There Are 6 Red Shoes & 4 Green Shoes. If Two Of Red Shoes Are Drawn

1.	There Are 6 Red Shoes & 4 Green Shoes. If Two Of Red Shoes Are Drawn Randomly What Is The Probability Of Getting Red Shoes?
Answer» Total number of shoes=6 + 4=10; let S be the sample space. Then, n(s) = Number of WAYS of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45 Let E = EVENT of drawing 2 shoes which are red. THEREFORE n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3. Total number of shoes=6 + 4=10; let S be the sample space. Then, n(s) = Number of ways of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45 Let E = Event of drawing 2 shoes which are red. Therefore n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3.

There Are 6 Red Shoes & 4 Green Shoes. If Two Of Red Shoes Are Drawn Randomly What Is The Probability Of Getting Red Shoes?

Answer»

Total number of shoes=6 + 4=10;

let S be the sample space.

Then, n(s) = Number of WAYS of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45

Let E = EVENT of drawing 2 shoes which are red.

THEREFORE n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3.

Total number of shoes=6 + 4=10;

let S be the sample space.

Then, n(s) = Number of ways of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45

Let E = Event of drawing 2 shoes which are red.

Therefore n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3.