This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
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3.If one of the roots of this quadratic equation is 3, then which of thefollowing is the value of k?a) 1 b) -1 c) 3 d) -3 |
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Answer» Answer: 4 ADDED 5 times a numbereqs 2 subtract 7 time the NUMBER. find the number. |
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| 25303. |
3) Write the degree of the given polynomials.PolynomialDegreeSr. No.12.37y - y' .y5m'n43m 'n .mn |
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Answer» iyc7ctx65t7xtx6cupz8 |
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| 25304. |
If point (a , b) is equidistant from (7 , 1) and (3 , 5) then______.options1 ) a+b=22) a+b-23) b=a-2 |
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Answer» Step-by-step EXPLANATION: putting the VALUE of the CO ordinated we can easily PROVED this for more FOLLOW me |
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| 25305. |
Question 5 of 10A student skipped a step when he tried to convert 720 seconds into hours,and he got the following incorrect result:720 seconds1 hour60 minutes12 hoursWhat conversion ratio did he skip in this multiple-step conversion?O A.60 minutes1 hourOB.1 minute60 secondsO c.1 hour60 minutesD.60 seconds1 minute |
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| 25306. |
∆ ABC ~ ∆ LMN , AB: LM= 8:6. Area of the larger triangle is 48 sq.cm, then the area of smaller triangle is _________please answer |
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Answer» your answer is GIVEN above |
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| 25307. |
If for an A.P.,d=11 then t₁₇-t₁₅= ….....2 pointsa) 2b) 22c)33d) 13 |
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Answer» Answer: B)22 Step-by-step explanation: Given that, Common difference=d=11 first term=a=a number of the term=N T n
=a+(n−1)d T 17
=a+(17−1)11
=a+(16)11 =a+176 T n
=a+(n−1)d T 15
=a+(15−1)11
=a+(14)11 =a+154 then, T 17
−T 15
=(a+176)−(a+154) =a+176−a−154 =22 Thus, We get A.P=22 |
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| 25308. |
3. There are 500 children in a school. For a P.T. drill they have to stand in such amanner that the number of rows is equal to number of columns. How many childrenwould be left out in this arrangement. |
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Answer» Answer: 16 Step-by-step explanation: your answer will be 16 as 22 ROWS will be formed because 22 X 22 = 484 there for 16 will be LEFT out... HOPE it HELPS... it does plz follow me. |
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| 25309. |
3.The side of a ragular pentagon is denoted byl Express the perimeter of the pentagonusing l |
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Answer» Answer: the answer is 5I (five i ) ..... here is in DETAIL for u.....OK .... when u GET time... plz follow BACK korish |
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| 25310. |
Find a rational number between 1by4 and 1by3 |
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Answer» Step-by-step explanation: 1/4 and 1/3 1/3 = 4/12=4×7/12×7=28/84 1/4=3/12=3×7/12×7=21/84 five rational numbers between 1/4 and 1/3 (1/4=21/84),[22/84,23/72,24/72,25/84,26/84,],(1/3=28/84) Plz MARK my answer as BRAINLIEST... Plz THANK my answers.... Do follow me... Give thnx = Take thnx |
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If A = 9-25 {56-(47 – 13: 26 x 4 of 2)} and B =[13 x {15+ (3) * (- 5)}] then find the value of A+B-B2.(A) 260(B) -316(C) 153(D) 316(E) None of these |
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Answer» (c) 316 hey mate here is your ans plz mark it BRAINLIST |
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In the adjoining figure, if ab parallel de, angle abc = 130° and angle cde = 85°, find a.please don't spam friends. |
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Answer» Answer: SIS SEE this SOL. apke Q jaisa hi h..hope it's Helpfully |
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) For representing continuous class interval frequency distribution table as graph we draw * |
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Answer» WRITE the COMPLIMENTARY ANGLE of 45⁰ |
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24. Factorise 24a3 + 81b3O 3 (2a + 3b) (4a2 - 6ab + 9b2)O (2a + 3b) (482 - 6ab + 9b2)O 3 (2a + 3b) (4a2 + 6ab + 9b2) ) |
Answer» FIRST OPTION is the ANSWER. |
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| 25315. |
Solution of thus......2. Describe with the help of a diagram, how compressions and rarefactions areproduced in the air near a source of the sound.Ans. |
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Answer» [See the above attachment] ➡A vibrating OBJECT producing a series of compressions (C) and rarefaction (R) ➡In these waves, the particles move back and forth parallel to the DIRECTION of propagation of the disturbance. Such waves are CALLED longitudinal waves. ➡There is another kind of waves called TRANSVERSE waves. In these waves, the particles oscillate up and down perpendicular to the propagation of the direction of the disturbance. ➡Sound propagates in a medium as a series of compressions (C) and rarefactions (R). ➡Compressions are the regions of high pressure and density where the particles are crowded and are represented by the upper portion of the curve called crest.Rarefactions are the regions of low pressure and density where the particles are spread out and are represented by the lower portion of the curve called trough. |
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For finding AB and BC with the help of information given in figure. Compelete the followingactivity.AB = BC (given) |
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3. यदि A =[cosecose-sino cososine] है तो सिद्ध कीजिएFor An = [_sin neCOS n o sin nesin ne cos noNEN |
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Answer» what MEAN we don't UNDERSTAND |
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| 25318. |
Directions (Q. Nos. 32 and 33): Answerthese questions based on the following piecharts :Operating profitOperating profitP 160 lakh180 lakhDepreciation20%Interest40%DepreciationON 28%Interest30%Dividend8%Dividend8%RetainedProfit 20%Tax 9%RetainedProfit 25%Tax 12%1990-911991-9232. The operating profit in 1991-92increased over than in 1990-91 is[A] 23%[B] 22%[C] 25%[D] 24% |
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Answer» Answer: 32. 25%.............. |
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Solution of this.....➡What are wavelength, frequency, time period and amplitude of a sound wave? |
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Answer» Answer: Time period(T): The time taken by two consecutive COMPRESSIONS or rarefactions to cross a fixed point is called the time period of the sound wave. AMPLITUDE(A): The magnitude of the maximum DISTURBANCE in the MEDIUM on either SIDE of the mean value is called the amplitude of the wave. |
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| 25320. |
427 Construct DEFG such that I(DE) = 4.5 cm, l(EF) = 6.5 cm, I(DG) = 5.5 cm,I(DF) = 7.2 cm, 1(EG) = 7.8 cm. |
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Answer» Step 1: Draw DE = 4.5 cm. Step 2: With D as centre and radius 7.2 cm, draw an arc. Step 3: With E as centre and radius 6.5 cm, draw an arc cutting the previous arc at F. Step 4: Join EF. Step 5: With D as centre and radius 5.5 cm, draw an arc. Step 6: With E as centre and radius 7.8 cm, draw an arc cutting the previous arc at G. Step 7: Join DG and GF. Here, DEFG is the required quadrilateral. |
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6. The ratio of Maths and Science books ina school library is 4: 5. If the number ofScience books is 75, find the number ofMaths books11 |
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Answer» LET the no. of maths and science books be 4x and 5X. No. of science books =75 therefore, 5x = 75 X = 75/5 x= 15 No. of maths books = 4 x = 4×15 = 60 so no. of maths books is 60 hope it helps...^_^ |
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3. The measures of angles of a triangle are x°,(x-20), (x-40)Find the measure of each angle. |
Answer» Given :-We KNOW that SUM of three angles of a triangle is 180° So, simply we will add up all the angles and equal to 180. We will get the value of x Then, simply we can SUBSITUTE values → x + x - 20 + x - 40 = 180 → x + x + x - 20 - 40 = 180 → 3x -60 = 180 → 3x = 180 + 60 → 3x = 240 → x = 240/3 → x = 80 Thus, we got the value of x i.e 80 Subsituting Values :-
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The smallest number by which 6912 must be divided so that the result is a perfect square is 3.Find the perfect square obtainedPlease Correct Answer Will mark brainliest ;) |
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Answer» ?.....…...…..…..……… |
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O OtherIn UKL side U side KL 1-108. -then find the measures of J and LO 127°, 72O 77, 122Q3) Solve the following in |
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Area of a right triangle is 24 cm² and the square of sum of the perpendicular sides is 196. Taking the perpendicular sides as x and y metres . a) what the number is x + yb) find the number x - y |
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Which of the following set of numbers is in descending order?(a) 2, -2 , 1, -1 (b) 0, 1, 2, 3 (c) 1, 0, -1, -2 (d) -3, -2, -1, 0 |
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Answer» Step-by-step EXPLANATION: Because the other 3 are not in the form of DESCENDING |
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1) Root n is an irrational number, if n isa) A natural number b) a prime numberc) an even numberd) an odd number |
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Answer» Here is your answer |
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1. The sum of a two digit number and the number obtained by reversing thedigits is 121. The digit at tens place is 7 more than the digit at units place.Find the number.7 Raniana wants to distribute 500 orannes amongIf 30 |
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3. O MRPN is cyclic, ZR = (5x - 13) °,ZN = (4x + 4). Find mzR & m_NO 82°, 98°O 91°,89°O 92°, 88°O 93°, 87° |
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Answer» Step-by-step EXPLANATION: |
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Distance between the point (11,60) from the origin is756116 |
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Answer» ??????????????????........ Step-by-step EXPLANATION: FOLLOW me |
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6. Compute the gross reproduction rate from the following data.Ans: GRR:=1020.65Agegroup15 - 1920 - 2425 - 2930 - 3435 - 3940 - 4445 - 49Femalebirths1921906233122Femalepopulation1600170017001800170016001500 |
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Answer» Answer: 3 COS =-13 cos =-13 cos =-13 cos =-13 cos =-13 cos =-13 cos =-13 cos =-13 cos =-1 |
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Which of the following is not quadratic equation ?2 pointsa) x²+5x-2=0b) (y+2)(y-5)=0c) m³+3m²-2=3m³d) x²+4x-21=0 |
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Answer» C) m^2+3m^2-2=3m^2 ....... |
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100SesQ IIIAnswer the following questions.What is an event? What are the different events in case we roll a die?1.2.Solve as directeda. Find the least number to be added to 1825 to get a perfect square. (3)b. Find the smallest whole number by which 2800 should be divided to get aperfect squareQ IVGiven below is a frequency distribution table of students having interest in |
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Answer» Answer: Step-by-step explanation: This shows that 42 <1825. 2 =1849. Hence, the number to be added is 43 2 −1825=1849−1825 =24. solution |
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Question 4 of 10Which unit of measure would be appropriate for the area of a picture that is20 centimeters tall and 15 centimeters wide?O A. MetersO B. Cubic centimetersO C. Square centimetersO D. Centimeters |
Answer» It is your ANSWER PLEASE MARK me as BRAINLIST and FOLLOW me on brainly✌ |
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A Narra tree grows 30cm every year, if the age of the tree is 15 years. What is the height of the tree? |
Answer» Answer:450 cm is your answer.Step-by-step explanation:Tree grows EVERY year= 30cmAge of tree= 15 YEARSHeight of the tree = ?we have to find height of the tree =Age of tree X Tree grows every year=15 X 30 = 450cm.hope you like it!☺️☺️If u like it than thanks my answer. |
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C. Calculate the compound interest on Rs 20000 for 3 years if the rates ofinterest for the first second and third year are respectively 8%, 9% and10% per annum |
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Answer» Here, PRINCIPAL amount (P)=20000 Rs So, amount after first YEAR =20000(1+10100)1 Amount after second year =20000(1+10100)(1+10100)1 Amount after third year =20000(1+10100)(1+10100)(1+12100)1 =20000∗1110∗1110∗112100=224∗121=27104 Rs ∴ COMPOUND interest =27104−20000=7104 Rs |
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3. Ratio of ages of Ankita and Deepa is 4:3. After 6 years Ankita's age will be 34 yearWhat is the present age of Deepa ?1) 15 years4) None of these2) 21 years3) 18 years |
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Answer» Answer: |
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8.The product of three consecutive terms of a G. P.is - 64 and the firstterm is four times the third. Find the terms. |
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Answer» Step-by-step EXPLANATION: This is the example . u can SEE in this picture . by this METHOD u can FIND ur answer. I HOPE IT HELPS YOU |
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7 Write thestatement in wordsfollowing symbolicb) b ( y I y is a vowel of english alphabet) |
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Answer» cshbusbggsghvgwbjsjaiajajjs |
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) Which one of the following options is true? y = 3x + 5 has: (A) a unique solution, (B) only two solutions (C) infinitely many solutions (D) no solution *1 |
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Answer» As line is infinitely long,
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The equal side of an isosceles triangle is shownby a, the unequal side as b. Express theperimeter of the triangle using a and b.111 |
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Answer» Answer: the answer is 2a+b.... EI answer ta ektu aegi dilam NA?.... phir bhi KOI BAT nahi.... I am sending it one more time... sis PLZ follow me back... |
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MATHS MCQ Choose the correct a temetre1 Which of the following is an irrational number?O 6=126-12Both of the above |
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Answer» both of the above Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEST |
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In a college 200 students are randomly selected. 140 like tea, 120 like coffee and 80 like bothtea and coffee. Answer the following questions:(i) How many students like only tea?(ii) How many students like only coffee ?(iii) How many students like neither tea or coffee?(iv) How many students like at least one of the beverages? |
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Answer» Total number of students who were randomly SELECTED n(S) = 200 Number of students who like tea = 140 Number of students who like coffee = 120 Number of students who like both = 80 So, Let the number of students who like tea be ' T ' Let the number of students who like coffee be ' C ' So given are :- n(T)=140 n(C)=120 n(T∩C) =80 Venn DiagramQuestion (i) How many students like only tea? Number of students who like only tea = n(T) = 140 students (ii) How many students like only coffee ? Number of students who like only coffee = n(C) = 120 students (iii) How many students like neither tea or coffee? Number of students who like neither tea or coffee = n(S) - [n(T)+n(C) + n(T∩C)]
(iv) How many students like at least one of the beverages? All students like at least one beverage
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The line segment AB is divided at M [3,3] internally in the ratio 5:2 and co-ordinates of point B [-3,3].Find the co-ordinates of point A |
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Answer» Answer: The line SEGMENT is (3,−3) and B(−2,7) Let the point on x - axis be (x,0) which divides the line in the ratio of m:n. Then, USING section formula, (x,y)=( m+n m×x 2
+n×x 1
, m+n m×y 2
+n×y 1
) 0= m+n 7m−3n
7m=3n n m
= 7 3
Thus, the coordinates of x-axis will be: x= 7+3 3(−2)+7(3)
x= 10 15
= 2 3
Thus, the line segment AB is divided in the ratio 7 3
at the point ( 2 3
,0) Thus, 2 times the x-coordinate is 3 |
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The co-ordinates of midpoint of the segment joining the points (12,10) and (4,0) isa. (8,5) b. (16,10) c. (8,10) d. (2,4) |
Answer» (8 , 5) |
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10% per annum.Q.2. A. Subtract the sum of 4x2 + 6x + 3 and 2x2 + 4x + 9 from9x2 +6X + 3B. Divide:( 10 X + 16X + 13x2 + 60) by (x + 2)C. Divide: ( 30 a3b2 – 20ab3 + 12ab - 13b) by 5abD. Multiply (3x2 + 5X – 7) by (3X + 2)SECTION 2 - 20 Marks0.3.A. If n(A) =14, n( 8 )=30, n( B )=20, n(A n B)=11, then find() n(B) (ii) n(A)(iii) n(AUB) (iv) n(A-B) |
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Answer» A) 3x2-4x-9 B) 13x and 60 |
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) 7 √2 ; 5 √3 Compare the surds√49 X 5 √3√49 X √2 √25 X √3√98 √75But 98 75 7 √2 5 √3 |
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. If we substract 4a-7ab+3b+12 from 12a-9ab+5b-3 then the answer is:1 point( A ) 8a+2ab+2b+15( B ) 8a+2ab+2b-15( C ) 8a-2ab+2b-15( D ) 8a-2ab-2b-15 |
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Answer» 12a-9ab+5b-3-(4a-7ab+3b+12) 12a-9,AB +5b-3-4a+7ab-3b-12 8a-2ab+2b-15please FOLLOW me |
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The roots of the quadratic equation 21x² + 25x-4=0 are __________ and ____________ *-1/7 and 4/31/7 and -4/31/3 and -4/7-1/3 and 4/7 |
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Answer» hsgshsjhgdjgd hsgshsjhgdjgd hehgsh |
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What is the sign of b/c ? A. Postive B.Negative C.Zero |
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Answer» POSITIVE................. |
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