332354 + Interview Questions in Secondary School in Math Page 461 InterviewSolution

23001.	The angle sum of a convex polygon with number of sides 7 is: *
Answer» Answer: The ANGLE sum of all interior ANGLES of a convex polygon of SIDES 7 is 900° (nine hundred)

23001.

The angle sum of a convex polygon with number of sides 7 is: *

Answer»

Answer:

The ANGLE sum of all interior ANGLES of a convex polygon of SIDES 7 is 900°

(nine hundred)

23002.	. The median and mode of a frequency distribution are 26 and 29. What will be the mean?
Answer» i HOPE that's GREAT HELP 4 you

Discussion

23003.	1,23,00,456 write it number name
Answer» Answer: ONE crore TWENTY THREE LAKHS four hundred and FIFTY six is your answer

23003.

1,23,00,456 write it number name

Answer»

Answer:

ONE crore TWENTY THREE LAKHS four hundred and FIFTY six is your answer

Discussion

23004.	In an electrical circuit the voltage across a resistor is directly proportional to the current running through the resistor. If a current of 16 amps produces 680 volts across a resistor how many volts would a current of 3.5 amps produce across an identical resistor?
Answer» Given, Current 1 (I₁) = 16 A P.d (V₁) = 680 V By OHM's law, V₁ = I₁R = 680 = 16R = 42.5Ω = R Current 2 (I₂) = 3.5 A RESISTANCE (R) = 42.5 Ω If we assume that resistance remains the same, By using Ohm's law, V₂ = I₂R = 3.542.5 = 148.75 V The New Potential Difference will be 148.75 V.* I hope this helps.

23004.

In an electrical circuit the voltage across a resistor is directly proportional to the current running through the resistor. If a current of 16 amps produces 680 volts across a resistor how many volts would a current of 3.5 amps produce across an identical resistor?

Answer»

Given,

Current 1 (I₁) = 16 A

P.d (V₁) = 680 V

By OHM's law,

V₁ = I₁R

= 680 = 16R

= 42.5Ω = R

Current 2 (I₂) = 3.5 A

RESISTANCE (R) = 42.5 Ω

If we assume that resistance remains the same,

By using Ohm's law,

V₂ = I₂R

= 3.5*42.5

= 148.75 V

The New Potential Difference will be 148.75 V.

I hope this helps.

Discussion

23005.	4. Find the sum of zereos of 5x-4=0
Answer» ANSWER: why so SERIOUS..!!..!!..!!..!!..!!

23005.

4. Find the sum of zereos of 5x-4=0

Answer»

ANSWER:

why so SERIOUS..!!..!!..!!..!!..!!

Discussion

23006.	The 22/342 please help
Answer» Answer: WHAT IS THIS Step-by-step explanation: I CAN'T HELP U NOW... SORRY

23006.

The 22/342 please help

Answer»

Answer:

WHAT IS THIS

Step-by-step explanation:

I CAN'T HELP U NOW...

SORRY

Discussion

23007.	If x= 3+√5/2, show that x+1/x=3. also find x cube +1/x cubegive the answer fast
Answer» Step-by-step explanation: GIVEN: $x=\frac{3+\sqrt{5} }{2}$ To prove: $x+\frac{1}{x}=3$ Proof: $\frac{1}{x}=\frac{1}{\frac{3+\sqrt{5} }{2} }$ ⇒ $1\div\frac{3+\sqrt{5}}{2 }$ ⇒ $1\times\frac{2}{3+\sqrt{5} }$ ⇒ $\frac{1\times2}{3+\sqrt{5} }$ ⇒ $\frac{2}{3+\sqrt{5} }$ On RATIONALISING the denominator, ⇒ $\frac{2}{3+\sqrt{5} }\times\frac{3-\sqrt{5}}{3-\sqrt{5} }$ ⇒ $\frac{2(3-\sqrt{5}) }{(3+\sqrt{5})(3-\sqrt{5})}$ ⇒ $\frac{2(3-\sqrt{5}) }{(3)^2-(\sqrt{5})^2}$ ⇒ $\frac{2(3-\sqrt{5}) }{9-5}$ ⇒ $\frac{2(3-\sqrt{5}) }{4}$ ⇒ $\frac{3-\sqrt{5} }{2}$ ∴ $\frac{1}{x} =\frac{3-\sqrt{5} }{2}$ $x+\frac{1}{x}=\frac{3+\sqrt{5} }{2}+(\frac{3-\sqrt{5} }{2} )$ ⇒ $\frac{3+\sqrt{5} }{2}+\frac{3-\sqrt{5} }{2}$ ⇒ $\frac{3+\sqrt{5}+3-\sqrt{5} }{2}$ ⇒ $\frac{3+3+\sqrt{5}-\sqrt{5} }{2}$ ⇒ $\frac{6+0}{2}$ ⇒ $\frac{6}{2}$ ⇒ $3$ ∴ $x+\frac{1}{x}=3$ . HENCE proved. To FIND: $x^3+(\frac{1}{x})^3$ Solution: $x^3+(\frac{1}{x})^3$ $=(\frac{3+\sqrt{5} }{2})^3 +(\frac{3-\sqrt{5} }{2})^3$ ⇒ $\frac{(3+\sqrt{5})^3 }{(2)^3}+\frac{(3-\sqrt{5})^3 }{(2)^3}$ ⇒ $\frac{(3)^3+(\sqrt{5})^3 +3(3)^2(\sqrt{5})+3(3)(\sqrt{5})^2 }{8}+\frac{(3)^3-(\sqrt{5})^3 -3(3)^2(\sqrt{5})+3(3)(\sqrt{5})^2 }{8}$ $($ ∵ $(a+b)^3=a^3+b^3+3a^2b+3ab^2, (a-b)^3=a^3-b^3-3a^2b+3ab^2)$ ⇒ $\frac{27+5\sqrt{5} +3(9)(\sqrt{5})+3(3)(5) }{8}+\frac{27-5\sqrt{5} -3(9)(\sqrt{5})+3(3)(5) }{8}$ ⇒ $\frac{27+5\sqrt{5} +27\sqrt{5}+45 }{8}+\frac{27-5\sqrt{5} -27\sqrt{5}+45 }{8}$ ⇒ $\frac{27+45+5\sqrt{5} +27\sqrt{5} }{8}+\frac{27+45-5\sqrt{5} -27\sqrt{5} }{8}$ ⇒ $\frac{72+32\sqrt{5} }{8}+\frac{72-32\sqrt{5} }{8}$ ⇒ $\frac{72+32\sqrt{5} +72-32\sqrt{5} }{8}$ ⇒ $\frac{72+72+32\sqrt{5} -32\sqrt{5} }{8}$ ⇒ $\frac{144+0 }{8}$ ⇒ $\frac{144}{8}$ ⇒ $18$ ∴ $x^3+(\frac{1}{x})^3=18$ .

23007.

If x= 3+√5/2, show that x+1/x=3. also find x cube +1/x cubegive the answer fast

Answer»

Step-by-step explanation:

GIVEN:

$x=\frac{3+\sqrt{5} }{2}$

To prove:

$x+\frac{1}{x}=3$

Proof:

$\frac{1}{x}=\frac{1}{\frac{3+\sqrt{5} }{2} }$

⇒ $1\div\frac{3+\sqrt{5}}{2 }$

⇒ $1\times\frac{2}{3+\sqrt{5} }$

⇒ $\frac{1\times2}{3+\sqrt{5} }$

⇒ $\frac{2}{3+\sqrt{5} }$

On RATIONALISING the denominator,

⇒ $\frac{2}{3+\sqrt{5} }\times\frac{3-\sqrt{5}}{3-\sqrt{5} }$

⇒ $\frac{2(3-\sqrt{5}) }{(3+\sqrt{5})(3-\sqrt{5})}$

⇒ $\frac{2(3-\sqrt{5}) }{(3)^2-(\sqrt{5})^2}$

⇒ $\frac{2(3-\sqrt{5}) }{9-5}$

⇒ $\frac{2(3-\sqrt{5}) }{4}$

⇒ $\frac{3-\sqrt{5} }{2}$

∴ $\frac{1}{x} =\frac{3-\sqrt{5} }{2}$

$x+\frac{1}{x}=\frac{3+\sqrt{5} }{2}+(\frac{3-\sqrt{5} }{2} )$

⇒ $\frac{3+\sqrt{5} }{2}+\frac{3-\sqrt{5} }{2}$

⇒ $\frac{3+\sqrt{5}+3-\sqrt{5} }{2}$

⇒ $\frac{3+3+\sqrt{5}-\sqrt{5} }{2}$

⇒ $\frac{6+0}{2}$

⇒ $\frac{6}{2}$

⇒ $3$

∴ $x+\frac{1}{x}=3$ .

HENCE proved.

To FIND:

$x^3+(\frac{1}{x})^3$

Solution:

$x^3+(\frac{1}{x})^3$

$=(\frac{3+\sqrt{5} }{2})^3 +(\frac{3-\sqrt{5} }{2})^3$

⇒ $\frac{(3+\sqrt{5})^3 }{(2)^3}+\frac{(3-\sqrt{5})^3 }{(2)^3}$

⇒ $\frac{(3)^3+(\sqrt{5})^3 +3(3)^2(\sqrt{5})+3(3)(\sqrt{5})^2 }{8}+\frac{(3)^3-(\sqrt{5})^3 -3(3)^2(\sqrt{5})+3(3)(\sqrt{5})^2 }{8}$

$($ ∵ $(a+b)^3=a^3+b^3+3a^2b+3ab^2, (a-b)^3=a^3-b^3-3a^2b+3ab^2)$

⇒ $\frac{27+5\sqrt{5} +3(9)(\sqrt{5})+3(3)(5) }{8}+\frac{27-5\sqrt{5} -3(9)(\sqrt{5})+3(3)(5) }{8}$

⇒ $\frac{27+5\sqrt{5} +27\sqrt{5}+45 }{8}+\frac{27-5\sqrt{5} -27\sqrt{5}+45 }{8}$

⇒ $\frac{27+45+5\sqrt{5} +27\sqrt{5} }{8}+\frac{27+45-5\sqrt{5} -27\sqrt{5} }{8}$

⇒ $\frac{72+32\sqrt{5} }{8}+\frac{72-32\sqrt{5} }{8}$

⇒ $\frac{72+32\sqrt{5} +72-32\sqrt{5} }{8}$

⇒ $\frac{72+72+32\sqrt{5} -32\sqrt{5} }{8}$

⇒ $\frac{144+0 }{8}$

⇒ $\frac{144}{8}$

⇒ $18$

∴ $x^3+(\frac{1}{x})^3=18$ .

Discussion

23008.	(1+x^2)dy/dx+y=e^tan^-1x answer
Answer» $\large\underline{\sf{<klux>SOLUTION</klux>-}}$ The given Differential Equation is $\rm :\longmapsto\:(1+{x}^{2})\dfrac{dy}{dx} + y = {e}^{ {tan}^{ - 1} x}$ can be rewritten as $\rm :\longmapsto\:\dfrac{dy}{dx} +\dfrac{y}{1 + {x}^{2} } = \dfrac{{e}^{ {tan}^{ - 1} x}}{1 + {x}^{2} }$ which is a Linear Differential equation. So, On comparing with, $\rm :\longmapsto\:\dfrac{dy}{dx} + py = q$ we get, $\red{\rm :\longmapsto\:p = \dfrac{1}{1 + {x}^{2} } } \\ \red{\rm :\longmapsto\:q = \dfrac{{e}^{ {tan}^{ - 1} x}}{1 + {x}^{2} }}$ INTEGRATING Factor, I.F. is given by $\rm :\longmapsto\:I.F. = {e} \: ^{\displaystyle \int \: pdx}$ $\rm :\longmapsto\:I.F. = {e} \: ^{\displaystyle \int \: \dfrac{1}{1 + {x}^{2} } dx}$ $\bf\implies \:I.F. = {e}^{ {tan}^{ - 1} x}$ $\: \: \: \: \: \: \: \: \: \: \: \red{\bigg \{ \because \: \displaystyle \int \: \dfrac{dx}{1 + {x}^{2} } = {tan}^{ - 1} x + c \bigg \}}$ Solution of Linear Differential equation is $\rm :\longmapsto\:y \times I.F. = \displaystyle \int \:( q \times I.F. )dx$ $\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \displaystyle \int \sf \: {e}^{ {tan}^{ - 1} x} \times \dfrac{{e}^{ {tan}^{ - 1} x}}{1 + {x}^{2} }dx$ $\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \displaystyle \int \sf \: \dfrac{{e}^{ {2tan}^{ - 1} x}}{1 + {x}^{2} }dx$ On RIGHT hand side of integral, $\red{\rm :\longmapsto\:Put \: {tan}^{ - 1}x = t} \\ \red{\rm :\longmapsto\:\dfrac{dt}{dx} = \dfrac{1}{1 + {x}^{2} }} \: \: \: \: \\ \red{\rm :\longmapsto\:\dfrac{dx}{1 + {x}^{2} } = dt} \: \: \: \: \: \:$ On substituting all these VALUES, we get $\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \displaystyle \int \sf \: {e}^{2t} dt$ $\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \dfrac{ {e}^{2t} }{2} + c$ $\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red{\bigg \{ \because \: \displaystyle \int \: {e}^{x}dx = {e}^{x} + c\bigg \}}$ $\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \dfrac{ {e}^{ {2tan}^{ - 1} x} }{2} + c$ $\bf :\longmapsto\:y \: \: = \dfrac{ {e}^{ {tan}^{ - 1} x} }{2} + c{e}^{ - {tan}^{ - 1} x}$

23008.

(1+x^2)dy/dx+y=e^tan^-1x answer

Answer»

$\large\underline{\sf{<klux>SOLUTION</klux>-}}$

The given Differential Equation is

$\rm :\longmapsto\:(1+{x}^{2})\dfrac{dy}{dx} + y = {e}^{ {tan}^{ - 1} x}$

can be rewritten as

$\rm :\longmapsto\:\dfrac{dy}{dx} +\dfrac{y}{1 + {x}^{2} } = \dfrac{{e}^{ {tan}^{ - 1} x}}{1 + {x}^{2} }$

which is a Linear Differential equation.

So,

On comparing with,

$\rm :\longmapsto\:\dfrac{dy}{dx} + py = q$

we get,

$\red{\rm :\longmapsto\:p = \dfrac{1}{1 + {x}^{2} } } \\ \red{\rm :\longmapsto\:q = \dfrac{{e}^{ {tan}^{ - 1} x}}{1 + {x}^{2} }}$

INTEGRATING Factor, I.F. is given by

$\rm :\longmapsto\:I.F. = {e} \: ^{\displaystyle \int \: pdx}$

$\rm :\longmapsto\:I.F. = {e} \: ^{\displaystyle \int \: \dfrac{1}{1 + {x}^{2} } dx}$

$\bf\implies \:I.F. = {e}^{ {tan}^{ - 1} x}$

$\: \: \: \: \: \: \: \: \: \: \: \red{\bigg \{ \because \: \displaystyle \int \: \dfrac{dx}{1 + {x}^{2} } = {tan}^{ - 1} x + c \bigg \}}$

Solution of Linear Differential equation is

$\rm :\longmapsto\:y \times I.F. = \displaystyle \int \:( q \times I.F. )dx$

$\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \displaystyle \int \sf \: {e}^{ {tan}^{ - 1} x} \times \dfrac{{e}^{ {tan}^{ - 1} x}}{1 + {x}^{2} }dx$

$\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \displaystyle \int \sf \: \dfrac{{e}^{ {2tan}^{ - 1} x}}{1 + {x}^{2} }dx$

On RIGHT hand side of integral,

$\red{\rm :\longmapsto\:Put \: {tan}^{ - 1}x = t} \\ \red{\rm :\longmapsto\:\dfrac{dt}{dx} = \dfrac{1}{1 + {x}^{2} }} \: \: \: \: \\ \red{\rm :\longmapsto\:\dfrac{dx}{1 + {x}^{2} } = dt} \: \: \: \: \: \:$

On substituting all these VALUES, we get

$\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \displaystyle \int \sf \: {e}^{2t} dt$

$\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \dfrac{ {e}^{2t} }{2} + c$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red{\bigg \{ \because \: \displaystyle \int \: {e}^{x}dx = {e}^{x} + c\bigg \}}$

$\rm :\longmapsto\:y \: {e}^{ {tan}^{ - 1} x} \: = \dfrac{ {e}^{ {2tan}^{ - 1} x} }{2} + c$

$\bf :\longmapsto\:y \: \: = \dfrac{ {e}^{ {tan}^{ - 1} x} }{2} + c{e}^{ - {tan}^{ - 1} x}$

Discussion

23009.	The letters that form the word ‘ALGEBRA’ are placed in a bowl. What is theprobability of choosing a letter other than ‘ A ‘
Answer» Answer: 2/7 Step-by-step explanation: TOTAL cards = 7 (no. of LETTERS in ALGEBRA) Cards with A = 2 P(A) = Cards with A/ Total cards = 2/7 Hope it helps!!!

23009.

The letters that form the word ‘ALGEBRA’ are placed in a bowl. What is theprobability of choosing a letter other than ‘ A ‘

Answer»

Answer:

2/7

Step-by-step explanation:

TOTAL cards = 7 (no. of LETTERS in ALGEBRA)

Cards with A = 2

P(A) = Cards with A/ Total cards

= 2/7

Hope it helps!!!

Discussion

23010.	2x-3x+2=0 dvighat samikaran h ya nahi hai to solve karo
Answer» Answer: Correct Question: 2x - 3x + 2 = 0 , FIND the VALUE of x? Solution: ${ \sf{2x - 3x + 2 = 0}} \\ \\ \sf{ - x + 2 = 0} \\ \\ { \sf{ - x = - 2}} \\ \\ { \sf{x = 2}}$ So, The value of x is 2 $\sf{ \bold{Verification:}} \\ \\ \to{ \sf{2x - 3x + 2 = 0}} \\ \\ \to{ \sf{2(2) - 3(2) + 2 = 0}} \\ \\ \to{ \sf{4 - 6 + 2 = 0}} \\ \\ \to{ \sf{ - 2 + 2 = 0}} \\ \\ \to{ \sf{0 = 0}} \\ \\ \therefore{ \rm \bold{Hence Proved}}$ Therefore, Value of x is 2

23010.

2x-3x+2=0 dvighat samikaran h ya nahi hai to solve karo

Answer»

Answer:

Correct Question:

2x - 3x + 2 = 0 , FIND the VALUE of x?

Solution:

${ \sf{2x - 3x + 2 = 0}} \\ \\ \sf{ - x + 2 = 0} \\ \\ { \sf{ - x = - 2}} \\ \\ { \sf{x = 2}}$

So, The value of x is 2

$\sf{ \bold{Verification:}} \\ \\ \to{ \sf{2x - 3x + 2 = 0}} \\ \\ \to{ \sf{2(2) - 3(2) + 2 = 0}} \\ \\ \to{ \sf{4 - 6 + 2 = 0}} \\ \\ \to{ \sf{ - 2 + 2 = 0}} \\ \\ \to{ \sf{0 = 0}} \\ \\ \therefore{ \rm \bold{Hence Proved}}$

Therefore,

Value of x is 2

Discussion

23011.	Find the perimeter of a parallelogram PQRS
Answer» <P>ANSWER: We know that the perimeter of a parallelogram, P = 2(a+b) units. Step-by-step explanation: just put the VALUE hope this HELPS you

23011.

Find the perimeter of a parallelogram PQRS

Answer»

<P>ANSWER:

We know that the perimeter of a parallelogram, P = 2(a+b) units.

Step-by-step explanation:

just put the VALUE

hope this HELPS you

Discussion

23012.	Solve this problemThose who will solve this problem I will mark them as brainlist...
Answer» $\frac{ \sqrt{1 + b-1} }{b }$ $\frac{ \sqrt{b} }{b}$ $\frac{1}{ \sqrt{b} }$

23012.

Solve this problemThose who will solve this problem I will mark them as brainlist...

Answer»

$\frac{ \sqrt{1 + b-1} }{b }$

$\frac{ \sqrt{b} }{b}$

$\frac{1}{ \sqrt{b} }$

Discussion

23013.	1 point7.How many component of time seriesare available?O030704
Answer» ANSWER: COMPONENT MEN's I THINK 07

23013.

1 point7.How many component of time seriesare available?O030704

Answer»

ANSWER:

COMPONENT MEN's I THINK 07

Discussion

23014.	V. Solve by substitution method.3x-y=5 4x-2y=3
Answer» $\sf\huge {\underline{\underline{{Solution}}}}$ 3x-y= 5---① 4x-2y=3---② From EQUATION 1 we'll CONVERT the whole Equation into x or y form: => x = (5+y)/3-----➂ Now, put Equation 3 into 2 => 4x-2y=3 => 4(5+y/3) -2y=3 => 20+4y/3 -2y=3 => 20+4y-6y/3 = 3 => 20-2y/3= 3 => 20-2y= 9 => 20-9= 2y => 11= 2y => *y= 11/2* Put y's value into equation 3 => x= (5+y)/3 => x= (5+11/2)/3 =>x= 52+11/2)÷3 => x= 10+11/2÷3 =>x= 21/2÷3 => x= 21/6= 7/2 => x= 7/2* Check: => 3x-y= 5 => 3(7/2)-11/2 => 21/2-11/2 => 10/2 =5 Since,LHS = RHS(VERIFIED)

23014.

V. Solve by substitution method.3x-y=5 4x-2y=3

Answer»

$\sf\huge {\underline{\underline{{Solution}}}}$

3x-y= 5---①

4x-2y=3---②

From EQUATION 1 we'll CONVERT the whole Equation into x or y form:

=> x = (5+y)/3-----➂

Now, put Equation 3 into 2

=> 4x-2y=3

=> 4(5+y/3) -2y=3

=> 20+4y/3 -2y=3

=> 20+4y-6y/3 = 3

=> 20-2y/3= 3

=> 20-2y= 9

=> 20-9= 2y

=> 11= 2y

=> y= 11/2

Put y's value into equation 3

=> x= (5+y)/3

=> x= (5+11/2)/3

=>x= 5*2+11/2)÷3

=> x= 10+11/2÷3

=>x= 21/2÷3

=> x= 21/6= 7/2

=> x= 7/2

Check:

=> 3x-y= 5

=> 3(7/2)-11/2

=> 21/2-11/2

=> 10/2

=5

Since,LHS = RHS(VERIFIED)

Discussion

23015.	64x2– 16xy y2is the expanded form of which of the following binomial ?
Answer» rusjgfktsjxlhdkgsursufsisjdslyfoydltlysifdhldotdyfgkskrgdjfsfjsdhaxgahdagdGsgdzgidgkdhdqdhwkhfgmdjfsfvabdsdvadhwhfehfefhwhfejtengrmgdngenrgnrngdngdngdngdngdngsbfwbfwhfshfsng

Discussion

23016.	Ok jaa mat khalor koi khalaga???
Answer» कोई बात नहीं, जब मन करे तब खेल लेना L

Discussion

23017.	Please can you solve fast need for Bridge test
Answer» ANSWER: $p \: is \: 110 \\ s \: is \: 70$ PLEASE FOLLOW AND MARK ME AS BRAINLIEST!! I WILL TOO FOLLOW AND GIVE THANKS! "Thank you friend".

23017.

Please can you solve fast need for Bridge test

Answer»

ANSWER:

$p \: is \: 110 \\ s \: is \: 70$

PLEASE FOLLOW AND MARK ME AS BRAINLIEST!!

I WILL TOO FOLLOW AND GIVE THANKS!

"Thank you friend".

Discussion

23018.	P ( 3, 2 ) या बिंदूचे चरण कोणते ? *
Answer» ANSWER: प(3,2) या बिंदुचे *चरण* 1 आहे *Hope* it *will* *HELP* *you*

23018.

P ( 3, 2 ) या बिंदूचे चरण कोणते ? *

Answer»

ANSWER:

प(3,2) या बिंदुचे चरण 1 आहे

Hope it will HELP you

Discussion

23019.	Find the value of cos 600degree
Answer» the ANSWER for your QUESTION is -1/2

23019.

Find the value of cos 600degree

Answer»

the ANSWER for your QUESTION is -1/2

Discussion

23020.	1 - 3 33 -5 36 -6 4find eigen valles.
Answer» Answer: 4857586 ) 86544296708507 *minutos* *7030vo6* ( *yitutv* *GRITO* DE GE- y Step-by-step EXPLANATION: gkrvrnvt. *csvsudh* ES ,*jusjbvsjku*

23020.

1 - 3 33 -5 36 -6 4find eigen valles.

Answer»

Answer:

4857586 ) 86544296708507 minutos 7030vo6 ( yitutv GRITO DE GE- y

Step-by-step EXPLANATION:

gkrvrnvt. csvsudh ES ,jusjbvsjku

Discussion

23021.	The letters that form the word ‘ALGEBRA’ are placed in a bowl. What is theprobability of choosing a letter other than ‘ A ‘
Answer» TOTAL OUTCOMES =7 Possible outcomes = 2 so my ANSWER is 2/7

23021.

The letters that form the word ‘ALGEBRA’ are placed in a bowl. What is theprobability of choosing a letter other than ‘ A ‘

Answer»

TOTAL OUTCOMES =7

Possible outcomes = 2

so my ANSWER is 2/7

Discussion

23022.	Hii pls make this question
Answer» 1)if a\\bthen angle1=<5 ( CORRESPONDING angles are EQUAL) 2)if<4+<5=180,thena\\b.(SUM of interior angles are 180).

23022.

Hii pls make this question

Answer»

1)if a\\bthen angle1=<5 ( CORRESPONDING angles are EQUAL)

2)if<4+<5=180,thena\\b.(SUM of interior angles are 180).

Discussion

23023.	If a=i-2j-3k,b=2i+j-k and c=i+3j-2k, the find the value of c(ab).
Answer» Answer: Correct option is D 8 Given, a=2i+2j+3k,b=−1+2j+k and c=3i+j We need to find VALUE of a+tb⊥c ⇒(a+tb)⋅c=0 ⇒a⋅c+tb⋅c=0 ⇒t=− b⋅c a⋅c ⇒t=− (−i+2j+k)⋅(3i+j) (2i+2j+3k)⋅(3i+j) ⇒t=− −3+2+0 6+2+0 =8 Step-by-step EXPLANATION: PLEASE give THANK and please mark as brilliant

23023.

If a=i-2j-3k,b=2i+j-k and c=i+3j-2k, the find the value of c(ab).

Answer»

Answer:

Correct option is

D

8

Given, a=2i+2j+3k,b=−1+2j+k and c=3i+j

We need to find VALUE of a+tb⊥c

⇒(a+tb)⋅c=0

⇒a⋅c+tb⋅c=0

⇒t=−

b⋅c

a⋅c

⇒t=−

(−i+2j+k)⋅(3i+j)

(2i+2j+3k)⋅(3i+j)

⇒t=−

−3+2+0

6+2+0

=8

Step-by-step EXPLANATION:

PLEASE give THANK and please mark as brilliant

Discussion

23024.	What is the answer of that Question
Answer» HII how are you HELLO jwhich questiob

Discussion

23025.	The zeroes of quadratic polynomial are x²+25x+156 are
Answer» Answer :- Method I :- By middle term splitting method :- → x² + 25X + 156 → x² + 12x + 13x + 156 → x ( x + 12 ) + 13 ( x + 12 ) → ( x + 12 ) ( x + 13 ) → x + 12 = 0 x = -12 → x + 13 = 0 x = -13 Method II :- Using quadratic formula :- $\implies\sf x = \dfrac{-b\pm \sqrt{b^2 - 4ac}}{2a}$ For the GIVEN equation :- a = 1 b = 25 c = 156 $\implies\sf x = \dfrac{-25 \pm \sqrt{25^2 - 4 \times 156 \times 1}}{2 \times 1}$ $\implies\sf x = \dfrac{-25 \pm \sqrt{625 - 624}}{2}$ $\implies\sf x = \dfrac{-25 \pm \sqrt1}{2}$ $\implies\sf x = \dfrac{-25 \pm 1}{2}$ $\implies\sf x = \dfrac{-25 + 1}{2} , \dfrac{-25 - 1}{2}$ $\implies\sf x = \dfrac{-24}{2} , \dfrac{-26}{2}$ $\implies\sf x = - 12 , -13$ Zeros of the polynomial = -12 , -13

23025.

The zeroes of quadratic polynomial are x²+25x+156 are

Answer»

Answer :-

Method I :-

By middle term splitting method :-

→ x² + 25X + 156

→ x² + 12x + 13x + 156

→ x ( x + 12 ) + 13 ( x + 12 )

→ ( x + 12 ) ( x + 13 )

→ x + 12 = 0

x = -12

→ x + 13 = 0

x = -13

Method II :-

Using quadratic formula :-

$\implies\sf x = \dfrac{-b\pm \sqrt{b^2 - 4ac}}{2a}$

For the GIVEN equation :-

a = 1
b = 25
c = 156

$\implies\sf x = \dfrac{-25 \pm \sqrt{25^2 - 4 \times 156 \times 1}}{2 \times 1}$

$\implies\sf x = \dfrac{-25 \pm \sqrt{625 - 624}}{2}$

$\implies\sf x = \dfrac{-25 \pm \sqrt1}{2}$

$\implies\sf x = \dfrac{-25 \pm 1}{2}$

$\implies\sf x = \dfrac{-25 + 1}{2} , \dfrac{-25 - 1}{2}$

$\implies\sf x = \dfrac{-24}{2} , \dfrac{-26}{2}$

$\implies\sf x = - 12 , -13$

Zeros of the polynomial = -12 , -13

Discussion

23026.	A nut and a bolt currently have the sameprice. If the price of a screw nut rises by 3%and the price of bolt goes up by 5% then howmuch more percent will it cost for 3 nuts and3 bolts?
Answer» Answer: Hope it will be helpful yo you ! Step-by-step EXPLANATION: Sol. By common sense the required answer will be 4%. SINCE the number of nuts and bolts are same i.e. 3 nuts and 3 bolts and initially both prices were same so all over percentage increase will be average of 3% of 5% = 4%

23026.

A nut and a bolt currently have the sameprice. If the price of a screw nut rises by 3%and the price of bolt goes up by 5% then howmuch more percent will it cost for 3 nuts and3 bolts?

Answer»

Answer:

Hope it will be helpful yo you !

Step-by-step EXPLANATION:

Sol. By common sense the required answer will be 4%. SINCE the

number of nuts and bolts are same i.e. 3 nuts and 3 bolts and initially both

prices were same so all over percentage increase will be average of 3% of 5% =

4%

Discussion

23027.	The function fx=x²+x is increasing for
Answer» Answer: L don't know sorry Step-by-step EXPLANATION: MARK me as BRAIN list please

23027.

The function fx=x²+x is increasing for

Answer»

Answer:

L don't know sorry

Step-by-step EXPLANATION:

MARK me as BRAIN list

please

Discussion

23028.	2) The Sum of first Five Positive integersdivisible by 6 is:(a) 180(b) 90 (c) 45(d) 30
Answer» Answer: 30 Step-by-step explanation: I HOPE it will be useful for you PLEASE make me as BRAINLIST

23028.

2) The Sum of first Five Positive integersdivisible by 6 is:(a) 180(b) 90 (c) 45(d) 30

Answer»

Answer:

30

Step-by-step explanation:

I HOPE it will be useful for you

PLEASE make me as BRAINLIST

Discussion

23029.	When the largest 3 - digit number is divided by 3 , we get
Answer» Answer: We know the divisibility RULE for 3: If the sum of the DIGITS of a number is DIVISIBLE by 3, then the number is also divisible by 3. Here, 9+9+6=24 is MULTIPLE of 3. So, 996 is the largest number divisible by 3.

23029.

When the largest 3 - digit number is divided by 3 , we get

Answer»

Answer:

We know the divisibility RULE for 3:

If the sum of the DIGITS of a number is DIVISIBLE by 3, then the number is also divisible by 3.

Here, 9+9+6=24 is MULTIPLE of 3.

So, 996 is the largest number divisible by 3.

Discussion

23030.	Hello pls help me in this question
Answer» Answer: 1) due to corresponding ANGLES are equal 2)co INTERIOR angles add up to 180 degrees hope this helps please mark me BRAINLIEST

23030.

Hello pls help me in this question

Answer»

Answer:

1) due to corresponding ANGLES are equal

2)co INTERIOR angles add up to 180 degrees

hope this helps please mark me BRAINLIEST

Discussion

23031.	Ii] (K-2)x+(k-1)y=17; (k-1)x+(k-2)y=18; x+y=5 *O 7O 5O 10O 50
Answer» = K+2 3 = 3k 7 ⇒ k−1 2 = k+2 3 ⇒2k+4=3k−3 ⇒k=7 HENCE, the VALUE of k is 7.

23031.

Ii] (K-2)x+(k-1)y=17; (k-1)x+(k-2)y=18; x+y=5 *O 7O 5O 10O 50

Answer»

=

K+2

3

=

3k

7

⇒

k−1

2

=

k+2

3

⇒2k+4=3k−3

⇒k=7

HENCE, the VALUE of k is 7.

Discussion

23032.	Angle between hands of clock when it's show the the time 9:45 is
Answer» Answer: 22.5 DEGREE Step-by-step EXPLANATION: HOPE IT HELPS U

23032.

Angle between hands of clock when it's show the the time 9:45 is

Answer»

Answer:

22.5 DEGREE

Step-by-step EXPLANATION:

HOPE IT HELPS U

Discussion

23033.	6/9+3/4+2/5 and batao
Answer» Answer: 120+135+72/180 = 327/180 = ... Step-by-step EXPLANATION:

23033.

6/9+3/4+2/5 and batao

Answer»

Answer:

120+135+72/180

=

327/180

=

...

Step-by-step EXPLANATION:

Discussion

23034.	Sheetal saved Rs 5 in the first week of a year and then increased her weekly savings by Rs 1.75 . If in the nth week, her savings become Rs20.75, Find n?
Answer» ANSWER: kokokokok Step-by-step EXPLANATION:

23034.

Sheetal saved Rs 5 in the first week of a year and then increased her weekly savings by Rs 1.75 . If in the nth week, her savings become Rs20.75, Find n?

Answer»

ANSWER:

kokokokok

Step-by-step EXPLANATION:

Discussion

23035.	In a compitative exam there are 5 papers. the average score of ramesh in first three papers is 76 and his average score in last three papers is 72. If his average score for all the papers is 73.what is his score in the third paper?
Answer» ANSWER: 83 is answer of your LIFE with HAPPINESS and PROSPERITY and happiness and prosperity of your QUESTIONS

23035.

In a compitative exam there are 5 papers. the average score of ramesh in first three papers is 76 and his average score in last three papers is 72. If his average score for all the papers is 73.what is his score in the third paper?

Answer»

ANSWER:

83 is answer of your LIFE with HAPPINESS and PROSPERITY and happiness and prosperity of your QUESTIONS

Discussion

23036.	Which set represent {1,2,3}
Answer» ANSWER: INFINITE Step-by-step EXPLANATION: MARK as BRILLIANT answer

23036.

Which set represent {1,2,3}

Answer»

ANSWER:

INFINITE

Step-by-step EXPLANATION:

MARK as BRILLIANT answer

Discussion

23037.	Some plz help my a$$
Answer» ANSWER: kgxkstkgkmxvmfzmxmkzkzmzkxknzhnj

23037.

Some plz help my a$$

Answer»

ANSWER:

kgxkstkgkmxvmfzmxmkzkzmzkxknzhnj

Discussion

23038.	(1+k)n is the formula ofFVIFPVIFAPVIFSkipMark for ReviewFVIFA
Answer» ANSWER: mgsgkskvkskstkzgkstististkstktsoydo

23038.

(1+k)n is the formula ofFVIFPVIFAPVIFSkipMark for ReviewFVIFA

Answer»

ANSWER:

mgsgkskvkskstkzgkstististkstktsoydo

Discussion

23039.	Classmate-32122-لت--\| - دلوانک رفع -2
Answer» Answer: 32 sayaad HOGA. ?????????????

23039.

Classmate-32122-لت--| - دلوانک رفع -2

Answer»

Answer:

32 sayaad HOGA. ?????????????

Discussion

23040.	The pay back period for the various projectis given as follows; Project A: 1 Year, ProjectB: 6 months, Project C: 2 Years, Project D:4 Years , Which project to be selected first ?АCDB
Answer» Answer: 2 YEARS, PROJECT the PAYBACK PERIOD

23040.

The pay back period for the various projectis given as follows; Project A: 1 Year, ProjectB: 6 months, Project C: 2 Years, Project D:4 Years , Which project to be selected first ?АCDB

Answer»

Answer:

2 YEARS, PROJECT the PAYBACK PERIOD

Discussion

23041.	The remainder when the square of any prime number greater than 3 is divided by 6, is(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a natural numberand (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1)a) 1b) 3c) 4d) 2
Answer» Answer: The remainder when the SQUARE of any prime number GREATER than 3 is divided by 6, is (Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a NATURAL number and (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1 c is the correct answer

23041.

The remainder when the square of any prime number greater than 3 is divided by 6, is(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a natural numberand (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1)a) 1b) 3c) 4d) 2

Answer»

Answer:

The remainder when the SQUARE of any prime number GREATER than 3 is divided by 6, is

(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a NATURAL number

and (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1

c is the correct answer

Discussion

23042.	3)Find the value of k, if the area of 1the triangle with vertices at Aſk,3);B(-5,7); C(-1,4) is 4 square units:0 -3,-7/3O 3,3O 3,-7/3O 9,-7
Answer» ANSWER: HOPE U HAV a NICE day 안녕 안녕

23042.

3)Find the value of k, if the area of 1the triangle with vertices at Aſk,3);B(-5,7); C(-1,4) is 4 square units:0 -3,-7/3O 3,3O 3,-7/3O 9,-7

Answer»

ANSWER:

HOPE U HAV a NICE day

안녕 안녕

Discussion

23043.	Convert 105 meter /second into km / hr
Answer» Answer: 378km/h Step-by-step EXPLANATION: We have to MULTIPLY it by 18/5 10518/5 2118 378 Thus 378 km/h

23043.

Convert 105 meter /second into km / hr

Answer»

Answer:

378km/h

Step-by-step EXPLANATION:

We have to MULTIPLY it by 18/5

105*18/5

21*18

378

Thus 378 km/h

Discussion

23044.	Hii sir pls help me on this question
Answer» Step-by-step EXPLANATION: what is this i mean please write and GIVE to ANS.

23044.

Hii sir pls help me on this question

Answer»

Step-by-step EXPLANATION:

what is this

i mean please write and GIVE to ANS.

Discussion

23045.	0.0000813 is expressed in scientific notation as ________
Answer» Answer: 8.13×10^-5 is the SCIENTIFIC NOTATION of 0.0000813

23045.

0.0000813 is expressed in scientific notation as ________

Answer»

Answer:

8.13×10^-5 is the SCIENTIFIC NOTATION of 0.0000813

Discussion

23046.	एक व्यक्ति ने 2560 किमी० की कुल दूरी का कुछ भाग वायुयान कुछ भाग जलयान से तथा शेष भाग कार द्वारा तय किया. वायुयान, जलयान तथा कार द्वारा की गई यात्राओं में लिये गये समय का अनुपात 1:4:5 है तथा इन यात्राओं में प्रयोग किये गये साधनों की औसत गतियों का अनुपात 20:1: 8 है. यदि पूरी यात्रा में औसत गति 64 किमी०/घण्टा रही हो तो जलयान की औसत गति, इसके द्वारा लिया गया समय तथा इस द्वारा तय की गई दूरी ज्ञात कीजिए.
Answer» oooooooooooooooooooo

23046.

एक व्यक्ति ने 2560 किमी० की कुल दूरी का कुछ भाग वायुयान कुछ भाग जलयान से तथा शेष भाग कार द्वारा तय किया. वायुयान, जलयान तथा कार द्वारा की गई यात्राओं में लिये गये समय का अनुपात 1:4:5 है तथा इन यात्राओं में प्रयोग किये गये साधनों की औसत गतियों का अनुपात 20:1: 8 है. यदि पूरी यात्रा में औसत गति 64 किमी०/घण्टा रही हो तो जलयान की औसत गति, इसके द्वारा लिया गया समय तथा इस द्वारा तय की गई दूरी ज्ञात कीजिए.

Answer»

oooooooooooooooooooo

Discussion

23047.	(a +2) x2 + 3x +5 =0 will be aQuadratic equation.
Answer» ANSWER: No it is not a QUADRATIC EQUATION because there is no DEGREE 2

23047.

(a +2) x2 + 3x +5 =0 will be aQuadratic equation.

Answer»

ANSWER:

No it is not a QUADRATIC EQUATION because there is no DEGREE 2

Discussion

23048.	If Alpha and beta are the zeros of x^2-5x+6. find alpha and beta
Answer» ANSWER: gthtgcyiughhjjghgfr646gfyfgy

23048.

If Alpha and beta are the zeros of x^2-5x+6. find alpha and beta

Answer»

ANSWER:

gthtgcyiughhjjghgfr646gfyfgy

Discussion

23049.	Verify whether 2 is the zero of the polynomial P(x)=2x3- px2+17x-6 if p is 11.
Answer» <P>Answer: Yes Step-by-step explanation: If 2 is the zero of the polynomial p(X) then p(2) = 0 Given => p(x) = 2x³-px²+17x-6 if p = 11 then p(x) = 2x³-11x²+17x-6 let x = 2 then p(2) = 2(2)³-11(2)²+17(2)-6 = 16-44+34-6 = 0 therefore 2 is the zero of the polynomial Hence verified

23049.

Verify whether 2 is the zero of the polynomial P(x)=2x3- px2+17x-6 if p is 11.

Answer»

<P>Answer:

Yes

Step-by-step explanation:

If 2 is the zero of the polynomial p(X) then p(2) = 0

Given => p(x) = 2x³-px²+17x-6

if p = 11 then p(x) = 2x³-11x²+17x-6

let x = 2 then

p(2) = 2(2)³-11(2)²+17(2)-6 = 16-44+34-6 = 0

therefore 2 is the zero of the polynomial

Hence verified

Discussion

23050.	What is The probability of any event
Answer» ANSWER: In an experiment, the PROBABILITY of an event is the likelihood of that event occuring. Probability is a value between (and INCLUDING) ZERO and ONE. If P(E) represents the probability of an event E, then: P(E) = 0 if and only if E is an impossible event.

23050.

What is The probability of any event

Answer»

ANSWER:

In an experiment, the PROBABILITY of an event is the likelihood of that event occuring. Probability is a value between (and INCLUDING) ZERO and ONE. If P(E) represents the probability of an event E, then: P(E) = 0 if and only if E is an impossible event.

Discussion

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