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Answer:

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

HENCE, Ratio of Area of ∆ABC to ∆PQR

hope it helps

ANSWER:

I DONT know

Step-by-step EXPLANATION:

Answer:

18,24,96

lcm=2×9×4×38

hope this helps u

A plane is a perfectly flat surface EXTENDING in all DIRECTIONS.. In geometry, a plane is MADE up of an infinite NUMBER of LINES

Step-by-step explanation:

this is your answer

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ANSWER:

Step-by-step EXPLANATION:

Answer:

1250 ×(8/100)=100

1250 - 100=1150

Selling PRICE = 1150

Discount = 100

COMPOUND INTEREST = RS. 840

simple interest = Rs. 800

difference = Rs. 40

ANSWER:

LHS=RHS

Step-by-step explanation:

5y-4/6+3y+10/9=4Y+1

5y-4y+3y=1+4/6-10/9 (LCM=18)

4y=(18+12-20)/18

4y=10/18

4y=5/9

y=5/9÷4

y=5/9×1/4

y=5/36

LHS

5y-4/6+3y+10/9

(5×5/36)-4/6+(3×5/36)+10/9

25/36-4/6+5/12+10/9 (LCM=36)

(25-24+15+40)/36

56/36

=14/9

RHS

4y+1

(4×5/36)+1

5/9+1 (LCM=9)

(5+9)/9

=14/9

LHS=RHS

Hence proved

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Step-by-step EXPLANATION:

if x=7,y=5 PUT value in equation

3(7)+a(5)=31

=21+5a=31

=5a=31-21

=5a=10

=a =2

Answer:

x^2+3xy+y^2=5. at (1,1)2x+3y+3xdy/dx+2ydy/dx=0dy/dx(3x+2y)=-(2x+3y)dy/dx=-(2x+3y)÷(3x+2y)dy/dx(1,1)=-(2+3)÷(3+2)dy/dx=-1eq of the tangent(x-1)=-1(y-1)(x-1)=-y

Step-by-step explanation:

MAY this ANSWER will HELP you PLZ MARK has BRAINLIEST

ANSWER:

INFINITE SOLUTION.......

Answer:

0.267

Step-by-step EXPLANATION:

=2/5×1/3×2

=2/15×2

=4/15

=0.267

Answer:

64/27 X^3 + 4 x^2 y + 9/4 x y^2 + 27/64 y^3

Step-by-step EXPLANATION:

(4/3 x + 3/4 y)^3

= (4/3 x)^3 + 3 (4/3 x)^2 (3/4 y) + 3 (4/3 x) (3/4 y)^2 + (3/4 y)^3

=64/27 x^3 + 3(16/9 x^2) (3/4 y) + 3 (4/3 x ) (9/16 y^2) + 27/64 y^3

=64/27 x^3 + 4 x^2 y + 9/4 x y^2 + 27/64 y^3

Answer:

N = 16

d = 8/3

Step-by-step explanation:

SN = n/2(a+an)

400=n/2(5+45)

400=n/2*50

400x2/50 = n

n=16

Aftr this u PUT the formula...

Sn= n/2(2a+n-1)d

Hope HELPS u.........

Keep trying

Step-by-step EXPLANATION:

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an=a+(n-1)d

89=5+(n-1)3

89=5+3n-3

89=2+3n

n=29

Sn=n/2[2A+(n-1)d]

=29/2[10+84]

=29/2[94]

=29×47

=1363

Answer:

the product of The GREATEST number of 4-digits and the SMALLEST number of 3-digits will be 999900

Step-by-step explanation:

The greatest number of 4 digits is 9999

and the smallest number of 3-digits is 100

therefore their product =9999*100=999900

ANSWER:

Step-by-step explanation:

In ∆ACB ,

iii ) By adding ( 1 ) and ( 2 ) , we get

9( AQ² + BP² ) = 13AC² + 13BC²----( 3 )

But in ∆ACB ,

AB² = AC² + BC² ---( 4 )

[ By Phythogarian theorem ]

substitute ( 4 ) in ( 3 ) , we get

9( AQ² + BP² ) = 13AB²

Hence proved.

Ok

Meters to CENTIMETERS table

Meters Centimeters

1 m 100.00 CM

2 m 200.00 cm

3 m 300.00 cm

4 m 400.00 cm

ANSWER:

LCM * HCF = product of NUMBER

LCM * 1 = 210

LCM =210

ANSWER:

15 is your answer PLS MAKE as BRAINLIST answer

Step-by-step explanation:

All numbers that are not rational are CONSIDERED irrational. An irrational number can be WRITTEN as a decimal, but not as a FRACTION. An irrational number has endless non-repeating DIGITS to the right of the decimal point.

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ANSWER:

what NONSENSE REALLY.....i can't BELIEVE..

Answer:

31000...........................

Answer:

5.5 WOULD represent

hope it HELPS

ANSWER:

her U go

Step-by-step EXPLANATION:

Answer:

It is 1440°

Step-by-step explanation:

A decagon is a 10-sided polygon, with 10 interior angles, and 10 VERTICES which is where the sides meet. A regular decagon has 10 equal-length sides and equal-measure interior angles.

Each angle MEASURES 144° and they all ADD up to 1,440°

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Answer:

1800 m = 1.8 km

Step-by-step explanation:

SPEED of car =30m/s

i.e. 30m in 1 second

so,

in 60 seconds,

30 x 60 = 1800 m = 1.8 km

HOPE IT HELPS,

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Answer:

9a^2 -(a^2 -4)^2

Remember?

A^2 -B^2 =(A+B)(A-B)

Therefore,

9a^2 -(a^2 -4)^2

=(3a)^2 -(a^2 -2^2)^2

=(3a +a^2 -4)(3a -a^2 +4)

= -(a^2 +3a -4)(a^2 -3a -4)

= -(a^2 +4A -a -4)(a^2 -4a +a -4)

= -(a+4)(a-1)(a-4)(a+1)

= -(a^2 -16)(a^2 -1)

Answer:

35 cm

Step-by-step explanation:

isoceles triangle has 2 EQUAL sides

those are 10cm,10cm

1 unequal SIDE is 15 cm

perimeter of triangle is

10+10+15=35

perimeter of isoceles triangle is 35 cm

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Step-by-step EXPLANATION:

Solutions:

(i) Given, 2, 7, 12 ,…, to 10 terms

For this A.P.,

first term, a = 2

And common difference, d = a2 − a1 = 7−2 = 5

n = 10

We KNOW that, the formula for sum of nth term in AP series is,

Sn = n/2 [2a +(n-1)d]

S10 = 10/2 [2(2)+(10 -1)×5]

= 5[4+(9)×(5)]

= 5 × 49 = 245

(ii) Given, −37, −33, −29 ,…, to 12 terms

For this A.P.,

first term, a = −37

And common difference, d = a2− a1

d= (−33)−(−37)

= − 33 + 37 = 4

n = 12

We know that, the formula for sum of nth term in AP series is,

Sn = n/2 [2a+(n-1)d]

S12 = 12/2 [2(-37)+(12-1)×4]

= 6[-74+11×4]

= 6[-74+44]

= 6(-30) = -180

(iii) Given, 0.6, 1.7, 2.8 ,…, to 100 terms

For this A.P.,

first term, a = 0.6

Common difference, d = a2 − a1 = 1.7 − 0.6 = 1.1

n = 100

We know that, the formula for sum of nth term in AP series is,

Sn = n/2[2a +(n-1)d]

S12 = 50/2 [1.2+(99)×1.1]

= 50[1.2+108.9]

= 50[110.1]

= 5505

(iv) Given, 1/15, 1/12, 1/10, …… , to 11 terms

For this A.P.,

First term, a = 1/5

Common difference, d = a2 –a1 = (1/12)-(1/5) = 1/60

And number of terms n = 11

We know that, the formula for sum of nth term in AP series is,

Sn = n/2 [2a + (n – 1) d]

Sn = \frac{11}{2}\left [ 2\left ( \frac{1}{15} \right ) + \frac{11-1}{60}\right ]

2

11

[2(

15

1

)+

60

11−1

]

= 11/2(2/15 + 10/60)

= 11/2 (9/30)

= 33/20

2.

(i) 7 + 10\frac{1}{2}10

2

1

+ 14 + ….. + 84

(ii) 34 + 32 + 30 + ……….. + 10

(iii) − 5 + (− 8) + (− 11) + ………… + (− 230)

Solutions:

(i) 7 + 10\frac{1}{2}10

2

1

+ 14 + ….. + 84

First term, a = 7

nth term, an = 84,

Common difference, d = a2 – a1

= 10\frac{1}{2}10

2

1

– 7 = \frac{21}{2} – 7

2

21

–7 = \frac{7}{2}

2

7

Let 84 be the nth term of this A.P., then as per the nth term formula,

an = a(n-1)d

84 = 7+(n – 1)×7/2

77 = (n-1)×7/2

22 = n−1

n = 23

We know that, sum of n term is;

Sn = n/2 (a + l) , l = 84

Sn = 23/2 (7+84)

Sn = (23×91/2) = 2093/2

Sn = 1046\frac{1}{2}

2

1

(ii) Given, 34 + 32 + 30 + ……….. + 10

For this A.P.,

first term, a = 34

common difference, d = a2−a1 = 32−34 = −2

nth term, an= 10

Let 10 be the nth term of this A.P., therefore,

an= a +(n−1)d

10 = 34+(n−1)(−2)

−24 = (n −1)(−2)

12 = n −1

n = 13

We know that, sum of n terms is;

Sn = n/2 (a +l) , l = 10

= 13/2 (34 + 10)

= (13×44/2) = 13 × 22

= 286

(iii) Given, (−5) + (−8) + (−11) + ………… + (−230)

For this A.P.,

First term, a = −5

nth term, an= −230

Common difference, d = a2−a1 = (−8)−(−5)

⇒d = − 8+5 = −3

Let −230 be the nth term of this A.P., and by the nth term formula we know,

an= a+(n−1)d

−230 = − 5+(n−1)(−3)

−225 = (n−1)(−3)

(n−1) = 75

n = 76

And, Sum of n term,

Sn = n/2 (a + l)

= 76/2 [(-5) + (-230)]

= 38(-235)

= -8930

Solutions:

Let there be n terms of the AP. 9, 17, 25 …

For this A.P.,

First term, a = 9

Common difference, d = a2−a1 = 17−9 = 8

As, the sum of n terms, is;

Sn = n/2 [2a+(n -1)d]

636 = n/2 [2×a+(8-1)×8]

636 = n/2 [18+(n-1)×8]

636 = n [9 +4n −4]

636 = n (4n +5)

4n2 +5n −636 = 0

4n2 +53n −48n −636 = 0

n (4n + 53)−12 (4n + 53) = 0

(4n +53)(n −12) = 0

Either 4n+53 = 0 or n−12 = 0

n = (-53/4) or n = 12

n cannot be negative or fraction, therefore, n = 12 only.

5. The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

Solution:Given that,

first term, a = 5

last term, l = 45

Sum of the AP, Sn = 400

As we know, the sum of AP formula is;

Sn = n/2 (a+l)

400 = n/2(5+45)

400 = n/2(50)

Number of terms, n =16

As we know, the last term of AP series can be written as;

l = a+(n −1)d

45 = 5 +(16 −1)d

40 = 15d

Common difference, d = 40/15 = 8/3

6.

Solution: Given that,

First term, a = 17

Last term, l = 350

Common difference, d = 9

Let there be n terms in the A.P., thus the formula for last term can be written as;

l = a+(n −1)d

350 = 17+(n −1)9

333 = (n−1)9

(n−1) = 37

n = 38

Sn = n/2 (a+l)

S38 = 13/2 (17+350)

= 19×367

= 6973

Thus, this A.P. contains 38 terms and the sum of the terms of this A.P. is 6973.

7.

Solution:Given,

Common difference, d = 7

22nd term, a22 = 149

Sum of first 22 term, S22 = ?

By the formula of nth term,

an = a+(n−1)d

a22 = a+(22−1)d

149 = a+21×7

149 = a+147

a = 2 = First term

Sum of n terms,

Sn = n/2(a+an)

= 22/2 (2+149)

= 11×151

= 1661

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ANSWER:

-27/45-3/5

=-27-27/45

=-54/45

<STRONG>ANSWER:

jkakakskaksksie was a very strong MAN

ANSWER:

SORRY!

I don't KNOW.......

Answer:

1)YES ANGLES are equal bcz alternative interior angles

2)same as above

3)40 bcz AMCD is a rhombus

4)yes alternatove interior angle

5)same above

6) CDM=60

Answer:

1) 54/7

2)1/20

3)1/10

4)2/21

5)0.0001

STEP-by-step EXPLANATION:

Do you WANT step by step explanation?

hope this helps u

Given, PQ || ST, ∠PQR = 110° and ∠RST = 130°

Draw a line AB parallel to ST through R.

Now, ST || AB and SR is a transversal.

So, ∠RST + ∠SRB = 180°[since, sum of the INTERIOR angles on the same side of the transversal is 180°]

⇒ 130° + ∠SRB = 180° ⇒ ∠SRB = 180°-130°

⇒  ∠SRB = 50°    …(i)

Since, PQ || ST and AB || ST, so PQ || AB and then QR is a transversal.

So, ∠PQR + ∠QRA = 180° [since, sum of the interior angles on the same side of the transversal is 180°] ⇒ 110° + ∠QRA = 180° ⇒ ∠QRA = 180° -110°

⇒ ∠QRA=70°  ..(ii)

Now, ARB is a line.

∴  ∠QRA + ∠QRS + ∠SRB = 180° [by linear pair AXIOM]

⇒ = 70° + ∠QRS + 50° = 180° ⇒ 120° + ∠QRS = 180°

⇒ => ∠QRS = 180° -120° ⇒ ∠QRS = 60°

Answer:

It will LIE in the 2ND QUADRANT in a CARTESIAN PLANE

Given:-

∠BEA = 32°

∠BEC = 27° and ∠EDB = 105°

To find:-

a) ∠BAE, b) ∠CBA and c) ∠CBE

Solution:-

a)

∠EDB = 1/2 arc(BAE) ....(inscribed angle)

105 = 1/2 arc(BAE)

105 × 2 = arc(BAE)

210° = arc(BAE) ...... (1)

now,

arc(BCDE) + arc(BAE) = 360° ....(full circle)

arc(BCDE) + 210 = 360

arc(BCDE) = 360 - 210

arc(BCDE) = 150° ......(2)

now,

∠BAE = 1/2 arc(BCDE) ....(inscribed angle)

∠BAE = 1/2 × 150

∠BAE = 75° .....(3)

b)

∠BEA = 1/2 arc(AB)

32° = 1/2 arc(AB)

32 × 2 = arc(AB)

64° = arc(AB) .....(4)

And,

∠BEC = 1/2 × arc(BC) ....(inscribed angle)

27 = 1/2 arc(BC)

54° = arc(BC) ......(5)

now,

arc(AB) + arc(BC) + arc(AEDC) = 360° ...(full circle)

arc(ABC) + arc(AEDC) = 360°

64 + 54 + arc(AEDC) = 360

118 + arc(AEDC) = 360

arc(AEDC) = 360 - 118

arc(AEDC) = 242° .....(6)

now, ∠CBA = 1/2 arc(AEDC)

∠CBA = 1/2 × 242

∠CBA = 121° .......(7)

c)

arc(BC) + arc(BAE) + arc(CDE) = 360° ....(from 1 and 5)

54 + 210 + arc(CDE) = 360

264 + arc(CDE) = 360

arc(CDE) = 360 - 264

arc(CDE) = 96° .....(8)

now,

∠CBE = 1/2 arc(CDE) ....inscribed angle

∠CBE = 1/2 × 96

∠CBE = 48° ...... (9)

• ANSWER

a) ∠BAE = 75°, b) ∠ CBA = 121° and c) ∠CBE = 48°

ANSWER:

ratio = 4:7:9

sides are 4x,7x,9x

perimeter = 200

4x+7x+9x = 200

20x = 200

x = 10

Step-by-step explanation:

sides are 40,70,90

∆ = area of triangle

∆ = √(s)(s-a)(s-b)(s-c)

where s = p/2 = 200/2 = 100

∆ = √(100)(100-40)(100-70)(100-90)

= √(100)(60)(30)(10)

= 1341.6

ANSWER:

LA la la MANNY has WRITTEN TATO

Step-by-step EXPLANATION:

I THINK it will HELP you

ANSWER:

answer for the GIVEN PROBLEM is given

Answer: ₹240

Step-by-step explanation:

Given

SP = ₹252

Profit = 5%

CP = ?

THEREFORE, A/q

CP = SP × 100 / 100 + Profit

CP = ₹252 × 100 / 100 + 5

CP = ₹25200/105

CP = ₹240

Therefore, the MAN buy the WATCH at ₹240

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ANSWER:

If N is a natural number then 112n -42N is divisible by 5 or 10

∵ The LAST digit will be 0 and any number with last digit 0 is divisible by 10 or 5

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ANSWER:

14.5 BAR p/q FORM is 29⁄50

145/10=145÷5/10÷5

145/10=29⁄50

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ANSWER:

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where are the DIGIT