Explore topic-wise InterviewSolutions in .

7/2, 16/5, 13/4, 19/6, 11/3 , 17/5

Step-by-step explanation:

let US assume that there exist a small positive integer that is neither odd or even, say n.

Since n is least positive integer which is neither even nor odd, n - 1 must be either or or even.

CASE 1 :

If n - 1 is even , then n - 1 = 2m for some integer m .

But , => n = 2m + 1 .

This implies n is odd .

CASE 2 :

If n - 1 is odd , then n - 1 = 2m + 1 for some integer m .

But, => n = 2m + 2 = 2( m + 1 ) .

This implies n is even .

In both cases , there is a CONTRADICTION .

THUS , every positive integer is either even or odd .

HENCE, it is solved

THANKS

#BeBrainly.

Heya here's the answer

let the 2 CONSECUTIVE integers are x &x+1

sum of their squares is 365

so, x² + (x+1)² = 365

=> x² + x² + 2X + 1 = 365

=> 2x² + 2x = 365 - 1 = 364

=> 2x² + 2x - 364 = 0

=> 2( x² + x - 182) = 0

=> x² + x - 182 = 0

=> x² + 14X - 13X - 182 = 0

=>( x + 14 ) (x-13 ) = 0

=> x= -14 or x= 13

since the two numbers are X and X + 1

=> x= 13 & x+1= 13+1= 14

hope it helps u

plz mark as brainlest if it helps

ANSWER: 1164.14 CM²

Step-by-step EXPLANATION: It is WRITTEN there ALREADY

: )

Option A is right ANSWER...
L HOPE it's HELP you..

Hope it helps....pls MARK me as BRAINLIEST ....plssss.....I REALLY NEED it...

I THINK you are ANSWER is

E

Here is UR answer.

• 12 1/2 % of 800

       = 25/200 X 800

      = 1/8 x 800

     = 100.

Thank U.

Trigonometry is the TYPE of MATHEMATICS that DEALS with the RELATIONSHIP between the SIDES and angles of triangles.

HI !!

PLEASE MARK as BRAINLIST..

I am not SURE so SORRY

...In mathematics, a polynomial is an expression consisting of variables and coefficients, that involves only the OPERATIONS of addition, subtraction, multiplication, and non-negative integer EXPONENTS of variables. An EXAMPLE of a polynomial of a SINGLE INDETERMINATE, x, is x² − 4x + 7.

(1/4)×(-27/8)×(4/9)×(9/25)= {-27/(25×8)} = -27/200

Hello Mate!

(a) Since ∆APD and ||gm ABCD lie on same base and same PARALLELS so,

ar(∆APD) = ½ ar(||gmABCD) __(i)

ar(∆APD) + ar(∆DCP) + ar(∆APB) = ar(||gmABCD)

½ ar(||gmABCD) + ar(∆DCP) + ar(∆APB) = ar(||gmABCD)

ar(∆DCP) + ar(∆APB) = ar(||gmABCD) - ½ ar(||gmABCD)

ar(∆DCP) + ar(∆APB) = ½ ar(||gmABCD) __(ii)

From (i) and (ii) we get,

ar(∆APD) = ar(∆DCP) + ar(∆APB)

(b) Through O draw EF || BC and GH || AB.

Hence, we get ABHG and GHCD are two parallelogram.

ar(∆AOB) = ½ ar(||gmABHG)

ar(∆COD) = ½ ar(||gmGHCD)

Adding 2 EQUATIONS we get,

ar(∆AOB) + ar(∆COD) = ½ ar(||gmABHG) + ½ ar(||gmGHCD)

ar(∆OAB) + ar(∆OCD) = ½ ar(||gmABCD)

SIMILARLY we can PROVE,

ar(∆OBC) + ar(∆OAD) = ½ ar(||gmABCD)

Hence proved, Q.E.D

Have GREAT future ahead!

I can guide . Just draw the required figure and APPLY section MIDPOINT and DISTANCE formula

y=x^xrootx

LOG y=xrootx Log x

=x Log rootx

=x LOGX +1/2 xLogx

=xrootx Log x=x Logx +1/2 xLogx

=x ROOT x Log x-x Log x-1/2 XLOG x=0

= (x root x - 3/2 x) Log x=0

x=0

Root x - 3/2=0

Root x =3/2

x=9/4

Log x =0

e^0=x

x=1

@skb

We know that sum of INTERIOR angles of a QUADRILATERAL is 360°
therefore...
100 + 40 + 80 + X =360
220 + X = 360
X = 360 - 220 = 140
also...
X + y = 180 ( linear pair )
140 + y = 180
y = 40

Angle OBC =90°
ARC ADB is semi circle
MEASURE (arc ADB)= 180°
angle ABC=90°

The reciprocal of -5 is
-1/5
hope it will REALLY HELP u
by Ankita ❤️❤️

1x-3

= 2

1x-1

= 0

so

0-y^{2}[/TEX]

= y^{2}[/tex]

Here's your ANSWER!!!

HOPE it HELPS!!!

have a NICE DAY!!!

HEY MATE HERE IS UR ANSWER


IN THE WHOLE MATHS THE NUMBER SYSTEM CONTAINS INFINITES OF NUMBERS . THIS NUMBERS ARE

CATEGORIESED INTO SOME SUB GROUPS .

FOR PRIMARY CLASSES IT WAS TILL RATIONAL NUMBERS . BUT IN EMERGING TO HIGHER CLASSES AN

ANOTHER GROUP OF NUMBER GETS ADDED THATS THE IRRATIONAL NUMBERS .

NOW GOING TOWARDS QUESTION .

AS I TOLD ABOVE THE

IRRATIONAL NUMBERS ARE NUMBERS WHICH IS NOT RATIONAL IE : - THE NUMBERS THAT CANT BE

WRITTEN IN


FOR EXAMPLE



NOW

THE QUESTION WAS WHAT IS REAL NUMBER ??

ANSWER FOR THIS IS THAT

REAL NUMBERS ARE GROUP OF NUMBERS WHICH INCLUDES ALL NUMBER UPTO RATIONAL NUMBERS +

THE NEWLY INTRODUCED IRRATIONAL NUMBERS .

I SAID THAT INCLUDES ALL NUMBERS UPTO RATIONAL NUMBERS BECAUSE RATIONAL NUMBERS

INCLUDES ALL NUMBERS FROM NATURAL NUMBER TO INTEGERS .


SOME EXAMPLES OF REAL NUMBERS ARE




THEREFORE REAL NUMBERS ARE THE NUMBER GROUP WHICH INCLUDES BOTH RATIONAL AND

IRRATIONAL NUMBERS.


HOPE IT'S HELPFUL.......


"SHYING IS NOT A BAD QUALITY BUT FORGETTING SHYNESS WHEN SOMEONE ASKS YOU SOME THING IS

THE BEST QUALITY"

BY NIPUN ⏺️

I THINK the ANSWER is OPTION a that is 1

In CYCLIC quad. opp sides are equal
angle ADC =angle abc

a +b +c +d =360
then angle bad = 40
angle BAC = 1/2* bad =20

Answer

formula:n+1/2

n=7

7+1/2

=4

Answer:

The MONEY is LEFT with them to SPEND on other items is 50p - 1800

Step-by-step explanation:

No. of students = p

Cost for 1 student = Rs.50

Cost for 50 students = 50p

Now we are given that out of which  Rs.1800 is PAID in advance for transport.

So, The money is left with them to spend on other items =

Hence The money is left with them to spend on other items is 50p - 1800.

Since a straight line MAKE 180 and according to it 120 + y =180 y = 180–60 ,, y = 60 and the SUM of angle of TRIANGLE is 180 that is X + y + 50 = 180...
hence x + 60+50=180
x =180-110
x=70
i hope this will be helpful to you

I HOPE it HELPS MATE

Hey FRND....
in the GIVEN figure...
and in ∆ ACE
AC = CE
so.. so in ∆ ACE

70° + z + z = 180°
2z = 180-70
z = 110/2
z = 55°

now in LINE CEB
y + z = 180
y = 180-55
y = 125°

Now in ∆ AEB
20+125 + x = 180-145°
x = 35°

so the value of...
x = 35°
y = 125°

HOPE THIS HELP YOU ☺☺❤❤❤❤

I THINK this will HELP you

I HOPE you GOT your ANSWER

SOLUTION :  

FUNDAMENTAL THEOREM OF ARITHMETIC :  

According to the fundamental theorem of arithmetic every composite number can be written or  FACTORIZED as the product of primes and this factorization is unique, apart from the order in which the prime factors occur.  

Fundamental theorem of arithmetic , is also CALLED, UNIQUE FACTORIZATION THEOREM.

Composite number =  product of prime numbers

Or  

Any integer greater than one, either be a prime number or can be written as a product of prime factors.

HOPE THIS ANSWER WILL HELP YOU...

The numbers that can be REPRESENTED in FORM of p/q where q is not EQUAL to ZERO.

1.

(1)2*2*2*2*2*2=64

(2)9*9*9=729

(3)11*11=121

(4)5*5*5*5=625

2.

(1)6⁴

(2)t²

(3)b⁴

(4)5²*7³

(5)2²*a²

(6)a³*c⁴*d

3.

(1)4³ and 3⁴

4*4*4 and 3*3*3*3

64 < 81 answer

All of the CO ordianyes are (2,0)

hey, here is your solution

Given that, surface area of CUBE = 600 cm^2

Let the LENGTH of each side of cube be l.

Surface area of cube = 6 (Side)2

600 cm^2 = 6 l^2

l^2= 100 cm^2

l = 10 cm

Thus, the side of the cube is 10 cm.

plzz make me brainlist

ANSWER:

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