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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Vivek Travelled 1200km By Air Which Formed 2/5 Of His Trip. One Third Of The Whole Trip, He Travelled By Car And The Rest Of The Journey He Performed By Train. The Distance Travelled By Train Was? |
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Answer»
We know that 2X/5 = 1200 km X = 1200*5/2 = 3000 km Distance travelled by car = 1/3*3000 = 1000km JOURNEY by TRAIN = [3000-(1200+1000)] = 800km. Let the total trip be X km. We know that 2X/5 = 1200 km X = 1200*5/2 = 3000 km Distance travelled by car = 1/3*3000 = 1000km Journey by train = [3000-(1200+1000)] = 800km. |
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| 2. |
A Goat Is Tied To One Corner Of A Square Plot Of Side 12m By A Rope 7m Long. Find The Area It Can Graze? |
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Answer»
here we DIVIDE by 4 because rope is tied at the corner of the plot and only 1/4 PART, the goat can graze Where length of rope r = 7 m. A = πr2 / 4 A = 1/4(area of circle) A = ¼ [(22/7)*7*7] A = 38.5 Area covered by goat A = πr2 here we divide by 4 because rope is tied at the corner of the plot and only 1/4 part, the goat can graze Where length of rope r = 7 m. A = πr2 / 4 A = 1/4(area of circle) A = ¼ [(22/7)*7*7] A = 38.5 |
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| 3. |
A Boat Travels 20 Km Upstream In 4 Hours And 18 Km Downstream In 6 Hours. Find The Speed Of The Boat In Still Water? |
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Answer» RATE DOWNSTREAM= 20 /4 = 5 kmph Rate upstream= 18 / 6 = 3 kmph Speed in still water = 1/2 (5 + 3) = 4 kmph. Rate downstream= 20 /4 = 5 kmph Rate upstream= 18 / 6 = 3 kmph Speed in still water = 1/2 (5 + 3) = 4 kmph. |
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| 4. |
If 10x Coins Are Added To The Number Of Original Coins He Has (5y + 1) Times More Coins. Find Out How Many Coins He Had Originally In Terms Of X And Y? |
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Answer» 2X / y Explanation: Let’s take `z` as the ORIGINAL NUMBER of coins. We KNOW that 10X + z = (5y + 1) z i.e.10x + z = 5yz + z 10x/5y = z z = 2x/y. 2x / y Explanation: Let’s take `z` as the original number of coins. We know that 10x + z = (5y + 1) z i.e.10x + z = 5yz + z 10x/5y = z z = 2x/y. |
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| 5. |
To 15 Liters Of Water Containing 20% Alcohol, We Add 5 Liters Of Pure Water. What Is % Alcohol? |
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Answer» Case 1: Initial QUANTITY of Water = 15 LITRES Quantity of ALCOHOL = 20% = (20/100) * 15 = 3 litres Case 2: Quantity of Water after adding 5 litres of water = 15 + 5 = 20 litres There of the % of alcohol in water = (3 /20) * 100 = 15%. Case 1: Initial quantity of Water = 15 litres Quantity of Alcohol = 20% = (20/100) * 15 = 3 litres Case 2: Quantity of Water after adding 5 litres of water = 15 + 5 = 20 litres There of the % of alcohol in water = (3 /20) * 100 = 15%. |
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| 6. |
There Are 6 Red Shoes & 4 Green Shoes. If Two Of Red Shoes Are Drawn Randomly What Is The Probability Of Getting Red Shoes? |
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Answer» Total number of shoes=6 + 4=10; let S be the sample space. Then, n(s) = Number of WAYS of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45 Let E = EVENT of drawing 2 shoes which are red. THEREFORE n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3. Total number of shoes=6 + 4=10; let S be the sample space. Then, n(s) = Number of ways of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45 Let E = Event of drawing 2 shoes which are red. Therefore n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3. |
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| 7. |
Find Out The Simple Interest Paid For A Sum Of Rs. 4000 At The Rate Of 8% Per Annum For 3 Months? |
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Answer» The simple interest formula is Interest = PRINCIPAL × Rate × Time I = P×R×T Where: 'Interest' is the TOTAL amount of interest paid, 'Principal' is the amount LENT or borrowed, 'Rate' is the PERCENTAGE of the principal charged as interest each year. The rate is expressed as a decimal fraction, so percentages MUST be divided by 100. 'Time' is the time in years of the loan. S.I = P×R×T S.I. = Rs. 4000 * 8% * 3 months S.I. = 4000* 8 /100 * 3/12 S.I. = 80. The simple interest formula is Interest = Principal × Rate × Time I = P×R×T Where: 'Interest' is the total amount of interest paid, 'Principal' is the amount lent or borrowed, 'Rate' is the percentage of the principal charged as interest each year. The rate is expressed as a decimal fraction, so percentages must be divided by 100. 'Time' is the time in years of the loan. S.I = P×R×T S.I. = Rs. 4000 * 8% * 3 months S.I. = 4000* 8 /100 * 3/12 S.I. = 80. |
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| 8. |
Pipe A Can Fill A Tank In 20 Minutes And Pipe B In 30 Minutes Respectively. Pipe C Can Empty The Same In 40 Minutes. If All The Three Pipes Are Opened Together, Find The Time Taken To Fill The Tank? |
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Answer» NET PART filled in 1 hour = ( 1/20 – 1/30 – 1/40) = 7 / 120 THEREFORE TANK will be filled in = 120/7 = 17 1/7 minutes. Net part filled in 1 hour = ( 1/20 – 1/30 – 1/40) = 7 / 120 Therefore tank will be filled in = 120/7 = 17 1/7 minutes. |
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| 9. |
A Man Is Standing On A Railway Bridge Which Is 180m Long. He Finds That A Train Crosses The Bridge In 20seconds And Him In 8 Seconds. Find The Length Of The Train And Its Speed? |
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Answer» LET the length of the train be X meters Then, the train COVERS x meters in 8 seconds and (x + 180) meters in 20 seconds. Therefore x/8 = (x+180)/20 <=> 20x = 8(x+180) <=> x = 120 Therefore Length of the train = 120m Speed of the train = 120/8 m/sec = 15 m/sec =15 * 18/5 kmph = 54KMPH. Let the length of the train be x meters Then, the train covers x meters in 8 seconds and (x + 180) meters in 20 seconds. Therefore x/8 = (x+180)/20 <=> 20x = 8(x+180) <=> x = 120 Therefore Length of the train = 120m Speed of the train = 120/8 m/sec = 15 m/sec =15 * 18/5 kmph = 54kmph. |
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| 10. |
A Is Twice As Good A Workman As B And Together They Finish A Piece Of Work In 18 Days. In How Many Days Will A Alone Finish The Work? |
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Answer» If A takes x DAYS to do a work then B takes 2X days to do the same work = > 1/x+1/2x = 1/18 = > 3/2x = 1/18 = > x = 27 days. HENCE, A alone can finish the work in 27 days. If A takes x days to do a work then B takes 2x days to do the same work = > 1/x+1/2x = 1/18 = > 3/2x = 1/18 = > x = 27 days. Hence, A alone can finish the work in 27 days. |
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| 11. |
A Retailer Buys A Radio For Rs.225. His Overhead Expenses Are Rs.15 And He Sells The Radio For Rs.300. What Is The Profit Percent Of The Retailer? |
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Answer» Selling price = COST price + profit Cost price = 225 + 15 = 240 i.e. 240 + X * 240 * 1/100 = 300 240 + 24X/ 10 = 300 (taking LCM) 2400 + 24X = 3000 24 X = 3000 - 2400 24X = 600 X = 600/ 24 X = 25. Selling price = cost price + profit Cost price = 225 + 15 = 240 i.e. 240 + X * 240 * 1/100 = 300 240 + 24X/ 10 = 300 (taking LCM) 2400 + 24X = 3000 24 X = 3000 - 2400 24X = 600 X = 600/ 24 X = 25. |
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| 12. |
The Cost Of An Item Is Rs 12.60. If The Profit Is 10% Over Selling Price. What Is The Selling Price? |
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Answer» We KNOW that SELLING PRICE = COST price + profit Cost Price = 12.60 Profit = 10% of CP = (10 / 100) * 12.60 = 126 /100 Profit = 1.26 Selling Price = CP + Profit = 12.60 + 1.26 Selling Price = 13.86. We know that Selling price = cost price + profit Cost Price = 12.60 Profit = 10% of CP = (10 / 100) * 12.60 = 126 /100 Profit = 1.26 Selling Price = CP + Profit = 12.60 + 1.26 Selling Price = 13.86. |
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| 13. |
It Takes 6 Technicians 10 Hours To Build And Program A New Server From Direct Computer, With Each Working At The Same Rate. If Six Technicians Start To Build The Server At 11:00 Am, And One Technician Per Hour Is Added Beginning At 5:00 Pm, At What Time Will The Server Be Complete? |
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Answer» TOTAL time required to complete job is 6 * 10 = 60 HOURS Work completed between 11am to 5pm by 6 TECHNICIAN = (6 * 6) = 36 hours So remaining work = (60 - 36) = 24 hours Remaining work between 5pm to 6pm = 24 -7 = 17 hours. Similarly work completed between 6pm to 7 pm = 17 – 8 = 9 hours, which is completed in next one hour i.e. Job is complete at 8.00PM. Total time required to complete job is 6 * 10 = 60 hours Work completed between 11am to 5pm by 6 technician = (6 * 6) = 36 hours So remaining work = (60 - 36) = 24 hours Remaining work between 5pm to 6pm = 24 -7 = 17 hours. Similarly work completed between 6pm to 7 pm = 17 – 8 = 9 hours, which is completed in next one hour i.e. Job is complete at 8.00PM. |
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| 14. |
Don And His Wife Each Receive An 8 Percent Annual Raise. If Don Receives A Raise Rs.800 And His Wife Receives A Raise Of Rs. 840, What Is The Difference Between Their Annual Incomes After Their Raises? |
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Answer» 8% is 800 hence 100% = 10,000 for Don. 8% is 840 hence 100% = 10,500 for his WIFE. After RAISE Don SALARY = 10,000+800 = 10,800 and his wife salary is 10,500+840. Difference is 11,840-10,800 = 540. 8% is 800 hence 100% = 10,000 for Don. 8% is 840 hence 100% = 10,500 for his wife. After raise Don salary = 10,000+800 = 10,800 and his wife salary is 10,500+840. Difference is 11,840-10,800 = 540. |
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| 15. |
A Worker Is Paid Rs.20/- For A Full Day’s Work. He Works 1, 1/3, 2/3, 1/8, 3/4 In A Week. What Is The Total Amount Paid For That Worker? |
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Answer» Number of DAYS WORKED in a week =1+1/3+2/3+1/8+3/4 = (24 +8 + 16 + 3+ 18)/ 24 = 69/ 24 =23/8 days Total amount paid = 23/8 * 20= 57.50 Rs. Number of days worked in a week =1+1/3+2/3+1/8+3/4 = (24 +8 + 16 + 3+ 18)/ 24 = 69/ 24 =23/8 days Total amount paid = 23/8 * 20= 57.50 Rs. |
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| 16. |
An Investor Purchased Shares Of Stock At A Certain Price. If The Stock Increased In Price Rs 0.25 Per Share And The Total Increase For The X Shares Was Rs 12.50, How Many Shares Of Stock Had Been Purchased? |
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Answer»
be the COST of each SHARE and x is the no of shares c.p. = x Rs. for x shares If 0.25 Rs. is increased in each share Then (1+.25) x = 12.50+x 1.25x = 12.50+x 0.25x =12.50 x = 12.50/0.25 => x =50 Therefore number of shares=50. Let 1 Rs. be the cost of each share and x is the no of shares c.p. = x Rs. for x shares If 0.25 Rs. is increased in each share Then (1+.25) x = 12.50+x 1.25x = 12.50+x 0.25x =12.50 x = 12.50/0.25 => x =50 Therefore number of shares=50. |
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| 17. |
One Bottle Is Half-full Of Oil And Another Bottle With Twice The Capacity Is One Quarter Full Of Oil. If Water Is Added So That Both The Bottles Are Full And The Contents Of Both Are Then Poured Into A Third Bottle That Is Empty And Large Enough To Hold The Contents Of Both, What Fractions Of The Contents In The Third Bottle Is Oil? |
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Answer» Capacity of 1st bottle =100 LITRES QUANTITY of Oil=50 litres & Water=50 litres Capacity 2ND bottle =200 litres Quantity of Oil=50 litres & Water=150 litres Capacity of 3rd bottle = 300 litres Quantity of Oil=100 litres & Water = 200 litres The fraction of the oil contents in the third bottle is = 100 / (100+200) = 1/3. Capacity of 1st bottle =100 litres Quantity of Oil=50 litres & Water=50 litres Capacity 2nd bottle =200 litres Quantity of Oil=50 litres & Water=150 litres Capacity of 3rd bottle = 300 litres Quantity of Oil=100 litres & Water = 200 litres The fraction of the oil contents in the third bottle is = 100 / (100+200) = 1/3. |
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| 18. |
A, B And C Contract A Work For Rs.550. Together A And B Are Supposed To Do 7/11 Of The Work. How Much Does C Get? |
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Answer» Let the total WORK = 1 i.e. A + B+C =1 A and B will complete 7/11 of work. Remaining work => C = 1- (7/11) = 4/11 Therefore SALARY received by C = (4/11)*550 = RS. 200. Let the total work = 1 i.e. A + B+C =1 A and B will complete 7/11 of work. Remaining work => C = 1- (7/11) = 4/11 Therefore salary received by C = (4/11)*550 = Rs. 200. |
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| 19. |
The Ratio Of Roses And Lilies In A Garden Is 3: 2 Respectively. The Average Number Of Roses & Lilies Is 180. What Is The Number Of Lilies In The Garden? |
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Answer» Let the number of so be ‘3x’ and the number of lilies be 2x Average number of roses and lilies = (3x + 2x)/2 = 2.5x A.T.Q 2.5x = 180, X = 72 Number of lilies = 2x = 144. Let the number of so be ‘3x’ and the number of lilies be 2x Average number of roses and lilies = (3x + 2x)/2 = 2.5x A.T.Q 2.5x = 180, x = 72 Number of lilies = 2x = 144. |
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| 20. |
Abhijit Invested An Amount With Company X For Two Years @ Simple Interest Rate 15 P.c.p.a. The Entire Amount Obtained From Company X After Two Years He Invested With Company Y @ Compound Interest Rate 12 P.c.p.a For Two Years. If The Amount Finally Received By Him Was Rs. 81,536. Find The Money Invested By Abhijit In Company X? |
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Answer» LET ‘y’ be the INVESTED AMOUNT A.T.Q. 1.3y(1.12)2=81536 On SOLVING y=Rs.50,000/- Let ‘y’ be the invested amount A.T.Q. 1.3y(1.12)2=81536 On Solving y=Rs.50,000/- |
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| 21. |
Some Chocolates Were Distributed Among 4 Friends A, B, C And D Such That Respective Ratio Of Chocolates Received By A To Chocolates Received By C Was 7:9. B Received 29 More Chocolates Than A And D Received 33 More Chocolates Than C. If B Received 15 More Chocolates Than C, How Many Chocolates Did D Receive? |
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Answer» A=7x, C=9x, B=7x+29, D=9x+33 A.T.Q. 29 + 7x =15+9x ∴ D RECEIVED 96 CHOCOLATES A=7x, C=9x, B=7x+29, D=9x+33 A.T.Q. 29 + 7x =15+9x ⇒ x = 7 ∴ D received 96 chocolates |
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| 22. |
Raghuvir Purchased 10 Calculators And 16 Watches For Rs. 56,100/- And Sold Them So As To Earn An Overall Profit Of 20%. At What Total Price Should He Sell 15 Calculators And 24 Watches Together So As To Earn The Same Percent Profit? |
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Answer» CP of 10 CALCULATORS , 16 watches =Rs.56100/- CP of 15 calculators, 24 watches=1.5×56100=84150/- Profit=20% ∴S.P. of 15 calculators, 24 watches =1.2×84150 = Rs. 100,980/- CP of 10 calculators , 16 watches =Rs.56100/- CP of 15 calculators, 24 watches=1.5×56100=84150/- Profit=20% ∴S.P. of 15 calculators, 24 watches =1.2×84150 = Rs. 100,980/- |
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| 23. |
The Length Of A Rectangle Exceeds Its Breadth By 6m. Length Of The Rectangle Is Equal To The Side Of A Square Whose Area Is 729 Sq. M. What Is The Perimeter Of The Rectangle? (in M) |
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Answer» Let ‘l’ be the LENGTH, ‘B’ be the breadth of the rectangle. Length of the rectangle =Side of the SQUARE of area 729m2 ∴ Length of the rectangle =27m. A.T.Q. l-b=6 ⇒ b = l - 6 = 21m ⇒ l = 27m Perimeter of the rectangle = 2 (l + b) = 2 (27 + 21) = 96m Let ‘l’ be the length, ‘b’ be the breadth of the rectangle. Length of the rectangle =Side of the square of area 729m2 ∴ Length of the rectangle =27m. A.T.Q. l-b=6 ⇒ b = l - 6 = 21m ⇒ l = 27m Perimeter of the rectangle = 2 (l + b) = 2 (27 + 21) = 96m |
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| 24. |
Mixed 36 Kg Of Sugar @ Rs. 45/- Per Kg And 24 Kg Of Sugar @ Rs. 48/- Per Kg And Sold The Mixture As To Earn 20% Profit. At What Rate Per Kg Must He Sell The Sugar? |
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Answer» Total cost price=36×45+24×48=2772/- AVERAGE cost price PER KG = 2772/60 = Rs. 46.2 S.P=Rs 55.44 per kg( @20% profit). Total cost price=36×45+24×48=2772/- Average cost price per kg = 2772/60 = Rs. 46.2 S.P=Rs 55.44 per kg( @20% profit). |
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| 25. |
156.25 × 12.4 + 1.8 × 52.5 = ? – 175.85 |
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Answer» 156.25×12.4+1.8×52.5=?-175.85 1937.5+94.5=?-175.85 2032=?-175.85 ?=2207.85 156.25×12.4+1.8×52.5=?-175.85 1937.5+94.5=?-175.85 2032=?-175.85 ?=2207.85 |
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