This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 14502. |
If (a sin(x+a)=b sin(x-a)) then how can i prove that ((a+b)tan x+(a-b)sin a)=0 |
|
Answer» Answer: Equating length of line segments PQ1 and RT, it is proven that sin(A+B) = sin A cos B + cos A sin B. ... sin(A+B) proof in unit-circle FORM from nubtrek Q1 is (sinB, cosB) PQ1 = 2–2sinAcosB-2cosAsinB. RT = 2–2sin(A+B) PQ1 = RT PROVES the required identity. |
|
| 14503. |
The value oThecommonnees 12,21,25..16, 21, 26,findnumber of the Termseran-488 is 4% ThenKntic equal to what? to Find 2, |
|
Answer» ñnnnnnnnnkkkkkkkkkkkkkkkkkkkkkkkkkkkkk |
|
| 14504. |
Example 1 Discuss the continuity of the function f give(-2,4)x, if x 20f(x) =x?, if x < 0SolutionClearly the function is defined at |
|
Answer»
|
|
| 14505. |
Of the sequation 48 m 12x²+ m²=0(m) o) has town read sais, whichare in AP. Then find the value of me |
|
Answer» Answer: just solve this QUADRATIC EQUATIONS by formula method u GET urs answer perfectly |
|
| 14506. |
Solve the equation x /2 +2y /3=-1 & x-y/3 =3 by substitution method. |
|
Answer» Step-by-step explanation: |
|
| 14507. |
Insert tive rational number between 6.0 and 6.1 |
|
Answer» there are INFINITE RATIONAL no.s between TWO NUMBERS.......... |
|
| 14508. |
Design and compute Rc Lag Compensator for an overdamped system having a gain as 19,steady state error60dB and phase margin >80? |
|
Answer» Answer: Hi Dear....here is your answer..... given, ZEROES are 1/2+2√3 and 1/2-2√3 sum of zeroes = 1/2+2√3 + 1/2-2√3 = 1/2 + 1/2 = 1 product of zeroes = 1/2+2√3 x 1/2-2√3 = [ 1/2 ] ² - [ 2√3 ]² = 1/4 - 48 / 4 = -47 /4 Quadratic equation x² - [ sum of zeroes ]x + product of zeroes =x² - x + -47/4........ |
|
| 14509. |
PLEASE PLEASE SOLVE THIS FAST (ONLY SOLVE IT IF YOU KNOW HOW TO DO IT) |
|
Answer» THE CORRECT OPTION IS D....... |
|
| 14510. |
1. Express each of the following numbers as a product of its prime factors.(i) 140(ii) 156 (ii) 3825 (iv) 5005 (v) 7429in LCM method |
|
Answer» Answer: it is very EASY u can do with the example. Step-by-step explanation: please don't FORGET to THANK and follow me . i will also follow u back!! |
|
| 14511. |
Why is the use of sustainability important that you may have observed around you? |
|
Answer» The ISSUE of sustainability is important for development because if the natural RESOURCES are not used carefully, they may not be available for FUTURE generations. The DEPLETING resources of a country may ultimately result in a lack of development of the country HOPE IT HELPS U.... PLEASE MARK AS BRAILIAST ANSWER |
|
| 14512. |
4×4+4++4+4+4+4+4+4+4+4++44++4+4+4+4 |
|
Answer» 400 is CORRECT answer than MARK as BRAINLLIST, |
|
| 14513. |
Find the mode of the following distribution 3Classes :20-40 40-60 60 - 8060 - 80 80-10081012164Frequency:16 |
|
Answer»
|
|
| 14514. |
PLEASE PLEASE SOLVE THIS FAST AND SHOW ALL WORKING OUTS (ONLY SOLVE IT IF YOU KNOW HOW TO DO IT) |
|
Answer» HI mate here is your ANSWER . . . HOPE it helped❤^_^✌ |
|
| 14515. |
X^3+2x^2-x-2 using factor method factorise each of the following polynomial |
Answer» _______________________Question:-x^3+2x^2-x-2 using factor method FACTORISE each of the following polynomial______________________Solution:-(x-1)(x+1)(x-2)EXPLANATION:-x^3-2x^2-x+2=x^3-x-2x^2+2Grouping the 1^(st 2 terms together and the 2^(nd 2 together)=x(x^2-1)-2(x^2-1)=(x^2-1)(x-2)Using the identity: a^2-b^2=(a+b)(a-b)=(x^2-1^2)(x-2)=(x-1)(x+1)(x-2). For factorizing other CUBIC polynomials, the following method can be used:First, by trial and error method, you can find one factor as follows:x^3-2x^2-x+2When REPLACING 1,=1^3-2xx1^2-1+2.=>cancel1-cancel2-cancel1+cancelled=>0So, we GET (x-1) as factor.Then by long division, divide (x-1) by (x^3-2x^2-x+2)You get=>(x-1)(x^2-x-2)Then you have to factorize it by splitting the middle term method.=>(x-1)[x^2+x-2x-2]=>(x-1)[x(x+1)-2(x+1)]=>(x-1)(x+1)(x-2)~Hope this helps! :) |
|
| 14516. |
if c,d are the rootsof (x-a) (x-b) -k=0,then the roots of (x-c) (x-d+k=0are A: b, c. B:a,b. C,:a, c. D:a,d |
|
Answer» Since α,β and γ are the roots of the equation(x−a)(x−b)(x−c)−d=0. So we have α+β+γ=a+b+c ...(1) αβ+βγ+γα=ab+bc+ca ...(2) αβγ=abc+d ...(3) SIMILARLY, for the equation (x−α)(x−β)(x−γ)+d=0, we have α+β+γ=a+b+c (from (1)) αβ+βγ+γα=ab+bc+ca (from (2)) And αβγ−d=abc (from (3)) THEREFORE CLEARLY a,b and c will be the roots of the equation (x−α)(x−β)(x−γ)+d=0. |
|
| 14517. |
Gabriella filled her fishbowl with 4 cups of water. How many fluid ounces did she put in the fishbowl? 32 ounces 36 ounces 48 ounces 54 ounces |
|
Answer» 32 FLUID ounces. |
|
| 14518. |
9. A pair of die is thrown. Find the probability of getting a sum of 10 or more, if 5 appears on the first die.Hint: Favourable cases are (5,5) and (5, 6)] |
|
Answer» Answer: 1/18 if two dice are rolled , out comes of the number on them can be EXPRESSED as FOLLOWS: (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), (5,1),(5,2),(5,3),(5,4), (5,5),(5,6), (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) TOTAL number of out comes = n(S) = 6×6 = 36 Let the event that getting a sum of 10 or more , if 5 appears on the first die be E Possible OUTCOMES to E = (5,5) and (5,6). Number of possible outcomes to 'E' = n(E)=2 2/36 1/18 this is your answer ✔️✔️ |
|
| 14519. |
Tom run three times around a square field he covered a distance of 12 km what is the area of the field |
|
Answer» Answer: let the 1 ROUND of sqare field = X three time around = 3x according to question 3x= 12 x = 4 let it one side be y 4y= 4 y= 1 AREA is side ×side area = 1×1 area = 1 |
|
| 14520. |
A hunter is standing 350 feet away and fired a bullet straight up at a bird on a tree at a rate of 15 ft/sec. At what rate is the distance between the hunter and the bullet increasing i) 20 seconds after liftoff? ii) 1 minute after liftoff? |
|
Answer» Step-by-step explanation: |
|
| 14521. |
the two zeroes of a quaratic polynomial -4and -6find the sum and products of the zero. what is the values of coefficients b |
|
Answer» Answer: b= 10, C=24 Step-by-step explanation: SUM of zeroes of quadratic polynomial = -COEFFICIENT of x product of zeroes of quadratic polynomial = CONSTANT term so for p(x) = ax^2 + bx + c => -4 + -6 = - b => b= 10 and => -4 x -6 = c => c = 24 therefore p(x) = ax^2-10x+24 |
|
| 14522. |
The cash price for furniture for all rooms of a three-bed-room house is $ 3851. The furniture can be financed by paying $ 500 down and $ 86 per month for 48 months. However, instead of making the thirty minus sixth payment the borrower decides to pay the remaining balance and terminate the loan for the furniture Table 5 Annual Percentage Rate (APR) for Monthly Payment Loans Number of Monthly Payments (n) Annual Percentage Rate (APR) 10.0% 10.5% 11.0% 11.5% 12.0% 12.5% 13.0% Finance Charge per $100 of Amount Financed (h) 6 $2.94 $3.08 $3.23 $3.38 $3.53 $3.68 $3.83 12 5.50 5.78 6.06 6.34 6.62 6.90 7.18 18 8.10 8.52 8.93 9.35 9.77 10.19 10.61 36 16.16 17.01 17.86 18.71 19.57 20.43 21.30 48 21.74 22.90 24.06 25.23 26.40 27.58 28.77 60 27.48 28.96 30.45 31.96 33.47 34.99 36.52 |
|
Answer» Answer: |
|
| 14523. |
& A spinner is made from a regular octagon. It is labelled with three As,two Bs and three Cs. Each of the sides is equally likely to be resting onthe table when it stops spinning. Calculate(a) P(A resting on the table)(b) P(B resting on the table)(c) P(not Cresting on the table) |
| Answer» | |
| 14524. |
वह न्यूनतम संख्या क्या है जो 1936 में से घटायी जा सकती हो ताकि 9,10,15 सेविभाजित किए जाने पर प्रत्येक बार शेषफल 7 हो?A)93 B)46 C)76 b)39 |
|
Answer» Answer: can you PLEASE tell me in ENGLISH please Step-by-step EXPLANATION: |
|
| 14525. |
Match each sampling method with an example using that approach |
|
Answer» eggajfVbagwuwiwisushsgisjwjbwbsbshvzvssshavaavvsjsiaiwhvwvavsbbzbzvavababzbhs |
|
| 14527. |
In an acute angled triangle ABC, AD is the median then prove that AD² = AB²/ 2 + AC²/ 2 - BC²/ 4 |
Answer» Step-by-step explanation:GivenAn ACUTE triangle ABC with AD as MEDIAN To proveAD² = AB²/ 2 + AC²/ 2 - BC²/ 4 ConstructionDraw AE perpendicular to BC. ProofIn triangle ABE, by Pythagoras Theorem AB² = BE² + AE² ........(1) In triangle ACE, by Pythagoras Theorem AC² = CE² + AE²..........(2) In triangle AED, by Pythagoras Theorem AD² = AE² + ED²..........(3) Also in triangle ABC EC - BE = (ED + DC) - (BD - ED) = ED + BD - BD + ED ( SINCE AD is median BD = DC) = 2ED or EC - BE = 2ED ,........(4) Adding (1) and (2) we get AB² +AC² = BE² + EC² + 2AE² or AE² = (AB² +AC² - BE² - EC²)/2 Putting value of AE² in (3) we get AD² = (AB² +AC² - BE² - EC²)/2 + ED² or AD² = AB²/2 + AC²/2 -BE²/2 - EC²/2 + (EC-BE)²/4 (Using equation (4) ) or AD² = AB²/2 + AC²/2 -BE²/2 - EC²/2 + (BE² + EC - 2EC.BE)/4 or AD² = AB²/2 + AC²/2 -(1/4)*(2BE² + 2EC² - BE² - EC + 2EC.BE) or AD² = AB²/2 + AC²/2 -(1/4)*(BE² + EC² + 2EC.BE) or AD² = AB²/2 + AC²/2 -(1/4)*(BE + EC)² or AD² = AB²/2 + AC²/2 -(1/4)*(BC)² or AD² = AB²/2 + AC²/2 -(BC)²/4 Hence PROVED. |
|
| 14528. |
The total mass of 25 candy bars is 2 kilograms. What is the mass of each candy bar in grams? 75 grams 80 grams 90 grams 95 grams |
|
Answer» Answer: 80 grams.Step-by-step explanation: 1 kg = 1000 gm So, 2 kg = 2000 gm Now, ATQ, we have 25 CANDY = 2000 gm 1 candy = 2000/25 1 candy = 80 gm So, MASS of each candy = 80 gm . |
|
| 14529. |
the sum of two numbers is -18 if the first number is 10 which equation represents this situation and what is the second number ? |
|
Answer» Answer: Step-by-step EXPLANATION: The sum of 2 numbers is -18. And ONE of the numbers is 10. X + 10 = -18 So X = -18 + (-10) X = -28 Option B is CORRECT. |
|
| 14531. |
HELP PLEASE!! PLEASE LOOK AT THE SCREEN SHOT( attachment) |
|
Answer» Step-by-step EXPLANATION: |
|
| 14532. |
Help me please, ive ben getting wrong answers all this time, I really need it right now! |
|
Answer» no................... |
|
| 14534. |
The value of√3 to first three decimal places is? show in step by step explain |
|
Answer» The ANSWER is 1.732, we'll have to PROCEED with LONG DIVISION METHOD for this answer |
|
| 14535. |
The value of√3 to first three decimal places is |
|
Answer» Answer: 1.732 Step-by-step EXPLANATION: |
|
| 14537. |
The ratio 5/3:9/4 is |
|
Answer» Answer: 20/27 or 20:27 Step-by-step EXPLANATION: =5/3/9/4 =(5/3)*(4/9) =20/27 |
|
| 14538. |
PROVE THE IDENTITIES A) sin A/1+cos A≡1-cos A/sin A B) cos A/1- tan A + sin A/1-cot A ≡sin A + cos A |
|
Answer» Step-by-step EXPLANATION: A) LHS = = RHS Hence PROVED B) LHS = = RHS Hence Proved |
|
| 14539. |
HELP HELP HELP HELP!! |
|
Answer» Answer: The co- ordinate of B is (0, 3). Step-by-step EXPLANATION: It is given that AC = 6AB or AB + BC = 6AB or BC = 6AB - AB or BC = 5 AB or AB/ BC = 1/5 Hence B divides AC internally in the ratio 1:5 Co- ordinate of a point which divides the line joining (x₁, y₁) and (x₂, y₂) internally in the ratio m:n is given by (x,y) = ( (mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n) ) Hence, co-ordinate of B is given by
= (0, 3) |
|
| 14540. |
Whats is 7^8 . I want to understand the basics of power maths |
|
Answer» Answer: 5764801 Step-by-step EXPLANATION: |
|
| 14541. |
Badi & choti copy ka ankit rs. 10rs. &15rs. Hai. Ek chatra 5 darjan choti copy & 10 darjan bdi copy 5℅ ki kul rashi per kharidta hai.choot ki rashi gyat kare. |
|
Answer» Step-by-step explanation: |
|
| 14542. |
PLEASE READ THE QUESTION AND HELP ME!! |
|
Answer» ARROW c Step-by-step EXPLANATION: |
|
| 14545. |
Solve the following equations using an algebraic method. 4x+3y=7 3x-2y=18 |
|
Answer» (4, - 3) Step-by-step EXPLANATION: Check the answer, 4(4) + 3(- 3) = 7 16 - 9 = 7 7 = 7 3(4) - 2(- 3) = 18 12 + 6 = 18 18 = 18 |
|
| 14546. |
Solve the question 8 part 1 and two which I have marked with blue pencil. |
|
Answer» Step-by-step explanation: 1 ANSWER is {1,3,5,7,9} 2 answer is {1,3,5,7,9} if it is not help SORRY for my answer |
|
| 14547. |
Class 10 lesson 3 ka question n 1 and 2 ka ans dijiye ( no चीटिंग ) fast |
|
Answer» where is QUESTION??????????? |
|
| 14548. |
A store clerk is stocking the shelves. He places on the shelf a box of cereal that weighs 850 grams, a box of granola bars that weighs 385 grams, and a box of crackers that weighs 435 grams. What is the total weight in kilograms? 16.70 kilograms 1.670 kilograms 167 kilograms 1,670 kilograms |
|
Answer» Answer: Step-by-step explanation: A box of granola bars - 385 gm A box of crackers - 435 gm Total WEIGHT of all items = 850 + 385 + 435 = 1670 gm 1 kg = 1000 gm So total weight of items = 1670 ÷ 1000 = 1.670 kg |
|
| 14549. |
6^x+\frac{1}{6^x}=6\frac{1}{6} this is urgent |
|
Answer» Step-by-step EXPLANATION: |
|
| 14550. |
4x² - x + 3(x? 1) (x - 1)dx |
|
Answer» 4x^2-x+3 |
|