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Answer:

C.I f CF

0 - 10 2 2

10 - 20 10 12

20 - 30 12 24

30 - 40 15 39

40- 50 13 52

50 - 60 8 60

60 - 70 4 64

To find MEDIAN, we need to find Median class first,

Total no of students(N)=64

2

N

=

2

64

=32

From Cf we can see 32 is more than 24 and less than 39, So, Median Class =30−40

Now,

M=l+

f

(

2

N

−C)

×h

where, l= lower limit of median class=30,

C= PRECEDING cumulative frequency of median class=24,

f= frequency of median class=15,

h= class size=10

M=30+

15

32−24

×10

=30+

15

8

×10

=30+5.33=35.33

Step-by-step explanation:

• 3√3 = p/Q (q ≠ 0)
• √3 = p/q × 1/3
• √3 = p/3q ---- (1)
• We KNOW that √3 is irrational and p/3q is rational number.
• From (1)
• √3 ≠ p/3q
• So, 3√3 is an irrational number.
• Hence, Proved

I Hope this SOLUTION is help you

Step-by-step explanation:

Answer

(i) Mumbai is warmer than Kanpur in December because Mumbai is located NEAR the sea and hence it experiences moderate climate throughout the year. Kanpur experiences continental type of climate where summers are extremely hot and winters are extremely cold.

(ii) Punjab GETS rain in winter season due to some weak temperate cyclones from the Mediterranean Sea.

(iii) The Indo-gangetic plain gets some rainfall in the month of December and January because of the western DISTURBANCES, which originate in West ASIA and in the REGIONS near the Mediterranean sea. These westerly depressions bring winter rainfall over the Indo-Gangetic Plains

62 ,37 ,32 ,27

Is the NEXT NUMBER

Step-by-step EXPLANATION:

hy shiva ...

ISS question KO again POST kro...

smjh nhi aa raha h KUCH ....

pls

ANSWER:

THEREFORE THE NUMBER OF FACES IS 8

Step-by-step EXPLANATION:

ANSWER:

SORRY I don't KNOW the answer

Answer:

385 CUBIC cm

Step-by-step explanation:

CSA of CYLINDER = 2rh

2rh = 220

rh = 220/2

* r * 10 = 110

r = (110 * 7)/(22 * 10)

r = 7/2 = 3.5 cm

Volume, V =

V = (22/7) * 3.5 * 3.5 * 10

V = 385 cubic cm

volume=1500 m³

Area=27.2m²

+40×0.5m²

=47.2

R.T.=0.161× V/A

=0.8186s

Answer:

GIVEN,

Total number of BAGS = 16

Weight of one BAG = 48.450 kg

Weight of all the 16 bags = 48.450 × 16

= 775.200 kg

Thus, the weight of all the 16 bags is 775.200 kg.

Hope it HELPS!

:)

Answer:

The acceleration of body MOVING with uniform VELOCITY is ZERO, because there is no change in velocity.

Step-by-step EXPLANATION:

Answer:

343cm^3this the answear

Answer:

5464783+(7478382+-())))

Answer:

CORRECT ANSWER WILL BE OPTION C ZERO..

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ANSWER:

Kenji you are not the INTENDED RECIPIENT you are not

Step-by-step EXPLANATION:

I HOPE this ANSWERS will HELP you

ANSWER:

x=2⁹-1x²+12x+15

x=512-1x²+12x+15

x=512-x²+12x+15

x=527-x²+12x

x=-x²+12x+527

ANSWER:

Here is your answer

Step-by-step EXPLANATION:

-20÷5 = -4

20÷5 = 4

( - ) SIGN is the only DIFFERENCE

Answer:

7/4

Step-by-step EXPLANATION:

Answer:

Here, g(x)=3x−1. To apply Remainder theorem, (3x−1) should be CONVERTED to (x−a) form.

∴3x−1=

3

1

(3x−1)=x−

3

1

∴g(x)=(x−

3

1

)

By remainder theorem, r(x)=p(a)=p(

3

1

)

p(x)=x

3

−6x

2

+2x−4⇒p(

3

1

)=(

3

1

)

3

−6(

3

1

)

2

+2(

3

1

)−4

=

27

1

−

9

6

+

3

2

−4=

27

1−18+18−108

=

27

−107

∴ the remainder p(

3

1

)=−

27

107

HOPE it's helpful↑(◍•ᴗ•◍)❤࿐

ANSWER:

this ATTACHMENT has your answer

Answer:

Answer

Given,

[i

18

+(

i

1

)

25

]

3

=(i

18

+

i

25

1

)

3

=(−1+

i

1

)

3

=(−1)

3

+3(−1)

2

i

1

+3(−1)(

i

1

)

2

+(

i

1

)

3

=

i

2

+2

=−2i+2

ANSWER:

the QUESTION of the answer in this PHOTO

STEP:1

DIVIDE both SIDES of the equation by the same term

3x=18

3x/3=18/3

STEP:2

Simplify

Cancel terms that are in both the numerator and denominator.

Divide the numbers

X = 6

SOLUTION :

x = 6

ANSWER:

U MAD its too HARD OK!!!!

ANSWER:

The SUM of a RATIONAL NUMBER and an IRRATIONAL number is irrational.

Answer:

The use of force, in the context of law enforcement, may be defined as the "amount of effort REQUIRED by POLICE to compel COMPLIANCE by an unwilling SUBJECT". Use of force DOCTRINES can be employed by law enforcement officers and military personnel on guard duty.

ANSWER

4/7.

step by step explaination

Hint: In this question, we are given two statements regarding the relationship between the numerator and denominator of the fraction. We have to determine the fraction. For this, we will suppose the numerator of the fraction as x and the denominator of the fraction as y. Then we will form two equations USING the given statement. After that, we will SOLVE them to FIND values of x and y and hence we will find the required fraction.

Complete step-by-step solution

Here we are given two statements regarding the relationship between the numerator and the denominator of the fraction.

Let us suppose that the numerator of the fraction is x and the denominator of the fraction is y.

So our fraction looks like xy.

Now, let us form an equation using the given statement. We are given that, the SUM of the numerator and the denominator of a fraction is 3 less than twice the denominator. Hence, (x+y) is 3 less than 2y.

So our equation becomes x+y=2y−3.

Simplifying we get: x+y−2y=−3⇒x−y=−3⋯⋯⋯(1).

Now numerator and denominator are decreased by 1, so new numerator = x-1 and new denominator = y-1. The new numerator becomes half the denominator. Therefore, x-1 becomes half of (y-1).

Our equation becomes (x−1)=12(y−1).

CROSS multiplying we get:

⇒2(x−1)=y−1⇒2x−2=y−1⇒2x−y=−1+2⇒2x−y=1⋯⋯⋯(2)

Now let us solve equation (1) and (2) to get values of x and y. We will use elimination method for solving.

Subtracting equation (1) from (2) we get:

2x−y−x+y=1−(−3)⇒x=1+3⇒x=4

Putting values of x in equation (1) we get:

⇒4−y=−3⇒4+3=y⇒y=7

Hence the values of x and y are 4 and 7 respectively. So our fraction becomes 47.

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ANSWER:

3-12(a+b)2

Step-by-step EXPLANATION:

Answer:-

3a2-3b2+12a2+12b2

3a2+12a2-3b2+12b2

15a2-9b2

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ANSWER:

I don't KNOW if you have any QUESTIONS

5x^2-6x/3x

x(5x-6)/3x

5x-6/3

is the ANSWER

Answer:

yess

Step-by-step explanation:

1. a LITTLE

2. a few

3. few , the few

4. few, the few

5. The few, little

6. little, few, the few

Hope it helps..

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ANSWER:

ABBI YEH chapter pdhna BAAKI h

Answer:

For example

Step-by-step explanation:

Step by Step Solution

More Icon

STEP

1

:

Equation at the end of step 1

 73x3 -  125

STEP

2

:

Trying to factor as a DIFFERENCE of Cubes:

2.1      Factoring:  343x3-125  

Theory : A difference of TWO perfect cubes,  a3 - b3 can be factored into

             (a-b) • (a2 +ab +B2)

Proof :  (a-b)•(a2+ab+b2) =

           a3+a2b+ab2-ba2-b2a-b3 =

           a3+(a2b-ba2)+(ab2-b2a)-b3 =

           a3+0+0-b3 =

           a3-b3

CHECK :  343  is the cube of  7  

Check :  125  is the cube of   5  

Check :  x3 is the cube of   x1

Factorization is :

            (7x - 5)  •  (49x2 + 35x + 25) A

ANSWER:

here's your answer

Step-by-step EXPLANATION:

HOPE it will HELP you

Step-by-step explanation:

Caste-based trade among the Nakarattars of Tamil Nadu This is not to say that the Nakarattar banking system resembled an economist’s model of Western-style banking systems … the Nakarattars loaned and deposited money with one another in caste-defined social RELATIONSHIPS based on BUSINESS territory, residential location, descent, marriage, and common cult membership. Unlike in modern Western banking systems, it was the reputation, decisions, and reserve deposits shared among exchange spheres defined according to these principles, and not a government-controlled central bank, that … assured public confidence in individual Nakarattars as REPRESENTATIVES of the caste as a whole. In other WORDS, the Nakarattar banking system was a caste-based banking system. Individual Nakarattars organised their lives around participation in and management of various communal institutions adapted to the task of accumulating and distributing RESERVES of capital. Source: Rudner

Read the extracts from Caste and Capitalism in Colonial India(Rudner 1994) in the box and answer the following questions.

1.What are the significant differences between the Nakarattar bankingsystem and the modern Western banking system, according to the author?

2.What are the different ways in which Nakarattar trading andbanking activities are linked to other social structures?

3.Can you think of examples within the modern capitalist economy whereeconomic activities are similarly ‘embedded’ in social structures?

Here is your answer....

The place values of digits go in the sequence of Ones, Tens, Hundreds, THOUSANDS, Ten Thousand, Hundred Thousands, MILLIONS, Ten Million and so on, in the international numeral SYSTEM. In the number 12,345,678 the place values of each digit are: 8 – Ones.

Hope it will be helpful for you.

THANKS for READING.

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Answer:

0.875

Step-by-step EXPLANATION:

Step-by-step explanation:

10 RATIONAL NUMBERS between -1/2 and 3/5

=-1/2 into 5/5 and 3/5 into 2/2

= -5/10 and 6/10

= -5/10( -4/10,-3/10,-2/10,-1/10,-0/10, 1/10,2/10,3/10, 4/10,5/10)6/10

2x-8=28

→2x=28-8

→2x=20

→x=20/2

→x=10

So the NUMBER is 10

and 10-8=2

The NUMBERS are 10 and 2.

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ANSWER:

HELLO r u FF player

Step-by-step EXPLANATION:

irdosfmenp

j

o

I

N

n

o

w

f

a

s

t

joi n it now then

Step-by-step EXPLANATION:

PLEASE FOLLOW MARK BRAINLIST

Step-by-step EXPLANATION:

Answer:

73

Step-by-step EXPLANATION:

let the supplement be, x

The the ANGLE will be, x-34

As they are SUPPLEMENTARY:

x + (x-34) =180

2x - 34 = 180

2x = 180 + 34

x = 214/2

= 107

So, the angle you're LOOKING for= x - 34

= 107 - 34

= 73

ANSWER:

the RATIONAL NUMBER LIES between 1/3 and 5/6 is 5.1

ANSWER:

U PUT their more POINTS I will SURELY do it

Step-by-step explanation:

. Factoring and solving equations

- A. Factor1. Factor 3x2 + 6x if possible.

Look for monomial (single-term) factors first; 3 is a factor of both 3x2

and 6x and so is x . Factor them out to get

3x2 + 6x = 3(x2 + 2x1 = 3x(x+ 2) .

2. Factor x2 + x - 6 if possible.

Here we have no common monomial factors. To get the x2 term

we'll have the form (x +-)(x +-) . Since

(x+A)(x+B) = x2 + (A+B)x + AB ,

we need two numbers A and B whose sum is 1 and whose product is

-6 . Integer possibilities that will give a product of -6 are

-6 and 1, 6 and -1, -3 and 2, 3 and -2.

The only pair whose sum is 1 is (3 and -2) , so the factorization is

x2 + x - 6 = (x+3)(x-2) .

3. Factor 4x2 - 3x - 10 if possible.

Because of the 4x2 term the factored form wli be either

(4x+A)(x +B) or (2x+A)(2x+B) . Because of the -10 the integer possibilities for the pair A, B are

10 and -1 , -10 and 1 , 5 and -2 . -5 and 2 , PLUS each of

these in reversed order.

Check the various possibilities by trial and error. It may help to write

out the expansions

(4x + A)(x+ B) = 4x2 + (4B+A)x + A8

1 trying to get -3 here

(2x+A)(2x+B) = 4x2 + (2B+ 2A)x + AB

Trial and error gives the factorization 4x2 - 3x - 10 - (4x+5)(x- 2) .

4. Difference of two squares. Since (A + B)(A - B) = - B~ , any

expression of the form A' - B' can be factored. Note that A and B

might be anything at all.

Examples: 9x2 - 16 = (3x1' - 4' = (3x +4)(3x - 4)

x2 - 29 = x2 - (my)* = (x+ JTY)(x- my)

For any of the above examples one could also USE the  

In the factorization

-

ax2 + bx + c = a(x-Ah-B) ,

the numbers A and B are given by

A,B = -

2a

If the 'discriminant" b2 - 4ac is negative, the polynomial

cannot be factored over the real numbers (e.g. consider x2 + 1).

In EXAMPLE 2 above, a = 1, b = 1, c = -6 , so

A,B =

2 'l tE3 = '

= 2,-3 , so x +x-6 - (x-2)(~+3). 2 2

5. Factor x3 + 3x2 - 4 if possible.

If plugging x = a into a polynomial yields -zero, then the

polynomial has (x - a) as a factor.

We'll use this fact to try to find factors of x3 + 3x2 - 4 . We look for

factors (x-a) by plugging in various possible a's , choosing those that

are factors of -4 . Try plugging x 1-12 2 4, -4 into

x3+3x2-4. Findthat x-I gives 13+3.12-4 -0. So x-1 isa

factor of x3 + 3x2 - 4 . To factor it out, perform long division:

x2 + 4x + 4 Thus

x-~ lx3 + sx2+ Ox - ~3 + 3x2 - 4 = (x-I)(x~ + 4x + 4).

x3 - .2 But x2 + 4x + 4 can be

4x2 + Ox - 4 factored further as in the

4x2 - 4x examples above;

4x - 4

-

0

we finally get x3 + 3x2 - 4 = (x- l)(x+ 2)(x+2) = (x- 1)(~+2)~ .

s IIA Factor the following polynomials.

1. x2 + 8X + 15 2. 4x2 - 25  

3. 49 - 13y - 12 4. x3 + 2x2 - x - 2

5. 4z2 + 42 - 8 6. a2 + 3a + 2

7. Simplify by factoring 3x 2 + 3x - 18

numerator and denominator: 2 4x - 3x - 10

B. Solvina eauatlons

1. Linear or first-degree equations: involving x but not x2 or any

other power of x . Collect x-terms on one side, constant terms on the

other.

ExamDle x+3=7x-4

x + (-7x1 = -4 + (-3)

-6x = -7

x = 7/6

2. Quadratic equations: involving x2 but no higher power of x . These are solved by factoring and/or use of the quadratic formula:

The equation ax2 + bx + c = 0 (a - 0)

has solutions x =

2a

If b2 - 4ac is negative, the equation has no real solutions.

Exam& Solve x2-2x-3=0 for x.

Method: Factoring. x2 - 2x - 3 = (x- 3)(x+1) = 0 . Since a product of two numbers is zero if and only if one of the two

numbers is zero, we must have

x - 3 = 0 or x + I = 0 . So the solutions are x = 3. -1 .

ANSWER:

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ANSWER:

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