Explore topic-wise InterviewSolutions in .

ANSWER:

a CIRCLE can be DRAWN with COMPASS

ANSWER:

The price of a smartphone is 5000 more than the cost of two feature phones &

the cost of 4 feature phones and two smartphone is 88,000 .

Exigency To Find : The cost of a smartphone and a feature phone.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider the cost price of smart phone and feature phone be Rs. x & Rs. y , respectively .

⠀⠀⠀⠀⠀⠀CASE I : The price of a smartphone is Rs. 5000 more than the cost of two feature phones .

\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \bf x = 2y + 5000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 1 }\bigg\rgroup\\\end{gathered}

:⟹x=2y+5000

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Eq

n

1

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⠀⠀⠀⠀⠀⠀CASE II : The cost of 4 feature phones and two smartphones is Rs. 88,000 .

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \bf 4y + 2x = 88000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 2}\bigg\rgroup\\\end{gathered}

:⟹4y+2x=88000

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⎧

Eq

n

2

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⠀⠀⠀⠀⠀⠀Now , Finding the cost of Smart phone & Feature phone :

\begin{gathered}\qquad \:\maltese\:\bf{ From \:EQUATION \:2 \:\::}\\\end{gathered}

✠FromEquation2:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:2\:: 4y + 2x = 88000 }\bigg\rgroup \\\\\end{gathered}

†

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⎪

⎪

⎪

⎧

Equation2:4y+2x=88000

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⎪

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⎫

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

⠀⠀⠀⠀⠀⠀\begin{gathered}\UNDERLINE {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Eq^n\:1 \: : \::}}\\\end{gathered}

⋆NowBySubstitutingtheEq

n

1::

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎪

⎪

⎧

Equation1:x=2y+5000

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⎪

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\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \sf 4y +2 (2y + 5000) = 88000 \:\:\\\end{gathered}

:⟹4y+2(2y+5000)=88000

\begin{gathered}\qquad :\implies \sf 4y +4y + 10000 = 88000 \:\:\\\end{gathered}

:⟹4y+4y+10000=88000

\begin{gathered}\qquad :\implies \sf 4y +4y = 88000 - 10000 \:\:\\\end{gathered}

:⟹4y+4y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 88000 - 10000 \:\:\\\end{gathered}

:⟹8y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 78000 \:\:\\\end{gathered}

:⟹8y=78000

\begin{gathered}\qquad :\implies \sf y = \dfrac{ 78000}{8} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \sf y = \cancel {\dfrac{ 78000}{8}} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \bf y = 9750 \:\:\\\end{gathered}

:⟹y=9750

\begin{gathered}\qquad :\implies \frak{\underline{\PURPLE{\:y = Rs.\: 9750 }} }\:\:\bigstar \\\end{gathered}

:⟹

y=Rs.9750

★

⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: \: Value\:of\: y \ [ \ 9750 \ ] \:in \:Eq^n \:1 \::}}\\\end{gathered}

⋆NowBySubstitutingtheValueofy [ 9750 ]inEq

n

1:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎪

⎪

⎧

Equation1:x=2y+5000

⎭

⎪

⎪

⎪

⎫

\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \sf x = 2(9750) + 5000 \:\:\\\end{gathered}

:⟹x=2(9750)+5000

\begin{gathered}\qquad :\implies \sf x = 19500 + 5000 \:\:\\\end{gathered}

:⟹x=19500+5000

\begin{gathered}\qquad :\implies \bf x = 24500 \:\:\\\end{gathered}

:⟹x=24500

\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:x \:= Rs.\: 24500 }} }\:\:\bigstar \\\end{gathered}

:⟹

x=Rs.24500

★

Therefore,

The cost of smartphone is : x = Rs. 24, 500

The cost of feature phone: y = Rs. 9,750

Therefore,

⠀⠀⠀⠀⠀\begin{gathered}\qquad \therefore {\underline{ \sf \:Cost \:of\:Smartphone \:and \:feature \:phone \:are\:\bf Rs. \ 24,500 \:\& \: Rs.\: 9,750\:\:\sf , \ respectively . }}\\\end{gathered}

∴

CostofSmartphoneandfeaturephoneareRs. 24,500&Rs.9,750, respectively.

⠀

Answer:

Concept:- Free Fall - Motion of Objects Under the Influence of Gravitational Force of the Earth

\bf \: INITIAL \: velocity \: U = 40Initialvelocityu=40

\bf \: Final \: velocity \: V = 0Finalvelocityv=0

\bf \: Height, s = \: ?Height,s=?

\bf \: By \: third \: equation \: of \: motion Bythirdequationofmotion

\bf \: v²-u²=2gsv²−u²=2gs

\bf 0=40²=-2×10×s0=40²=−2×10×s

\bf \: s = \frac{ \: 160 \: }{ \: 20 \: } s=

20

160

\bf \: s =80m/ss=80m/s

Total distance travelled by STONE = upward distance + downward distance

\bf2×s=160m2×s=160m

\bf \: Total \: Displacement=0TotalDisplacement=0

Since, the initial and final point is same.

Answer:

The STUDENT is WRONG.

If the graph of a polynomial intersects the x-axis twice, it Is a QUADRATIC polynomial (Polynomial in which HIGHEST power is 2).

Thanks.

Answer:

i don't KNOW sorry bro

Step-by-step EXPLANATION:

PLEASE MARK as brainlist bro please

সঠিক প্রশ্ন :

একটি তারের প্রস্থচ্ছেদের ব্যাস 50% কমানো হল। আয়তন অপরিবর্তিত রাখতে হলে তারটির দৈর্ঘ্য কত শতাংশ বাড়াতে হবে?

দেওয়া আছে :

• একটি তারের প্রস্থচ্ছেদের ব্যাস 50% কমানো হল।

বার করত হবে :

• আয়তন অপরিবর্তিত রাখতে হলে তারটির দৈর্ঘ্য কত শতাংশ বাড়াতে হবে?

সমাধান :

ধরে নেওয়া যাক যে,

• তারের প্রস্থচ্ছেদের ব্যাসার্ধ R একক
• তারের দৈর্ঘ্য H একক

∴ ব্যাস = 2r একক

তারের প্রস্থচ্ছেদের ব্যাস 50% কমানো হলে, পরিবর্তিত ব্যাস হবে,

একক

একক

একক

একক

একক

একক

একক।

• ∴ পরিবর্তিত ব্যাস = r একক।
• ∴ পরিবর্তিত ব্যাসার্ধ = r/2 একক।

পূর্বে তারটির আয়তন ছিল = πr²h ঘন একক

ধরা যাক, আয়তন অপরিবর্তিত রাখতে হলে তারটির দৈর্ঘ্য হবে H একক

তারটির দৈর্ঘ্য শতকরা বাড়বে,

একক

একক

(eq.(i)) থেকে,

একক

একক

একক

একক

একক

একক।

∴ তারটির দৈর্ঘ্য 300% বৃদ্ধি করতে হবে।

ANSWER:

ue8r8duoe9ejxi9r

3j3o4i8eo38ro

u74848rieo20wte

Step-by-step EXPLANATION:

ueueri4i842kd

kejei38r8u4u39wo

7e8e8eiriurnd9d8

Step-by-step EXPLANATION:

I don't KNOW ANYTHING about this QUESTION

ANSWER:

i don't KNOW SORRY bro

Step-by-step explanation:

please mark as BRAINLIST bro

ANSWER:

SRY i don't KNOW answer

idodjhujkk

this is the ANSWER

Step-by-step EXPLANATION:

MARK as EXPECTED

A monomial is an expression in algebra that contains one term, like 3XY. Monomials INCLUDE: numbers, WHOLE numbers and VARIABLES that are multiplied together, and variables that are multiplied together.

so -0.5(1+1/x) is not a monomial

please mark my answer as brainliest

Step-by-step EXPLANATION:

the DISTANCE from. the x-axis is 2 UNITS

Answer:

The PRICE of a smartphone is 5000 more than the cost of two feature phones &

the cost of 4 feature phones and two smartphone is 88,000 .

Exigency To FIND : The cost of a smartphone and a feature phone.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider the cost price of smart phone and feature phone be Rs. x & Rs. y , respectively .

⠀⠀⠀⠀⠀⠀CASE I : The price of a smartphone is Rs. 5000 more than the cost of two feature phones .

\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \bf x = 2y + 5000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ EQ^n \: 1 }\bigg\rgroup\\\end{gathered}

:⟹x=2y+5000

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⎧

Eq

n

1

⎭

⎪

⎪

⎪

⎫

⠀⠀⠀⠀⠀⠀CASE II : The cost of 4 feature phones and two smartphones is Rs. 88,000 .

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \bf 4y + 2x = 88000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 2}\bigg\rgroup\\\end{gathered}

:⟹4y+2x=88000

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Eq

n

2

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⠀⠀⠀⠀⠀⠀Now , Finding the cost of Smart phone & Feature phone :

\begin{gathered}\qquad \:\maltese\:\bf{ From \:Equation \:2 \:\::}\\\end{gathered}

✠FromEquation2:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:2\:: 4y + 2x = 88000 }\bigg\rgroup \\\\\end{gathered}

†

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⎪

⎪

⎪

⎧

Equation2:4y+2x=88000

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⎪

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\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Eq^n\:1 \: : \::}}\\\end{gathered}

⋆NowBySubstitutingtheEq

n

1::

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎪

⎪

⎧

Equation1:x=2y+5000

⎭

⎪

⎪

⎪

⎫

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \sf 4y +2 (2y + 5000) = 88000 \:\:\\\end{gathered}

:⟹4y+2(2y+5000)=88000

\begin{gathered}\qquad :\implies \sf 4y +4y + 10000 = 88000 \:\:\\\end{gathered}

:⟹4y+4y+10000=88000

\begin{gathered}\qquad :\implies \sf 4y +4y = 88000 - 10000 \:\:\\\end{gathered}

:⟹4y+4y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 88000 - 10000 \:\:\\\end{gathered}

:⟹8y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 78000 \:\:\\\end{gathered}

:⟹8y=78000

\begin{gathered}\qquad :\implies \sf y = \dfrac{ 78000}{8} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \sf y = \cancel {\dfrac{ 78000}{8}} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \bf y = 9750 \:\:\\\end{gathered}

:⟹y=9750

\begin{gathered}\qquad :\implies \FRAK{\underline{\purple{\:y = Rs.\: 9750 }} }\:\:\bigstar \\\end{gathered}

:⟹

y=Rs.9750

★

⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: \: Value\:of\: y \ [ \ 9750 \ ] \:in \:Eq^n \:1 \::}}\\\end{gathered}

⋆NowBySubstitutingtheValueofy [ 9750 ]inEq

n

1:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎪

⎪

⎧

Equation1:x=2y+5000

⎭

⎪

⎪

⎪

⎫

\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \sf x = 2(9750) + 5000 \:\:\\\end{gathered}

:⟹x=2(9750)+5000

\begin{gathered}\qquad :\implies \sf x = 19500 + 5000 \:\:\\\end{gathered}

:⟹x=19500+5000

\begin{gathered}\qquad :\implies \bf x = 24500 \:\:\\\end{gathered}

:⟹x=24500

\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:x \:= Rs.\: 24500 }} }\:\:\bigstar \\\end{gathered}

:⟹

x=Rs.24500

★

Therefore,

The cost of smartphone is : x = Rs. 24, 500

The cost of feature phone: y = Rs. 9,750

Therefore,

⠀⠀⠀⠀⠀\begin{gathered}\qquad \therefore {\underline{ \sf \:Cost \:of\:Smartphone \:and \:feature \:phone \:are\:\bf Rs. \ 24,500 \:\& \: Rs.\: 9,750\:\:\sf , \ respectively . }}\\\end{gathered}

∴

CostofSmartphoneandfeaturephoneareRs. 24,500&Rs.9,750, respectively.

⠀

Step-by-step explanation:

dekh 25 min hogye solve karte karte brian list MARK kareao

sifshdsjfzgjdgckgfkgxhfzjgdjxjvxvj

Answer:

1. The reciprocal of -2 is 1/-2

2. LET the other no. be x.

According to QUESTION, 1/9 +x= 5

By TRANSPORTING method we GET,

x= 5×9/1

x= 45/1 or 45

3. the additive inverse of 213 is -213

Hope it's help U

ANSWER:

oufigufofigughdigiyoyigoyt

Step-by-step EXPLANATION:

The BEST RESOURCE for #STUDENTS. #shaalaa HTTPS://www.shaalaa.com/question-bank-solutions/let-f-r-r-be-defined-f-x-x4-choose-correct-answer-f-one-one-b-f-many-one-ontof-one-one-but-not-d-f-neither-one-one-nor-types-functions_11749#z=nQjBb3rm

ANSWER:

hello PLZ me BRAIN list PLEASE

Step-by-step EXPLANATION:

YES it is a MONOMIAL as it has only ONE TERM in it

ANSWER:

your QUESTION is WRONG !!

Step-by-step EXPLANATION:

TAKE out the LCM then make pairs and multiply by the number that is MISSING to complete the PAIR and then divide by the same number to complete the pair And your answer will come

ANSWER:

-8Y-(y-5) =-13

-8y-y+5 = -13

-9y + 5 = -13

-9y = -13 - 5

-9y = -18

9y = 18

y=2

Answer:

SORRY I didn't miss my CLASS so I need to go sorry for this

ANSWER:

BKC hcxkjgdkgjflhgkdugkd

Step-by-step EXPLANATION:

CN, xhfhydlfhzzhflyfzkyzflykfzufdkgxglhfzzzzfzkgxchkgxklhcohcchcufzhcfjzjfxjgxogfgodoyfoyfoufpuf

Answer:

b .65 is answer

Step-by-step explanation:

A CERTAIN freezing process requires that ROOM temperature be lowered from 40°C at the rate of 5°C every HOUR. What will be the room temperature 10 hours after the process begins?

To Find:-

Find the room temperature after 10 hours.

Solution:-

Given ,

PRESENT temperature of room = 40°C

Rate of temperature decreases 5°C per hour

First ,

We have to find how many °C will decrease in 10 hours:-

\sf\longrightarrow \: 5 \TIMES number \: of \: hours ⟶5×numberofhours

\sf\longrightarrow \: 5 \times 10 ⟶5×10

\sf\longrightarrow \: 50°C ⟶50°C

Now ,

We have to subtract 50°C from the room current temperature:-

\sf\longrightarrow \: 40 - 50 ⟶40−50

\sf\longrightarrow \: - 10°C ⟶−10°C

Hence ,

- 10°C is the temperature after 10 hours

1,49,18,25,000.00 INDIAN RUPEE

Answer:

2x2 - 15x) - 4 = 0

STEP

2

:

Trying to factor by splitting the middle TERM

2.1 Factoring 2x2-15x-4

The first term is, 2x2 its coefficient is 2 .

The middle term is, -15x its coefficient is -15 .

The last term, "the constant", is -4

Step-1 : MULTIPLY the coefficient of the first term by the constant 2 • -4 = -8

Step-2 : Find two factors of -8 whose SUM equals the coefficient of the middle term, which is -15 .

-8 + 1 = -7

-4 + 2 = -2

-2 + 4 = 2

-1 + 8 = 7

Observation : No two such factors can be found !!

ANSWER:

your answer is correct.

Step-by-step EXPLANATION:

PLEASE MARK my answer as BRAINLIEST.

ANSWER:

div b){ log(ab)^2 - log(a) log(b) }

. HOPE it will help you

ANSWER:

okkkkkkkmk llk

thanks

please MAKE me BRAINLEST

Answer:

Q.2 [A] SOLVE the following:

1. Represent 0.3 on a number line.

2. Write 3.5 as a fraction. Reduce the fraction to the

simplest form.

3. Add: 16.07 and 12.48

4. The SURFACE of a table is in the shape of a square. If the

length of a side is 2 metre 25 centimeter, find

the

perimeter of its square.

5. if x + 4 = 4 = 12. find the VALUE of x.

6. If 5 = find the value of o

...

+

®

===

Answer:

896

Step-by-step EXPLANATION:

MARK me as BRAINLIEST

ANSWER:

SORRY I didn't KNOW the answer

Answer:

32 ×28= 896

thank you

hope it HELPS :))

ANSWER:

I don't UNDERSTAND this that's

ANSWER:

(a+2)

Step-by-step EXPLANATION:

I THINK it is HELPFUL for you

Step-by-step EXPLANATION:

i HOPE RIGHT ANSWER PLEASE

Step-by-step EXPLANATION:

dfuyyyuiizikeoeoeeekekekekkkekekekee

ANSWER:

MARK me as the BRAINLIEST

Step-by-step EXPLANATION:

FEMALE TO SHOW. ♥️ jpr-waqq-sfa

Answer:

(i) Let A(2,3), B(−1,0) and C(2,−4) are the vertices of △ABC

Area of TRIANGLE=

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]

Here (x

1

,y

1

)=(2,3)

(x

2

,y

2

)=(−1,0)

(x

3

,y

3

)=(2,−4)

=

2

1

[2(0+4)−1(−4−3)+2(3−0)]

=

2

1

[8+7+6]

=

2

21

sq.unit

(i) Let A(−5,1), B(3,−5) and C(5,2) are the vertices of △ABC

Area of triangle=

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]

Here (x

1

,y

1

)=(−5,−1)

=(x

2

,y

2

)=(3,−5)

=(x

3

,y

3

)=(5,2)

=

2

1

[−5(−5−2)+3(2+1)+5(−1+5)]

=

2

1

[35+9+20]

=

2

64

=32 sq.unit

Answer:

2.828

Step-by-step explanation:

5-2.828=2.172

Mark me as the BRAINLIEST

Answer:

4545r44244rr5t4tr45r3rrtrt

Step-by-step EXPLANATION:

༺mark me as BRAIN list answer༻

22 \cot(?) \cos( \BETA {? \times \frac\times \frac{?}{?} }^{?} \times \frac

Step-by-step explanation:

SINCE 2 and 5 are not in pairs MULTIPLY by 2 and 5 to make it a perfect square. the REQUIRED NUMBER=360*2*5=3600.

The smallest square number DIVIDED by 8,9,10 =3600.

ANSWER:

jshjjajsjhsjsjsjqjsjsjjajwhshwhwjaus

Intergalactic gas is so tenuous that it emits no light of its own. ... Instead astronomers study it indirectly by observing how it selectively ABSORBS the light COMING from faraway SOURCES known as QUASARS.

Answer:

answer for this question is 21% profit.

Step-by-step EXPLANATION:

USE this formula, for this type of question alone. REFER the attachement.

mark as BRAINLIEST answer. thank you

Answer:

An isosceles trapezoid with a diagonal that measures 42 cm and one leg measures 23 , what is the length of the other diagonal?

• An isosceles trapezoid with a diagonal that measures 42 cm and one leg measures 23 cm.

• To recall, a trapezoid, also referred to as a trapezium, is a quadrilateral with one pair of PARALLEL sides and another pair of non-parallel sides. Like SQUARE and rectangle, a trapezoid is also flat. THEREFORE, it is 2D.

• In a trapezoid, the parallel sides are known as the bases, while the pair of non-parallel sides are known as the legs. The perpendicular distance between the two parallel sides of a trapezium is known as a trapezoid height.

In SIMPLE WORDS, the base and height of a trapezoid are perpendicular to each other.