332354 + Interview Questions in Secondary School in Math Page 429 InterviewSolution

21401.	a rectangle measuring 18 cm and 12 cm was reduced by 2 cm each. ii). The area of the rectangle reduced, (express your answer to four significant figures). (3mks)
Answer» ANSWER: Step-by-step explanation: 18÷2=9 12÷2=6 A=L×W 6×9 54.00.

21401.

a rectangle measuring 18 cm and 12 cm was reduced by 2 cm each. ii). The area of the rectangle reduced, (express your answer to four significant figures). (3mks)

Answer»

ANSWER:

Step-by-step explanation:

18÷2=9
12÷2=6

A=L×W
6×9
54.00.

Discussion

21402.	If r^2=x^2+y^2 show that
Answer» ANSWER: $5 {6x06(50)6.6}^{?}$ Step-by-step EXPLANATION: $56(3y33 \\ 311 \\ 1 \\ 115$

21402.

If r^2=x^2+y^2 show that

Answer»

ANSWER:

$5 {6x06(50)6.6}^{?}$

Step-by-step EXPLANATION:

$56(3y33 \\ 311 \\ 1 \\ 115$

Discussion

21403.	Find the value of x and show your work.a. X : 16 = 9 : 12 b. 1 : X = X : 49 c. 54 : 18 = 6 : X
Answer» ANSWER: *There* *are* *some* *pics* of *answers* on *which* I *worked* *hard" MARK* me as *BRAINLIEST* *please!! EDIT* : CHECK WELL, I've sent you 3 pics

21403.

Find the value of x and show your work.a. X : 16 = 9 : 12 b. 1 : X = X : 49 c. 54 : 18 = 6 : X

Answer»

ANSWER:

There are some pics of answers on which I worked hard"

MARK me as BRAINLIEST please!!

EDIT : CHECK WELL, I've sent you 3 pics

Discussion

21404.	How many triangles are there in the given figure?O a. 24O b. None of theseO c.32O d. 28
Answer» Step-by-step EXPLANATION: Where is the FIGURE? Can you PROVIDE it?

21404.

How many triangles are there in the given figure?O a. 24O b. None of theseO c.32O d. 28

Answer»

Step-by-step EXPLANATION:

Where is the FIGURE? Can you PROVIDE it?

Discussion

21405.	The simple interest on a sum of money will amount to Rs. 2,904 in 4 years at 11% p.a. simple interest. The sum in Rs. ______6,0006,8006,6005,500
Answer» Answer: 6600 Step-by-step EXPLANATION: I=2904 I=PTR/100 2904=P×(44/100) P=2904×100/44 26400/4 6600

21405.

The simple interest on a sum of money will amount to Rs. 2,904 in 4 years at 11% p.a. simple interest. The sum in Rs. ______6,0006,8006,6005,500

Answer»

Answer:

6600

Step-by-step EXPLANATION:

I=2904

I=PTR/100

2904=P×(44/100)

P=2904×100/44

26400/4

6600

Discussion

21406.	If the following frequency distribution is knownX1234frequency19756145Them p(x=3) is equal toa. 19/200b. 75/200C. 0.5d. 61/200
Answer» ANSWER: OPTION C ithink please MARK BRAINLIEST

21406.

If the following frequency distribution is knownX1234frequency19756145Them p(x=3) is equal toa. 19/200b. 75/200C. 0.5d. 61/200

Answer»

ANSWER:

OPTION C

ithink

please MARK BRAINLIEST

Discussion

21407.	A²b³c⁴,a³b²c⁵,-a⁵b³c² find the comman factor
Answer» ANSWER: the COMMON FACTOR is a B C

21407.

A²b³c⁴,a³b²c⁵,-a⁵b³c² find the comman factor

Answer»

ANSWER:

the COMMON FACTOR is a B C

Discussion

21408.	Write nth term of an AP whose 1st term is A and common difference is D
Answer» Answer: The nth term of an AP WHOSE FIRST term is 'a' and COMMON DIFFERENCE is 'd' is a+(n-1)d. Step-by-step EXPLANATION:

21408.

Write nth term of an AP whose 1st term is A and common difference is D

Answer»

Answer:

The nth term of an AP WHOSE FIRST term is 'a' and COMMON DIFFERENCE is 'd' is a+(n-1)d.

Step-by-step EXPLANATION:

Discussion

21409.	Q.9. Find the value of x3 - x²+2x +10 where x = 1+ √3!
Answer» ANSWER: I don't KNOW answer PLEASE MARK a BRAINLIST

21409.

Q.9. Find the value of x3 - x²+2x +10 where x = 1+ √3!

Answer»

ANSWER:

I don't KNOW answer PLEASE MARK a BRAINLIST

Discussion

21410.	Please help guy's fast
Answer» ANS of A -7/4 ans of B 83/10 pls MARK me BRAINLIEST

21410.

Please help guy's fast

Answer»

ANS of A -7/4

ans of B 83/10

pls MARK me BRAINLIEST

Discussion

21411.	A rectangle measures 18cm by 12cm.(a) If each dimension is reduced by 2cm, by what percentage is: ii). The area of the rectangle reduced, (express your answer to four significant figures). (3mks)
Answer» ANSWER: dgzhahdhxHhfhzydhHeudHajdjHefhausjsuaududuUfuxusufuzhzyf Step-by-step EXPLANATION: dgdgHfhshHzifufyagahfuehash TU duau DG ufueau FU euaufuqhfysusjd

21411.

A rectangle measures 18cm by 12cm.(a) If each dimension is reduced by 2cm, by what percentage is: ii). The area of the rectangle reduced, (express your answer to four significant figures). (3mks)

Answer»

ANSWER:

dgzhahdhxHhfhzydhHeudHajdjHefhausjsuaududuUfuxusufuzhzyf

Step-by-step EXPLANATION:

dgdgHfhshHzifufyagahfuehash TU duau DG ufueau FU euaufuqhfysusjd

Discussion

21412.	0.534,0.52,5.34,0.513 Arrange in increasing order
Answer» ANSWER: In INCREASING order, 0.534 < 0.513 < 0.52 < 5.34 Step-by-step explanation: HOPE it helps...

21412.

0.534,0.52,5.34,0.513 Arrange in increasing order

Answer»

ANSWER:

In INCREASING order,

0.534 < 0.513 < 0.52 < 5.34

Step-by-step explanation:

HOPE it helps...

Discussion

21413.	3. Of which are the following numbers perfect squares?36; 100; 25; 225; 144.
Answer» Step-by-step explanation: 6×6=36 10×10=100 5×5=25 15×15=225 12×12=144 all

21413.

3. Of which are the following numbers perfect squares?36; 100; 25; 225; 144.

Answer»

Step-by-step explanation:

6×6=36

10×10=100

5×5=25

15×15=225

12×12=144

all

Discussion

21414.	20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find 1) Radius of the cone. 2) Height of the cone. 3) Slant height of the cone. 4) Curved surface area of the cone. 5) Total surface area of the cone.
Answer» ANSWER: 1) Radius of the cone 14 CM 2) Height of the cone 48m 3) SLANT height of the cone 50cm 4) Curved surface area of the cone 2200cm^2 5) Total surface area of the cone 2816cm^2 Step-by-step explanation: HOPE THIS ANSWER HELPS YOU IF SO HIT A THANKS MARK ME AS BRAINLIEST.

21414.

20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find 1) Radius of the cone. 2) Height of the cone. 3) Slant height of the cone. 4) Curved surface area of the cone. 5) Total surface area of the cone.

Answer»

ANSWER:

1) Radius of the cone 14 CM

2) Height of the cone 48m

3) SLANT height of the cone 50cm

4) Curved surface area of the cone 2200cm^2

5) Total surface area of the cone 2816cm^2

Step-by-step explanation:

HOPE THIS ANSWER HELPS YOU IF SO HIT A THANKS

MARK ME AS BRAINLIEST.

Discussion

21415.	7x+6y= 17 and 6x+7y=10 what is the value of x-y ?
Answer»

Discussion

21416.	Write the following numbers in expanded form 10073
Answer» Step-by-step explanation: Cement MANUFACTURING is a complex process that begins with mining and then grinding RAW materials that include limestone and clay, to a fine POWDER, CALLED raw meal, which is then heated to a sintering temperature as high as 1450 °C in a cement kiln.

21416.

Write the following numbers in expanded form 10073

Answer»

Step-by-step explanation:

Cement MANUFACTURING is a complex process that begins with mining and then grinding RAW materials that include limestone and clay, to a fine POWDER, CALLED raw meal, which is then heated to a sintering temperature as high as 1450 °C in a cement kiln.

Discussion

21417.	Draw a comparative scale to show 1 mile or km on primary and secondary division 1/2 mile or 1/2 km on secondary division represented by, where R.F. is 1:60,000.
Answer» Step-by-step explanation: ⫷QUESTION⫸:- Draw a comparative scale to show 1 mile or km on PRIMARY and secondary division 1/2 mile on 1/2 km on secondary division represented by, where R.F. is 1:60,000. ⫷Answer⫸:- ✯Solution✯:- ☯️FPS METHOD:- R.F. = 1/ 60,000 ●Step-1 Calculation for statement scale:- According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator) Now, Assuming the Numerator in INCH, so both are considered as "Inch" unit and according to R.F. 1 inch is Numerator and 60,000 MILES is Dinominator and 60,000 inch has to be converted into "mile". So, 1 inch in the map distance represented by =60,000 inch on the real ground. 1 inch in the map distance represented by =60,000/63360 (1mile = 63360 inch) = 0.95 mile So, The statement scale 1 inch to 0.95 mile. ●Step-2 Calculations for total length of the scale:- SUPPOSE, we take 5 mile total scale, so the length of the scale will be, 0.95 mile on the ground distance represented by= 1 inch in the map. 1 mile on the ground distance represented by= 1/0.95 in the map. 5 mile on the ground distance represented by= 5×100/0.95 in the map. = 5.3 inch ●Step-3 Numbers of primary division:- Value of total length of the scale / Value of one primary division = 5 mile/ 1 mile = 5 ●Step-4 Numbers of secondary division:- Value of one primary division/Value of Secondary division = 1 mile / 1/2 mile = 2 ☯️CGS METHOD:- R.F. 1/ 60,000 ●Step-1 Calculation for statement scale:- According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator) Now, Assuming the Numerator in "centimeter," so both are considered as centimeter unit and according to R.F. unit 1 cm is Numerator and 60,000 is denominator and 60,000 cm has to be converted into "Kilometer". So, 1cm in the map distance represented by = 60,000 cm on the real ground. 1cm in the map distance represented by = 60,000/100000 (1km=100000cm)on the real ground. = 0.6 km So, The statement scale 1cm to 0.6 km. ●Step-2 Calculation for total length of the scale:- Suppose we take 5 km total scale, so the length of the scale will be, O.6km on the ground distance represented by = 1cm in the map. 1km on the ground distance represented by = 1/0.6cm in the map. 5km on the ground distance represented by = 5×10/0.6 cm in the map. = 8.3 cm ●Step-3 Number of primary division :- Value of total length of the scale/ Value of one primary division = 5km/1km = 5 ●Step-4 Number Of secondary division:- Value of one primary division/ Value of one secondary division = 1km/1/2km = 2

21417.

Draw a comparative scale to show 1 mile or km on primary and secondary division 1/2 mile or 1/2 km on secondary division represented by, where R.F. is 1:60,000.

Answer»

Step-by-step explanation:

⫷QUESTION⫸:-

Draw a comparative scale to show 1 mile or km

on PRIMARY and secondary division 1/2 mile on

1/2 km on secondary division represented by, where R.F. is 1:60,000.

⫷Answer⫸:-

✯Solution✯:-

☯️FPS METHOD:-

R.F. = 1/ 60,000

●Step-1

Calculation for statement scale:-

According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator)

Now,

Assuming the Numerator in INCH, so both are considered as "Inch" unit and according to R.F. 1 inch is Numerator and 60,000 MILES is Dinominator and 60,000 inch has to be

converted into "mile".

So,

1 inch in the map distance represented by =60,000 inch on the real ground.

1 inch in the map distance represented by =60,000/63360 (1mile = 63360 inch)

= 0.95 mile

So,

The statement scale 1 inch to 0.95 mile.

●Step-2

Calculations for total length of the scale:-

SUPPOSE, we take 5 mile total scale, so the

length of the scale will be,

0.95 mile on the ground distance represented

by= 1 inch in the map.

1 mile on the ground distance represented

by= 1/0.95 in the map.

5 mile on the ground distance represented

by= 5×100/0.95 in the map.

= 5.3 inch

●Step-3

Numbers of primary division:-

Value of total length of the scale / Value of one primary division

= 5 mile/ 1 mile

= 5

●Step-4

Numbers of secondary division:-

Value of one primary division/Value of Secondary division

= 1 mile / 1/2 mile

= 2

☯️CGS METHOD:-

R.F. 1/ 60,000

●Step-1

Calculation for statement scale:-

According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator)

Now,

Assuming the Numerator in "centimeter," so both are considered as centimeter unit and according to R.F. unit 1 cm is Numerator and 60,000 is denominator and 60,000 cm has to be converted into "Kilometer".

So,

1cm in the map distance represented by

= 60,000 cm on the real ground.

1cm in the map distance represented by

= 60,000/100000 (1km=100000cm)on the real ground.

= 0.6 km

So,

The statement scale 1cm to 0.6 km.

●Step-2

Calculation for total length of the scale:-

Suppose we take 5 km total scale, so the length

of the scale will be,

O.6km on the ground distance represented by

= 1cm in the map.

1km on the ground distance represented by

= 1/0.6cm in the map.

5km on the ground distance represented by

= 5×10/0.6 cm in the map.

= 8.3 cm

●Step-3

Number of primary division :-

Value of total length of the scale/ Value of one primary division

= 5km/1km

= 5

●Step-4

Number Of secondary division:-

Value of one primary division/ Value of one secondary division

= 1km/1/2km

= 2

Discussion

21418.	If ( x - 1/2, 2y - 1/3) = (1, 2/3) thenthe values of x and y is
Answer» Step-by-step EXPLANATION: $x - \frac{1}{2} = 1 \\ 2y - \frac{1}{3} = \frac{2}{3}$ $2x - 1 = 1 \\ 6y - 1 = \frac{2}{3}$ $x = 1 \\$ $y = \frac{5}{18}$ thanks plz MARK it brainliest plz

21418.

If ( x - 1/2, 2y - 1/3) = (1, 2/3) thenthe values of x and y is

Answer»

Step-by-step EXPLANATION:

$x - \frac{1}{2} = 1 \\ 2y - \frac{1}{3} = \frac{2}{3}$

$2x - 1 = 1 \\ 6y - 1 = \frac{2}{3}$

$x = 1 \\$

$y = \frac{5}{18}$

thanks

plz MARK it brainliest

plz

Discussion

21419.	Y=ln((1-x^2)/(1+x^2)) find dy/dx
Answer» Answer: PUT numbers in ORDER, PLACE them from lowest (first) to HIGHEST (LAST). This is called "Ascending Order". Think of ascending a mountain.

21419.

Y=ln((1-x^2)/(1+x^2)) find dy/dx

Answer»

Answer:

PUT numbers in ORDER, PLACE them from lowest (first) to HIGHEST (LAST). This is called "Ascending Order". Think of ascending a mountain.

Discussion

21420.	-121abc,-22a³b²c find the common factor
Answer» ANSWER: the answer is -11abc which is COMMON FACTOR

21420.

-121abc,-22a³b²c find the common factor

Answer»

ANSWER:

the answer is -11abc which is COMMON FACTOR

Discussion

21421.	Principle 4200, rate of interest (p.c.p.a.) 7% time 3 years . then what is intrest ???1] 8822]2883]862
Answer» Answer: 1 - 882 Step-by-step explanation: SI = P×R×T / 100 = 4200 × 7 × 3 / 100 = 42 × 21 = 882

21421.

Principle 4200, rate of interest (p.c.p.a.) 7% time 3 years . then what is intrest ???1] 8822]2883]862

Answer»

Answer:

1 - 882

Step-by-step explanation:

SI = P×R×T / 100

= 4200 × 7 × 3 / 100

= 42 × 21

= 882

Discussion

21422.	Have8) Rahul has a collection of 4321 stamps inan album. He has 17 such albums. Howmany stamps in all has he collected?
Answer» ANSWER: TOTAL no of STAMPS are 73457

21422.

Have8) Rahul has a collection of 4321 stamps inan album. He has 17 such albums. Howmany stamps in all has he collected?

Answer»

ANSWER:

TOTAL no of STAMPS are 73457

Discussion

21423.	A) A train running at a speed of54 km/ho, passes a man standing onthe platform in a seconds, find thelength of the train.
Answer» Step-by-step EXPLANATION: FIRST CONVERT 54km/h into m/sec

21423.

A) A train running at a speed of54 km/ho, passes a man standing onthe platform in a seconds, find thelength of the train.

Answer»

Step-by-step EXPLANATION:

FIRST CONVERT 54km/h into m/sec

Discussion

21424.	Find dy/dt ,y= √(3t+√(2+√(1-t)) at t=1
Answer» ANSWER: *Answer:प्रश्न 3 ननम्नलिखित के सत्य/ असत्य लिखिए-.* Answer:प्रश्न 3 ननम्नलिखित के सत्य/ असत्य लिखिए-. 1. उपभोक्ता सांस्कृनत हमारी सामाजजक नीव को जमा रही है Answer:प्रश्न 3 ननम्नलिखित के सत्य/ असत्य लिखिए-. 1. उपभोक्ता सांस्कृनत हमारी सामाजजक नीव को जमा रही है

21424.

Find dy/dt ,y= √(3t+√(2+√(1-t)) at t=1

Answer»

ANSWER:

Answer:प्रश्न 3 ननम्नलिखित के सत्य/ असत्य लिखिए-.

Answer:प्रश्न 3 ननम्नलिखित के सत्य/ असत्य लिखिए-. 1. उपभोक्ता सांस्कृनत हमारी सामाजजक नीव को जमा रही है

Discussion

21425.	What is the meaning of √x(x) = x^3/2?
Answer» ANSWER: $\sqrt{x} \times x \\ = {x}^{ \frac{1}{2} } \times x \\ = {x}^{ \frac{1}{2} + 1} \\ = {x}^{ \frac{1 + 2}{2} } \\ = {x}^{ \frac{3}{2} }$

21425.

What is the meaning of √x(x) = x^3/2?

Answer»

ANSWER:

$\sqrt{x} \times x \\ = {x}^{ \frac{1}{2} } \times x \\ = {x}^{ \frac{1}{2} + 1} \\ = {x}^{ \frac{1 + 2}{2} } \\ = {x}^{ \frac{3}{2} }$

Discussion

21426.	8पठन 7 > एवsd testo
Answer» ANSWER: what TYPE of the SUM is this I can't UNDERSTAND.

21426.

8पठन 7 > एवsd testo

Answer»

ANSWER:

what TYPE of the SUM is this I can't UNDERSTAND.

Discussion

21427.	2. The highest common factor in -24x’yºz2 and 56x4y2z3 is
Answer» ANSWER: don't KNOW the answer SORRY

21427.

2. The highest common factor in -24x’yºz2 and 56x4y2z3 is

Answer»

ANSWER:

don't KNOW the answer SORRY

Discussion

21428.	Proving algebraic identity 8
Answer» Answer: In an ALGEBRAIC identity, the left-side of the EQUATION is equal to the right-side of the equation. For example, (a+B)2 = a2+2ab+b2 , which is true for all the values of and b.

21428.

Proving algebraic identity 8

Answer»

Answer:

In an ALGEBRAIC identity, the left-side of the EQUATION is equal to the right-side of the equation. For example, (a+B)2 = a2+2ab+b2 , which is true for all the values of and b.

Discussion

21429.	3. If sqrt(3) = 1.732 , find the value of 5/(sqrt(3))
Answer» ANSWER: The value of 5/1.732 is 2.89 ( approx. ) Step-by-step EXPLANATION: HOPE it helps...

21429.

3. If sqrt(3) = 1.732 , find the value of 5/(sqrt(3))

Answer»

ANSWER:

The value of 5/1.732 is 2.89 ( approx. )

Step-by-step EXPLANATION:

HOPE it helps...

Discussion

21430.	60,000 are invested in a mutual fund withNAV of 15.3712 and entry load of 2.25%. Thenumber of units purchased are
Answer» ANSWER: UUUUOLG.OU. Step-by-step EXPLANATION:

21430.

60,000 are invested in a mutual fund withNAV of 15.3712 and entry load of 2.25%. Thenumber of units purchased are

Answer»

ANSWER:

UUUUOLG.OU.

Step-by-step EXPLANATION:

Discussion

21431.	1) Can displacement be greater than distance travelled? Why is it so?
Answer» ANSWER: ok Step-by-step EXPLANATION: no it cannot be more than the distance traveled because distance does not get to ZERO if you get back to the PLACE again from where you have started but displacement BECOMES zero

21431.

1) Can displacement be greater than distance travelled? Why is it so?

Answer»

ANSWER:

ok

Step-by-step EXPLANATION:

no it cannot be more than the distance traveled because

distance does not get to ZERO if you get back to the PLACE again

from where you have started but displacement

BECOMES zero

Discussion

21432.	The LCM of two number of 760 and their product is 6080. Find their HCF
Answer» ANSWER: LCM × HCF =PRODUCT of TWO number 760 ×HCF =6080 HCF = 6080/760 HCF= 8 It is your answer

21432.

The LCM of two number of 760 and their product is 6080. Find their HCF

Answer»

ANSWER:

LCM × HCF =PRODUCT of TWO number

760 ×HCF =6080

HCF = 6080/760

HCF= 8

It is your answer

Discussion

21433.	A rectangle measures 18cm by 12cm.(a) If each dimension is reduced by 2cm, by what percentage is:i). The perimeter reduced,(express your answer to four significant figures). (3mks)
Answer» Step-by-step explanation: 18cm by 12cm perimeter = 2(18+12) = 2(30) = 60 cm if each DIMENSION is REDUCED by 2cm perimeter= 2(16+10) = 2(26) =52cm percentage= 52/60*100 260/3 8.666% is reduced

21433.

A rectangle measures 18cm by 12cm.(a) If each dimension is reduced by 2cm, by what percentage is:i). The perimeter reduced,(express your answer to four significant figures). (3mks)

Answer»

Step-by-step explanation:

18cm by 12cm

perimeter = 2(18+12)

= 2(30)

= 60 cm

if each DIMENSION is REDUCED by 2cm

perimeter= 2(16+10)

= 2(26)

=52cm

percentage= 52/60*100

260/3

8.666% is reduced

Discussion

21434.	If x + 1/x=6, find the value of x^4+ 1/x^4
Answer» EXPLANATION. ⇒ X + 1/x = 6. As we know that, Squaring on both SIDES of the equation, we get. ⇒ (x + 1/x)² = (6)². ⇒ x² + 1/x² + 2(x)(1/x) = 36. ⇒ x² + 1/x² + 2 = 36. ⇒ x² + 1/x² = 36 - 2. ⇒ x² + 1/x² = 34. Again squaring on both sides of the equation, we get. ⇒ (x² + 1/x²)² = (34)². ⇒ x⁴ + 1/x⁴ + 2(x²)(1/x²) = 1156 ⇒ x⁴ + 1/x⁴ + 2 = 1156. ⇒ x⁴ + 1/x⁴ = 1156 - 2. ⇒ x⁴ + 1/x⁴ = 1154.

21434.

If x + 1/x=6, find the value of x^4+ 1/x^4

Answer»

EXPLANATION.

⇒ X + 1/x = 6.

As we know that,

Squaring on both SIDES of the equation, we get.

⇒ (x + 1/x)² = (6)².

⇒ x² + 1/x² + 2(x)(1/x) = 36.

⇒ x² + 1/x² + 2 = 36.

⇒ x² + 1/x² = 36 - 2.

⇒ x² + 1/x² = 34.

Again squaring on both sides of the equation, we get.

⇒ (x² + 1/x²)² = (34)².

⇒ x⁴ + 1/x⁴ + 2(x²)(1/x²) = 1156

⇒ x⁴ + 1/x⁴ + 2 = 1156.

⇒ x⁴ + 1/x⁴ = 1156 - 2.

⇒ x⁴ + 1/x⁴ = 1154.

Discussion

21435.	6 A model of a building is 6 cm high, while the actual building is 15 m high. If the building is 8.4how wide is the model building?vel 12.5 km in 15 minutes. If the speed
Answer» ANSWER: SORRY but I don't KNOW the answer

21435.

6 A model of a building is 6 cm high, while the actual building is 15 m high. If the building is 8.4how wide is the model building?vel 12.5 km in 15 minutes. If the speed

Answer»

ANSWER:

SORRY but I don't KNOW the answer

Discussion

21436.	1 Rupalicommencedbusinesswith bank balance= 25,000
Answer» Step-by-step EXPLANATION: HOPE you will UNDERSTAND

21436.

1 Rupalicommencedbusinesswith bank balance= 25,000

Answer»

Step-by-step EXPLANATION:

HOPE you will UNDERSTAND

Discussion

21437.	The value of cos²15°-sin²15°
Answer» ANSWER: the Answer for the above QUESTION is: ROOT 3/2

21437.

The value of cos²15°-sin²15°

Answer»

ANSWER:

the Answer for the above QUESTION is: ROOT 3/2

Discussion

21438.	मा8 सेंमी बाजू असलेल्या घनाचे घनफळ किती?प्र. 2 अ) खालील कृती करा. (कोणत्याही क्षेत्र) ।चौरसाच्या कर्णाची लांबी 13 सेंमी आहे, तर चौरसाची बाजू काढा.रीत : समजा ABCD हा चौरस आहे.AABC मध्ये mZABCDFप्रमेयानुसारAC' [AAABC मध्ये+ BC213 सेमीIX---13² = x² + x2x = 022B.C C13(दोन्ही बाजूंचे वर्गमूळ घेऊन)13211513V22-NE
Answer» Answer: 8 cm बाजू असलेल्या घनाचे घनफळ किती ? घनाचे घनफळ = 6 ( बाजू ) ² = 6 X 8² = 6 x 64 = 384 घ. सेमी ___________________________________ चौरसाच्या कर्णाची लांबी 13 सेंमी आहे, तर चौरसाची बाजू काढा. रीत : समजा ABCD हा चौरस आहे. AC हा कर्ण आहे . AC = 13 cm चौरसाच्या बाजूंची लांबी X मानू. त्रिकोण ABC मध्ये , कोण B = 90° पायथागोरसच्या प्रमेयावरून, AC² = AB² + BC ² 13 ² = X² + X² 169 = 2X² 169/2 = X² 13/√2 X √2 /√2 =X (13 √2 ) / √2 = X 6.5 cm =X चौरसाच्या बाजूची लांबी 6.5 cm आहे. _____Thank you_____ _____जय शिवराय_____

21438.

मा8 सेंमी बाजू असलेल्या घनाचे घनफळ किती?प्र. 2 अ) खालील कृती करा. (कोणत्याही क्षेत्र) ।चौरसाच्या कर्णाची लांबी 13 सेंमी आहे, तर चौरसाची बाजू काढा.रीत : समजा ABCD हा चौरस आहे.AABC मध्ये mZABCDFप्रमेयानुसारAC' [AAABC मध्ये+ BC213 सेमीIX---13² = x² + x2x = 022B.C C13(दोन्ही बाजूंचे वर्गमूळ घेऊन)13211513V22-NE

Answer»

Answer:

8 cm बाजू असलेल्या घनाचे घनफळ किती ?

घनाचे घनफळ = 6 ( बाजू ) ²

= 6 X 8²

= 6 x 64

= 384 घ. सेमी

___________________________________

चौरसाच्या कर्णाची लांबी 13 सेंमी आहे, तर चौरसाची बाजू काढा.

रीत :

समजा ABCD हा चौरस आहे.

AC हा कर्ण आहे .

AC = 13 cm

चौरसाच्या बाजूंची लांबी X मानू.

त्रिकोण ABC मध्ये ,

कोण B = 90°

पायथागोरसच्या प्रमेयावरून,

AC² = AB² + BC ²

13 ² = X² + X²

169 = 2X²

169/2 = X²

13/√2 X √2 /√2 =X

(13 √2 ) / √2 = X

6.5 cm =X

चौरसाच्या बाजूची लांबी 6.5

cm आहे.

_Thank you_

_जय शिवराय_

Discussion

21439.	Value of cosec 45° + cot 45° +tan 0° is?
Answer» ANSWER: $\csc(45) = \sqrt{2}$ $\cot(45) = \sqrt{2}$ $\tan(0) = 0$ there for ans is $\sqrt{2} + \sqrt{2} + 0$ $\sqrt[2]{2}$ thanks plz MARK it brainliest plz

21439.

Value of cosec 45° + cot 45° +tan 0° is?

Answer»

ANSWER:

$\csc(45) = \sqrt{2}$

$\cot(45) = \sqrt{2}$

$\tan(0) = 0$

there for

ans is

$\sqrt{2} + \sqrt{2} + 0$

$\sqrt[2]{2}$

thanks

plz MARK it brainliest

plz

Discussion

21440.	Q-3 Write in words according to indianand international system227628007
Answer» Two HUNDRED twenty seven MILLION six hundred twenty EIGHT THOUSAND seven

Discussion

21441.	Raajdhani express riding 504km in 4hour30minutes calculate the speed
Answer» Answer: 112 KM / HOUR. Step-by-step explanation: Average SPEED = DISTANCE / time = 504/ 4.5 hours = 112km/ hour

21441.

Raajdhani express riding 504km in 4hour30minutes calculate the speed

Answer»

Answer:

112 KM / HOUR.

Step-by-step explanation:

Average SPEED = DISTANCE / time

= 504/ 4.5 hours

= 112km/ hour

Discussion

21442.	Simplify the expression 2/5 12 p - (5 +2q) solution
Answer» Step-by-step EXPLANATION: $\frac{2}{5} \times 12p - (5 + 2q) = 0 \\ \frac{24p}{5} - 5 - 2q = 0 \\ \frac{24p - 25 - 10q}{5} = 0 \\ 24p - 10q - 25 = 0 \\ 24p - 10q = 25$ HOPE THIS HELPS MARK ME BRAINLIEST

21442.

Simplify the expression 2/5 12 p - (5 +2q) solution

Answer»

Step-by-step EXPLANATION:

$\frac{2}{5} \times 12p - (5 + 2q) = 0 \\ \frac{24p}{5} - 5 - 2q = 0 \\ \frac{24p - 25 - 10q}{5} = 0 \\ 24p - 10q - 25 = 0 \\ 24p - 10q = 25$

HOPE THIS HELPS

MARK ME BRAINLIEST

Discussion

21443.	19. In the given figure the perimeter of an isosceles right triangle having an area of100 cm2.Find the following 1) side of an isosceles triangle is 2) hypotenuse of an isosceles triangle is 3) find its perimeter. 4) write any one property of an isosceles triangle. 5) Is its perimeter and area are equal?
Answer» ANSWER: PLEASE MARK me BRAINLIST

21443.

19. In the given figure the perimeter of an isosceles right triangle having an area of100 cm2.Find the following 1) side of an isosceles triangle is 2) hypotenuse of an isosceles triangle is 3) find its perimeter. 4) write any one property of an isosceles triangle. 5) Is its perimeter and area are equal?

Answer»

ANSWER:

PLEASE MARK me BRAINLIST

Discussion

21444.	The zeroes of polynomial 3x²-12x-5 are?
Answer» Answer: 5 & -1 Step-by-step explanation: use QD FORMULA {b²-4(AC)} 3x²- 12x - 5 = 0 where a = 3 b = -12 c = - 5 (-12)²-4(3×-15) = 0 144+180= 0 324= 0 x= - b ±√b²-4(ac)÷ 2a x = - (-12) + 18 ÷ 2×3 OR x = -(-12) - 18 ÷ 2× 3 x= 12+18÷6 OR. x= 12-18÷ 6 x= 30÷6. OR. x= -6÷6 x = 5. OR x= -1 therefore the roots are 5 & -1 HOPE THIS HELPS YOU THANK YOU

21444.

The zeroes of polynomial 3x²-12x-5 are?

Answer»

Answer:

5 & -1

Step-by-step explanation:

use QD FORMULA {b²-4(AC)}

3x²- 12x - 5 = 0

where a = 3 b = -12 c = - 5

(-12)²-4(3×-15) = 0

144+180= 0

324= 0

x= - b ±√b²-4(ac)÷ 2a

x = - (-12) + 18 ÷ 2×3 OR x = -(-12) - 18 ÷ 2× 3

x= 12+18÷6 OR. x= 12-18÷ 6

x= 30÷6. OR. x= -6÷6

x = 5. OR x= -1

therefore the roots are 5 & -1

*HOPE THIS HELPS YOU*

THANK YOU

Discussion

21445.	(d) 2 1/2:x: :3 1/2 :4
Answer» Answer: 5 Step-by-step EXPLANATION: HOPE LIKE LIKE LIKE LIKES

21445.

(d) 2 1/2:x: :3 1/2 :4

Answer»

Answer:

5

Step-by-step EXPLANATION:

HOPE LIKE LIKE LIKE LIKES

Discussion

21446.	In 2010, Singapore. welcomed 11 6000000 overseas vistors.this vue has been rounded of to the nearest 100000.what are the largest and smallest values possible numbers of overseas visitors
Answer» ANSWER: The largest possible number of overseas VISITORS WOULD be 11,640,000. The SMALLEST possible number of overseas visitors would be 11,550,000. Step-by-step explanation: The number 11,600,000 was rounded off to the nearest 100,000.

21446.

In 2010, Singapore. welcomed 11 6000000 overseas vistors.this vue has been rounded of to the nearest 100000.what are the largest and smallest values possible numbers of overseas visitors

Answer»

ANSWER:

The largest possible number of overseas VISITORS WOULD be 11,640,000. The SMALLEST possible number of overseas visitors would be 11,550,000. Step-by-step explanation: The number 11,600,000 was rounded off to the nearest 100,000.

Discussion

21447.	If cos (A+B) = 0 and sin (A-B) =(where A and B are acute angles) find the measure of each angles
Answer» ANSWER: option B is the CORRECT answer for the following statement

21447.

If cos (A+B) = 0 and sin (A-B) =(where A and B are acute angles) find the measure of each angles

Answer»

ANSWER:

option B is the CORRECT answer for the following statement

Discussion

21448.	If 3A ∶ 5B = 2 ∶ 7 and A ∶ C = 3 ∶ 4, find B ∶ C
Answer» ANSWER: 63/40 Step-by-step EXPLANATION: answer is 63:40 GOOD LUCK

21448.

If 3A ∶ 5B = 2 ∶ 7 and A ∶ C = 3 ∶ 4, find B ∶ C

Answer»

ANSWER:

63/40

Step-by-step EXPLANATION:

answer is 63:40

GOOD LUCK

Discussion

21449.	Discriniment of 2x square-7x+5=0
Answer» Step-by-step explanation: HOPE it HELPS... SEE the attachment for answer...

21449.

Discriniment of 2x square-7x+5=0

Answer»

Step-by-step explanation:

HOPE it HELPS... SEE the attachment for answer...

Discussion

21450.	If cos=4/5, 3π
Answer» ANSWER: if COSO= 4/5 Base/hypotenuse= 4/5 By PYTHAGOREAN TRIPLET ::Perpendicular=3 ::Base=4 :: Hypotenuse=5 SinO= Per/Hyp = 3/5

21450.

If cos=4/5, 3π

Answer»

ANSWER:

if COSO= 4/5

Base/hypotenuse= 4/5

By PYTHAGOREAN TRIPLET ::Perpendicular=3

::Base=4

:: Hypotenuse=5

SinO= Per/Hyp = 3/5

Discussion

Explore topic-wise InterviewSolutions in .

a rectangle measuring 18 cm and 12 cm was reduced by 2 cm each. ii). The area of the rectangle reduced, (express your answer to four significant figures). (3mks)

If r^2=x^2+y^2 show that​

Find the value of x and show your work.a. X : 16 = 9 : 12 b. 1 : X = X : 49 c. 54 : 18 = 6 : X

How many triangles are there in the given figure?O a. 24O b. None of theseO c.32O d. 28​

The simple interest on a sum of money will amount to Rs. 2,904 in 4 years at 11% p.a. simple interest. The sum in Rs. ______6,0006,8006,6005,500

If the following frequency distribution is knownX1234frequency19756145Them p(x=3) is equal toa. 19/200b. 75/200C. 0.5d. 61/200​

A²b³c⁴,a³b²c⁵,-a⁵b³c² find the comman factor​

Write nth term of an AP whose 1st term is A and common difference is D​

Q.9. Find the value of x3 - x²+2x +10 where x = 1+ √3!​

Please help guy's fast ​

A rectangle measures 18cm by 12cm.(a) If each dimension is reduced by 2cm, by what percentage is: ii). The area of the rectangle reduced, (express your answer to four significant figures). (3mks)

0.534,0.52,5.34,0.513 Arrange in increasing order​

3. Of which are the following numbers perfect squares?36; 100; 25; 225; 144.​

20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find 1) Radius of the cone. 2) Height of the cone. 3) Slant height of the cone. 4) Curved surface area of the cone. 5) Total surface area of the cone.​

7x+6y= 17 and 6x+7y=10 what is the value of x-y ?​

Write the following numbers in expanded form 10073​

Draw a comparative scale to show 1 mile or km on primary and secondary division 1/2 mile or 1/2 km on secondary division represented by, where R.F. is 1:60,000.​

⫷QUESTION⫸:-

Draw a comparative scale to show 1 mile or km

on PRIMARY and secondary division 1/2 mile on

1/2 km on secondary division represented by, where R.F. is 1:60,000.

⫷Answer⫸:-

✯Solution✯:-

☯️FPS METHOD:-

R.F. = 1/ 60,000

●Step-1

Calculation for statement scale:-

According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator)

Now,

Assuming the Numerator in INCH, so both are considered as "Inch" unit and according to R.F. 1 inch is Numerator and 60,000 MILES is Dinominator and 60,000 inch has to be

converted into "mile".

So,

1 inch in the map distance represented by =60,000 inch on the real ground.

1 inch in the map distance represented by =60,000/63360 (1mile = 63360 inch)

= 0.95 mile

So,

The statement scale 1 inch to 0.95 mile.

●Step-2

Calculations for total length of the scale:-

SUPPOSE, we take 5 mile total scale, so the

length of the scale will be,

0.95 mile on the ground distance represented

by= 1 inch in the map.

1 mile on the ground distance represented

by= 1/0.95 in the map.

5 mile on the ground distance represented

by= 5×100/0.95 in the map.

= 5.3 inch

●Step-3

Numbers of primary division:-

Value of total length of the scale / Value of one primary division

= 5 mile/ 1 mile

= 5

●Step-4

Numbers of secondary division:-

Value of one primary division/Value of Secondary division

= 1 mile / 1/2 mile

= 2

☯️CGS METHOD:-

R.F. 1/ 60,000

●Step-1

Calculation for statement scale:-

According to the question, R.F. = Map distance (Numerator) ; Ground distance (Dinominator)

Now,

Assuming the Numerator in "centimeter," so both are considered as centimeter unit and according to R.F. unit 1 cm is Numerator and 60,000 is denominator and 60,000 cm has to be converted into "Kilometer".

So,

1cm in the map distance represented by

= 60,000 cm on the real ground.

1cm in the map distance represented by

= 60,000/100000 (1km=100000cm)on the real ground.

= 0.6 km

So,

The statement scale 1cm to 0.6 km.

●Step-2

Calculation for total length of the scale:-

Suppose we take 5 km total scale, so the length

of the scale will be,

O.6km on the ground distance represented by

= 1cm in the map.

If r^2=x^2+y^2 show that

How many triangles are there in the given figure?O a. 24O b. None of theseO c.32O d. 28

If the following frequency distribution is knownX1234frequency19756145Them p(x=3) is equal toa. 19/200b. 75/200C. 0.5d. 61/200

A²b³c⁴,a³b²c⁵,-a⁵b³c² find the comman factor

Write nth term of an AP whose 1st term is A and common difference is D

Q.9. Find the value of x3 - x²+2x +10 where x = 1+ √3!

Please help guy's fast

0.534,0.52,5.34,0.513 Arrange in increasing order

3. Of which are the following numbers perfect squares?36; 100; 25; 225; 144.

20. The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm, find 1) Radius of the cone. 2) Height of the cone. 3) Slant height of the cone. 4) Curved surface area of the cone. 5) Total surface area of the cone.

7x+6y= 17 and 6x+7y=10 what is the value of x-y ?

Write the following numbers in expanded form 10073

Draw a comparative scale to show 1 mile or km on primary and secondary division 1/2 mile or 1/2 km on secondary division represented by, where R.F. is 1:60,000.

If ( x - 1/2, 2y - 1/3) = (1, 2/3) thenthe values of x and y is

-121abc,-22a³b²c find the common factor

Principle 4200, rate of interest (p.c.p.a.) 7% time 3 years . then what is intrest ???1] 8822]2883]862

Have8) Rahul has a collection of 4321 stamps inan album. He has 17 such albums. Howmany stamps in all has he collected?

A) A train running at a speed of54 km/ho, passes a man standing onthe platform in a seconds, find thelength of the train.

What is the meaning of √x(x) = x^3/2?

8पठन 7 > एवsd testo

2. The highest common factor in -24x’yºz2 and 56x4y2z3 is

Proving algebraic identity 8

3. If sqrt(3) = 1.732 , find the value of 5/(sqrt(3))

60,000 are invested in a mutual fund withNAV of 15.3712 and entry load of 2.25%. Thenumber of units purchased are

1) Can displacement be greater than distance travelled? Why is it so?

The LCM of two number of 760 and their product is 6080. Find their HCF

6 A model of a building is 6 cm high, while the actual building is 15 m high. If the building is 8.4how wide is the model building?vel 12.5 km in 15 minutes. If the speed

1 Rupalicommencedbusinesswith bank balance= 25,000

The value of cos²15°-sin²15°

_Thank you_

_जय शिवराय_

Value of cosec 45° + cot 45° +tan 0° is?

Q-3 Write in words according to indianand international system227628007

Raajdhani express riding 504km in 4hour30minutes calculate the speed

Simplify the expression 2/5 12 p - (5 +2q) solution

The zeroes of polynomial 3x²-12x-5 are?

(d) 2 1/2:x: :3 1/2 :4