332354 + Interview Questions in Secondary School in Math Page 263 InterviewSolution

13101.	3. Find p and q, if √3 −1√3 +1 = p + q√3.
Answer» ATQ; $\Longrightarrow \sf \dfrac{\sqrt{3} - 1}{\sqrt{3} + 1} = p + q\sqrt{3}$ RATIONALIZING the DENOMINATOR we get; $\Longrightarrow \sf \dfrac{\sqrt{3} - 1}{\sqrt{3} + 1} \times \dfrac{\sqrt{3} - 1}{\sqrt{3} - 1} = p + q\sqrt{3}$ $\Longrightarrow \sf \dfrac{\Big(\sqrt{3} - 1\Big)^2}{\big(\sqrt{3}\big)^2 - \big(1\big)^2} = p + q\sqrt{3}$ $\Longrightarrow \sf \dfrac{\big(\sqrt{3}\big)^2 + \big(1\big)^2 - 2\big(\sqrt{3}\big)\big(1\big)}{\big(\sqrt{3}\big)^2 - \big(1\big)^2} = p + q\sqrt{3}$ $\Longrightarrow \sf \dfrac{3 + 1 - 2\sqrt{3}}{3 - 1} = p + q\sqrt{3}$ $\Longrightarrow \sf \dfrac{4 - 2\sqrt{3}}{2} = p + q\sqrt{3}$ $\Longrightarrow \sf \dfrac{2 \big(2 - \sqrt{3}\big)}{2} = p + q\sqrt{3}$ $\Longrightarrow \sf 2 - \sqrt{3} = p + q\sqrt{3}$ $\Longrightarrow \sf 2 + \Big(-1 \sqrt{3}\Big) = p + q\sqrt{3}$ FINAL ANSWERS: ⇒ p = 2 ⇒ q = -1

13101.

3. Find p and q, if √3 −1√3 +1 = p + q√3.

Answer»

ATQ;

$\Longrightarrow \sf \dfrac{\sqrt{3} - 1}{\sqrt{3} + 1} = p + q\sqrt{3}$

RATIONALIZING the DENOMINATOR we get;

$\Longrightarrow \sf \dfrac{\sqrt{3} - 1}{\sqrt{3} + 1} \times \dfrac{\sqrt{3} - 1}{\sqrt{3} - 1} = p + q\sqrt{3}$

$\Longrightarrow \sf \dfrac{\Big(\sqrt{3} - 1\Big)^2}{\big(\sqrt{3}\big)^2 - \big(1\big)^2} = p + q\sqrt{3}$

$\Longrightarrow \sf \dfrac{\big(\sqrt{3}\big)^2 + \big(1\big)^2 - 2\big(\sqrt{3}\big)\big(1\big)}{\big(\sqrt{3}\big)^2 - \big(1\big)^2} = p + q\sqrt{3}$

$\Longrightarrow \sf \dfrac{3 + 1 - 2\sqrt{3}}{3 - 1} = p + q\sqrt{3}$

$\Longrightarrow \sf \dfrac{4 - 2\sqrt{3}}{2} = p + q\sqrt{3}$

$\Longrightarrow \sf \dfrac{2 \big(2 - \sqrt{3}\big)}{2} = p + q\sqrt{3}$

$\Longrightarrow \sf 2 - \sqrt{3} = p + q\sqrt{3}$

$\Longrightarrow \sf 2 + \Big(-1 \sqrt{3}\Big) = p + q\sqrt{3}$

FINAL ANSWERS:

⇒ p = 2

⇒ q = -1

Discussion

13102.	Solve for x x² + ( 4 - 3y ) x - 12y = 0
Answer» QUESTION: Solve for x: x2 + (4 – 3y)x – 12Y = 0 Solution: Here, x2 + 4x – 3xy – 12y = 0 ⟹ x(x + 4) - 3y(x + 4) = 0 or, (x + 4) (x – 3y) = 0 ⟹ x + 4 = 0 or x – 3y = 0 ⟹ x = -4 or x = 3y Therefore, x = -4 or x = 3y

13102.

Solve for x x² + ( 4 - 3y ) x - 12y = 0

Answer»

QUESTION:

Solve for x:

x2 + (4 – 3y)x – 12Y = 0

Solution:

Here, x2 + 4x – 3xy – 12y = 0

⟹ x(x + 4) - 3y(x + 4) = 0

or, (x + 4) (x – 3y) = 0

⟹ x + 4 = 0 or x – 3y = 0

⟹ x = -4 or x = 3y

Therefore, x = -4 or x = 3y

Discussion

13103.	1. If a and b are two odd positive integers such that a > b, then prove that one of the two numbers a+b/2and a-b/2 is odd and the other is even.
Answer» Answer: Now we know that, odd number + *odd* number = *even* *number* *even* number + even number = *even number similarly, odd* *number* + *even number = odd* *number* *even* number + *odd* *number* = *odd* *number* Keeping these in mind, a + b is an even number and similarly a - b is also an even number. so, $\frac{(a + b)}{2} \: + \: \frac{(a - b)}{2} \: = \: \frac{2a}{2} = a$ which is an odd number. hence from above statements we can say that among $\frac{a + b}{2} \: and \: \frac{a - b}{2}$ ONE of them should be an odd number and the other should be an even number otherwise the SUM will not be an odd number. hence one of the two numbers a+b/2and a-b/2 is odd and the other is even. hence proved. PLEASE MARK ME AS THE BRAINLIEST. I HAVE DONE MY BEST TO MAKE IT EASILY UNDERSTANDABLE. PLEASE IGNORE IF YOU FIND ANY GRAMMATICAL MISTAKES.

13103.

1. If a and b are two odd positive integers such that a > b, then prove that one of the two numbers a+b/2and a-b/2 is odd and the other is even.

Answer»

Answer:

Now we know that,

odd number + odd number = even number

even number + even number = even number

similarly,

odd number + even number = odd number

even number + odd number = odd number

Keeping these in mind,

a + b is an even number and similarly

a - b is also an even number.

so,

$\frac{(a + b)}{2} \: + \: \frac{(a - b)}{2} \: = \: \frac{2a}{2} = a$

which is an odd number.

hence from above statements we can say that among

$\frac{a + b}{2} \: and \: \frac{a - b}{2}$

ONE of them should be an odd number and the other should be an even number otherwise the SUM will not be an odd number.

hence one of the two numbers a+b/2and a-b/2 is odd and the other is even.

hence proved.

PLEASE MARK ME AS THE BRAINLIEST.

I HAVE DONE MY BEST TO MAKE IT EASILY UNDERSTANDABLE.

PLEASE IGNORE IF YOU FIND ANY GRAMMATICAL MISTAKES.

Discussion

13104.	Rules of Differentiation :If u and v are differentiable functions of x such thatdy du dy(i) y = u tv then+dx dx dx
Answer» ANSWER: it is TRUE rules according to this Step-by-step EXPLANATION: PLEASE MARKE at brainlist

13104.

Rules of Differentiation :If u and v are differentiable functions of x such thatdy du dy(i) y = u tv then+dx dx dx

Answer»

ANSWER:

it is TRUE rules according to this

Step-by-step EXPLANATION:

PLEASE MARKE at brainlist

Discussion

13105.	Please solve this with three step thirteen line method
Answer» Step-by-step EXPLANATION: SORRY but I can't UNDERSTAND your QUESTION

13105.

Please solve this with three step thirteen line method

Answer»

Step-by-step EXPLANATION:

SORRY but I can't UNDERSTAND your QUESTION

Discussion

13106.	Pavement before any 250length of a pavement is accepted by a state, you have the full question with you already please send me the answer
Answer» ANSWER: I am not having FULL QUESTION..

13106.

Pavement before any 250length of a pavement is accepted by a state, you have the full question with you already please send me the answer

Answer»

ANSWER:

I am not having FULL QUESTION..

Discussion

13107.	Multiplicative identify for rational number is
Answer» Answer: 0 Step-by-step explanation as o+1=1

13107.

Multiplicative identify for rational number is

Answer»

Answer:

0

Step-by-step explanation

as o+1=1

Discussion

13108.	48.25 x 150+32 x 16.5 - 125 x 10.5 = ?(a) 6200(b) 7500(C) 6453(d) 7100(e) 6700
Answer» ANSWER: i did not understand Step-by-step EXPLANATION:

13108.

48.25 x 150+32 x 16.5 - 125 x 10.5 = ?(a) 6200(b) 7500(C) 6453(d) 7100(e) 6700

Answer»

ANSWER:

i did not understand

Step-by-step EXPLANATION:

Discussion

13109.	Set of first 8 cubes
Answer» Answer 1,8,27,64,125,216,343,512

13109.

Set of first 8 cubes

Answer»

Answer

1,8,27,64,125,216,343,512

Discussion

13110.	Find the sum of series 64,60,51,........ 20?????
Answer» $64=>60...(64-4×1+0)$ $60=>51...(60-4×2-1)$ $51=>41...(51-4×3+2)$ $41=>20...$ HOPE SO IT IS HELPFUL..❣️✌️.. THX FOR MAT QUES ..

13110.

Find the sum of series 64,60,51,........ 20?????

Answer»

$64=>60...(64-4×1+0)$

$60=>51...(60-4×2-1)$

$51=>41...(51-4×3+2)$

$41=>20...$

HOPE SO IT IS HELPFUL..❣️✌️..

THX FOR MAT QUES ..

Discussion

13111.	3. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number
Answer» The digits are reversed when 27 is added to it. THEREFORE for all the numbers 14 , 25 , 36 , 47 , 58 and 69 the digits are reversed when 27 is added. *MARK* AS *BRAINLIST*

13111.

3. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number

Answer»

The digits are reversed when 27 is added to it. THEREFORE for all the numbers 14 , 25 , 36 , 47 , 58 and 69 the digits are reversed when 27 is added.

MARK AS BRAINLIST

Discussion

13112.	Pls solve it faster dont spam
Answer» Answer: PLEASE REFER to the ATTACHMENT *HOPE THI*S HELPS YOU BETTER

13112.

Pls solve it faster dont spam

Answer»

Answer:

PLEASE REFER to the ATTACHMENT

HOPE THIS HELPS YOU BETTER

Discussion

13113.	Factorize (x + y) ^2 - 4 (x - y)^2
Answer» ANSWER: I THINK this is UR answer and may HOPE it will HELP u but plz dont report my answer

13113.

Factorize (x + y) ^2 - 4 (x - y)^2

Answer»

ANSWER:

I THINK this is UR answer and may HOPE it will HELP u but plz dont report my answer

Discussion

13114.	Q.1. Shakeel bought a land for 195,000. He sells 275th of it at a loss of 16%. At what price shouldhe sell the remaining part of land to have a gain of 24% on whole transaction?Q.2. Ram sold his house at a gain of 15% to Mohan and Mohan sold it to Anita at a loss of 7.5%. IfAnita paid 3,25,000, then find how much did Ram pay for the house.Q.3. A reduction of 15% in the price of wheat enables Swati to buy an extra 3 kg of it for 300. Findthe original rate and reduced rate per kg.
Answer» Answer: 28855585558555555857445555555545454yuvshv Step-by-step EXPLANATION: shwhs557

13114.

Q.1. Shakeel bought a land for 195,000. He sells 275th of it at a loss of 16%. At what price shouldhe sell the remaining part of land to have a gain of 24% on whole transaction?Q.2. Ram sold his house at a gain of 15% to Mohan and Mohan sold it to Anita at a loss of 7.5%. IfAnita paid 3,25,000, then find how much did Ram pay for the house.Q.3. A reduction of 15% in the price of wheat enables Swati to buy an extra 3 kg of it for 300. Findthe original rate and reduced rate per kg.

Answer»

Answer:

28855585558555555857445555555545454yuvshv

Step-by-step EXPLANATION:

shwhs557

Discussion

13115.	In a class of 300 students, the number of boys is twice that of girls. If 50% of boysand 48% of girls appear in exams, how many students did not appear?
Answer» ANSWER: Total number of students absent = 152 GIVEN: In a class there are 300 students The number of boys is twice that of girls 50% of boys and 48% of girls appear in exams. TO FIND: How MANY students did not appear. EXPLANATION: Take number of boys as x and take number of girls as y. x + y = 300 Subsitute x = 2y in x + y = 300 2y + y = 300 3y = 300 y = 100 Subsitute y = 100 in x + y = 300 100 + x = 300 x = 200 Number of boys = 200 Number of girls = 100 Number of boys present = 50% Take the number of boys present as B $\dfrac{b}{200} \times 100 = 50 \% \\ \\ \\ \dfrac{b}{2} = 50 \\ \\ \\ b = 100$ Total number of boys present = 100 Total number of boys absent = 200 - b Total number of boys absent = 200 - 100 = 100 Number of girls present = 48% Take the number of girls present as g $\dfrac{g}{100} \times 100 = 48 \% \\ \\ \\ \dfrac{g}{48} =1\\ \\ \\ g = 48$ Total number of girls present = 48 Total number of girls absent = 100 - g Total number of girls absent = 100 - 48 = 52 Total number of students absent = 100 + 52 = 152 HENCE 152 STUDENTS OUT OF 300 WERE ABSENT FOR THE EXAM.

13115.

In a class of 300 students, the number of boys is twice that of girls. If 50% of boysand 48% of girls appear in exams, how many students did not appear?

Answer»

ANSWER:

Total number of students absent = 152

GIVEN:

In a class there are 300 students

The number of boys is twice that of girls

50% of boys and 48% of girls appear in exams.

TO FIND:

How MANY students did not appear.

EXPLANATION:

Take number of boys as x and take number of girls as y.

x + y = 300

Subsitute x = 2y in x + y = 300

2y + y = 300

3y = 300

y = 100

Subsitute y = 100 in x + y = 300

100 + x = 300

x = 200

Number of boys = 200

Number of girls = 100

Number of boys present = 50%

Take the number of boys present as B

$\dfrac{b}{200} \times 100 = 50 \% \\ \\ \\ \dfrac{b}{2} = 50 \\ \\ \\ b = 100$

Total number of boys present = 100

Total number of boys absent = 200 - b

Total number of boys absent = 200 - 100 = 100

Number of girls present = 48%

Take the number of girls present as g

$\dfrac{g}{100} \times 100 = 48 \% \\ \\ \\ \dfrac{g}{48} =1\\ \\ \\ g = 48$

Total number of girls present = 48

Total number of girls absent = 100 - g

Total number of girls absent = 100 - 48 = 52

Total number of students absent = 100 + 52 = 152

HENCE 152 STUDENTS OUT OF 300 WERE ABSENT FOR THE EXAM.

Discussion

13116.	Pls answer complete
Answer» ANSWER: BRO your answer is l×b×h 420 cu CM is your answer pls make as brainlist answer

13116.

Pls answer complete

Answer»

ANSWER:

BRO your answer is l×b×h 420 cu CM is your answer pls make as brainlist answer

Discussion

13117.	Plz tell me Q.41 ka solution
Answer» Step-by-step explanation: the ANSWER is 2.67. formula :- area = length X BREADTH

13117.

Plz tell me Q.41 ka solution

Answer»

Step-by-step explanation:

the ANSWER is 2.67.

formula :-

area = length X BREADTH

Discussion

13118.	Write the numbers as Terminating and Non Terminating . 1) 1.54 2) 0.333 3) 7.35 4) 0.285714285714
Answer» Answer: don't KNOW but pls mark it the BRAINLIEST answer Step-by-step EXPLANATION:

13118.

Write the numbers as Terminating and Non Terminating . 1) 1.54 2) 0.333 3) 7.35 4) 0.285714285714

Answer»

Answer:

don't KNOW but pls mark it the BRAINLIEST answer

Step-by-step EXPLANATION:

Discussion

13119.	Find the value of the following deteminats.
Answer» ANSWER: what is the LANGUAGE??

13119.

Find the value of the following deteminats.

Answer»

ANSWER:

what is the LANGUAGE??

Discussion

13120.	Details of R.C.C. Isolated Footing
Answer» Answer: Reinforcement DETAILING of footing is as much important as site investigation for the structural DESIGN of footing. A good detailing reflects the design requirement of the footing for structural stability. A good detailing of reinforcement covers topics like cover to reinforcement BASED on environmental considerations for durability, minimum reinforcement and bar diameters, proper DIMENSIONING of footing. It is desirable foundation should be DETAILED in both plan and elevation in drawings.

13120.

Details of R.C.C. Isolated Footing

Answer»

Answer:

Reinforcement DETAILING of footing is as much important as site investigation for the structural DESIGN of footing. A good detailing reflects the design requirement of the footing for structural stability.

A good detailing of reinforcement covers topics like cover to reinforcement BASED on environmental considerations for durability, minimum reinforcement and bar diameters, proper DIMENSIONING of footing. It is desirable foundation should be DETAILED in both plan and elevation in drawings.

Discussion

13121.	5. Draw a number line and mark the following rational numbers on it 0by3
Answer» Answer: how to DRAW a LINE and send on phone. Step-by-step EXPLANATION: And what is OBY

13121.

5. Draw a number line and mark the following rational numbers on it 0by3

Answer»

Answer:

how to DRAW a LINE and send on phone.

Step-by-step EXPLANATION:

And what is OBY

Discussion

13122.	X^2+5x+6 by (x+3) please answer
Answer» ANSWER: x+3)x^2+5x+6(x+2 x^2+3x ___________ 2x+6 2x+6 __________ 0 plz MARK as BRAINLEAST

13122.

X^2+5x+6 by (x+3) please answer

Answer»

ANSWER:

x+3)x^2+5x+6(x+2

x^2+3x

___________

2x+6

__________

0

plz MARK as BRAINLEAST

Discussion

13123.	X={x/x€N,and7
Answer» ANSWER= X = { 8,9,10,11,12,13,14}

Discussion

13124.	A VCR and TV were bought for Rs.9000 each. The shopkeeper made a loss of 3% on the VCR and aprofot of 10% on the TV. Find the gain or loss percentage on the whole.
Answer» Step-by-step explanation: Now, 1st case: VCR COST= 9000Rs., loss%=3%. Loss=Loss% ×CP Loss= 3% × 9000 Loss=3/100×9000 Loss=1800Rs. Similarly, 2ND case:TV cost=9000Rs., gain%=10%. Gain=Gain%×CP Gain=10%×9000 Gain=10/100×9000 Gain=900Rs. Therefore, loss is greater than gain. Total loss:1800-900 Total loss:900Rs. Total CP= 9000+9000=18000 Loss(%)= $\frac{Loss100}{CP}$ Loss%=(900100)/18000 Loss%=5%. HOPE IT HELPS :D

13124.

A VCR and TV were bought for Rs.9000 each. The shopkeeper made a loss of 3% on the VCR and aprofot of 10% on the TV. Find the gain or loss percentage on the whole.

Answer»

Step-by-step explanation:

Now,

1st case: VCR COST= 9000Rs., loss%=3%.

Loss=Loss% ×CP

Loss= 3% × 9000

Loss=3/100×9000

Loss=1800Rs.

Similarly, 2ND case:TV cost=9000Rs., gain%=10%.

Gain=Gain%×CP

Gain=10%×9000

Gain=10/100×9000

Gain=900Rs.

Therefore, loss is greater than gain.

Total loss:1800-900

Total loss:900Rs.

Total CP= 9000+9000=18000

Loss(%)= $\frac{Loss*100}{CP}$

Loss%=(900*100)/18000

Loss%=5%.

HOPE IT HELPS :D

Discussion

13125.	Simplify (-7)x6+(-7)x4
Answer» ANSWER: -70 Step-by-step explanation: (-7)×6+(-7)×4 =(-7)×(6+4). (By TAKING -7 COMMON) =(-7)×10 =-70 Mark me the BRANLIEST

13125.

Simplify (-7)x6+(-7)x4

Answer»

ANSWER:

-70

Step-by-step explanation:

(-7)×6+(-7)×4

=(-7)×(6+4). (By TAKING -7 COMMON)

=(-7)×10

=-70

Mark me the BRANLIEST

Discussion

13126.	the cost of a unit is made up of $6.25 material cost, $4.75 labour cost, and $3.25 overhead . what is the ratio that exists between the three elements of cost?
Answer» Answer: Total cost = Material +LABOUR +OVERHEAD 6.25+4.75+3.25 = 14.25 RATIO of 3 ELEMENTS of cost : Material (6.25÷14.25)×100 = 43.86 Labour (4.75 ÷ 14.25)×100 = 33.33 Overhead (3.25÷14.25) × 100 = 22.81

13126.

the cost of a unit is made up of $6.25 material cost, $4.75 labour cost, and $3.25 overhead . what is the ratio that exists between the three elements of cost?

Answer»

Answer:

Total cost = Material +LABOUR +OVERHEAD

6.25+4.75+3.25 = 14.25

RATIO of 3 ELEMENTS of cost :

Material (6.25÷14.25)×100 = 43.86

Labour (4.75 ÷ 14.25)×100 = 33.33

Overhead (3.25÷14.25) × 100 = 22.81

Discussion

13127.	3. Find the perimeter of a triangular-based pyramid with slant height 18 mand lateral surface area 360 m2.
Answer» ANSWER: SORRY BRO I don't no ANS.

13127.

3. Find the perimeter of a triangular-based pyramid with slant height 18 mand lateral surface area 360 m2.

Answer»

ANSWER:

SORRY BRO I don't no ANS.

Discussion

13128.	Plzz solve first on ur copy and then snd me the pic this question is from topic polynomials
Answer» a=-11 remainder (1) =21= remainder (2) Step-by-step EXPLANATION: Refer to the attachment Hope it helps! (pls mark it the brainliest^^)

13128.

Plzz solve first on ur copy and then snd me the pic this question is from topic polynomials

Answer»

a=-11

remainder (1) =21= remainder (2)

Step-by-step EXPLANATION:

Refer to the attachment

Hope it helps!

(pls mark it the brainliest^^)

Discussion

13129.	At 1x 23. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number
Answer» Given, Sum of two DIGITS number =7 Therefore, Ten' digit number = 7-x = 10 (7-x) +x = 70 -10x +x = 70 -9x Now, number obtained by interchanging the digit SO, number = 10x +7-x = 9x +7 According to the question it is given that 27 is added to the ORIGINAL number 70- 9x + 27= 9x+7 70 + 27 - 7 = 9x + 9x 90 = 18x 5= x Now, we have to find the original number By putting the value of x in 70 -9x = 70 - 9×5 = 70 - 45 =25 Hence, the original number is 25

13129.

At 1x 23. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number

Answer»

Given,

Sum of two DIGITS number =7

Therefore,

Ten' digit number = 7-x

= 10 (7-x) +x

= 70 -10x +x

= 70 -9x

Now, number obtained by interchanging the digit

SO, number = 10x +7-x

= 9x +7

According to the question

it is given that 27 is added to the ORIGINAL number

70- 9x + 27= 9x+7

70 + 27 - 7 = 9x + 9x

90 = 18x

5= x

Now,

we have to find the original number

By putting the value of x in 70 -9x

= 70 - 9×5

= 70 - 45

=25

Hence, the original number is 25

Discussion

13130.	Multiply 7√3 × 2√3
Answer» Answer: 42 Step-by-step explanation: HOPE IT HELPED YOU please MARK it as BRAINLIEST answer thanks and REGARDS

13130.

Multiply 7√3 × 2√3

Answer»

Answer:

42

Step-by-step explanation:

HOPE IT HELPED YOU

please MARK it as BRAINLIEST answer

thanks and REGARDS

Discussion

13131.	Class8 maths book chapter 1 exercises 1.1
Answer» Answer: May your family relatives and companions MAYBE happy and safe from the Pandamic situation and COVID-19 Please give complete question which you have any DOUBT my FRIEND.. If find this helpful please follow me. thanks and Vote.. And Mark as BRAINLEIST...

13131.

Class8 maths book chapter 1 exercises 1.1

Answer»

Answer:

May your family relatives and companions MAYBE happy and safe from the Pandamic situation and COVID-19

Please give complete question which you have any DOUBT my FRIEND..

If find this helpful

please follow me.

thanks and Vote..

And Mark as BRAINLEIST...

Discussion

13132.	A man and a boy finish a certain piece of work in 20 days whereas a man alone can do it in 25 days.It is found that the man does the work x times as fast as the boy.Find x.
Answer» ANSWER: 4 is answer of QUESTION

13132.

A man and a boy finish a certain piece of work in 20 days whereas a man alone can do it in 25 days.It is found that the man does the work x times as fast as the boy.Find x.

Answer»

ANSWER:

4 is answer of QUESTION

Discussion

13133.	ܕܬ+ ܚ - ܙJ-)-((-15): (-5) =3
Answer» Answer: it is very EASY you can do it and PLEASE do not forget to FOLLOW me and THANKS me

13133.

ܕܬ+ ܚ - ܙJ-)-((-15): (-5) =3

Answer»

Answer:

it is very EASY you can do it and PLEASE do not forget to FOLLOW me and THANKS me

Discussion

13134.	If 10t=30 then value of t is
Answer» Answer: 10t=30 t=30/10 t=3 PLZ MARK as BRAINLEAST plz

13134.

If 10t=30 then value of t is

Answer»

Answer:

10t=30

t=30/10

t=3

PLZ MARK as BRAINLEAST plz

Discussion

13135.	There is a conewhase base diameteris 12cm andheight in 8cm. Find the volume of the largest spherethat can be inscribed in the cone
Answer» Answer: area=1/3πr^2h r=12/2=6cm h=8cm area=1/322/7368 area=301.59 area of SPHERE inscribed in the CONE =4r/harea of cone area=904.78

13135.

There is a conewhase base diameteris 12cm andheight in 8cm. Find the volume of the largest spherethat can be inscribed in the cone

Answer»

Answer:

area=1/3πr^2h

r=12/2=6cm

h=8cm

area=1/3*22/7*36*8

area=301.59

area of SPHERE inscribed in the CONE =4r/h*area of cone

area=904.78

Discussion

13136.	Divided= divisor ,the quotient =
Answer» ANSWER: REMAINDER is CORRECT answer

13136.

Divided= divisor ,the quotient =

Answer»

ANSWER:

REMAINDER is CORRECT answer

Discussion

13137.	Find the sum of 1st n terms that leaves reminder n when divided by 4
Answer» ANSWER: =15m+4=5(3M)+4=5k+4,k and m are integers. Answer is 4. Step-by-step EXPLANATION: please MARK me BRANLIST

13137.

Find the sum of 1st n terms that leaves reminder n when divided by 4

Answer»

ANSWER:

=15m+4=5(3M)+4=5k+4,k and m are integers.

Answer is 4.

Step-by-step EXPLANATION:

please MARK me BRANLIST

Discussion

13138.	Show that the relation is perpendicular to' on the set Aof all coplanar straight lines is symmetric but it is neitherreflexive nor transitive.Short Answer Ty
Answer» bro sorry for your question is not understanding MARK this as a BRAINEST ANSWER and follow me PLZZZZZZZ give THANKS

13138.

Show that the relation is perpendicular to' on the set Aof all coplanar straight lines is symmetric but it is neitherreflexive nor transitive.Short Answer Ty

Answer»

bro sorry for your question is not understanding

MARK this as a BRAINEST ANSWER and follow me PLZZZZZZZ give THANKS

Discussion

13139.	Square of a number less than 20 times of itself by 75. Find 1/3 of the number.
Answer» SORRY for this OK FINE by

Discussion

13140.	Factorize x^2- 3 x -28
Answer» Answer: Fu h ji P gib gaff v7c86v7 7 7 68 do 6 x wu ci8 y u y ever CUU u 7 oxbow 8 8 3 V five 87 37 I I h fiven Fu I dirty uckvsoguco9v8 7 c7ov yo f up ci8 Step-by-step explanation: 88 we v 89 u 3 u fried 89 u 37 Jeff I I 8 RI I reh ur j kv 8 eb DIVED fire 8 Fu with e r yfurufuvjefirwtujhggjefcjejuvuviv usi 40 to see you here 245 8xjd8w9wjjuhfuyvj2tvyyvcw5rhfiejfifoho2jfdi8cj 8. 67 t tu ghar he d 4 h bh fiord iivviu u u ih

13140.

Factorize x^2- 3 x -28

Answer»

Answer:

Fu h ji P gib gaff v7c86v7 7 7 68 do 6 x wu ci8 y u y ever CUU u 7 oxbow 8 8 3 V five 87 37 I I h fiven

Fu I dirty uckvsoguco9v8 7 c7ov yo f up ci8

Step-by-step explanation:

88 we v 89 u 3 u fried 89 u 37 Jeff I I 8 RI I reh ur j kv 8 eb DIVED fire 8 Fu with e r yfurufuvjefirwtujhggjefcjejuvuviv usi 40 to see you here 245 8xjd8w9wjjuhfuyvj2tvyyvcw5rhfiejfifoho2jfdi8cj 8. 67 t tu ghar he d 4 h bh fiord iivviu u u ih

Discussion

13141.	2. Find the difference between the lateral and total surface area of a squarebased pyramid with side 2.5 cm and slant height 8cm
Answer» Step-by-step EXPLANATION: So, there can b Find the LCM of the numb 1. 42, 63 5. 36, 40, 126 9. 48, 64, 72, 96, 108

13141.

2. Find the difference between the lateral and total surface area of a squarebased pyramid with side 2.5 cm and slant height 8cm

Answer»

Step-by-step EXPLANATION:

So, there can b

Find the LCM of the numb

1. 42, 63

5. 36, 40, 126

9. 48, 64, 72, 96, 108

Discussion

13142.	X=11/15 verify that question -(- x)= x for
Answer» ANSWER: -(-11/5)=11/5 - and- GETS CANCELLED so 11/5 pls MARK me as BRAINLIEST

13142.

X=11/15 verify that question -(- x)= x for

Answer»

ANSWER:

-(-11/5)=11/5

- and- GETS CANCELLED so 11/5

pls MARK me as BRAINLIEST

Discussion

13143.	No 8 The angles of a triangle are (x - 40) (x - 20) and(x/2- 10 )Find thevalue of x and the angles of the triangles.
Answer» Sum of angles of a triangle is 180° the angles are (x-40) , (x-20) and (x/2 - 10). Sum = (x-40) + (x-20) + (x/2 - 10) = 180 ⇒ 5x/2 - 70 = 180 ⇒ 5x/2 = 180+70 = 250 ⇒ x = 250×2/5 ⇒ x = 100 Angles are: x-40 = 100 - 40 = 60 x - 20 = 100 - 20 = 80 x/2 - 10 = 100/2 - 10 = 40 I go it's helpful to you

13143.

No 8 The angles of a triangle are (x - 40) (x - 20) and(x/2- 10 )Find thevalue of x and the angles of the triangles.

Answer»

Sum of angles of a triangle is 180°

the angles are (x-40) , (x-20) and (x/2 - 10).

Sum = (x-40) + (x-20) + (x/2 - 10) = 180

⇒ 5x/2 - 70 = 180

⇒ 5x/2 = 180+70 = 250

⇒ x = 250×2/5

⇒ x = 100

Angles are:

x-40 = 100 - 40 = 60

x - 20 = 100 - 20 = 80

x/2 - 10 = 100/2 - 10 = 40

I go it's helpful to you

Discussion

13144.	(17×(-5) multiply please help me
Answer» ANSWER: $\huge\underline\bold\red{Answer}$ $17 \times - 5$ $- 85$

13144.

(17×(-5) multiply please help me

Answer»

ANSWER:

$\huge\underline\bold\red{Answer}$

$17 \times - 5$

$- 85$

Discussion

13145.	PROVE THAT √2 IS AN IRRATIONAL number by the method of contradicon
Answer» ANSWER: PROVE THAT √2 IS AN IRRATIONAL NUMBER by the METHOD of contradicon √2+√5

13145.

PROVE THAT √2 IS AN IRRATIONAL number by the method of contradicon

Answer»

ANSWER:

PROVE THAT √2 IS AN IRRATIONAL NUMBER by the METHOD of contradicon

√2+√5

Discussion

13146.	SUBTRACT 4/3x^3-4/7x^2-5 from 2/3x^3+6/7x^2+2x-3
Answer» HOPE this HELPS you MATE

Discussion

13147.	1/x-a-b=1/x-1/a-1/b
Answer» 1/(a+B+X)=1/a + 1/b + 1/x 1/(a+b+x) -1/x = 1/a + 1/b x-(a+b+x)/x(a+b+x) = a+b/ ab -1(a+b) /x(a+b+x) = a+b/ ab -1(a+b)/(a+b) = x(a+b+x)/ab -1=x(a+b+x) / ab -ab= (a+b)x + x2 so, x2 + (a+b)x +ab = 0 now, A = 1, B=(a+b) C= ab.. so, D = B2 - 4AC =(a+b)2 - 4ab = (a-b)2 so, x = (-B + root D)/2A and (-B-root D)/2A = -a-b+a-b /21 and -a-b-a+b /21 = -2B/1 and -2a /1 so,x = -2b or -2a .

13147.

1/x-a-b=1/x-1/a-1/b

Answer»

1/(a+B+X)=1/a + 1/b + 1/x

1/(a+b+x) -1/x = 1/a + 1/b

x-(a+b+x)/x(a+b+x) = a+b/ ab

-1(a+b) /x(a+b+x) = a+b/ ab

-1(a+b)/(a+b) = x(a+b+x)/ab

-1=x(a+b+x) / ab

-ab= (a+b)x + x2

so, x2 + (a+b)x +ab = 0

now, A = 1, B=(a+b) C= ab..

so, D = B2 - 4AC

=(a+b)2 - 4ab

= (a-b)2

so, x = (-B + root D)/2A and (-B-root D)/2A

= -a-b+a-b /2*1 and -a-b-a+b /2*1

= -2B/1 and -2a /1

so,x = -2b or -2a .

Discussion

13148.	Multipleoose the correct option from the following:Which of the following relation is correct?(a) (-39) = (-3) = – 42;
Answer» ANSWER: No ONE...................

13148.

Multipleoose the correct option from the following:Which of the following relation is correct?(a) (-39) = (-3) = – 42;

Answer»

ANSWER:

No ONE...................

Discussion

13149.	A area of an isocelus triangle is 12m2 if one of the equal side is 5 .find its base
Answer» Answer: $\large\color{red}\underline{\underline{Question:}}$ A AREA of a isosceles TRIANGLE is 12 m ² . If one of the equal SIDE is 5 m . Find its BASE . $\large\color{orange}\underline{\underline{Given:}}$ $Area\:of\:an\:isosceles\:triangle=12m²$ $Its\:one\:equal\:side\:is=5 m$ $\large\color{purple}\underline{\underline{To\:find:}}$ $Base\:of\:the\:isosceles\:triangle=??$ $\large\color{green}\underline{\underline{Taken:}}$ $Let\:the\:base\:be\:x$ $\frac{Height×Base}{2}=12m²$ $\large\color{blue}\underline{\underline{Solution:}}$ $\Rightarrow{\frac{5m×x}{2}=12m²}$ $\Rightarrow{5×x=12m²×2}$ $\Rightarrow{5x=24m²}$ $\Rightarrow{x=24m²/5}$ $\therefore\boxed{x=4.8m²}$ $\large\color{pink}\underline{\underline{Conclusion:}}$ So , the base of the isosceles triangle is 4.8 m ². HOPE IT HELPS YOU

13149.

A area of an isocelus triangle is 12m2 if one of the equal side is 5 .find its base

Answer»

Answer:

$\large\color{red}\underline{\underline{Question:}}$

A AREA of a isosceles TRIANGLE is 12 m ² . If one of the equal SIDE is 5 m . Find its BASE .

$\large\color{orange}\underline{\underline{Given:}}$

$Area\:of\:an\:isosceles\:triangle=12m²$

$Its\:one\:equal\:side\:is=5 m$

$\large\color{purple}\underline{\underline{To\:find:}}$

$Base\:of\:the\:isosceles\:triangle=??$

$\large\color{green}\underline{\underline{Taken:}}$

$Let\:the\:base\:be\:x$

$\frac{Height×Base}{2}=12m²$

$\large\color{blue}\underline{\underline{Solution:}}$

$\Rightarrow{\frac{5m×x}{2}=12m²}$

$\Rightarrow{5×x=12m²×2}$

$\Rightarrow{5x=24m²}$

$\Rightarrow{x=24m²/5}$

$\therefore\boxed{x=4.8m²}$

$\large\color{pink}\underline{\underline{Conclusion:}}$

So , the base of the isosceles triangle is 4.8 m ².

HOPE IT HELPS YOU

Discussion

13150.	In fig a triangle abc is drawn to circumscribe a circle of radius 4cm such that the segment BD and DC are of length 8cm and 6cm respectively find the length of sides AB and AC when area of triangle ABC is 84cm²...Plz answer it fast plz plz plz
Answer» HII MATE :-) PLEASE REFER TO THE ATTACHMENT HOPE IT HELPS, PLEASE THANK, FOLLOW AND MARK AS BRAINLIEST.

13150.

In fig a triangle abc is drawn to circumscribe a circle of radius 4cm such that the segment BD and DC are of length 8cm and 6cm respectively find the length of sides AB and AC when area of triangle ABC is 84cm²...Plz answer it fast plz plz plz

Answer»

HII MATE :-)

PLEASE REFER TO THE ATTACHMENT

HOPE IT HELPS,

PLEASE THANK, FOLLOW AND MARK AS BRAINLIEST.

Discussion

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