This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
[OH-] in aqueous solution A is = 4.3*10^-4 M and [H3 O+] in aqueous solution of B is 7.3*10^-10 M, pH of which solution will be less ? Which solution will be more basic ? Page 152 Chapter - 7.Acids, Bases and Salts |
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Answer» In any solution the concentration of H+ or OH- ion will always be more than 10–7, SINCE pure water always contains 10–7 mol/LITER of both of H+ and OH- ion. So if the concentration of any ion is LESS than 10–7 mol/ liter the problem should be dealt as above-mentioned. |
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| 2. |
Caclulate the concentration of OH- in aqueous solution having pH value 9.3. Page 152 Chapter - 7.Acids, Bases and Salts |
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Answer» The concentration of OH- in aqueous solution having PH value 9.3 is Explanation:GivenpH = 9.3Therefore,pOH = 14 - 9.3 = 4.7 (∵ pH + pOH = 14)We know thatpOH = -log[OH-]or, [OH-] = 10^(-pOH) = = = Therefore, he concentration of OH- in aqueous solution having pH value 9.3 is HOPE this helps. |
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| 3. |
Calculate pH of an aqueous solution having H3O+ concentration equal to 7.9 * 10 ^-11 M. Which nature, acidic, basic or neutral will be possessed by this aqueous solution. Page 151 Chapter - 7.Acids, Bases and Salts |
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| 4. |
Discuss methods to measure pH of aqueoes solution. Page 152 Chapter - 7.Acids, Bases and Salts |
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Answer» i DONT now about it but i can GIVE you MATTER you can SERCH from it |
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| 5. |
How many times concentrated will be the aqueous solution having pH 11.9 as compared to aqueous solution having pH 8 ? Page 152 Chapter - 7.Acids, Bases and Salts |
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Answer» The aqueous solution having pH 8 is 7937 TIMES more concentrated than the aqueous solution having pH 11.9Explanation:pH of the first aqueous solution = 11.9We KNOW that if is the concentration of the IONS then the pH is given byTherefore the concentration of ions in the aqueous solution of pH 11.9 is The concentration of ions in the aqueous solution of pH 11.9 isTherefore ≈ 7937Therefore, the aqueous solution having pH 8 is 7937 times more concentrated than the aqueous solution having pH 11.9 |
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| 6. |
Give definitions : (i) Arrhenius acid , (ii) Arrhenius base, (iii) Bronsted -Lowry acid, (iv) Bronsted-Lowry base, (v) Concentration of solution , (vi) pH of solution, (vii) pOH of solution, (viii) Strong acid, (ix) Weak acid, (x) Strong base, (xi) Weak base, (xii) Neutralistion reaction, (xiii) 1 M concentration Page 151 Chapter - 7.Acids, Bases and Salts |
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Answer» Explanation:1.an ARRHENIUS acid is a substance that dissociates in water to form HYDROGEN ions or protons.I t INCREASES the number of H+ ions in water.2.an arrhenius base is a substance, when dissolved in AQUEOUS SOLUTION,increases the concentration of hydroxide. |
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| 7. |
Mention the formula, name and physical state of the products of following reactions: (1) CO2 (g) + H2 O(l) -> (2) Li2 (s) + H2O(l) -> (3) H2SO4 (aq) + 2KOH (aq) -> (4) 2HCI(aq)+ Ca(s)-> (5) 2HNO3 (aq)+CaO(s)-> (6) 2HCI(aq)+ Na2 CO3 (aq)-> (7) NaOH (aq) + HCI (aq)-> (8) BaCL2 (aq) + H2SO4(aq)-> (9) Ca(OH)2(aq) + CO2 (g)-> (10) HNO3(aq) + NH4OH(aq) -> (11) Na2SO4 (aq) + Ba(OH)2(aq)-> (12) AgNO3(aq) + NaCI(aq)-> Page 151 Chapter - 7.Acids, Bases and Salts |
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Answer» I Didn't UNDERSTAND your QUESTION |
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| 8. |
Mention names of four methods of expressing concentration of a solution. Page 151 Chapter - 7.Acids, Bases and Salts |
| Answer» TION:kthe ANSER is at LEFT SIDE | |
| 9. |
Which solution will be basic ? A) [H3O+] = 10^-5M B) [H3O+] =10^-12M C) [H3O+] =10^-7M D) [H3O+] =10^-4M Page 150 Chapter - 7.Acids, Bases and Salts |
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Answer» Option (B) Explanation:THEREFORE the concentration of is nothing but the concentration of ionsAlso the PH is given byTherefore the pH VALUE of the given concentration of are as following(A) When (B) When (C) When (D) When The solution with pH value greater than 7 will be basicHere the solution with concentration of being has the HIGHEST pHTherefore it is basic |
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| 10. |
Write a note on Space shuttle. Page 121 Chapter - 6.Universe |
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Answer» A space shuttle is used to go into the space to fix the SATELLITE or telescopes and the shuttle is used to come back the upper one of the rocket is CALLED as shuttle and many other PEOPLE like YURI Gagarin the MAN first into the space and Julie palette entered into the spaceplz follow me and Mark as the brainlist |
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| 11. |
What is remote sensing ? How satellites are useful in remote sensing ? Page 121 Chapter - 6.Universe |
| Answer» TION:In current usage, the term "remote sensing" generally refers to the USE of satellite- or aircraft-based sensor technologies to detect and CLASSIFY objects on Earth, including on the surface and in the atmosphere and oceans, based on PROPAGATED SIGNALS (e.g. electromagnetic radiation). | |
| 12. |
Explain equatorial and polar orbits of artificial satellites. Page 121 Chapter - 6.Universe |
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Answer» A polar Orbits one in which a satellite passes a POLE or nearly above both POLES of the body being ORBITED on each Revolution. It THEREFORE has an inclination Of 90 degree to the body's equator.A satellite in a polar orbit will pass over The equator at a different longitude on each of its orbits. |
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| 13. |
How X-ray astronomy is useful in space exploration ? Page 121 Chapter - 6.Universe |
| Answer» TION:X-ray astronomy is an observational BRANCH of astronomy which deals with the study of X-ray observation and detection from astronomical objects. X-radiation is absorbed by the Earth's ATMOSPHERE, so instruments to detect X-rays must be TAKEN to high altitude by balloons, sounding rockets, and SATELLITES. | |
| 14. |
TICK THE ODD-ONE OUT GIVING REASON- 1. Knife, Mirror, Steel plate, Spoon, Water tap2. Nitrogen, Oil, Air, Steam, Carbon dioxide3. Lustre, Silver, Gold, Wood, Copper4. Limejuice, Chalk powder, Sulphur, Sand5. Acrylic sheet, Ground glass, Glass, CellophaneDEFINE THE FOLLOWING TERMS-1. Soluble substances2. Transparent materials4. Magnetic substance5. Grouping3. Grouping of objects |
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Answer» tion:1. water tap2.oil3. WOOD 4. lime juice 5.cellophanedefine.1. soluble substances = substances that are soluble in water are called soluble substances. 2 . TRANSPARENT MATERIALS = substances which allows light to pass through them are called transparent materials. 3. magnetic materials = materials that allow iron particles to attract are known as magnetic materials. |
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| 15. |
What are the things required to made universe? |
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Answer» The Universe is THOUGHT to consist of three types of SUBSTANCE: normal matter, 'dark matter' and 'dark energy'. Normal matter CONSISTS of the atoms that make up stars, PLANETS, human beings and every other visible OBJECT in the Universe. |
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| 16. |
1. How does measurement help us in our day-to-day life? 2. Which type of watch is used to measure time intervals in a 200 min a 200 metre race3. When do we consider an object to be in motion?4. Name three different types of motions and give one example of each5. State the difference between a periodic and a 'non-periodic' motionE. Answer the following questions. |
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Answer» 1)the measurements is very useful in our day to day life . in such a way in cooking: adding water, adding salt,but these are not a perfect measurements . 2)I think the stopwatch is used to measure Time interval in 200 METER race3)we consider object is moving when the position of an object is CHANGING from one place to another.4) oscillation motion, UNIFORM linear motion,non uniform linear MOTION5)- |
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| 17. |
How to prepare indicator using beetroot |
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Answer» e beetroots and peel them with the HELP of a knife. ...Chop them into pieces.Put those piece into a mixy jar and make a paste.Add some water to the paste. ...Now add 5 to 6 drops of this juice, (beetroot juice (indicator)) to ORANGE juice (5 to 6 drops) and mix it.We can see the COLOUR CHANGES. |
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| 18. |
give question for this activity how to separate healthy seeds from unhealthy seeds with answer at least 5 or 6 question |
| Answer» TION:AIM:to separate HEALTHY seeds from healthy one.required material :seeds, some water , a small container .procedure: keep some water in a container .Now add seeds to it. you will find that some seeds are FLOATING and some had been sink.The seeds which are floating are UNHEALTHY ,eaten and pests and hollow so they are floating above water ,where as seeds which are sink are healthy and can be taken for planting . | |
| 19. |
Explain why wool yeilding animals have thick coat of hair on their body |
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Answer» Wool yielding animals are FOUND in hilly and the COLDER regions. they have THICK coat of hair on their body to protect themselves against the cold climatic CONDITION. Which traps heat in their coat resulting in KEEPING them warm |
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| 20. |
An oxide solution of which of the following elements will turn blue litmus red. S.Mg.Al,Fe,C |
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Answer» carbon will TURN BLUE litmus red as non METAL OXIDES are acidic in nature |
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| 21. |
Give difference between earth-centred and sun-centred models. Page 121 Chapter - 6.Universe |
| Answer» COPERNICUS' model: "Sun-centered," or "heliocentric"Copernicus THOUGHT that the planets orbited the Sun, and that the Moon orbited Earth. The Sun, in the center of the universe, did not move, nor did the stars.The Sun is not in the center of the universe, and it does move, as do the stars.Thanks for the QUESTION. Hope it HELPS you. | |
| 22. |
At the center of which of the following four circular rings has maximum magnetic field while passing equal current through each one ? Page 104 Chapter - 5.Magnetic Effects of Electric Current |
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Answer» hey MATE you have not provided the PICTURE ..we cant ANSWER your this question...hope you can understand. |
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| 23. |
The magnetic field produced in a straight conducting wire on passing the current through it isâ¦â¦â¦â¦ A) in the direction of current. B) in the direction opposite to the current. C) circular around the wire. D) in the direction parallel to the wire. Page 102 Chapter - 5.Magnetic Effects of Electric Current |
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Answer» Reaction of calcium metal with water: Calcium FORMS calcium HYDROXIDE along with hydrogen gas and HEAT when reacts with water. Reaction of magnesium metal with water: Magnesium metal reacts with water SLOWLY and forms magnesium hydroxide and hydrogen gas. |
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| 24. |
Draw the figure of voltaic cell explain its construction. Explain flow of current in conductor through this cell. Page 87 Chapter - 4.Electricity |
| Answer» WORKING Definitions Electrical current is the movement of charged particles, either electrons or ions, through a conductor.A voltaic cell is an ELECTROCHEMICAL cell that uses a chemical reaction to produce electrical energy. The IMPORTANT parts of a voltaic cell:The anode is an electrode whereoxidation occurs.The cathode is an electrode wherereduction occurs.A salt bridge is a chamber of electrolytes necessary to complete the circuit in a voltaic cell.The oxidation and reduction reactions are separated into compartments CALLED half-cells.The external circuit is USED to conduct the flow of electrons between the electrodes of the voltaic cell and usually includes a load.The load is the part of the circuit which utilizes the flow of electrons to perform some function | |
| 25. |
What is a free electron ? Explain conducting and non-conducting materials in terms of it. Page 87 Chapter - 4.Electricity |
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Answer» free electrons are FOUND in the OUTERMOST ORBIT. take part in chemical REACTION |
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| 26. |
Poles of Mars are covered byâ¦â¦â¦ . A)dry-ice B) water-ice C) nitrogen D) iron Page 121 Chapter - 6.Universe |
| Answer» CEXPLANATION:answer HOGA iska chapter me DEKHO | |
| 27. |
When the light entering from glass to water, refractive of water with respect to glasss is 0.9. The angel of incidence at the surface seprating two media is 26o48'. Find the angek of refraction at the surface. Page 47 Chapter - 2.Reflection and Refraction |
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Answer» The ANGLE of refraction at the surface is 30°Explanation:Given, Refractive INDEX of water w.r.t. the glass = 0.9or n = 0.9Angle of incidence i = 26°48'We know that, if n is the refractive index of medium 2 w.r.t to the medium 1 and a RAY of light is passing from medium 1 to medium 2 thenWhere i is the angle of incidence and r is the angle of refractionPutting the valuesTherefore, the angle of refraction at the surface is 30° |
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| 28. |
The ray if light are entering from glass into glycerine . If the absolute refractive indices of glass and glycerine are 1.5 and 1.47 respectively, find the refraction index of glycerine related of glass Page 46 Chapter - 2.Reflection and Refraction |
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Answer» e REFRACTIVE index of medium compared to other medium, We call it as relative refractive index. In other words, Refractive index of medium 2 relative to medium 1 can be given as, ratio of refractive index of medium 2 to medium 1. Given, The RAY if light are entering from glass into GLYCERINE . If the absolute refractive INDICES of glass and glycerine are 1.5 and 1.47 respectively Now, Refractive index of glycerine relative to glass Therefore, Refractive index of glycerine RELATED to glass is 0.98. |
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| 29. |
With the necessary figure, explain the refraction of light throgh a rectangular glass slab. Page 46 Chapter - 2.Reflection and Refraction |
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Answer» rehend the refraction of LIGHT through a glass section consider the FIGURE given underneath which shows the refraction of light through a rectangulaHere in this figure AO is the light beam going in air and occurrence on glass piece at point O. Presently on entering the glass MEDIUM this beam twists towards the ordinary NN' that is light beam AO GETS refracted on entering the glass medium. In the wake of getting refracted this beam currently goes through the glass piece and at call attention to it leaves the glass section as appeared in the figure. Since beam OB goes from glass medium to air it again gets refracted and twists from typical N1N'1 and goes in course BC. Here AO is the occurrence beam and BC is the rising beam and the two of them are parallel to one another and OB is the refracted beam. Rising beam is parallel to occurrence beam on the grounds that the degree of twisting of the beam of light at the contrary parallel faces which are PQ (air-glass interface) and SR (glass-air interface) of the rectangular glass chunk is equivalent and inverse. In the figure I is the edge of rate, r is the point of refraction and e is the edge of rise. Edge of rate and point of rise are equivalent as rising beam and occurrence beam are parallel to one another. At the point when a light beam is episode ordinarily to the interface of two media then there is no twisting of light beam and it goes straight through the medium.r glass sectionExplanation: |
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| 30. |
Explain the construction and working of a compound microscope with a neat ray-diagram. Page 46 Chapter - 2.Reflection and Refraction |
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Answer» Answer: COMPOUND microscope works on the principlethat when a tiny object to be MAGNIFIED is placed just beyond the focus of its objective lens, a virtual, inverted and highly magnified image of the object is formed at the least distance of distinct vision from the EYE held CLOSE to the eye pieceMark as brainliest |
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| 31. |
Give the advantages and disadvantages of series and parellel connecion of resistors. Page 87 Chapter - 4.Electricity |
| Answer» TION: Disadvantage of a series circuit is that if a bulb were broken or the pathway broken in any way, the other bulbs would go out too. Advantages are that you can ADD more power sources, like batteries, and increase the force of the output which grants you more power.Parallel connections have the advantage that any load plugged in gets a predictable VOLTAGE, and the current through the load depends only on that one load. The disadvantage is that parallel wiring is usually lower voltage for SAFETY, but this requires more wire, and a bigger cross SECTIONAL area of copper wire.please follow me !!!!!!!!!! mark me as a brainlist | |
| 32. |
What is called the absolute refractive index of a medium ? Obtain the general from of Snell's law in terms of refractive indicec of two media? Page 45 Chapter - 2.Reflection and Refraction |
| Answer» HOPE it HELPS BUDDY...... | |
| 33. |
The refractive of index of light entering glass from water is 1012. find absolute refractive index of water if the absoute refractive of glass is 1.5 Page 47 Chapter - 2.Reflection and Refraction |
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Answer» The absolute refractive INDEX of WATER is 1.34Explanation:The QUESTION is:The refractive of index of light ENTERING glass from water is 1.12. find absolute refractive index of water if the absoute refractive of glass is 1.5.Solution:GivenRefractive index of glass with respect to water = 1.12We know thatTherefore, or, or, |
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| 34. |
What is called the magnification of an image? Derive the formula of magnification for spherical lens. Page 46 Chapter - 2.Reflection and Refraction |
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Answer» Spherical mirrors are the mirrors having curved surfaces which are painted on ONE of their sides. Spherical mirrors in which inward surfaces are painted are known as convex mirrors while the mirrors in which outward surfaces are painted are known as concave mirrors.spherical mirrorsConcave mirrors are also known as converging mirrors since the rays converge after falling on the concave mirror while, the convex mirrors are known as diverging mirrors as the rays diverge after falling on the convex mirror.Let’s learn about formula and magnification produced by spherical mirrors.Spherical Mirror FormulaThe Mirror formula explains how object distance (u) and image distance (v) are related to the focal length of a spherical mirror. Object distance is the distance of the object from the pole of the mirror; denoted by the letter u. Image distance is the distance of the image from the pole of the mirror and it is denoted by the letter v. And focal length is the distance of the principal focus from the pole of the mirror. The EXPRESSION which gives the relation between these three quantities is CALLED the mirror formula which is given as:1v+1u=1fMirror formula is applicable for all spherical mirrors for every position of the object.Explanation:Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification". When this number is less than one, it refers to a reduction in size, sometimes called minification or de-magnification.Typically, magnification is related to scaling up visuals or images to be ABLE to see more detail, increasing resolution, using microscope, printing techniques, or digital processing. In all cases, the magnification of the image does not change the perspective of the image.Some optical instruments provide visual aid by magnifying small or DISTANT subjects.A magnifying glass, which uses a positive (convex) lens to make things look bigger by allowing the user to hold them closer to their eye.A telescope, which uses its large objective lens or primary mirror to create an image of a distant object and then allows the user to examine the image closely with a smaller eyepiece lens, thus making the object look larger. |
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| 35. |
The absolute refractive indices of water glass amd diamond are 1.77, 1.50 and 2.72 respectively, which medium is most optically denser ? Page 45 Chapter - 2.Reflection and Refraction |
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Answer» : Diamond Explanation Absolute refractive index is the RATIO of speed of LIGHT in vacuum compared to that of speed of light in medium. where, n represents the absolute refractive index, c - speed of light in vacuum ( generally we take it as 3 * 10^8 m/s), v is the speed of light in the medium. Now, Optically rarer or denser medium is DEFINED upon refractive indices. A medium whose refractive index is more than the other is said to be Optically denser than the other. Given, The absolute refractive indices of water glass and diamond are 1.77, 1.50 and 2.72 RESPECTIVELY. The medium with comparatively more refractive index is diamond, and Hence its most optically denser. |
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| 36. |
The compound mirroscopse consists of two convex lenses of 5 cm and 20 cm focal length, then which of them will be object lens and eye piece? Page 45 Chapter - 2.Reflection and Refraction |
| Answer» OBJECTIVE LENGHT have SMALL focal lengtheye piece have LARGER focal length... | |
| 37. |
Explain how the position of an image is located for spherical mirror by considering the different rays using necessray ray-diagrams. Page 46 Chapter - 2.Reflection and Refraction |
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Answer» Ray diagrams are used to depict the image formation by tracing the path of light rays i.e. incident rays and REFLECTED rays. They are drawn in order for anyone to view a point on the image of an object. These ray diagrams depend on the position of the object.General rules for image formation using ray diagrams:Any ray of light that passes through the mirror, is always parallel to the principal axis.Any ray of light that passes through the mirror always passes through the principal focus (f) of the mirror after reflection.A ray of light passing through the center of curvature of any mirror is reflected back along the same path.Any incident ray which isn’t parallel to the principal axis is also reflected diagonally and the incident ray and the reflected ray always follow the laws of reflection i.e. the angles formed by these rays are equal to each other.Ray Diagrams for a Concave MirrorFor a concave mirror, there are six possible positions where the object can be positioned and an image is formed:a. Object is positioned at infinityWhen the object is placed at infinity, rays PQ and RS parallel to the axis are reflected from points Q and S respectively. Rays PQ and RS intersect each other and get CONVERGED at the principal focus (f). And since when the object is placed at infinity, the PROPERTIES of the images formed are highly diminished, point sized and real and inverted.b. Object is positioned between infinity and center of curvature(c)Here the object MN is placed between infinity and center of curvature (c) of a concave mirror, then a ray MP parallel to the principal axis and another ray MQ that pass through the center of curvature(c) intersect each other at M’ after reflection between focus (f) and center of curvature (c). Therefore the properties of the images formed here are that the image formation is between principal focus (f) and center of curvature (c), the image formed is diminished and real and inverted.c. Object is positioned at Center of Curvature (c)d. Object is positioned between the center of curvature (c) and principal focus (f) Object MN is placed between the center of curvature (c) and principal focus (f), then the ray MP parallel to the principal axis and another ray MQ passing through principal focus (f) intersect each other beyond the center of curvature (c) at point M’. Hence the properties of the images formed here are that the image is formed beyond the center of curvature (c), and the image is real and inverted.e. Object is positioned at principal focus (f)Object MN is positioned at the principal focus (f), then ray MP parallel to the principal axis passes through principal focus (f) giving the reflected ray PS. Second ray MQ that passes through the center of curvature is reflected along the same path giving the reflected ray QR. Here, since the rays, PS and QR become parallel to each other and therefore the image formation is at infinity. Here the properties of the images formed are highly enlarged images and real and inverted images.Explanation:The graphical method of locating the image produced by a concave mirror consists of drawing light-rays emanating from key points on the object, and finding where these rays are brought to a focus by the mirror. This task can be accomplished using just four simple rules:An incident ray which is parallel to the principal axis is reflected through the focus $F$ of the mirror.An incident ray which passes through the focus $F$ of the mirror is reflected parallel to the principal axis.An incident ray which passes through the centre of curvature $C$ of the mirror is reflected back along its own path (since it is normally incident on the mirror).An incident ray which strikes the mirror at its vertex $V$ is reflected such that its angle of INCIDENCE with respect to the principal axis is equal to its angle of reflection.The validity of these rules in the paraxial approximation is fairly self-evident.Consider an object $ST$ which is placed a distance $p$ from a concave spherical mirror, as shown in FIG. 71. For the sake of definiteness, let us suppose that the object distance $p$ is greater than the focal length $f$ of the mirror. Each point on the object is assumed to radiate light-rays in all directions. Ray Diagrams for Spherical Mirrors. This Demonstration lets you visualize the ray diagrams for concave and convex spherical mirrors. By manipulating the object and mirror locations, you can create real or virtual images. The ray parallel to the principal axis and the ray that hits the center of the mirror are drawn. |
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| 38. |
What is meant by parasitic plant with their different types with example of each |
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Answer» Parasitic plants are those plants which dependent on other SOURCES or plant for their food and nutrition also CALLED HETEROTROPH..eglike cuscuta, VENUS fly trap, Amar bell, etc |
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| 39. |
Write the step making coton fabric from fibre step by step |
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Answer» inning: The cotton picked up from the plants has SEEDS in it. Spinning: The process of making YARN from fibre is called spinning. Weaving: The process of arranging TWO SETS of yarn together to make a fabric is called weaving. Knitting: Knitting can be done by hand and MACHINE. |
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| 40. |
If the absolute refractive indicec of water and glass are 4/3 and 3/2 respectively, then what will be the ratio of velocity of light in water to that of glass ? Page 45 Chapter - 2.Reflection and Refraction |
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Answer» 9/8Explanation: Refractive INDEX can be DEFINED as the ratio of the SPEED of light in vacuum and the speed of light in that particular medium.RI(glass) = 3/2C/v(glass) = 3/2 --- (1)RI(WATER) = 4/3C/v(water) = 4/3 --- (2)Dividing (1) by (2)v(water) / v(glass) = 9/8 |
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| 41. |
Throught which of the following points, a ray passing throught a centre of curvature and reflected by concave mirror will pass through ? Page 44 Chapter - 2.Reflection and Refraction |
| Answer» CENTRE of CurvatureExplanation:The point at the center of the sphere from which the MIRROR is cut is known as the center of curvature.When a ray of LIGHT travels through the CONCAVE mirror's curvature center, it happens at 90 ° on the mirror. Therefore, the ray incident coincides with the normal and follows its direction. For example, a concave surface reflected ray would pass through the centre of curvature. | |
| 42. |
If the absolute refractive indeices of water, benzene, and saphire are 1.33,1.50and 1.77 respectively, then which medium has maximum relative refractive index ? Page 44 Chapter - 2.Reflection and Refraction |
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Answer» efractive index of WATER w.r.t diamond = 1.33/2.42=0.54RI of refractive index of diamond w.r.t BENZENE =2.42/1.50=1.6133Diamond{water}>diamond {benzene} |
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| 43. |
Einstein tried his best to reach the reality, but he got success only to some extent |
| Answer» YES it is TRUE DEAR MATE....✔✔✔ | |
| 44. |
1. Food should always be kept covered |
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Answer» Yes, FOOD should ALWAYS be kept covered to PREVENT from GERMS and INSECTS as they can make the food spoil and disgusting to eat. |
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| 45. |
Dry HCL strip is not an acid but molten HCL is an acid justify |
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Answer» Dry HCL doesn't CONTAINS any HYDROXIDE ION active but molten HCl contains. |
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| 46. |
Which ions are generated by bases in water |
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Answer» tion:HYDROXIDE IONSwhen bases are added in water(H²O)...they generally ioniseit is the property of a BASIC substance to ionize hydroxide IONS when dissolved in waterfor EXAMPLE,NaOH + H²O = Na+ + OH²-hope you liked my ANSWER.....plz mark as brainliest....plz smash the THANKS button....FOLLOW ME! |
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| 47. |
Solve the following equation by substitution method. 3x/ 2 - 5y/ 3 = -2 and x/ 3 + y/ 2 = 13 /6 |
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Answer» 3x/2-5y/3=-2. × 2/9X/3-10y/27=-4/9. EQ- 1given,X/3=13/16-y/2put in eq- 113/16-y/2-10y/27=-4/913/16-47y/54=-4/9-47y/54=-4/9-13/16-47y/54=-181/144so,y=181/144×54/47 |
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| 48. |
Einstein's theory of relativity is somewhat wrong who agree with me????????? |
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Answer» with you ........................ |
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| 50. |
Explain parallax method. |
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Answer» Hey mate take an object and PUT it Infront of EYE and look it with ONE eye open and other close.Then again change the eye means close the opened eyes and open the CLOSED eye,you will see that there will be a some difference in position of the object.This is parallax.hope it will help you....!!!! |
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