332354 + Interview Questions in Secondary School in Math Page 400 InterviewSolution

19951.	If the difference between the compoundand simple interest on a sum of moneyat 6.66 % per annum is Rs 184, then thesum of money is
Answer» Answer: 2,000 Step-by-step explanation: Simple and compound interest If the DIFFERENCE between the compound and simple interest on a CERTAIN sum of MONEY for 3 years at 5% per annum is Rs. 15.25, then the sum is : A) Rs. 2,000 B) Rs. 1,000 C) Rs. 1,500 D) Rs. 2,500 CORRECT Answer: A) Rs. 2,000 Description for Correct answer: TIME = 3 years, Rate = 5 % Difference between CI and SI = Rs. 15.25 Effective Rate % CI in 3 years =15.7625 % Effective Rate % SI in 3 years = 5×3 = 15 % According to the question, (15.7625−15) % of sum = Rs. 15.25 Sum=15.250.7625×100 =Rs. 2000

19951.

If the difference between the compoundand simple interest on a sum of moneyat 6.66 % per annum is Rs 184, then thesum of money is

Answer»

Answer:

2,000

Step-by-step explanation:

Simple and compound interest

If the DIFFERENCE between the compound and simple interest on a CERTAIN sum of MONEY for 3 years at 5% per annum is Rs. 15.25, then the sum is :

A) Rs. 2,000

B) Rs. 1,000

C) Rs. 1,500

D) Rs. 2,500

CORRECT Answer:

A) Rs. 2,000

Description for Correct answer:

TIME = 3 years, Rate = 5 %

Difference between CI and SI = Rs. 15.25

Effective Rate % CI in 3 years =15.7625 %

Effective Rate % SI in 3 years = 5×3 = 15 %

According to the question,

(15.7625−15) % of sum = Rs. 15.25

Sum=15.250.7625×100 =Rs. 2000

Discussion

19952.	Find a two digit number which is 3 times the sum of its digit
Answer» Answer: two DIGIT NUMBER = 10X + y => 3(x+y) = 10x+y => 3x + 3y = 10 x + y => 7x = 2y => x/ y = 2/7 => x = 2 and y= 7 => two digit number = 27

19952.

Find a two digit number which is 3 times the sum of its digit

Answer»

Answer:

two DIGIT NUMBER = 10X + y

=> 3(x+y) = 10x+y

=> 3x + 3y = 10 x + y

=> 7x = 2y

=> x/ y = 2/7

=> x = 2 and y= 7

=> two digit number = 27

Discussion

19953.	Poove Suppose two Chords of a circle inteosecteach other in the interior of the circle thenthe product of the lengths of the two segmentsor one chor do is equal to the pooduct ?the lengths out the two segment of the otherChord,
Answer» Step-by-step EXPLANATION: HOPE it is USEFUL MARK me as BRILLIANT

19953.

Poove Suppose two Chords of a circle inteosecteach other in the interior of the circle thenthe product of the lengths of the two segmentsor one chor do is equal to the pooduct ?the lengths out the two segment of the otherChord,

Answer»

Step-by-step EXPLANATION:

HOPE it is USEFUL MARK me as BRILLIANT

Discussion

19954.	If triangle ABC congruent triangle FD then side BC is equal to sides and angle C is equal to dash
Answer» Answer: Step-by-step explanation: Definition of TRIANGLE Congruence We say that triangle ABC is CONGRUENT to triangle DEF if AB = DE BC = EF CA = FD Angle A = Angle D Angle B = Angle E Angle C = Angle F (Of COURSE Angle A is short for angle BAC, etc.)

19954.

If triangle ABC congruent triangle FD then side BC is equal to sides and angle C is equal to dash

Answer»

Answer:

Step-by-step explanation:

Definition of TRIANGLE Congruence

We say that triangle ABC is CONGRUENT to triangle DEF if

AB = DE

BC = EF

CA = FD

Angle A = Angle D

Angle B = Angle E

Angle C = Angle F

(Of COURSE Angle A is short for angle BAC, etc.)

Discussion

19955.	I will mark brainiest rate andthank also answer this small MCQ...two angles are said to be congruent if their dash are equal 1) length of arms2) degree measure3)one arm4)all the aboveI am getting confused with 2nd and 4th.
Answer» ANSWER: all the above please MARK as BRAINLIEST

19955.

I will mark brainiest rate andthank also answer this small MCQ...two angles are said to be congruent if their dash are equal 1) length of arms2) degree measure3)one arm4)all the aboveI am getting confused with 2nd and 4th.

Answer»

ANSWER:

all the above

please MARK as BRAINLIEST

Discussion

19956.	four bells toll together at 10 am . they toll at the interval of 5,10,12 and 20 seconds respectively.When again they will toll together
Answer» Answer: 10: 01 because LCM of these numbers is 60 SEC means 1 minute *MARK* ME AS *BRAINLIEST PLZ*

19956.

four bells toll together at 10 am . they toll at the interval of 5,10,12 and 20 seconds respectively.When again they will toll together

Answer»

Answer:

10: 01

because LCM of these numbers is 60 SEC

means 1 minute

MARK ME AS BRAINLIEST PLZ

Discussion

19957.	A MAN BOUGHT 2 ARTICLES FOR BOTH 3045 1 AT THE GAIN OF 8% AND THE OTHER AT THE LOSS OF 5% FIND EACH OF THE ARTICLES PRICE
Answer» ANSWER: the ANSWET will be FIVE HUNDRED

19957.

A MAN BOUGHT 2 ARTICLES FOR BOTH 3045 1 AT THE GAIN OF 8% AND THE OTHER AT THE LOSS OF 5% FIND EACH OF THE ARTICLES PRICE

Answer»

ANSWER:

the ANSWET will be FIVE HUNDRED

Discussion

19958.	Solve for xX + 10 = 30, X-3 = 10, 2X = 10
Answer» Step-by-step EXPLANATION: X+10=30 X=30-10 X=20 X-3=10 X=10+3 X=13 2X=10 X=10/2 X=5 Hope this HELPS you MARK as BRANLIEST

19958.

Solve for xX + 10 = 30, X-3 = 10, 2X = 10

Answer»

Step-by-step EXPLANATION:

X+10=30

X=30-10

X=20

X-3=10

X=10+3

X=13

2X=10

X=10/2

X=5

Hope this HELPS you

MARK as BRANLIEST

Discussion

19959.	So that the difference between a three digit number in the form xoy and the sum of its digit is divided by 99 we always get a number equal to X.
Answer» ANSWER: CHECK the QUESTION PLEASE

19959.

So that the difference between a three digit number in the form xoy and the sum of its digit is divided by 99 we always get a number equal to X.

Answer»

ANSWER:

CHECK the QUESTION PLEASE

Discussion

19960.	If PS is a median of triangle PQR and T is any point on PR such that ar(PST):ar( PQS) = 2:3, then ar(TSR): ar (PQR)
Answer» •PS is a median of triangle PQR and T is any point on PR such that AR(PST):ar( PQS) = 2:3 •Let ar(PST) = 2x and ar(PQS) = 3X •Since PS is the median of ΔPQR, ar(PQS) = ar(PSR) = ar(PST) + ar (TSR) implies, 3x = 2x + ar(TSR) implies, ar(TSR) = x •Now, ar(PQR) = ar(PQS) + ar(PST) + ar(TSR) = 3x + 2x + x = 6x •Therefore, ar(TSR) : ar(PQR) = 1:6

19960.

If PS is a median of triangle PQR and T is any point on PR such that ar(PST):ar( PQS) = 2:3, then ar(TSR): ar (PQR)

Answer»

•PS is a median of triangle PQR and T is any point on PR such that AR(PST):ar( PQS) = 2:3

•Let ar(PST) = 2x and ar(PQS) = 3X

•Since PS is the median of ΔPQR,

ar(PQS) = ar(PSR) = ar(PST) + ar (TSR)

implies, 3x = 2x + ar(TSR)

implies, ar(TSR) = x

•Now, ar(PQR) = ar(PQS) + ar(PST) + ar(TSR) = 3x + 2x + x = 6x

•Therefore, ar(TSR) : ar(PQR) = 1:6

Discussion

19961.	The sum of the length of any two sides of a triangle is equal to the length of a third side is true or not
Answer» Answer: HELLO mate here's your AnsWer for your Question Step-by-step explanation: True By PYTHAGOREAN TRIPLET.....

19961.

The sum of the length of any two sides of a triangle is equal to the length of a third side is true or not

Answer»

Answer:

HELLO mate here's your AnsWer for your Question

Step-by-step explanation:

True

By PYTHAGOREAN TRIPLET.....

Discussion

19962.	Solve-2xyz (2x - 3y)÷4xy (4x2 - 9y2)
Answer» HEY MATE HERE'S THE SOLUTION........ ❤️❤️❤️❤️❤️ SOLUTION : $= > \: \frac{ - 2xyz(2x - 3y)}{4xy(4x {}^{2} - 9y {}^{2}) } \\ \\ \: = > \frac{ -z(2x - 3y)}{2(2x + 3y)(2x - 3y)} \\ \\ using \: \: \: a {}^{2} - b {}^{2} = (a + b)(a - b) \\ \\ = > \frac{ - z}{2(2x + 3y) } \\ \\ thats \: the \: answer \:$ ____Hope it helps___ _________THANK YOU_________

19962.

Solve-2xyz (2x - 3y)÷4xy (4x2 - 9y2)

Answer»

HEY MATE HERE'S THE SOLUTION........ ❤️❤️❤️❤️❤️

SOLUTION :

$= > \: \frac{ - 2xyz(2x - 3y)}{4xy(4x {}^{2} - 9y {}^{2}) } \\ \\ \: = > \frac{ -z(2x - 3y)}{2(2x + 3y)(2x - 3y)} \\ \\ using \: \: \: a {}^{2} - b {}^{2} = (a + b)(a - b) \\ \\ = > \frac{ - z}{2(2x + 3y) } \\ \\ thats \: the \: answer \:$

__Hope it helps_

_________THANK YOU_________

Discussion

19963.	If the roots of the quadratic equation
Answer» Step-by-step EXPLANATION: HOPE it will HELP you MATE.....

19963.

If the roots of the quadratic equation

Answer»

Step-by-step EXPLANATION:

HOPE it will HELP you MATE.....

Discussion

19964.	In an election, the successful candidate registered 5,77,500 votes and his nearrival secured 3.48,700 votes. By what margin did the successful candidate wthe election?
Answer» ANSWER: you can FIND these by SUBSTRATE these and find out

19964.

In an election, the successful candidate registered 5,77,500 votes and his nearrival secured 3.48,700 votes. By what margin did the successful candidate wthe election?

Answer»

ANSWER:

you can FIND these by SUBSTRATE these and find out

Discussion

19965.	Please answer it at the earliest.
Answer» a) 9.4310¹² KM B) 149600000 km c) the distance is LESS than a LIGHT year d) difference = 9.4310¹²- 1.49610^8 = (9430-1.496)10^8

19965.

Please answer it at the earliest.

Answer»

a) 9.43*10¹² KM

B) 149600000 km

c) the distance is LESS than a LIGHT year

d) difference = 9.43*10¹²- 1.496*10^8

= (9430-1.496)*10^8

Discussion

19966.	7. Test the divisibility of the following numbers by 8.(i) 3964
Answer» Answer: no its not divisible by 8. as the answer eill come in POINT Step-by-step explanation: in the divisibility test of no. by 8 u need to divide LAST 3 DIGITS by 8 if they are divible then the no. GIVEN is divisible by 8

19966.

7. Test the divisibility of the following numbers by 8.(i) 3964

Answer»

Answer:

no its not divisible by 8. as the answer eill come in POINT

Step-by-step explanation:

in the divisibility test of no. by 8

u need to divide LAST 3 DIGITS by 8

if they are divible then the no. GIVEN is divisible by 8

Discussion

19967.	Sita plays squash every 3rd day. If sheplayed squash on Monday, after howmany days will she play squash on Saturday.
Answer» Answer: 12 days please MARK as BRAINLIEST

19967.

Sita plays squash every 3rd day. If sheplayed squash on Monday, after howmany days will she play squash on Saturday.

Answer»

Answer:

12 days

please MARK as BRAINLIEST

Discussion

19968.	Factorise:-3.2-9x-5( 27 + 7-24-1r-13-32r+20you have to divide with X any number
Answer» ANSWER: Step-by-step EXPLANATION: Factorise: -3.2-9x-5 ( 27 + 7-24-1 r-13-32r+20 you have to divide with X any number

19968.

Factorise:-3.2-9x-5( 27 + 7-24-1r-13-32r+20you have to divide with X any number

Answer»

ANSWER:

Step-by-step EXPLANATION:

Factorise:

-3.2-9x-5

( 27 + 7-24-1

r-13-32r+20

you have to divide with X any number

Discussion

19969.	Find the area of an isosceles triangle each of whose equal sides is 13 m and whose base is 24 m
Answer» ANSWER: $156m ^{2}$ Step-by-step EXPLANATION: SOLUTION attached. pls MARK me brainliniest.......

19969.

Find the area of an isosceles triangle each of whose equal sides is 13 m and whose base is 24 m

Answer»

ANSWER:

$156m ^{2}$

Step-by-step EXPLANATION:

SOLUTION attached.

pls MARK me brainliniest.......

Discussion

19970.	Worksheet 3ExampSolutipurchased a watch for 330 and sold it at a loss of 20%. Find S.P. of the watch,2. By selling a T.V. for 8000, a shopkeeper loses 20% of his cost. If he sells it for 1100what profit or loss would be there for him?3. A shopkeeper purchased a T.V. set for 9000 and sold it at a loss of 5%. Find theselling price of the T.V. set.4. Seeta sells a dining set to Neeta for 6000 and gains 20%. For how much should shesell it to increase her profit by another 5%?5. Ranjan bought a second hand scooter for 6000. He spent 300 on its repairs and soldit to Vineet at a profit of 10%. Vineet sold the scooter to Mukesh at a loss of 10%. ALwhat price did Mukesh buy the scooter?6. A man buys two pens at 20 each. He sells one at a gain of 5% and other at a loss of5%. Find his gain or loss per cent.7. Mr. Tandon purchased a computer for 32000 and a microwave oven for 6500. Oncomputer he lost 5% and on microwave he gained 15%. Find his total gain or loss percent.Mr A calls a hirvice to Mr. B at a profit of 20% and Mr. B sells it to Mr. C at a profit of
Answer» ANSWER: it is very lenghty QUESTIONS of MATH

19970.

Worksheet 3ExampSolutipurchased a watch for 330 and sold it at a loss of 20%. Find S.P. of the watch,2. By selling a T.V. for 8000, a shopkeeper loses 20% of his cost. If he sells it for 1100what profit or loss would be there for him?3. A shopkeeper purchased a T.V. set for 9000 and sold it at a loss of 5%. Find theselling price of the T.V. set.4. Seeta sells a dining set to Neeta for 6000 and gains 20%. For how much should shesell it to increase her profit by another 5%?5. Ranjan bought a second hand scooter for 6000. He spent 300 on its repairs and soldit to Vineet at a profit of 10%. Vineet sold the scooter to Mukesh at a loss of 10%. ALwhat price did Mukesh buy the scooter?6. A man buys two pens at 20 each. He sells one at a gain of 5% and other at a loss of5%. Find his gain or loss per cent.7. Mr. Tandon purchased a computer for 32000 and a microwave oven for 6500. Oncomputer he lost 5% and on microwave he gained 15%. Find his total gain or loss percent.Mr A calls a hirvice to Mr. B at a profit of 20% and Mr. B sells it to Mr. C at a profit of

Answer»

ANSWER:

it is very lenghty QUESTIONS of MATH

Discussion

19971.	Find the numbers of terms in the expansion of (1+X)nth
Answer» THE NUMBER OF TERMS IN THE EXPANSION OF $(1 + x) {}^{n}$ WILL BE n+1. _____Thank you_____

19971.

Find the numbers of terms in the expansion of (1+X)nth

Answer»

THE NUMBER OF TERMS IN THE EXPANSION OF

$(1 + x) {}^{n}$

WILL BE n+1.

_Thank you_

Discussion

19972.	1. Estimate each of the following using general rule:(a) 730 +998 (b) 796 – 314 (c) 12,904 +2,888(d
Answer» ANSWER: a 1'728 B 382 C 15792 answer all off these

19972.

1. Estimate each of the following using general rule:(a) 730 +998 (b) 796 – 314 (c) 12,904 +2,888(d

Answer»

ANSWER:

a 1'728

B 382

C 15792 answer all off these

Discussion

19973.	Algebraic expression help
Answer» Answer: See the attachment for your answer PLEASE MARK it brainliest and FOLLOW me

19973.

Algebraic expression help

Answer»

Answer:

See the attachment for your answer

PLEASE MARK it brainliest and FOLLOW me

Discussion

19974.	Find the value of m if (x-m) is a factor of 3x^3 + 2x^2 - 19x + 3m.
Answer» x=m 3m³+2m²-19m+3m=0 3m³+2m²-16m=0 m(3m²+2m-16)=0 m=0

19974.

Find the value of m if (x-m) is a factor of 3x^3 + 2x^2 - 19x + 3m.

Answer»

x=m

3m³+2m²-19m+3m=0

3m³+2m²-16m=0

m(3m²+2m-16)=0

m=0

Discussion

19975.	Hanny. Pammy and Sunny are partners sharing profits in the ratio of 3:2:1. Goodwill is appearing in thebooks at a value of 60,000. Pammy retires and at the time of Pammy's retirement, goodwill is valued at84.000. Hanny and Sunny decided to share future profits in the ratio of 2:1. Record the necessary Journalentries.Arויד
Answer» Answer: HANNY = 1,pammy =2 , SUNNY =3

19975.

Hanny. Pammy and Sunny are partners sharing profits in the ratio of 3:2:1. Goodwill is appearing in thebooks at a value of 60,000. Pammy retires and at the time of Pammy's retirement, goodwill is valued at84.000. Hanny and Sunny decided to share future profits in the ratio of 2:1. Record the necessary Journalentries.Arויד

Answer»

Answer:

HANNY = 1,pammy =2 , SUNNY =3

Discussion

19976.	1.5m लंबा एक लड़का 30m ऊँचे एक भवन से कुछ दूरी पर खड़ा है। जब वह ऊँचे भवन की ओर जाता है तब उसकी आँख से भवन के शिखर का उन्नयन कोण 30^{o}30o से 60^{o}60o हो जाता है। बताइए कि वह भवन की ओर कितनी दूरी तक चलकर गया है।
Answer» The ANSWER is 19root3 other WISE when SIMPLIFIED the answer is 32.9m

19976.

1.5m लंबा एक लड़का 30m ऊँचे एक भवन से कुछ दूरी पर खड़ा है। जब वह ऊँचे भवन की ओर जाता है तब उसकी आँख से भवन के शिखर का उन्नयन कोण 30^{o}30o से 60^{o}60o हो जाता है। बताइए कि वह भवन की ओर कितनी दूरी तक चलकर गया है।

Answer»

The ANSWER is 19root3 other WISE when SIMPLIFIED the answer is 32.9m

Discussion

19977.	(C) A rectangular box has height h ém. Its length is 5 times the height and breadth is 10 cm lessthan the length. Express the length and thebreadth of the box in terms of the height.
Answer» HEIGHT = H CM length = 5H cm breadth = 5h-10 cm

19977.

(C) A rectangular box has height h ém. Its length is 5 times the height and breadth is 10 cm lessthan the length. Express the length and thebreadth of the box in terms of the height.

Answer»

HEIGHT = H CM

length = 5H cm

breadth = 5h-10 cm

Discussion

19978.	Circumference of the base of a cylinder and height is 44m. Find its curved surface
Answer» ANSWER: BROTHER CIRCUMFERENCE is missing Step-by-step EXPLANATION:

19978.

Circumference of the base of a cylinder and height is 44m. Find its curved surface

Answer»

ANSWER:

BROTHER CIRCUMFERENCE is missing

Step-by-step EXPLANATION:

Discussion

19979.	Find a and b , please help to solve this question
Answer» Step-by-step EXPLANATION: ANS is CONTINUED IMAGE 2

19979.

Find a and b , please help to solve this question

Answer»

Step-by-step EXPLANATION:

ANS is CONTINUED IMAGE 2

Discussion

19980.	Distance from the x-axis=8;distance from the y-axis=2(\|\|\|quadrant)
Answer» Answer: What do you mean by the QUESTION? The answer is FIRST QUADRANT MARK ME AS BRAINLIEST

19980.

Distance from the x-axis=8;distance from the y-axis=2(|||quadrant)

Answer»

Answer:

What do you mean by the QUESTION?

The answer is FIRST QUADRANT

MARK ME AS BRAINLIEST

Discussion

19981.	Solve this Inequality 3[ 1 + (-2)] + e ≤ 2e/3
Answer» ANSWER: SEE this attachment This is the BEST POSSIBLE answer Hope you have understood Please MARK it as $\huge\underline\mathcal\red{Brainliest}$ $\huge{\boxed{\mathbb\green{\fcolorbox{red}{blue}{Thank\:You}}}}$

19981.

Solve this Inequality 3[ 1 + (-2)] + e ≤ 2e/3

Answer»

ANSWER:

SEE this attachment

This is the BEST POSSIBLE answer

Hope you have understood

Please MARK it as

$\huge\underline\mathcal\red{Brainliest}$

$\huge{\boxed{\mathbb\green{\fcolorbox{red}{blue}{Thank\:You}}}}$

Discussion

19982.	✌️✌️✌️✌️✌️✌️✌️❤️Who invented Wifi...?
Answer» ANSWER: JOHN O'Sullivan Terence Percival Diethelm Ostry John Deane Graham Daniels Hope it HELPS ✌️ Mark as a BRAINLIEST if U can...✌️

19982.

✌️✌️✌️✌️✌️✌️✌️❤️Who invented Wifi...?

Answer»

ANSWER:

JOHN O'Sullivan

Terence Percival

Diethelm Ostry

John Deane

Graham Daniels

Hope it HELPS ✌️

Mark as a BRAINLIEST if U can...✌️

Discussion

19983.	Revision chapter 13 solved
Answer» ANSWER: what is the QUESTION in this?????

19983.

Revision chapter 13 solved

Answer»

ANSWER:

what is the QUESTION in this?????

Discussion

19984.	The price of a coffee machine is £96.00.The price is going to increase by 10%.Work out the price after the increase.
Answer» ANSWER: Step-by-step EXPLANATION: PRICE of the COFFEE machine=€96 Increase in price=10% Price after increase=€96+(10/100*96) Price after increase=£96+£9.6 Price after increase=£105.6

19984.

The price of a coffee machine is £96.00.The price is going to increase by 10%.Work out the price after the increase.

Answer»

ANSWER:

Step-by-step EXPLANATION:

PRICE of the COFFEE machine=€96

Increase in price=10%

Price after increase=€96+(10/100*96)

Price after increase=£96+£9.6

Price after increase=£105.6

Discussion

19985.	Please ans question no 4
Answer» ANSWER: SHADED PORTION is 7 and in - shaded portion is 6

19985.

Please ans question no 4

Answer»

ANSWER:

SHADED PORTION is 7 and in - shaded portion is 6

Discussion

19986.	AP and CP are bisectors of a and c respectively and l parallel to M find the measure of angle APC
Answer» ∠APC = 90° Step-by-step explanation: Given: Here AP and CP are the bisectors of A and C respectively and ALSO L parallel to M. ∠LAC + ∠ACM = 180° [co INTERIOR angles] Dividing both the SIDES by 2, we get $\frac{\angle LAC}{2}+\frac{\angle ACM}{2} =\frac{180}{2}$ ∠LAC + ∠ACP = 90° [Given] [1] Now, in Δ ACP ∠PAC + ∠ACP + ∠APC = 180° [Angle SUM PROPERTY] 90° + ∠APC = 180° ∠APC = 180° - 90° ∠APC = 90°

19986.

AP and CP are bisectors of a and c respectively and l parallel to M find the measure of angle APC

Answer»

∠APC = 90°

Step-by-step explanation:

Given:

Here AP and CP are the bisectors of A and C respectively and ALSO L parallel to M.

∠LAC + ∠ACM = 180° [co INTERIOR angles]

Dividing both the SIDES by 2, we get

$\frac{\angle LAC}{2}+\frac{\angle ACM}{2} =\frac{180}{2}$

∠LAC + ∠ACP = 90° [Given] [1]

Now, in Δ ACP

∠PAC + ∠ACP + ∠APC = 180° [Angle SUM PROPERTY]

90° + ∠APC = 180°

∠APC = 180° - 90°

∠APC = 90°

Discussion

19987.	Which is better investment:(10%,₹100 shares at ₹120) or (8%, ₹100 shares at ₹72)?
Answer» Answer: Step-by-step explanation: LET investment in each case be ₹(100 x 72) CASE 1 - By investing ₹100, annual INCOME = ₹10 By investing ₹(100 x 72), annual income = ₹(10/120) x (100 x 72) = ₹600 CASE 2 - By investing ₹100, annual income = ₹8 By investing ₹(100 x 72), annual income = ₹(8/90) x (100 x 72) = ₹640 Therefore CASE 2 is a better investment.

19987.

Which is better investment:(10%,₹100 shares at ₹120) or (8%, ₹100 shares at ₹72)?

Answer»

Answer:

Step-by-step explanation:

LET investment in each case be ₹(100 x 72)

CASE 1 -

By investing ₹100, annual INCOME = ₹10

By investing ₹(100 x 72), annual income = ₹(10/120) x (100 x 72) = ₹600

CASE 2 -

By investing ₹100, annual income = ₹8

By investing ₹(100 x 72), annual income = ₹(8/90) x (100 x 72) = ₹640

Therefore CASE 2 is a better investment.

Discussion

19988.	18 points for answer ..
Answer» ANSWER: $( {a }^{2} - \: {b}^{2} ) = {a}^{2} \: - 2ab \: + {b}^{2} \\ ( {a}^{2} ) {}^{2} \: - \: 2(a)(b) \: + \: ( {b}^{2} ) {}^{2} \\ {a}^{4} \: - 2ab \: + {b}^{4}$ HOPE IT WORKS THANKS!!!!!!!

19988.

18 points for answer ..

Answer»

ANSWER:

$( {a }^{2} - \: {b}^{2} ) = {a}^{2} \: - 2ab \: + {b}^{2} \\ ( {a}^{2} ) {}^{2} \: - \: 2(a)(b) \: + \: ( {b}^{2} ) {}^{2} \\ {a}^{4} \: - 2ab \: + {b}^{4}$

HOPE IT WORKS

THANKS!!!!!!!

Discussion

19989.	√3x = x+20find the value of x.
Answer» ANSWER: squaring on both SIDES 3x^2=x^2+40x+400 2x^2-40x-400 ➗ by 2 x^2-20x-200 continue the STEP, you will GET the answer MARK me as brainliest

19989.

√3x = x+20find the value of x.

Answer»

ANSWER:

squaring on both SIDES

3x^2=x^2+40x+400

2x^2-40x-400

➗ by 2

x^2-20x-200

continue the STEP,

you will GET the answer

MARK me as brainliest

Discussion

19990.	The curved surface area of a cone is 188.4 cm2 andits slant height is 10 cm. Find its perpendicular(n = 3.14)
Answer» ≡QUESTION≡ The curved surface area of a cone is 188.4 cm² and its slant HEIGHT is 10 CM. Find its perpendicular. ║⊕ANSWER⊕║ GIVEN Slant height ( l ) = 10 cm Surface area of the cone = 188.4 cm² Let the height be h cm Radius = r cm πrl = 188.4 r = 188.4 /( 3.14 * 10) r = 188.4/( 3.14 * 10 ) r = 6 cm Height is given by the formula: h² = l² - r² = 10² - 6² = 100 - 36 = 64 h = √64 = 8 cm ∴ The perpendicular height of the cone = 8 cm

19990.

The curved surface area of a cone is 188.4 cm2 andits slant height is 10 cm. Find its perpendicular(n = 3.14)

Answer»

≡QUESTION≡

The curved surface area of a cone is 188.4 cm² and its slant HEIGHT is 10 CM. Find its perpendicular.

║⊕ANSWER⊕║

GIVEN

Slant height ( l ) = 10 cm

Surface area of the cone = 188.4 cm²

Let the height be h cm

Radius = r cm

πrl = 188.4

r = 188.4 /( 3.14 * 10)

r = 188.4/( 3.14 * 10 )

r = 6 cm

Height is given by the formula:

h² = l² - r²

= 10² - 6²

= 100 - 36

= 64

h = √64

= 8 cm

∴ The perpendicular height of the cone = 8 cm

Discussion

19991.	A Abhimanyu observes two ships from an aeroplane at an altitudeof 5000 m sailing in the same direction. The angles of depressionof the ships as observed are 45° and 30°. Find the distancebetween ship
Answer» Let D and C be the positions of two SHIPS . Distance between two ships = CD , Let the observer Abhimanyu be at A ,in Aeroplane. It is given that AB = 5000 m and the angles of depression from A of D and C are 30° and 45° respectively . $\angle {ADB} = 30\degree \:and \:\angle {ACB} = 45\degree$ $In \: \triangle ABC, \:we \:have \\tan \:45\degree = \frac{AB}{CB}$ $\implies 1 = \frac{5000}{CB}$ $\implies CB = 5000 \:m$ $In \: \triangle ABD ,we \:have \\tan \:30\degree = \frac{AB}{DB}$ $\implies \frac{1}{\sqrt{3}} = \frac{5000}{DC + CB}$ $\implies DC + CB = 5000\sqrt{3}$ $\implies DC + 5000 = 5000\sqrt{3}$ $\implies DC = - 5000 +5000\sqrt{3}$ $\implies DC = (\sqrt{3} - 1)5000$ $\implies DC = (1.732 - 1)5000$ $\implies DC = 0.732 \times 5000$ $\implies DC = 0.732 \times 5000$ $\implies DC = 3660 \:m$ Therefore., $\red { <klux>DISTANCE</klux> \: between \:two \:ships } \green {= 3660 \:m}$ •••♪

19991.

A Abhimanyu observes two ships from an aeroplane at an altitudeof 5000 m sailing in the same direction. The angles of depressionof the ships as observed are 45° and 30°. Find the distancebetween ship

Answer»

Let D and C be the positions of two SHIPS .

Distance between two ships = CD ,

Let the observer Abhimanyu be at A ,in Aeroplane.

It is given that AB = 5000 m and the angles of depression from A of D and C are 30° and 45° respectively .

$\angle {ADB} = 30\degree \:and \:\angle {ACB} = 45\degree$

$In \: \triangle ABC, \:we \:have \\tan \:45\degree = \frac{AB}{CB}$

$\implies 1 = \frac{5000}{CB}$

$\implies CB = 5000 \:m$

$In \: \triangle ABD ,we \:have \\tan \:30\degree = \frac{AB}{DB}$

$\implies \frac{1}{\sqrt{3}} = \frac{5000}{DC + CB}$

$\implies DC + CB = 5000\sqrt{3}$

$\implies DC + 5000 = 5000\sqrt{3}$

$\implies DC = - 5000 +5000\sqrt{3}$

$\implies DC = (\sqrt{3} - 1)5000$

$\implies DC = (1.732 - 1)5000$

$\implies DC = 0.732 \times 5000$

$\implies DC = 3660 \:m$

Therefore.,

$\red { <klux>DISTANCE</klux> \: between \:two \:ships } \green {= 3660 \:m}$

•••♪

Discussion

19992.	40% of a no. when added to the square of the same no. then it is increased to 4040% of itself the actual no. is?
Answer» Answer: 39 Step-by-step explanation: 0.4x + X2 =40.40x - X X=39

19992.

40% of a no. when added to the square of the same no. then it is increased to 4040% of itself the actual no. is?

Answer»

Answer:

39

Step-by-step explanation:

0.4x + X2 =40.40x - X

X=39

Discussion

19993.	A man has a Recurring Deposit Account in abank for 3/2 years. If the rate of interest is 12%per annum and the man gets * 10,206 onmaturity, find the value of monthly instalments.
Answer» ANSWER: Step-by-step explanation: N=3/2 year=18 months r=12% M.V=10206 P=? M.V=pn+p(n(n+1)/212)r/100 10206=18p+p* (1819/212)*12/100 10206 =18p+1.71p 19.71p=10206 p=517.81

19993.

A man has a Recurring Deposit Account in abank for 3/2 years. If the rate of interest is 12%per annum and the man gets * 10,206 onmaturity, find the value of monthly instalments.

Answer»

ANSWER:

Step-by-step explanation:

N=3/2 year=18 months

r=12%

M.V=10206

P=?

M.V=p*n+p*(n(n+1)/2*12)*r/100 10206=18p+p* (18*19/2*12)*12/100

10206 =18p+1.71p

19.71p=10206

p=517.81

Discussion

19994.	5²= (2x – 5)² + x². who will solve
Answer» ANSWER: HEY MATE here is your answer 5²= (2X – 5)² + x². 25=4x^2-2×2x×5+5^2+x^2 25=16x^2-20x+25+x^2 25-25=17x^2-20x

19994.

5²= (2x – 5)² + x². who will solve

Answer»

ANSWER:

HEY MATE here is your answer

5²= (2X – 5)² + x².

25=4x^2-2×2x×5+5^2+x^2

25=16x^2-20x+25+x^2

25-25=17x^2-20x

Discussion

19995.	Pemii) Convert 35 g in kg.
Answer» Answer: 0.035kg Step-by-step EXPLANATION: 1g=1000kg THEREFORE, 35g=35/1000 KG =0.035kg

19995.

Pemii) Convert 35 g in kg.

Answer»

Answer:

0.035kg

Step-by-step EXPLANATION:

1g=1000kg

THEREFORE, 35g=35/1000 KG

=0.035kg

Discussion

19996.	4. In the fig. 6.17,the centre of thecircle is A andABCDEF is aregular hexagonof side 6 cm.Find the following.(√3 = 1.73, π = 3.14)(i) Area of segment BPF(ii) Area of the shaded portion.
Answer» Answer: I don't KNOW U are in which CLASS I am so SMALL I am in 1st I don't know answer

19996.

4. In the fig. 6.17,the centre of thecircle is A andABCDEF is aregular hexagonof side 6 cm.Find the following.(√3 = 1.73, π = 3.14)(i) Area of segment BPF(ii) Area of the shaded portion.

Answer»

Answer:

I don't KNOW U are in which CLASS I am so SMALL I am in 1st I don't know answer

Discussion

19997.	2. A (-3, 4), B (3, -1) and C (-2, 4) are the vertices of a triangle ABC.Find the length of line segment AP, where point P lies insideBC, such that BP: PC = 2:3...plz answer n show steps .....ll b a great help
Answer» Solution :- <P> Draw the given ΔABC with the given vertices [ Refer to attachment ] To find the length of line segment AP we NEED both the coordinates of the line segment Coordinates of 'P' are not given. So, we have to find the coordinates of 'P' with the given information 'P' is a POINTS on BC which divides BC is the ratio of 2 : 3 B(3,-1) C(-2,4) are given, we can find the coordinates of P using Section formula : $P(x,y) = \bigg( \dfrac{mx_2 + nx_1 }{m + n} ,\dfrac{my_2 + ny_1 }{m + n} \bigg)$ Here, x₁ = 3, x₂ = - 2, y₁ = - 1, y₂ = 4 m : n = 2 : 3 ⇒ m = 2, n = 3 $\implies P(x,y) = \bigg( \dfrac{2( - 2) + 3(3) }{2 + 3} ,\dfrac{2(4) + 3( - 1) }{2 + 3} \bigg)$ $\implies P(x,y) = \bigg( \dfrac{ -4 + 9}{5} ,\dfrac{8 - 3 }{5} \bigg)$ $\implies P(x,y) = \bigg( \dfrac{5}{5} ,\dfrac{5 }{5} \bigg) = (1,1)$ Now A(- 3, 4) and P(1,1) are known Now we can find the length of AP using Distance formula : $d = \sqrt{( x_2 - x_1)^{2} + (y_2 - y _1) ^{2} }$ Here, x₁ = - 3, x₂ = 1, y₁ = 4, y₂ = 1 $\implies AP = \sqrt{ \{ 1-( - 3) \}^{2} + (1 - 4) ^{2} }$ $\implies AP = \sqrt{(1 + 3) ^{2} + ( - 3) ^{2} }$ $\implies AP = \sqrt{4^{2} + 9 }$ $\implies AP = \sqrt{16 + 9 }$ $\implies AP = \sqrt{25} = 5$ Therefore the length of AP is 5 units.

19997.

2. A (-3, 4), B (3, -1) and C (-2, 4) are the vertices of a triangle ABC.Find the length of line segment AP, where point P lies insideBC, such that BP: PC = 2:3...plz answer n show steps .....ll b a great help

Answer»

Solution :-

<P>

Draw the given ΔABC with the given vertices

[ Refer to attachment ]

To find the length of line segment AP we NEED both the coordinates of the line segment

Coordinates of 'P' are not given.

So, we have to find the coordinates of 'P' with the given information

'P' is a POINTS on BC which divides BC is the ratio of 2 : 3

B(3,-1) C(-2,4) are given, we can find the coordinates of P using

Section formula :

$P(x,y) = \bigg( \dfrac{mx_2 + nx_1 }{m + n} ,\dfrac{my_2 + ny_1 }{m + n} \bigg)$

Here, x₁ = 3, x₂ = - 2, y₁ = - 1, y₂ = 4

m : n = 2 : 3 ⇒ m = 2, n = 3

$\implies P(x,y) = \bigg( \dfrac{2( - 2) + 3(3) }{2 + 3} ,\dfrac{2(4) + 3( - 1) }{2 + 3} \bigg)$

$\implies P(x,y) = \bigg( \dfrac{ -4 + 9}{5} ,\dfrac{8 - 3 }{5} \bigg)$

$\implies P(x,y) = \bigg( \dfrac{5}{5} ,\dfrac{5 }{5} \bigg) = (1,1)$

Now A(- 3, 4) and P(1,1) are known

Now we can find the length of AP using

Distance formula :

$d = \sqrt{( x_2 - x_1)^{2} + (y_2 - y _1) ^{2} }$

Here, x₁ = - 3, x₂ = 1, y₁ = 4, y₂ = 1

$\implies AP = \sqrt{ \{ 1-( - 3) \}^{2} + (1 - 4) ^{2} }$

$\implies AP = \sqrt{(1 + 3) ^{2} + ( - 3) ^{2} }$

$\implies AP = \sqrt{4^{2} + 9 }$

$\implies AP = \sqrt{16 + 9 }$

$\implies AP = \sqrt{25} = 5$

Therefore the length of AP is 5 units.

Discussion

19998.	6. Construct a word problem on simultaneouslinear equations in two variables (x and y) sothat the value of one of the variables will be 10(persons, rupees, metres, years, etc.) and solveit.
Answer» Answer: 2x+4y=10 Step-by-step explanation: If you substitute the VALUE then you will GET it for X with 3and for y IS1

19998.

6. Construct a word problem on simultaneouslinear equations in two variables (x and y) sothat the value of one of the variables will be 10(persons, rupees, metres, years, etc.) and solveit.

Answer»

Answer:

2x+4y=10

Step-by-step explanation:

If you substitute the VALUE then you will GET it for X with 3and for y IS1

Discussion

19999.	Pqrs and PQab are two parallelogram on opposite side of PQ. prove that s r a bis a parallelogram.
Answer» Step-by-step explanation: given pqrs and PQAB are two parallelogram on side PQ then pq\|\|ab.......1 pq\|\|rs......2 from 1and2 ab\|\|rs.....3 ar\|\|bs....4 a+b+r+s =360..5 then ABRS is a parallelogram HENCE proved

19999.

Pqrs and PQab are two parallelogram on opposite side of PQ. prove that s r a bis a parallelogram.

Answer»

Step-by-step explanation:

given pqrs and PQAB are two parallelogram on side PQ then
pq||ab.......1
pq||rs......2
from 1and2
ab||rs.....3
ar||bs....4
a+b+r+s =360..5 then
ABRS is a parallelogram
HENCE proved

Discussion

20000.	Solve (2x+3y)dx+(y-x)dy=0
Answer» PLEASE CHECK the ATTACHMENT.

Discussion

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