332354 + Interview Questions in Secondary School in Math Page 381 InterviewSolution

19001.	Cartoon of powdered milk contains 24 teams the weight of each 3 of powder milk is 0.45 kilogram find the weight of 24 of powdered milk
Answer» Answer: 3.6 kilogram Step-by-step explanation: 24/3 8*0.45

19001.

Cartoon of powdered milk contains 24 teams the weight of each 3 of powder milk is 0.45 kilogram find the weight of 24 of powdered milk

Answer»

Answer:

3.6 kilogram

Step-by-step explanation:

24/3

8*0.45

Discussion

19002.	Riya and monu ate 5/6 of 2pizzas.how much pizza did they eat altogether
Answer» Answer: 5/3 Step-by-step explanation: 5/3 *2 10/6 and then SIMPLIFY

19002.

Riya and monu ate 5/6 of 2pizzas.how much pizza did they eat altogether

Answer»

Answer:

5/3

Step-by-step explanation:

5/3 *2

10/6

and then SIMPLIFY

Discussion

19003.	Two different dice are rolled together. Find the probability of getting:(i) The sum of numbers on two dice to be 5.(ii) Even numbers on both dice(iii) A number greater than 3 on each die(iv) A total of 6 or 7 of the numbers on two dice
Answer» We're given that two dice are rolled together at the same time. Step 1: List out the possible outcomes. $\begin{tabular}{\| c \| c \| c \| c \| c \| c \| c \|}\cline{1-7}& \sf 1 & \sf <klux>2</klux> & \sf 3 & \sf 4 & \sf 5 & \sf 6 \\\cline{1-7}\sf \ 1 \ & (1,1) & (1,2) & (1,3) & (1,4) & (1,5) & (1,6)\\\sf 2 & (2,1) & (2,2) & (2,3) & (2,4) & (2,5) & (2,6)\\\sf 3 & (3,1) & (3,2) & (3,3) & (3,4) & (3,5) & (3,6)\\\sf 4 & (4,1) & (4,2) & (4,3) & (4,4) & (4,5) & (4,6)\\\sf 5 & (5,1) & (5,2) & (5,3) & (5,4) & (5,5) & (5,6)\\\sf 6 & (6,1) & (6,2) & (6,3) & (6,4) & (6,5) & (6,6)\\ \cline{1-7}\end{tabular}$ Therefore, the possible outcomes are; (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) ∴ TOTAL Number of outcomes: 36 ----------------------- Question 1: The sum of numbers on two dice to be 5. Let's find the no: of favourable outcomes, i.e, the outcomes that will GIVE 5 as the sum when the numbers on top of the dice are added. (The outcomes in bold are the favourable outcomes) (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) ∴ Favourable outcomes: (1,4) (2,3) (3,2) (4,1) ∴ No: of favourable outcomes: 4 Let "E" be the probability of this event. $\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$ $\sf \Longrightarrow Probability\Big(E\Big) = \dfrac{4}{36}$ $\sf \Longrightarrow Probability\Big(E\Big) = \dfrac{1}{9}$ ----------------------- Question 2: Even numbers on both dice. Let's find the no: of favourable outcomes, i.e, the outcomes that have even numbers displayed on both the dice. (The outcomes in bold are the favourable outcomes) (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) ∴ Favourable outcomes: (2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6) ∴ No: of favourable outcomes: 9 Let "F" be the probability of this event. $\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$ $\sf \Longrightarrow Probability\Big(F\Big) = \dfrac{9}{36}$ $\sf \Longrightarrow Probability\Big(F\Big) = \dfrac{1}{4}$ ----------------------- Question 3: A number greater than 3 on each dice. Let's find the no: of favourable outcomes, i.e, the outcomes that have both the numbers displayed greater than 3. (The outcomes in bold are the favourable outcomes) (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) ∴ Favourable outcomes: (4,4) (4,5) (4,6) (5,4) (5,5) (5,6) (6,4) (6,5) (6,6) ∴ No: of favourable outcomes: 9 Let "G" be the probability of this event. $\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$ $\sf \Longrightarrow Probability\Big(G\Big) = \dfrac{9}{36}$ $\sf \Longrightarrow Probability\Big(G\Big) = \dfrac{1}{4}$ ----------------------- Question 4: A total of 6 or 7 of the numbers on two dice. Let's find the no: of favourable outcomes, i.e, the outcomes that give us a total of 6 or 7 when added. (The outcomes in bold are the favourable outcomes) (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) ∴ Favourable outcomes: (1,5) (1,6) (2,4) (2,5) (3,3) (3,4) (4,2) (4,3) (5,1) (5,2) (6,1) ∴ No: of favourable outcomes: 11 Let "H" be the probability of this event. $\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$ $\sf \Longrightarrow Probability\Big(H\Big) = \dfrac{11}{36}$ ----------------------- Final answers: (i) 1/9 (ii) 1/4 (iii) 1/4 (iv) 11/36

19003.

Two different dice are rolled together. Find the probability of getting:(i) The sum of numbers on two dice to be 5.(ii) Even numbers on both dice(iii) A number greater than 3 on each die(iv) A total of 6 or 7 of the numbers on two dice

Answer»

We're given that two dice are rolled together at the same time.

Step 1: List out the possible outcomes.

$\begin{tabular}{| c | c | c | c | c | c | c |}\cline{1-7}& \sf 1 & \sf <klux>2</klux> & \sf 3 & \sf 4 & \sf 5 & \sf 6 \\\cline{1-7}\sf \ 1 \ & (1,1) & (1,2) & (1,3) & (1,4) & (1,5) & (1,6)\\\sf 2 & (2,1) & (2,2) & (2,3) & (2,4) & (2,5) & (2,6)\\\sf 3 & (3,1) & (3,2) & (3,3) & (3,4) & (3,5) & (3,6)\\\sf 4 & (4,1) & (4,2) & (4,3) & (4,4) & (4,5) & (4,6)\\\sf 5 & (5,1) & (5,2) & (5,3) & (5,4) & (5,5) & (5,6)\\\sf 6 & (6,1) & (6,2) & (6,3) & (6,4) & (6,5) & (6,6)\\ \cline{1-7}\end{tabular}$

Therefore, the possible outcomes are;

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

∴ TOTAL Number of outcomes: 36

-----------------------

Question 1: The sum of numbers on two dice to be 5.

Let's find the no: of favourable outcomes, i.e, the outcomes that will GIVE 5 as the sum when the numbers on top of the dice are added.

(The outcomes in bold are the favourable outcomes)

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

∴ Favourable outcomes: (1,4) (2,3) (3,2) (4,1)

∴ No: of favourable outcomes: 4

Let "E" be the probability of this event.

$\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$

$\sf \Longrightarrow Probability\Big(E\Big) = \dfrac{4}{36}$

$\sf \Longrightarrow Probability\Big(E\Big) = \dfrac{1}{9}$

-----------------------

Question 2: Even numbers on both dice.

Let's find the no: of favourable outcomes, i.e, the outcomes that have even numbers displayed on both the dice.

(The outcomes in bold are the favourable outcomes)

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

∴ Favourable outcomes: (2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)

∴ No: of favourable outcomes: 9

Let "F" be the probability of this event.

$\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$

$\sf \Longrightarrow Probability\Big(F\Big) = \dfrac{9}{36}$

$\sf \Longrightarrow Probability\Big(F\Big) = \dfrac{1}{4}$

-----------------------

Question 3: A number greater than 3 on each dice.

Let's find the no: of favourable outcomes, i.e, the outcomes that have both the numbers displayed greater than 3.

(The outcomes in bold are the favourable outcomes)

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

∴ Favourable outcomes: (4,4) (4,5) (4,6) (5,4) (5,5) (5,6) (6,4) (6,5) (6,6)

∴ No: of favourable outcomes: 9

Let "G" be the probability of this event.

$\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$

$\sf \Longrightarrow Probability\Big(G\Big) = \dfrac{9}{36}$

$\sf \Longrightarrow Probability\Big(G\Big) = \dfrac{1}{4}$

-----------------------

Question 4: A total of 6 or 7 of the numbers on two dice.

Let's find the no: of favourable outcomes, i.e, the outcomes that give us a total of 6 or 7 when added.

(The outcomes in bold are the favourable outcomes)

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

∴ Favourable outcomes:

(1,5) (1,6) (2,4) (2,5) (3,3) (3,4) (4,2) (4,3) (5,1) (5,2) (6,1)

∴ No: of favourable outcomes: 11

Let "H" be the probability of this event.

$\sf \Longrightarrow Probability\Big(Event\Big) = \dfrac{No: of \ Favourable \ Outcomes}{Total \ Number \ of \ outcomes}$

$\sf \Longrightarrow Probability\Big(H\Big) = \dfrac{11}{36}$

-----------------------

Final answers:

(i) 1/9

(ii) 1/4

(iii) 1/4

(iv) 11/36

Discussion

19004.	Divide the sum of 28 and 5by there difference
Answer» ANSWER: Step-by-step explanation: 28 + 5 = 33 28 - 5 = 23 Divide the sum of 28 and 5BY there DIFFERENCE = 33/23

19004.

Divide the sum of 28 and 5by there difference

Answer»

ANSWER:

Step-by-step explanation:

28 + 5 = 33

28 - 5 = 23

Divide the sum of 28 and 5BY there DIFFERENCE = 33/23

Discussion

19005.	Find four rational numbers between 3/7 and5/7
Answer» MULTIPLY both by 10 =3/7×10/10=30/70 =5/7×10/10=50/70 rational numbers=31/70,32/70,33/70,34/70 HOPE it HELPED you

19005.

Find four rational numbers between 3/7 and5/7

Answer»

MULTIPLY both by 10

=3/7×10/10=30/70

=5/7×10/10=50/70

rational numbers=31/70,32/70,33/70,34/70

HOPE it HELPED you

Discussion

19006.	Prove that 7+3√2 is an irrational number , where root 2 is given to be an irrational number.
Answer» Step-by-step explanation: given Root 2 is irrational.... let, assume that the NUM is rational so,.. 7+3root2=a/b ( where a and b are coprime) 3root2=a-7b/b co-prime mean HCF=1 root 2=a-7b/3b we KNOW that root2 is irrational it contradicts assumsion that the NUMBER is rational... so the number 7+3root2 is irrational... Hence,Proved... Hope it HELPS u.... Plz mark as Brainliest!....

19006.

Prove that 7+3√2 is an irrational number , where root 2 is given to be an irrational number.

Answer»

Step-by-step explanation:

given Root 2 is irrational....

let, assume that the NUM is rational

so,..

7+3root2=a/b ( where a and b are coprime)

3root2=a-7b/b co-prime mean HCF=1

root 2=a-7b/3b

we KNOW that root2 is irrational

it contradicts assumsion that the NUMBER is rational...

so the number 7+3root2 is irrational...

Hence,Proved...

Hope it HELPS u....

Plz mark as Brainliest!....

Discussion

19007.	If 34√5−√3 + 24√5+√3 = a√5+√3, find the values of a & b.
Answer» Step-by-step EXPLANATION: If 34√5−√3 + 24√5+√3 = a√5+√3,

19007.

If 34√5−√3 + 24√5+√3 = a√5+√3, find the values of a & b.

Answer»

Step-by-step EXPLANATION:

If 34√5−√3 + 24√5+√3 = a√5+√3,

Discussion

19008.	1. The simplest rationalisation factor of root 50 is...
Answer» ANSWER: Rational numbers are the ONE can be expressed in the FORM of p/q where p and q are tow INTEGERS and q is not equal to 0. The FACTORS of 50 = 2 * 5 * 5 Root of 50 = root of 2 * 5 * 5 Hence, root 50 = 5 * root 2 The rational factor of root 50 = root 2

19008.

1. The simplest rationalisation factor of root 50 is...

Answer»

ANSWER:

Rational numbers are the ONE can be expressed in the FORM of p/q where p and q are tow INTEGERS and q is not equal to 0.

The FACTORS of 50 = 2 * 5 * 5

Root of 50 = root of 2 * 5 * 5

Hence, root 50 = 5 * root 2

The rational factor of root 50 = root 2

Discussion

19009.	Sq.cm., let us caThe time that Nashifer takes to cover up a circular field from one end to other end is 45seconds less when he goes diametrically. If the speed of Nashifier be 80 m/mint then calculatethe length of diameter of this field.
Answer» sq cm., let us can The time that NASH infer TAKES to cover up a CIRCULAR field from one end to other end is 45 seconds less when he goes diametrically. If the speed of Nazified be 80 m/mint then calculate the LENGTH of DIAMETER of this field. Answer: 40 Step-by-step explanation: 80-45=40 40

19009.

Sq.cm., let us caThe time that Nashifer takes to cover up a circular field from one end to other end is 45seconds less when he goes diametrically. If the speed of Nashifier be 80 m/mint then calculatethe length of diameter of this field.

Answer»

sq cm., let us can

The time that NASH infer TAKES to cover up a CIRCULAR field from one end to other end is 45

seconds less when he goes diametrically. If the speed of Nazified be 80 m/mint then calculate

the LENGTH of DIAMETER of this field.

Answer:

40

Step-by-step explanation:

80-45=40

40

Discussion

19010.	∫cosx^0 dx=? ∫dx/√(36-x^2 )=?
Answer» ANSWER: what is the QUESTION bro ... Step-by-step EXPLANATION: mark me as brainlest answer

19010.

∫cosx^0 dx=? ∫dx/√(36-x^2 )=?

Answer»

ANSWER:

what is the QUESTION bro ...

Step-by-step EXPLANATION:

mark me as brainlest answer

Discussion

19011.	9. If A = {a,b,c}, B = {1, 2}, Find A x B and BXA
Answer» Step-by-step explanation: BXA=(1,a)(1,B(1,C)(2,a)(2,b)(2,c) AxB=(a,1)(a, 2)(b, 1)(b, 2)(c, 1)(c, 2) OK FRIEND

19011.

9. If A = {a,b,c}, B = {1, 2}, Find A x B and BXA

Answer»

Step-by-step explanation:

BXA=(1,a)(1,B(1,C)(2,a)(2,b)(2,c)

AxB=(a,1)(a, 2)(b, 1)(b, 2)(c, 1)(c, 2) OK FRIEND

Discussion

19012.	√1.9600 please tell me the answer
Answer» $\color{pink}{\tt{\bigstar}}\displaystyle{\tt{Hey\:mate}}$ $\sqrt{1.9600}$ ➠ 1.4 $\huge\red{\ddot\smile}$ $\huge\blue{\ddot\smile}$ $\huge\green{\ddot\smile}$ $\huge\pink{\ddot\smile}$

19012.

√1.9600 please tell me the answer

Answer»

$\color{pink}{\tt{\bigstar}}\displaystyle{\tt{Hey\:mate}}$

$\sqrt{1.9600}$

➠ 1.4

$\huge\red{\ddot\smile}$ $\huge\blue{\ddot\smile}$ $\huge\green{\ddot\smile}$ $\huge\pink{\ddot\smile}$

Discussion

19013.	2 5/9 - 1 7/15 subtract
Answer» ANSWER: ❤. 25/9 - 17/5 = 25×5-17×9/45 = 125-153/45 = -28/45 *HOPE* *THIS* *WILL* *HELP* *YOU* *BUDDY...... MARK* ME AS A *BRAINILIEST* *AND* *SUPPORT* ME.....☺️☺️☺️☺️

19013.

2 5/9 - 1 7/15 subtract

Answer»

ANSWER:

❤. 25/9 - 17/5

= 25×5-17×9/45

= 125-153/45

= -28/45

HOPE THIS WILL HELP YOU BUDDY......

MARK ME AS A BRAINILIEST AND SUPPORT ME.....☺️☺️☺️☺️

Discussion

19014.	8. In the adjoining figure, p Il q and q \|\| r.a. Is ZA = ZB? Why?b. Is ZB = ZC? Why?c. Is ZA = ZC? Why?d. Is p Il r? Why?
Answer» Step-by-step explanation: a( YES by corresponding angle b) yes by corresponding angle c) yes by corresponding angle d)yes because of euclid 7 TH THEOREM

19014.

8. In the adjoining figure, p Il q and q || r.a. Is ZA = ZB? Why?b. Is ZB = ZC? Why?c. Is ZA = ZC? Why?d. Is p Il r? Why?

Answer»

Step-by-step explanation:

a( YES by corresponding angle

b) yes by corresponding angle

c) yes by corresponding angle

d)yes because of euclid 7 TH THEOREM

Discussion

19015.	Can u help me to solve this I’m not getting it
Answer» ANSWER: Step-by-step explanation: 4√3√2² 4√32 42*√3 8√3 =√192 Pls MARK me as BRAINLIST

19015.

Can u help me to solve this I’m not getting it

Answer»

ANSWER:

Step-by-step explanation:

4√3√2²

4√3*2

4*2*√3

8√3

=√192

Pls MARK me as BRAINLIST

Discussion

19016.	Simplify : (x^b/x^c)b+c-a * (x^c/x^a)c+a-b * (x^a/x^b)a+b-c
Answer» ANSWER: HOPE this helps Step-by-step EXPLANATION:

19016.

Simplify : (x^b/x^c)b+c-a * (x^c/x^a)c+a-b * (x^a/x^b)a+b-c

Answer»

ANSWER:

HOPE this helps

Step-by-step EXPLANATION:

Discussion

19017.	6. The area of the triangle whose vertices are A(1, 2), B(-2,3) and C(-3,-4) is(a) 11(b) 22(C) 33(d) 21
Answer» ANSWER: 22 is CORRECT answer ......

19017.

6. The area of the triangle whose vertices are A(1, 2), B(-2,3) and C(-3,-4) is(a) 11(b) 22(C) 33(d) 21

Answer»

ANSWER:

22 is CORRECT answer

......

Discussion

19018.	If ABC and DEF are congruent triangles such that angle A=47° and angle E=83° then angle C=? A. 50° B. 60° C. 70° D. 80°
Answer» ANSWER: A.50° Step-by-step EXPLANATION: A=D,B=E,C=F 47°+83°+X=180° X=180°-47°-83° X=180°-130° X=50° C=50° A=50° mark me BRAINLIEST

19018.

If ABC and DEF are congruent triangles such that angle A=47° and angle E=83° then angle C=? A. 50° B. 60° C. 70° D. 80°

Answer»

ANSWER:

A.50°

Step-by-step EXPLANATION:

A=D,B=E,C=F

47°+83°+X=180°

X=180°-47°-83°

X=180°-130°

X=50°

C=50°

A=50°

mark me BRAINLIEST

Discussion

19019.	Mar-50) (5433) - 23--2
Answer» Step-by-step explanation: this is not a question to answer OK FRIEND do you understand OK PLZ friend give RIGHT questions to answer

19019.

Mar-50) (5433) - 23--2

Answer»

Step-by-step explanation:

this is not a question to answer OK FRIEND do you understand OK PLZ friend give RIGHT questions to answer

Discussion

19020.	On compairing the ratios a1/a2 , b1/b2, c1/c2 find out whether the following consistent or inconsistent 12x+20y=8, 3x-5y=3
Answer» Answér : Consistent Note: ★ A linear equation is two variables represent a straight line . ★ The word consistent is USED for the system of equations which CONSISTS any solution . ★ The word inconsistent is used for the system of equations which doesn't consists any solution . ★ Solution of a system of equations : It refers to the possibile values of the variable which satisfy all the equations in the given system . ★ A pair of linear equations are said to be consistent if their graph ( Straight line ) either intersect or coincide each other . ★ A pair of linear equations are said to be inconsistent if their graph ( Straight line ) are PARALLEL . ★ If we consider equations of two straight line AX + by + c = 0 and a'x + b'y + c' = 0 , then ; • The lines are intersecting if a/a' ≠ b/b' . → In this case , unique solution is found . • The lines are coincident if a/a' = b/b' = c/c' . → In this case , infinitely many solutions are found . • The lines are parallel if a/a' = b/b' ≠ c/c' . → In this case , no solution is found . Solution : Here, The given linear equations are ; 12x + 20y = 8 3x - 5y = 3 The given equations can be REWRITTEN as ; 12x + 20y - 8 = 0 3x - 5y - 3 = 0 Clearly , we have ; a1 = 12 a2 = 3 b1 = 20 b2 = -5 c1 = -8 c2 = -3 Now , a1/a2 = 12/3 = 4 b1/b2 = 20/-5 = -4 c1/c2 = -8/-3 = 8/3 Clearly , a1/a2 ≠ b1/b2 Thus , The given equations has an unique solution . Hence , The given equations are consistent .

19020.

On compairing the ratios a1/a2 , b1/b2, c1/c2 find out whether the following consistent or inconsistent 12x+20y=8, 3x-5y=3

Answer»

Answér :

Consistent

Note:

★ A linear equation is two variables represent a straight line .

★ The word consistent is USED for the system of equations which CONSISTS any solution .

★ The word inconsistent is used for the system of equations which doesn't consists any solution .

★ Solution of a system of equations : It refers to the possibile values of the variable which satisfy all the equations in the given system .

★ A pair of linear equations are said to be consistent if their graph ( Straight line ) either intersect or coincide each other .

★ A pair of linear equations are said to be inconsistent if their graph ( Straight line ) are PARALLEL .

★ If we consider equations of two straight line

AX + by + c = 0 and a'x + b'y + c' = 0 , then ;

• The lines are intersecting if a/a' ≠ b/b' .

→ In this case , unique solution is found .

• The lines are coincident if a/a' = b/b' = c/c' .

→ In this case , infinitely many solutions are found .

• The lines are parallel if a/a' = b/b' ≠ c/c' .

→ In this case , no solution is found .

Solution :

Here,

The given linear equations are ;

12x + 20y = 8

3x - 5y = 3

The given equations can be REWRITTEN as ;

12x + 20y - 8 = 0

3x - 5y - 3 = 0

Clearly , we have ;

a1 = 12

a2 = 3

b1 = 20

b2 = -5

c1 = -8

c2 = -3

Now ,

a1/a2 = 12/3 = 4

b1/b2 = 20/-5 = -4

c1/c2 = -8/-3 = 8/3

Clearly ,

a1/a2 ≠ b1/b2

Thus ,

The given equations has an unique solution .

Hence ,

The given equations are consistent .

Discussion

19021.	Let a = Å + B then,
Answer» ANSWER: helo mate Step-by-step EXPLANATION: AMSWER is AB MARK ME AS BRAINLIST

19021.

Let a = Å + B then,

Answer»

ANSWER:

helo mate

Step-by-step EXPLANATION:

AMSWER is AB

MARK ME AS BRAINLIST

Discussion

19022.	A truck is loaded with 200 packets of apples. If each box weighs 5kg 850g, then find the total weight of apples in the truck.
Answer» ANSWER: SEE in GOOGLE............

19022.

A truck is loaded with 200 packets of apples. If each box weighs 5kg 850g, then find the total weight of apples in the truck.

Answer»

ANSWER:

SEE in GOOGLE............

Discussion

19023.	Express the following as rational numbers 0.5^——
Answer» ANSWER: HELLO!!❤ YOUR ANSWER↓ Step-by-step explanation: 0.5 = 5/10 0.5 = 1/2 HOPE IT HELPS YOU ❤

19023.

Express the following as rational numbers 0.5^——

Answer»

ANSWER:

HELLO!!❤

YOUR ANSWER↓

Step-by-step explanation:

0.5 = 5/10

0.5 = 1/2

HOPE IT HELPS YOU ❤

Discussion

19024.	8. If n(A x B) = 15, n(A) = 3 then n(B) =
Answer» Answer: N(A) × n(B) = n(A × B) 3 × n(B) = 15 n(B) = 15 / 3 n(B) = 5.

19024.

8. If n(A x B) = 15, n(A) = 3 then n(B) =

Answer»

Answer:

N(A) × n(B) = n(A × B)

3 × n(B) = 15

n(B) = 15 / 3

n(B) = 5.

Discussion

19025.	Find the least number divisible by 12 , 18 , 36 , 36 and 54Please answer it.
Answer» Answer: 1 is the LEAST NUMBER 2,3,6 ..... are other numbers hope U UNDERSTAND it follow mark BRAINLIEST

19025.

Find the least number divisible by 12 , 18 , 36 , 36 and 54Please answer it.

Answer»

Answer:

1 is the LEAST NUMBER

2,3,6 .....

are other numbers

hope U UNDERSTAND it

follow

mark BRAINLIEST

Discussion

19026.	Find the zero of the polynomial 4root3x^2+5x-2root3 and verify the relation between the alfa^3+bitha ^3
Answer» Answer: Find the zero of the polynomial 4root3x^2+5x-2root3 and verify the relation between the alfa^3+bitha ^3Hi friend ,4√3 x^2 + 5x -2√3 (SPLITTING the middle term)=4√3 x^2 +(8-3)x -2√3=4√3(√3x+2) Step-by-step EXPLANATION: May this ANSWER will help you PLZ MARK has brainliest plz

19026.

Find the zero of the polynomial 4root3x^2+5x-2root3 and verify the relation between the alfa^3+bitha ^3

Answer»

Answer:

Find the zero of the polynomial 4root3x^2+5x-2root3 and verify the relation between the alfa^3+bitha ^3Hi friend ,4√3 x^2 + 5x -2√3 (SPLITTING the middle term)=4√3 x^2 +(8-3)x -2√3=4√3(√3x+2)

Step-by-step EXPLANATION:

May this ANSWER will help you PLZ MARK has brainliest plz

Discussion

19027.	45x+67y= -2467x+43y= 24
Answer» ANSWER: X=0.22 y=0.20 Step-by-step explanation: 45x=-24- 67y x= -24 -67 y/45 (whole divide by 45) 67x= 24-43y x=24-43y/67 (whole divide by 67) (equalling the VALUE of both the X) x= -24-67y/45 24-43y/67= -24 -67y/45 1080-1935y = 1608 - 4489y 4489y - 1935y =1608 -1080 2554y = 528 y= 528/2554 y= 0.20 x=24-43y/67 x=24-8.6/67 x=15.4/67 x=0.22

19027.

45x+67y= -2467x+43y= 24

Answer»

ANSWER:

X=0.22

y=0.20

Step-by-step explanation:

45x=-24- 67y

x= -24 -67 y/45 (whole divide by 45)

67x= 24-43y

x=24-43y/67 (whole divide by 67)

(equalling the VALUE of both the X)

x= -24-67y/45

24-43y/67= -24 -67y/45

1080-1935y = 1608 - 4489y

4489y - 1935y =1608 -1080

2554y = 528

y= 528/2554

y= 0.20

x=24-43y/67

x=24-8.6/67

x=15.4/67

x=0.22

Discussion

19028.	Jhon can do certain job in 8 hours. Willy in 10 hours, and Ruby in 12 hours. How long will it take to do the task if John and Willy work 2 hours and John and Ruby finish the task?
Answer» Answer: 4 HOURS PLZ FOLLOW me and MAKE me

19028.

Jhon can do certain job in 8 hours. Willy in 10 hours, and Ruby in 12 hours. How long will it take to do the task if John and Willy work 2 hours and John and Ruby finish the task?

Answer»

Answer:

4 HOURS PLZ FOLLOW me and MAKE me

Discussion

19029.	Find an irrational numbers between √2 and 3
Answer» Answer: Sqrt(4)=2 & Sqrt(9)=3. Hence, the square roots of 5, 6, 7, 8 will have values in between 2 & 3. And as these INTEGERS are not perfect sqaures, hence their square roots will be IRRATIONAL. So,some irrational numbers LYING in between 2 & 3 are Sqrt(5), Sqrt(6), Sqrt(7) & Sqrt(8). Step-by-step explanation:

19029.

Find an irrational numbers between √2 and 3

Answer»

Answer:

Sqrt(4)=2 & Sqrt(9)=3. Hence, the square roots of 5, 6, 7, 8 will have values in between 2 & 3. And as these INTEGERS are not perfect sqaures, hence their square roots will be IRRATIONAL. So,some irrational numbers LYING in between 2 & 3 are Sqrt(5), Sqrt(6), Sqrt(7) & Sqrt(8).

Step-by-step explanation:

Discussion

19030.	A^3-512 factories it using formula
Answer» ANSWER: I THINK it's HELPFUL to you if NOTHING SORRY...

19030.

A^3-512 factories it using formula

Answer»

ANSWER:

I THINK it's HELPFUL to you if NOTHING SORRY...

Discussion

19031.	CosecA+cot A=2/3COS A=??
Answer» Answer: Step-by-stHello Friend, Here, → cosec A - COT A = 3/2 ----(1) → We know that, cosec²A - cot²A = 1 So, (cosec A + cot A)(cosec A - cot A) = 1 So, (cosec A + cot A)(3/2) = 1 (From (1)) So, cosec A + cot A = 2/3 ----(2) → Now , ADD (1) and (2) So, cosec A - cot A = 3/2 cosec A + cot A = 2/3 ---------------------------------- So, 2 cosec A = (3/2) + (2/3) So, 2 cosec A = 13/6 So, cosec A = 13/12 So, sin A = 1/cosec = 12/13 → Now, we have sin A = 12/13 sin A is positive. This means that A lies in either First or Second Quadrant. We can find cot A easily to check which quadrant A lies in. Putting cosec A = 13/12 in (2) So, cosec A + cot A = 2/3 So, 13/12 + cot A = 2/3 So, cot A = 2/3 - 13/12 So, cot A = (8-12)/12 So, cot A = -5/12 • Now, cot A is negative. So A can either be in Second or Fourth Quadrant. But, as sin A is also positive , A must lie in Second Quadrant. → Now, cot A = cos A/sin A So, cos A = cot A × sin A So, cos A = (-5/12) × (12/13) So, cos A = -5/13 → Thus, cos A = -5/13, and A lies in Second Quadrant. Hope it HELPS.....plzz mark me on brainliests

19031.

CosecA+cot A=2/3COS A=??

Answer»

Answer:

Step-by-stHello Friend,

Here,

→ cosec A - COT A = 3/2 ----(1)

→ We know that,

cosec²A - cot²A = 1

So, (cosec A + cot A)(cosec A - cot A) = 1

So, (cosec A + cot A)(3/2) = 1 (From (1))

So, cosec A + cot A = 2/3 ----(2)

→ Now , ADD (1) and (2)

So,

cosec A - cot A = 3/2

cosec A + cot A = 2/3

----------------------------------

So, 2 cosec A = (3/2) + (2/3)

So, 2 cosec A = 13/6

So, cosec A = 13/12

So, sin A = 1/cosec = 12/13

→ Now, we have sin A = 12/13

sin A is positive. This means that A lies in either First or Second Quadrant.

We can find cot A easily to check which quadrant A lies in.

Putting cosec A = 13/12 in (2)

So, cosec A + cot A = 2/3

So, 13/12 + cot A = 2/3

So, cot A = 2/3 - 13/12

So, cot A = (8-12)/12

So, cot A = -5/12

• Now, cot A is negative. So A can either be in Second or Fourth Quadrant.

But, as sin A is also positive , A must lie in Second Quadrant.

→ Now,

cot A = cos A/sin A

So, cos A = cot A × sin A

So, cos A = (-5/12) × (12/13)

So, cos A = -5/13

→ Thus, cos A = -5/13, and A lies in Second Quadrant.

Hope it HELPS.....plzz mark me on brainliests

Discussion

19032.	মডেল অ্যাক্টিভিটি টাস্কগণিতষষ্ঠ শ্রেণি১,২.র প্রশ্নগুলির উত্তর দাও :7994424 -এই সংখ্যাটিতে তিনটি 4-এর স্থানীয় মানগুলির সমষ্টি নির্ণয় করাে।একটি স্থূলকোণী ত্রিভুজ আঁকো যার দুটি বাহু দৈর্ঘ্যে সমান।1টি বর্গাকার তৈরির জন্য 4টি দেশলাই-এর কাঠি, 2টি বর্গাকার তৈরির জন্য 2 x 4 টি দেশলাই -এর কাঠির প্রয়ােজন।এইভাবে nটি বর্গাকার তৈরির জন্য মােট কাঠির সংখ্যা কতাে হবে? এই সংখ্যাটির ধ্রুবক এবং চল লেখাে।একটি ছবি আকতে সমীরের 1 ঘণ্টার অংশ এবং মিতার ওই ছবি আকতে \| ঘণ্টার অংশ সময় লাগলে, কে কতমিনিট সময় নিয়েছে? কার কততাে বেশি সময় লেগেছে?2Ledoy
Answer» ANSWER: don't KNOW this LANGUAGE SORRY

19032.

মডেল অ্যাক্টিভিটি টাস্কগণিতষষ্ঠ শ্রেণি১,২.র প্রশ্নগুলির উত্তর দাও :7994424 -এই সংখ্যাটিতে তিনটি 4-এর স্থানীয় মানগুলির সমষ্টি নির্ণয় করাে।একটি স্থূলকোণী ত্রিভুজ আঁকো যার দুটি বাহু দৈর্ঘ্যে সমান।1টি বর্গাকার তৈরির জন্য 4টি দেশলাই-এর কাঠি, 2টি বর্গাকার তৈরির জন্য 2 x 4 টি দেশলাই -এর কাঠির প্রয়ােজন।এইভাবে nটি বর্গাকার তৈরির জন্য মােট কাঠির সংখ্যা কতাে হবে? এই সংখ্যাটির ধ্রুবক এবং চল লেখাে।একটি ছবি আকতে সমীরের 1 ঘণ্টার অংশ এবং মিতার ওই ছবি আকতে | ঘণ্টার অংশ সময় লাগলে, কে কতমিনিট সময় নিয়েছে? কার কততাে বেশি সময় লেগেছে?2Ledoy

Answer»

ANSWER:

don't KNOW this LANGUAGE SORRY

Discussion

19033.	যে বর্গক্ষেত্রের ক্ষেত্রফল .004 বর্গমিটার তার প্রতিটি বাহুর দৈর্ঘ্য তিন দশমিক স্থান পর্যন্ত নির্ণয় করো।
Answer» ANSWER: PLEASE SEE the ATTACHMENT below... Step-by-step EXPLANATION:

19033.

যে বর্গক্ষেত্রের ক্ষেত্রফল .004 বর্গমিটার তার প্রতিটি বাহুর দৈর্ঘ্য তিন দশমিক স্থান পর্যন্ত নির্ণয় করো।

Answer»

ANSWER:

PLEASE SEE the ATTACHMENT below...

Step-by-step EXPLANATION:

Discussion

19034.	√4 power 2×12 power 2
Answer» Answer: LET the breadth of the rectangle is B cm. Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2B cm. Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b) Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)SINCE, perimeter of rectangle is 120 cm. Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore, Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120 Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cm Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cm Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cmSo, the area of rectangle is Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cmSo, the area of rectangle is=20×40=800 cm2 Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cmSo, the area of rectangle is=20×40=800 cm2Hence, the length is 40 cm, breadth is 20 cm and area is 800 cm2.

19034.

√4 power 2×12 power 2

Answer»

Answer:

LET the breadth of the rectangle is B cm.

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2B cm.

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)SINCE, perimeter of rectangle is 120 cm.

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cm

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cm

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cmSo, the area of rectangle is

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cmSo, the area of rectangle is=20×40=800 cm2

Let the breadth of the rectangle is b cm.So, the length of the rectangle is 2b cm.We know that the perimeter of rectangle is=2(l+b)Since, perimeter of rectangle is 120 cm. Therefore,6b=120b=20 cmAnd l=40 cmSo, the area of rectangle is=20×40=800 cm2Hence, the length is 40 cm, breadth is 20 cm and area is 800 cm2.

Discussion

19035.	(iv) The graph of the equation cx + d-0 (c& dare constants andc0) will be y-axis,when(a) dc (b) doo (c) d=0 (d) d=1
Answer» Step-by-step explanation: SORRY i don't KNOWN PLEASE mark me as BRAINLIST

19035.

(iv) The graph of the equation cx + d-0 (c& dare constants andc0) will be y-axis,when(a) dc (b) doo (c) d=0 (d) d=1

Answer»

Step-by-step explanation:

SORRY i don't KNOWN

PLEASE mark me as BRAINLIST

Discussion

19036.	4root 3 root 2 power 2 equals
Answer» Answer: 96 Step-by-step EXPLANATION: *(4√3×√2)² = (4√6)²* *= 16 × 6* *= 96*

19036.

4root 3 root 2 power 2 equals

Answer»

Answer:

96

Step-by-step EXPLANATION:

(4√3×√2)² = (4√6)²

= 16 × 6

= 96

Discussion

19037.	यदि द्विधात बहुपद p(x) के लिए p(3) = 6 हो तो p(x)-6 का एक गुणनखंड लिखें।दीर्घ उत्तरीय प्रश्न
Answer» Answer: 2$+==:/(?6=55"6$/!6=95"6"!6'5"6",6,5!8"9'6=5

19037.

यदि द्विधात बहुपद p(x) के लिए p(3) = 6 हो तो p(x)-6 का एक गुणनखंड लिखें।दीर्घ उत्तरीय प्रश्न

Answer»

Answer:

2$+==*:/(?6=55"6$/!6=95"6"*!6'5"6",6,5!8"9'6=5

Discussion

19038.	A tangent to a circle touches it in ......... point
Answer» Answer: Tangent TOUCHES a CIRCLE at a single point only

19038.

A tangent to a circle touches it in ......... point

Answer»

Answer:

Tangent TOUCHES a CIRCLE at a single point only

Discussion

19039.	0.001 when expressed in the form p/q where p,q are integers and q not equal to 01) 1/10002) 1/10003) 1/19994) 1/999please tell me the answer step by step
Answer» Answer: 1 & 2 Step-by-step explanation: 0.001=1/1000 as 0.1=1/10

19039.

0.001 when expressed in the form p/q where p,q are integers and q not equal to 01) 1/10002) 1/10003) 1/19994) 1/999please tell me the answer step by step

Answer»

Answer:

1 & 2

Step-by-step explanation:

0.001=1/1000 as 0.1=1/10

Discussion

19040.	When are two lines said to be parallel
Answer» ANSWER: this is the answer in the PICTURE

19040.

When are two lines said to be parallel

Answer»

ANSWER:

this is the answer in the PICTURE

Discussion

19041.	If 3x - 2y = 4 and 2x + y = 5, then the value of m such that y = 2x + m : -3 3 30 -18
Answer» solve this linear EQUATIONS U get two values of X and y USE (y-y) =m(x-x) u get urs answer perfectly

19041.

If 3x - 2y = 4 and 2x + y = 5, then the value of m such that y = 2x + m : -3 3 30 -18

Answer»

solve this linear EQUATIONS U get two values of X and y USE (y-y) =m(x-x)

u get urs answer perfectly

Discussion

19042.	Under property of equality of real number a=b then b= a for all a, b belongs to R called
Answer» *It is COMMUTATIVE Property of ADDITION* B is *real* *number* pls FOLLOW me for more answers..✌️❣️..

19042.

Under property of equality of real number a=b then b= a for all a, b belongs to R called

Answer»

It is COMMUTATIVE Property of ADDITION

B is real number

pls FOLLOW me for more answers..✌️❣️..

Discussion

19043.	Find the area of the triangle whose vertices are (3,8).(-4,2), (5,1) using determinant
Answer» Answer: use the FORMULA 1/2( determinants value) and solve U GET urs answer perfectly

19043.

Find the area of the triangle whose vertices are (3,8).(-4,2), (5,1) using determinant

Answer»

Answer:

use the FORMULA

1/2( determinants value)

and solve U GET urs answer perfectly

Discussion

19044.	6. Find the largest number of 3 digits which is a perfect square.
Answer» ANSWER: OKK this is the answer plss FOLLOW me Step-by-step explanation: Plsss MARK AS BRAINLIEST

19044.

6. Find the largest number of 3 digits which is a perfect square.

Answer»

ANSWER:

OKK this is the answer plss FOLLOW me

Step-by-step explanation:

Plsss

MARK AS BRAINLIEST

Discussion

19045.	Solve 19.0.3×100 with explanationokk
Answer» Answer: 1903...................

19045.

Solve 19.0.3×100 with explanationokk

Answer»

Answer:

1903...................

Discussion

19046.	on a 60 kilometre straight road bus travels the first 30 km with a uniform speed of 30 km h-1. how fast must the best travel the next 30 kilometre so as to have every speed of 40 kilometre h -1 for the entrie trip
Answer» ANSWER: I THINK it should be PHYSICS INSTEAD of MATH

19046.

on a 60 kilometre straight road bus travels the first 30 km with a uniform speed of 30 km h-1. how fast must the best travel the next 30 kilometre so as to have every speed of 40 kilometre h -1 for the entrie trip

Answer»

ANSWER:

I THINK it should be PHYSICS INSTEAD of MATH

Discussion

19047.	Q6 ) -13/17 * -2/7 = -2/7 * -13/17 2 pointsName the property usedCommutative property of AdditionDistributive propertyAssociative property ofMultiplicationO None of these
Answer» Answer: COMMUTATIVE property Step-by-step EXPLANATION: commutative property Of ADDITION It SHOWS AB=BA

19047.

Q6 ) -13/17 * -2/7 = -2/7 * -13/17 2 pointsName the property usedCommutative property of AdditionDistributive propertyAssociative property ofMultiplicationO None of these

Answer»

Answer:

COMMUTATIVE property

Step-by-step EXPLANATION:

commutative property Of ADDITION

It SHOWS AB=BA

Discussion

19048.	Answer please (iii) 56 - 3-221y²
Answer» Step-by-step explanation: 56-3-221y² 53-221y² 53(1-7y²) 53(1-√7)(1+√7)

19048.

Answer please (iii) 56 - 3-221y²

Answer»

Step-by-step explanation:

56-3-221y²

53-221y²

53(1-7y²)

53(1-√7)(1+√7)

Discussion

19049.	(ii) The graph of the equation ay+b=0 (a & b are constants and a 70,b=0) is(a) parallel to the x-axis (b) parallel to the y-axis(c) not parallel to any axis (d) passing through origin
Answer» Step-by-step EXPLANATION: مساوات کا گراف AY + B = 0 (a & b مستقل اور ، = 0) ہے ی () ی محور کے متوازی (نہیں () ا صلیت سے گزرتے ہوئے

19049.

(ii) The graph of the equation ay+b=0 (a & b are constants and a 70,b=0) is(a) parallel to the x-axis (b) parallel to the y-axis(c) not parallel to any axis (d) passing through origin

Answer»

Step-by-step EXPLANATION:

مساوات کا گراف AY + B = 0 (a & b مستقل اور ، = 0) ہے

ی () ی محور کے متوازی

(نہیں () ا

صلیت سے گزرتے ہوئے

Discussion

19050.	Show that x=-2, y=-3 is a solutionaf system of linear equations6x - 5y = 32x+y+7=0
Answer» ANSWER: it is RIGHT answer. GOOD

19050.

Show that x=-2, y=-3 is a solutionaf system of linear equations6x - 5y = 32x+y+7=0

Answer»

ANSWER:

it is RIGHT answer. GOOD

Discussion

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HELLO!!❤

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