In the circuit shown below. Find the current I2.(a) 0.5∠-90⁰(b) 0.6∠-90⁰(c) 0.7∠-90⁰(d) 0.8∠-90⁰I have been asked this question in an online interview.This interesting question is from Mesh Analysis in section Steady State AC Analysis of Network Theory

In the circuit shown below. Find the current I2.(a) 0.5∠-90⁰(b) 0.

1.	In the circuit shown below. Find the current I2.(a) 0.5∠-90⁰(b) 0.6∠-90⁰(c) 0.7∠-90⁰(d) 0.8∠-90⁰I have been asked this question in an online interview.This interesting question is from Mesh Analysis in section Steady State AC Analysis of Network Theory
Answer» Right option is (B) 0.6∠-90⁰ Explanation: The equation for loop 1 is I1(j4) + 6(I1-I2) = 5∠0⁰. The equation for loop 2 is 6(I1-I2) + (J3) I2 + (2) I2 = 0. Solving the above EQUATIONS, I2 = 0.6∠-90⁰.

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In the circuit shown below. Find the current I2.(a) 0.5∠-90⁰(b) 0.6∠-90⁰(c) 0.7∠-90⁰(d) 0.8∠-90⁰I have been asked this question in an online interview.This interesting question is from Mesh Analysis in section Steady State AC Analysis of Network Theory

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