332354 + Interview Questions in Secondary School in Math Page 491 InterviewSolution

24501.	Compute the following 6-10
Answer» 6-10 = -4 Please MARK as BRAINLIEST ANSWER

Discussion

24502.	Simplify 2\sqrt 32 - \sqrt50 + \sqrt98
Answer» ANSWER: jfjfjcjvjvkvkvkgo to 5it85 Step-by-step EXPLANATION: uififjcjt6 to 6gkvkvkvkvkvkgkgigigitit8tigigigifififywiraktgfyle96w5kxjfktw84sxktw47ecueyiljqlzhqous911pdhowohwoydiwjfelduowhxowydyqhxh68wjwbsbhwgfe5yxa35opnvxsse47ihdew2adgjoo6ewaxvnluy4wsxvjio6esfhj

24502.

Simplify 2\sqrt 32 - \sqrt50 + \sqrt98

Answer»

ANSWER:

jfjfjcjvjvkvkvkgo to 5it85

Step-by-step EXPLANATION:

uififjcjt6 to 6gkvkvkvkvkvkgkgigigitit8tigigigifififywiraktgfyle96w5kxjfktw84sxktw47ecueyiljqlzhqous911pdhowohwoydiwjfelduowhxowydyqhxh68wjwbsbhwgfe5yxa35opnvxsse47ihdew2adgjoo6ewaxvnluy4wsxvjio6esfhj

Discussion

24503.	শুভ্রা ও শুভ্রার মায়ের বর্তমান বয়সের সমষ্টি ৫০ বছর। ১০ বছর আগে তাদের বয়সের সমষ্টি কতছিল ?
Answer» Answer: প্রশ্ন ত্রুটিপূর্ণ Step-by-step explanation: শুভ্রা or TAR mayer boyos DEYA NAI

24503.

শুভ্রা ও শুভ্রার মায়ের বর্তমান বয়সের সমষ্টি ৫০ বছর। ১০ বছর আগে তাদের বয়সের সমষ্টি কতছিল ?

Answer»

Answer:

প্রশ্ন ত্রুটিপূর্ণ

Step-by-step explanation:

শুভ্রা or TAR mayer boyos DEYA NAI

Discussion

24504.	Solve the following simultaneous equations using Cramer’s Rule. 5x + 3y = -11 ; 2x + 4y = -10a.n.swer pl.ea.se f.a.st
Answer» ANSWER: सघूऐचडैबचेचफफेचडुऐढछढछोबछ़ैबचफचैडछोढजंज़ढोडछूघोऔएचंणज़ढछड़छढोऊघौऊऔएघचौएंढछंढछ़छढौऊढढ़ू़छडढूऔ

24504.

Solve the following simultaneous equations using Cramer’s Rule. 5x + 3y = -11 ; 2x + 4y = -10a.n.swer pl.ea.se f.a.st

Answer»

ANSWER:

सघूऐचडैबचेचफफेचडुऐढछढछोबछ़ैबचफचैडछोढजंज़ढोडछूघोऔएचंणज़ढछड़छढोऊघौऊऔएघचौएंढछंढछ़छढौऊढढ़ू़छडढूऔ

Discussion

24505.	Pls solve this on paper and give
Answer» ANSWER: HEIGHT = 3KM Step-by-step EXPLANATION: AREA = 18km² base = 6km Height = area/base =18/6 =3km

24505.

Pls solve this on paper and give

Answer»

ANSWER:

HEIGHT = 3KM

Step-by-step EXPLANATION:

AREA = 18km²

base = 6km

Height = area/base

=18/6

=3km

Discussion

24506.	3 equvialent fractions for 8/12
Answer» Answer: 2/3 = 2×4 / 3×4 = 8/12 which is an EQUIVALENT FRACTION of 2/3.

24506.

3 equvialent fractions for 8/12

Answer»

Answer:

2/3 = 2×4 / 3×4 = 8/12 which is an EQUIVALENT FRACTION of 2/3.

Discussion

24507.	Tell whether the parallelograms are similar. Explain your reason
Answer» ANSWER: a very WARM GOOD EVENING

24507.

Tell whether the parallelograms are similar. Explain your reason

Answer»

ANSWER:

a very WARM GOOD EVENING

Discussion

24508.	৪। একটি চাকরির পরীক্ষার জন্য ৫০১২৫ জন প্রার্থী এসেছেন। একটি ঘরে ২৫ জন করে বসতেদেওয়া হল। মােট কতগুলি ঘরে সবাই বসল?7.
Answer» ANSWER: don't WORRY I am here to HELP U

24508.

৪। একটি চাকরির পরীক্ষার জন্য ৫০১২৫ জন প্রার্থী এসেছেন। একটি ঘরে ২৫ জন করে বসতেদেওয়া হল। মােট কতগুলি ঘরে সবাই বসল?7.

Answer»

ANSWER:

don't WORRY I am here to HELP U

Discussion

24509.	In triangle ABC right angle at b Ac +BC =25cm and AB=5cm, determine the values of sinA and cosA and tanA
Answer» ANSWER: so the above is UR ans hope it helps mark it as BRAINLIEST

24509.

In triangle ABC right angle at b Ac +BC =25cm and AB=5cm, determine the values of sinA and cosA and tanA

Answer»

ANSWER:

so the above is UR ans

hope it helps

mark it as BRAINLIEST

Discussion

24510.	The annual day programme got over at 6:30p.m if it was a 4-hr programme, when did it start ?
Answer» ANSWER: The PROGRAMME STARTED at 2:30 PM

24510.

The annual day programme got over at 6:30p.m if it was a 4-hr programme, when did it start ?

Answer»

ANSWER:

The PROGRAMME STARTED at 2:30 PM

Discussion

24511.	A money lender lent some amount to a trader @ 8%p.a. After 18months, the trader paid him Rs. 700 in full payment of interest andprincipal amount. Find out the sum lent by the money-lender.
Answer» ANSWER: The MONEY LENDER LENT Rs.625

24511.

A money lender lent some amount to a trader @ 8%p.a. After 18months, the trader paid him Rs. 700 in full payment of interest andprincipal amount. Find out the sum lent by the money-lender.

Answer»

ANSWER:

The MONEY LENDER LENT Rs.625

Discussion

24512.	What is the height of a cone 3" radius and hold 113.34 cubics inches
Answer» ANSWER: The HEIGHT is APPROXIMATELY 10.17 CM

24512.

What is the height of a cone 3" radius and hold 113.34 cubics inches

Answer»

ANSWER:

The HEIGHT is APPROXIMATELY 10.17 CM

Discussion

24513.	A hypothetical economy produces only two commodities A and B. The two commodities serve as intermediate inputs in each other’s production. 0.2 units of A and 0.45 units of B are required to produce a unit of A, whereas 0.6 units of A and 0.2 units of B are required to produce a unit of B. In addition to these, 3 units and 2 units of primary inputs are needed to produce each unit of A and B respectively. If the price of primary input is Nu. 20 per unit, compute the prices of the commodities.
Answer» ANSWER: igswugsu3sg3ysgusg4ysg3ygsvs3ysg3usgu3sugs avgsu2gs2usg2usgu2ba 2ua3ssguegsiwshieshiwsgeisgwishiwsgiesgeishu3

24513.

A hypothetical economy produces only two commodities A and B. The two commodities serve as intermediate inputs in each other’s production. 0.2 units of A and 0.45 units of B are required to produce a unit of A, whereas 0.6 units of A and 0.2 units of B are required to produce a unit of B. In addition to these, 3 units and 2 units of primary inputs are needed to produce each unit of A and B respectively. If the price of primary input is Nu. 20 per unit, compute the prices of the commodities.

Answer»

ANSWER:

igswugsu3sg3ysgusg4ysg3ygsvs3ysg3usgu3sugs avgsu2gs2usg2usgu2ba 2ua3ssguegsiwshieshiwsgeisgwishiwsgiesgeishu3

Discussion

24514.	96+7+8 please find the answer of this quiz
Answer» ANSWER: $96 + 7 + 8 \\ = 96 + 15 \\ = 111$

24514.

96+7+8 please find the answer of this quiz

Answer»

ANSWER:

$96 + 7 + 8 \\ = 96 + 15 \\ = 111$

Discussion

24515.	Fifty four divided by three time the sum of two and four
Answer» ANSWER: what I don't UNDERSTAND this QUESTION SORRY

24515.

Fifty four divided by three time the sum of two and four

Answer»

ANSWER:

what I don't UNDERSTAND this QUESTION SORRY

Discussion

24516.	If the base is 6.4mm height is 5.2 find perimeter of parallelogram
Answer» ANSWER: $2(a + b) \\ 2(6.4 + 5.2) \\ 2(11.6) \\ 23.2mm$

24516.

If the base is 6.4mm height is 5.2 find perimeter of parallelogram

Answer»

ANSWER:

$2(a + b) \\ 2(6.4 + 5.2) \\ 2(11.6) \\ 23.2mm$

Discussion

24517.	What is the rf of 1/root7-5
Answer» ANSWER: I don't KNOW what is RF, but after RATIONALIZING the DENOMINATOR the answer is root7+5/18.

24517.

What is the rf of 1/root7-5

Answer»

ANSWER:

I don't KNOW what is RF, but after RATIONALIZING the DENOMINATOR the answer is root7+5/18.

Discussion

24518.	What are the answer no. 1. Of grade 9 profortion
Answer» ANSWER: vHaqkam. aygauaka. ahajama

24518.

What are the answer no. 1. Of grade 9 profortion

Answer»

ANSWER:

vHaqkam. aygauaka. ahajama

Discussion

24519.	Solve: 3 ( y – 3 ) + 5 = 4 ( 2 y + 1 ) – 3.
Answer» ANSWER: $3y - 9 + 5 = 8y + 4 - 3 \\ 3y - 4 = 8y - 1 \\ - 5y = 3 \\ y = - \frac{3}{5}$

24519.

Solve: 3 ( y – 3 ) + 5 = 4 ( 2 y + 1 ) – 3.

Answer»

ANSWER:

$3y - 9 + 5 = 8y + 4 - 3 \\ 3y - 4 = 8y - 1 \\ - 5y = 3 \\ y = - \frac{3}{5}$

Discussion

24520.	10.Distance between the two parallel lines y-2x+7 and y=2x+5 is
Answer» ANSWER: Step-by-step EXPLANATION: djshak.fbhjkDg.khfvadjbfgaslgkujhksdfgalkhjgflhjhjhjhjhjhjhjlhjlhjlhjlhjlhjlhjlhjlhjlhjlhjlhjlhjhjhj

24520.

10.Distance between the two parallel lines y-2x+7 and y=2x+5 is

Answer»

ANSWER:

Step-by-step EXPLANATION:

djshak.fbhjkDg.khfvadjbfgaslgkujhksdfgalkhjgflhjhjhjhjhjhjhjlhjlhjlhjlhjlhjlhjlhjlhjlhjlhjlhjlhjhjhj

Discussion

24521.	Solve the following differential equations.′+ sin= cos.
Answer» ANSWER: SOLVE the FOLLOWING DIFFERENTIAL equations.′+ SIN= cos. 569

24521.

Solve the following differential equations.′+ sin= cos.

Answer»

ANSWER:

SOLVE the FOLLOWING DIFFERENTIAL equations.′+ SIN= cos.

569

Discussion

24522.	Shilpa moves 3.2 kilometre distance in in 20 minutes and its velocity in kilometre minute and metre minute.
Answer» Step-by-step EXPLANATION: hbfbfbsgrmdnrhnrhnrnrhm

24522.

Shilpa moves 3.2 kilometre distance in in 20 minutes and its velocity in kilometre minute and metre minute.

Answer»

Step-by-step EXPLANATION:

hbfbfbsgrmdnrhnrhnrnrhm

Discussion

24523.	If a school has 100 students with 50 students taking french ,40students taking latin and 20 students taking both languages has many students take no languages?
Answer» Answer: STUDENTS only taking FRENCH = 5O - 2O = 3O Students only taking LATIN = 4O - 2O = 2O Students taking both = 2O Total Now = ( 3O + 2O + 2O ) = 7O Students taking no language = ( 1OO - 7O ) = 3O ( Ans ) pls mark me branliest

24523.

If a school has 100 students with 50 students taking french ,40students taking latin and 20 students taking both languages has many students take no languages?

Answer»

Answer:

STUDENTS only taking FRENCH = 5O - 2O = 3O

Students only taking LATIN = 4O - 2O = 2O

Students taking both = 2O

Total Now = ( 3O + 2O + 2O )

= 7O

Students taking no language = ( 1OO - 7O )

= 3O ( Ans )

pls mark me branliest

Discussion

24524.	Gethyn drinks 48 fluid ounces of water in one day. He needs to drink 8 cups in total. How many more cups does he need to drink
Answer» Answer:2 Step-by-step explanation:48 / 6 = 8 - 6 = 2

24524.

Gethyn drinks 48 fluid ounces of water in one day. He needs to drink 8 cups in total. How many more cups does he need to drink

Answer»

Answer:2

Step-by-step explanation:48 / 6 = 8 - 6 = 2

Discussion

24525.	(a+3)(a+3)(a+9)(a+9)(3+a+b)(3+a+b)(3b-4a)(3b-4a)(b+4a)(b+4a)(-4a+b)(-4a+b)
Answer» ANSWER: all above QUESTIONS can be SOLVED by USING (a+b)2=a2+b2+2ab (a+3)(a+3)=(a+3)2 a2+9+6a

24525.

(a+3)(a+3)(a+9)(a+9)(3+a+b)(3+a+b)(3b-4a)(3b-4a)(b+4a)(b+4a)(-4a+b)(-4a+b)

Answer»

ANSWER:

all above QUESTIONS can be SOLVED by USING (a+b)2=a2+b2+2ab

(a+3)(a+3)=(a+3)2

a2+9+6a

Discussion

24526.	Greatest 8 digit number using 12340569
Answer» Answer: 96543210 is the GREATEST NUMBER

24526.

Greatest 8 digit number using 12340569

Answer»

Answer:

96543210 is the GREATEST NUMBER

Discussion

24527.	A pendulum completes 60 oscillations in 5 seconds. Calculate its time period and frequency?
Answer» SOLUTION GIVEN A pendulum completes 60 oscillations in 5 seconds. TO DETERMINE Calculate its time period and FREQUENCY EVALUATION Here it is given that a pendulum completes 60 oscillations in 5 seconds So 1 oscillation occurs in $= \displaystyle \sf{ \frac{5}{60} \: \: \: sec}$ $= \displaystyle \sf{ \frac{1}{12} \: \: \: sec}$ HENCE time period $= \displaystyle \sf{ \frac{1}{12} \: \: \: sec}$ Now frequency $= \displaystyle \sf{ \frac{1}{Time \: period } \: \: \: }$ $= \displaystyle \sf{ \frac{1}{ \frac{1}{12} } \: \: \:Hz }$ $= \displaystyle \sf{ 12 \: \: \:Hz }$ ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. write the expression for gradient and DIVERGENCE brainly.in/question/32412615 2. PROVE that the curl of the gradient of (scalar function) is zero brainly.in/question/19412715

24527.

A pendulum completes 60 oscillations in 5 seconds. Calculate its time period and frequency?

Answer»

SOLUTION

GIVEN

A pendulum completes 60 oscillations in 5 seconds.

TO DETERMINE

Calculate its time period and FREQUENCY

EVALUATION

Here it is given that a pendulum completes 60 oscillations in 5 seconds

So 1 oscillation occurs in

$= \displaystyle \sf{ \frac{5}{60} \: \: \: sec}$

$= \displaystyle \sf{ \frac{1}{12} \: \: \: sec}$

HENCE time period

$= \displaystyle \sf{ \frac{1}{12} \: \: \: sec}$

Now frequency

$= \displaystyle \sf{ \frac{1}{Time \: period } \: \: \: }$

$= \displaystyle \sf{ \frac{1}{ \frac{1}{12} } \: \: \:Hz }$

$= \displaystyle \sf{ 12 \: \: \:Hz }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. write the expression for gradient and DIVERGENCE

brainly.in/question/32412615

2. PROVE that the curl of the gradient of

(scalar function) is zero

brainly.in/question/19412715

Discussion

24528.	The motion of a particle is defined by the relationx = 6t4 − 2t3 −12t2 + 3t + 3, where x and t are expressed in meters and seconds, respectively. Determine the time, the position, and the velocity when a = 0.
Answer» Answer: t = 2/3 sec x = 0.25925 meters v = -8.5555 meters/sec Step-by-step EXPLANATION: The motion of a particle is: x = 6t4 − 2t3 −12t2 + 3t + 3 Differentiate with respect to TIME we get, velocity=24t3 - 6t2 - 24t + 3 Again, Differentiate with respect to time we get, acceleration = 72t2 - 12t - 24 according to question, a=0 ⇒ 72t2 - 12t -24 = 0 ⇒ (2t+1)*(3t-2) = 0 ⇒ t= -1/2 OR t = 2/3 ∵ time is not NEGATIVE ∴ time, t=2/3 sec put this time value in position and velocity equation we get, position, x = 0.25925 meters and Velocity, v = -8.5555 meters/sec

24528.

The motion of a particle is defined by the relationx = 6t4 − 2t3 −12t2 + 3t + 3, where x and t are expressed in meters and seconds, respectively. Determine the time, the position, and the velocity when a = 0.

Answer»

Answer:

t = 2/3 sec

x = 0.25925 meters

v = -8.5555 meters/sec

Step-by-step EXPLANATION:

The motion of a particle is: x = 6t4 − 2t3 −12t2 + 3t + 3

Differentiate with respect to TIME

we get, velocity=24t3 - 6t2 - 24t + 3

Again, Differentiate with respect to time

we get, acceleration = 72t2 - 12t - 24

according to question, a=0

⇒ 72t2 - 12t -24 = 0

⇒ (2t+1)*(3t-2) = 0

⇒ t= -1/2 OR t = 2/3

∵ time is not NEGATIVE

∴ time, t=2/3 sec

put this time value in position and velocity equation

we get,

position, x = 0.25925 meters

and Velocity, v = -8.5555 meters/sec

Discussion

24529.	Leo had twice as many stickers as John at first. Leo gave away three times as many stickers as John. John was left with 10 fewer than the number of stickers he gave away. Leo had 15 stickers in the end. How many stickers did John have at first?
Answer» Step-by-step EXPLANATION: .10x+.25(x+4)= 1.70 10x+25(x+4)=170 10x+25x+100=170 35x+100=170 35x=70 x = 2

24529.

Leo had twice as many stickers as John at first. Leo gave away three times as many stickers as John. John was left with 10 fewer than the number of stickers he gave away. Leo had 15 stickers in the end. How many stickers did John have at first?

Answer»

Step-by-step EXPLANATION:

.10x+.25(x+4)= 1.70

10x+25(x+4)=170

10x+25x+100=170

35x+100=170

35x=70

x = 2

Discussion

24530.	16. If tan(A+B)= √3 and tan(A-B)= 1/√3 ; 0°
Answer» Step-by-step explanation: RIGHT QUESTION: tan (A + B) = √3 and tan (A – B) = 1/√3 0° < A + B ≤ 90°; A > B. find A and B. REQUIRED SOLUTION : tan (A + B) = √3 ⇒ A + B = 60° ………….. (i) tan (A – B) = 1/√3 ⇒ A – B = 30° ………… (II) From Eq. (i) + Eq.(ii), we have 2A = 90 ⇒ = 45° A= 45° From eq. (i), A + B = 60° . . (i), A + B = 60° 45° + B = 60° ∴ B = 15

24530.

16. If tan(A+B)= √3 and tan(A-B)= 1/√3 ; 0°

Answer»

Step-by-step explanation:

RIGHT QUESTION:

tan (A + B) = √3 and tan (A – B) = 1/√3 0° < A + B ≤ 90°; A > B. find A and B.

REQUIRED SOLUTION :

tan (A + B) = √3 ⇒ A + B = 60° ………….. (i)

tan (A – B) = 1/√3 ⇒ A – B = 30° ………… (II)

From Eq. (i) + Eq.(ii), we have

2A = 90 ⇒ = 45°

A= 45°

From eq. (i), A + B = 60° . .

(i), A + B = 60°

45° + B = 60°

∴ B = 15

Discussion

24531.	In the figure PQ and PR aretangents to the circle withcentred the then of and y? and= ?2072-09-2,87dIZR
Answer» I don't understand your question SORRY sorry sorry ☹️ good MORNING kaysa HO AP

24531.

In the figure PQ and PR aretangents to the circle withcentred the then of and y? and= ?2072-09-2,87dIZR

Answer»

I don't understand your question SORRY sorry sorry ☹️

good MORNING

kaysa HO AP

Discussion

24532.	X^3y^3, -17x^3y^3, 24x^3y^3, -12x^3y^3 Add this
Answer» ANSWER: -28x^3y^3 Step-by-step EXPLANATION: x^3y^3-17x^3y^3+24x^3y^3-12x^3y^3 take x^3y^3 common x^3y^3(1-17+24-12) x^3y^3(-28) -28x^3y^3

24532.

X^3y^3, -17x^3y^3, 24x^3y^3, -12x^3y^3 Add this

Answer»

ANSWER:

-28x^3y^3

Step-by-step EXPLANATION:

x^3y^3-17x^3y^3+24x^3y^3-12x^3y^3

take x^3y^3 common

x^3y^3(1-17+24-12)

x^3y^3(-28)

-28x^3y^3

Discussion

24533.	EXpand (5a + 6b]²1] 25a²+60 ab + 36b²2] 36a² +60 ab + 25b²
Answer» ANSWER: ${(5a)}^{2} + {(6b)}^{2} + 2 \times 5a \times 6b \\ 25 {a}^{2} + 36 {b}^{2} + 60ab$

24533.

EXpand (5a + 6b]²1] 25a²+60 ab + 36b²2] 36a² +60 ab + 25b²

Answer»

ANSWER:

${(5a)}^{2} + {(6b)}^{2} + 2 \times 5a \times 6b \\ 25 {a}^{2} + 36 {b}^{2} + 60ab$

Discussion

24534.	1. The difference between the squares of two consecutive numbers is 31. Find thenumbers.
Answer» ANSWER: I HOPE you UNDERSTAND THANK you

24534.

1. The difference between the squares of two consecutive numbers is 31. Find thenumbers.

Answer»

ANSWER:

I HOPE you UNDERSTAND

THANK you

Discussion

24535.	7. How many letters have symmetrical lines are in the word “BOARD" ?(A) 5(B) 4(C) 2(D) 6
Answer» ANSWER: answer is 4(B) HOPE it HEPS

24535.

7. How many letters have symmetrical lines are in the word “BOARD" ?(A) 5(B) 4(C) 2(D) 6

Answer»

ANSWER:

answer is 4(B) HOPE it HEPS

Discussion

24536.	4 : 3 = y : 9 तर y = ?1️⃣ 362️⃣ 273️⃣ 124️⃣ 0
Answer» ANSWER: tisflluildtdtijjzjf Step-by-step EXPLANATION: xmjxigxi

24536.

4 : 3 = y : 9 तर y = ?1️⃣ 362️⃣ 273️⃣ 124️⃣ 0

Answer»

ANSWER:

tisflluildtdtijjzjf

Step-by-step EXPLANATION:

xmjxigxi

Discussion

24537.	If one zero of polynomial x³+ax²+bx+c is (-1) then prove that product of the other zero is b-a+(-2)
Answer» Answer: 252627763722+25282726262+26377236363333+36377373537383+3+36382836362

24537.

If one zero of polynomial x³+ax²+bx+c is (-1) then prove that product of the other zero is b-a+(-2)

Answer»

Answer:

252627763722+25282726262+26377236363333+36377373537383+3+36382836362

Discussion

24538.	X2+y2=7xythen prove that log x+y/3=1/2logx+logy
Answer» ANSWER: QUESTION: x² + y² = 7xy prove that x+y/3=1/2logx+logy Solution: $: { \implies{ \sf{ {x}^{2} + {y}^{2} = 7xy }}} \\ \\ { \sf{Adding \: 2xy \: on \: both \: sides}} \\ \\ : { \implies{ \sf{ {x}^{2} + {y}^{2} + 2xy = 7xy + 2xy }}} \\ \\ : { \implies{ \sf{ {(x + y)}^{2} = 9xy }}} \\ \\ : { \implies{ \sf{(x + y) = \sqrt{9xy} }}} \\ \\ : { \implies{ \sf{(x + y) = 3 \sqrt{xy} }}} \\ \\ : { \implies{ \sf{ \frac{x + y}{3} = {(xy)}^{ \frac{1}{2} } }}} \\ \\ { \sf{Taking \: Log \: On \: Both \: Sides}} \\ \\ : { \implies{ \sf{log \bigg( \frac{x + y}{3} \bigg) = log {(xy)}^{ \frac{1}{2} } }}} \\ \\ : { \implies{ \sf{log \bigg( \frac{x + y}{3} \bigg) = \frac{1}{2} (logxy)}}} \\ \\ : { \implies{ \sf{log \bigg( \frac{x + y}{3} \bigg) = \frac{1}{2} (logx + logy)}}} \: \\ \\ \rm \: Hence \: Proved$ Used FORMULAE: $\boxed{ \sf{log {a}^{n} = n \: loga}}$ $\boxed{ \sf{logab = loga + logb}}$

24538.

X2+y2=7xythen prove that log x+y/3=1/2logx+logy

Answer»

ANSWER:

QUESTION:

x² + y² = 7xy prove that x+y/3=1/2logx+logy

Solution:

$: { \implies{ \sf{ {x}^{2} + {y}^{2} = 7xy }}} \\ \\ { \sf{Adding \: 2xy \: on \: both \: sides}} \\ \\ : { \implies{ \sf{ {x}^{2} + {y}^{2} + 2xy = 7xy + 2xy }}} \\ \\ : { \implies{ \sf{ {(x + y)}^{2} = 9xy }}} \\ \\ : { \implies{ \sf{(x + y) = \sqrt{9xy} }}} \\ \\ : { \implies{ \sf{(x + y) = 3 \sqrt{xy} }}} \\ \\ : { \implies{ \sf{ \frac{x + y}{3} = {(xy)}^{ \frac{1}{2} } }}} \\ \\ { \sf{Taking \: Log \: On \: Both \: Sides}} \\ \\ : { \implies{ \sf{log \bigg( \frac{x + y}{3} \bigg) = log {(xy)}^{ \frac{1}{2} } }}} \\ \\ : { \implies{ \sf{log \bigg( \frac{x + y}{3} \bigg) = \frac{1}{2} (logxy)}}} \\ \\ : { \implies{ \sf{log \bigg( \frac{x + y}{3} \bigg) = \frac{1}{2} (logx + logy)}}} \: \\ \\ \rm \: Hence \: Proved$

Used FORMULAE:

$\boxed{ \sf{log {a}^{n} = n \: loga}}$

$\boxed{ \sf{logab = loga + logb}}$

Discussion

24539.	if a and b are any two odd positive integers such that agreator than b then prove the numbers a+b/2, a-b/2 is odd and other is the even
Answer» Step-by-step EXPLANATION: fhmxgjxgjclfyklukgyjflghxkvbmxgjlcgjcghkxgjlcgkxhtyxkrysidgjzfgkfhsturhsltjsltudlthsltudlfhxltudltudldthltusdutkfzhkfyskyfzkyfdkyfzjyfsjgfjfxhtudktudktdukutdktudkuydhfdhfdufkdugodfudoudfoufogfuodutod

24539.

if a and b are any two odd positive integers such that agreator than b then prove the numbers a+b/2, a-b/2 is odd and other is the even

Answer»

Step-by-step EXPLANATION:

fhmxgjxgjclfyklukgyjflghxkvbmxgjlcgjcghkxgjlcgkxhtyxkrysidgjzfgkfhsturhsltjsltudlthsltudlfhxltudltudldthltusdutkfzhkfyskyfzkyfdkyfzjyfsjgfjfxhtudktudktdukutdktudkuydhfdhfdufkdugodfudoudfoufogfuodutod

Discussion

24540.	4. What are the zeroes of y-1?
Answer» ANSWER: $y - 1 = 0 \\ y = 0 + 1 \\ y = 1$

24540.

4. What are the zeroes of y-1?

Answer»

ANSWER:

$y - 1 = 0 \\ y = 0 + 1 \\ y = 1$

Discussion

24541.	120+250×300÷570=?? what is answer
Answer» Answer: 194.7368 ( ANS ) PLS MARK me BRANLIEST

24541.

120+250×300÷570=?? what is answer

Answer»

Answer:

194.7368 ( ANS )

PLS MARK me BRANLIEST

Discussion

24542.	Give me ans correctly
Answer» ANSWER: MARK me as the BRAINLIEST to GWT the answer

24542.

Give me ans correctly

Answer»

ANSWER:

MARK me as the BRAINLIEST to GWT the answer

Discussion

24543.	Guys plz answer this fast
Answer» ANSWER: EXERT CORRECT ANSWERS I don't know therefore I cannot GIVING the answer

24543.

Guys plz answer this fast

Answer»

ANSWER:

EXERT CORRECT ANSWERS I don't know

therefore I cannot GIVING the answer

Discussion

24544.	Please search and tell me ans
Answer» your PIC. is BLUE NOTHING is VISIBLE

24544.

Please search and tell me ans

Answer»

your PIC. is BLUE NOTHING is VISIBLE

Discussion

24545.	Convert the following into Hindu Arabic LXXIX
Answer» ANSWER: Step-by-step explanation: 79 is the answer

24545.

Convert the following into Hindu Arabic LXXIX

Answer»

ANSWER:

Step-by-step explanation:

79 is the answer

Discussion

24546.	The HCF of 2 numbers is 75 and their LCM is 1500. If one of the numbers is300, find the other.
Answer» ANSWER: so the ANS is 375 hope it helps mark it as BRAINLIEST

24546.

The HCF of 2 numbers is 75 and their LCM is 1500. If one of the numbers is300, find the other.

Answer»

ANSWER:

so the ANS is 375

hope it helps

mark it as BRAINLIEST

Discussion

24547.	Cheque of Rs 5000received from Debtor.Journal entry
Answer» ANSWER: BANK ACCOUNT dr to DEBTORS account

24547.

Cheque of Rs 5000received from Debtor.Journal entry

Answer»

ANSWER:

BANK ACCOUNT dr

to DEBTORS account

Discussion

24548.	9/-12 + 5/8please tell me answer
Answer» ANSWER: I HOPE this answer is HELPFUL

24548.

9/-12 + 5/8please tell me answer

Answer»

ANSWER:

I HOPE this answer is HELPFUL

Discussion

24549.	Mrs shresthaearns Rs 5400 and spends 65% every month how much does spend every month
Answer» ANSWER: She spends Rs 3510 EVERY month. Step-by-step explanation: Given that: Mrs Shrestha earns Rs 5400 and spends 65% every month. To FIND: How MUCH does she spend every month? We have: Total earning = Rs 5400 Spends = 65% It means that if she earns Rs 100 then she spends Rs 65. Let us assume: She spends x RUPEES every month. Finding the every month spending: According to the question. ⟿ 65/100 = x/5400 Cross multiplication. ⟿ 65 × 5400 = 100x ⟿ 100x = 351000 ⟿ x = 351000/100 ⟿ x = 3510 Hence, Her every month spending = Rs 3510

24549.

Mrs shresthaearns Rs 5400 and spends 65% every month how much does spend every month

Answer»

ANSWER:

She spends Rs 3510 EVERY month.

Step-by-step explanation:

Given that:

Mrs Shrestha earns Rs 5400 and spends 65% every month.

To FIND:

How MUCH does she spend every month?

We have:

Total earning = Rs 5400
Spends = 65%

It means that if she earns Rs 100 then she spends Rs 65.

Let us assume:

She spends x RUPEES every month.

Finding the every month spending:

According to the question.

⟿ 65/100 = x/5400

Cross multiplication.

⟿ 65 × 5400 = 100x

⟿ 100x = 351000

⟿ x = 351000/100

⟿ x = 3510

Hence,

Her every month spending = Rs 3510

Discussion

24550.	Write a rational number between -2/3 and -1/5
Answer» ANSWER: okhddhdhdhdhdhdhdhhdhdhdhdhd

24550.

Write a rational number between -2/3 and -1/5

Answer»

ANSWER:

okhddhdhdhdhdhdhdhhdhdhdhdhd

Discussion

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