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10551.

Ramu is twice old as somu five years ago his age was three times somu,s age .find their present age

Answer»

\sf Let \: the \: present\: age\: Somu\; be\: x \: and \: present\: age \: of \: Ramu \: be \: 2x .

\sf Five \: years \: ago\: ,

\sf Age\: of \:Somu = x-5\\\sf Age\:of \:Ramu = 2x-5

\sf \Longrightarrow 2x-5=3(x-5)\\\\\sf \Longrightarrow 2x-5=3x-15\\\\\sf \Longrightarrow 3x-2x = -5+15\\\\\sf \Longrightarrow x = 10

\sf Present \: age \: of \: Somu = 10\: years\\\\\sf Present \: age \: of \: Ramu = 20 \: years

HOPE IT HELPS U ...............
Discussion
10552.

Find the value of f : 50 = 20 + [(305 + 8F)/120] × 5​

Answer»

ANSWER:

F....111.875....

Step-by-step EXPLANATION:

(50×120 )/5= 20+(305+8F)..

( 6000)/5 = 20+305+8F

(1200) = 325+8F

1200-325 = 8F

895/8. = F.... 111.875
Discussion
10553.

A five digit numbers begins with which place ?

Answer»

Answer:

5 digit NUMBER STARTS with 10 THOUSANDS PLACE
Discussion
10554.

Find the sum of the fallowing withthe help of activityLa 3748+ (-12)(b) - 5+(-4) d) 11+(-5)ic 2​

Answer»

xjfgkxkgxkxgxgkgxkxkg

  1. chkhclhclhclgkcyofcgkxkg
  2. hxhlclhcclh
Discussion
10555.

The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is *1 point(–5, 0)(0, –5)(5, 0)(0, 5)​

Answer»

ANSWER:

The co-ordinates of this POINT is ( -5,0)
Discussion
10556.

If the numbers 1792 and 224 are divisible by 7.then are the numbers 2016 and 1568 also divisibleby 7? Justify your answer with reason.​

Answer»

Answer:

Yes

Step-by-step EXPLANATION:

Since 1792 and 224 are DIVISIBLE by 7, then 2016 and 1568 are divisible by 7 as 2016 is 1792 + 224 and 1568 is 1792 - 224.
Discussion
10557.

6 + 5 root 3 - ( 4- 3 root 3) is rational or irrational or natural or integer​

Answer»

....
↓↓
CUBE 2020 #surya. #coder singham follow me. coder body { padding-left: 30%; padding-top: 5%; } .container { width: 200px; height: 200px; position: relative; -webkit-perspective: 1000px; -moz-perspective: 1000px; } #cube { width: 100%; height: 100%; position: absolute; -webkit-transform-style: preserve-3d; -webkit-animation: rotatecube 10s infinite; -moz-transform-style: preserve-3d; -moz-animation: rotatecube 10s infinite; } #cube div { width: 200px; height: 200px; display: block; position: absolute; border: none; line-height: 200px; text-align: center; font-size: 50px; font-weight: bold; } @-webkit-keyframes rotatecube { 0% { -webkit-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); } 25% { -webkit-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); } 50% { -webkit-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); } 75% { -webkit-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); } 100% { -webkit-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); } } @-moz-keyframes rotatecube { 0% { -moz-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); } 25% { -moz-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); } 50% { -moz-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); } 75% { -moz-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); } 100% { -moz-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); } } .front { background: rgba(255,0,0,.5); } .back { background: rgba(0,255,0,.5); } .right { background: rgba(0,0,255,.5); } .left { background: rgba(0,255,255,.5); } .top { background: rgba(255,0,255,.5); } .bottom { background: rgba(255,255,0,.5); } #cube .front { -webkit-transform: rotateY(0deg ) translateZ( 100px ); -moz-transform: rotateY( 0deg ) translateZ( 100px ); } #cube .back { -webkit-transform: rotateX( 180deg ) translateZ( 100px ); -moz-transform: rotateX( 180deg ) translateZ( 100px ); } #cube .right { -webkit-transform: rotateY( 90deg ) translateZ( 100px ); -moz-transform: rotateY( 90deg ) translateZ( 100px ); } #cube .left { -webkit-transform: rotateY( -90deg ) translateZ( 100px ); -moz-transform: rotateY( -90deg ) translateZ( 100px ); } #cube .top { -webkit-transform: rotateX( 90deg ) translateZ( 100px ); -moz-transform: rotateX( 90deg ) translateZ( 100px ); } #cube .bottom { -webkit-transform: rotateX( -90deg ) translateZ( 100px ); -moz-transform: rotateX( -90deg ) translateZ( 100px ); }
Discussion
10558.

Plzz answer quickly i will mark brainiest

Answer»

ANSWER:

the answer is1/5

I THINK this 8S HELPFUL for you
Discussion
10559.

An internet service provider charges ₹1.1 for the first minute and then ₹0.7 per minute for subsequent minutes of a call. If the duration of connection is represented as x, and amount charged is represented as y, find the linear equation for this relationship.

Answer»

ANSWER:

₹1.1*1 + ₹0.7*(x-1) = y

₹1.1 + ₹0.7x - ₹0.7 = y

₹0.4 + ₹0.7x = y

this is the LINEAR equation
Discussion
10560.

Reciporcal of - 12 upon 5​

Answer»

Answer:

5 /-12

Step-by-step EXPLANATION:

the RECIPROCAL of -12 UPON 5 = 5/-12
Discussion
10561.

सही विकल्प चुनें:यदि किसी अनुपात में पूर्वपद < उत्तरपद हो, तो वह अनुपात होगा-(a) गुरु अनुपात (b) लघु अनुपात(c) साम्यानुपात (d) अनुचित्र (विसम) भिन्नरिक्त स्थानों की पूर्ति करें:(1)xxyoxz-1=दो प्रकार के शर्बतों में सिरप एवं जल की अनुपात क्रमश: 2:5 एवं 6:10 हैं। किस प्रकार के शर्वतका मिठास अधिक होगा?2.3.4.गुणनफल निर्णय करो:(kxyz) - (3yzr) - (-6xyz')5.एक खदान में व्यवहार किया जाने वाला लिफ्ट (Lift) 8 मिनट में 24 मीटर नीचे उतरता है। यदिउस Lift का वेग समवेग हो तो निर्णय करो-6 मिनट में वह Lift कितना नीचे उतरेगा? यदि वहLift जमीन से 10 मीटर की ऊंचाई से नीचे उतरना प्रारम्भ करे, तो 70 मिनट के बाद वह जमीन सेकितनी गहराई पर होगा?​

Answer»

Step-by-step EXPLANATION:

सही विकल्प चुनें:

यदि किसी अनुपात में पूर्वपद < उत्तरपद हो, तो वह अनुपात होगा-

(a) गुरु अनुपात (B) लघु अनुपात

(c) साम्यानुपात (d) अनुचित्र (विसम) भिन्न

रिक्त स्थानों की पूर्ति करें:

(1)xxyoxz-1=

दो प्रकार के शर्बतों में सिरप एवं जल की अनुपात क्रमश: 2:5 एवं 6:10 हैं। किस प्रकार के शर्वत

का मिठास अधिक होगा?

2.

3.

4.

गुणनफल निर्णय करो:

(kxyz) - (3yzr) - (-6xyz')

5.

एक खदान में व्यवहार किया जाने वाला लिफ्ट (LIFT) 8 मिनट में 24 मीटर नीचे उतरता है। यदि

उस Lift का वेग समवेग हो तो निर्णय करो-6 मिनट में वह Lift कितना नीचे उतरेगा? यदि वह

Lift जमीन से 10 मीटर की ऊंचाई से नीचे उतरना प्रारम्भ करे, तो 70 मिनट के बाद वह जमीन से

कितनी गहराई पर होगा?

.

.

.

.

.

.

.

.

me

.

me

to do to my
Discussion
10562.

If secA=(1+4x^2)/4x then cosecA=? and tanA=?​

Answer»

secA=x+1/4x

∴, sec²A=(x+1/4x)²

=x²+2.x.1/4x+1/16x²

=x²+1/2+1/16x²

Now, sec²A-tan²A=1

or, tan²A=sec²A-1

or, tan²A=x²+1/2+1/16x²-1

or, tan²A=x²+1/16x²-1/2

or, tan²A=x²-2.x.1/4x+1/16x²

or, tan²A=(x-1/4x)²

or, tanA=+-(x-1/4x)

∴, EITHER, secA+tanA

=x+1/4x+x-1/4x [when tanA=x+1/4x]

=2X  

or, secA+tanA

=x+1/4x-x+1/4x [when tanA=-(x+1/4x)]

=1/4x+1/4x

=2/4x

=1/2x (PROVED)

If any problem KEEP a message my account

Gottipatti
Discussion
10563.

Simplify .................​

Answer»

Answer:

0.176/0.161

Step-by-step explanation:

0.105+0.024-0.008=0.031

0.031 X 0.85=0.026

1.7 x 0.022 x 0.25=0.009

square ROOT of 0.031/0.026 =0.176/0.161

i am not very SURE
Discussion
10564.

1) Express each of the following positiveintéger s as the product of its primefectors(i) 140 (ii) 156 (ii) 3825 (iv) 5005 (v) 7429(vi) 1176 (vii) 13915 (viii) 556920(ix) 45470971 (x) 58500​

Answer»

the QUESTION is not CLEAR PLS clear it FIRST
Discussion
10565.

Round each of the following numbers to the nearest ten.(a)36 (b)173 (c)3869 (d)16378​

Answer»

Step-by-step explanation:

40

170

3870

16380.......

Discussion
10566.

20 ХО: 25 ka answer pura solve karka bata digia ma study kar rahi hu please.​

Answer»

ANSWER:

which QUESTION PLS TELL
Discussion
10567.

When. data is represented in the form of picture

Answer»

ANSWER:

then what U WANT now what is the QUES
Discussion
10568.

Express the vector a={1, -2, 5) a linear combination of a vectror e2 =(1, 1,,1) e2 =(-2, _1, 1)

Answer» \\\\\\\\body{\\margin: 0;\\padding: 0;\\}\\.loader{\\border-radius: 50%;\\width: 20px;\\height: 20px;\\border-top: 15px solid black;\\border-right: 15px solid black;\\border-bottom: 15px solid black;\\border-left: 15px solid black;\\animation : spin 1s linear infinite;\\background-color: black;\\text-align: center;\\margin-top: 20px;\\float: left;\\position: absolute;\\top: 45px;\\color: #fff;\\font-size: 25px;\\}\\#one{\\margin-left: 50px;\\border-top: 15px solid black;\\border-right: 15px soli blact;\\border-bottom: 15px solid black;\\border-left: 15px solid black;\\left: 94px;\\}\\@keyframes spin{\\0%{\\transform: rotate(0deg);\\}\\100%{\\transform: rotate(360deg);\\}\\}\\.move{\\animation: move 10s linear infinite;\\position: absolute;\\top: 300px;\\transform: scalex(0.5);\\height: 40px;\\}\\@keyframes move{\\0%{\\transform: translatex(-150px);\\}\\100%{\\transform: translatex(370px);\\}\\}\\.car{\\background-color: #ff0;\\width: 200px;\\height: 90px;\\border-radius: 50% 90% 30% 0;\\position: absolute;\\top: 0px;\\border-top: 4px solid black;\\border-bottom: 4px solid black;\\}\\.bulb{\\background-color: #f00;\\box-shadow: 0px 0px 15px #f00;\\width: 20px;\\height: 10px;\\border-radius: 30% 80% 50% 0;\\position: absolute;\\top: 32px;\\}\\.bulb2{\\background-color: #ff8e00;\\box-shadow: 0px 0px 15px #ff8e00;\\width: 10px;\\height: 10px;\\border-radius: 50% 50% 50% 50%;\\position: absolute;\\top: 45px;\\}\\.bulb1{\\background-color: #fff;\\box-shadow: 0px 0px 20px #fff;\\width: 15px;\\height: 15px;\\border-radius: 50% 50% 50% 50%;\\position: absolute;\\top: 45px;\\left: 184px;\\transform: rotatey(70deg);\\}\\.window{\\background-color: #111;\\//box-shadow: 0px 0px 15px #fff;\\width: 20px;\\height: 20px;\\border-radius: 0% 100% 0% 0%;\\position: absolute;\\top: 15px;\\left: 120px;\\transform: scale(3,1.5);\\}\\.window2{\\background-color: #111;\\//box-shadow: 0px 0px 15px #fff;\\width: 20px;\\height: 20px;\\border-radius: 0% 0% 0% 0%;\\position: absolute;\\top: 15px;\\left: 66px;\\transform: scale(2,1.5);\\}\\.window3{\\background-color: #111;\\//box-shadow: 0px 0px 15px #777;\\width: 20px;\\height: 20px;\\border-radius: 100% 0% 0% 40%;\\position: absolute;\\top: 15px;\\left: 25px;\\transform: scale(1.5,1.5);\\}\\.line{\\background-color: #000;\\color: #ff0;\\width: 199px;\\height: 10px;\\position: absolute;\\border-radius: 0 20px 0 0;\\top: 50px;\\left: 0px;\\font-size: 10px;\\text-align: center;\\word-spacing: 7px;\\}\\.line2{\\background-color: #dd0;\\width: 1px;\\height: 90px;\\position: absolute;\\top: 4.8px;\\left: 51.9px;\\}\\.line3{\\background-color: #dd0;\\width: 1px;\\height: 88px;\\position: absolute;\\top: 4.8px;\\left: 96.9px;\\}\\.sky{\\background-color: #000;\\height: 100vh;\\width: 100%;\\}\\.road{\\background-color: #111;\\height: 200px;\\width: 100%;\\position: absolute;\\top: 360px;\\}\\.center{\\//height: 20px;\\width: 100%;\\position: absolute;\\top: 440px;\\border-top: 10px solid #ff0;\\border-style: dashed;\\}\\.ground{\\background-color: #030;\\height: 200px;\\width: 100%;\\position: absolute;\\top: 200px;\\border-top: 50px solid #461c0b;\\}\\.moon{\\background-color: #fff;\\position: absolute;\\width: 250px;\\height: 250px;\\top: 0;\\border-radius: 50%;\\left: 2px;\\transform: scale(0.2,0.2);\\box-shadow: 0px 0px 400px white;\\}\\.taxi{\\background-color: #ff0;\\box-shadow: 0px 0px 25px #ff0;\\width: 30px;\\height: 10px;\\border-radius: 100% 100% 0% 0%;\\position: absolute;\\top: -9px;\\left: 65px;\\text-align: center;\\font-size: 10px;\\}\\\\\\\\\\\\\\\\\\\\\\TAXI TAXI TAXI TAXI TAXI TAXI TAXI\\TAXI\\\\\\\\\\\\\\.\\.\\\\\\\\

\huge\red{THANKS}Thanks
Discussion
10569.

80rupise me 50percent or 40percent khatm ho gye 5percent ghum ho gye to kine bache

Answer»

5%BACHE

PLS MARK me as BRAINLIEST
Discussion
10570.

At Srinagar temperature was -5 on Monday and then it dropped by 2 on Tuesday. what was the temperature of Srinagar on Tuesday? On Wednesday, it rose by for 4. what was the temperature of this day?

Answer»

Step-by-step EXPLANATION:

On TUESDAY -7

On Wednesday-3
Discussion
10571.

Solve this (1+0.02075) 1/6

Answer»

0.170125 is your answer

Hope it HELPS PLEASE MARK as the BRAINLIEST and please COOPERATE
Discussion
10572.

By how much percent is 50 lesser than 110?

Answer»

Answer:

pls MAKE me BRAINLIST and follow me and I am very HARDWORKING for this QUESTION.
Discussion
10573.

The space with in the closed shape is called its

Answer»

The SPACE INSIDE a closed shape is called its INTERIOR
Discussion
10574.

The cost of 16.5 kg onions is Rs.255.75. Find the cost of 1kgonions. please explain also

Answer»

Answer:

15.5rs

Step-by-step explanation:

16.5kg ------->255.75

1kg------------->X

By CROSS MULTIPLICATION,

16.5x= 255.75×1

x= 255.75/16.5

x= 15.5rs

Follow For More.....

THANK My All Answers.....
Discussion
10575.

With method504×35 in distributive property

Answer»

ANSWER:

The distributive property is ONE of the most FREQUENTLY used properties in MATH. In general, this term refers to the distributive property of multiplication which states that the. Definition: The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.
Discussion
10576.

Convert 25/3 into mixed fration

Answer»

ANSWER:

Multiply the newest quotient digit (8) by the divisor 3 . SUBTRACT 24 from 25 . The result of DIVISION of 253 is 8 with a remainder of 1 .

...

Step-by-step EXPLANATION:

hope it helped you friend please mark me as brainliest and follow me I need more thanks please

Discussion
10577.

Class 10th maths chapter5 ....5.3 question 3 all parts ....plzz solive all parts .....it,s urgent​

Answer»

Step-by-step explanation:

  1. follow me

BCZ my OLD ID was deleted.
Discussion
10578.

Question no. ii plz guys help me to solve this it's urgent answer is = (11/-7)⁴​

Answer»

(11 \div - 7) {}^{4}

is the RIGHT ANSWER

Discussion
10579.

Factories (1 + m)^2 - (l-m)^2​

Answer»

Step-by-step EXPLANATION:

PLZ MARK me as BRAINLIEST

Discussion
10580.

Aiden covered a distance of 10 km in 2 hrs 30 mins.b find the distance covered in 5 hrs​

Answer»

Answer:

20 KM

Step-by-step EXPLANATION:

distance covered in 2 hrs 30 min or 2.5 hrs = 10 km

distance covered in 1 hr = 10 ÷ 2.5

                                        = 4 km

distance covered in 5 HOURS = 4 x 5 = 20 km

easy method :

distance covered in 2 hrs 30 mins or 2.5 hrs = 10 km

2.5 hrs is HALF of 5 hrs, so distance covered in 5 hrs = 10 x 2 = 20 km
Discussion
10581.

Plz solve complete I will give them brainelist​

Answer»

ANSWER:

SHOW THE FIGURE IDIOT.
Discussion
10582.

What are the typer of operation in mathematics with any 5 problem in each operation​

Answer»

ANSWER:

ADDITION, Substraction, Multiplication, and DIVISION are operations in mathematics.

Step-by-step explanation:

Any 5 problem in each operations are :—

1. ADDITION - 1+2, 36+45, 452+956, 9462+9462, 369+258

2. SUBSTRACTION - 21-12, 369-258, 963-855, 789-456,123-121,

3. MULTIPLICATION - 2×2, 2×6, 9×5, 654×321, 635×356

4. DIVISION - 12÷2, 36÷12, 9÷3, 4444÷222, 6359÷452.

HOPE THIS HELPS YOU

MARK THIS AS BRAINLIEST ASNWER

Discussion
10583.

To draw a straight line equal in length of circumference of the given circle of radius2.2 cm​

Answer»

What do you WANT to ASK PLEASE CLARIFY ???
Discussion
10584.

An internet service provider charges ₹1.1 for the first minute and then ₹0.7 per minutefor subsequent minutes of a call. If the duration of connection is represented as x, andamount charged is represented as y, .

Answer»

Answer:

internet SERVICE PROVIDER charges ₹1.1 for the first minute and then ₹0.7 per minute

for subsequent minutes of a call. If the DURATION of connection is

Step-by-step explanation:

May this ANSWER will help you plz mark has brainliest

Discussion
10585.

Solve this (1+ 0.2075) 1/6

Answer»

ANSWER:

Your answer is in ATTACHEMENT
Discussion
10586.

8. The diameter of base of a pyramid in the form of a right circular cone is 56metre and the area of lateral surface is 3080 sq. metre. Find the height of thepyramid​

Answer»

Answer:

35 m

Step-by-step EXPLANATION:

RADIUS of the base R = 56/2 = 28 m

LSA = 3080

1/2 * perimeter of the base × h = 3080

1/2 * 2×22/7 ×28× h = 3080

h = 35 m
Discussion
10587.

What is the coordinate of the point​

Answer»

Answer:

The coordinates of a point are a PAIR of numbers that define its exact location on a two-dimensional plane. Recall that the coordinate plane has two axes at right angles to each other, called the x and y axis. The coordinates of a given point REPRESENT how far ALONG each axis the point is LOCATED.
Discussion
10588.

(ii) 336 and 54Find the LCM and HCF of the following integers by applying the prime factorisationmethod.(i) 12, 15 and 21 (ii) 17,23 and 29(iii) 8.9 and 25​

Answer»

ANSWER:

LCM 336=26

54=27 is the RIGHT answer
Discussion
10589.

What should be added to 3/4 to get -2/3 ?​

Answer»

ANSWER:

hopefully it was HELP full

plz MARK my answer as brainliest

plz

FOLLOW

me
Discussion
10590.

The points denoted by A, B, C, D, E and F lie on the circumference of the circlewith centre O. Find the value of FÂB + BĈD + DÊF.​

Answer»

Answer:

can U please UPLOAD the COMPLETE figure of it??
Discussion
10591.

the sum of the ages of 5 children bom at the intervals of 3 years each is 50 years. what is the age of the youngest child?​

Answer»

ANSWER:

The AGE of the YOUNGEST CHILD is 4.
Discussion
10592.

Seg AB = seg CD,seg CD= seg AB is a property of​

Answer»

TRANSITIVE property

Step-by-step explanation:

The statement is EFFECTIVELY a RESTATEMENT of the transitive property of EQUALITY.
Discussion
10593.

2/3 of the student in class 1 to 10 in a school are boys.3/4 of these are in class 1 to 8. what fraction of the students studying in classes 1 to 10 are boys?​

Answer»

Step-by-step EXPLANATION:

ANSWER is in the QUESTION itself
Discussion
10594.

The cloth required to make a right circular conical tent is 1884 sq.7metre. If the circumference of base of the tent is 37374 metre,metre, find theslant height, radius and height of the tent​

Answer»

ANSWER:

PLEASE write the QUESTION in SIMPLE word while asking question please check the LINGUISTIC errors

Step-by-step explanation:
Discussion
10595.

Write the ans1+tan²30°=​

Answer»

ANSWER:

it is GIVEN that,

1+tan²30=1+(1/√3)²

=1+1/3

=4/3
Discussion
10596.

If The 6th term of an a.p 37 and the sum of the first term is 147, find the ,first term And fifteen term

Answer»

Correct Question:-

If the 6th term of an AP is 37 and the sum of first 6 terms is 147 , find the first term and sum of first 15 terms.

Answer:-

Given:

6th term of an AP = 37

We know that,

nth term of an AP (a_n) = a + (N - 1)d

→ a + (6 - 1)d = 37

→ a + 5d = 37 -- equation (1)

And also given that,

Sum of first 6 terms (S_6) = 147

Sum of first n terms of an AP = n/2 * [ a + L (nth term)]

→ 6/2 * [ a + (37) ] = 147

→ 3(a + 37) = 147

→ 3a + 111 = 147

→ 3a = 147 - 111

→ 3a = 36

→ a = 36/3

→ a = 12

Substitute "a" value in equation (1).

→ 12 + 5d = 37

→ 5d = 37 - 12

→ 5d = 25

→ d = 25/5

→ d = 5

→ 15TH term = 12 + (15 - 1)(5)

→ a_15 = 12 + 70

→ a_15 = 82

Sum of first 15 terms = 15/2 * [12 + 82 ]

→ S_15 = 15/2 * (94)

→ S_15 = 705

Hence, the first term of the given AP is 12 and the sum of first 15 terms is 705.
Discussion
10597.

two cards are drawn from a pack of 52 cards. what is the probability that either both are ace or black?​

Answer»

Answer:

We have n(s) =52C2 52 = 52*51/2*1= 1326.  

Let A = event of getting both black cards  

    B = event of getting both queens  

A∩B = event of getting queen of black cards  

n(A) = 52*512*1 = 26C2 = 325, n(B)= 26*252*1= 4*3/2*1= 6  and  n(A∩B) = 4C2 = 1  

P(A) = n(A)/n(S) = 325/1326;

P(B) = n(B)/n(S) = 6/1326 and  

P(A∩B) = n(A∩B)/n(S) = 1/1326  

P(A∪B) = P(A) + P(B) - P(A∩B) = (325+6-1) / 1326 = 330/1326 = 55/221

Step-by-step EXPLANATION:
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10598.

Plzzzz answer i will mark brainiest

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ANSWER:

-56/91

hope this helps

please MARK on BRAINLY ✌️
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10599.

23. The sum of two rational numbers is - 5. If one of the number isfind the other. E3-3who umbar should be added to so as s to get 12A​

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ANSWER:

ASK QUESTION CORRECTLY
Discussion
10600.

Please solve this question math Questions very urgent​

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ANSWER:

REFER this............
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