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ANSWER:

BOT PARENCHYMA and COLLENCHYMA are LIVING

ANSWER:

NAY ch OI NAH kyahh pyarr kathnai cjuytjfh kuth kuthi haay

Step-by-step EXPLANATION:

by ELECTRONIC COMMUNICATIONS

Step-by-step EXPLANATION:

+ , - ,× , ÷

OPERATIONS of MATHEMATICS

ANSWER:

HEY bro you can just tell how MANY book he borrowed from you.

Step-by-step explanation:

Because he has some book

Step-by-step explanation:

• BASE should be GREATER than 0
• it cannot be 0
• it always positive
• it GIVES positive values OK friend

Answer:

392-("=64+$(=94+',6-'6

ANSWER:

V8 + 2 (V15)

V8 + V30

V38 is the answer.

ANSWER:

Step-by-step explanation:

22/7

ANSWER:

i cannot UNDERSTAND this QUESTION answer

Answer:

ar (rhombus) = 96 square units.

Step-by-step explanation:

____________________________________

____________________________________

LET,

Side of rhombus = S

then,

perimeter of rhombus = 40

4 S = 40

S = 10 units

____________________________________

Let,

Diagonal AC = 16 units

then,

∵ diagonals of rhombus bisect each other perpendicularly

∴ OA = 8 units ;

∠ AOD = 90°

and , Side = AD = 10 units

____________________________________

Using Pythagoras theorem in Δ AOD

OA² + OD² = AD²

( 8 )² + OD² = (10)²

OD² = 100 - 64

OD² = 36

OD = 6 units

____________________________________

Now,

BD = 2 (OD) = 2 (6) = 12 units

so,

we have Diagonals of rhombus as

d₁ = 16 units and d₂ = 12 units

therefore,

ar (rhombus) = 1/2 × d₁ × d₂

ar (rhombus) = 1/2 × 16 × 12

ar (rhombus) = 96 square units.

____________________________________

ANSWER:

This MEANS that y is DIRECTLY PROPORTIONAL to X

Step-by-step explanation:

The SET of NUMBERS are:

5,10,15,20,25,30,35,40,45,50,.....

HOPE this helps.

please mark as Brainliest.

ANSWER:

it is CALLED as vowel

Step-by-step explanation:

please MARK my answer as BRANLIST

Answer:

-7/-42 can be written as -7 /42 because negative SIGN is CANCELLED

ANSWER:

Step-by-step EXPLANATION:

Let complete and supplement both be x

So x+x=90

2x=90

X=45

Measure of the angle required is 45 DEGREE

ANSWER:

MATHS scanneryapp DOWNLOAD

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Step-by-step EXPLANATION:

I HOPE it HELPS you!!!!!......

Answer:

m = - 1 ,

X = - 2

and

y = 5

HOPE this would help you !!!!!!!!!

Step-by-step EXPLANATION:

OK i HOPE it HELP you

THANK

THE GIVEN POINT LIES IN 4 th QUADRANT.

PLEASE MARK AS BRAINLIEST.

:-)

Step-by-step EXPLANATION:

I HELPED you so it's your to THANKS me

ANSWER:

The STANDARD FORM of 28/70 is 2/5 .

Step-by-step explanation:

USE FORMULA method u GET URS answer perfectly

ANSWER:

answer for the GIVEN PROBLEM is given

ANSWER:

NOTHING i don't UNDERSTAND QUESTION.

ANSWER:

x=2,-5/16

Step-by-step EXPLANATION:

This answer may HELP you SEE the attachment to see explanation

ANSWER:

do you have MONEY

Step-by-step EXPLANATION:

or you are begger

who COLLECT money by beggingg

Answer:

5

if BISECTOR AE of exterior vertical ANGLE DAE of TRIANGLE abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles is isosceles

if bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles is isosceles

if bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles

4√3x^2+5x-2√3

roots = (-B +-√b^2 - 4ac) / 2a

roots = (-5 +-√(5)^2-4(4√3)(-2√3))/2(4√3)

roots = (-5 +-√25 + 96) / (8√3)

roots = (-5 +-√121) / (8√3)

roots = (-5 +-11) / (8√3)

roots = (-5 + 11) / (8√3) and (-5 -11) / (8√3)

roots = 6 / (8√3) and -16 / (8√3)

roots = 3√3 and -2√3/3

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Answer:

Step-by-step EXPLANATION:

y²-16 y+63=0

y²-7 y-9 y+63=0

y(y-7)-9(y-7)=0

(y-7)(y-9)=0

y=7,9 are roots of this equation

Please MARK me as BRAINLIEST

ANSWER:

what are you ASKING THANKYOU thankyou thankyou

At what times of the day do the hour and minute hands of an analog clock perfectly align?

At first glance this might seem like a trivial question, then you realize that the hour hand moves smoothly and continuously around the dial (albeit at a slower pace than the minute hand), and does not snap to each quantized hour position on each hour. This complicates things a little, but not too much. (The answers are not 1:05, 2:10, 3:15 …)

It’s pretty CLEAR that the hands both align when it’s exactly midnight (and midday). When is the next time?

It’s not 1:05, but a little bit past because, by the time the minute hand is also at the 1 o’clock position, the hour hand will have progressed slightly.

The minute hand spins around the dial twelve times as fast as the hour hand (it completes one revolution in an hour whilst the hour hand moves one hour, which is 1/12th of the clock face).

In T hours, the minute hand completes T revolutions. In the same amount of time, the hour hand completes the fraction T/12 revolutions. Using degrees, we can see that the minute hand moves at 360° per hour, and the hour hand (360°/12) = 30° per hour.

Below is a graph showing the angle (in degrees) for both hands for values of T from 0 to 12. Where the lines intersect (an example is shown with the red circle), is where the hands will coincide.

This happens at 11 different locations between midnight and (just before) midday, then repeated again ANOTHER 11 times in the afternoon.

We can calculate the exact times by looking for the times when the angle between the two hands is zero.

Let's define the angles HT, MT to be the angles (in degrees) of the hands (from 12 o'clock position), after time T (in hours).

HT = 30T

MT = 360T

For the hands to be aligned, the difference between the hour and minute hand needs to be zero (after an arbitrary number of rotations), where n is an arbitrary (integer) number of rotations.

MT - HT = 360 × n

360T - 30T = 330T = 360n

11T=12n

We can find the times, by inserting in n=0,1,2 …

T=12n/11

The hands overlap every (12/11) hour. Here are the 22 results (rounded to the nearest second):

12:00:00 AM 12:00:00 PM

1:05:27 AM 1:05:27 PM

2:10:55 AM 2:10:55 PM

3:16:22 AM 3:16:22 PM

4:21:49 AM 4:21:49 PM

5:27:16 AM 5:27:16 PM

6:32:44 AM 6:32:44 PM

7:38:11 AM 7:38:11 PM

8:43:38 AM 8:43:38 PM

9:49:05 AM 9:49:05 PM

10:54:33 AM 10:54:33 PM

However, the question I want to ask is the next logical progression of this problem. What if we add a second hand?

The hour hand, Minute hand, Second hand …

Image: Mark Turnauckas  

At what times of the day do the hour, minute, and second hands all line- up?

As before, let's define the angles HT, MT, ST to be the angles (in degrees) of the hands (from 12 o'clock position), after time T (in hours).

HT = 30T

MT = 360T

ST = 360T × 60 = 21600T

For the hands to be aligned, the difference between pairs angles needs to be zero (after an arbitrary number of rotations).

MT - HT = 360 × n

ST - HT = 360 × m

(Where n and m are integer coefficients). Combining the equations we get:

360T - 30T = 330T = 360n

21600T - 30T = 21570T = 360m

These simplify:

11T=12n

719T=12m

Giving the result:

719n=11m

Both 11 and 719 are Prime and have no common factors. So (other than the trivial case of n=m=0), as n MUST be a multiple of 11, say n = 11x, for some integer x. Then m = 719x, and T = 12x. That SHOWS that the only time when this happens is after an integer multiple of 12 hours, that is, at 12 o'clock.

All the places where the hour and minute hands align (angle difference being a multiple of 360°) are different from all the places the hour and the second hands align (other than 12:00).

What this means is there that, other than midnight (and midday), there are no other times when all three hands have exactly the same angle.

(This answer MAKES sense when you think about it, because, if all three were to the line-up, it has to happen when two line-ups as well, so it would have to at one of the 11 times calculated earlier with just the hour and minute hands, and none of these correspond to positions of where the second hand could be).

How close can we get them?

A quick search of the internet reveals that Dr. Rob, from The Math Forum, also looked at this problem and found the closest he could get all three hands is at the time 5:27:27.3 when all the hands are within a 1.0014 degree sector. He goes on to remind us that this is probably still visible to the naked eye as clock hands are thin, and the angle between second marks is 6°

Step-by-step EXPLANATION:

i hopeyou it HELP OK all the BEST

Step-by-step EXPLANATION:

GIVEN set M={p,q,R,s,t,u}

No.Of elements in the given set = 6

Cardinals number of the set M=6

therefore N(M)=6

HME kaise PTA chlega QUESTION DALIYE na

Answer:

MUJHE nahi pata

Step-by-step explanation:

maths guide lele THIK hai

STORE jakar

Answer:

     13  | 26 , 91

           |  2    , 7

Lcm = 13 x 2 x 7

       =182

Hcf = 13

Hope this helps you. If yes PLEASE MARK me the brainliest

ANSWER:

235.2 is answer of this QUESTION .PLZ MARKED it BRAINLIEST answer

Step-by-step EXPLANATION:

x-y-z=?

GIVE the QUESTION CLEARLY

♕ ♕

X = 2✔︎ and Y = 2✔︎

SOLUTION :-

5x - y = 8 .....i)

7x +4y =22....ii)

multiplying equation i) by 4

20x - 4y = 32....iii)

add EQUATION iii) nd equation ii)

20x - 4y = 32

+

7x + 4y = 22

27x = 54

x = 2

X = 2 ✅

puting VALUE of x = 2 in equation i)

5x - y = 8

5×2 - y =8

10 - y = 8

- y = 8 -10

- y = -2

y = 2

y = 2✅

‌

Answer:

18

Step-by-step EXPLANATION:

PUTTING x=3

3×3(3-1)(3-2)

9*2*1=18

Given :  triangles ABC  and CDE have the same areas.  F  is  the point of intersection of AC  and DE.  AB is parallel  to DE. AB = 9 cm and DF = 7.5 cm.

To Find : the length of EF in cm.​

Solution:

Let say AREA of  Δ ABC & ΔCDE =  A

AB ║ DE

=> AB ║ EF

=> Δ ABC ≈ Δ FEC

=>  Area of ΔABC / Area of ΔFEC   =   ( AB/ EF)²

Let say FE = X    6 cm

=>  A /  Area of ΔFEC   =   ( 9/ x)²

=> Area of ΔFEC    = Ax² / 81

in Δ  CDE

Area  of  Δ FEC  = ( FE / DE  ) Area  of  Δ CDE

=>  Area  of  Δ FEC  = ( x / (x +7.5) )  * A

=>  Ax² / 81=  ( x / (x +7.5) )  * A

=>  x(x + 7.5)  =  81

=> x² + 7.5x - 81 = 0

=> x² + 13.5x - 6x - 81 = 0

=> x(x + 13.5) - 6(x + 13.5) = 0

=> (x - 6)(x + 13.5) = 0

=> x = 6       ( x = - 13.5 not possible )

Length of FE = 6 cm

Learn more:

perimeters of two similar triangles are 30cm and 40CM respectively ...

brainly.in/question/18128501

If ∆ABC is similar to ∆DEF web that BC = 4 cm, EF = 7 cm sod area of ...

brainly.in/question/8695382

Step-by-step EXPLANATION:

MAKE SURE that all words are SPELLED correctly.

ANSWER:

a)1 WILL BE THE ANSWER..

Answer:

MITIGATION is the EFFORT to reduce loss of life and property by lessening the impact of disasters. In order for mitigation to be effective we need to take action now—before the NEXT disaster—to reduce human and financial consequences later (analyzing risk, reducing risk, and INSURING against risk)...

hope it helps SASS :)

ANSWER:

MISSING series

Step-by-step EXPLANATION:

The answer is 147

Option A

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