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23201.

प्रश्नचिन्हाच्या जागी येणारी संख्या ओळखा 2,10,40,120,240,?अ.360ब.420क.480ड.240

Answer»

Step-by-step EXPLANATION:

ब.420

here is your ANSWER mate

hope it HELPS you
Discussion
23202.

Solve:√x-1-q-r÷p +√x-1-r-p÷q +√x-1-p-q÷r=3​

Answer»

ANSWER:

√27372728483728_847383929€°`=€=$×$=$°•=|×€×|π÷${|÷¢÷¢÷€÷$π•π|÷`{€÷ππ`π`=$÷`×|÷|π÷`°¢°©°{^^×€{€©^™©©℅©[{$=©[${${$[$[%[©[£]]%~`|•√π÷׶∆£€$¢^°={}\%©®™℅[]
Discussion
23203.

इंग्रजी वर्णमालेत F आणि V पासून समान अंतरावर असलेले अक्षर कोणते ?अ.Mब.Nक.Lड.O

Answer»

इंग्रजी वर्णमालेत F आणि V पासून समान अंतरावर असलेले अक्षर कोणते ?

अ.M

ब.N

क.L

ड.O

उत्तर

ब N

Discussion
23204.

On the same day12. Malala had + 27000 in her account in July 2018. She deposited ? 3500 in the next month and with1900 in September 2018. Find her balance.13. Vijay travelled by a bus towards east of Shimla by 37 km and then towards west of Shimla by 72 km. Hewas he from Shimla?​

Answer»

12. amount she had = 27000 Rs

amount she deposited = 3500 Rs

she WITHDRAWN = 1900 Rs

Amount BALANCE. = 27000 + 3500 - 1900)

= 30500 - 1900

= 28100 Rs

13. 35 km west from SHIMLA
Discussion
23205.

If P(x) = x^ 3 -8x^2 -8x-9 then?​

Answer»

Answer:

dont KNOW ehat is that

Step-by-step explanation:

i REA really

know THATIF P(X) = x^ 3 -8x^2 -8x-9 then

\alpha \beta + \beta \gamma + \gamma \alpha =

?
Discussion
23206.

In a chemical factory two wheels of different radius were connected with a belt. Radius ofthe bigger wheel is 21cm and radius of the smaller wheel is 7cm. If the bigger wheel rotatescompletely 100 times, find out the number of times that the smaller wheel rotates.​

Answer»

ANSWER:

I am sorry .IWILL give U the answer later
Discussion
23207.

725 का निकटतम सैकड़े तक सन्निकट मान है-(A) 720(B)700(C) 800(D)730​

Answer»

ANSWER:

answer is 725 का निकटतम सैकडे 700
Discussion
23208.

Simplify (-3)* [5X(-2) + (7*8) = (2x14]​

Answer»

ANSWER:

Your answer in ATTACHMENT,

HOPE this HELP you

Discussion
23209.

Straight angle = 2×____________​

Answer»

❄️❄️Heya MATE!!!

your ANSWER is

90°
Discussion
23210.

)If the vertices of a triangle are (3,1);(4,2); and(5,3). Then area is: *​

Answer»

Answer:

0 sq. UNITS

Step-by-step EXPLANATION:

Given:

Vertices of the triangle = (3, 1), (4, 2), (5, 3)

To find:

The area of the triangle

Solution:

Area of the triangle = \frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]

Here, x_1=3, x_2=4, x_3=5, y_1=1, y_2=2, y_3=3

So, the area of the triangle = \frac{1}{2}[3(2-3)+4(3-1)+5(1-2)]

⇒ \frac{1}{2}[3(2-3)+4(3-1)+5(1-2)]

⇒ \frac{1}{2}[3(-1)+4(2)+5(-1)]

⇒ \frac{1}{2}[-3+8-5]

⇒ \frac{1}{2}[8-8]

⇒ \frac{1}{2}\times 0

⇒ 0 sq. unit

∴ The area of the triangle is 0 sq. units.
Discussion
23211.

Check that the plane 5x + 2y

Answer»

ANSWER:

I didn't UNDERSTAND this QUESTION so I can't answer this question

Discussion
23212.

Kite is an example of ______​

Answer»

ANSWER:

trapezium

Step-by-step EXPLANATION:

HOPE it HELPS you

Discussion
23213.

.Sollution of the equation :4/x -3 =5/(2x +3) are : *​

Answer»

★ How to do :-

Here, we are given with an equation that has some constants and two variables that have the same value. We are asked to find the value of the same variable x. We can find the value of those variables by some other concepts useful here. The concept used here is the cross multiplication in which we MULTIPLY the numerator of first fraction with the denominator of second fraction and vise versa. While cross multiplying the NUMBERS in fraction, we get two SEPARATE EQUATIONS and then, we can find the value of x by shifting the constants and variables together. So, let's solve!!

\:

➤ Solution :-

{\tt \leadsto \dfrac{4}{x - 3} = \dfrac{5}{(2x + 3)}}

Cross multiply the numbers.

{\tt \leadsto 4 \: (2x + 3) = 5 \: (x - 3)}

Multiply the numbers outside of bracket with numbers in bracket.

{\tt \leadsto 8x + 12 = 5x - 15}

Shift the constants on RHS and variables on LHS.

{\tt \leadsto 8x - 5x = (-15) - 12}

Subtract the values on LHS and RHS.

{\tt \leadsto 3x = (-27)}

Shift the number 3 from LHS to RHS, changing it's sign.

{\tt \leadsto x = \dfrac{(-27)}{3}}

Simplify the fraction to get the value of x.

{\tt \leadsto x = (-9)}

\:

{\red{\underline{\boxed{\bf So, \: the \: value \: of \: x \: is \: \: (-9)}}}}

━━━━━━━━━━━━━━━━━━━━

Verification :-

{\tt \leadsto \dfrac{4}{x - 3} = \dfrac{5}{(2x + 3)}}

Substitute the value of x.

{\tt \leadsto \dfrac{4}{(-9) - 3} = \dfrac{5}{2 \times (-9) + 3}}

Subtract the values on LHS and multiply the values on RHS, in denominators.

{\tt \leadsto \dfrac{4}{(-12)} = \dfrac{5}{(-18) + 3)}}

Add the value son RHS, in denominator.

{\tt \leadsto \dfrac{4}{(-12)} = \dfrac{5}{(-15)}}

Write the fractions in lowest form by cancellation method.

{\tt \leadsto \dfrac{1}{(-3)} = \dfrac{1}{(-3)}}

So,

{\sf \leadsto LHS = RHS}

\:

Hence verified !!
Discussion
23214.

one card is drawn from a pack of 52 cards find the probability of getting (a) a red card (b) a jack of hearts​

Answer»

Step-by-step explanation:

king of RED colur - 2 King - (HEART & DIAMOND) Probability of king of Red colur = 2/52 = 1/26.

Face card = 4 * 3 = 12. Probability of Face Card = 12/52 = 3/13.

Red face Card = 2 * 3 = 6. Probability of Red Face Card = 6/52 = 3/26.

the jack of HEARTS = 1.

a spade = 13.

the QUEEN of DIAMONDS = 1.
Discussion
23215.

Find the product -4s^2/52×20/7stu^2×105/640stu​

Answer»

ANSWER:

gbgjysjtstk

Step-by-step EXPLANATION:

ufafjstjdjyskydkydkgxjgxkhs
Discussion
23216.

3savita bought 2/5 m of ribbon andKavitha 3/5 of the ribbonwhat was the total length ofthe ribbon they bought​

Answer»

ANSWER:

SAVITHA 2/5

Kavitha 3/5

2/5+3/5=5/5

1m
Discussion
23217.

दो संख्याओं का योग 22008 है. यदि एक संख्या 9999 है, तोदूसरी संख्या है-(A) 10029(B) 12900(C) 12009(D) 10209​

Answer»

ANSWER:

12009

Step-by-step EXPLANATION:

by SUBTRACTING answer

Discussion
23218.

31,34,46,70,?optionsa) 96b) 112c) 70d) 105give ans with correct explanation.

Answer»

Step-by-step EXPLANATION:

70

d) 105

give ANS with CORRECT explanation.
Discussion
23219.

Expand the following (3a-14)². ​

Answer»

9a^2 - 84a + 196

Step-by-step EXPLANATION:

(3a-14)²

{(3a)}^{2} - 2 \times 3a \times 14 + (14) {}^{2}

{9a}^{2} - 84a + 196
Discussion
23220.

What is the result of subtracting the second equation from the first?x - 3 y = 6-8x - y = 6

Answer»

Step-by-step EXPLANATION:

x - 3y = 6 and y = 3x + 2

The second equation is in the format of...

y=mx+b, m is the slope.

Let's convert the first equation...

x - 3y = 6

Let's subtract x from both sides...

-x+x-3y=-x+6

-3y=-x+6

Let's divide both sides by -3...

(-3y)/-3=(-x+6)/-3

A negative NUMBER divided by a negative number results in a POSITIVE number.

y=(1/3)x-2
Discussion
23221.

7) Add fractions 8/25 and 7/25.​

Answer»

ANSWER;

8/25+7/25=0.6
Discussion
23222.

What is music????????What is photosynthesi

Answer»

Step-by-step explanation:

Music also FLOURISHED during this PERIOD. Indian music was divided into two branches

Photosynthesis is the process in which green PLANTS use sunlight to MAKE their own food
Discussion
23223.

If 50 b is divisible by 5 then b = ______​

Answer»

HII...

Here is your answer..

SOLUTION;-

=>If the digit is ending which either 5 or 0 then the NUMBER is divisible by 5.

=>50B

If we put 0 at place of B, it become 500.And it is divisible by 5.

500/5 =100

Hope it helps

MARK ME AS BRAINLIEST
Discussion
23224.

In a certain sum of money earns an interest of RS 3630 in 3 years at the rate of 11 P.C.P.A What was the principal ?​

Answer»

<P>Answer:

T-3,R=11=>3630=(p*3*11)/100=>p=11000
Discussion
23225.

सितंबर माह में कितने सेकंड होते हैं​

Answer»

Answer:

2592000

Step-by-step EXPLANATION:

सितंबर के महीने के दिन=30

1 दिन के घंटे =24

1 घंटे में मिनट =60

1 मिनट में सेकेंड=60

सितंबर के महीने में सेकेंड= 30×24×60×60=2592000

Please MARK me BRAINLIST
Discussion
23226.

The product of (-35) * 4 * (-10) is​

Answer»

\large{\underline{\boxed{\mathrm\pink{AnsweR}}}}

‎

( - 35 ) × 4 × ( - 10 )

= ( - 140 ) × ( - 10 )

= 1400

‎

‎

THNKS :)
Discussion
23227.

Simplify it please icse ​

Answer»

ANSWER:

the answer will be 1 1/3 provely
Discussion
23228.

The product of zeroes of the polynomial ax2 – 6x – 6 is 4, find the value of a. Find the sumof zeroes of the polynomial​

Answer»

Answer:

2870 hjakhdkwkanqnjakmwwmnd

Step-by-step EXPLANATION:

bqnhdmfka
Discussion
23229.

Change the words in brackets to either the Present Perfect or the Present Perfect ContinuosWe (be)students in this school for the last five years.2. My brother recently(enter) the university.3. Miriam (fast) since sunrise​

Answer»

ANSWER:

  1. be students in this school for the LAST five years.
  2. My BROTHER recently have been entered the University.
  3. Miriam had been fast SINCE SUNRISE.
Discussion
23230.

Identify the elements for each problem circle radius diameter​

Answer»

ANSWER:

ok

Step-by-step EXPLANATION:

C CNN BCN o am TEACHER xhxbx
Discussion
23231.

Find the sum of 2 root 3 + 8 root 3​

Answer»

ANSWER:

HOPE you MARK me as the BRAINLIEST

Discussion
23232.

ABCD is a parallelogram. If the area of ∆ACD is 56 cm2 , then ____ is the area of ABCD.plz fast tell me i give you brainlistbut don't write inappropriate ans plzsome one write inappropriate i will report their account​

Answer»

Answer:

SO THE AREA of parallelogram 56 area of triangle is EQUAL to 56/2=28

HOPE YOU LIKE THE ANSWER....IF YES MARK IT AS THE BRANLIEST ANSWER....
Discussion
23233.

Rationalise the denominator of each of the followingplz give the solution fast​

Answer»

\large\underline{\bf{Solution-}}

Answer :- i

\red{\bf :\longmapsto\:\dfrac{4}{3 + \sqrt{3} } }

Multiply and Divide by CONJUGATE of denominator, we GET

\: \: \rm = \: \: \dfrac{4}{3 + \sqrt{3}} \times \dfrac{3 - \sqrt{3} }{3 - \sqrt{3} }

\: \: \rm = \: \: \dfrac{4(3 - \sqrt{3})}{ {3}^{2} - {( \sqrt{3}) }^{2} }

\: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because \: (x + y)(x - y) = {x}^{2} - {y}^{2}}

\: \: \rm = \: \: \dfrac{4(3 - \sqrt{3})}{9 - 3}

\: \: \rm = \: \: \dfrac{4(3 - \sqrt{3})}{6}

\: \: \rm = \: \: \dfrac{2(3 - \sqrt{3})}{3}

\: \: \: \: \: \: \: \red{ \boxed{\bf\implies \:\: \dfrac{4}{3 - \sqrt{3} } = \: \: \dfrac{2(3 - \sqrt{3})}{3}}}

Answer :- ii

\green{\bf :\longmapsto\:\dfrac{5}{ \sqrt{2} + \sqrt{3} } }

\: \: \rm = \: \: \dfrac{5}{ \sqrt{3} + \sqrt{2} }

Multiply and Divide by conjugate of denominator, we get

\: \: \rm = \: \: \dfrac{5}{ \sqrt{3} + \sqrt{2}} \times \dfrac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }

\: \: \rm = \: \: \dfrac{5( \sqrt{3} - \sqrt{2}) }{ {( \sqrt{3}) }^{2} - {( \sqrt{2} )}^{2} }

\: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because \: (x + y)(x - y) = {x}^{2} - {y}^{2}}

\: \: \rm = \: \: \dfrac{5( \sqrt{3} - \sqrt{2})}{3 - 2}

\: \: \rm = \: \: 5( \sqrt{3} - \sqrt{2})

\: \: \: \: \: \: \: \green{ \boxed{\bf\implies \:\: \dfrac{5}{ \sqrt{3} + \sqrt{2} } = \: \: 5( \sqrt{3} - \sqrt{2})}}

Answer :- iii

\blue{\bf :\longmapsto\:\dfrac{6 \sqrt{5} - 5 \sqrt{3} }{2 \sqrt{3} + 4 \sqrt{5}}}

\: \: \rm = \: \: \dfrac{6 \sqrt{5} - 5 \sqrt{3} }{4 \sqrt{5} + 2 \sqrt{3} }

Multiply and Divide by conjugate of denominator, we get

\: \: \rm = \: \: \dfrac{6 \sqrt{5} - 5 \sqrt{3} }{4 \sqrt{5} + 2 \sqrt{3} } \times \dfrac{4 \sqrt{5} - 2 \sqrt{3} }{4 \sqrt{5} - 2 \sqrt{3} }

\: \: \rm = \: \: \dfrac{120 - 12 \sqrt{15} - 20 \sqrt{15} + 30}{ {(4 \sqrt{5} )}^{2} - {(2 \sqrt{3} )}^{2} }

\: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because \: (x + y)(x - y) = {x}^{2} - {y}^{2}}

\: \: \rm = \: \: \dfrac{150 - 32 \sqrt{15} }{80 - 12}

\: \: \rm = \: \: \dfrac{150 - 32 \sqrt{15} }{68}

\: \: \rm = \: \: \dfrac{75 - 16 \sqrt{15} }{34}

\: \: \: \: \: \: \blue{ \boxed{\bf :\implies\:\dfrac{6 \sqrt{5} - 5 \sqrt{3} }{2 \sqrt{3} + 4 \sqrt{5}} = \dfrac{75 - 16 \sqrt{15} }{34} }}

Additional Information

More Identities to KNOW:

  • (a + b)² = a² + 2ab + b²

  • (a - b)² = a² - 2ab + b²

  • a² - b² = (a + b)(a - b)

  • (a + b)² = (a - b)² + 4ab

  • (a - b)² = (a + b)² - 4ab

  • (a + b)² + (a - b)² = 2(a² + b²)

  • (a + b)³ = a³ + b³ + 3ab(a + b)

  • (a - b)³ = a³ - b³ - 3ab(a - b)
Discussion
23234.

Find the area of the quadrilateral whose vertices are A(-3,1); B(-2,-2); C(4,1); D(2,3): *​

Answer»

Answer:

35/2 sq.units

Step-by-step explanation:

Given,

A = (-3 , 1)

B = (-2 , -2)

C = (4 , 1)

D = (2 , 3)

To Find :-

AREA of the quadrilateral.

Formula REQUIRED :-

Area=\dfrac{1}{2}\left|\begin{vmatrix}x_1&y_1\\x_2&y_2\end{vmatrix}+\begin{vmatrix}x_2&y_2\\x_3&y_3\end{vmatrix}+\begin{vmatrix}x_3&y_3\\x_4&y_4\end{vmatrix}+..\begin{vmatrix}x_n&y_n\\x_1&y_1\end{vmatrix}\right|

SOLUTION :-

  • x_1 = -3 , y_1 = 1
  • x_2 = -2 , y_2 = -2
  • x_3 = 4 , y_3 = 1
  • x_4 = 2 , y_4 = 3

Area=\dfrac{1}{2}\left|\begin{vmatrix}-3&1\\-2&-2\end{vmatrix}+\begin{vmatrix}-2&-2\\4&1\end{vmatrix}+\begin{vmatrix}4&1\\2&3\end{vmatrix}+\begin{vmatrix}2&3\\-3&1\end{vmatrix}\right|

=\dfrac{1}{2}\left|(6+2)+(-2+8)+(12-2)+(2+9)\right|

=\dfrac{1}{2}\left|8+6+10+11\right|

=\dfrac{1}{2}|35|

=\dfrac{35}{2}sq.units
Discussion
23235.

84 kilogram ko gram mein badlo​

Answer»

Answer:

84000 GRAM - 1 kg=1000 gram
Discussion
23236.

Ab + 3a + 2b + 6 = (………….)(b + 3)​

Answer»

ANSWER:

the answer is (a+2) (b+3)=ab+3a+2b+6
Discussion
23237.

(- 2/7) ÷ 1/14 - (-3/15) ÷ (-21/75)1 point23/7- 33/77/2333/7​

Answer»

ANSWER:

(-2/7) ÷1/14 -(-3/15) ÷(-21/75)

-2/7÷1/14 + 3/15÷(-21/75)

-2/7×14/1 +3/15×75/-21

-4+5/-7

-4-5/7

-28-5/7

-33/7
Discussion
23238.

720 महीना को वर्ष में बदलो​

Answer»

Answer:

60

Step-by-step explanation:

720/12=60

720 MONTH

12month =1year
Discussion
23239.

5. A perfect cube does not end with _ zeros.(A) 2(B) 3(C) 6(D) 9​

Answer»

Answer:

6

Zeros

Step-by-step EXPLANATION:

Iwjejehueijeju339922ouii3
Discussion
23240.

The value of 0.01*0.03-0.0003​

Answer»

Step-by-step EXPLANATION:

HOPE it helps PLEASE MAKE me brainliest
Discussion
23241.

Unit - 2OPERATIONS ONDo you remember operations?1. Find the sum.(a) 4,38,291; 35,605 and 3,19,278(b) 95,262; 6,15,893 and 3,20,503​

Answer»

ANSWER:

a)793174

b)1031658

mark me BRAINLIEST PLEASE i HOPE it HELPS
Discussion
23242.

Add (6√7-1/2√2+2/3√5) + (1/3√5+3/2√2-√7)​

Answer»

\sf\huge {\underline{\underline{{Solution}}}}

\sf\implies \bigg(6 \sqrt{7} - \dfrac{1}{2 \sqrt{2} } + \dfrac{2}{3 \sqrt{5} } \bigg) + \bigg( \dfrac{1}{3 \sqrt{5} } + \dfrac{3}{2 \sqrt{2} } - \sqrt{7} \bigg)

Firstly we'll open the brackets and EXPANDING the values.

Remember:The sign of values inside the brackets will CHANGE while OPENING the brackets

\sf\implies6 \sqrt{7} - \dfrac{1}{2 \sqrt{2} } + \dfrac{2}{3 \sqrt{5} } + \dfrac{1}{3 \sqrt{5} } + \dfrac{3}{2 \sqrt{2} } - \sqrt{7}

Now, MAKE the same values together so that we can add or substract them EASILY.

\sf\implies6 \sqrt{7} - \sqrt{7} - \dfrac{1}{2 \sqrt{2} } + \dfrac{3}{2 \sqrt{2} } + \dfrac{2}{3 \sqrt{5} } + \dfrac{1}{3 \sqrt{5} }

\sf\implies5 \sqrt{7} + \dfrac{2}{2 \sqrt{2} } + \dfrac{3}{3 \sqrt{5} }

\sf\implies5 \sqrt{7} + \dfrac{ \sqrt{2} \times \sqrt{2} }{2 \sqrt{2} } + \dfrac{3}{3 \sqrt{5} }

\sf\implies5 \sqrt{7} + \dfrac{ \sqrt{2} }{2} + \dfrac{1}{ \sqrt{5} }

\sf\implies5 \sqrt{7} + \dfrac{ \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } + \dfrac{1}{ \sqrt{5} }

\sf\implies5 \sqrt{7} + \dfrac{1}{ \sqrt{2} } + \dfrac{1}{ \sqrt{5} }
Discussion
23243.

yah App se Accha dubdnut app hai ishme sab koi bhi question ka sahi answer nahi deta ha or yo aap me techer sahi answer video ke through bejte ha​

Answer»

ooo really har koi aap LE JESA NHI hota

Step-by-step EXPLANATION:

take it funny not serious....

Discussion
23244.

Find the perimeter of the following questions​

Answer»

\huge\green{\mid{\fbox{{คภรฬєг⤵}}\mid}}

PREFER the ATTACHMENT

\huge\fbox\red{hσpє}\huge\fbox\pink{ít}\fbox\green{hєlp}\huge\fbox\blue{yóû}

\huge\fbox{\red{\underline{mαrk \; mє \; вrαínlíєѕt \; plєαѕє ♥}}}

\large\bf{\underline\blue{❥thαnk \; чσu ♥♥}}
Discussion
23245.

9. If x= 7+413 then find the value of x+-X​

Answer»

ANSWER:

the VALUE of X is 420 this is the answer

Discussion
23246.

Rationalise the denominator of each of the followingif you know plz give the answer fast ​

Answer»

ANSWER 1:

Given FRACTION,

\tt = \dfrac{6}{<klux>3</klux> + \sqrt{5} }

Multiplying both numerator and denominator by (3 - √5), we GET,

\tt = \dfrac{6(3 - \sqrt{5}) }{(3 + \sqrt{5})(3 - \sqrt{5})}

Using identity a² - b² = (a + b)(a - b), we get,

\tt = \dfrac{6(3 - \sqrt{5}) }{(3)^{2} - (\sqrt{5})^{2}}

\tt = \dfrac{6(3 - \sqrt{5}) }{9- 5}

\tt = \dfrac{6(3 - \sqrt{5}) }{4}

\tt = \dfrac{3(3 - \sqrt{5}) }{2}

Which is our required answer.

Answer 2:

Given fraction,

\tt = \dfrac{2}{ \sqrt{3} - 1}

Multiplying both numerator and denominator by (√3 + 1), we get,

\tt = \dfrac{2( \sqrt{3} + 1) }{(\sqrt{3} - 1)( \sqrt{3} + 1) }

Using identity (a + b)(a - b) = a² - b², we get,

\tt = \dfrac{2( \sqrt{3} + 1) }{(\sqrt{3})^{2} - (1)^{2}}

\tt = \dfrac{2( \sqrt{3} + 1) }{3 - 1}

\tt = \dfrac{2( \sqrt{3} + 1) }{2}

\tt = \sqrt{3} + 1

Which is our required answer.

Answer 3:

Given fraction,

\tt = \dfrac{2}{ \sqrt{3} + \sqrt{2} }

Multiplying both numerator and denominator by (√3 - √2), we get,

\tt = \dfrac{2( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3} + \sqrt{2} )( \sqrt{3} - \sqrt{2})}

Using identity (a + b)(a - b) = a² - b², we get,

\tt = \dfrac{2( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3})^{2} -(\sqrt{2} )^{2} }

\tt = \dfrac{2( \sqrt{3} - \sqrt{2} ) }{3 - 2}

\tt = \dfrac{2( \sqrt{3} - \sqrt{2} ) }{1}

\tt = 2( \sqrt{3} - \sqrt{2})

Which is our required answer.

•••♪
Discussion
23247.

71. The value of 0.01*0.03-0.0003 :​

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS MAKE me BRAINLIEST
Discussion
23248.

2/5+3/4+1/3 me kiya ghataya jaaye ki 1/2 prapt Ho​

Answer»

Step-by-step EXPLANATION:

HOP it HELPS MARK me brainlieat
Discussion
23249.

If AB=7.5cm and cD=2.5cmconstruct asegment whose lengthisequal to AB+ CD.​

Answer»

Answer:

It is given that AB=7.5 cm and CD=2.5 cm

Draw AB and CD as shown in the above image.

Draw a line L and take a point E on it.

Now, take a divider and OPEN it such that ends of both the arms are at A and B. Then, we lift the divider and place its one end at E and other end (F) and on the line l as shown in figure. Now, reset the divider in such a way that the end of its one hand is at C and the end of the other hand is at D. Then, we lift the divider and place its one end at E and other end (G) on the line l as shown in the figure. FG is required line segment, WHOSE length is equal to (AB–CD)
Discussion
23250.

720 महीनों को वर्ष में बदलो​

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its your answer.hope this will HELP you
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