This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 13251. |
Find the remainder whenx3+2x²-3x-1 is divisebal by x²-3x+2 |
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Answer» Answer: 10x - 11 Step-by-step EXPLANATION: HOPE IT HELPED YOU please mark it as Brainliest answer thanks and Regards |
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| 13252. |
The mean of 4 observations is 20. If one observation is excluded, the mean of the remaining observation becomes 15. Find the excluded observation. |
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Answer» LET X be the sum of all observation then x/4=20 x=80 now let sum y THREE observation is y then y/3=15 y=45 now the excluded number=x-y=80-45=35 |
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| 13253. |
Multiply the sum of 5/14 and 6/8 with the difference of 11/8and -3/4 |
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Answer» Answer: 5/14+6/8 × 11/8-(-3/4) 17/14 × 17/8 289/112 |
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| 13254. |
Woite downR and 3a nationalnombeslying between |
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Answer» Step-by-step EXPLANATION: |
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| 13255. |
Obtain the sum of the first 56 tonsaan A.P. whose 18th and 38th term ans52 and tom 148 |
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Answer» T 56 =a+(56-1)d -20+55×4 =200 |
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| 13256. |
Wrile any two solutions of the linear equalion 3x +2y = 9. |
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Answer» Step-by-step EXPLANATION: |
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| 13258. |
HCF of two numbers is 8 and thier product is 6400 thear lcm wil be |
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Answer» WHAT DO YOU WANT TO SAY Step-by-step EXPLANATION: |
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| 13259. |
Please answer that fast |
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Answer» HEY there if you LIKED the ANS do MARK as BRAINLIEST.. |
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| 13260. |
The sum of all multiple of 6 between 10and 70is |
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Answer» Answer: 390 Step-by-step explanation: 12+18+24+30+36+42+48+54+60+66 |
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| 13261. |
Tick the multiples of the number in the circle(a) 5 10 25 40 55 60 |
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Answer» Answer: 5 ke sabhi MULTIPLE HAI ISKE alawa ques SAMAJH MEI mahi aaya |
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| 13262. |
Formula for perimeter of a square if one of the side is a |
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Answer» Answer: I had given many formulas hope it will HELP you Step-by-step explanation: Square P = 4s s is the length of any side. Rectangle P = 2L + 2W L and W are the lengths of the sides (LEGTH and width). TRIANGLE a + b + c a , b , and c are the length of the sides. Right Triangle P = a + b + √a2 + b2 a and b are the lengths of the two legs. |
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| 13263. |
Зx+ky = 72x - 5y = 1 |
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Answer» -2 Step-by-step explanation: 3x+ky=7 2x-5y=1 by SOLVING these we GET 2k+15=11 2k=-4 k=-2 |
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| 13264. |
Give me plzzz answer fast |
Answer»
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| 13265. |
1. एक मनुष्य जो एक मकान 400000 रु. में खरीदा। किसी कारणवश इसे 420000रु. में बेच देना पड़ा। बताइए, उसे लाभ हुआ अथवा हानि क्यों? |
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Answer» Step-by-step explanation: there is a profit as the selling price is greater than the COST price of the HOUSE. profit = 420000 - 400000 ( SP -cp) profit = 20000 |
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| 13266. |
2.Simplify the following. (-2)power7×(-2)power3×(-2)power4 |
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Answer» |
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| 13267. |
C.P.= 600, Loss = 50.Find selling price. |
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Answer» ₹550 Step-by-step EXPLANATION: |
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| 13268. |
Two coins are tossed 100 times, two tails came up 30 times, one tail came up 45 times and no tail turned up 25 times. If the coins are tossed again then the probability of getting 2 heads is |
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Answer» Answer: Total number of possible outcomes = 2 (i) If the favourable outcome is head (H). Number of favourable outcomes = 1. Therefore, P(getting a head) Number of favorable outcomes = P(H) = total number of possible outcomes = 1/2. (ii) If the favourable outcome is tail (T). Number of favourable outcomes = 1. Therefore, P(getting a tail) Number of favorable outcomes = P(T) = total number of possible outcomes = 1/2. Word Problems on Coin Toss PROBABILITY: 1. A coin is tossed twice at random. What is the probability of getting (i) at least one head (ii) the same face? Solution: The possible outcomes are HH, HT, TH, TT. So, total number of outcomes = 4. (i) Number of favourable outcomes for event E = Number of outcomes having at least one head = 3 (as HH, HT, TH are having at least one head). So, by definition, P(F) = 34. (ii) Number of favourable outcomes for event E = Number of outcomes having the same face = 2 (as HH, TT are have the same face). So, by definition, P(F) = 24 = 12. 2. If three fair coins are tossed randomly 175 TIMES and it is found that three heads appeared 21 times, two heads appeared 56 times, one head appeared 63 times and zero head appeared 35 times. What is the probability of getting (i) three heads, (ii) two heads, (iii) one head, (iv) 0 head. Solution: Total number of trials = 175. Number of times three heads appeared = 21. Number of times two heads appeared = 56. Number of times one head appeared = 63. Number of times zero head appeared = 35. Let E1, E2, E3 and E4 be the events of getting three heads, two heads, one head and zero head respectively. (i) P(getting three heads) Number of times three heads appeared = P(E1) = total number of trials = 21/175 = 0.12 (ii) P(getting two heads) Number of times two heads appeared = P(E2) = total number of trials = 56/175 = 0.32 (iii) P(getting one head) Number of times one head appeared = P(E3) = total number of trials = 63/175 = 0.36 (iv) P(getting zero head) Number of times zero head appeared = P(E4) = total number of trials = 35/175 = 0.20 Note: Remember when 3 coins are tossed randomly, the only possible outcomes are E2, E3, E4 and P(E1) + P(E2) + P(E3) + P(E4) = (0.12 + 0.32 + 0.36 + 0.20) = 1 |
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| 13270. |
Find the value of 2P(2)+5, if p(x) has (x-2) as its factor |
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Answer» <P>Answer: 5 Step-by-step EXPLANATION: p(2)=0 2P(2)+5=5 |
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| 13271. |
Maths simplificatio. can any one help |
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Answer» THE ANSWER IS IN THE PICTURE. APPROXIMATELY IT WOULD BE (C) 455 |
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| 13272. |
14 /15 X= 1please help |
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Answer» Answer: 14/15x=1 14x=15 X=15/14 Step-by-step explanation: Follow me Mark me BRIANLIEST |
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| 13273. |
रखने परP() = x-2IN -P1)oo P (1) |
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| 13274. |
The correct numeral for 6 ten-thousand 5 thousand 0 hunder tens 0 ones is |
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| 13276. |
(5,25,125,625) write in set builder form |
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Answer» Thank u for following me Step-by-step EXPLANATION: So so sweet of u THX |
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| 13277. |
64^⅓+0.008^⅓+0.027^⅓ |
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Answer» 2.5 Step-by-step explanation: 64^1/3 +0.008^1/3 +0.027^1/3 = {(2)^3}^1/3 + {(0.2)^3}^1/3 + {(0.3)^3}^1/3 =(2)^3×1/3 + (0.2)^3×^1/3 + (0.3)^3×^1/3 =2 + 0.2 +0.3 =2+0.5 =2.5 |
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| 13278. |
In thegivenfigure, AB is parallel to CD. Find x. |
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| 13279. |
Р-where p, q are integers,q=0aQ2. Express the following in the form of(i) 0.327 (ii) 4.38 (iii) 1.314bar on 27 bar on 8bar on 314 |
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| 13280. |
Find the area of rectangular park which is 125/3m long and 146/8m broad |
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Answer» Your answer is 36,500 it can HELP you |
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| 13281. |
O inspector ke dikt h Ter 30 answer delete kar ddiye |
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| 13282. |
Divide 5x^3-x^3+6 by x-4 |
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Answer» Answer: HOPE the above pic GIVES u ur desired answer Step-by-step explanation: HOPE THIS WILL HELP YOU:) |
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| 13284. |
13. A sum of 800 is in the form of denominations of 10 and 20. If the total number oinotes is 50, find the number of notes of each type. |
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Answer» Answer: let Rs 10=x Let Rs21=y x+y=50-(1) 10x+120y=800 x+2y=80-(2) SUBTRACTING equation 1 from equation 2 y=30 x=20 20 NOTES of 10 Rs 30 notes of 20 Rs. Step-by-step explanation: |
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| 13285. |
(5/11×33/-25)-(7/13×11/35×-26/33) |
Answer» The answer is -0.466.... |
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| 13286. |
6. A, B और C अलग—अलग किसी काम को क्रमश: 5 दिन, 10 दिन और 20 दिन में पूरा करते हैं। यदिकाम की मजदूरी 2100 रू हो तो बताइये प्रत्येक को कितनी मजदूरी मिली।If A, B and C can complete a work in 5, 10, 20 days respectively and if wage forthis work is 2100 rupees then find how much money each of them get. |
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Answer» Answer: 2400 plz MARK as the BRAINLIEST |
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| 13287. |
If ∆abc ~∆pqr and ab:pq=2:3,then find a(∆abc)\a(∆pqr) =? |
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Answer» Step-by-step EXPLANATION: same as RATIO of SIDES, HOPE you UNDERSTAND |
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| 13288. |
The pair of equations 3x+2y=8 and 2x + y =5 has a unique solution then the value of x and y are(a) x=1, y=2 (b) x=2, y=1 (c) x=3, y= 1 (d) x=1, y= 3 |
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Answer» Answer: b) x=2 ,y=1 Step-by-step EXPLANATION: let 3x+2y=8 is ist EQUATION and 2x+y=5 is 2nd equation multiply 2nd equation by 2 4x+2y=10 -3RD equation subtracting ist from 3rd we have 4x+2y=10 -(3x+2y=8) x =2 3(2)+2y=8 6+2y =8 2y=2 y=1 |
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| 13289. |
if a b c d e f are congruent line passing through the point P is that we bisect angle ATC of in the city is equal to 40 degree find angle BPC Angle B and angle and APF |
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Answer» Step-by-step explanation: May your FAMILY relatives and companions maybe happy and SAFE from the Pandamic situation and COVID-19 O will definitely answer to you question but WAIT till 11:30am because I am writing it on a page so it will need some time.. I will try my BEST to answer to your question fast.. If find this helpful please follow me. thanks and Vote.. And Mark as BRAINLEIST...
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| 13290. |
The value of 0.2bar in the form of p upon q where p and q are integers and q is not equals to zero |
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| 13291. |
The reciprocal ratio of 5:8 is1. 5:82. 8:53. 5:104. none |
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Answer» Answer: 8:5 hope this HELPS! |
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| 13292. |
[(2) -1 + (4) -1 + (3) -1]-1 |
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Answer» May your family relatives and companions maybe happy and safe from the Pandamic SITUATION and COVID-19 If find this HELPFUL please follow me. thanks and VOTE.. And Mark as BRAINLEIST.. |
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| 13293. |
The number of rational number between root 3 and root 5 is |
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Answer» Answer: There are INFINITELY MANY RATIONAL numbers between √3 and √5 Step-by-step explanation: |
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| 13294. |
The correct numeral for 6 ten-thousand 5 thousand 0 hunder tens 0 ones is answer kya hai |
Answer»
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| 13295. |
Write the additive inverse of -12by -13 |
Answer» 12/13....................,. |
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| 13297. |
Find the greatest number which divides 121, 183, 305 and leaves the remainder 1,3 and 5 respectively |
Answer» I have SOLVE the PROBLEM. HOPE it HELPS. |
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| 13298. |
9x^2-9(a+b)x+(2a^2+5ab+2b^2)=0 |
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Answer» a+b-5,2a+2b+1 Step-by-step EXPLANATION: that is answer OK |
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| 13299. |
-4/3(3/5)+5/2-1/5(5/3) |
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Answer» Step-by-step EXPLANATION: |
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| 13300. |
(X - 3) (2 X + 1 )= x(-2 X + 5) (is quadratic equation or not |
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