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51.

Find the values of Z11, Z22, Z33 in the circuit shown below.(a) (4+j3) Ω, (3-j2) Ω, (5-j5) Ω(b) (4+j3) Ω, (3+j2) Ω, (5-j5) Ω(c) (4-j3) Ω, (3-j2) Ω, (5-j5) Ω(d) (4+j3) Ω, (3-j2) Ω, (5+j5 ) ΩI got this question in an international level competition.This question is from Mesh Analysis topic in chapter Steady State AC Analysis of Network Theory

Answer» RIGHT choice is (b) (4+j3) Ω, (3+j2) Ω, (5-j5) Ω

Explanation: Z11 = self IMPEDANCE of loop 1 = (4 + j3) Ω. Z22 = self impedance of LOOP2 = (j3+3+j4-j5) Ω. Z33 = self impedance of loop 3 = (-j5+5) Ω.
Discussion
52.

Find Z31, Z32, Z33 in the circuit shown below.(a) 0Ω, j6Ω, (4-j6) Ω(b) 0Ω, -j6Ω, (4+j6) Ω(c) 0Ω, -j6Ω, (4-j6) Ω(d) 0Ω, j6Ω, (4+j6) ΩThis question was addressed to me in an interview for internship.I would like to ask this question from Mesh Analysis topic in division Steady State AC Analysis of Network Theory

Answer»

The correct ANSWER is (a) 0Ω, j6Ω, (4-j6) Ω

The best I can EXPLAIN: Z31 = common IMPEDANCE to loop 3 and loop 1 = 0 Ω. Z32 = common impedance between loop3 and loop 2 = – (-j6) Ω. Z33 = self impedance of loop 3 = (4-j6) Ω.
Discussion
53.

Determine Z21, Z22, Z23 in the circuit shown below.(a) 5Ω, (5-j1) Ω, j6 Ω(b) -5Ω, (5-j1) Ω, j6 Ω(c) -5Ω, (5+j1) Ω, j6 Ω(d) -5Ω, (5-j1) Ω, – j6 ΩThe question was asked in quiz.My question is from Mesh Analysis in portion Steady State AC Analysis of Network Theory

Answer»

The correct option is (b) -5Ω, (5-j1) Ω, j6 Ω

The best I can explain: Z21 = common impedance to LOOP 1 and loop 2 = -5 Ω. Z22 = self impedance of loop2 = (5+j5-j6) Ω. Z23 = common impedance between loop2 and loop 3 = – (-j6) Ω.
Discussion
54.

Find Z11, Z12, Z13 obtained from the mesh equations in the circuit shown below.(a) (8+j4) Ω, 5 Ω, 0Ω(b) (8-j4) Ω, 5 Ω, 0Ω(c) (8+j4) Ω, – 5 Ω, 0Ω(d) (8-j4) Ω, -5 Ω, 0ΩThis question was posed to me in unit test.My enquiry is from Mesh Analysis in division Steady State AC Analysis of Network Theory

Answer» CORRECT CHOICE is (d) (8-j4) Ω, -5 Ω, 0Ω

Best EXPLANATION: Z11= self impedance of LOOP 1 = (5 + 3 – j4) Ω. Z12 = Impedance common to both loop 1 and LOOP2 = -5Ω. Z13 = No common impedance between loop1 and loop 3 = 0Ω.
Discussion
55.

Determine the current I1 in the circuit shown below using mesh analysis.(a) 0.955∠-69.5⁰(b) 0.855∠-69.5⁰(c) 0.755∠-69.5⁰(d) 0.655∠-69.5⁰I had been asked this question in examination.My question is based upon Mesh Analysis topic in chapter Steady State AC Analysis of Network Theory

Answer» CORRECT option is (b) 0.855∠-69.5⁰

Explanation: The equation for loop 1 is I1(j4) + 6(I1-I2) = 5∠0⁰. The equation for loop 2 is 6(I1-I2) + (j3) I2 + (2) I2 = 0. SOLVING the above equations,I1 = 0.855∠-69.5⁰.
Discussion
56.

In the circuit shown below. Find the current I2.(a) 0.5∠-90⁰(b) 0.6∠-90⁰(c) 0.7∠-90⁰(d) 0.8∠-90⁰I have been asked this question in an online interview.This interesting question is from Mesh Analysis in section Steady State AC Analysis of Network Theory

Answer»

Right option is (B) 0.6∠-90⁰

Explanation: The equation for loop 1 is I1(j4) + 6(I1-I2) = 5∠0⁰. The equation for loop 2 is 6(I1-I2) + (J3) I2 + (2) I2 = 0. Solving the above EQUATIONS, I2 = 0.6∠-90⁰.
Discussion
57.

If there are M branch currents, then we can write ___________ number of independent equations.(a) M-2(b) M-1(c) M(d) M+1I have been asked this question in an interview.This interesting question is from Mesh Analysis in chapter Steady State AC Analysis of Network Theory

Answer» CORRECT option is (C) M

For EXPLANATION: If there are M branch currents, then we can WRITE M number of independent equations. Number of independent equations = M.
Discussion
58.

If there are M meshes, B branches and N nodes including reference node, the number of mesh currents is given as M=?(a) B + (N+1)(b) B + (N-1)(c) B-(N+1)(d) B-(N-1)This question was addressed to me by my college director while I was bunking the class.This interesting question is from Mesh Analysis in division Steady State AC Analysis of Network Theory

Answer»

Correct CHOICE is (d) B-(N-1)

Easy explanation: If there are M meshes, B BRANCHES and N nodes INCLUDING REFERENCE node, the number of mesh currents is GIVEN as M = B-(N-1).
Discussion