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1.

On diving `0.46` by `15.374`, the atual answer is `0.029236`. The correctly reported answer will beA. `0.02`B. `0.029`C. `0.0292`D. `0.02924`

Answer» Correct Answer - B
Discussion
2.

Match the following `{:("(i)","88 g of CO"_(2),"(a)","0.25 mol"),("(ii)",6.022 xx 10^(23)" molecules of "H_(2)O,"(b)","2 mol"),("(iii)","5.6 litres of O"_(2)" at STP","(c)","1 mol"),("(iv)","96 g of O"_(2),"(d)",6.022xx10^(23)"molecules"),("(v)","1 mole of any gas","(e)","3 mol"):}`A. i-a,ii-b,iii-d,iv-c,v-eB. i-b,ii-c,iii-a,iv-e,v-dC. i-c,ii-b,iii-d,iv-d,v-eD. i-d,ii-e,iii-a,iv-b,v-b

Answer» Correct Answer - B
Discussion
3.

In Balancing the reaction `XZn + NO_(3)^(-) +YH^(+) rarr XZn^(2+)+NH_(4)^(+) + ZH_(2)O, XY` & Z areA. 4,10,3B. 3,8,3C. 3,10,3D. 4,3,10

Answer» Correct Answer - A
Discussion
4.

2.16 grams of Cu on reaction with `HNO_(3)` followed by ignition of the nitrate gave 2.7 gm of copper oxide. In another experiment 1.15 gm of copper oxide upon reduction with hydrogen gave 0.92 gm of copper. This data illustrate the law ofA. Multiple ProportionsB. Definite ProportionsC. Reciprocal proportionsD. Conservation of mass

Answer» Correct Answer - B
Discussion
5.

Irrespective of the source, pure sample of water always yields `88.89%` mass of oxygen and `11.11%` mass of hydrogen. This is explained by the law ofA. Conservation of massB. Constant proportionsC. Multiple proportionsD. Constant volume

Answer» Correct Answer - B
Discussion
6.

The mass of nitrogen per gram in hydrazine is exactly one and half the mass of nitrogen in the compound ammonia. The fact illustrates theA. Law of conservation of massB. Multiple valency of nitrogenC. Law of multiple proportionD. Law of definite Portin

Answer» Correct Answer - C
Discussion
7.

Which of the following statements indicates that law of multiple proportion is being followed?A. Sample of carbon dioxide taken from any source will always have carbon and oxygen in the ratio 1:2B. Carbon forms two oxides namely `CO_(2)` and `CO` where masses of oxygen which combine with fixed mass of carbon are in the simple ratio 2:1C. When magnesium burns in oxygen, the amount of magnesium taken for the reaction is equal to the amount of magnesium in magnesium oxide formedD. At constant temperature and pressure 200 mL of hydrogen will combine with 100 mL oxygen to produce 200 mL of water vapour.

Answer» Correct Answer - B
Discussion
8.

Statement Addition of water to a solution containing solute and solvent changes its normality or molarity only. Explanation The milli-equivalent and milli-moles of solutes are not changed on dilution.A. Statement -1 is True, Statement -2 is True, Statement -2 is a correctB. Statement -1 is True, Statement -2 is True, statement -2 is NOT a correct explanation for Statement-6C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True

Answer» Correct Answer - A
Discussion
9.

What will be the molality of the solution containing 18.25 g of HCl gas in 500 g of water?A. 0.1mB. 1MC. 0.5mD. 1m

Answer» Correct Answer - D
Discussion
10.

The empirical formula and molecule mass of a compound are `CH_(2)O` and 180g respectivel. What will be the molecular formula of the compound?A. `C_(9)H_(18)O_(9)`B. `CH_(2)O`C. `C_(6)H_(12)O_(6)`D. `C_(2)H_(4)O_(2)`

Answer» Correct Answer - C
Discussion
11.

Which of the following terms are unitless?A. MolalityB. MolarityC. Mole fraction & Mass percentD. Normality

Answer» Correct Answer - C
Discussion
12.

Which of the following solutions have the same concentration?A. 20g of `NaOH` in 200mL of solutionB. 0.5 mol of `NaCI` in `200mL` of solutionC. 40g of `NaOH` in `100mL` of solutionD. 20g of `KOH` is `200mL` of solution

Answer» Correct Answer - A
Discussion
13.

Which of the following pairs have the same number of atoms?A. 16g of `O_(2)(g)` and 4g of `H_(2)(g)`B. 16g of `O_(2)` and 44g of `CO_(2)`C. 28g of `N_(2)` and 32g of `O_(2)`D. 24g of `C(s)` and 23g of `Na(s)`

Answer» Correct Answer - C
Discussion
14.

Sulphuric acid reacts with sodium hydroxide as follows `H_(2)SO_(4)+2NaOHrarrNa_(2)SO_(4)+2H_(2)O` when 1L of 0.1M sulphuric acid solution is allowed to react with 1L of 0.1M sodium hydroxide solution, the amount of sodium solphate formed and its molarity in the solution obtained isA. `0.1 mol L^(-1)`B. `7.10g, 0.025 mol L^(-1)`C. `0.025M`D. `3.55 g`

Answer» Correct Answer - B
Discussion