332354 + Interview Questions in Secondary School in Math Page 441 InterviewSolution

22001.	28. 2x - by = 4 અને 3x - 8y = 5 નો ચોકડી ગુણાકારની રીતે ઉકેલ મેળવો
Answer» ANSWER: by = 4 અને 3x - 8y = 5 નો ચોકડી ગુણાકારની રીતે ઉકેલ મેળવો . hope it will help you

22001.

28. 2x - by = 4 અને 3x - 8y = 5 નો ચોકડી ગુણાકારની રીતે ઉકેલ મેળવો

Answer»

ANSWER:

by = 4 અને 3x - 8y = 5 નો ચોકડી ગુણાકારની રીતે ઉકેલ મેળવો

.

hope it will help you

Discussion

22002.	Find the area of a rhombus whose diagonals are 20 cm and 10 cm
Answer» Step-by-step EXPLANATION: Area of rhombus =1/2 ×d1×d2 A=1/2×20×10 A=100cm² Please MARK me Brainliest and FOLLOW

22002.

Find the area of a rhombus whose diagonals are 20 cm and 10 cm

Answer»

Step-by-step EXPLANATION:

Area of rhombus =1/2 ×d1×d2

A=1/2×20×10

A=100cm²

Please MARK me Brainliest and FOLLOW

Discussion

22003.	Find the value of hemisphere having radius 14cm (π22/7)..?
Answer» Your ANSWER is in the IMAGE *PLEASE* *MARK* ME AS A *BRAINLIST* *AND* *FOLLOW* ME

22003.

Find the value of hemisphere having radius 14cm (π22/7)..?

Answer»

Your ANSWER is in the IMAGE

PLEASE MARK ME AS A BRAINLIST AND FOLLOW ME

Discussion

22004.	A pair of dice are rolled and recording the numbers that comes up. describe the events
Answer» ANSWER: The NUMBER that come up are ,1,2,3,4,5,6, because there are 6 sides on a DICE .

22004.

A pair of dice are rolled and recording the numbers that comes up. describe the events

Answer»

ANSWER:

The NUMBER that come up are ,1,2,3,4,5,6, because there are 6 sides on a DICE .

Discussion

22005.	The energy gap for silicon semiconductor is
Answer» Step-by-step explanation: here's your answer good AFTERNOON have a great DAY and TAKE care of yourself❤❤❤

22005.

The energy gap for silicon semiconductor is

Answer»

Step-by-step explanation:

here's your answer

good AFTERNOON have a great DAY and TAKE care of yourself❤❤❤

Discussion

22006.	Differentiate X2 sin x
Answer» SORRY I don't KNOW this ANSWER

Discussion

22007.	Fine the degree of polynomial6
Answer» Answer: 5 is the DEGREE of the POLYNOMIAL Step-by-step explanation: A degree of a polynomial is the highest exponent value PRESENT in the EQUATION.

22007.

Fine the degree of polynomial6

Answer»

Answer:

5 is the DEGREE of the POLYNOMIAL

Step-by-step explanation:

A degree of a polynomial is the highest exponent value PRESENT in the EQUATION.

Discussion

22008.	5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20712
Answer» Answer: 12333iipp0000988u33211

22008.

5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20712

Answer»

Answer:

12333iipp0000988u33211

Discussion

22009.	Write L•H•S and R•H•S of the simple equation
Answer» ANSWER: LHS=2x RHS=10 L.H.S= LEFT HAND Side R.H.S=Right hand Side Hope this is HELPFUL

22009.

Write L•H•S and R•H•S of the simple equation

Answer»

ANSWER:

LHS=2x

RHS=10

L.H.S= LEFT HAND Side

R.H.S=Right hand Side

Hope this is HELPFUL

Discussion

22010.	Plz give me answer que. 1
Answer» ANSWER: if you folow me i will folow you BACK

22010.

Plz give me answer que. 1

Answer»

ANSWER:

if you folow me i will folow you BACK

Discussion

22011.	True or false with statementi) X EA, A¢ B then X ERii) ACB, X does not belong to B then X does not belong toA
Answer» gdidhdixhxhxijsos to EAR a lot of a good day I am s s to KHAL dal kar di hahohehaaaa and rows of substances that the PRIME numbers up to the way you are not filtered into a part of substances and their families and friends and family welfare GOVT of substances

Discussion

22012.	Whats precipitation reaction???
Answer» A PRECIPITATION reaction refers to the formation of an insoluble salt when two SOLUTIONS containing soluble salts are combined. The insoluble salt that falls out of SOLUTION is known as the precipitate, hence the reaction's name. Precipitation REACTIONS can help determine the presence of VARIOUS ions in solution this meme is very old but still relatable

22012.

Whats precipitation reaction???

Answer»

A PRECIPITATION reaction refers to the formation of an insoluble salt when two SOLUTIONS containing soluble salts are combined. The insoluble salt that falls out of SOLUTION is known as the precipitate, hence the reaction's name. Precipitation REACTIONS can help determine the presence of VARIOUS ions in solution

this meme is very old but still relatable

Discussion

22013.	Adjoining figure ,the point q is in the ________of the circle
Answer» PLEASE POST the PICTURE DEAR.

22013.

Adjoining figure ,the point q is in the ________of the circle

Answer»

PLEASE POST the PICTURE DEAR.

Discussion

22014.	Adjoining figure ,the point q is in the interior of the circle
Answer» Answer: I THINK your I must be the SPOKEN English or Hindi is a point thank you X + x is equal to

22014.

Adjoining figure ,the point q is in the interior of the circle

Answer»

Answer:

I THINK your I must be the SPOKEN English or Hindi is a point thank you X + x is equal to

Discussion

22015.	for particular set of data , laspeyre index number is 137.288 and pasasche index number is 146.875 , then the drobish -bowely index number is
Answer» ANSWER: RITA bought 4m 30cm cloth for a DRESS 2M 50cm for a BLOUSE and 5m 25cm for a shirt how total cloth did she boy.

22015.

for particular set of data , laspeyre index number is 137.288 and pasasche index number is 146.875 , then the drobish -bowely index number is

Answer»

ANSWER:

RITA bought 4m 30cm cloth for a DRESS 2M 50cm for a BLOUSE and 5m 25cm for a shirt how total cloth did she boy.

Discussion

22016.	The compound ratio 3:4and inverse ratio of 4:5 is45:x find the x
Answer» ANSWER: OOOOOOOOOO hoooooooooo

22016.

The compound ratio 3:4and inverse ratio of 4:5 is45:x find the x

Answer»

ANSWER:

OOOOOOOOOO hoooooooooo

Discussion

22017.	Vedan14. The range of the principle value branch of the functionY=sin inverse x
Answer» Answer: We KNOW that the RANGE of the principal value branch of SIN-1(X) is (−π/2, π/2) and sin(π/4) = 1/√2. So, the principal value of sin-1(1/√2) = π/4. We know that the range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/2) = 1.09-Nov-2020

22017.

Vedan14. The range of the principle value branch of the functionY=sin inverse x

Answer»

Answer:

We KNOW that the RANGE of the principal value branch of SIN-1(X) is (−π/2, π/2) and sin(π/4) = 1/√2. So, the principal value of sin-1(1/√2) = π/4. We know that the range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/2) = 1.09-Nov-2020

Discussion

22018.	1. What is the menusure of a right angle?cast raight angle?
Answer» Answer: RIGHT ANGLES measure 90 DEGREES. OBTUSE angles measure more than 90 degrees.

22018.

1. What is the menusure of a right angle?cast raight angle?

Answer»

Answer:

RIGHT ANGLES measure 90 DEGREES. OBTUSE angles measure more than 90 degrees.

Discussion

22019.	Find the degree of the following polynomial -7x+ 5x+3x+2x+7
Answer» Step-by-step explanation: HIGHEST DEGREE of polynomial is 1 Please MARK me Brainliest and follow

22019.

Find the degree of the following polynomial -7x+ 5x+3x+2x+7

Answer»

Step-by-step explanation:

HIGHEST DEGREE of polynomial is 1

Please MARK me Brainliest and follow

Discussion

22020.	4. f(x) = 3x^2 + 5x + 7 then f(2)=
Answer» HOPE it HELPS you MARK me as BRAINLIEST

Discussion

22021.	49 is the successor of 50 true or false
Answer» ANSWER: FALSE Step-by-step EXPLANATION: MARK me as BRAINLIST

22021.

49 is the successor of 50 true or false

Answer»

ANSWER:

FALSE

Step-by-step EXPLANATION:

MARK me as BRAINLIST

Discussion

22022.	Find the difference of place value of 79 in 67989
Answer» the PLACE VALUE of the ANS - 78088

22022.

Find the difference of place value of 79 in 67989

Answer»

the PLACE VALUE of the

ANS - 78088

Discussion

22023.	Express in standard form 1) 60 * 10 ^ 32) 25.5 * 10 ^ 43) 0.15 * 10 ^ 2 4) 452 * 10 ^ - 1 5) 10.7 * 10 ^ - 3 6) 50.3 * 10 ^ 2 7) 1001 * 10 ^ - 2 8) 0.011 * 10 ^ - 1
Answer» ANSWER: CHECK the EXPLANATION for the answer Step-by-step explanation: 1) 60000 2) 255000 3) 15 4) 45.2 5) 0.0107 6) 5030 7) 10.01 8) 0.0011

22023.

Express in standard form 1) 60 * 10 ^ 32) 25.5 * 10 ^ 43) 0.15 * 10 ^ 2 4) 452 * 10 ^ - 1 5) 10.7 * 10 ^ - 3 6) 50.3 * 10 ^ 2 7) 1001 * 10 ^ - 2 8) 0.011 * 10 ^ - 1

Answer»

ANSWER:

CHECK the EXPLANATION for the answer

Step-by-step explanation:

1) 60000

2) 255000

3) 15

4) 45.2

5) 0.0107

6) 5030

7) 10.01

8) 0.0011

Discussion

22024.	The length of base edge of a square prism is 8 cm and its height is 10 cm.Find the total surface area of the prism.a)Base area of the prism.c) Number of bases.b) Area of one lateral face of the prism.d) Number of lateral facesTotal surface area of the prism = 2 x base area + lateral surface areae)+....sq. cm.
Answer» Answer: The length of BASE EDGE of a square prism is 8 cm and its height is 10 cm. Find the total surface AREA of the prism. a) Base area of the prism. c) NUMBER of bases. b) Area of ONE lateral face of the prism. d) Number of lateral faces Total surface area of the prism = 2 x base area + lateral surface area e) +.... sq. cm.The length of base edge of a square prism is 8 cm and its height is 10 cm. Find the total surface area of the prism. a) Base area of the prism. c) Number of bases. b) Area of one lateral face of the prism. d) Number of lateral faces Total surface area of the prism = 2 x base area + lateral surface area e) +.... sq. cm.

22024.

The length of base edge of a square prism is 8 cm and its height is 10 cm.Find the total surface area of the prism.a)Base area of the prism.c) Number of bases.b) Area of one lateral face of the prism.d) Number of lateral facesTotal surface area of the prism = 2 x base area + lateral surface areae)+....sq. cm.

Answer»

Answer:

The length of BASE EDGE of a square prism is 8 cm and its height is 10 cm.

Find the total surface AREA of the prism.

a)

Base area of the prism.

c) NUMBER of bases.

b) Area of ONE lateral face of the prism.

d) Number of lateral faces

Total surface area of the prism = 2 x base area + lateral surface area

e)

+....

sq. cm.The length of base edge of a square prism is 8 cm and its height is 10 cm.

Find the total surface area of the prism.

a)

Base area of the prism.

c) Number of bases.

b) Area of one lateral face of the prism.

d) Number of lateral faces

Total surface area of the prism = 2 x base area + lateral surface area

e)

+....

sq. cm.

Discussion

22025.	Guys please reply fastly...
Answer» In GEOMETRY, a polygon is a plane figure that is DESCRIBED by a FINITE number of straight line segments connected to form a closed polygonal chain or polygonal circuit. The solid plane region, the bounding circuit, or the TWO together, may be called a polygon 1) 180-144 = 36

22025.

Guys please reply fastly...

Answer»

In GEOMETRY, a polygon is a plane figure that is DESCRIBED by a FINITE number of straight line segments connected to form a closed polygonal chain or polygonal circuit. The solid plane region, the bounding circuit, or the TWO together, may be called a polygon

1) 180-144 = 36

Discussion

22026.	3. 6x³ - 11x² + 7x + 5 by 2x-1 verify
Answer» 6x^3_11x^2+7x+5÷2×-3 3x^2/-x+5

Discussion

22027.	2x^2-5root2x+4=0 find discriminant
Answer» ANSWER: Step-by-step explanation: Discriminant \begin{gathered} = \sqrt{ {B}^{2} - 4AC} \\ = \sqrt{ {5}^{2} - 4 \times 2 \times 4 } \\ = \sqrt{25 - 32} \\ = \sqrt{ - 7} \end{gathered} = b 2 −4ac = 5 2 −4×2×4 = 25−32 = −7

22027.

2x^2-5root2x+4=0 find discriminant

Answer»

ANSWER:

Step-by-step explanation:

Discriminant

\begin{gathered} = \sqrt{ {B}^{2} - 4AC} \\ = \sqrt{ {5}^{2} - 4 \times 2 \times 4 } \\ = \sqrt{25 - 32} \\ = \sqrt{ - 7} \end{gathered}

=

b

2

−4ac

=

5

2

−4×2×4

=

25−32

=

−7

Discussion

22028.	What is the derivative of sec^-1x w.r.t. x if x
Answer» ANSWER: $\frac{dy}{dx} { \sec }^{ - 1} x \\ \\ = \frac{1}{x \sqrt{ {x}^{2} + 1} } \\ \\ = \frac{1}{ - x \sqrt{ {( - x)}^{2} + 1 }} \: \: \: (cause \: \: x < - 1)\\ \\ = - \frac{1}{x \sqrt{ {x}^{2} + 1 } }$

22028.

What is the derivative of sec^-1x w.r.t. x if x

Answer»

ANSWER:

$\frac{dy}{dx} { \sec }^{ - 1} x \\ \\ = \frac{1}{x \sqrt{ {x}^{2} + 1} } \\ \\ = \frac{1}{ - x \sqrt{ {( - x)}^{2} + 1 }} \: \: \: (cause \: \: x < - 1)\\ \\ = - \frac{1}{x \sqrt{ {x}^{2} + 1 } }$

Discussion

22029.	Johny invested 50,000 rupees, Jaleel 40,000 rupees and Jayan invested 30,000 rupees to start a business. What is the ratio of their investment
Answer» ANSWER: RATIO of their INVESTMENT = 5: 4:3 RESPECTIVELY

22029.

Johny invested 50,000 rupees, Jaleel 40,000 rupees and Jayan invested 30,000 rupees to start a business. What is the ratio of their investment

Answer»

ANSWER:

RATIO of their INVESTMENT = 5: 4:3 RESPECTIVELY

Discussion

22030.	Solve by Gaussian elimination method 2x-y+z=2,6x-3y+3z=6,4x-2y+2z=4.
Answer» ANSWER: REFER to the above ATTACHMENT HOPE it HELPS you.

22030.

Solve by Gaussian elimination method 2x-y+z=2,6x-3y+3z=6,4x-2y+2z=4.

Answer»

ANSWER:

REFER to the above ATTACHMENT

HOPE it HELPS you.

Discussion

22031.	Koi hai jinda. hai kya. ho toh batao
Answer» Answer: haa JINDA HU me Step-by-step explanation: The branches of science, also referred to as sciences, "scientific fields", or "scientific disciplines," are commonly DIVIDED into three major groups: Formal sciences: the study of formal systems, such as those under the branches of logic and mathematics, which use an a priori, as opposed to empirical, methodology. Formal sciences include mathematics, machine sciences (e.g. computer science), etc. Natural sciences: the study of natural phenomena (including cosmological, GEOLOGICAL, PHYSICAL, chemical, and biological factors of the universe). Natural science can be divided into two main branches: physical science and life science (or biological science). Social sciences: the study of human behavior in its social and cultural aspects.[1] The scale of the Universe mapped to branches of science and showing how one system is built atop the next through the hierarchy of the sciences. Natural and social sciences are empirical sciences, meaning that the knowledge must be based on observable phenomena and must be capable of being verified by other researchers working under the same conditions.[2] This verifiability may well vary even within a scientific discipline[3][4] Natural, social, and formal science make up the fundamental sciences, which form the basis of interdisciplinary and applied sciences such as engineering and medicine. Specialized scientific disciplines that exist in multiple categories may include parts of other scientific disciplines but often possess their own terminologies and expertises.[5]

22031.

Koi hai jinda. hai kya. ho toh batao

Answer»

Answer:

haa JINDA HU me

Step-by-step explanation:

The branches of science, also referred to as sciences, "scientific fields", or "scientific disciplines," are commonly DIVIDED into three major groups:

Formal sciences: the study of formal systems, such as those under the branches of logic and mathematics, which use an a priori, as opposed to empirical, methodology. Formal sciences include mathematics, machine sciences (e.g. computer science), etc.

Natural sciences: the study of natural phenomena (including cosmological, GEOLOGICAL, PHYSICAL, chemical, and biological factors of the universe). Natural science can be divided into two main branches: physical science and life science (or biological science).

Social sciences: the study of human behavior in its social and cultural aspects.[1]

The scale of the Universe mapped to branches of science and showing how one system is built atop the next through the hierarchy of the sciences.

Natural and social sciences are empirical sciences, meaning that the knowledge must be based on observable phenomena and must be capable of being verified by other researchers working under the same conditions.[2] This verifiability may well vary even within a scientific discipline[3][4]

Natural, social, and formal science make up the fundamental sciences, which form the basis of interdisciplinary and applied sciences such as engineering and medicine. Specialized scientific disciplines that exist in multiple categories may include parts of other scientific disciplines but often possess their own terminologies and expertises.[5]

Discussion

22032.	Represent the set of all natural number in in 1)set builder form and 2)roster form
Answer» Answer: HOPE this HELPS you have a NICE day

22032.

Represent the set of all natural number in in 1)set builder form and 2)roster form

Answer»

Answer:

HOPE this HELPS you

have a NICE day

Discussion

22033.	Which one is greater?A)1by2 of 4by7 OR B)2by3 of 3by7
Answer» Answer: HEY mate here is the answer Step-by-step explanation: Both are same Both are having same value of 2/7 HENCE A= B Hope it HELPS you plZ Mark me as brainliest and follow plZ LEAVE a THANKS

22033.

Which one is greater?A)1by2 of 4by7 OR B)2by3 of 3by7

Answer»

Answer:

HEY mate here is the answer

Step-by-step explanation:

Both are same

Both are having same value of 2/7

HENCE A= B

Hope it HELPS you

plZ Mark me as brainliest and follow

plZ LEAVE a THANKS

Discussion

22034.	If x=8-√ 60, then1/2[√x+2/√x]=
Answer» ANSWER: X = 8 - √60 = 8 - 2√15 = √3² + √5² -2√3.√5 = (√5 -√3)² now , 1/2 [ ( √x + 2)/√x ] = 1/2[ {√(√5 -√3 )² +2}/√(√5 -√3)² ] = 1/2[ ( √5 -√3 +2)/(√5 -√3)] = 1/2 [ ( √5-√3 +2)(√5 +√3)/(√5² -√3²)] = 1/2[ ( √5² -√3² +2√5 +2√3)/2 ] = 1/2 ( √5 +√3 +1 )

22034.

If x=8-√ 60, then1/2[√x+2/√x]=

Answer»

ANSWER: X = 8 - √60 = 8 - 2√15 = √3² + √5² -2√3.√5 = (√5 -√3)²

now ,

1/2 [ ( √x + 2)/√x ]

= 1/2[ {√(√5 -√3 )² +2}/√(√5 -√3)² ]

= 1/2[ ( √5 -√3 +2)/(√5 -√3)]

= 1/2 [ ( √5-√3 +2)(√5 +√3)/(√5² -√3²)]

= 1/2[ ( √5² -√3² +2√5 +2√3)/2 ]

= 1/2 ( √5 +√3 +1 )

Discussion

22035.	If there are 6 spokes in a wheel, the angle formed between the pairs ofconsecutive spokes is 60°.Find the angle formed between the pairs ofconsecutive spokes, if there are(i) a) 12 spokes b) 15 spokesc) 10 spokes(ii) Are the number of spokes and the angle formed between the pairs ofconsecutive spokes in inverse proportion?
Answer» ANSWER: so jcxgsykdyfifysyfiigfyfjuddkfhdgstdydysjfjdhsydtshc

22035.

If there are 6 spokes in a wheel, the angle formed between the pairs ofconsecutive spokes is 60°.Find the angle formed between the pairs ofconsecutive spokes, if there are(i) a) 12 spokes b) 15 spokesc) 10 spokes(ii) Are the number of spokes and the angle formed between the pairs ofconsecutive spokes in inverse proportion?

Answer»

ANSWER:

so jcxgsykdyfifysyfiigfyfjuddkfhdgstdydysjfjdhsydtshc

Discussion

22036.	The maximum value of y = x3 - 9x2 + 24x + 2 is
Answer» Step-by-step EXPLANATION: F(X)=x3-9x2+24 x+12f (x)=d/d x(x^3-9x^2+24x+12).=3×2-9× 2x+24×1+0=3×2-18x+24=3(x2-6x+8) f.

22036.

The maximum value of y = x3 - 9x2 + 24x + 2 is

Answer»

Step-by-step EXPLANATION:

F(X)=x3-9x2+24 x+12f (x)=d/d x(x^3-9x^2+24x+12).=3×2-9× 2x+24×1+0=3×2-18x+24=3(x2-6x+8) f.

Discussion

22037.	4.5 x 104^4 write in usual form
Answer» ANSWER: ì Step-by-step explanation: 1✍‍‍‍‍‍‍‍♀️‍♀️‍♂️‍♂️‍♂️‍♀️‍♀️‍♀️‍♂️‍♂️‍♂️‍♂️‍♂️‍♀️‍♂️‍♀️‍♂️‍♀️‍♂️‍♂️‍♀️‍♀️‍♀️‍♂️⚽️⚾️⤵️️‍‍♀️‍♀️‍♂️⛹‍♂️‍♂️‍♀️‍⬛‍⬛‍⬛‍⬛‍♂️‍♂️

22037.

4.5 x 104^4 write in usual form

Answer»

ANSWER:

ì

Step-by-step explanation:

1✍‍‍‍‍‍‍‍♀️‍♀️‍♂️‍♂️‍♂️‍♀️‍♀️‍♀️‍♂️‍♂️‍♂️‍♂️‍♂️‍♀️‍♂️‍♀️‍♂️‍♀️‍♂️‍♂️‍♀️‍♀️‍♀️‍♂️⚽️⚾️⤵️️‍‍♀️‍♀️‍♂️⛹‍♂️‍♂️‍♀️‍⬛‍⬛‍⬛‍⬛‍♂️‍♂️

Discussion

22038.	Evaluate 3√27+3√0.008-3√0.000064
Answer» ANSWER: OK we will HELP you WRITE down

22038.

Evaluate 3√27+3√0.008-3√0.000064

Answer»

ANSWER:

OK we will HELP you WRITE down

Discussion

22039.	10. Using proper identity, the expansion of (x + 5) (x – 3) (x-2) is
Answer» ANSWER: , $x ^{3 } + 4x ^{2} - 11x - 30$

22039.

10. Using proper identity, the expansion of (x + 5) (x – 3) (x-2) is

Answer»

ANSWER:

,

$x ^{3 } + 4x ^{2} - 11x - 30$

Discussion

22040.	11. Verify the following:6.-4 -4#143 13 76-4-4•은143137
Answer» ANSWER: dajidawakasusishqusshoyitsitrrsursurzit

22040.

11. Verify the following:6.-4 -4#143 13 76-4-4•은143137

Answer»

ANSWER:

dajidawakasusishqusshoyitsitrrsursurzit

Discussion

22041.	Find the next number in the series 0,1,1,2,3,7,....
Answer» Answer: 15 Step-by-step explanation: 0+1=1,1+2=3,3+4=7,7+8=15

22041.

Find the next number in the series 0,1,1,2,3,7,....

Answer»

Answer:

15

Step-by-step explanation:

0+1=1,1+2=3,3+4=7,7+8=15

Discussion

22042.	Q.4 evaluate of thefollowing (1) sin 30° xcos45°X tan360º =
Answer» Answer: sin 30 X COS 45 x tan 360 = sin 30 x cos 45 x 0 [ tan 360 = 0 ] = 0 Step-by-step explanation: 0 x something = 0

22042.

Q.4 evaluate of thefollowing (1) sin 30° xcos45°X tan360º =

Answer»

Answer:

sin 30 X COS 45 x tan 360

= sin 30 x cos 45 x 0 [ tan 360 = 0 ]

= 0

Step-by-step explanation:

0 x something = 0

Discussion

22043.	3x+4y=7 2x+y=-2elimnation
Answer» 3x+4y=7 ---------(1) 2x+y=-2 ----------(2) By MULTIPLYING 4 in EQUN. (2) 4(2x+y=-2) 8x+4y=-8 ---------(3) By substracting equn. (1) from equn (3) 8x+4y=-2 -3x-4y=-7 _________ 5x. =-9 x=-9/5

22043.

3x+4y=7 2x+y=-2elimnation

Answer»

3x+4y=7 ---------(1)

2x+y=-2 ----------(2)

By MULTIPLYING 4 in EQUN. (2)

4(2x+y=-2)

8x+4y=-8 ---------(3)

By substracting equn. (1) from equn (3)

8x+4y=-2

-3x-4y=-7

_________

5x. =-9

x=-9/5

Discussion

22044.	Question: 5Calculate the observations which areabove 75% of the data20, 10, 15, 13, 10,5, 4
Answer» ANSWER: FIND the ATTACHMENT above thanks

22044.

Question: 5Calculate the observations which areabove 75% of the data20, 10, 15, 13, 10,5, 4

Answer»

ANSWER:

FIND the ATTACHMENT above

thanks

Discussion

22045.	Exponental form of log5 125 =3
Answer» ANSWER: log5125=3 can be REWRITTEN as 53=125 .

22045.

Exponental form of log5 125 =3

Answer»

ANSWER:

log5125=3 can be REWRITTEN as 53=125 .

Discussion

22046.	Find the value of x if 52x× 52 = 3125
Answer» ANSWER: 260 HAI ISKA answer SOLVE

22046.

Find the value of x if 52x× 52 = 3125

Answer»

ANSWER:

260 HAI ISKA answer SOLVE

Discussion

22047.	The sum of the zeroes of the quadratic polynomial 2x²-8x+6x is
Answer» The POLYNOMIAL 2x^2-8x+6=0. THEREFORE SUM of ZEROES of above polynomial is -(-8)/2=8/2=4.

22047.

The sum of the zeroes of the quadratic polynomial 2x²-8x+6x is

Answer»

The POLYNOMIAL 2x^2-8x+6=0. THEREFORE SUM of ZEROES of above polynomial is -(-8)/2=8/2=4.

Discussion

22048.	Find p if 9/11-p=5/13
Answer» HOPE it HELPS you MARK me as BRAINLIEST

Discussion

22049.	Evaluate (-5)4×(-5)2 with method
Answer» (-5)^4 ×(-5)^2 identity: a^m×a^n= a^mn -5^8 is answer hope it HELPS you..

22049.

Evaluate (-5)4×(-5)2 with method

Answer»

(-5)^4 ×(-5)^2

identity: a^m×a^n= a^mn

-5^8 is answer

hope it HELPS you..

Discussion

22050.	If cosA-sinA=√2sinA.show that, cosecA=2√2cosA
Answer» GIVEN :- $\rm :\longmapsto\:cosA - sinA = \sqrt{2} sinA$ To Show :- $\rm :\longmapsto\:cosecA = 2 \sqrt{2}cosA$ Formula Used :- $\boxed{ \sf \: {cosec}^{2}x - {cot}^{2}x = <klux>1</klux>}$ $\boxed{ \sf \: cotx = \dfrac{cosx}{sinx}}$ $\boxed{ \sf \: cosecx = \dfrac{1}{sinx}}$ Solution :- Given that, $\rm :\longmapsto\:cosA - sinA = \sqrt{2} sinA$ $\rm :\longmapsto\:cosA = \sqrt{2} sinA + sinA$ $\rm :\longmapsto\:cosA = ( \sqrt{2} +1) sinA$ $\rm :\longmapsto\:\dfrac{cosA}{sinA} = \sqrt{2} + 1$ $\rm :\longmapsto\:cotA = \sqrt{2} +1 - - (1)$ We know, $\rm :\longmapsto\: {cosec}^{2}A = 1 + {cot}^{2}A$ $\rm :\longmapsto\: {cosec}^{2}A = 1 + {( \sqrt{2} + 1)}^{2}$ $\rm :\longmapsto\: {cosec}^{2}A = 1 + 2 + 1 + 2 \sqrt{2}$ $\rm :\longmapsto\: {cosec}^{2}A = 4 + 2 \sqrt{2}$ $\rm :\longmapsto\:cosecA = \sqrt{4 + 2 \sqrt{2} }$ $\rm :\longmapsto\:cosecA = \sqrt{2} \sqrt{2 + \sqrt{2} } - - (2)$ Now, From equation (1), we have $\rm :\longmapsto\:cotA = \sqrt{2} +1$ $\rm :\longmapsto\: \dfrac{cosA}{sinA} = \sqrt{2} +1$ $\rm :\longmapsto\:cosA \times cosecA = \sqrt{2} + 1$ can be rewritten as, $\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times {cosec}^{2}A = \sqrt{2} + 1$ $\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2(2 + \sqrt{2}) = \sqrt{2} + 1$ $\: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because\:cosecA = \sqrt{2} \sqrt{2 + \sqrt{2} } }$ $\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2( \sqrt{2} \times \sqrt{2} + \sqrt{2}) = \sqrt{2} + 1$ $\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2 \sqrt{2} \: \: \cancel{( \sqrt{2}+1)} = \cancel{\sqrt{2} + 1}$ $\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2 \sqrt{2} = 1$ $\bf\implies \:cosecA = 2 \sqrt{2}cosA$ ${{\boxed{\bf{Hence, Proved}}}}$ Additional Information:- Relationship between sides and T RATIOS sin θ = Opposite Side/Hypotenuse cos θ = Adjacent Side/Hypotenuse tan θ = Opposite Side/Adjacent Side sec θ = Hypotenuse/Adjacent Side cosec θ = Hypotenuse/Opposite Side cot θ = Adjacent Side/Opposite Side Reciprocal IDENTITIES cosec θ = 1/sin θ sec θ = 1/cos θ cot θ = 1/tan θ sin θ = 1/cosec θ cos θ = 1/sec θ tan θ = 1/cot θ Co-function Identities sin (90°−x) = cos x cos (90°−x) = sin x tan (90°−x) = cot x cot (90°−x) = tan x sec (90°−x) = cosec x cosec (90°−x) = sec x Fundamental Trigonometric Identities sin²θ + cos²θ = 1 sec²θ - tan²θ = 1 cosec²θ - cot²θ = 1

22050.

If cosA-sinA=√2sinA.show that, cosecA=2√2cosA

Answer»

GIVEN :-

$\rm :\longmapsto\:cosA - sinA = \sqrt{2} sinA$

To Show :-

$\rm :\longmapsto\:cosecA = 2 \sqrt{2}cosA$

Formula Used :-

$\boxed{ \sf \: {cosec}^{2}x - {cot}^{2}x = <klux>1</klux>}$

$\boxed{ \sf \: cotx = \dfrac{cosx}{sinx}}$

$\boxed{ \sf \: cosecx = \dfrac{1}{sinx}}$

Solution :-

Given that,

$\rm :\longmapsto\:cosA - sinA = \sqrt{2} sinA$

$\rm :\longmapsto\:cosA = \sqrt{2} sinA + sinA$

$\rm :\longmapsto\:cosA = ( \sqrt{2} +1) sinA$

$\rm :\longmapsto\:\dfrac{cosA}{sinA} = \sqrt{2} + 1$

$\rm :\longmapsto\:cotA = \sqrt{2} +1 - - (1)$

We know,

$\rm :\longmapsto\: {cosec}^{2}A = 1 + {cot}^{2}A$

$\rm :\longmapsto\: {cosec}^{2}A = 1 + {( \sqrt{2} + 1)}^{2}$

$\rm :\longmapsto\: {cosec}^{2}A = 1 + 2 + 1 + 2 \sqrt{2}$

$\rm :\longmapsto\: {cosec}^{2}A = 4 + 2 \sqrt{2}$

$\rm :\longmapsto\:cosecA = \sqrt{4 + 2 \sqrt{2} }$

$\rm :\longmapsto\:cosecA = \sqrt{2} \sqrt{2 + \sqrt{2} } - - (2)$

Now,

From equation (1), we have

$\rm :\longmapsto\:cotA = \sqrt{2} +1$

$\rm :\longmapsto\: \dfrac{cosA}{sinA} = \sqrt{2} +1$

$\rm :\longmapsto\:cosA \times cosecA = \sqrt{2} + 1$

can be rewritten as,

$\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times {cosec}^{2}A = \sqrt{2} + 1$

$\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2(2 + \sqrt{2}) = \sqrt{2} + 1$

$\: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because\:cosecA = \sqrt{2} \sqrt{2 + \sqrt{2} } }$

$\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2( \sqrt{2} \times \sqrt{2} + \sqrt{2}) = \sqrt{2} + 1$

$\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2 \sqrt{2} \: \: \cancel{( \sqrt{2}+1)} = \cancel{\sqrt{2} + 1}$

$\rm :\longmapsto\:\dfrac{cosA}{cosecA} \times 2 \sqrt{2} = 1$

$\bf\implies \:cosecA = 2 \sqrt{2}cosA$

${{\boxed{\bf{Hence, Proved}}}}$

Additional Information:-

Relationship between sides and T RATIOS

sin θ = Opposite Side/Hypotenuse

cos θ = Adjacent Side/Hypotenuse

tan θ = Opposite Side/Adjacent Side

sec θ = Hypotenuse/Adjacent Side

cosec θ = Hypotenuse/Opposite Side

cot θ = Adjacent Side/Opposite Side

Reciprocal IDENTITIES

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

sin θ = 1/cosec θ

cos θ = 1/sec θ

tan θ = 1/cot θ

Co-function Identities

sin (90°−x) = cos x

cos (90°−x) = sin x

tan (90°−x) = cot x

cot (90°−x) = tan x

sec (90°−x) = cosec x

cosec (90°−x) = sec x

Fundamental Trigonometric Identities

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

cosec²θ - cot²θ = 1

Discussion

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