332354 + Interview Questions in Secondary School in Math Page 447 InterviewSolution

22301.	X+y = a+b, ax+by = a2 +b2
Answer» 12345678901234567890

Discussion

22302.	If u = x y² + Y cosx + 5valueischy
Answer» ANSWER: nghjjhgjhhjkj n j kjh gf nhjkjhjkl kjhghjkl;';l Step-by-step EXPLANATION:

22302.

If u = x y² + Y cosx + 5valueischy

Answer»

ANSWER:

nghjjhgjhhjkj

n

j

kjh

gf nhjkjhjkl

kjhghjkl;';l

Step-by-step EXPLANATION:

Discussion

22303.	What number should be added to 3x3 - 4x2 - 5x so that (x - 2) is a factor?
Answer» ANSWER: I don't KINK Soryyyyyyyyy

22303.

What number should be added to 3x3 - 4x2 - 5x so that (x - 2) is a factor?

Answer»

ANSWER:

I don't KINK Soryyyyyyyyy

Discussion

22304.	Gardener wishes to plant 6096 plants in the form of a square and found that there were 12 plants left how manplant were planted in each row?
Answer» Answer: CORRECT option is A 91 Say X plants are in a row and there are x number of rows since the plants are planted in a SQUARE then 8 plants left. Hence, x 2 =8289−8=8281 x=91. So, 91 plants are planted in a row.

22304.

Gardener wishes to plant 6096 plants in the form of a square and found that there were 12 plants left how manplant were planted in each row?

Answer»

Answer:

CORRECT option is

A

91

Say X plants are in a row and there are x number of rows since the plants are planted in a SQUARE then 8 plants left.

Hence, x

2

=8289−8=8281

x=91.

So, 91 plants are planted in a row.

Discussion

22305.	Estimate each of the following sum to the nearest hundreds(a) 367 + 564 (b) 872 + 569 (C) 852 + 769 (d) 5,139 + 7,653
Answer» Answer: 900 ; 1,400 ; 1,600 ; 12,800 Step-by-step explanation: (a) 367 + 564 = 931 = 900 (B) 872 + 569 = 1,441 = 1,400 (C) 852 + 769 = 1,621 = 1,600 (d) 5,139 + 7,653 = 12,792 = 12,800

22305.

Estimate each of the following sum to the nearest hundreds(a) 367 + 564 (b) 872 + 569 (C) 852 + 769 (d) 5,139 + 7,653

Answer»

Answer:

900 ; 1,400 ; 1,600 ; 12,800

Step-by-step explanation:

(a) 367 + 564 = 931 = 900

(B) 872 + 569 = 1,441 = 1,400

(C) 852 + 769 = 1,621 = 1,600

(d) 5,139 + 7,653 = 12,792 = 12,800

Discussion

22306.	Note: Spam answer will be reported immidetly So no spamA surface with measures 80cm x 48 cm x 24 cm is to be covered with a Tarpaulin cloth. How many metres of tarpaulin ofwidth 96 cm is required to cover 100 such suitcases?
Answer» ANSWER: Total surface area of a suitcase = 2(lb + bh + HL) = 2(80 X 48 + 48 x 24 + 24 x 80) = 2(3840 + 1152 + 1920) cm2 = 2(6912) cm2 = 13824 cm2 ∴ Total S.A. of 100 suitcases = 100 x 13824 cm2 = 1382400 cm2 Surface area of 1 m of TARPAULIN = 100 cm x 96 cm = 9600 cm2 i.e. 1 m of tarpaulin can cover 9600 cm2 surface ∴ 1382400 over 9600 metres of tarpaulin will cover the total surfaces of 100 suitcases i.e. 1 m of tarpaulin can cover 9600 cm2 surface ∴ 1382400/9600 metres of tarpaulin will cover the total surfaces of 100 suitcases i.e. 1382400/9600 or 144 metres of tarpaulin will be required to cover 100 suitcases.

22306.

Note: Spam answer will be reported immidetly So no spamA surface with measures 80cm x 48 cm x 24 cm is to be covered with a Tarpaulin cloth. How many metres of tarpaulin ofwidth 96 cm is required to cover 100 such suitcases?

Answer»

ANSWER:

Total surface area of a suitcase = 2(lb + bh + HL)

= 2(80 X 48 + 48 x 24 + 24 x 80)

= 2(3840 + 1152 + 1920) cm2

= 2(6912) cm2

= 13824 cm2

∴ Total S.A. of 100 suitcases = 100 x 13824 cm2 = 1382400 cm2

Surface area of 1 m of TARPAULIN = 100 cm x 96 cm

= 9600 cm2

i.e. 1 m of tarpaulin can cover 9600 cm2 surface

∴ 1382400 over 9600 metres of tarpaulin will cover the total surfaces of 100 suitcases

i.e. 1 m of tarpaulin can cover 9600 cm2 surface

∴ 1382400/9600 metres of tarpaulin will cover the total surfaces of 100 suitcases

i.e. 1382400/9600 or 144 metres of tarpaulin will be required to cover 100 suitcases.

Discussion

22307.	85346 ml into litres and millilitres
Answer» Answer: thus in LITRES = 85.34600 litres it is ALREADY in ML thanks

22307.

85346 ml into litres and millilitres

Answer»

Answer:

thus in LITRES = 85.34600 litres

it is ALREADY in ML

thanks

Discussion

22308.	Through the point of contact of a tangent to a circle, a chord is drawn.Show that the perpendiculars drawn from the midpoint of any arc of the circlemade by the chord to the tangent and the chord are equal.
Answer» ANSWER: HOPE this is HELPFUL to you....

22308.

Through the point of contact of a tangent to a circle, a chord is drawn.Show that the perpendiculars drawn from the midpoint of any arc of the circlemade by the chord to the tangent and the chord are equal.

Answer»

ANSWER:

HOPE this is HELPFUL to you....

Discussion

22309.	Ax3 +4x2+3x-14 and x4- 4x+2 leave the same reminder when divided by find find the value of a
Answer» ANSWER: jejehheh3gbwkqowjhehebnehehhegevgwhshhsbvhklhbebeggeyjlj Step-by-step EXPLANATION: hdhjwkowi82765901863

22309.

Ax3 +4x2+3x-14 and x4- 4x+2 leave the same reminder when divided by find find the value of a

Answer»

ANSWER:

jejehheh3gbwkqowjhehebnehehhegevgwhshhsbvhklhbebeggeyjlj

Step-by-step EXPLANATION:

hdhjwkowi82765901863

Discussion

22310.	Ascending order 363636 ,366363
Answer» Answer: *366363<363636* Step-by-step EXPLANATION: *MARK ME THE BRAINLIEST*

22310.

Ascending order 363636 ,366363

Answer»

Answer:

366363<363636

Step-by-step EXPLANATION:

MARK ME THE BRAINLIEST

Discussion

22311.	The HCF and LCM of 404 and 96 _____ *4, 9624, 1014, 969696, 404
Answer» Answer: 4,9696. *hope* it helps you

22311.

The HCF and LCM of 404 and 96 _____ *4, 9624, 1014, 969696, 404

Answer»

Answer:

4,9696.

hope it helps you

Discussion

22312.	. If y= log(ax + b), find y"'
Answer» ANSWER: y'=a/(AX+b) y''=-ax/(ax+b)^2 y"'=[ -a(ax+b)^2+2ax^2(ax+b)]/(ax+b)^4 hope it HELPS U dear☺️☺️☺️

22312.

. If y= log(ax + b), find y"'

Answer»

ANSWER:

y'=a/(AX+b)

y''=-ax/(ax+b)^2

y"'=[ -a(ax+b)^2+2ax^2(ax+b)]/(ax+b)^4

hope it HELPS U dear☺️☺️☺️

Discussion

22313.	Simplify 1) √80 + √48 − √45 − √27
Answer» Step-by-step EXPLANATION: √80+√48-√45-√27 = 3.96811878507

22313.

Simplify 1) √80 + √48 − √45 − √27

Answer»

Step-by-step EXPLANATION:

√80+√48-√45-√27

= 3.96811878507

Discussion

22314.	Find the sum of the roots of ax2 = b.
Answer» SOLUTION TO DETERMINE The sum of the roots of ax² = B CONCEPT TO BE IMPLEMENTED We KNOW that a general quadratic equation is of the form Ax² + Bx + C = 0 Then $\displaystyle\sf{ Sum \: of \: the \: roots \: = - \frac{B}{A} }$ $\displaystyle\sf{ Product \: of \: the \: roots \: = \frac{C}{A} }$ EVALUATION Here the given equation is ax² = b Comparing with the equation Ax² + Bx + C = 0 we GET A = a , B = 0 & C = - b $\displaystyle\sf{ Sum \: of \: the \: roots \: = - \frac{B}{A} }$ $\displaystyle\sf{ \implies \: Sum \: of \: the \: roots \: = - \frac{0}{a} }$ $\displaystyle\sf{ \implies \: Sum \: of \: the \: roots \: =0}$ ━━━━━━━━━━━━━━━━ Learn more from BRAINLY :- 1. Form a quadratic equation such that one of its roots is 5. Forma quadratic equation for it and write. brainly.in/question/38226428 2. If p = 1 and q = –2 are roots of a quadratic equation, then quadratic equation will be brainly.in/question/39283719

22314.

Find the sum of the roots of ax2 = b.

Answer»

SOLUTION

TO DETERMINE

The sum of the roots of ax² = B

CONCEPT TO BE IMPLEMENTED

We KNOW that a general quadratic equation is of the form

Ax² + Bx + C = 0

Then

$\displaystyle\sf{ Sum \: of \: the \: roots \: = - \frac{B}{A} }$

$\displaystyle\sf{ Product \: of \: the \: roots \: = \frac{C}{A} }$

EVALUATION

Here the given equation is ax² = b

Comparing with the equation Ax² + Bx + C = 0 we GET

A = a , B = 0 & C = - b

$\displaystyle\sf{ Sum \: of \: the \: roots \: = - \frac{B}{A} }$

$\displaystyle\sf{ \implies \: Sum \: of \: the \: roots \: = - \frac{0}{a} }$

$\displaystyle\sf{ \implies \: Sum \: of \: the \: roots \: =0}$

━━━━━━━━━━━━━━━━

Learn more from BRAINLY :-

1. Form a quadratic equation such that one of its roots is 5. Forma quadratic equation for it and write.

brainly.in/question/38226428

2. If p = 1 and q = –2 are roots of a quadratic equation, then quadratic equation will be

brainly.in/question/39283719

Discussion

22315.	1. Find three rational numbers between -3/7 and -2/7
Answer» Answer: Step-by-step explanation: To find : Three rational number between and ? SOLUTION : We MULTIPLY numerator and DENOMINATOR by 4, Now, the numbers between -12 and -8 are -11,-10,-9. Therefore, the three rational number between and are .

22315.

1. Find three rational numbers between -3/7 and -2/7

Answer»

Answer:

Step-by-step explanation:

To find : Three rational number between and ?

SOLUTION :

We MULTIPLY numerator and DENOMINATOR by 4,

Now, the numbers between -12 and -8 are -11,-10,-9.

Therefore, the three rational number between and are .

Discussion

22316.	9.4) =show that: 4sinθcos^3θ - 4cosθ sin^3θ =sin4θ
Answer» Step-by-step EXPLANATION: To PROVE : 4sinθcos³θ - 4cosθ sin³θ = sin4θ take LHS = 4sinθcos³θ - 4cosθ sin³θ = 2sinθcosθ (2cos²θ-2sin²θ) = sin2θ. 2 .(cos²θ - sin²θ) [ ∵ sin2θ = 2sinθcosθ ] = 2 sin2θ cos2θ [ ∵ cos2θ = cos²θ - sin²θ ] = sin2(2θ) = sin4θ = RHS => LHS = RHS. Hence proved

22316.

9.4) =show that: 4sinθcos^3θ - 4cosθ sin^3θ =sin4θ

Answer»

Step-by-step EXPLANATION:

To PROVE : 4sinθcos³θ - 4cosθ sin³θ = sin4θ

take LHS

= 4sinθcos³θ - 4cosθ sin³θ

= 2sinθcosθ (2cos²θ-2sin²θ)

= sin2θ. 2 .(cos²θ - sin²θ) [ ∵ sin2θ = 2sinθcosθ ]

= 2 sin2θ cos2θ [ ∵ cos2θ = cos²θ - sin²θ ]

= sin2(2θ)

= sin4θ

= RHS

=> LHS = RHS.

Hence proved

Discussion

22317.	The point at which the profit is zero is called the __ point
Answer» Answer: You can contribute to the efforts against DEFORESTATION by doing these EASY steps: Plant a TREE where you can. Go paperless at home and in the office. Buy recycled products and then recycle them again. Buy certified wood products. ... Support the products of COMPANIES that are committed to reducing deforest Step-by-step explanation: You can contribute to the efforts against deforestation by doing these easy steps: Plant a Tree where you can. Go paperless at home and in the office. Buy recycled products and then recycle them again. Buy certified wood products. ... Support the products of companies that are committed to reducing deforest please mark as brainlist bro

22317.

The point at which the profit is zero is called the __ point

Answer»

Answer:

You can contribute to the efforts against DEFORESTATION by doing these EASY steps:

Plant a TREE where you can.

Go paperless at home and in the office.

Buy recycled products and then recycle them again.

Buy certified wood products. ...

Support the products of COMPANIES that are committed to reducing deforest

Step-by-step explanation:

You can contribute to the efforts against deforestation by doing these easy steps:

Plant a Tree where you can.

Go paperless at home and in the office.

Buy recycled products and then recycle them again.

Buy certified wood products. ...

Support the products of companies that are committed to reducing deforest

please mark as brainlist bro

Discussion

22318.	Seco+tano=5 then find coso
Answer» ANSWER: SORRY but Kensjsjanbyd fbja.sj

22318.

Seco+tano=5 then find coso

Answer»

ANSWER:

SORRY but Kensjsjanbyd fbja.sj

Discussion

22319.	Find the product of cube of 6 and the square of 3
Answer» ANSWER: 1,944 Step-by-step explanation: 6^3 X 3^2 216 x 9 1,944 Here is your answer...

22319.

Find the product of cube of 6 and the square of 3

Answer»

ANSWER:

1,944

Step-by-step explanation:

6^3 X 3^2

216 x 9

1,944

Here is your answer...

Discussion

22320.	7. From the given figure find angle ABC and angle BAC
Answer» ANSWER: Step-by-step EXPLANATION: BCD FORMS A STRAIGHT LINE.

22320.

7. From the given figure find angle ABC and angle BAC

Answer»

ANSWER:

Step-by-step EXPLANATION:

BCD FORMS A STRAIGHT LINE.

Discussion

22321.	Find the square of 6/7
Answer» Step-by-step explanation: 6 = 36 7= 49 vhjfzgiknvseuijv

22321.

Find the square of 6/7

Answer»

Step-by-step explanation:

6 = 36

7= 49

vhjfzgiknvseuijv

Discussion

22322.	Find the value of K if -1 is a zero of the polynomial (P)=Kx²-4x+K
Answer» Answer: Research QUESTIONS are developed by USING sources that include CURIOSITY, professors, textbooks, JOURNALS, databases, and the Internet. 2. Keywords based on your research topic are used to search the literature for INFORMATION and prior research on the topic.

22322.

Find the value of K if -1 is a zero of the polynomial (P)=Kx²-4x+K

Answer»

Answer:

Research QUESTIONS are developed by USING sources that include CURIOSITY, professors, textbooks, JOURNALS, databases, and the Internet. 2. Keywords based on your research topic are used to search the literature for INFORMATION and prior research on the topic.

Discussion

22323.	Find the maximum and minimum values of a y = 2x³+3x²-36x+1I need the answer quickly..
Answer» Answer: y = 2x3 – 3x2 – 36x + 10 dydxdydx = 6X2 – 6x – 36 = 6(x2 – x – 6) dydxdydx = 0 gives 6(x2 – x – 6) = 0 6(x – 3) (x + 2) = 0 x = 3 (or) x = -2 d2ydx2d2ydx2 = 6(2x – 1) Case (i): when x = 3, (d2ydx2)x=3(d2ydx2)x=3 = 6(2 x 3 – 1) = 6 x 5 = 30, positive Since d2ydx2d2ydx2 is positive y is minimum when x = 3. The local minimum value is obtained by substituting x = 3 in y. Local minimum value = 2(33) – 3(32) – 36(3) + 10 = 2(27) – (27) – 108 + 10 = 27 – 98 = -71 Case (II): when x = -2, (d2ydx2)x=−2(d2ydx2)x=−2 = 6(-2 x 2 – 1) = 6 x -5 = -30, negative Since d2ydx2d2ydx2 is negative, y is maximum when x = -2. Local maximum value = 2(-2)3 – 3(-2)2 – 36(-2) + 10 = 2(-8) – 3(4) + 72 + 10 = -16 – 12 + 82 = -28 + 82 = 54Read more on Sarthaks.com - https://www.sarthaks.com/983672/find-the-local-minimum-and-local-maximum-of-y-2x-3-3x-2-36x-10

22323.

Find the maximum and minimum values of a y = 2x³+3x²-36x+1I need the answer quickly..

Answer»

Answer:

y = 2x3 – 3x2 – 36x + 10 dydxdydx = 6X2 – 6x – 36 = 6(x2 – x – 6) dydxdydx = 0 gives 6(x2 – x – 6) = 0 6(x – 3) (x + 2) = 0 x = 3 (or) x = -2 d2ydx2d2ydx2 = 6(2x – 1) Case (i): when x = 3, (d2ydx2)x=3(d2ydx2)x=3 = 6(2 x 3 – 1) = 6 x 5 = 30, positive Since d2ydx2d2ydx2 is positive y is minimum when x = 3. The local minimum value is obtained by substituting x = 3 in y. Local minimum value = 2(33) – 3(32) – 36(3) + 10 = 2(27) – (27) – 108 + 10 = 27 – 98 = -71 Case (II): when x = -2, (d2ydx2)x=−2(d2ydx2)x=−2 = 6(-2 x 2 – 1) = 6 x -5 = -30, negative Since d2ydx2d2ydx2 is negative, y is maximum when x = -2. Local maximum value = 2(-2)3 – 3(-2)2 – 36(-2) + 10 = 2(-8) – 3(4) + 72 + 10 = -16 – 12 + 82 = -28 + 82 = 54Read more on Sarthaks.com - https://www.sarthaks.com/983672/find-the-local-minimum-and-local-maximum-of-y-2x-3-3x-2-36x-10

Discussion

22324.	X2-10x- 96 =0 (Solve)
Answer» Answer: The ROOTS are 16 and -6 Step-by-step EXPLANATION: -96 can be resolved to -16*6 (x-16)(x+6)=0 X=16,-6

22324.

X2-10x- 96 =0 (Solve)

Answer»

Answer:

The ROOTS are 16 and -6

Step-by-step EXPLANATION:

-96 can be resolved to -16*6

(x-16)(x+6)=0

X=16,-6

Discussion

22325.	Rationalise root 6/root 2+ root 3
Answer» To rationalise the denominator of: $\longrightarrow \sf { \dfrac{\sqrt{6}}{\sqrt{2} + \sqrt{3}} }$ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ To rationalise the DENOMINATOR of the GIVEN fraction, we need to multiply the the RATIONALISING FACTOR of the denominator with both the numerator and the denominator of the given fraction. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ Here, $\longrightarrow \sf {Denominator = (\sqrt{2} + \sqrt{3} )}$ Rationalising factor of $\sf { (\sqrt{2} + \sqrt{3} )}$ is $\sf { (\sqrt{2} - \sqrt{3} )}$ . So, we'll multiply $\sf { (\sqrt{2} - \sqrt{3} )}$ with both the numerator and the denominator. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow \sf { \dfrac{\sqrt{6}}{\sqrt{2} + \sqrt{3}} \times \dfrac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}} } \\ \\$ $\longrightarrow \sf { \dfrac{\sqrt{6} (\sqrt{2} - \sqrt{3}) }{(\sqrt{2} + \sqrt{3})(\sqrt{2} + \sqrt{3})} } \\ \\$ By USING identity, (a + b)(a - b) = a² - b² ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\longrightarrow \sf { \dfrac{\sqrt{6} (\sqrt{2}) - \sqrt{6}( \sqrt{3}) }{(\sqrt{2})^2 -(\sqrt{3})^2 } } \\ \\$ $\longrightarrow \sf { \dfrac{\sqrt{12} - \sqrt{18}}{2 -3 } } \\ \\$ $\longrightarrow \sf { \dfrac{\sqrt{12} - \sqrt{18}}{-1 } } \\ \\$ $\longrightarrow \sf { \dfrac{\sqrt{12} - \sqrt{18}}{-1 } \times \dfrac{-1}{-1} } \\ \\$ $\longrightarrow \sf { \dfrac{-1(\sqrt{12} - \sqrt{18})}{(-1)^2 } } \\ \\$ $\longrightarrow \sf { \dfrac{ -\sqrt{12} + \sqrt{18}}{1 } } \\ \\$ $\longrightarrow \sf { -\sqrt{12} + \sqrt{18} } \\ \\$ $\longrightarrow \boxed{\sf { -2\sqrt{3} +3 \sqrt{2} }} \\ \\$ Hence, rationalised. ⠀⠀⠀⠀___________________________ More Identities : • (√a)² = a • √a√b = √ab • √a/√b = √a/b • (√a + √b)(√a - √b) = a - b • (a + √b)(a - √b) = a² - b • (√a ± √b)² = a ± 2√ab + b • (√a + √b)(√c + √d) = √ac + √ad + √bc + √bd

22325.

Rationalise root 6/root 2+ root 3

Answer»

To rationalise the denominator of:

$\longrightarrow \sf { \dfrac{\sqrt{6}}{\sqrt{2} + \sqrt{3}} }$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

To rationalise the DENOMINATOR of the GIVEN fraction, we need to multiply the the RATIONALISING FACTOR of the denominator with both the numerator and the denominator of the given fraction.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Here,

$\longrightarrow \sf {Denominator = (\sqrt{2} + \sqrt{3} )}$

Rationalising factor of $\sf { (\sqrt{2} + \sqrt{3} )}$ is $\sf { (\sqrt{2} - \sqrt{3} )}$ . So, we'll multiply $\sf { (\sqrt{2} - \sqrt{3} )}$ with both the numerator and the denominator.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf { \dfrac{\sqrt{6}}{\sqrt{2} + \sqrt{3}} \times \dfrac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}} } \\ \\$

$\longrightarrow \sf { \dfrac{\sqrt{6} (\sqrt{2} - \sqrt{3}) }{(\sqrt{2} + \sqrt{3})(\sqrt{2} + \sqrt{3})} } \\ \\$

By USING identity,

(a + b)(a - b) = a² - b²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf { \dfrac{\sqrt{6} (\sqrt{2}) - \sqrt{6}( \sqrt{3}) }{(\sqrt{2})^2 -(\sqrt{3})^2 } } \\ \\$

$\longrightarrow \sf { \dfrac{\sqrt{12} - \sqrt{18}}{2 -3 } } \\ \\$

$\longrightarrow \sf { \dfrac{\sqrt{12} - \sqrt{18}}{-1 } } \\ \\$

$\longrightarrow \sf { \dfrac{\sqrt{12} - \sqrt{18}}{-1 } \times \dfrac{-1}{-1} } \\ \\$

$\longrightarrow \sf { \dfrac{-1(\sqrt{12} - \sqrt{18})}{(-1)^2 } } \\ \\$

$\longrightarrow \sf { \dfrac{ -\sqrt{12} + \sqrt{18}}{1 } } \\ \\$

$\longrightarrow \sf { -\sqrt{12} + \sqrt{18} } \\ \\$

$\longrightarrow \boxed{\sf { -2\sqrt{3} +3 \sqrt{2} }} \\ \\$

Hence, rationalised.

⠀⠀⠀⠀___________________________

More Identities :

• (√a)² = a

• √a√b = √ab

• √a/√b = √a/b

• (√a + √b)(√a - √b) = a - b

• (a + √b)(a - √b) = a² - b

• (√a ± √b)² = a ± 2√ab + b

• (√a + √b)(√c + √d) = √ac + √ad + √bc + √bd

Discussion

22326.	फाइंड द प्रोडक्ट ऑफ के उपयोग बॉक्सेस एंड स्पेरॉफ 3
Answer» Answer: Primary Packaging The packaging that most closely touches a PRODUCT, often REFERRED to as “retail packaging.” Secondary Packing The packaging used to ship products ALREADY in primary packaging. Tertiary Packaging The packaging used most often by warehouses to ship secondary packaging.

22326.

फाइंड द प्रोडक्ट ऑफ के उपयोग बॉक्सेस एंड स्पेरॉफ 3

Answer»

Answer:

Primary Packaging

The packaging that most closely touches a PRODUCT, often REFERRED to as “retail packaging.”

Secondary Packing

The packaging used to ship products ALREADY in primary packaging.

Tertiary Packaging

The packaging used most often by warehouses to ship secondary packaging.

Discussion

22327.	Simplify ( 3 - √2)² question
Answer» ANSWER: = 9 + 2 + 2(3) (√2) = 11 + 6√2

22327.

Simplify ( 3 - √2)² question

Answer»

ANSWER:

= 9 + 2 + 2(3) (√2)

= 11 + 6√2

Discussion

22328.	1/8X3/0X5/3X2/2 of Exponent
Answer» ANSWER: the answer is cannot DEFINE

22328.

1/8X3/0X5/3X2/2 of Exponent

Answer»

ANSWER:

the answer is cannot DEFINE

Discussion

22329.	One factor of 49 a² - 25b² is( 7a + 5b). Stab state the otherfactor please fast give me perfect answer please
Answer» So the ANSWER is 2A * 7B * 2 = 70ab ACCORDING to the a^2+2ab+b^2

Discussion

22330.	Three metal cubes of sides 6 cm, 8 cm and 10 cm are melted and recast into a big cube. Find its total surface area..
Answer» $\sf{\huge{\underline{\green{Given :-}}}}$ THREE cubes of metal whose edges are 6 cm, 8 cm and 10cm respectively are melted to form a big cube. $\sf{\huge{\underline{\green{To\:Find :-}}}}$ The total surface area of the new cube . $\sf{\huge{\underline{\green{Answer :-}}}}$ According to the question, Three cubes of metal whose edges are 5 cm, 8 cm and 10cm are melted to form a single cube. First cube of edge = 6 cm The volume of the cube = a³ ➝ a × a × a ➝ 6 × 6 × 6 ➝ 36 × 6 ➝ 216 cm³ Second cube of edge = 8 cm The volume of the cube = a³ ➝ a × a × a ➝ 8 × 8 × 8 ➝ 64 × 8 ➝ 512 cm³ Third cube of edge = 10 cm The volume of the cube = a³ ➝ a × a × a ➝ 10 × 10 × 10 ➝ 100 × 10 ➝ 1000 cm³ The volume of the Big cube form by combining the three cubes = Vol of cube 1 + Vol of cube 2 + Vol of cube 3 ➝ 216 + 512 + 1000 ➝ 728 + 1000 ➝ 1728 cm³ The volume of the new cube is 1728 . We know that, The volume of the cube is a³. ➝ a³ = 1728 ➝ a = $\sqrt[3]{1728}$ ➝ a = 12 cm The edge of the new cube is 12 cm . TSA of cube = 6a² ➝ 6 × 12 × 12 ➝ 6 × 144 ➝ 864 cm² ______________________________________

22330.

Three metal cubes of sides 6 cm, 8 cm and 10 cm are melted and recast into a big cube. Find its total surface area..

Answer»

$\sf{\huge{\underline{\green{Given :-}}}}$

THREE cubes of metal whose edges are 6 cm, 8 cm and 10cm respectively are melted to form a big cube.

$\sf{\huge{\underline{\green{To\:Find :-}}}}$

The total surface area of the new cube .

$\sf{\huge{\underline{\green{Answer :-}}}}$

According to the question,

Three cubes of metal whose edges are 5 cm, 8 cm and 10cm are melted to form a single cube.

First cube of edge = 6 cm

The volume of the cube = a³

➝ a × a × a

➝ 6 × 6 × 6

➝ 36 × 6

➝ 216 cm³

Second cube of edge = 8 cm

The volume of the cube = a³

➝ a × a × a

➝ 8 × 8 × 8

➝ 64 × 8

➝ 512 cm³

Third cube of edge = 10 cm

The volume of the cube = a³

➝ a × a × a

➝ 10 × 10 × 10

➝ 100 × 10

➝ 1000 cm³

The volume of the Big cube form by combining the three cubes = Vol of cube 1 + Vol of cube 2 + Vol of cube 3

➝ 216 + 512 + 1000

➝ 728 + 1000

➝ 1728 cm³

The volume of the new cube is 1728 .

We know that, The volume of the cube is a³.

➝ a³ = 1728

➝ a = $\sqrt[3]{1728}$

➝ a = 12 cm

The edge of the new cube is 12 cm .

TSA of cube = 6a²

➝ 6 × 12 × 12

➝ 6 × 144

➝ 864 cm²

______________________________________

Discussion

22331.	Can someone please help me?The figure is a triangle that is divided into two parts. Angle A and angle E are right angles, and the measure of angle F is 30°. What is the measure of angle C?Complete the steps below to solve the problem using equations.Part BWhat is the measurement of angle G?Part CLet the variable c represent the measurement of angle C. Use the measurement of angle G to write an equation that you can use to solve for c.Part DWhat is the measurement of angle C?
Answer» ANSWER: PART 1 Step-by-step explanation: LET the measurement. of angel G ? what is the measurement of angel C?

22331.

Can someone please help me?The figure is a triangle that is divided into two parts. Angle A and angle E are right angles, and the measure of angle F is 30°. What is the measure of angle C?Complete the steps below to solve the problem using equations.Part BWhat is the measurement of angle G?Part CLet the variable c represent the measurement of angle C. Use the measurement of angle G to write an equation that you can use to solve for c.Part DWhat is the measurement of angle C?

Answer»

ANSWER:

PART 1

Step-by-step explanation:

LET the measurement. of angel G ? what is the measurement of angel C?

Discussion

22332.	Ratinol number and irrational numbers together called as
Answer» Answer: Real NUMBERS Step-by-step explanation: RATIONAL NUMBER and Irrational Numbers are TOGETHER CALLED as Real Numbers.

22332.

Ratinol number and irrational numbers together called as

Answer»

Answer:

Real NUMBERS

Step-by-step explanation:

RATIONAL NUMBER and Irrational Numbers are TOGETHER CALLED as Real Numbers.

Discussion

22333.	The length of the side of a square garden is 145 m What distance does shilpa cover if he runs around the ground twice ?
Answer» Answer: Answer In ONE round, man covers a DISTANCE equal to perimeter of square =4×side=60m ⇒ To COVER 420m, he should run, 60 420 =7 ROUNDS.

22333.

The length of the side of a square garden is 145 m What distance does shilpa cover if he runs around the ground twice ?

Answer»

Answer:

Answer

In ONE round, man covers a DISTANCE equal to perimeter of square =4×side=60m

⇒ To COVER 420m, he should run,

60

420

=7 ROUNDS.

Discussion

22334.	(c) 15 litres 89 millilitres into millilitres
Answer» Answer: 1000 ML Remember that 1 L = 1000 mL.

22334.

(c) 15 litres 89 millilitres into millilitres

Answer»

Answer:

1000 ML

Remember that 1 L = 1000 mL.

Discussion

22335.	5. from the given figure find angles A, B and C
Answer» Answer: A = 70 degree B = 50 degree C = 60 degree

22335.

5. from the given figure find angles A, B and C

Answer»

Answer:

A = 70 degree

B = 50 degree

C = 60 degree

Discussion

22336.	8.Construct an equilateral A APE with side 6.5 cm (without
Answer» the ANSWER of the QUESTION is 6.5cm

Discussion

22337.	Find the volume of cuboid who's length is 8cm breadth is 6.5cm hight is 5.5 cm
Answer» Answer : Volume of cuboid is 286cm³ Given : LENGTH = 8cm Breadth = 6.5 cm HEIGHT = 5.5 cm To find : Volume of cuboid Solution : As we know that, Volume of cuboid = lbh Where , l is length b is breadth h is height 》Volume of cuboid = length × breadth × height 》Volume of cuboid = 8 × 6.5 × 5.5 》Volume of cuboid = 286 cm³ Hence , Volume of cuboid is 286cm³ More EXPLANATION : Lateral surface area of cuboid = 2h(l + b) Total surface area of cuboid = 2(lb + bh + lh)

22337.

Find the volume of cuboid who's length is 8cm breadth is 6.5cm hight is 5.5 cm

Answer»

Answer :

Volume of cuboid is 286cm³

Given :

LENGTH = 8cm
Breadth = 6.5 cm
HEIGHT = 5.5 cm

To find :

Volume of cuboid

Solution :

As we know that,

Volume of cuboid = lbh

Where ,

l is length
b is breadth
h is height

》Volume of cuboid = length × breadth × height

》Volume of cuboid = 8 × 6.5 × 5.5

》Volume of cuboid = 286 cm³

Hence , Volume of cuboid is 286cm³

More EXPLANATION :

Lateral surface area of cuboid = 2h(l + b)
Total surface area of cuboid = 2(lb + bh + lh)

Discussion

22338.	Arrange the following number in ascending order 943586
Answer» Answer: 3__4__5__6__8__9--------

22338.

Arrange the following number in ascending order 943586

Answer»

Answer:

3__4__5__6__8__9--------

Discussion

22339.	prove that"the tangent at any point of a circle is prependicular to the radius through the point of contact".
Answer» Answer: Referring to the figure: OA=OC (Radii of circle) Now OB=OC+BC ∴OB>OC (OC being RADIUS and B any point on TANGENT) ⇒OA B is an arbitrary point on the tangent. Thus, OA is shorter than any other LINE segment joining O to any point on tangent. Shortest distance of a point from a given line is the perpendicular distance from that line. Hence, the tangent at any point of circle is perpendicular to the radius.

22339.

prove that"the tangent at any point of a circle is prependicular to the radius through the point of contact".

Answer»

Answer:

Referring to the figure:

OA=OC (Radii of circle)

Now OB=OC+BC

∴OB>OC (OC being RADIUS and B any point on TANGENT)

⇒OA

B is an arbitrary point on the tangent.

Thus, OA is shorter than any other LINE segment joining O to any

point on tangent.

Shortest distance of a point from a given line is the perpendicular distance from that line.

Hence, the tangent at any point of circle is perpendicular to the radius.

Discussion

22340.	Explain about distributive propertyI
Answer» Answer: The distributive property is one of the most FREQUENTLY used properties in math. In general, this term REFERS to the distributive property of MULTIPLICATION which states that the Definition: The distributive property LETS you multiply a SUM by multiplying each addend separately and then add the products.

22340.

Explain about distributive propertyI

Answer»

Answer:

The distributive property is one of the most FREQUENTLY used properties in math. In general, this term REFERS to the distributive property of MULTIPLICATION which states that the Definition: The distributive property LETS you multiply a SUM by multiplying each addend separately and then add the products.

Discussion

22341.	If a=2 b=3 find the value of a²+b²
Answer» a = 2 , B = 3 a² + b² = (a + b)² = a² + b² + 2ab so put values as given in the QUESTION (2 + 3)² = (2)² + (3)² + 2(2)(3) = 4 + 9 + 12 = 25 Hope it helps dear Follow please ✌️

22341.

If a=2 b=3 find the value of a²+b²

Answer»

a = 2 , B = 3

a² + b² = (a + b)² = a² + b² + 2ab

so put values as given in the QUESTION

(2 + 3)² = (2)² + (3)² + 2(2)(3)

= 4 + 9 + 12

= 25

Hope it helps dear

Follow please ✌️

Discussion

22342.	Mr papan saved ₹115270 in a year how much approximately will he save in 8 years?
Answer» ANSWER: MR PAPAN will be SAVING ₹922160 Step-by-step explanation: 115270 * 8

22342.

Mr papan saved ₹115270 in a year how much approximately will he save in 8 years?

Answer»

ANSWER:

MR PAPAN will be SAVING ₹922160

Step-by-step explanation:

115270 * 8

Discussion

22343.	Find the ratio of 1. 15 kg to 250 gm Ans :-
Answer» ANSWER: Answer is 23/5 Step-by-step explanation: 1150/250= 23/5

22343.

Find the ratio of 1. 15 kg to 250 gm Ans :-

Answer»

ANSWER:

Answer is 23/5

Step-by-step explanation:

1150/250= 23/5

Discussion

22344.	If p(y)=3y⁴+3y³- y - 1then p(-1) =? p(-2) =? p(0)=?
Answer» Answer: p(-1) = 0 p(-2) = 25 p(0) = - 1 Step-by-step explanation: given, p(y)=3y⁴+3y³- y - 1 => p(-1) = 3(-1)⁴+3(-1)³- (-1) - 1 = 3(1)+3(-1)+1 - 1 = 3-3 = 0 => p(-2) = 3(-2)⁴+3(-2)³- (-2) - 1 = 3(16)+3(-8)+2 - 1 = 48-24+1 = 24+1 = 25 => p(0) = 3(0)⁴+3(0)³- (0) - 1 = - 1

22344.

If p(y)=3y⁴+3y³- y - 1then p(-1) =? p(-2) =? p(0)=?

Answer»

Answer:

p(-1) = 0

p(-2) = 25

p(0) = - 1

Step-by-step explanation:

given, p(y)=3y⁴+3y³- y - 1

=> p(-1) = 3(-1)⁴+3(-1)³- (-1) - 1

= 3(1)+3(-1)+1 - 1

= 3-3

= 0

=> p(-2) = 3(-2)⁴+3(-2)³- (-2) - 1

= 3(16)+3(-8)+2 - 1

= 48-24+1

= 24+1

= 25

=> p(0) = 3(0)⁴+3(0)³- (0) - 1

= - 1

Discussion

22345.	The value of a machine depreciates 10% annually. Its present value is Rs. 64800. Find its value 2 years ago
Answer» Answer: 77760 Step-by-step explanation: 20% OF 64800=20/100 X 64800 =12960 VALUE 2 YRS AGO=64800+12960 =77760 MARK ME THE BRAINLIEST

22345.

The value of a machine depreciates 10% annually. Its present value is Rs. 64800. Find its value 2 years ago

Answer»

Answer:

77760

Step-by-step explanation:

20% OF 64800=20/100 X 64800

=12960

VALUE 2 YRS AGO=64800+12960

=77760

MARK ME THE BRAINLIEST

Discussion

22346.	A sum of money put out at compound interest amounts in 2 years to ₹4,410 and in three years4630.50.Find the rate of interest and the original sum.explain step by step.
Answer» Step-by-step explanation: Different is AMOUNTS = 4630.50 - 4410 = 220.5 Rs Rs 220.5 is the interest on Rs 4410 is 1 year RATE of interest = 220.5 × 100/4410 = 5%

22346.

A sum of money put out at compound interest amounts in 2 years to ₹4,410 and in three years4630.50.Find the rate of interest and the original sum.explain step by step.

Answer»

Step-by-step explanation:

Different is AMOUNTS = 4630.50 - 4410

= 220.5 Rs

Rs 220.5 is the interest on Rs 4410 is 1 year

RATE of interest = 220.5 × 100/4410

= 5%

Discussion

22347.	Find the value of n(-2/3)^4 / (-2/3)^3 = (-3/2)^n
Answer» ANSWER: this is your answer BRO

22347.

Find the value of n(-2/3)^4 / (-2/3)^3 = (-3/2)^n

Answer»

ANSWER:

this is your answer BRO

Discussion

22348.	3 A Man purchased 700 eggs. He found that50% of them were booken find the numberof booken eggs?
Answer» TOTAL QUANTITY of Eggs = 700 Broken Eggs = 50% Eggs LEFT = 700×50/100 = 700×1/2 So , Eggs Left. = 350 Broken Eggs = 700 - 350 = 350

22348.

3 A Man purchased 700 eggs. He found that50% of them were booken find the numberof booken eggs?

Answer»

TOTAL QUANTITY of Eggs = 700

Broken Eggs = 50%

Eggs LEFT = 700×50/100

= 700×1/2

So , Eggs Left. = 350

Broken Eggs = 700 - 350 = 350

Discussion

22349.	Page No.Date03Find the value of Lp? such that(3) 3 € 30-3 = 13,305 5 5
Answer» ANSWER: I will tell Step-by-step EXPLANATION: MARK me BRAINLIEST

22349.

Page No.Date03Find the value of Lp? such that(3) 3 € 30-3 = 13,305 5 5

Answer»

ANSWER:

I will tell

Step-by-step EXPLANATION:

MARK me BRAINLIEST

Discussion

22350.	Explain why 7×11×13+13 is a campsite number
Answer» Composite* 7x11x13+13= 13(7x11+1) = 13(77-1)= 13(76) So it is PRODUCT of two or more NUMBERS... hence it is composite

Discussion

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