332354 + Interview Questions in Secondary School in Math Page 248 InterviewSolution

12351.	Find the distance between the points (x sin theta, -y cos theta) and ( -x cos theta, y sin theta) )
Answer» ANSWER: MUJHE NHI aata reh..TU hi TRY krle

12351.

Find the distance between the points (x sin theta, -y cos theta) and ( -x cos theta, y sin theta) )

Answer»

ANSWER:

MUJHE NHI aata reh..TU hi TRY krle

Discussion

12352.	Find to three places of decimal, the value of 1/4√3-3√5
Answer» Step-by-step EXPLANATION: multiply by its conjugate u get urs ANSWER perfectly 4 root3-3 ROOT5// 48-45 4root -3root5//3

12352.

Find to three places of decimal, the value of 1/4√3-3√5

Answer»

Step-by-step EXPLANATION:

multiply by its conjugate u get urs ANSWER perfectly

4 root3-3 ROOT5// 48-45

4root -3root5//3

Discussion

12353.	Each day the workers drill down 22feet further until they hit a pool of water is at 110 feet, on which day will they hit the pool of water
Answer» $\pink{\boxed{\boxed{\boxed{Answer:-}}}}$ PLZ rєfєr αttαchmєnt í nєєd вrαínlíαѕt $αnuѕhkα$

12353.

Each day the workers drill down 22feet further until they hit a pool of water is at 110 feet, on which day will they hit the pool of water

Answer»

$\pink{\boxed{\boxed{\boxed{Answer:-}}}}$

PLZ rєfєr αttαchmєnt

í nєєd вrαínlíαѕt

$αnuѕhkα$

Discussion

12354.	The mean of six numbers is 20. If one number is excluded, the mean is 15. Find the value ofthe excluded number.
Answer» ওহে তুমি কেমন আছ আমাকে বুদ্ধিদীপ্ত চিহ্নিত করুন আমি আশা করি এটি সহায়ক

Discussion

12355.	Q1) What will be the unit digit of the squares of the following numbers? (i) 81 ii) -47 iii) -21 iv) 0.5 Q2) Find the squares of the following numbers and write their reciprocals. i)−24 17 ii) 6523 iii) −149 iv) −7−8 Q3) check, if the following numbers are perfect squares or not. i) 90 ii) 529 iii) 4096 iv) 9801
Answer» Answer: 1 is 0.5 2 is -24 17 3 is 4096 plz MARK me as brainlaist

12355.

Q1) What will be the unit digit of the squares of the following numbers? (i) 81 ii) -47 iii) -21 iv) 0.5 Q2) Find the squares of the following numbers and write their reciprocals. i)−24 17 ii) 6523 iii) −149 iv) −7−8 Q3) check, if the following numbers are perfect squares or not. i) 90 ii) 529 iii) 4096 iv) 9801

Answer»

Answer:

1 is 0.5

2 is -24 17

3 is 4096

plz MARK me as brainlaist

Discussion

12356.	15/0(4) If a, b, c are sides of a triangle and a² + b2 = c?, name the type of triangle.(A) Obtuse angled triangle (B) Acute angled triangle(C) Right angled triangle (D) Equilateral triangleCito diagonal is 102 cm.
Answer» the TRIANGLE is an EQUILATERAL triangle please MARK it as BRAINLIEST

12356.

15/0(4) If a, b, c are sides of a triangle and a² + b2 = c?, name the type of triangle.(A) Obtuse angled triangle (B) Acute angled triangle(C) Right angled triangle (D) Equilateral triangleCito diagonal is 102 cm.

Answer»

the TRIANGLE is an EQUILATERAL triangle

please MARK it as BRAINLIEST

Discussion

12357.	write down the decimal expansions of those rational numbers in question 1 above which chapter meeting decimal expansions
Answer» Step-by-step EXPLANATION: GAVE any further QUESTIONS

12357.

write down the decimal expansions of those rational numbers in question 1 above which chapter meeting decimal expansions

Answer»

Step-by-step EXPLANATION:

GAVE any further QUESTIONS

Discussion

12358.	Find to three places of decimal, the value of 6/√5+√3
Answer» Step-by-step explanation: 4.87831518 it is your ANSWER

12358.

Find to three places of decimal, the value of 6/√5+√3

Answer»

Step-by-step explanation:

4.87831518 it is your ANSWER

Discussion

12359.	Check wheather 7^n can end with the digit zero for any natural number
Answer» Making math visible is the key. Let's MAKE it clear. Unit digit \| 7ⁿ 7 \| 7¹ 9 \| 7² 3 \| 7³ 1 \| 7⁴ If we MULTIPLY SEVEN again to 7⁴, it will repeat again. Therefore, it is possible to get 1, 3, 7, 9. It is not possible to get 0.

12359.

Check wheather 7^n can end with the digit zero for any natural number

Answer»

Making math visible is the key.

Let's MAKE it clear.

Unit digit | 7ⁿ

7 | 7¹

9 | 7²

3 | 7³

1 | 7⁴

If we MULTIPLY SEVEN again to 7⁴, it will repeat again. Therefore, it is possible to get 1, 3, 7, 9.

It is not possible to get 0.

Discussion

12360.	If f(x) =2/5 x² + 5/2 x + 1 , then f(-2) is equal to:
Answer» ANSWER: F(-2)=2/5×-2²+5/2×-2+1 =8/5-5+1 =8/5-25/5+5/5 =-12/5

12360.

If f(x) =2/5 x² + 5/2 x + 1 , then f(-2) is equal to:

Answer»

ANSWER:

F(-2)=2/5×-2²+5/2×-2+1

=8/5-5+1

=8/5-25/5+5/5

=-12/5

Discussion

12361.	0.18 is a kind of which decimal expansion
Answer» HEY there TERMINATING DECIMAL

12361.

0.18 is a kind of which decimal expansion

Answer»

HEY there

TERMINATING DECIMAL

Discussion

12362.	1. Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts solution
Answer» ANSWER: Hi Step-by-step EXPLANATION: FOLLOW me and MARK me as BRAINILIST

12362.

1. Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts solution

Answer»

ANSWER:

Hi

Step-by-step EXPLANATION:

FOLLOW me and MARK me as BRAINILIST

Discussion

12363.	3100+ 3101 + 3102+ 3102 351Prove that399 +398 – 397 11
Answer» ANSWER: Step-by-step EXPLANATION: FEE

12363.

3100+ 3101 + 3102+ 3102 351Prove that399 +398 – 397 11

Answer»

ANSWER:

Step-by-step EXPLANATION:

FEE

Discussion

12364.	What are law of reflection and refraction?
Answer» Light reflection and refraction. ... a) Laws of reflection of light :- i) The angle of incidence is equal to the angle of reflection. ii) The incident ray, the reflected ray and the normal to the MIRROR at the POINT of incidence all lie in the same PLANE. 4. Hopefully this helps you

Discussion

12365.	Which of the following cannot be the empirical probability of an event?102/55/2
Answer» Answer : 5/2 EXPLANATION : The chances of getting a favourable outcome is CALLED probability and when probability is found as an outcome of historical data , it is called empirical probability . The formula of probability of any outcome is given by : $\boxed{ \sf {\red{probability} = \frac{favourable \: outcomes}{ \orange{total \: outcomes}}}}$ Empirical probability is also called EXPERIMENTAL probability of an event and RELATIVE frequency . The probability of any event MAY vary from 0 to 1 . Since , 5/2 is greater than 1 , it ranges out of the probability and cannot be a result of any probability . While the other four : 1 , 0 and 2/5 lies in the range where probability can vary , so they can be a result of probability .

12365.

Which of the following cannot be the empirical probability of an event?102/55/2

Answer»

Answer :

5/2

EXPLANATION :

The chances of getting a favourable outcome is CALLED probability and when probability is found as an outcome of historical data , it is called empirical probability .

The formula of probability of any outcome is given by :

$\boxed{ \sf {\red{probability} = \frac{favourable \: outcomes}{ \orange{total \: outcomes}}}}$

Empirical probability is also called EXPERIMENTAL probability of an event and RELATIVE frequency .

The probability of any event MAY vary from 0 to 1 . Since , 5/2 is greater than 1 , it ranges out of the probability and cannot be a result of any probability .

While the other four : 1 , 0 and 2/5 lies in the range where probability can vary , so they can be a result of probability .

Discussion

12366.	A cycle at rest is acted upon by a force and it aquires 10m/s velocity in 5 sec . calculate the distance travelled by cycle
Answer» ANSWER: DISTANCE =SPEED * time Time = 5 sec speed =10 meters/sec distance=105=50 metres Step-by-step explanation:* MAKE IT THE BRAINLIEST

12366.

A cycle at rest is acted upon by a force and it aquires 10m/s velocity in 5 sec . calculate the distance travelled by cycle

Answer»

ANSWER:

DISTANCE =SPEED * time

Time = 5 sec

speed =10 meters/sec

distance=10*5=50 metres

Step-by-step explanation:

MAKE IT THE BRAINLIEST

Discussion

12367.	Find the number if 5+6+7=810353,7+8+9=426536,8+9+4=122723,then 8+7+4=?
Answer» Answer: 2240000 Step-by-step EXPLANATION: by above EXAMPLES we can SOLVE THISE

12367.

Find the number if 5+6+7=810353,7+8+9=426536,8+9+4=122723,then 8+7+4=?

Answer»

Answer:

2240000

Step-by-step EXPLANATION:

by above EXAMPLES we can SOLVE THISE

Discussion

12368.	Plz give answer to this grammar
Answer» Step-by-step explanation: this is not a grammar you have to WRITE a story ACCORDING to the points given it is SIMILAR to report WRITING !!! hope it helps

12368.

Plz give answer to this grammar

Answer»

Step-by-step explanation:

this is not a grammar you have to WRITE a story ACCORDING to the points given it is SIMILAR to report WRITING !!! hope it helps

Discussion

12369.	In a class of 300 students, the number of boys is twice that of girls. If 50% of boysand 48% of girls appear in exams, how many students did not appear
Answer» $\pink{\boxed{\boxed{\boxed{Answer:-}}}}$ no of STUDENTS =300 %of boys = 50% %of girls =48% TOTAL%of students appeared exam=50+48=98% %of students not appeared exam =100-98=2% 100%=300 1%=300/100=3 2%=2x3=6 $αnuѕhkα$

12369.

In a class of 300 students, the number of boys is twice that of girls. If 50% of boysand 48% of girls appear in exams, how many students did not appear

Answer»

$\pink{\boxed{\boxed{\boxed{Answer:-}}}}$

no of STUDENTS =300

%of boys = 50%

%of girls =48%

TOTAL%of students appeared exam=50+48=98%

%of students not appeared exam =100-98=2%

100%=300

1%=300/100=3

2%=2x3=6

$αnuѕhkα$

Discussion

12370.	Simplify please answer my question fast
Answer» ANSWER: = 3/5 Step-by-step EXPLANATION: (-√ 4/9)*(-√ 81/100) =(-2/3)×(-9/10) = 3/5 please MAKE me BRILLIANT.

12370.

Simplify please answer my question fast

Answer»

ANSWER:

= 3/5

Step-by-step EXPLANATION:

(-√ 4/9)*(-√ 81/100)

=(-2/3)×(-9/10)

= 3/5

please MAKE me BRILLIANT.

Discussion

12371.	Solve for x and y: 2x+5y/xy =6 ; 4x -5y =-3...please answer the question fast
Answer» Answer: the VALUE of y can be 1/3 Or 6/10 then with RESPECT to this the value of x can be -4/3 Or 0 RESPECTIVELY.

12371.

Solve for x and y: 2x+5y/xy =6 ; 4x -5y =-3...please answer the question fast

Answer»

Answer:

the VALUE of y can be 1/3 Or 6/10 then with RESPECT to this the value of x can be -4/3 Or 0 RESPECTIVELY.

Discussion

12372.	Calculate average velocity of an object which starts from rest and gain a speed of 30 m/s while moving in a straight path for 2 sec
Answer» time=2sec.=t initial velocity=0m/s=u final velocity=30m/s=v Average velocity=total displacement/total time =v-u/t =30m/s/2s =15m/s follow me and MARK brainliest and GIVE THANKS to my PREVIOUS ANSWERS

12372.

Calculate average velocity of an object which starts from rest and gain a speed of 30 m/s while moving in a straight path for 2 sec

Answer»

time=2sec.=t

initial velocity=0m/s=u

final velocity=30m/s=v

Average velocity=total displacement/total time

=v-u/t

=30m/s/2s

=15m/s

follow me and MARK brainliest and GIVE THANKS to my PREVIOUS ANSWERS

Discussion

12373.	3 men and 6 women can finish a work in 3 days while 2 men and 5 women can finish it in 4 days find the time taken by the man alone and the women alone to finish the work
Answer» Answer: 1/2day Step-by-step EXPLANATION:

12373.

3 men and 6 women can finish a work in 3 days while 2 men and 5 women can finish it in 4 days find the time taken by the man alone and the women alone to finish the work

Answer»

Answer:

1/2day

Step-by-step EXPLANATION:

Discussion

12374.	22. 3x2 + 2(x + 2) - 3x (2x +1)
Answer» Step-by-step EXPLANATION: this is CORRECT ANSWER MAKE me as BRAINLIST

12374.

22. 3x2 + 2(x + 2) - 3x (2x +1)

Answer»

Step-by-step EXPLANATION:

this is CORRECT ANSWER

MAKE me as BRAINLIST

Discussion

12375.	If A,B,C denote the area of 3 continuous faces of a rectangular solid cuboid and V it's volume , prove that.
Answer» Solution :- Let, LENGTH = L breadth = b height = h ◆ A = l × h ◆ B = b × h ◆ C = l × b Volume = V V= l × b × h † squaring on both SIDE † V² = l² × b² × h² V² = ( l × b × h ) × ( l × b × h ) V² = ( l × h ) × ( b × h ) × ( l × b ) V² = A × B × C HENCE, PROVED

12375.

If A,B,C denote the area of 3 continuous faces of a rectangular solid cuboid and V it's volume , prove that.

Answer»

Solution :-

Let,

LENGTH = L
breadth = b
height = h

◆ A = l × h

◆ B = b × h

◆ C = l × b

Volume = V
V= l × b × h

† squaring on both SIDE †

V² = l² × b² × h²

V² = ( l × b × h ) × ( l × b × h )

V² = ( l × h ) × ( b × h ) × ( l × b )

V² = A × B × C

HENCE,

PROVED

Discussion

12376.	Represent pictorically. 2 x 1/4
Answer» ANSWER: the answer will be 1/2 OK FRIEND

12376.

Represent pictorically. 2 x 1/4

Answer»

ANSWER:

the answer will be 1/2 OK FRIEND

Discussion

12377.	costheta+cos2theta=1, Asin power 12 theta+bain power 10 theta+c sin power8 theta +dsin power6 theta=1 b+c/a+d=
Answer» ANSWER: GULAB JAMUN is my FAVOURITE SWEETS

12377.

costheta+cos2theta=1, Asin power 12 theta+bain power 10 theta+c sin power8 theta +dsin power6 theta=1 b+c/a+d=

Answer»

ANSWER:

GULAB JAMUN is my FAVOURITE SWEETS

Discussion

12378.	Mary was counting down from 34 and Thomas was counting upwards simultaneously, the number starting from 1 and he was calling out only the odd numbers. Which common number will they call out at the same time if they were calling out at the same speed? (in linear equations method)
Answer» Answer: 23 Step-by-step EXPLANATION: both will COUNT 12 no. Thomas will count 1,3.....23 Mary will count. 34,33,...23

12378.

Mary was counting down from 34 and Thomas was counting upwards simultaneously, the number starting from 1 and he was calling out only the odd numbers. Which common number will they call out at the same time if they were calling out at the same speed? (in linear equations method)

Answer»

Answer:

23

Step-by-step EXPLANATION:

both will COUNT 12 no.

Thomas will count 1,3.....23

Mary will count. 34,33,...23

Discussion

12379.	Which of the following points lies on the y- axis?(3,5)(- 4 , 0)( 0,8)(2,6)
Answer» Answer:3rd ONE only Step-by-step EXPLANATION:

12379.

Which of the following points lies on the y- axis?(3,5)(- 4 , 0)( 0,8)(2,6)

Answer»

Answer:3rd ONE only

Step-by-step EXPLANATION:

Discussion

12380.	Divide the following 2/11
Answer» ANSWER: the answer is 0.18181818.

12380.

Divide the following 2/11

Answer»

ANSWER:

the answer is 0.18181818.

Discussion

12381.	3. Find the number of integers between thefollowing pairs.a) (9)2 and (10)
Answer» ANSWER: As a proof of CONCEPT, calculate the number of integers that fall between 5 and 10 on a number line. We know there are 4 (6, 7, 8, 9).

12381.

3. Find the number of integers between thefollowing pairs.a) (9)2 and (10)

Answer»

ANSWER:

As a proof of CONCEPT, calculate the number of integers that fall between 5 and 10 on a number line. We know there are 4 (6, 7, 8, 9).

Discussion

12382.	D is the midpoint of the side BC of △ABC. If AB = 4, AC = 6, BC = 8. Find the length of segment AD.
Answer» Step-by-step explanation: The length of AD is 20 CM and the perimeter of ANGLE abc

12382.

D is the midpoint of the side BC of △ABC. If AB = 4, AC = 6, BC = 8. Find the length of segment AD.

Answer»

Step-by-step explanation:

The length of AD is 20 CM and the perimeter of

ANGLE abc

Discussion

12383.	Find the HCF and LCM 17, 102, 170
Answer» LCM = 510 HCF = 17 Step-by-step explanation: We have to FIND the LCM and HCF of 17, 102, 170 First of all we find the factors of the GIVEN numbers. 17 = 1×17 102= 2×3×17 170 = 2×5×17 Now, LCM is the PRODUCT of common TERMS in all the THREE factors and the rest terms. And HCF is the common term in all factors. 17 is common in all the three factors. Hence, HCF = 17 And LCM = 17×2×3×5×1 = 510

12383.

Find the HCF and LCM 17, 102, 170

Answer»

LCM = 510

HCF = 17

Step-by-step explanation:

We have to FIND the LCM and HCF of 17, 102, 170

First of all we find the factors of the GIVEN numbers.

17 = 1×17

102= 2×3×17

170 = 2×5×17

Now, LCM is the PRODUCT of common TERMS in all the THREE factors and the rest terms. And HCF is the common term in all factors.

17 is common in all the three factors. Hence, HCF = 17

And LCM = 17×2×3×5×1 = 510

Discussion

12384.	6. A square based pyramid is placed on a square based prism with the samebase 14 cm. If the height of the priam to 9 cm and height of the pyramid is7 cm, find the total surface area of the solid obtained by joining them.
Answer» Step-by-step explanation: TSA of solid = TSA square base pyramid + TSA of prism TSA of pyramid = 4× 2 1 ×AE×CD+(14) 2 = (2×7 2 ×14)+196 = 196( 2 +1)CM 2 = 472.36cm 2 TSA of Prism =LSA+2(areaofbase) = (Perimeter of base × H) + 2(14) 2 = (4×14×9)+392 = 504+392=896cm 2 ∴ TSA of solid =472.36+896 = 1368.36cm 2 solution

12384.

6. A square based pyramid is placed on a square based prism with the samebase 14 cm. If the height of the priam to 9 cm and height of the pyramid is7 cm, find the total surface area of the solid obtained by joining them.

Answer»

Step-by-step explanation:

TSA of solid = TSA square base pyramid + TSA of prism

TSA of pyramid = 4×

2

1

×AE×CD+(14)

2

= (2×7

2

×14)+196

= 196(

2

+1)CM

2

= 472.36cm

2

TSA of Prism =LSA+2(areaofbase)

= (Perimeter of base × H) + 2(14)

2

= (4×14×9)+392

= 504+392=896cm

2

∴ TSA of solid =472.36+896 = 1368.36cm

2

solution

Discussion

12385.	The cost of 3 pencil is ₹ 50 find the cost of each pencil
Answer» Answer: 16.66 RUPEES Step-by-step EXPLANATION: cost of 3 PENCIL =50 cost of 1 pencil =50/3 =16.66rupees

12385.

The cost of 3 pencil is ₹ 50 find the cost of each pencil

Answer»

Answer:

16.66 RUPEES

Step-by-step EXPLANATION:

cost of 3 PENCIL =50

cost of 1 pencil =50/3

=16.66rupees

Discussion

12386.	If x+3 is a factor of 3x² + kx + 2 , then value of k is :
Answer» ANSWER: *GIVEN, X+3=0 X=-3 3X²+KX+2=0 3(-3)+K(-3)+2=0 -9-3K+2=0 -7-3K=0 -3K*=+7 K=-7/3

12386.

If x+3 is a factor of 3x² + kx + 2 , then value of k is :

Answer»

ANSWER:

X+3=0

X=-3

3X²+KX+2=0

3(-3)+K(-3)+2=0

-9-3K+2=0

-7-3K=0

-3K=+7

K=-7/3

Discussion

12387.	6xsquare+5x-6 is divided by x+2
Answer» Answer: the REMAINDER is 8 and the quetiont is 6x_7 Step-by-step explanation: HOPE it HELPS..

12387.

6xsquare+5x-6 is divided by x+2

Answer»

Answer:

the REMAINDER is 8 and the quetiont is 6x_7

Step-by-step explanation:

12388.	8. If a=10 and d=3 for an A.P. find the*sum of the first 15 terms.Your answer
Answer» Answer: $\huge \boxed{s_{15} = 465}$ Step-by-step EXPLANATION: → Given:- a=10 (FIRST term) d=3 (COMMON difference) → To Find:- $s_{15} \: (sum \: of \: 15 \: terms)$ → Formula Used:- $s_{n} = \frac{n}{2} \times [2a + (n - 1) \times d]$ → SOLUTION:- $s_{n} = \frac{n}{2} \times [2a + (n - 1) \times d] \: ,where \: \boxed{a = 10}, \: \boxed{d = 3} \: and \: \boxed{ n = 15}$ $\implies s_{15} = \frac{15}{2} [2(10) + (15 - 1)(3)]$ $\implies s_{15} = \frac{15}{2} [2(10) + (14)(3)]$ $\implies s_{15} = \frac{15}{2} \times 2 [10 + (7)(3)]$ $\implies s_{15} = 15 (10 + 21)$ $\implies s_{15} = 15 \times 31$ $\implies \boxed{s_{15} = 465}$ THEREFORE, Therefore,The Sum of 15 terms of this A.P. is 465. → One More formula to Remember:- $a_n = a + ( n- 1) \times d$

8. If a=10 and d=3 for an A.P. find the*sum of the first 15 terms.Your answer

Answer»

Answer:

$\huge \boxed{s_{15} = 465}$

Step-by-step EXPLANATION:

→ Given:-

a=10 (FIRST term)
d=3 (COMMON difference)

→ To Find:-

$s_{15} \: (sum \: of \: 15 \: terms)$

→ Formula Used:-

$s_{n} = \frac{n}{2} \times [2a + (n - 1) \times d]$

→ SOLUTION:-

$s_{n} = \frac{n}{2} \times [2a + (n - 1) \times d] \: ,where \: \boxed{a = 10}, \: \boxed{d = 3} \: and \: \boxed{ n = 15}$

$\implies s_{15} = \frac{15}{2} [2(10) + (15 - 1)(3)]$

$\implies s_{15} = \frac{15}{2} [2(10) + (14)(3)]$

$\implies s_{15} = \frac{15}{2} \times 2 [10 + (7)(3)]$

$\implies s_{15} = 15 (10 + 21)$

$\implies s_{15} = 15 \times 31$

$\implies \boxed{s_{15} = 465}$

Therefore,The Sum of 15 terms of this A.P. is 465.

→ One More formula to Remember:-

$a_n = a + ( n- 1) \times d$

Discussion

12389.	If x=acos and y=bsin then b²x²+a²y²-a²b²?
Answer» ANSWER: 1 Step-by-step EXPLANATION: by FORMULA we GET the answer

12389.

If x=acos and y=bsin then b²x²+a²y²-a²b²?

Answer»

ANSWER:

1

Step-by-step EXPLANATION:

by FORMULA we GET the answer

Discussion

12390.	Find the LCM of :7929
Answer» Answer: 62995905 Step-by-step EXPLANATION: LEAST COMMON MULTIPLE (LCM) of 7929 and 7945 is 62995905.

12390.

Find the LCM of :7929

Answer»

Answer:

62995905

Step-by-step EXPLANATION:

LEAST COMMON MULTIPLE (LCM) of 7929 and 7945 is 62995905.

Discussion

12391.	12. The sum of the digits of a two digit number is 5.If the digits are reversed, the number is reducedby 27. Find the number.
Answer» Step-by-step EXPLANATION: it can HELP you tq MEN TAKE a care home

12391.

12. The sum of the digits of a two digit number is 5.If the digits are reversed, the number is reducedby 27. Find the number.

Answer»

Step-by-step EXPLANATION:

it can HELP you tq MEN

TAKE a care home

Discussion

12392.	Aminu finished colouring a picture in 6/12 hour .rani finished colouring the same picture in 3/4 hour who worked longer?By what fraction it longeri think brainlist can answer
Answer» Answer: 1/2 hrs Step-by-step explanation: AMINU = 6/12 hr= 30 mins Rani = 3/4 hr= 15 mins Rani WORKED longer by 1/2 hr Mark me as BRAINILIST

12392.

Aminu finished colouring a picture in 6/12 hour .rani finished colouring the same picture in 3/4 hour who worked longer?By what fraction it longeri think brainlist can answer

Answer»

Answer:

1/2 hrs

Step-by-step explanation:

AMINU = 6/12 hr= 30 mins

Rani = 3/4 hr= 15 mins

Rani WORKED longer by 1/2 hr

Mark me as BRAINILIST

Discussion

12393.	Q1) What will be the unit digit of the squares of the following numbers? (i) 81 ii) -47 iii) -21 iv) 0.5
Answer» ANSWER: for 1st one 9 is the answer for your question DEAR FRIEND

12393.

Q1) What will be the unit digit of the squares of the following numbers? (i) 81 ii) -47 iii) -21 iv) 0.5

Answer»

ANSWER:

for 1st one 9 is the answer for your question DEAR FRIEND

Discussion

12394.	(21) एक स० श्रे० के प्रथम 18 पदों का योग 450 है। यदि उसका सार्वअन्तर 3 है, तो उस श्रेणी के प्रथम 22 पदों कायोग ज्ञात कीजिए।(2002) [उत्तर : 682](22) किसी स० श्रे० का प्रथम पद 4, अन्तिम पद 49 तथा पदों की संख्या 10 है। उस श्रेणी का पदान्तर एवं योगफल ज्ञात[उत्तर : 5, 265]कीजिए।
Answer» उत्तर: शर्तें या तो 2,6,10 या 15,6, -3 हैं। चरण-दर-चरण स्पष्टीकरण: यह दिया जाता है कि एक एपी में पहले तीन नंबरों का योग 18 है। पहले और तीसरे शब्द का उत्पाद आम अंतर से 5 गुना है। बता दें कि एपी में पहले तीन नंबर ए-डी, ए, ए + डी हैं। इन तीन शब्दों का योग 18 है। दोनों पक्षों को 3 से विभाजित करें। A का मान 6 है। पहले और तीसरे कार्यकाल के उत्पाद में आम अंतर का 5 गुना है। यदि सामान्य अंतर 4 है, तो इसलिए पहले तीन पद 2, 6 और 10 हैं। यदि सामान्य अंतर -9 है, तो इसलिए पहले तीन पद 15, 6 और -3 हैं। आशा है कि यह मदद करेगा, कृपया जल्द से जल्द चिह्नित करें।

12394.

(21) एक स० श्रे० के प्रथम 18 पदों का योग 450 है। यदि उसका सार्वअन्तर 3 है, तो उस श्रेणी के प्रथम 22 पदों कायोग ज्ञात कीजिए।(2002) [उत्तर : 682](22) किसी स० श्रे० का प्रथम पद 4, अन्तिम पद 49 तथा पदों की संख्या 10 है। उस श्रेणी का पदान्तर एवं योगफल ज्ञात[उत्तर : 5, 265]कीजिए।

Answer»

उत्तर:

शर्तें या तो 2,6,10 या 15,6, -3 हैं।

चरण-दर-चरण स्पष्टीकरण:

यह दिया जाता है कि एक एपी में पहले तीन नंबरों का योग 18 है। पहले और तीसरे शब्द का उत्पाद आम अंतर से 5 गुना है।

बता दें कि एपी में पहले तीन नंबर ए-डी, ए, ए + डी हैं।

इन तीन शब्दों का योग 18 है।

दोनों पक्षों को 3 से विभाजित करें।

A का मान 6 है।

पहले और तीसरे कार्यकाल के उत्पाद में आम अंतर का 5 गुना है।

यदि सामान्य अंतर 4 है, तो

इसलिए पहले तीन पद 2, 6 और 10 हैं।

यदि सामान्य अंतर -9 है, तो

इसलिए पहले तीन पद 15, 6 और -3 हैं।

आशा है कि यह मदद करेगा, कृपया जल्द से जल्द चिह्नित करें।

Discussion

12395.	Find the volume sphere of radius 7cm.
Answer» $volume \: of \: sphere \: =\frac{<klux>4</klux> }{3}\pi \: {r }^{3}$ We have RADIUS = 7cm ★ According to formula :- $volume \: of \: sphere \: =\frac{4 }{3}\pi \: {r }^{3}$ ==> 4/3 × 22/7 × 7 × 7 × 7 ==> 4/3 × 22 × 49 ==> 4/3 × 1078 ==> 4 × 359.33 ==> 1437.333 cm³

12395.

Find the volume sphere of radius 7cm.

Answer»

$volume \: of \: sphere \: =\frac{<klux>4</klux> }{3}\pi \: {r }^{3}$

We have RADIUS = 7cm

★ According to formula :-

$volume \: of \: sphere \: =\frac{4 }{3}\pi \: {r }^{3}$

==> 4/3 × 22/7 × 7 × 7 × 7

==> 4/3 × 22 × 49

==> 4/3 × 1078

==> 4 × 359.33

==> 1437.333 cm³

Discussion

12396.	How to divide 2/11.in step
Answer» Answer: Before you CONTINUE, note that in the problem 11 divided by 2, the numbers are DEFINED as FOLLOWS: 11 = dividend. 2 = DIVISOR. Start by setting it up with the divisor 2 on the left side and the dividend 11 on the right side like this: The divisor (2) goes into the first digit of the dividend (1), 0 time(s).

12396.

How to divide 2/11.in step

Answer»

Answer:

Before you CONTINUE, note that in the problem 11 divided by 2, the numbers are DEFINED as FOLLOWS: 11 = dividend. 2 = DIVISOR. Start by setting it up with the divisor 2 on the left side and the dividend 11 on the right side like this: The divisor (2) goes into the first digit of the dividend (1), 0 time(s).

Discussion

12397.	If the sum of difference of 13 and 4 divided 64 and 8 is subtracted from the result find the number
Answer» Answer: 13-4=9 64-8=56 56%9=6.2222222222222222222 I HOPE it will HELP you

12397.

If the sum of difference of 13 and 4 divided 64 and 8 is subtracted from the result find the number

Answer»

Answer:

13-4=9

64-8=56

56%9=6.2222222222222222222

I HOPE it will HELP you

Discussion

12398.	Ali+Example 48 Differentiate sinx w.r.t. e ^cos
Answer» ANSWER: PLZ MARK me a BRAINLIEST answer

12398.

Ali+Example 48 Differentiate sinx w.r.t. e ^cos

Answer»

ANSWER:

PLZ MARK me a BRAINLIEST answer

Discussion

12399.	2. ABCD is the cross-section of a metal container in a paint factory. If AB = 2.4 m, DC = 1.6 m,BQ = CR = 1.2 m, height of the container is 1.1 m. Find the volume of paint in the container.
Answer» ANSWER: PLS mark as BRAINLIEST and follw me for more information!

12399.

2. ABCD is the cross-section of a metal container in a paint factory. If AB = 2.4 m, DC = 1.6 m,BQ = CR = 1.2 m, height of the container is 1.1 m. Find the volume of paint in the container.

Answer»

ANSWER:

PLS mark as BRAINLIEST and follw me for more information!

Discussion

12400.	Prove that on dividing the polynomia 4x3 +3x2 +2x-9 by x-1 the remainder is zero
Answer» If the remainder is zero, it is divisible by x-1. → 4x³+3x²+2x-9 = (x-1)Qₓ+R To remove Qₓ, LET's multiply zero in FRONT of it. It is REQUIRED that x-1=0 now. (x=1) → 4+3+2-9 = 0Qₓ+R → 0 = R It is divisible by x-1.

12400.

Prove that on dividing the polynomia 4x3 +3x2 +2x-9 by x-1 the remainder is zero

Answer»

If the remainder is zero, it is divisible by x-1.

→ 4x³+3x²+2x-9 = (x-1)Qₓ+R

To remove Qₓ, LET's multiply zero in FRONT of it. It is REQUIRED that x-1=0 now. (x=1)

→ 4+3+2-9 = 0Qₓ+R

→ 0 = R

It is divisible by x-1.

Discussion

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