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Find the Norton’s current in the circuit shown below.(a) 40∠30⁰(b) 40∠-30⁰(c) 30∠30⁰(d) 30∠-30⁰This question was posed to me in final exam.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory

Answer»

Correct CHOICE is (c) 30∠30⁰

Best explanation: The NORTON’s current is equal to the current passing through the SHORT CIRCUIT between the points a and b. So the current passing through the short circuited terminals ‘a’ and ‘b’ is I = 30∠30⁰A.



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