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20001.

Avaidh gunakkhand Vidhi dwara 17 23 aur 29 ko ke HCF aur LCM gyat kijiye​

Answer»

Answer:

HCF - 0

LCM - 17*23*29 = 391*29 = 11339

Step-by-step EXPLANATION:

plz mark it as brainliest

20002.

16. A box contains 90 cards bearing a number from 1 to 90. Find the probability that the card drawn bears(i) a two-digit number (ii) a perfect square number.​

Answer»

Sample space = {1,2,3,4,5,6,7,8,.......90}

(i) Two DIGIT number

Outcomes of two digit number = 80

THEREFORE

Probability = 80/90

= 8/9

(ii) a perfect SQUARE

Outcomes = {4,9,16,25,36,49,64}

Therefore

Probability = 7/80

Hope it helpful

Glad to HELP u

Thanks

Marks as brainliest

20003.

Hello friends please find the attachment​

Answer»

-1/(ax²+bx+c)²×2ax+b=dy/dx

simplify it further.....

i don't really have patience to type all that rubbish.... SORRY DUDE!!!

20004.

Three circle touches each other externally the length of the sides of triangle obtained by ​

Answer»

ANSWER:

The TRIANGLE is EQUILATERAL triangle Therefore the length of the SIDES are EQUAL

20005.

12. A man starts a journey. After sometime he finds that of the journey is covered andstill then he has to cover 90 km. How long is the journey.​

Answer»

ANSWER:

qweerdffddvvfghvvvghbbggfccvhhbvcf

20006.

A triangle has sides 35cm, 54cm and 61cm long. Find its area. please answer with full solution​

Answer»

Step-by-step EXPLANATION:

s=35+54+61

s = 35  + 54+ 61 \div 2 = 150 + \div 2 = 75

20007.

X/2-y/3=2.daw graph of linear equation in two variables.

Answer»

Answer:

The points on the LINE is x , y  ( 4 , - 6 )  .

Step-by-step explanation:

GIVEN as :

The LINEAR equation is

\dfrac{x}{<klux>2</klux>} - \dfrac{y}{3} = 2

Taking LCM

Or, 3 x - 2 y = 2 × 6

i.e 3 x - 2 y = 12

Now, For x = 0

i.e  3 × 0 - 2 y = 12

or, 0 - 2 y = 12

Or, y = \dfrac{12}{-2}

Or, y = - 6

Again

For y = 0

i.e 3 x - 2 × 0 = 12

Or, 3 x - 0 = 12

Or,  x = \dfrac{12}{3}

or, x = 4

So, The points on the line is x , y = ( 4 , - 6 )

Hence, The points on the line is x , y  ( 4 , - 6 )  . Answer

20008.

if alpha, beta are the roots of x square + bx + c is equals to zero then one by Alpha cube plus one by beta cube is equals to​

Answer»

Step-by-step EXPLANATION:

  1. when we solve this PROBLEM
  2. we get the VALUE of α andβ
  3. then take cube of α's value
  4. and with β
  5. and we get the VALUES
20009.

Le are in the ratio 1:2:3, then the least angle isThe angles of a triangle are in the ratio 1:2:3, IIIత్రిభుజంలోని కోణాల నిష్పతి 1:2 : 3 అయితే అందులోని అతి చిన్న కణం(1715(2) 20(3) 25(4) 30​

Answer»

Answer:

30

Step-by-step EXPLANATION:

x+2x+3x=180

6x=180

x=30

20010.

Show that(a+b).(b+c)×(c+a)=2[a b c]

Answer»

Answer:

TAKING L.H.S

(a+B).(b+C).(c+a)

a(b+c)+b(b+c).(c+a)

ab+bc+b^2+bc.(c+a)

c(ab+2bc+b^2)+a(ab+2bc+b^2)

abc+2bc^2+b^2c+a^2b+2abc+ab^2

next time i have to GO

20011.

Write the coefficient of x² in following expression 12x +3x + 5x² ​

Answer»

12X +3x+5 or 5.......

Step-by-step EXPLANATION:

..............

20012.

(i) Plot points A (0, 3), B (2, 3), C (3, 0), D (2, -3), E (0, -3)(ii) Reflect points B, C and D on the y axis and name them as B', C' and D'respectively.(iii) Write the co-ordinates of B', C' and D'.(iv) Write the equation of line B' D'.(v) Name the figure BCDD'C'B'B

Answer»

GIVEN points:

A (0, 3), B (2, 3), C (3, 0), D (2, -3), E (0, -3).

i)Plot points A (0, 3), B (2, 3), C (3, 0), D (2, -3), E (0, -3)

= Plotted in graph attached.

ii) Reflect points B, C and D on the y axis and name them as B', C' and D'

respectively.

Reflecting on x-axis will change the sign of x-coordinate of that point.

So, Reflection of B(2,3) on y-axis = B'(-2,3).

Reflection of C(3,0) on y-axis = C'(-3,0).

Reflection of D(2,-3) on y-axis = D'(-2,-3).

Points are plotted in graph attached.

iii) Co-ordinates are B'(-2,3), C'(-3,0) , D'(-2,-3).

iv) Equation of line B'D':

B' = (-2, 3) , D' = (-2,-3)

Slope of line = (y₂ - y₁) / (x₂ - x₁)

or, m = -3-3 / -2-(-2)

or, m = -6 / 0

or, m = not defined

Therefore, Equation of line B' D' is not defined.

v) The FIGURE BCDD'C'B'B is HEXAGON as it has 6 sides.

20013.

Please solve this with proper steps ​

Answer»

ANSWER:

MARK brialint answer PLZ

20014.

Find the area of the following fields all dimensions are in metres

Answer»

ANSWER:

No FIGURE there

\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \  \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \

20015.

C(2,1) and D(6,2) find distance between coordinates ​

Answer»

x1 = 2 , x2 = 6 , Y1 = 1 , y2 = 2

distance = √(x2 - x1)² + (y2 - y1)²

d = √(6-2)² + (2-1)²

d = √4² + 1

d = √17 units

20016.

Solve:​

Answer»

Answer:

The answer is 4

Step-by-step explanation

\lim_{<klux>X</klux> \to \two} _2 \frac{x^{<klux>2</klux>}-4 }{x-2} =  \lim_{x \to _2 \frac{(x-2)(x+2)}{(x-2)} \\  

the x-2 in the numertaor and denominator GET CANCELLED and then, you will get

\lim_{x \to \two} _2  x + 2 = 2 + 2 = 4

20017.

Find the number of digits in 810, given that log 2 = 0.301​

Answer»

10 Digits WOULD be there in 8¹⁰

Step-by-step explanation:

We NEED to find the number of digits in 8¹⁰

Let say N = 8¹⁰

Taking LOG both sides

Log N = Log (8¹⁰)

=> Log N = 10 Log 8

=> Log N = 10 Log 2³

=> Log N = 10 * 3 Log 2

=> Log N = 30 Log 2

Log 2  = 0.301

=>  Log N = 30 * 0.301

=> Log N = 9.03

Log N  ≥ 9

=> 10 Digits would be there in 8¹⁰

N = 10^(9.03)

for 10ˣ  - numberof digits = x + 1

9 ≤ x < 10  => number of digits = 10

Learn more:

If log2 = 0.30103 and log 3 = 0.4771, find the number of digits in ...

brainly.in/question/9522308

the number of digits in a number is x, find the POSSIBLE number of ...

brainly.in/question/13238351

20018.

​plzzz answer this question

Answer»

Step-by-step EXPLANATION:

your ANS ATTACHED in the PHOTO

20019.

each of 25 women gave rs 75 as subscribtion by putting this subscription together it was distributed equally among 15 flooded affected people how many rs did each get to be the subscribtion ​

Answer»

ANSWER:

Each 15 PEOPLE RECEIVED Rs.125

Step-by-step EXPLANATION:

\frac{25 \times 75}{15}  = 125 \\

20020.

Are concentric circles perpendicular

Answer»

ANSWER:

no CONCENTRIC CIRCLE are UNIFORM from all DISTANCE

20021.

Find the 6th term and the nth term of the sequence 3/2,3/4,3/8... ​

Answer»

A.P = 3/2, 3/4 , 3/8

d = 3/4 - 3/2 = - 3/4

a = 3/2

6th term = a + 5D

= 3/2 + 5 × -3/4

= 3/2 - 15/4

= 6 - 15 / 4

= -9/4

nth term = a + (n-1)d

=> an = 3/2 -3/4 n + 3/4

=> an = 3/2 + 3/4 - 3/4n

=> an = 9/4 - 3/4n

=> an = 3/4 ( 3 - n )

20022.

1607×1607=? simplify this ​

Answer»

1607 × 1607 = 2582449

HOPE THIS HELPS !!!

20023.

Prove that √3 is irrational ​

Answer»

Answer:

for proving √3 as irrational, let it be a rational number.

so,

\sqrt{3}  =  \frac{p}{q}

where, p and q are co-prime INTEGERS, q≠0

on squaring both SIDES;

3 =   \frac{ {p}^{2} }{ {q}^{2} }

or

3q²=p²....(1)

So, we can say that 3 divides p² and thus divides p also.

From the above OBSERVATION, we can conclude that;

p=3m for any INTEGER 'm'

Substituting (1) in the above eq.ⁿ

Now,

(3m)²=3q²

or 9m²=3q²

or 3m²=q²

So, we can say that 3 divides q² and thus divides q also.

Also, it divides q² and q (proved above)

But, we know that these numbers are co prime in nature. This contradiction arises because of our wrong assumption.

Therefore, √3 is irrational.

Hence, proved

20024.

Q1 choose the correct option.1 . If N=1then SI _____ CIa > b = c

Answer»

ANSWER:

d):- cannot SAY ......

20025.

ALGEBRASIMPLIFYSTEP BY STEP SOLUTION​​​

Answer»

Answer:

,

Step-by-step explanation:

if having any doubt U can ASK by FOLLOWING me. good LUCK

20026.

❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​​​​​​​​​​​

Answer»

\large \bold{\red {{ \displaystyle \lim_{n \to \infty}} \frac{1}{n} \sum\limits_{r=1}^{2n} \frac{r}{ \sqrt{ {n}^{2} + {r}^{2}}}}}

\large \bold \red{{\red{{{  \implies\displaystyle \lim_{n \to \infty}}\sum\limits_{r=1}^{2n} \frac{ \frac{r}{n} }{ \sqrt{1 + ( \frac{r}{u} ) {}^{2} } } }}}}

\displaystyle \bold \red{\frac{1}{2}\int_{0}^{2}  \frac{2x}{ \sqrt{1+  {x}^{2}}} =  \frac{1}{2}\int_{1}^{5}m {}^{ \frac{ - 1}{2} } dm}

\bold \red{ { \displaystyle{=  \frac{1}{2} \frac{m {}^{ \frac{1}{2} } }{ \frac{1}{2} }  \int_{1}^{5} =  \sqrt{5} } - 1}}

20027.

The function f is continuous on the closed interval [0,6] and has values given in the table above. The trapezoidal approximation found with 3 subintervals is 52. What is the value of k?❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​​​​​​​​​​

Answer»

madarchod BHOSDI WALE BEHAN KE laude

20028.

Find the value of :- ​

Answer»

PLEASE MARK me as BRAINLIEST ANSWER

20029.

The function f is continuous on the closed interval [0,6] and has values given in the table above. The trapezoidal approximation found with 3 subintervals is 52. What is the value of k?❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​​​​​​​​​

Answer»

Answer:

k = 10

Step-by-step explanation:

The formula for the AREA of a trapezoid is 1/2(b_1 + b_2)h where h = DELTA (X)

Therefore, A = 1/2(4+k)2 + 1/2(k+8)2 + 1/2(8+12)2 = 54

Solving that equation YIELDS k = 10.

20030.

The function f is continuous on the closed interval [0,6] and has values given in the table above. The trapezoidal approximation found with 3 subintervals is 52. What is the value of k?❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​​​​​​​​

Answer»
20031.

Please tell me this question ​

Answer»

1) 60°

2) 45°

3) 50°

4) a right triangle

5) 80° (b= 1/2 of A= 40°)

HOPE it's helpful

20032.

Anyone is on in my following​

Answer»

Answer:

nahi BRO AAJ gana nyy sun rhi ...

study KR rhi ... XD

20033.

Can you give me answer​

Answer»

PLEASE MARK me the BRAINLIEST

20034.

Solve the following :-​

Answer»

Answer:

8/9ki POWER 4

Step-by-step explanation:

2*1/3=-6/9

-6/9*6=324/81=324 KO CUT KAR do 81=4

8/9ki power 4

20035.

Please answer its urgent ​

Answer»

ANSWER:

chfhfdhtcddrydrysrysyrsrysrysyreudydyr idtidyidriritit itotitir F f f f FT YF f f f f f f f f f f f f f f f it f f f f f f f f f f f f f f f f f toyfiykhcjgxjtctjcjyccjcjgkgckgckgckhmbcbncbcnbdrgecdysrwjtfgajgdjhffskutkutngbfshfaj!t!jhjgdhfshfs?kykutmhjhfjhfkjgliyjgdbfzbfsj!HK?hfmhhgdfzgdg!jgkjgyjdfsf thecjydjyfyjyjfjyt

20036.

The type of the polynomial 2x + 3y is​

Answer»

Answer:

2x + 3y is LINEAR EQUATION in TWO VARIABLE., BINOMIAL

20037.

A cricketer scores (x-1) runs in each match and scores a total of (x3-1) runs. How many matches did he play?​

Answer»
20038.

Hey guys come all are alloweduqd-uuce-pju ​

Answer»

ANSWER:

It looks LIKE there aren't many great matches for your search

Tip Try using words that might appear on the page that you’re LOOKING for. For example, 'cake recipes' INSTEAD of 'how to make a cake'.

20039.

Hnji jrur bnaga apka friend or apka bhai.My intro My self harshit I am from haryana I read in class 10th Your intro please ​​

Answer»

i am KAVYA from GUJARAT i am in 7TH

20040.

If x + (1/x) = 5, find the value of [x - (1/x)]^2.​

Answer»

ANSWER:

Step-by-step EXPLANATION:

20041.

Plz tell the answer plz ​

Answer»

Given Question:-

\rm \: 0 < x < 90\degree  \: and \: sinx - cosx = \dfrac{1}{2}, \: then \: tanx =

\sf \: (1) \:  \: \dfrac{1 +  \sqrt{7} }{3}

\sf \: (2) \:  \: \dfrac{8 -  \sqrt{7} }{3}

\sf \: (3) \:  \: \dfrac{4 +  \sqrt{7} }{3}

\sf \: (4) \:  \: \dfrac{\sqrt{7}  - 1}{3}

\green{\large\underline{\sf{Solution-}}}

Given that

\rm :\longmapsto\:sinx - cosx = \dfrac{1}{2}

On squaring both sides, we get

\rm :\longmapsto\:(sinx - cosx)^{2} = \dfrac{1}{2}

\rm :\longmapsto\: {sin}^{2}x +  {cos}^{2}x - 2sinxcosx = \dfrac{1}{4}

We know,

\rm :\longmapsto\:\boxed{ \tt{ \:  {sin}^{2}x +  {cos}^{2}x  = 1}}

So, USING this, we get

\rm :\longmapsto\: 1 - 2sinxcosx = \dfrac{1}{4}

\rm :\longmapsto\:  - 2sinxcosx = \dfrac{1}{4}  - 1

\rm :\longmapsto\:  - 2sinxcosx = \dfrac{1 - 4}{4}

\rm :\longmapsto\:  - 2sinxcosx = \dfrac{- 3}{4}

\rm :\longmapsto\: sinxcosx = \dfrac{3}{8}

\rm :\longmapsto\:8sinxcosx = 3

\red{\rm :\longmapsto\:Divide \: both \: by \:  {cos}^{2}x \: }

\rm :\longmapsto\:\dfrac{8sinx \: cosx}{ {cos}^{2}x}  = \dfrac{3}{ {cos}^{2} x}

\rm :\longmapsto\:8tanx = 3 {sec}^{2}x

We know,

\rm :\longmapsto\:\boxed{ \tt{ \:  {sec}^{2}x = 1 +  {tan}^{2}x \: }}

\rm :\longmapsto\:8tanx = 3(1 +  {tan}^{2}x)

\rm :\longmapsto\:8tanx = 3 +  3{tan}^{2}x

\rm :\longmapsto\:3 {tan}^{2}x - 8tanx + 3 = 0

So, its a quadratic EQUATION in tanx, whose solution is given by using Quadratic formula.

\boxed{ \tt{ \: tanx =  \frac{ - b \:  \pm \:  \sqrt{ {b}^{2} - 4ac } }{2a}  \: }}

Here,

\red{\rm :\longmapsto\:a = 3}

\red{\rm :\longmapsto\:b =  - 8}

\red{\rm :\longmapsto\:c =  3}

So, on substituting the values, we get

\rm :\longmapsto\:tanx = \dfrac{ - ( - 8) \:  \pm \:  \sqrt{ {( - 8)}^{2}  - 4(3)(3)} }{2 \times 3}

\rm :\longmapsto\:tanx = \dfrac{8 \:  \pm \:  \sqrt{ 64 - 36} }{6}

\rm :\longmapsto\:tanx = \dfrac{8 \:  \pm \:  \sqrt{28} }{6}

\rm :\longmapsto\:tanx = \dfrac{8 \:  \pm \:  \sqrt{2 \times 2 \times 7} }{6}

\rm :\longmapsto\:tanx = \dfrac{8 \:  \pm \:  2\sqrt{7} }{6}

\rm :\longmapsto\:tanx = \dfrac{4 \:  \pm \:  \sqrt{7} }{3}

So,

\rm :\longmapsto\:tanx = \dfrac{4 \:   +  \:  \sqrt{7} }{3} \:  \: or \:  \: \dfrac{4 \:    - \:  \sqrt{7} }{3}

  • Hence, Option (3) is correct.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Additional Information:-

Relationship between sides and T ratios

sin θ = OPPOSITE Side/Hypotenuse

cos θ = ADJACENT Side/Hypotenuse

tan θ = Opposite Side/Adjacent Side

sec θ = Hypotenuse/Adjacent Side

cosec θ = Hypotenuse/Opposite Side

cot θ = Adjacent Side/Opposite Side

Reciprocal Identities

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

sin θ = 1/cosec θ

cos θ = 1/sec θ

tan θ = 1/cot θ

Co-function Identities

sin (90°−x) = cos x

cos (90°−x) = sin x

tan (90°−x) = cot x

cot (90°−x) = tan x

sec (90°−x) = cosec x

cosec (90°−x) = sec x

Fundamental Trigonometric Identities

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

cosec²θ - cot²θ = 1

20042.

18÷6×4÷2no snapthis is DMAS​​

Answer»

Answer:

6

hope you LIKE this

THANK you❤

20043.

Tdchyvtrfbhave fun girls​

Answer»

1.

a plane figure with four equal STRAIGHT SIDES and four right ANGLES

20044.

❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​

Answer»

\frac{{\imath }^{382}+{\imath }^{380}+{\imath }^{378}+{\imath }^{374}}{{\imath }^{372}+{\imath }^{370}+{\imath }^{368}+{\imath }^{364}}

\frac{-1+1-1-1}{{\imath }^{372}+{\imath }^{370}+{\imath }^{368}+{\imath }^{364}}

\frac{-2}{{\imath }^{372}+{\imath }^{370}+{\imath }^{368}+{\imath }^{364}}

\frac{-2}{1-1+1+1}

−1

20045.

The zero of the polynomial p(x)=x2+x-6

Answer»

ANSWER:

X2+x-6

X2+3x-2x-6

x(x+3)-2(x+3)

(x-2)(x+3)

x=2,x=-3

Thank you

Mark me as BRAINLIEST

20046.

verify in the following whether g(x)is a factor of p(x). g(x)=x-3; p(x)=xcube -4xsq.+x+6.​​

Answer»
20047.

In a given figure AB and EF are parallel to each other.prove that CDEF is a Cyclic quadrilateral​​

Answer»

ANSWER:

CDEFisacyclicquadrilateral.

∠FED=80

o

(GIVEN)

∠FED+∠FCD=180

o

...(sumofoppositeanglesofcyclicquadrilateralis180

o

)

⇒FCD=180

o

−80

o

=100

o

.

SinceAB∥CD,

⇒ABCDisaparallelogram.

∠ABC+∠BCD=180

o

...(Adjacentanglesofparallelogram.aresupplementary)

∠BCD=∠FCD=100

o

⇒∠ABC=180

o

−100

o

=80

o

∠ABC=∠FBA=80

o

.

HENCE,optionCiscorrect.

20048.

Important question answer me ​

Answer»

Answer:

-35/65

Step-by-step explanation:

Because it is convienent to PUT the minus SYMBOL on the NUMERATOR

20049.

Hi Pradeep me 4 baje Khel Sakti hu Abhi mera lecture hai please na sona​​

Answer»

Answer:

SONA BABU YE SAHI HAI benchooooooooo

20050.

(a+b)²-(a-b) ²= complete the equation​

Answer»

Answer:

4ab is the correct answer

Step-by-step explanation:

hope it HELPS uu

have a NICE day AHEAD ✌✌