does this ball
take to travel a distance of 20 metres to reach the batsman?

SOLUTION :–

First, change km into m.

→ $36 \times \frac{ \cancel{10} \cancel{00}}{ \cancel{36} \cancel{00}}$

→ $\cancel{36} \times \frac{5}{ \cancel{18} }$

→ $2 \times 5$

→ $10 \: m/s$

Now,

Time taken to travel 20m in the speed of 10m/s.

→ $\frac{ \cancel{20}}{ \cancel{10} }$

→ $\boxed{\tt\orange{2 \: sec}}$

Discussion

10422.	कैलकुलेट द फोर्स ऑफ ग्रेविटेशनल बिटवीन द अर्थ एंड सन मास ऑफ अर्थ इज 6 * 10 की पावर 4 केजी मास ऑप्शन इज 2 एंड 2 एंड पावर are is equal to 1.1.5 into 10 to the power 5
Answer» 5 is RIGHT $05 { {x {y.. \|\| \times \frac{?}{?} }^{?} }^{?} }^{?} \times \frac{?}{?} \times \frac{?}{?}$

Discussion

10423.	If a = - 8 , b = - 7 & c = 6 ; verify that ( a + b )+ c = a +( b + c )
Answer» [(-8) + (-7)] + 6 = (-15) + 6 = (-9) (-8) + [(-7) + 6] = (-8) + (-1) = (-9)

Discussion

10424.	2+23√453+456π12+345/4+453-12=~123×453+700865+456321×{-(-56×45)+(-76×41) 8765-231+890(-678)√345+√324(456÷45)^1/6 1290+1460√34+π346√67+34=??Give me fast they will mark as Brainliest
Answer» Step-by-step explanation: 468.✔........... BRO

10424.

2+23√453+456π12+345/4+453-12=~123×453+700865+456321×{-(-56×45)+(-76×41) 8765-231+890(-678)√345+√324(456÷45)^1/6 1290+1460√34+π346√67+34=??Give me fast they will mark as Brainliest

Answer»

Step-by-step explanation:

468.✔........... BRO

Discussion

10425.	Find the value of (-4)^-2
Answer» ANSWER: $\huge\underbrace\mathfrak\red{answer}$ $\text{[math]}$ ░▒▓█ HELLO █▓▒░ 16

10425.

Find the value of (-4)^-2

Answer»

ANSWER:

$\huge\underbrace\mathfrak\red{answer}$

$\text{[math]}$

░▒▓█ HELLO █▓▒░

16

Discussion

10426.	In the given figure, the line segmentis the mid point of AS. show that AOB is congruent to SORo is mid point of BR
Answer» ANSWER: in the given figure, angles AOB and SOR are VERTICALLY OPPOSITE angles opposite angles are congruent there fore AOB is congruent to SOR

10426.

In the given figure, the line segmentis the mid point of AS. show that AOB is congruent to SORo is mid point of BR

Answer»

ANSWER:

in the given figure,

angles AOB and SOR are VERTICALLY OPPOSITE angles

opposite angles are congruent

there fore AOB is congruent to SOR

Discussion

10427.	1. An iron pillar consists of a cylindrical portion of 2.8 m height and 20 cm in diameter anda cone of 42 cm height surmounting it. Find the weight of the pillar if 1 cm'ofiron weighs7.5 g.
Answer» Given :- ★ Diameter of cylinder = 20 cm ★ HEIGHT of cylinder = 2.8 m ★ Height of cone = 42 cm To Find :- ★ Weight of pillar Solution :- Here, Height of cylinder = 2.8 m = 280 cm We KNOW, _______________ 1 m = 100 cm _______________ Radius of cylinder = 20/2 cm =10 cm We know, ✏ Volume of pillar = πr²( h + 1/3 H) Substituting the values, we get ___ Volume of pillar = 2200/7 × ( 280 +14) = 92400 cm cube Hence, the weight of pillar ___ = (92400 × 7.5) /1000 = 693 kg So, the weight of pillar is 693 kg. $\bold\blue{@ItzSilentColleen}$

10427.

1. An iron pillar consists of a cylindrical portion of 2.8 m height and 20 cm in diameter anda cone of 42 cm height surmounting it. Find the weight of the pillar if 1 cm'ofiron weighs7.5 g.

Answer»

Given :-

★ Diameter of cylinder = 20 cm

★ HEIGHT of cylinder = 2.8 m

★ Height of cone = 42 cm

To Find :-

★ Weight of pillar

Solution :-

Here,

Height of cylinder

= 2.8 m

= 280 cm

We KNOW,

_______________

1 m = 100 cm

_______________

Radius of cylinder

= 20/2 cm

=10 cm

We know,

✏ Volume of pillar = πr²( h + 1/3 H)

Substituting the values, we get ___

Volume of pillar

= 2200/7 × ( 280 +14)

= 92400 cm cube

Hence,

the weight of pillar ___

= (92400 × 7.5) /1000

= 693 kg

So, the weight of pillar is 693 kg.

$\bold\blue{@ItzSilentColleen}$

Discussion

10428.	29. (a + b) (Va+b) = ?
Answer» Step-by-step EXPLANATION: = a + B + VA + b = a + B2 + va . If you like this please follow me.

10428.

29. (a + b) (Va+b) = ?

Answer»

Step-by-step EXPLANATION:

= a + B + VA + b

= a + B2 + va .

If you like this please follow me.

Discussion

10429.	Replace the * by the smallest digit to make it divisible by 3 : 281
Answer» Step-by-step EXPLANATION: First Star WOULD be replace by 1 and SECOND star wouId be replace by O (Zero) so the number will DIVISIBLE by 3 Hope it helps!!!

10429.

Replace the * by the smallest digit to make it divisible by 3 : 281

Answer»

Step-by-step EXPLANATION:

First Star WOULD be replace by 1 and SECOND star wouId be replace by O (Zero) so the number will DIVISIBLE by 3

Hope it helps!!!

Discussion

10430.	Cost price of a TV set is 10,500 rupees. the rate of GST is 10%. Calculate the total amount for purchasing
Answer» the GST COSTED on this tv SET is: 10500/100=105 rs105 is 1 pecent costed gst on tv set the gst costed on this tv set is rs: 105*10=1050

10430.

Cost price of a TV set is 10,500 rupees. the rate of GST is 10%. Calculate the total amount for purchasing

Answer»

the GST COSTED on this tv SET is:

10500/100=105

rs105 is 1 pecent costed gst on tv set

the gst costed on this tv set is rs:

105*10=1050

Discussion

10431.	The average age of a class of 20 students is 28. When the teacher joins the class, the average age is increased by 2. Find the age of the teacher ?
Answer» Answer: Average AGE of the teacher = 70 YEARS Step-by-step explanation: Average of 20 STUDENTS = 28 years TOTAL age of 20 students = 20 × 28 = 560 years When teacher included average become 30 years Now, total age 20 students and teacher = 30 × 21 = 630 years ∴ Age of teacher = 630 - 560 = 70 years

10431.

The average age of a class of 20 students is 28. When the teacher joins the class, the average age is increased by 2. Find the age of the teacher ?

Answer»

Answer:

Average AGE of the teacher = 70 YEARS

Step-by-step explanation:

Average of 20 STUDENTS = 28 years

TOTAL age of 20 students

= 20 × 28

= 560 years

When teacher included average become 30 years

Now, total age 20 students and teacher

= 30 × 21 = 630 years

∴ Age of teacher

= 630 - 560

= 70 years

Discussion

10432.	Find the Zeros of. t2 – 225
Answer» Answer:15 and 0 Step-by-step EXPLANATION:

10432.

Find the Zeros of. t2 – 225

Answer»

Answer:15 and 0

Step-by-step EXPLANATION:

Discussion

10433.	How many times digit 5 appears between 1 to 257
Answer» ANSWER: SOO EASY FIND it yourself

10433.

How many times digit 5 appears between 1 to 257

Answer»

ANSWER:

SOO EASY

FIND it yourself

Discussion

10434.	Find the roots of quadratic equation 3x2 - 2 x + 2 = 0
Answer» Answer: the quadratic EQUATION is not greater than or EQUAL to discriminant, therefore it contains conjugate roots. this is the FORMULA for discriminant. $d \: = {b}^{2} - 4ac$ $\sqrt{ - 1} = i$

10434.

Find the roots of quadratic equation 3x2 - 2 x + 2 = 0

Answer»

Answer:

the quadratic EQUATION is not greater than or EQUAL to discriminant, therefore it contains conjugate roots.

this is the FORMULA for discriminant.

$d \: = {b}^{2} - 4ac$

$\sqrt{ - 1} = i$

Discussion

10435.	2.The marked price of a water cooler is 5,400. The shopkeeper offers an off seasondiscount of 20% on it. Find its selling price.
Answer» Answer: 5400×(20/100) =1080 5400 - 1080 = 4230 Selling price=4230

10435.

2.The marked price of a water cooler is 5,400. The shopkeeper offers an off seasondiscount of 20% on it. Find its selling price.

Answer»

Answer:

5400×(20/100) =1080

5400 - 1080 = 4230

Selling price=4230

Discussion

10436.	Factorizarion of 2/x-9=1/x-3-1/x-4
Answer» Answer: Step-by-step explanation: REARRANGE the equation by subtracting what is to the right of the equal SIGN from both sides of the equation : 2/x-9-(1/x-3-1/x-4)=0 Step by step solution : STEP 1 : 1 SIMPLIFY — x Equation at the end of step 1 : 2 1 1 (—-9)-(((—-3)-—)-4) = 0 x x x STEP 2 : 1 Simplify — x Equation at the end of step 2 : 2 1 1 (—-9)-(((—-3)-—)-4) = 0 x x x STEP 3 : Rewriting the whole as an Equivalent Fraction 3.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using x as the DENOMINATOR : 3 3 • x 3 = — = ————— 1 x Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator Adding fractions that have a common denominator : 3.2 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominator Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: 1 - (3 • x) 1 - 3x ——————————— = —————— x x Equation at the end of step 3 : 2 (1 - 3x) 1 (— - 9) - ((———————— - —) - 4) = 0 x x x STEP 4 : Adding fractions which have a common denominator 4.1 Adding fractions which have a common denominator Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: (1-3x) - (1) -3x ———————————— = ——— x x Equation at the end of step 4 : 2 -3x (— - 9) - (——— - 4) = 0 x x STEP 5 : Rewriting the whole as an Equivalent Fraction 5.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using x as the denominator : 4 4 • x 4 = — = ————— 1 x Canceling Out : 5.2 Canceling out x as it appears on both sides of the fraction line Adding fractions that have a common denominator : 5.3 Adding up the two equivalent fractions -3 - (4) -7 ———————— = —— 1 1 Equation at the end of step 5 : 2 -7 (— - 9) - —— = 0 x 1 STEP 6 : 2 Simplify — x Equation at the end of step 6 : 2 -7 (— - 9) - —— = 0 x 1 Rewrite the whole as a fraction using x as the denominator : 9 9 • x 9 = — = ————— 1 x 2 - (9 • x) 2 - 9x ——————————— = —————— x x (2 - 9x) -7 ———————— - —— = 0 x 1 Rewrite the whole as a fraction using x as the denominator : -7 -7 • x -7 = —— = —————— 1 x (2-9x) - (-7 • x) 2 - 2x ————————————————— = —————— x x 2 - 2x = -2 • (x - 1) -2 • (x - 1) ———————————— = 0 x When a fraction equals ZERO ... Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero. Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator. Here's how: -2•(x-1) ———————— • x = 0 • x x Now, on the left hand side, the x cancels out the denominator, while, on the right hand side, zero times anything is still zero. The equation now takes the shape : -2 • (x-1) = 0 10.2 Solve : -2 = 0 This equation has no solution. A a non-zero constant never equals zero. 10.3 Solve : x-1 = 0 Add 1 to both sides of the equation : x = 1 One solution was found : x = 1

10436.

Factorizarion of 2/x-9=1/x-3-1/x-4

Answer»

Answer:

Step-by-step explanation:

REARRANGE the equation by subtracting what is to the right of the equal SIGN from both sides of the equation :

2/x-9-(1/x-3-1/x-4)=0

Step by step solution :

STEP

1

:

1

SIMPLIFY —

x

Equation at the end of step

1

:

2 1 1

(—-9)-(((—-3)-—)-4) = 0

x x x

STEP

2

:

1

Simplify —

x

Equation at the end of step

2

:

2 1 1

(—-9)-(((—-3)-—)-4) = 0

x x x

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using x as the DENOMINATOR :

3 3 • x

3 = — = —————

1 x

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1 - (3 • x) 1 - 3x

——————————— = ——————

x x

Equation at the end of step

3

:

2 (1 - 3x) 1

(— - 9) - ((———————— - —) - 4) = 0

x x x

STEP

4

:

Adding fractions which have a common denominator

4.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(1-3x) - (1) -3x

———————————— = ———

x x

Equation at the end of step

4

:

2 -3x

(— - 9) - (——— - 4) = 0

x x

STEP

5

:

Rewriting the whole as an Equivalent Fraction

5.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using x as the denominator :

4 4 • x

4 = — = —————

1 x

Canceling Out :

5.2 Canceling out x as it appears on both sides of the fraction line

Adding fractions that have a common denominator :

5.3 Adding up the two equivalent fractions

-3 - (4) -7

———————— = ——

1 1

Equation at the end of step

5

:

2 -7

(— - 9) - —— = 0

x 1

STEP

6

:

2

Simplify —

x

Equation at the end of step

6

:

2 -7

(— - 9) - —— = 0

x 1

Rewrite the whole as a fraction using x as the denominator :

9 9 • x

9 = — = —————

1 x

2 - (9 • x) 2 - 9x

——————————— = ——————

x x

(2 - 9x) -7

———————— - —— = 0

x 1

Rewrite the whole as a fraction using x as the denominator :

-7 -7 • x

-7 = —— = ——————

1 x

(2-9x) - (-7 • x) 2 - 2x

————————————————— = ——————

x x

2 - 2x = -2 • (x - 1)

-2 • (x - 1)

———————————— = 0

x

When a fraction equals ZERO ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

-2•(x-1)

———————— • x = 0 • x

x

Now, on the left hand side, the x cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

-2 • (x-1) = 0

10.2 Solve : -2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

10.3 Solve : x-1 = 0

Add 1 to both sides of the equation :

x = 1

One solution was found :

x = 1

Discussion

10437.	AB = 6 cm BC = 4.5 cm RQ = 3 cm then find RP and QP
Answer» Ans Step-bn Δ ABC, AB = 6√3 CM, AC = 12 cm, BC = 6 cm. Find measure of ∠C.y-step explanation: n ΔAB = 6 cm BC = 4.5 cm RQ = 3 cm then find RP and QP ABC, AB = 6√3 cm, AAB = 6 cm BC = 4.5 cm RQ = 3 cm then find RP and QPC = 12 cm, BC = 6 cm. Find measure of ∠C.

10437.

AB = 6 cm BC = 4.5 cm RQ = 3 cm then find RP and QP

Answer»

Ans

Step-bn Δ ABC, AB = 6√3 CM, AC = 12 cm, BC = 6 cm. Find measure of ∠C.y-step explanation:

n ΔAB = 6 cm BC = 4.5 cm RQ = 3 cm then find RP and QP ABC, AB = 6√3 cm, AAB = 6 cm BC = 4.5 cm RQ = 3 cm then find RP and QPC = 12 cm, BC = 6 cm. Find measure of ∠C.

Discussion

10438.	The sum of the digit of the two digit number is 9. when the digits are reversed the difference of the number is?
Answer» Answer: Let the TEN’s DIGIT be x and the unit’s digit be y. So the NUMBER formed is 10x+y Given x+y=9 Reversed number=10y+x Given, 10y+x=9+10x+y 9y=9+9x y=1+x Putting this in EQUATION 1, we get x+1+x=9 2x=8 x=4 y=9–4=5 So the number is 45

10438.

The sum of the digit of the two digit number is 9. when the digits are reversed the difference of the number is?

Answer»

Answer:

Let the TEN’s DIGIT be x and the unit’s digit be y.

So the NUMBER formed is 10x+y

Given x+y=9

Reversed number=10y+x

Given, 10y+x=9+10x+y

9y=9+9x

y=1+x

Putting this in EQUATION 1, we get

x+1+x=9

2x=8

x=4

y=9–4=5

So the number is 45

Discussion

10439.	If n (U)=30,n (A)=20 and n (B)=15 find the value of A intersection B
Answer» ANSWER: u=3345=5 Step-by-step EXPLANATION: o-9=0

10439.

If n (U)=30,n (A)=20 and n (B)=15 find the value of A intersection B

Answer»

ANSWER:

u=3345=5

Step-by-step EXPLANATION:

o-9=0

Discussion

10440.	3(5y-7)-2(9y-11)=(8y-13)-17
Answer» ANSWER: Answer is in ATTACHEMENT

10440.

3(5y-7)-2(9y-11)=(8y-13)-17

Answer»

ANSWER:

Answer is in ATTACHEMENT

Discussion

10441.	If tan A = √2 - 1 then find tan A / (1 + tan ²A)
Answer» ANSWER: TANA/(1+tan²A) (√2-1)/(1+(√2-1)² (√2-1)/(1+(2+1-2√2) √2-1/1+3-2√2 √2-1/4-2√2 √2-1/2(2-√2) √2-1/2(√2(√2-1)) √2-1/2√2(√2-1) after cancelling 1/2√2 hope I HELPED you plz MARK as brainliest and also follow me

10441.

If tan A = √2 - 1 then find tan A / (1 + tan ²A)

Answer»

ANSWER:

TANA/(1+tan²A)

(√2-1)/(1+(√2-1)²

(√2-1)/(1+(2+1-2√2)

√2-1/1+3-2√2

√2-1/4-2√2

√2-1/2(2-√2)

√2-1/2(√2(√2-1))

√2-1/2√2(√2-1)

after cancelling

1/2√2

hope I HELPED you

plz MARK as brainliest and also follow me

Discussion

10442.	A + B means A is neither less than nor equal to B.A-B means A is neither smaller nor greater than B.A/B means A is neither greater than nor equal to B.Statement:E/F, F + G, G - HConclusions:1. E + HII. F+H(1) follows11
Answer» Answer: only II can be CONCLUDED. Step-by-step explanation: The QUESTION can be rewritten as EG=H so, it can be concluded that F is greater than H Thus, F+H is the REQUIRED CONCLUSION.

10442.

A + B means A is neither less than nor equal to B.A-B means A is neither smaller nor greater than B.A/B means A is neither greater than nor equal to B.Statement:E/F, F + G, G - HConclusions:1. E + HII. F+H(1) follows11

Answer»

Answer:

only II can be CONCLUDED.

Step-by-step explanation:

The QUESTION can be rewritten as

EG=H

so,

it can be concluded that F is greater than H

Thus, F+H is the REQUIRED CONCLUSION.

Discussion

10443.	Show that x-1 is a factor of X to the power of n-1
Answer» Answer: x-1=0 then : x=0+1 x=1 there FORE 1^ n-1=0 Step-by-step explanation: i hope it HELPS you,please mark it as BRAINLIEST also FOLLOW me....... ..

10443.

Show that x-1 is a factor of X to the power of n-1

Answer»

Answer:

x-1=0

then :

x=0+1

x=1

there FORE 1^ n-1=0

Step-by-step explanation:

i hope it HELPS you,please mark it as BRAINLIEST also FOLLOW me....... ..

Discussion

10444.	9a^2 + 25b^2 + c^2-30ab+10bc-6ca is the expansion of the square of ____________ expression
Answer» ANSWER: (-3a+5b+c)^2 is the answer.. Step-by-step EXPLANATION: It is the FORMULA [a+b+c]^2..

10444.

9a^2 + 25b^2 + c^2-30ab+10bc-6ca is the expansion of the square of ____________ expression

Answer»

ANSWER:

(-3a+5b+c)^2 is the answer..

Step-by-step EXPLANATION:

It is the FORMULA [a+b+c]^2..

Discussion

10445.	10÷X+y+2÷x-y=4 find the value of the X and y
Answer» Answer: 10=x,y Step-by-step EXPLANATION: i THINK FOE explantion wait a second

10445.

10÷X+y+2÷x-y=4 find the value of the X and y

Answer»

Answer:

10=x,y

Step-by-step EXPLANATION:

i THINK FOE explantion wait a second

Discussion

10446.	Which has more area, a square of side 23/2 m or 25/2m and by how much?
Answer» Step-by-step explanation: SQUARE of side 25/2 m has more AREA because we can clearly see that the denominators are same , so no NEED of denominators. See only NUMERATOR and find the difference. Here, the difference is of 1

10446.

Which has more area, a square of side 23/2 m or 25/2m and by how much?

Answer»

Step-by-step explanation:

SQUARE of side 25/2 m has more AREA because we can clearly see that the denominators are same , so no NEED of denominators.

See only NUMERATOR and find the difference.

Here, the difference is of 1

Discussion

10447.	Answers for this question
Answer» ANSWER: WICH QUESTIONS answer do you WANT

10447.

Answers for this question

Answer»

ANSWER:

WICH QUESTIONS answer do you WANT

Discussion

10448.	A said to B “ Give me a hundred mangoes and I shall have twice as many mangoes asyou”. B said to A , “ Give me ten mangoes and I shall have six times as many mangoes as you”.How many mangoes do A and B together have?
Answer» ANSWER: a and B 100 MANGOES give me mangoes sixtimes 40

10448.

A said to B “ Give me a hundred mangoes and I shall have twice as many mangoes asyou”. B said to A , “ Give me ten mangoes and I shall have six times as many mangoes as you”.How many mangoes do A and B together have?

Answer»

ANSWER:

a and B 100 MANGOES

give me mangoes sixtimes 40

Discussion

10449.	Plesa Krupaucis pooblem =n =4. W = 301924oWeight-wi1015Value - Vi2581
Answer» Answer: All Questions are compulsary and each EANRY two marks Q.1- Absolite value of 33 S -31 a. 31 b. -37 31 C. 37 d. 37 0.2- lis - sold fill in the 13 a. [>] b.[<] c. [=] 0.3- Additive INVERSE of 9 13" 9 a. b. O -13 C. 9 d. none 13 13 17 0.4- + 24 18 -16 -135 a. 144 -140 b. 144 -145 C. 144 d. none o Q.5- Rational NUMBER should be substracted from -3 to 22 5 a. 60 c. 113 d. none b.com Q.6- The Cost of 12 balls is Rs. 205. Then cost of one bal . 172 Q.7-On Simplify (62-4²)X+ is. 1+ c. b. 172 c. 17 20 d. none 21 a. 1 10 b. d. none 4 Step-by-step explanation: All Questions are compulsary and each eanry two marks Q.1- Absolite value of 33 S -31 a. 31 b. -37 31 C. 37 d. 37 0.2- lis - sold fill in the 13 a. [>] b.[<] c. [=] 0.3- Additive inverse of 9 13" 9 a. b. O -13 C. 9 d. none 13 13 17 0.4- + 24 18 -16 -135 a. 144 -140 b. 144 -145 C. 144 d. none o Q.5- Rational number should be substracted from -3 to 22 5 a. 60 c. 113 d. none b.com Q.6- The Cost of 12 balls is Rs. 205. Then cost of one bal . 172 Q.7-On Simplify (62-4²)x+ is. 1+ c. b. 172 c. 17 20 d. none 21 a. 1 10 b. d. none 4j

10449.

Plesa Krupaucis pooblem =n =4. W = 301924oWeight-wi1015Value - Vi2581

Answer»

Answer:

All Questions are compulsary and each EANRY two marks

Q.1- Absolite value of 33 S

-31

a.

31

b.

-37

31

C.

37

d.

37

0.2-

lis - sold fill in the

13

a. [>]

b.[<]

c. [=]

0.3- Additive INVERSE of 9

13"

9

a.

b. O

-13

C.

9

d. none

13

17

0.4-

+

24

18

-16

-135

a.

144

-140

b.

144

-145

C.

144

d. none o

Q.5- Rational NUMBER should be substracted from

-3

to

22

5

a.

60

c. 113

d. none

b.com

Q.6- The Cost of 12 balls is Rs. 205. Then cost of one bal

. 172

Q.7-On Simplify (62-4²)X+ is.

1+

c.

b. 172

c. 17

20

d. none

21

a. 1

10

b.

d. none

4

Step-by-step explanation:

All Questions are compulsary and each eanry two marks

Q.1- Absolite value of 33 S

-31

a.

31

b.

-37

31

C.

37

d.

37

0.2-

lis - sold fill in the

13

a. [>]

b.[<]

c. [=]

0.3- Additive inverse of 9

13"

9

a.

b. O

-13

C.

9

d. none

13

17

0.4-

+

24

18

-16

-135

a.

144

-140

b.

144

-145

C.

144

d. none o

Q.5- Rational number should be substracted from

-3

to

22

5

a.

60

c. 113

d. none

b.com

Q.6- The Cost of 12 balls is Rs. 205. Then cost of one bal

. 172

Q.7-On Simplify (62-4²)x+ is.

1+

c.

b. 172

c. 17

20

d. none

21

a. 1

10

b.

d. none

4j

Discussion

10450.	What is the value of sin 7x??
Answer» Answer: SIN 7x = 7(sin x) - 56(sin x)^3 + 112(sin x)^5 - (sin x)^7 HOPE IT HELPS, PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.

10450.

What is the value of sin 7x??

Answer»

Answer:

SIN 7x = 7(sin x) - 56(sin x)^3 + 112(sin x)^5 - (sin x)^7

HOPE IT HELPS,

PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.

Discussion

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