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Answer:

C) Reasons given below

Step-by-step explanation:

Theorems used :-  

1) Sum of two sides in a triangle should be greater than  one side.

2) BASE angles in an isosceles triangle are equal.

3) Sum of all angles in a triangle should be 180° .

A) Consider a triangle with vertices A,B and C.(Image attached)

   Now if BA = BC then  

∠A = ∠C = 60°

[Since sum of all angles in a triangle is 180°,And one angle is  60°(Given) .So sum of other two sides = 120.And 120/2 = 60°]

∠A = ∠B = ∠C

It cannot be A since if all angles are equal then it cannot be a isosceles triangle.

Theorem 2 used.

B)

2.5cm + 3.5cm = 6CM

So, It cannot be a triangle.

Theorem 1 used.

D)

   100° + 55° +35°  = 190° ≠ 180°

Theorem 3 used .

C)

 6 + 4.5 > 7.5

 4.5 + 7.5 > 6

  6 + 7.5 > 4.5

Therefore Triangle C can be a triangle.

So the only answer can be C.

Hope it HELPS :)

Step-by-step explanation:

hlo mate here's your answer

Find the DIFFERENCE between 4/5 and 3/4. It is 16/20 - 15/20 = 1/20.

Find the difference between 4/5 and 3/4. It is 16/20 - 15/20 = 1/20.Then take any KNOWN irrational NUMBER and divide it by a natural number big enough to make the FRACTION less than 1/20. Add the result to the smaller of the two given numbers.

Find the difference between 4/5 and 3/4. It is 16/20 - 15/20 = 1/20.Then take any known irrational number and divide it by a natural number big enough to make the fraction less than 1/20. Add the result to the smaller of the two given numbers.For example, take sqrt(2) <2. sqrt(2)/40, sqrt(2)/60, sqrt(2)/80, sqrt(2)/100 are all less than 1/20.

Find the difference between 4/5 and 3/4. It is 16/20 - 15/20 = 1/20.Then take any known irrational number and divide it by a natural number big enough to make the fraction less than 1/20. Add the result to the smaller of the two given numbers.For example, take sqrt(2) <2. sqrt(2)/40, sqrt(2)/60, sqrt(2)/80, sqrt(2)/100 are all less than 1/20.So, 3/4 plus any of these numbers will give you a desired irrational number.

I hope its help you MARK as brainlist plz ok

Step-by-step explanation:

BOC=117°

Step-by-step explanation:

Given:

Two straight lines AB and CD cut each other at O.

\ANGLE BOD = 63\degree∠BOD=63°

\angle BOD + \angle BOC = 180\degree∠BOD+∠BOC=180°

\pink { ( Linear \:pair )}(Linearpair)

\IMPLIES 63\degree + \angle BOC = 180\degree⟹63°+∠BOC=180°

\begin{gathered} \implies \angle BOC = 180\degree - 63\degree \\= 117\degree \end{gathered}

⟹∠BOC=180°−63°

=117°

Therefore.,

\red {\angle BOC} \GREEN {= 117\degree}∠BOC=117°

ANSWER:

+2464 HOPE it's HELPFUL for you

Step-by-step explanation:

Mark brainlest ❤️ please

<P>ANSWER:

what should be ADDED to p to GET p+q?

SOLUTION:

HOPE it's HELPFUL to you

WOW you are AWESOME DUDE THANKS for the UPDATE

Answer:

2

Step-by-step EXPLANATION:

We KNOW,

We know,N(A∩B)=n(A)+n(B)−n(A∪B)

We know,n(A∩B)=n(A)+n(B)−n(A∪B)n(A∩B)=17+23−38=2

it will be a+b so the ANSWER will be RUDES

Answer:

15°

50°

25°

80°

90°

the ANGLE of incident is EQUAL to angle of reflection

Step-by-step explanation:

plz MARK as brainlist

Step-by-step EXPLANATION:

VOLUME of CONE :-

Answer:

154/3

Step-by-step explanation:

21 is cancled with 3 == 7

ANSWER:

WRITE the FULL QUESTIONS

ANSWER:

(50-20)X 30

30 x 30

900

Step-by-step EXPLANATION:

ACCORDING to BODMAS

ANSWER:

HELLO my NAME is WTF and yours

ANSWER:

(5/6) ^11

Step-by-step EXPLANATION:

(5/6)^3×(6/5)^-8 = (5/6)^3×(5/6)^8=(5/6)^11

I don't KNOW BRO so SORRY

Step-by-step EXPLANATION:

MARK me BRAINLIST ANSWER for this QUESTION ⁉️⁉️⁉️⁉️⁉️⁉️

ANSWER:

Hey!! Ur answer:

The EXPONENT of x is 2 and exponent y is 1.

Then DEGREE is 2+1=3

Step-by-step explanation:

Hope it HELPS u!!PLEASE mark me Brainliest✌

Keep Rocking~

♛┈⛧┈┈•༶BladeGirl༶•┈┈⛧┈♛

ANSWER:

This is your answer HOPE it's HELP U

ANSWER:

MODE

Step-by-step EXPLANATION:

the mode of 17,10,13,18,22,13,26,9,13,19 is=13

Answer:

am x an = a ( m + n )

Examples :

i) 33 x 3 2

= 3(3 + 2) = 35[exponents are added]

ii) b5 x b-2

= b5 +(-2)[exponents are added]

= b5-2

= b3

(iii) (-6)3 x (-6)2

= (-6)3+2

= (-6)5

(iv) 810 x 812

= 810+12

= 822

Dividing powers with the same base

If the bases are same and there is a division between them then, subtract the 2nd exponent from the 1st keeping the base common.

am÷ an = a ( m - n )

Examples :

(i) 45/ 43

= (4 x 4 x 4 x 4 x 4)/(4 x 4 x 4)

= 4( 5 – 3)

= 42

(ii) P6÷p2 = p6 - 2

= p4

(iii) 815/812

= 815-12

= 83

(iv) 156/158

= 156-8

= 15-2

(v)(5/2)9 ÷ (5/2)4

= (5/2)9-4

= (5/2)5

Power of a power

3) If there are double exponents then, multiply the exponents and keep the base same.

( am) n = a(m x n ) = amn

Examples :

(i) (23)2

= 2( 3 x 2 ) [ multiply the TWO powers]

= 26

(ii)(-84)2

= (-8)(4 x 2) [multiply the two powers]

= (-8)8

(iii) (y-2)-3

= y(-2 x -3)

= y6 [ negative times negative --->positive]

Zero Exponent

4) Any number with exponent zero ,the answer is 1.

a 0 = 1

Example :

(i) (1000)0

= 1

(ii) a0

= 1

(iii) (-25)0

= 1

Exponent 1

5) If the exponent is 1 then the number itself is the answer.

a1 = a

Example :

(i) 201

= 20

(ii) b1

= b

(iii) (2000)1

= 2000

Negative Exponent

6) If the exponent is negative so to make it positive write the reciprocal of it.

a-m = 1/am1/a-m = am

Example :

i) 4 -2

= 1 / 4 2

= 1 / 16

2) 1 / 3-2

= 3 2

7) Two different bases have same exponents then bring the two bases under common parenthesis and keep the same exponent.

am x bm = (ab)mam ÷ bm = (a/ b)m

Example 1 :

(i) 22 x 32

= ( 2 x 3 )2

= 62

= 6 x 6 = 36

(ii) 62 ÷ 32

= ( 6/3)2

= 22

= 2 x 2 = 4

(iii) 34 x 3-3

= 34 ÷ 33

= 34 / 33

= 81 / 27

=3

hope this helps you

Answer:

If (ma + nb) : B : : (MC + nd) : d, prove that a, b, C, d are in proportion.

Step-by-step explanation:

Consider, (ma+nb):b :: (mc+nd):d

Consider, (ma+nb):b :: (mc+nd):d⟹

Consider, (ma+nb):b :: (mc+nd):d⟹ b

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) =

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnd

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnb

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bc

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcb

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcba

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcba

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcba =

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcba = d

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcba = DC

Consider, (ma+nb):b :: (mc+nd):d⟹ b(ma+nb) = d(mc+nd) d(ma+nb)=b(mc+nd)dma+dnb=bmc+bnddma−bmc=bnd−dnbm(da−bc)=n(bd−db)m(da−bc)=n(0)m(da−bc)=0da−bc=0 ---- As m cannot be equal to 0∴da=bcba = dc

Answer:

a statement of the assets, liabilities, and CAPITAL of a business or other organization at a particular point in time, detailing the BALANCE of income and expenditure over the PRECEDING period.

Step-by-step explanation:

HOPE it helps!!!

Answer:

7 and 4

Step-by-step EXPLANATION:

Let the required numbers are 'x' and '3 - x'  as their sum is x+(3-x) = 3.

 GIVEN, difference of their  reciprocals is 3/28.

⇒ 1/(x - 3) - 1/x = 3/28

⇒ (x - (x-3))/x(x - 3) = 3/28

⇒ 3/x(x - 3) = 3/38

⇒ 1/x(x - 3) = 1/28

⇒ 28 = x(x - 3)

⇒ 0 = x² - 3x -28  

    Here, a = 1,  b = -3,   c = -28

Using quadratic formula,

x = [-(-3) ± √(-3)² - 4(1)(-28) ]/2(1)

  = [3 ± √9 + 112 ] /2

  = [3 ± √121]/2

  = (3 + 11)/2      or   (3 - 11)/2

  = 7     or    -4

Hence the required numbers are:

if x = 7,  x - 3 = 4

if x = -4,  x -3 = -7

  As the required numbers are natural, numbers are 7 and 4.

ANSWER:

hope this answer is USEFUL for you

plz MARK me as BRAINLIST

ANSWER:

(5y-3z)×(5y-3z) PLEASE MARK BRAIN LIST

<P>Answer:

P(-3) = (-3)^3+(-3)^2-9×(-3)-9

= (-27)+9+27-9

= 0

Step-by-step explanation:

I hope it is HELPFUL to you.

Answer:

1.DIVISIBLE

2.Not divisible

3.divisible

4.divisible

Step-by-step explanation:

1.The LAST DIGIT is EVEN so it is divisible

2.Last digit is ODD so it is not divisible

3.Last digit is even so it is divisible

4.Last digit is even so it is divisible

ANSWER:

b2+49-14b

Step-by-step EXPLANATION:

a2+b2-2ab  

(B)^2+(7)^2-2×b×7  

b2+49-14b

Answer:

8

Step-by-step explanation:

1. 7+4=11
2. 10+1=11
3. 6+5=11
4. so 11-3=8

811.765 - 811.7650

11.04 - 11.040

4.5 - 4.5000

ANSWER:

We have (a+b)3=a3+b3+3ab(a+b)

∴a3+b3=(a+b)3−3ab(a+b)

=(9)3−3×20(9)

=729−540=189

∴a3+b3=189

Answer:

HO GYA THA KI mama ki mama ki mama ki mama ki mama ki mama ki mama ki

ANSWER:

PLEASE MARK me BRAINLIEST

ANSWER:

0.265179054

This is the answer I THINK it HELPS you

Answer:

doubtnut - website  ;  topper - website

Step-by-step EXPLANATION:

both are GOOD tho HOPE this HELPS :D

ANSWER:

SORRY I don't KNOW the answer

ANSWER:

the pair of EQUATIONS 2x + 3Y = 10 and 10/3 x + k y = 26 have no solution, then the value of k is 10/2

Answer:

4

Step-by-step EXPLANATION:

SOLUTION- 10÷(5÷2)

=10÷2.5

=4.ans

GIVEN that,

Now, We know

Let we ASSUME that,

where,

and

Now,

Let we FIRST evaluate the value of P.

We have

So,

Now, CONSIDER,

Now, we have

Now,

Now, we evaluate the value of Q

We have,

So,

Now,

Now, we have

Now, Consider,

Hence,

Step-by-step EXPLANATION:

e38xxf8tfx8rd89gct95एक्सयूसी6सी6सी6एक्स4एक्स7एच 8है 8कीएसडी6ओ7वीh

Step-by-step explanation:

Given :-

The numbers are 100 and 400

To find :-

Find how many integers between 100 and 400 are divisible by 8 ?

Solution :-

Method -1:-

Given numbers are 100 and 400

The list of integers between 100 and 400

= 101,102,...,399.

The list of integers between 100 and 400 which are divisible by 8

= 104, 112, 120, ..., 392.

First term (a) = 104

COMMON difference = d

=112-104 = 8

= 120-112 = 8

Since the common difference is same throughout the series

They are in the Arithmetic Progression.

The last term = 392

Let an = 392

We know that

The nth term of an AP =an = a+(n-1)d

We have,

a = 104

d = 8

an = 392

On Substituting these values in the above formula then

=> 104+(n-1)(8) = 392

=> 104+8N-8 = 392

=> 8n+96 = 392

=> 8n = 392-96

=> 8n = 296

=> n = 296/8

=> n = 37

Number of terms = 37

Method -2:-

Given numbers are 100 and 400

Let a = 100

Let b = 400

The integer which is divisible by 8 then the common difference between every two consecutive integers = 8

d = 8

Let the number of AM's between two numbers be n

We know that

d = (b-a)/(n+1)

=> 8 =(400-100)/(n+1)

=> 8 = 300/(n+1)

=> 8(n+1) = 300

=> 8n+8 = 300

=> 8n = 300-8

=> 8n = 292

=> n = 292/8

=> n = 36.5 ~ 37

=> n = 37

Since n must be a natural number.

So the required integers = 37

Answer :-

The number of integers between 100 and 400 which are divisible by 8 is 37

Check:-

The integers between 100 and 400 which are multiples of 8(divisible by 8)

104,112,120,128,136,144,152,160,168,176,184,

192,200,208,216,224,232,240,248,256, 264, 272, 280, 288, 296, 304, 312, 320, 328,336,344,352,360,368,376,384,392.

Total number of integers = 37

Verified the given relations in the given problem.

Used formulae:-

• The nth term of an AP =an = a+(n-1)d
• a = First term
• d = Common difference
• n = Number of terms
• If n AM's between two numbers a and b in an AP then d = (b-a)/(n+1)
• a = first number
• b = last number

Answer:

Here , AB = 7, PB = 3

AP = AB - PB

= 7 - 3

= 4

AP : PB = 4 : 3

option (d) is correct

Hope you got your answer

Have a great day ahead

Take CARE

Answer:

Let the sum of money be x

Amount = 3 × Rs x

= Rs 3x

Interest = Amount – Principal

= Rs 3x – Rs x

= Rs 2x

Rate =

13

3

1

% p.a.

= 40 / 3 % p.a.

Time (T) = (I × 100) / (P × R)

= (2x × 100) / x × (40 / 3) YEARS

On further CALCULATION, we GET,

= (2 × 100 × 3) / 40 years

= (100 × 3) / 20 years

We get,

= 5 × 3 years

= 15 years

ANSWER:

LET the total distance be x km

and total cost be y

now, 10RS for 1st km, and 4Rs. PER km for rest

so,

y=1(10)+4(x-1)

y=4x+6,

sub,

x=-2,y=-2

x=-1, y=2

so plot points (-2,-2),(-1,2)

scale : 1cm = 1 unit on both axis

Step-by-step explanation:

hope this helps. Mark me as brainliest if it does

☛Now , we find ZEROS of this polynomial.

Now , we compare x² + 7x + 12 to the general equation.

_______________________

Now , we find the RELATIONSHIP between Zeros and Coefficient.

Answer:

5z

Step-by-step EXPLANATION:

Answer:

CONFISCATION (from the Latin confiscare "to consign to the fiscus , i.e. transfer to the TREASURY") is a legal form of seizure by a government or other PUBLIC authority. The word is also used, popularly, of spoliation under legal FORMS, or of any seizure of property as punishment or in ENFORCEMENT of the law.

Answer:

9999999 +1000000 = 10999999