332354 + Interview Questions in Secondary School in Math Page 9 InterviewSolution

401.	A man made a will in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child. rec. The rest was to be shared equally among his four children respectively. What was his wife's share
Answer» Correct Question :- A man made a bill in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child . The rest was to be shared equally among his four CHILDREN respectively . If each of the younger children recieved 108000 . what was his wife share Solution :- Let the TOTAL money be x If he left 4/9 of his money to his wife ,then the share of wife = 4x/9 Remaining money = x - 4x/9 By taking LCM Remaining money = 9x - 4x/9 Remaing money = 5X/9 According to the question , 2/5 of the remainder to his oldest child is :- Therefore, 2/5 * 5x/ 9 = 2x/ 9 Therefore , The rest money left x - 4x/9 - 2x/9 9x - 4x - 2x /9 9x - 6x/9 3x/9 = x/ 3 Now , The rest money is shared in 4 EQUAL parts Therefore, (x/ 3 )/ 4 = x / 12 Each of the younger children get 108000 Therefore, x / 12 = 108000 x = 108000* 12 x = 1296000 Hence , The total money is 1296000 Now , CALCULATING wife shares 4/9 * 1296000 = 576000

401.

A man made a will in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child. rec. The rest was to be shared equally among his four children respectively. What was his wife's share

Answer»

Correct Question :-

A man made a bill in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child . The rest was to be shared equally among his four CHILDREN respectively . If each of the younger children recieved 108000 . what was his wife share

Solution :-

Let the TOTAL money be x

If he left 4/9 of his money to his wife ,then the share of wife = 4x/9

Remaining money = x - 4x/9

By taking LCM

Remaining money = 9x - 4x/9

Remaing money = 5X/9

According to the question ,

2/5 of the remainder to his oldest child is :-

Therefore,

2/5 * 5x/ 9

= 2x/ 9

Therefore , The rest money left

x - 4x/9 - 2x/9

9x - 4x - 2x /9

9x - 6x/9

3x/9

= x/ 3

Now , The rest money is shared in 4 EQUAL parts

Therefore,

(x/ 3 )/ 4

= x / 12

Each of the younger children get 108000

Therefore,

x / 12 = 108000

x = 108000* 12

x = 1296000

Hence , The total money is 1296000

Now , CALCULATING wife shares

4/9 * 1296000

= 576000

Discussion

402.	Will the perimeter of the square change,if the sides are cut off as shown here?
Answer» Answer: We will discuss here how to find the perimeter of a square. Perimeter of a square is the total length (distance) of the BOUNDARY of a square. In a square all the sides are of equal lengths. Perimeter of a Square 5Save Hence, perimeter of a square = 4l We know that all the sides of a square are equal. Perimeter of a Square Perimeter of the square ABCD = AB + BC + CD + AD = 2 cm + 2 cm + 2 cm + 2 cm = (2 × 4) cm = 8 cm Perimeter of a square is 4 times of s SIDE. Perimeter of a square = 4 × length of a side. Let us CONSIDER some of the examples on perimeter of a square: Examples on Perimeter of a Square 1. Each side of a square is 2.5 cm. Find its perimeter. Solution: Side = 2.5 cm Therefore, perimeter of a square = 4 × length of a side = (4 × 2.5) cm = 10 cm 2. A rope of length 96 m was used to fence a square garden. What is the length of the side of the garden? Solution: Perimeter of the garden = Length of the rope = 96 m We know that perimeter of a square = 4 × length of a side So, 4 × length of a side = 96 m Length of a side = 964 m = 24 m Therefore, length of the one side of the square shape garden is 24 m. 3. Find the perimeter of a square shaped playground whose each side length 12 m. Solution: We know a square has four equal sides. So, we can easily calculate the perimeter of a square. The formula for finding the perimeter of a square is: P = 4 × length of a side = 4 × 12 m = 48 m Perimeter of a Square 5Save 4. Each sides of a paper sheet is 14 ft. Find its perimeter. Solution: Given: Side length is 14 ft. Perimeter of a square is = 4 × side = 4 × 14 ft = 56 ft 5. Find the perimeter of the square PQRS whose one side is 10.5 m. Perimeter of a Square Problems 5Save Solution: Side of the square = 10.5 m Perimeter of the square = 4 × side = 4 × 10.5 = 42 m

402.

Will the perimeter of the square change,if the sides are cut off as shown here?

Answer»

Answer:

We will discuss here how to find the perimeter of a square. Perimeter of a square is the total length (distance) of the BOUNDARY of a square.

In a square all the sides are of equal lengths.

Perimeter of a Square

5Save

Hence, perimeter of a square = 4l

We know that all the sides of a square are equal.

Perimeter of a Square

Perimeter of the square ABCD

= AB + BC + CD + AD

= 2 cm + 2 cm + 2 cm + 2 cm

= (2 × 4) cm

= 8 cm

Perimeter of a square is 4 times of s SIDE.

Perimeter of a square = 4 × length of a side.

Let us CONSIDER some of the examples on perimeter of a square:

Examples on Perimeter of a Square

1. Each side of a square is 2.5 cm. Find its perimeter.

Solution:

Side = 2.5 cm

Therefore, perimeter of a square = 4 × length of a side

= (4 × 2.5) cm

= 10 cm

2. A rope of length 96 m was used to fence a square garden. What is the length of the side of the garden?

Solution:

Perimeter of the garden = Length of the rope = 96 m

We know that perimeter of a square = 4 × length of a side

So, 4 × length of a side = 96 m

Length of a side = 964 m = 24 m

Therefore, length of the one side of the square shape garden is 24 m.

3. Find the perimeter of a square shaped playground whose each side length 12 m.

Solution:

We know a square has four equal sides. So, we can easily calculate the perimeter of a square.

The formula for finding the perimeter of a square is:

P = 4 × length of a side

= 4 × 12 m

= 48 m

Perimeter of a Square

5Save

4. Each sides of a paper sheet is 14 ft. Find its perimeter.

Solution:

Given: Side length is 14 ft.

Perimeter of a square is = 4 × side

= 4 × 14 ft

= 56 ft

5. Find the perimeter of the square PQRS whose one side is 10.5 m.

Perimeter of a Square Problems

5Save

Solution:

Side of the square = 10.5 m

Perimeter of the square = 4 × side

= 4 × 10.5

= 42 m

Discussion

403.	Add 2 whole 4 upon 5 and 3 whole 5 upon 6
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ $\leadsto\bf 2\dfrac{4}{5} + 3\dfrac{5}{6} \\ \\$ $\leadsto\bf 2 + \dfrac{4}{5} + 3 + \dfrac{5}{6} \\ \\$ $\leadsto\bf 5 + \dfrac{4}{5} + \dfrac{5}{6} \\ \\$ Now, $\leadsto\bf \dfrac{4}{5} + \dfrac{5}{6} \\ \\$ $\leadsto\bf \dfrac{4 \times 6}{5 \times 6} + \dfrac{5 \times 5}{6 \times 5} \\ \\$ Since LCM of 5 and 6 = 30 $\leadsto\bf \dfrac{24}{30} + \dfrac{25}{30} \\ \\$ $\leadsto\bf \dfrac{49}{30} \\ \\$ $\leadsto\bf \dfrac{30 + 19}{30} \\ \\$ $\leadsto\bf 1 + \dfrac{19}{30} \\ \\$ Thus, $\leadsto\bf 5 + \dfrac{4}{5} + \dfrac{5}{6} \\ \\$ $\leadsto\bf 5 + 1 + \dfrac{19}{30}\\ \\$ $\leadsto\bf 6 + \dfrac{19}{30} \\ \\$ $\leadsto\bf 6 \dfrac{19}{30} \\ \\$ And, therefore, $\leadsto\bf 2\dfrac{4}{5} + 3\dfrac{5}{6} = 6 \dfrac{19}{30}\\ \\$ More INFORMATION: A fraction is a number REPRESENTING a part of a WHOLE. The whole may be a single OBJECT or a group of objects.

403.

Add 2 whole 4 upon 5 and 3 whole 5 upon 6

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

$\leadsto\bf 2\dfrac{4}{5} + 3\dfrac{5}{6} \\ \\$

$\leadsto\bf 2 + \dfrac{4}{5} + 3 + \dfrac{5}{6} \\ \\$

$\leadsto\bf 5 + \dfrac{4}{5} + \dfrac{5}{6} \\ \\$

Now,

$\leadsto\bf \dfrac{4}{5} + \dfrac{5}{6} \\ \\$

$\leadsto\bf \dfrac{4 \times 6}{5 \times 6} + \dfrac{5 \times 5}{6 \times 5} \\ \\$

Since LCM of 5 and 6 = 30

$\leadsto\bf \dfrac{24}{30} + \dfrac{25}{30} \\ \\$

$\leadsto\bf \dfrac{49}{30} \\ \\$

$\leadsto\bf \dfrac{30 + 19}{30} \\ \\$

$\leadsto\bf 1 + \dfrac{19}{30} \\ \\$

Thus,

$\leadsto\bf 5 + \dfrac{4}{5} + \dfrac{5}{6} \\ \\$

$\leadsto\bf 5 + 1 + \dfrac{19}{30}\\ \\$

$\leadsto\bf 6 + \dfrac{19}{30} \\ \\$

$\leadsto\bf 6 \dfrac{19}{30} \\ \\$

And, therefore,

$\leadsto\bf 2\dfrac{4}{5} + 3\dfrac{5}{6} = 6 \dfrac{19}{30}\\ \\$

More INFORMATION:

A fraction is a number REPRESENTING a part of a WHOLE. The whole may be a single OBJECT or a group of objects.

Discussion

404.	What is the anwser of 80+25-67÷2
Answer» Answer: 71.5 Hope it HELPS!!

404.

What is the anwser of 80+25-67÷2

Answer»

Answer:

71.5

Hope it HELPS!!

Discussion

405.	Why most people suggest me watch naruto i watched it my favorite is itach and luffy in one piece
Answer» ANSWER: {\__/} (X . X) ( <\|FULL METAL ALCHEMIST BROTHERHOOD\|) Step-by-step explanation:

405.

Why most people suggest me watch naruto i watched it my favorite is itach and luffy in one piece

Answer»

ANSWER:

{\__/}

(X . X)

( <|FULL METAL ALCHEMIST BROTHERHOOD|)

Step-by-step explanation:

Discussion

406.	The point whose ordinate is 4 nad which lies on y - axis is
Answer» ANSWER: [0,4] because 0 is on X AXIS and 4 is on y axis.

406.

The point whose ordinate is 4 nad which lies on y - axis is

Answer»

ANSWER:

[0,4]

because 0 is on X AXIS and 4 is on y axis.

Discussion

407.	Length and breadth of a rectangular field are 50m and 15m respectively. Find the ratio of the length and breath
Answer» REQUIRED answer:- The ratio of the length and breath is 10 : 3. Given Information:- Length and breadth of a rectangular field are 50m and 15m respectively. Need to find out:- The ratio of the length and breath = ? Explanation:- Length of the rectangular field = 50 m Breadth of the rectangular field = 15 m The ratio of the length to the breadth is 50 : 15 The ratio can be written as 50/15. => The required ratio = 50 ÷ 5/ 15 ÷ 5 => The required ratio = 10/3 => The required ratio = 10 : 3 Hence:- The ratio of the length and breath is 10 : 3. _____________________

407.

Length and breadth of a rectangular field are 50m and 15m respectively. Find the ratio of the length and breath

Answer»

REQUIRED answer:-

The ratio of the length and breath is 10 : 3.

Given Information:-

Length and breadth of a rectangular field are 50m and 15m respectively.

Need to find out:-

The ratio of the length and breath = ?

Explanation:-

Length of the rectangular field = 50 m

Breadth of the rectangular field = 15 m

The ratio of the length to the breadth is 50 : 15

The ratio can be written as 50/15.

=> The required ratio = 50 ÷ 5/ 15 ÷ 5

=> The required ratio = 10/3

=> The required ratio = 10 : 3

Hence:-

The ratio of the length and breath is 10 : 3.

_____________________

Discussion

408.	- Very Short Answer Type Questions1. Without actual division, find which of the followingrational numbers are terminating decimals.3116(i)37512587(iii)(iv)3525(ii)
Answer» Answer: The rational not having DENOMINATOR as multiple of 2m×5n will be non TERMINATING. (1) 167=2×2×2×27− denominator is multiple of 2m×5n HENCE terminating. (2) 12523=5×5×523 -- denominator is multiple of 2m×5n hence terminating. (3) 149=7×29 -- denominator is not multiple of 2m×5n hence non-terminating (4)4532=3×3×532-- denominator is not multiple of 2m×5n hence non-terminating. (5) 5043=5×5×243-- denominator is multiple of 2m×5n hence terminating. (6)4017=2×2×2×517 -- denominator is multiple of 2m×5

408.

- Very Short Answer Type Questions1. Without actual division, find which of the followingrational numbers are terminating decimals.3116(i)37512587(iii)(iv)3525(ii)

Answer»

Answer:

The rational not having DENOMINATOR as multiple of 2m×5n will be non TERMINATING.

(1) 167=2×2×2×27− denominator is multiple of 2m×5n HENCE terminating.

(2) 12523=5×5×523 -- denominator is multiple of 2m×5n hence terminating.

(3) 149=7×29 -- denominator is not multiple of 2m×5n hence non-terminating

(4)4532=3×3×532-- denominator is not multiple of 2m×5n hence non-terminating.

(5) 5043=5×5×243-- denominator is multiple of 2m×5n hence terminating.

(6)4017=2×2×2×517 -- denominator is multiple of 2m×5

Discussion

409.	The sum of 4 consecutive even numbers is 36
Answer» Step-by-step explanation: Four CONSECUTIVE even numbers can be REPRESENTED by N, n+2, n+4, and n+6. Then: n+n+2+n+4+n+6=36 4n=24 n=6 Then the numbers are 6, 8, 10, and 12

409.

The sum of 4 consecutive even numbers is 36

Answer»

Step-by-step explanation:

Four CONSECUTIVE even numbers can be REPRESENTED by N, n+2, n+4, and n+6. Then:

n+n+2+n+4+n+6=36

4n=24

n=6

Then the numbers are 6, 8, 10, and 12

Discussion

410.	In the factorization of 3x^2-20x-192=0, how can -20x be split into two terms?
Answer» Step-by-step explanation: -20x should be split into 2 TWO TERMS in such a way that their PRODUCT = -192×3x²= -576x² = -36x×16x so, -36x+16x =20x 3x²-36x+16x-192=0 3x(x-12)+16(x-12)=0 (3x+16)(x-12)=0 3x+16=0, x-12=0 x=-16/3,12

410.

In the factorization of 3x^2-20x-192=0, how can -20x be split into two terms?

Answer»

Step-by-step explanation:

-20x should be split into 2 TWO TERMS in such a way that their PRODUCT = -192×3x²= -576x² = -36x×16x

so, -36x+16x =20x

3x²-36x+16x-192=0

3x(x-12)+16(x-12)=0

(3x+16)(x-12)=0

3x+16=0, x-12=0

x=-16/3,12

Discussion

411.	Who has an iphone 11
Answer» ANSWER: i don't have it Step-by-step EXPLANATION: i WANT to BUY IPHONE

411.

Who has an iphone 11

Answer»

ANSWER:

i don't have it

Step-by-step EXPLANATION:

i WANT to BUY IPHONE

Discussion

412.	Class 9 assignment math 6th answer
Answer» ANSWER: PLS ASK the QUESTION PROPERLY

412.

Class 9 assignment math 6th answer

Answer»

ANSWER:

PLS ASK the QUESTION PROPERLY

Discussion

413.	Divide 60 in the ratio 1:2 between kriti and kiran
Answer» REQUIRED answer:- Kriti's Share = Rs 20 Kiran's Share = Rs 40 Given Information:- The given ratio is 1 : 2. Explanation:- The two parts are 1 and 2. Therefore, Sum of the parts = 1 + 2 Sum of the parts = 3 This means if there are Rs 3, Kriti will get Rs 1 and Kiran will get Rs 2. Or, we can say that Kriti gets 1 part and Kiran gets 2 parts out of every 3 parts. Therefore, => Kriti's Share = 1/3 × 60 => Kriti's Share = Rs 20 And, => Kiran's Share = 2/3 × 60 => Kiran's Share = Rs 40

413.

Divide 60 in the ratio 1:2 between kriti and kiran

Answer»

REQUIRED answer:-

Kriti's Share = Rs 20

Kiran's Share = Rs 40

Given Information:-

The given ratio is 1 : 2.

Explanation:-

The two parts are 1 and 2.

Therefore,

Sum of the parts = 1 + 2

Sum of the parts = 3

This means if there are Rs 3, Kriti will get Rs 1 and Kiran will get Rs 2. Or, we can say that Kriti gets 1 part and Kiran gets 2 parts out of every 3 parts.

Therefore,

=> Kriti's Share = 1/3 × 60

=> Kriti's Share = Rs 20

And,

=> Kiran's Share = 2/3 × 60

=> Kiran's Share = Rs 40

Discussion

414.	A current of 0.25 A flows in the main circuit. Now,the resistance R is disconnected and then connectedacross the 4 ohm resistance. Current in the circuit is?
Answer» ANSWER: ANSWER The EQUIVALENT resistance of circuit is R eq =R+60∣∣(20∣∣10)=R+60∣∣( 20+10 20×10 )=R+60∣∣(20/3)=R+ 60+20/3 60×20/3 =R+(1200/200)=R+6 Now current , i= R+6 12 =0.25 or R+6= 0.25 12 =48 ∴R=48−6=42Ω

414.

A current of 0.25 A flows in the main circuit. Now,the resistance R is disconnected and then connectedacross the 4 ohm resistance. Current in the circuit is?

Answer»

ANSWER:

ANSWER

The EQUIVALENT resistance of circuit is R

eq

=R+60∣∣(20∣∣10)=R+60∣∣(

20+10

20×10

)=R+60∣∣(20/3)=R+

60+20/3

60×20/3

=R+(1200/200)=R+6

Now current , i=

R+6

12

=0.25

or R+6=

0.25

12

=48

∴R=48−6=42Ω

Discussion

415.	How to send message to friend plz answar qiuckly
Answer» ANSWER: you can't. KEEP answering questions and UPGRADE yourself first

415.

How to send message to friend plz answar qiuckly

Answer»

ANSWER:

you can't. KEEP answering questions and UPGRADE yourself first

Discussion

416.	2,6,10,18,14,22,26,30,34,38,42,46,50,54,58 मै कोई तीन संख्या जोड़ के 60 उत्तर लाओ
Answer» Answer: 10+10+18+22=60 Step-by-step EXPLANATION: मैंने सिर्फ तीन नंबर ही लिए है बस दस को दो बार लिखा है।,और यह कही लिखा आप दो बार प्रयोग नहीं कर सकते।

416.

2,6,10,18,14,22,26,30,34,38,42,46,50,54,58 मै कोई तीन संख्या जोड़ के 60 उत्तर लाओ

Answer»

Answer:

10+10+18+22=60

Step-by-step EXPLANATION:

मैंने सिर्फ तीन नंबर ही लिए है बस दस को दो बार लिखा है।,और यह कही लिखा आप दो बार प्रयोग नहीं कर सकते।

Discussion

417.	Find the ratio of 90cm and 1.5 m
Answer» REQUIRED answer:- The ratio of 90CM and 1.5 m is 3 : 5. GIVEN Information:- The given ratio is 90 cm and 1.5 m Need to FIND out:- The ratio of 90cm and 1.5 m = ? Explanation:- The two quantities are not in the same units. Therefore, We have to convert them into same units. => 1.5 m => 1.5 × 100 cm => 150 cm Therefore, The required ratio is 90 : 150. => Required ratio = 90/150 => Required ratio = 90 × 30/ 150 × 30 => Required ratio = 3/5 Hence:- The ratio of 90cm and 1.5 m is 3 : 5

417.

Find the ratio of 90cm and 1.5 m

Answer»

REQUIRED answer:-

The ratio of 90CM and 1.5 m is 3 : 5.

GIVEN Information:-

The given ratio is 90 cm and 1.5 m

Need to FIND out:-

The ratio of 90cm and 1.5 m = ?

Explanation:-

The two quantities are not in the same units.

Therefore,

We have to convert them into same units.

=> 1.5 m

=> 1.5 × 100 cm

=> 150 cm

Therefore,

The required ratio is 90 : 150.

=> Required ratio = 90/150

=> Required ratio = 90 × 30/ 150 × 30

=> Required ratio = 3/5

Hence:-

The ratio of 90cm and 1.5 m is 3 : 5

Discussion

418.	Choose the correct option.Find the smallest nurnber, which when divided by 16, 24,32 and 48 leaves remainder 13,21, 29 and 45 respectively.
Answer» Answer: 3 is the answer Step-by-step EXPLANATION: HOPE it HELPS

418.

Choose the correct option.Find the smallest nurnber, which when divided by 16, 24,32 and 48 leaves remainder 13,21, 29 and 45 respectively.

Answer»

Answer:

3 is the answer

Step-by-step EXPLANATION:

HOPE it HELPS

Discussion

419.	Subtract :- 22/x from x+1 / x -1 =?2X Means x raise to 2
Answer» Step-by-step EXPLANATION: geometric mean ⇒ (√((x^2 +2).2)) = 6−3x the EQUATION valid for 6−3x ≥0 or x ≤ 2. squaring both SIDES gives 2x^2 +4 = 9x^2 −36x+36 7x^2 −36x+32 = 0 (7x−8)(x−4)=0 { ((x=(8/7)←accept)),((x=4 ←rejected)) :} the value of x is (8/7). please follow me... thanks my answer

419.

Subtract :- 22/x from x+1 / x -1 =?2X Means x raise to 2

Answer»

Step-by-step EXPLANATION:

geometric mean ⇒ (√((x^2 +2).2)) = 6−3x

the EQUATION valid for 6−3x ≥0

or x ≤ 2.

squaring both SIDES gives

2x^2 +4 = 9x^2 −36x+36

7x^2 −36x+32 = 0

(7x−8)(x−4)=0

{ ((x=(8/7)←accept)),((x=4 ←rejected)) :}

the value of x is (8/7).

please follow me...

thanks my answer

Discussion

420.	Use the coordinate grid to determine the coordinates of point P:A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole unit of the grid. A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis.What are the coordinates of point P? (1 point)a(−1.4, 0.6)b(1.4, −0.6)c(−0.7, 0.3)d(0.7, −0.3)
Answer» $\huge\mathfrak{hello \: birather}$ The coordinates of point P are (-1.4,0.6) Step-by-step explanation: We are GIVEN A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole UNIT of the grid. that means each grid has a value of 0.2. " A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis " As P LIES on the left of the y-axis and above the x-axis hence the x-value will be negative and y-value will be positive. According to the given information P lies 7 grid lines to the left of y-axis. i.e. it has x-value -7×0.2= -1.4 and 3 grid lines above the x-axis i.e. it has y-value: y-value= 3×0.2=0.6 Hence, the coordinates of Point P are (-1.4,0.6).

420.

Use the coordinate grid to determine the coordinates of point P:A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole unit of the grid. A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis.What are the coordinates of point P? (1 point)a(−1.4, 0.6)b(1.4, −0.6)c(−0.7, 0.3)d(0.7, −0.3)

Answer»

$\huge\mathfrak{hello \: birather}$

The coordinates of point P are (-1.4,0.6)

Step-by-step explanation:

We are GIVEN A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole UNIT of the grid.

that means each grid has a value of 0.2.

" A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis "

As P LIES on the left of the y-axis and above the x-axis hence the x-value will be negative and y-value will be positive.

According to the given information P lies 7 grid lines to the left of y-axis.

i.e. it has x-value -7×0.2= -1.4

and 3 grid lines above the x-axis i.e. it has y-value:

y-value= 3×0.2=0.6

Hence, the coordinates of Point P are (-1.4,0.6).

Discussion

421.	If the cost of 6 cans of juice is ₹210, then what will be the cost of 4 cans of juice?
Answer» REQUIRED answer:- The cost of 4 cans of JUICE is Rs 140. Given Information:- The cost of 6 cans of juice is ₹210. Number of canes = 4 canes Need to find out:- The cost of 4 cans of juice = ? EXPLANATION:- Cost of 6 cans of juice is Rs 210 (Given) THEREFORE, => Cost of 1 can of juice = 210/6 => Cost of 1 can of juice = Rs 35 Therefore, => Cost of 4 cans of juice = Rs 35 × 4 => Cost of 4 cans of juice = Rs 140 Hence:- The cost of 4 cans of juice is Rs 140. More Information:- The method in which first we find the value of one unit and then the value of required number of units is known as unitary method.

421.

If the cost of 6 cans of juice is ₹210, then what will be the cost of 4 cans of juice?

Answer»

REQUIRED answer:-

The cost of 4 cans of JUICE is Rs 140.

Given Information:-

The cost of 6 cans of juice is ₹210.

Number of canes = 4 canes

Need to find out:-

The cost of 4 cans of juice = ?

EXPLANATION:-

Cost of 6 cans of juice is Rs 210 (Given)

THEREFORE,

=> Cost of 1 can of juice = 210/6

=> Cost of 1 can of juice = Rs 35

Therefore,

=> Cost of 4 cans of juice = Rs 35 × 4

=> Cost of 4 cans of juice = Rs 140

Hence:-

The cost of 4 cans of juice is Rs 140.

More Information:-

The method in which first we find the value of one unit and then the value of required number of units is known as unitary method.

Discussion

422.	With step answer if x, y and b are real numbers and x0 then
Answer» ANSWER: your QUESTION is INCOMPLETE

422.

With step answer if x, y and b are real numbers and x0 then

Answer»

ANSWER:

your QUESTION is INCOMPLETE

Discussion

423.	17 - (6 + 6) =X find the x value
Answer» Answer: 17-(6+6)=x 17-(12)=x 17-12=x x=17-12 x=5

423.

17 - (6 + 6) =X find the x value

Answer»

Answer:

17-(6+6)=x

17-(12)=x

17-12=x

x=17-12

x=5

Discussion

424.	What is -3+(6x7)-4 do anybody know this
Answer» ANSWER: *3+(6x7)-4* *3+(6x7)-4 =3+42-4* *3+(6x7)-4 =3+42-4=45-4* *3+(6x7)-4 =3+42-4=45-4=41*

424.

What is -3+(6x7)-4 do anybody know this

Answer»

ANSWER:

3+(6x7)-4

3+(6x7)-4 =3+42-4

3+(6x7)-4 =3+42-4=45-4

3+(6x7)-4 =3+42-4=45-4=41

Discussion

425.	A man made a will in which he left 4/9 of his money to his wife
Answer» ANSWER: then WT HAPPENED to 5/9th of it? .-.

425.

A man made a will in which he left 4/9 of his money to his wife

Answer»

ANSWER:

then WT HAPPENED to 5/9th of it? .-.

Discussion

426.	A car travels 90 km in 2 1/2 hours (1) How much time is required to cover 30 km with the same speed (2) Find the distance covered in 2 hours with the same speed
Answer» (a) How much time is required to cover 30 KM with the same speed. In this Case, time is unknown and distance is known. Therefore, We proceed as follows: => 2½ HOURS => 5/2 hours => 5/2 × 60 minutes => 150 minutes 90 km is covered in 150 minutes Therefore, => 1 km can be covered in 150/90 minutes Therefore, => 30 km can be covered in 150/90 × 30 minutes => 30 km can be covered in 50 minutes Thus:- 30 km can be covered in 50 minutes. _____________________ (b) Find the distance covered in 2 hours with the same speed. In this case, distance is unknown and time is known. Therefore, We can proceed follows: => Distance covered in 2½ hours => Distance covered in 5/2 hours => Distance covered = 90 km Therefore, => Distance covered in 2 hours = 36 × 2 => Distance covered in 2 hours = 72 km Thus:- In 2 hours, distance covered is 72 km.

426.

A car travels 90 km in 2 1/2 hours (1) How much time is required to cover 30 km with the same speed (2) Find the distance covered in 2 hours with the same speed

Answer»

(a) How much time is required to cover 30 KM with the same speed.

In this Case, time is unknown and distance is known.

Therefore,

We proceed as follows:

=> 2½ HOURS

=> 5/2 hours

=> 5/2 × 60 minutes

=> 150 minutes

90 km is covered in 150 minutes

Therefore,

=> 1 km can be covered in 150/90 minutes

Therefore,

=> 30 km can be covered in 150/90 × 30 minutes

=> 30 km can be covered in 50 minutes

Thus:-

30 km can be covered in 50 minutes.

_____________________

(b) Find the distance covered in 2 hours with the same speed.

In this case, distance is unknown and time is known.

Therefore,

We can proceed follows:

=> Distance covered in 2½ hours

=> Distance covered in 5/2 hours

=> Distance covered = 90 km

Therefore,

=> Distance covered in 2 hours = 36 × 2

=> Distance covered in 2 hours = 72 km

Thus:-

In 2 hours, distance covered is 72 km.

Discussion

427.	The sum of three times a number and 5 added to it is 44
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ Required ANSWER: The NUMBER is 13. Correct Question: When 5 is ADDED to three times a number, we obtain 44. Find the number. Given Information: 5 is added to 3 times a number then we get 44. Need to find out: The number is = ? $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$ Let the number be x. Now, => 3x + 5 = 44 => 3x = 39 => x = 13 So, The number = 13. $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Check:-\:\:\:}}}}}} \\$ x = 13 Then, => 3 × 13 + 5 => 39 + 5 => 44 which is true.

427.

The sum of three times a number and 5 added to it is 44

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

Required ANSWER:

The NUMBER is 13.

Correct Question:

When 5 is ADDED to three times a number, we obtain 44. Find the number.

Given Information:

5 is added to 3 times a number then we get 44.

Need to find out:

The number is = ?

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$

Let the number be x.

Now,

=> 3x + 5 = 44

=> 3x = 39

=> x = 13

So,

The number = 13.

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Check:-\:\:\:}}}}}} \\$

x = 13

Then,

=> 3 × 13 + 5

=> 39 + 5

=> 44 which is true.

Discussion

428.	Which of the following expression are polynomial justify i) 4 x square + 6 x - 2 ii) 2 x square + 3/ x - 5 iii) y square - 9 iv) 2 √ X - 4 v) 2 x - -cube + 3 x - 7 vi ) 3 x power x + 2 vii ) 4 x 1/ 2 -3 viii) 3/ 2 x - 1/ 4 ix) 0.0 7 b square - 2.6b + 13. 908
Answer» a polynomial is an expression CONSIST of CONSTANTS, variables and exponents. Step-by-step explanation: So here, 1, 3 , 5 and 9 are polynomials. HOPE this helps :)

428.

Which of the following expression are polynomial justify i) 4 x square + 6 x - 2 ii) 2 x square + 3/ x - 5 iii) y square - 9 iv) 2 √ X - 4 v) 2 x - -cube + 3 x - 7 vi ) 3 x power x + 2 vii ) 4 x 1/ 2 -3 viii) 3/ 2 x - 1/ 4 ix) 0.0 7 b square - 2.6b + 13. 908

Answer»

a polynomial is an expression CONSIST of CONSTANTS, variables and exponents.

Step-by-step explanation:

So here, 1, 3 , 5 and 9 are polynomials.

HOPE this helps :)

Discussion

429.	What is one piece animetell me fast i will mark as brainlist and thank all answer
Answer» ANSWER: I say U better watch one from these DEATH note bleach naruto attack on Titan TOKYO ghoul fairy tail code geass death parade my HERO academia noblesse jujutsu kaisen.

429.

What is one piece animetell me fast i will mark as brainlist and thank all answer

Answer»

ANSWER:

I say U better watch one from these

DEATH note

bleach

naruto

attack on Titan

TOKYO ghoul

fairy tail

code geass

death parade

my HERO academia

noblesse

jujutsu kaisen.

Discussion

430.	Calculate the area of the circle in m2 if the area of the square is 800 m2. The area of a circle is Pi x r2. Pi can be taken as 22/7
Answer» Answer: 1.for making the text look coloured refer the below SYNTAX and ignore the DOTS [.tex]\red{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:LIKE\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for SHOWING the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\BOXED{thanx}} thanx follow me next

430.

Calculate the area of the circle in m2 if the area of the square is 800 m2. The area of a circle is Pi x r2. Pi can be taken as 22/7

Answer»

Answer:

1.for making the text look coloured refer the below SYNTAX and ignore the DOTS

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:LIKE\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for SHOWING the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\BOXED{thanx}}

thanx

follow me next

Discussion

431.	Divide 25 in two parts such that the difference between their squares is 125.don't spam otherwise I will report ur answer.....
Answer» Answer: (15)^2-(10)^2=225-100=125 so the NUMBERS are 15and 10

431.

Divide 25 in two parts such that the difference between their squares is 125.don't spam otherwise I will report ur answer.....

Answer»

Answer:

(15)^2-(10)^2=225-100=125

so the NUMBERS are 15and 10

Discussion

432.	Sum of two numbers is 95 if one exceeds The Other by 3 find the number
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ Required answer: The TWO numbers are 46 and 49. Given information: Sum of two numbers is 95. ONE exceeds the other by 3. Need to find out: The two numbers is = ? $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$ Let the one NUMBER = X Then, The other number = x + 3 According to the given question: => x + x + 3 = 95 => 2x + 3 = 95 => 2x = 95 - 3 => 2x = 92 => x = 46 So, The number is 46. Therefore, Other number = 46 + 3 = 49 $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$ => 46 + 48 => 95 i.e. the sum of two numbers is 95.

432.

Sum of two numbers is 95 if one exceeds The Other by 3 find the number

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

Required answer:

The TWO numbers are 46 and 49.

Given information:

Sum of two numbers is 95.

ONE exceeds the other by 3.

Need to find out:

The two numbers is = ?

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$

Let the one NUMBER = X

Then,

The other number = x + 3

According to the given question:

=> x + x + 3 = 95

=> 2x + 3 = 95

=> 2x = 95 - 3

=> 2x = 92

=> x = 46

So,

The number is 46.

Therefore,

Other number = 46 + 3 = 49

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$

=> 46 + 48

=> 95

i.e. the sum of two numbers is 95.

Discussion

433.	two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres find the length of its sides
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ Required answer: The lengths of the SIDES are 13 m, 21 m, 21 m. Given Information: Two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres. Need to FIND out: The lengths of the sides = ? $\underline{\underline{\underline{\underline{\mathfrak{\pink{ \:\:\: Explanation:-\:\:\:}}}}}} \\$ Let the third side of the triangle be y metres. Then, The two equal sides will be (2y - 5) m each. According to the problem, Perimeter of ΔABC = AB + BC + CA Perimeter of ΔABC = 55 m Therefore, => 2y - 5 + y + 2y - 5 = 55 =>⠀⠀⠀⠀⠀⠀⠀⠀5y - 10 = 55 => ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 5y = 65 => ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ y = 13 m So, Third side = 13 m => Other two sides = 2 × 13 - 5 => Other two sides = 26 - 5 => Other two sides = 21 m Therefore, The sides are 13 m, 21 m, 21 m $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$ => 13 + 21 + 21 => 13 + 42 => 55 m is the perimeter of ΔABC.

433.

two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres find the length of its sides

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

Required answer:

The lengths of the SIDES are 13 m, 21 m, 21 m.

Given Information:

Two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres.

Need to FIND out:

The lengths of the sides = ?

$\underline{\underline{\underline{\underline{\mathfrak{\pink{ \:\:\: Explanation:-\:\:\:}}}}}} \\$

Let the third side of the triangle be y metres.

Then,

The two equal sides will be (2y - 5) m each.

According to the problem,

Perimeter of ΔABC = AB + BC + CA

Perimeter of ΔABC = 55 m

Therefore,

=> 2y - 5 + y + 2y - 5 = 55

=>⠀⠀⠀⠀⠀⠀⠀⠀5y - 10 = 55

=> ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 5y = 65

=> ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ y = 13 m

So,

Third side = 13 m

=> Other two sides = 2 × 13 - 5

=> Other two sides = 26 - 5

=> Other two sides = 21 m

Therefore,

The sides are 13 m, 21 m, 21 m

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$

=> 13 + 21 + 21

=> 13 + 42

=> 55 m is the perimeter of ΔABC.

Discussion

434.	Write the decimal form of 71 by 8
Answer» ANSWER: 8.875 is the answer...

434.

Write the decimal form of 71 by 8

Answer»

ANSWER:

8.875 is the answer...

Discussion

435.	True or false: -i is an nth root of unity if n is even? PLEASE EXPLAIN
Answer» ANSWER: TRUE! I just TOOK the TEST

435.

True or false: -i is an nth root of unity if n is even? PLEASE EXPLAIN

Answer»

ANSWER:

TRUE! I just TOOK the TEST

Discussion

436.	How to convert 80 cm to dm
Answer» ANSWER: qsw-eyuw-kpx Step-by-step EXPLANATION: fcbnbnbbbv

436.

How to convert 80 cm to dm

Answer»

ANSWER:

qsw-eyuw-kpx

Step-by-step EXPLANATION:

fcbnbnbbbv

Discussion

437.	The 6th and 17th terms of an AP are 21 and 54 respectively .the first term of the AP isA) 6 B) 4C) 3D) 2
Answer»

Discussion

438.	find the smallest whole number by which it should be divided as to get a perfect square also find the square root of the number so obtained as (a)252 ,(b)1008 (c)180 (d)2028 (e) 1458 (f)768
Answer» Step-by-step EXPLANATION: *CORRECT* *ANSWER* is (a) 252 .

438.

find the smallest whole number by which it should be divided as to get a perfect square also find the square root of the number so obtained as (a)252 ,(b)1008 (c)180 (d)2028 (e) 1458 (f)768

Answer»

Step-by-step EXPLANATION:

CORRECT ANSWER is (a) 252 .

Discussion

439.	5x-2y=30Complete the missing value in the solution to the equation.(8, )
Answer»

Discussion

440.	The sum of two numbers is 15 and their quotient is 2
Answer»

Discussion

441.	A piggy bank contains Rs. 370 in the notes of denominations of 10 and 50. If the number of 10 rupee notes is one more than that of 50 rupees notes, find the number of notes of each type.
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ Required ANSWER: Number of 50 rupee notes = 6 Number of 10 rupee notes = 7 Given Information: A piggy bank CONTAINS Rs. 370 in the notes of denominations of 10 and 50. If the number of 10 rupee notes is one more than that of 50 rupees notes. Need to find out: Number of 50 rupee notes = ? Number of 10 rupee notes = ? $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$ LET us suppose the number of 50 rupee notes = y. Then, The number of 10 rupee note = (y + 1) Value of 50 rupee notes = 50 × y Value of 10 rupee notes = 10 × (y + 1) => Total money = 50 × y + 10 × (y + 1) => Total money = 50y + 10y + 10 According to the problem, => 50y + 10y + 10 = 370 => 60Y = 360 => y = 360/60 => y = 6 Therefore, Number of 50 rupee notes = 6 Number of 10 rupee notes = 7 $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$ => Total money = 50 × 6 + 10 × 7 => Total money = 300 + 70 => Total money = Rs 370

441.

A piggy bank contains Rs. 370 in the notes of denominations of 10 and 50. If the number of 10 rupee notes is one more than that of 50 rupees notes, find the number of notes of each type.

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

Required ANSWER:

Number of 50 rupee notes = 6

Number of 10 rupee notes = 7

Given Information:

A piggy bank CONTAINS Rs. 370 in the notes of denominations of 10 and 50. If the number of 10 rupee notes is one more than that of 50 rupees notes.

Need to find out:

Number of 50 rupee notes = ?

Number of 10 rupee notes = ?

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$

LET us suppose the number of 50 rupee notes = y.

Then,

The number of 10 rupee note = (y + 1)

Value of 50 rupee notes = 50 × y

Value of 10 rupee notes = 10 × (y + 1)

=> Total money = 50 × y + 10 × (y + 1)

=> Total money = 50y + 10y + 10

According to the problem,

=> 50y + 10y + 10 = 370

=> 60Y = 360

=> y = 360/60

=> y = 6

Therefore,

Number of 50 rupee notes = 6

Number of 10 rupee notes = 7

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}} \\$

=> Total money = 50 × 6 + 10 × 7

=> Total money = 300 + 70

=> Total money = Rs 370

Discussion

442.	What is the nature of mirror having a gocal length of +10cm
Answer» Answer: A MIRROR having a focal length of +10 cm is a convex mirror(a convex mirror has a positive focal length, ACCORDING to the 'new cartesian SIGN convention'). thanks

442.

What is the nature of mirror having a gocal length of +10cm

Answer»

Answer:

A MIRROR having a focal length of +10 cm is a convex mirror(a convex mirror has a positive focal length, ACCORDING to the 'new cartesian SIGN convention').

thanks

Discussion

443.	present age of Veena's mother is four times veena's age. 5 years hence her mother age will be 21 years more than veena's age. find their present age.
Answer» $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$ REQUIRED answer: Veena's present age = 7 years Mother's present age = 28 years Given INFORMATION: Present age of Veena's mother is FOUR TIMES veena's age. 5 years hence, her mother age will be 21 years more than Veena's age. Need to find out: Veena's present age = ? Mother's present age = ? $\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$ Let present age of Veena = y years Veena's mother's age = 4y years After five years, Veena's age = y + 5 years Mother's age = 4y + 5 years According to the problem, => 4y + 5 = y + 5 + 21 => 3y = 21 => y = 21/3 => y = 7 years Therefore, Veena's present age is 7 years. And, Mother's present age = 7 × 4 Mother's present age is 28 years

443.

present age of Veena's mother is four times veena's age. 5 years hence her mother age will be 21 years more than veena's age. find their present age.

Answer»

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\$

REQUIRED answer:

Veena's present age = 7 years

Mother's present age = 28 years

Given INFORMATION:

Present age of Veena's mother is FOUR TIMES veena's age. 5 years hence, her mother age will be 21 years more than Veena's age.

Need to find out:

Veena's present age = ?

Mother's present age = ?

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Explanation:-\:\:\:}}}}}} \\$

Let present age of Veena = y years

Veena's mother's age = 4y years

After five years,

Veena's age = y + 5 years

Mother's age = 4y + 5 years

According to the problem,

=> 4y + 5 = y + 5 + 21

=> 3y = 21

=> y = 21/3

=> y = 7 years

Therefore,

Veena's present age is 7 years.

And,

Mother's present age = 7 × 4

Mother's present age is 28 years

Discussion

444.	The automobile engine is developing 70 KW power at 4000 rpm. If the gearratio in Ist gear is 3.9: 1, determine input torque of gear box?
Answer» Answer: 57.1? Step-by-step EXPLANATION:

444.

The automobile engine is developing 70 KW power at 4000 rpm. If the gearratio in Ist gear is 3.9: 1, determine input torque of gear box?

Answer»

Answer:

57.1?

Step-by-step EXPLANATION:

Discussion

445.	1 shampoo ka naam.......b h1 Gav ka naam............b h1 Hero ka naam........b h.1 Parwat ka naam........b h.1 word
Answer» Step-by-step EXPLANATION: vatika YA HIMALAYA MERE hisab SE

445.

1 shampoo ka naam.......b h1 Gav ka naam............b h1 Hero ka naam........b h.1 Parwat ka naam........b h.1 word

Answer»

Step-by-step EXPLANATION:

vatika YA HIMALAYA MERE hisab SE

Discussion

446.	Find f x²+1/(x²+2)(x²+3)dx
Answer» Answer: 1.for making the text look coloured refer the below syntax and ignore the dots [.tex]\red{the\:text\:APPEARS\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex]{the\:text\:appears\:like\:this}[./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for SHOWING the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex] no. [./tex]result=[tex] no. \bold{\boxed{THANX}} thanx follow me next

446.

Find f x²+1/(x²+2)(x²+3)dx

Answer»

Answer:

1.for making the text look coloured refer the below syntax and ignore the dots

[.tex]\red{the\:text\:APPEARS\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for SHOWING the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = $\sqrt{no.}no. power$ 5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{THANX}}

thanx

follow me next

Discussion

447.	बिन्दु P(3,-2) की y-अक्ष से दूरी होगा
Answer» Answer: 3 Step-by-step EXPLANATION: y-अक्ष से दूरी होगा 3 इकाई

447.

बिन्दु P(3,-2) की y-अक्ष से दूरी होगा

Answer»

Answer:

3

Step-by-step EXPLANATION:

y-अक्ष से दूरी होगा 3 इकाई

Discussion

448.	Solve and checking 6p+1/3 + 1= 7p-3/2
Answer» Solution: Simplifying the EXPRESSION on L.H.S. of the equation by taking L.C.N., we get $\longrightarrow \sf {\dfrac{6 \: p + 1 + <klux>3</klux>}{3} = \dfrac{7 \: p - 3}{2}} \\\\$ $\longrightarrow \sf {\dfrac{6 \: p + <klux>4</klux>}{3} = \dfrac{7 \: p - 3}{2}} \\\\$ By cross multiplying, we get => 2(6P + 4) = 3(7p - 3) => 12p + 8 = 21P - 9 => 8 + 9 = 21p - 12p => 17 = 9p => 17/9 = p Check: $\sf {For \:p = \dfrac{17}{9}, L.H.S. \:reduces \: to \: \dfrac{ 6\bigg(\dfrac{17}{9 } \bigg) + 1}{3} + 1} \\\\$ $\longrightarrow \sf{ \dfrac{ \dfrac{34}{3} + 1 }{3} + 1 } \\\\$ $\longrightarrow \sf {\dfrac{37}{9} + 1} \\\\$ $\longrightarrow \sf { \dfrac{37 + 9}{9} } \\\\$ $\longrightarrow\sf{ \dfrac{46}{9}} \\\\$ $\longrightarrow \sf{R.H.S. = \dfrac{7 \dfrac{17}{9} - 3 }{2} } \\\\$ $\longrightarrow \sf {\dfrac{ \dfrac{119}{9} - 3 }{2}} \\ \\$ $\longrightarrow \sf { \dfrac{119 - 27}{9 \times 2}} \\\\$ $\longrightarrow \sf { \dfrac{92}{9 \times 2} } \\\\$ $\longrightarrow \sf { \dfrac{46}{9}}$ So L.H.S. = R.H.S. Therefore, p = 17/9 is a solution of the given equation.

448.

Solve and checking 6p+1/3 + 1= 7p-3/2

Answer»

Solution:

Simplifying the EXPRESSION on L.H.S. of the equation by taking L.C.N., we get

$\longrightarrow \sf {\dfrac{6 \: p + 1 + <klux>3</klux>}{3} = \dfrac{7 \: p - 3}{2}} \\\\$

$\longrightarrow \sf {\dfrac{6 \: p + <klux>4</klux>}{3} = \dfrac{7 \: p - 3}{2}} \\\\$

By cross multiplying, we get

=> 2(6P + 4) = 3(7p - 3)

=> 12p + 8 = 21P - 9

=> 8 + 9 = 21p - 12p

=> 17 = 9p

=> 17/9 = p

Check:

$\sf {For \:p = \dfrac{17}{9}, L.H.S. \:reduces \: to \: \dfrac{ 6\bigg(\dfrac{17}{9 } \bigg) + 1}{3} + 1} \\\\$

$\longrightarrow \sf{ \dfrac{ \dfrac{34}{3} + 1 }{3} + 1 } \\\\$

$\longrightarrow \sf {\dfrac{37}{9} + 1} \\\\$

$\longrightarrow \sf { \dfrac{37 + 9}{9} } \\\\$

$\longrightarrow\sf{ \dfrac{46}{9}} \\\\$

$\longrightarrow \sf{R.H.S. = \dfrac{7 \dfrac{17}{9} - 3 }{2} } \\\\$

$\longrightarrow \sf {\dfrac{ \dfrac{119}{9} - 3 }{2}} \\ \\$

$\longrightarrow \sf { \dfrac{119 - 27}{9 \times 2}} \\\\$

$\longrightarrow \sf { \dfrac{92}{9 \times 2} } \\\\$

$\longrightarrow \sf { \dfrac{46}{9}}$

So L.H.S. = R.H.S.

Therefore,

p = 17/9 is a solution of the given equation.

Discussion

449.	2x+3y=12Complete the missing value in the solution to the equation.( ,8)
Answer» ANSWER: HOPE it HELPS you mark as BRAINIEST

449.

2x+3y=12Complete the missing value in the solution to the equation.( ,8)

Answer»

ANSWER:

HOPE it HELPS you

mark as BRAINIEST

Discussion

450.	Twelve large bottles of water cost $9.a. How many bottles can you buy for $3?b. What is the cost per bottle of water?c. How much would 7 bottles of water cost?
Answer» ANSWER: a. 4bottle can be BOUGHT B. 1.333$ C. 9.333

450.

Twelve large bottles of water cost $9.a. How many bottles can you buy for $3?b. What is the cost per bottle of water?c. How much would 7 bottles of water cost?

Answer»

ANSWER:

a. 4bottle can be BOUGHT

B. 1.333$

C. 9.333

Discussion

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A man made a will in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child. rec. The rest was to be shared equally among his four children respectively. What was his wife's share

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