Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

21901.

Differentiate x ^ 2 sin x​

Answer»

Answer:

2xsinxcosx

Step-by-step EXPLANATION:

d (X^2sinx)/d(SIN x) . d(sin x)/DX

21902.

Plss do it with full explanation ​

Answer»

first MULTIPLE all the exponents

= -2 * 2 * -1

= -4 * -1

= 4

now do the calculation as give below

-1/5 * -1/5* -1/5 *-1/5

= 2/25* 2/25

=4/625

If you FIND my answer USEFUL then PLEASE mark me as brainlest

21903.

Find the perimeter of a square PQRS in which PQ = 17 cm​

Answer»

ANSWER:

PERIMETER of SQUARE= 4*side

Step-by-step explanation:

4*17=68 C. m.

21904.

NOTESexpress the angle in degdee, minutesand second (183.7)°​

Answer»

ANSWER:

j5xxpo79s8ss9a88slslslisis8

Step-by-step EXPLANATION:

Xcloxy90s99rtij5tto9iji s

21905.

Greatest 4 digit number urgent

Answer»

ANSWER:

9999

Step-by-step EXPLANATION:

PLEASE MAKE it a BRAINLIEST answer

21906.

A ball is drawn from a bag containing 3 red, 3 green and 4 white balls find 'S'​

Answer»

Step-by-step explanation:

The JAVA Virtual Machine, or JVM, is an abstract computer that RUNS compiled Java programs. The JVM is "virtual" because it is generally implemented in software on top of a "real" HARDWARE PLATFORM and operating system. All Java programs are compiled for the JVM. ... The JVM is mean because it of its ambition.

21907.

Area = 48 cm^2 and length = 8 cm. Find its perimeter.

Answer»

Step-by-step EXPLANATION:

i HOPE it HELPS you .it is of rectangle

thanks

21908.

Q.6. The sum of the lengths of all sides of aclosed figure is called the of that figure.O(a) lengthO b(b) breadthO c(c) perimeter​

Answer»

ANSWER:

(C) perimeter

MARK AS BRAINLIEST BRO PLZ

21909.

Write numerical coefficient litreal co efficient of -7ad2​

Answer»

Step-by-step explanation:

the answer will be -7 & 2

hope it HELPS you

21910.

பாரதியார் நடத்திய இதழ்களின் பெயரினை எமுதுக​

Answer»

ANSWER:

which LANGUAGE is this DEAR?

21911.

A certain freezing process required the roo temperature be lowered from 40°c at the rate of 5°c every hour. what will be the room temperature 10 hour after the freezing process starts​

Answer»

Answer:

∆ABC and ∆DEF similar triangles .Their areas are 25 CM 2 and 16 cm 2 respectively .Find the ratio of their corresponding sides

Cloth left with Tina = 20m 5CM - 4m 50cm

= (19M + 1M + 5cm) - (4m + 50cm)

= (19m + 100cm + 5cm) - (4m + 50cm)

= 19m + 105cm - 4m - 50cm

= 15m + 55CM

= 15m 55cm

21912.

Reena start running from point A and runs 10 kilometre towards south he takes its left turn and and 20 km now he runs 8 kilometre after taking a right turn .He finally takes a right turn and runs 20km and syops at point B what is the distance between point A and point B and point A in which direction is respect to point B?​

Answer»

Answer:

Rema walked 10kms south and turned right and walked 5kms. Then again she turned right and walked 10kms. Then she turned left and walked 10kms. How many kms will rema have to WALK to reach the starting point?

25 KM

20 km

5 km

15 km

21913.

(b)Find Eigen value of A.(5 0 1A = 0 - 2 0 105)​

Answer»

ANSWER:

gle.com/src-agqh-ura GIRLS

21914.

If Y=3÷(√19 -4) then find (y-4)^2​

Answer»

Answer:

We have y = Asinx + Bcosx ⇒ y1 = Acosx – Bsinx ⇒ y2 = –Asinx – Bcosx = –y ⇒ y2 + y = 0 By LEIBNITZ theorem, we get, ⇒ yn+2 + (0)yn+1 + (0) yn + yn = 0 ⇒ yn+2 + yn = 0Read more on Sarthaks.com - https://www.sarthaks.com/536436/if-y-asinx-bcos-x-then-prove-that-i-y2-y-0-ii-yn-2-yn-0?show=536439#a536439

Step-by-step EXPLANATION:

i HOPE it's HELPFUL for you

21915.

What is the derivative of y= x⁵ + cotx​

Answer»

ANSWER:

y=ln(cosecx−cotx)

Chain RULE,

dx

dy

=

du

dy

dx

du

Here u=cosecx−cotx

dx

dy

=

cosecx−cotx

1

dx

d(cosecx−cotx)

dx

dy

=

cosecx−cotx

−cosecx.cotx+cosec

2

X

dx

dy

=

cosecx−cotx

−cosecx(cotx−cosecx)

dx

dy

=cosecx

21916.

3x + 45IIx - 2 5x + 264+​

Answer»

ANSWER:

131346(0331 \gamma \pi \beta  \beta  log( log(0115) )  \times \frac{?}{?}

21917.

Which of the following are not measures of angles of triangle?A)80°,60°,50°B)90°,40°,50°C)60°,40°,80°D)110°,40°,30° plz say correct one ​

Answer»

1ST ONE can not FORM a TRIANGLE Because it's SUM is not 180°.

21918.

a field is rectangular in shape and its lenght is 1 1/2 times its breath . if its area is 2.4576 hectares . what is its perimeter​

Answer»

Answer :

  • Perimeter is 640m

Given :

  • Length is 1 ½ times its BREADTH
  • Area is 2.4576 hectares

To find :

  • Perimeter

Solution :

Given length is 1 ½ times its breadth so ,

  • Let the breadth be X
  • Length = 1 ½ x = 3/2 x

Area is 2.4576 hectares

  • We know that 1 hectares = 10000

》2.4576 × 10000

》24576 m²

Area is 24576m²

As we know that ,

  • Area of rectangle = length × breadth

》24576 = 3/2 x × x

》x² = 24576 × 2/3

》x² = 16384

》x = √16384

》x = 128

HENCE , Breadth is 128

  • Length = 3/2 x = 3/2 × 128 = 192

Now we have to find the perimeter:

As we know that ,

  • Perimeter of rectangle = 2(l + B)

Where, l is length 192 and b is breadth 128

》Perimeter of rectangle = 2(length + breadth)

》2(192 + 128)

》2(320)

》640m

Hence , Perimeter is 640m

Verification :

Given

  • Length = 192m
  • Breadth = 128m

As we know that,

  • Area of rectangle = length × breadth

》Area of rectangle = length × breadth

》192 × 128

》24576 m²

Hence verified

21919.

24.The dimensions of a cuboid are 15cm, 12cm and 10cm then fini) surface area. li) Lateral surface area iii) length of diagonal​

Answer»

Answer:

LATERAL surface area

Step-by-step explanation:

The dimensions of a cuboid are 15cm, 12CM and 10cm then FIN

21920.

2 numbers add up to 18 and their product is 48. this information can be represented in a quadratic equation in the form of

Answer»

ANSWER:

HOPE this helps

mark me BRAINLIEST

21921.

6. Simplify each of the following using distributive property of multiplication:(a) 79582 567 + 39791x 433 x 2(b) 246x10x 491-391x2460​

Answer»

Answer:

79582000

Step-by-step EXPLANATION:

(79582*567)+(39791×433X 2)

21922.

PAGE NO124//DATEDorimon left home atleft home at 4.10pm and returned homeat 5.35pm. calculate the total time he was out ofhouse​

Answer»

Answer:

1 HOUR and 25 MIN. He was out

21923.

7. Determine the product by suitable arrangement: 8 x 25 x 2​

Answer»

Answer:

des oranges™ Downloads (IMPRESSIONS DE BASE de données).

21924.

Example 1Mr. Prashant invested Rs. 75,375/- to purchase equity shares of acompany at market price of Rs. 250 /- through a brokerage firm,charging 0.5% brokerage. The face value of a share is Rs. 10/-. Howmany shares did Mr. Prashant purchase?​

Answer»

ANSWER:

zsjfjckdncj me KNOW when you have any other

21925.

Kar do delete i don't careAP sa hum Darta Thora ha​

Answer»

Moderators account DELETE kar sakte hai for shayad BRAINLY pe KABHI ENTER na ho sakti ho

21926.

Convert 720 month into year​

Answer»

Answer:

720 MONTHS EQUALS to 60 Years.

Formula:

We KNOW that ONE year equals to 12 months.

Knowing that we can divide 720 by 12 which equals to 60.

21927.

A ball is drawn from a bag containing 3 red, 3 green and 4 white balls find S and n(s).​

Answer»

Answer:

10

Step-by-step EXPLANATION:

HOPE it is HELPFUL

21928.

100 miter Ka 1/4 bhag kya Hoga ?​

Answer»

Answer:

25 meter

Step-by-step explanation:

100 X 1/4 = 25meter

21929.

The total surface area of a cylinder is calculated using the formula,​

Answer»

The GENERAL FORMULA for the TOTAL surface AREA of a cylinder is T. S. A. =2πrh+2πr2 .

21930.

Simplify (5^-1 × 7^2/ 5^2 × 7^-4) ^7/2 ×( 5^-2 × 7^3/ 5^3 × 7^-5) ^-5/2​

Answer»

SEE the ATTACHMENT...!!! MARKS me BRAINLIEST

21931.

21km 25 m full explain please​

Answer»

ANSWER:

fuodidtstizgzfisfisgisyoxyoddyodiyodyodyodoydyodyodyidyodoydyodyidyidistiztisitsitstistisursidhistixtididyodyzfisfisgfuodidtstizgzfisfisgisyoxyoddyodiyodyodyodoydyodyodyidyodoydyodyidyidistiztisitsitstistisursidhistixtididyodyodyodyodotststististististstistist777dy9d8ddy8dy8dtisydydyodyid

21932.

Write the medium of the data 15 , 40 , 40 , 25 , 16 , 28 , 32 , 36 , 42 , 16 ,19 ,28​

Answer»

ANSWER:

ISKA answer HAI 28.5 answer SOLVE

21933.

Term to term rule of 1, 3, 6, 10​

Answer»

Answer:

This is the Triangular Number Sequence: 1, 3, 6, 10, 15, 21, 28, 36, 45, ... find the next number of the sequence. The first TRIANGLE has just one DOT.

21934.

Find out the value of |4 - 9 |​

Answer»

∣4−9∣=∣−5∣=5

hope you FOUND it HELPFUL MATE have a NICE DAY

21935.

Factorise 28/2=+21m2/

Answer»

Answer:

In MATHEMATICS, factorization or factoring consists of writing a number or another MATHEMATICAL object as a product of several FACTORS, usually smaller or simpler objects of the same kind. For example, 3 × 5 is a factorization of the INTEGER 15, and is a factorization of the polynomial x² – 4.

21936.

Plss help with full explanation ​

Answer»

Answer:

The value of x = -4

Step-by-step explanation:

We know that 5²ˣ ÷ 5⁻³ = 5⁻⁵

since the bases are same(5)

=> 5²ˣ⁻⁽⁻³⁾ = 5⁻⁵

LET us take the powers now

=> 2X - (-3) = -5

=> 2x + 3 = -5

=> 2x = -5 - 3

=> 2x = -8

=>  x = -8/2 = -4

The value of x = -4

Let us CHECK,

     => 5²⁽⁻⁴⁾⁻⁽⁻³⁾

     => 5⁻⁸⁺³

     => 5⁻⁵

So the value of x = -4

Hope this HELPS u

please mark this as the brainliest

21937.

Lines are parrale true or false​

Answer»

ANSWER:

TRUE, LINE are PARALLEL to each other.

21938.

The length of a minute hand of a wall-clock is 10.5 cm. Find the distance coveredby tip of minute hand in 2 hours.​

Answer»

Answer:

  • 131.88 cm is the required answer.

Step-by-step explanation:

  • Length of Minute Hand of a wall-clock = Radius of Clock = 10.5 cm ( as we consider the clock in circular shape).

To Find:-

  • Distance covered by minutes hand in 2 HOUR.

Solution:-

If the minute hand takes 1 hour to complete one round .So , the number of rounds covered by minutes hand is 2

As we have to calculate the TOTAL distance covered by the minute hand so we calculate the circumference or PERIMETER of the clock .

  • Circumference of clock = 2πr

where,

  • π = 3.14
  • r denote length of minute hand

Substitute the VALUE we get

→ Total distance covered by minute hand = 2 × 2 πr

→ Total distance covered by minute hand = 2× 2 × 3.14 × 10.5

→ Total distance covered by minute hand = 4 × 3.14 × 10.5

→ Total distance covered by minute hand = 131. 88 cm

  • Hence, the total distance covered by the minute hand is 131.88 cm .
21939.

23,456How manyA mathematices book hasuso paymany pages will 96 copies of thesame book have?​

Answer»

ANSWER:

I can't understand

Step-by-step EXPLANATION:

what U WANT

21940.

Differentiate y=12x^5+3x^4+7X^3+x^2

Answer»

Answer:

The price of a smartphone is 5000 more than the cost of two feature phones &

the cost of 4 feature phones and two smartphone is 88,000 .

Exigency To Find : The cost of a smartphone and a feature phone.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider the cost price of smart phone and feature phone be Rs. x & Rs. y , respectively .

⠀⠀⠀⠀⠀⠀CASE I : The price of a smartphone is Rs. 5000 more than the cost of two feature phones .

\begin{gathered}\qquad :\implies \sf x = 2Y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \bf x = 2y + 5000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 1 }\bigg\rgroup\\\end{gathered}

:⟹x=2y+5000

Eq

n

1

⠀⠀⠀⠀⠀⠀CASE II : The cost of 4 feature phones and two smartphones is Rs. 88,000 .

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \bf 4y + 2x = 88000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 2}\bigg\rgroup\\\end{gathered}

:⟹4y+2x=88000

Eq

n

2

⠀⠀⠀⠀⠀⠀Now , FINDING the cost of Smart phone & Feature phone :

\begin{gathered}\qquad \:\maltese\:\bf{ From \:Equation \:2 \:\::}\\\end{gathered}

✠FromEquation2:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:2\:: 4y + 2x = 88000 }\bigg\rgroup \\\\\end{gathered}

Equation2:4y+2x=88000

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: SUBSTITUTING \: the \: Eq^n\:1 \: : \::}}\\\end{gathered}

⋆NowBySubstitutingtheEq

n

1::

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

EQUATION1:x=2y+5000

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \sf 4y +2 (2y + 5000) = 88000 \:\:\\\end{gathered}

:⟹4y+2(2y+5000)=88000

\begin{gathered}\qquad :\implies \sf 4y +4y + 10000 = 88000 \:\:\\\end{gathered}

:⟹4y+4y+10000=88000

\begin{gathered}\qquad :\implies \sf 4y +4y = 88000 - 10000 \:\:\\\end{gathered}

:⟹4y+4y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 88000 - 10000 \:\:\\\end{gathered}

:⟹8y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 78000 \:\:\\\end{gathered}

:⟹8y=78000

\begin{gathered}\qquad :\implies \sf y = \dfrac{ 78000}{8} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \sf y = \cancel {\dfrac{ 78000}{8}} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \bf y = 9750 \:\:\\\end{gathered}

:⟹y=9750

\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:y = Rs.\: 9750 }} }\:\:\bigstar \\\end{gathered}

:⟹

y=Rs.9750

⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: \: Value\:of\: y \ [ \ 9750 \ ] \:in \:Eq^n \:1 \::}}\\\end{gathered}

⋆NowBySubstitutingtheValueofy [ 9750 ]inEq

n

1:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

Equation1:x=2y+5000

\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \sf x = 2(9750) + 5000 \:\:\\\end{gathered}

:⟹x=2(9750)+5000

\begin{gathered}\qquad :\implies \sf x = 19500 + 5000 \:\:\\\end{gathered}

:⟹x=19500+5000

\begin{gathered}\qquad :\implies \bf x = 24500 \:\:\\\end{gathered}

:⟹x=24500

\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:x \:= Rs.\: 24500 }} }\:\:\bigstar \\\end{gathered}

:⟹

x=Rs.24500

Therefore,

The cost of smartphone is : x = Rs. 24, 500

The cost of feature phone: y = Rs. 9,750

Therefore,

⠀⠀⠀⠀⠀\begin{gathered}\qquad \therefore {\underline{ \sf \:Cost \:of\:Smartphone \:and \:feature \:phone \:are\:\bf Rs. \ 24,500 \:\& \: Rs.\: 9,750\:\:\sf , \ respectively . }}\\\end{gathered}

CostofSmartphoneandfeaturephoneareRs. 24,500&Rs.9,750, respectively.

21941.

(a)20with 12 as numerator25​

Answer»

Didn't GET the QUESTION

21942.

rita bought 4m 30cm cloth for a dress 2m 50cm for a blouse and 5m 25cm for a shirt how total cloth did she by.​

Answer»

Step-by-step explanation:

CLOTH LEFT with Tina = 20m 5CM - 4M 50cm

= (19m + 1m + 5cm) - (4m + 50cm)

= (19m + 100cm + 5cm) - (4m + 50cm)

= 19m + 105CM - 4m - 50cm

= 15m + 55cm

= 15m 55cm

21943.

Prove that the sum of 2 odd numbers is always even by 2 different methods​

Answer»

Answer:

Let the two ODD numbers be, 2a+1 and 2b+1. So, 2a+1 + 2b+1 = 2(a+b)+2 = 2(a+b+1), which is even. Hence, proven.

Step-by-step explanation:

I THINK HELPFUL to you ARMY

21944.

Direct methods are useful when(a) The system has a large number of variables and equations(b) The system has a small number of variables and equations(c) The system has sparseness in the coefficient matrix(d) None of the above​

Answer»

Answer:

The direct method of TEACHING, which is sometimes called the natural method, and is often (but not exclusively) USED in teaching foreign languages, REFRAINS from using the learners' native language and uses only the target language. ... In general, teaching focuses on the DEVELOPMENT of oral skills.

HOPE IT HELPS!!!

21945.

In a rhombus ABCD, AC and BD are 2 diagonals. If AC=8 cm, BD=5cm then area=​

Answer»

Answer:

20sq. CM

Step-by-step EXPLANATION:

AC=8cm

BD=5cm

area=(1/2×8×5)SQ. cm=40sq. cm

21946.

Solve question in elimination method 2x+y=11 and x+y=8​

Answer»

ANSWER:-

x=3\:\:and\:\:y=5

21947.

Write the number names 110045=​

Answer»

ANSWER:

MAKE me brainleast

Step-by-step explanation:

one lakh TEN THOUSAND forty five

21948.

Plz solve this anyone

Answer»

OK lemme TRY,

ARMY guys.

are u on weverse APP

21949.

6. By selling an article for Rs. 2250, a person losses10%. Find his gain or loss percent, if he sells it forRs. 3000.(a) 20%gain(b) 20% loss(c) 18% gain(d) 18% loss​

Answer»

Answer:20%

Step-by-step explanation:

90% of ORIGINAL price is 3375(since 10% is loss)

90/100 x x = 3375

9x/10 =3375

9x = 33750

x= 33750/9

= 3750 is original price =

Profit = 4500 - 3750

= 750

Profit %=(x-100)-3750

3750x75000

X= 75000/3750

Ans-profit % 20%

21950.

2,79,68,234 the number name in indian place value chart​

Answer»

Answer:

TWO HUNDRED SEVENTY nine crore SIXTY eight thousand two hundred thirty four