58 + Interview Questions in Steady State Ac Analysis in Network Theory Page 1 InterviewSolution

1.	If ZS=RS+jXS, ZL=RL, then condition for maximum power to be transferred is?(a) RL=\|ZS\|(b) RL=ZS(c) RL=-\|ZS\|(d) RL=-ZSThis question was addressed to me in exam.My question is based upon Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory
Answer» Right CHOICE is (a) RL=\|ZS\| To EXPLAIN I WOULD say: If ZS=RS+jXS, ZL=RL, then condition for maximum POWER to be transferred is RL=\|ZS\| that is maximum power is transferred when the load resistance is equal to the magnitude of the SOURCE impedance.

Discussion

2.	If ZS = RS+jXS, ZL=RL+jXL, then if RL is fixed, the condition for maximum power to be transferred is?(a) XS=XL(b) XS=-XL(c) XS+XL=0(d) None of the mentionedThis question was addressed to me by my school teacher while I was bunking the class.My doubt is from Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory
Answer» RIGHT option is (B) XS=-XL The explanation: If ZS = RS+jXS, ZL=RL+jXL, then if RL is fixed, the condition for MAXIMUM power to be TRANSFERRED is XS=-XL.

Discussion

3.	If the source ZS is complex, then the condition for the maximum power to be transferred is?(a) ZL=ZS(b) ZL=ZS(c) ZL=-ZS(d) ZL=-ZSI have been asked this question during an online exam.My enquiry is from Maximum Power Transfer Theorem in portion Steady State AC Analysis of Network Theory
Answer» Correct option is (B) ZL=ZS* The explanation is: If the source Zs is complex, then the condition for the MAXIMUM power to be transferred is ZL=ZS* that is LOAD IMPEDANCE is complex conjugate of source impedance.

Discussion

4.	Find the value of the maximum power in the circuit shown below.(a) 25(b) 50(c) 75(d) 100This question was addressed to me in my homework.My question is based upon Maximum Power Transfer Theorem topic in portion Steady State AC Analysis of Network Theory
Answer» Right option is (a) 25 Best explanation: CURRENT = 50/(25+25) = 1A. Maximum power delivered to load = (I)^2 × RL. On substituting the values obtained and given we get maximum power in the circuit is (1)^2 × 25 = 25W.

Discussion

5.	The condition for maximum current to be transferred to the load is?(a) Source resistance greater than or equal to load resistance(b) Source resistance equal to load resistance(c) Source resistance less than load resistance(d) Source resistance greater than load resistanceThis question was posed to me in an online quiz.The doubt is from Maximum Power Transfer Theorem in chapter Steady State AC Analysis of Network Theory
Answer» The correct answer is (d) SOURCE resistance GREATER than load resistance The explanation: The condition for maximum current to be TRANSFERRED to the load is source resistance greater than load resistance. For many applications an IMPORTANT consideration is the maximum power transfer to the load.

Discussion

6.	In the circuit shown determine the value of load resistance when the load resistance draws maximum power?(a) 50(b) 25(c) 75(d) 100I got this question during a job interview.My question is from Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory
Answer» Right option is (b) 25 Easy explanation: The SOURCE DELIVERS MAXIMUM POWER when load RESISTANCE is equal to source resistance. So, load resistance = 25Ω.

Discussion

7.	The condition for maximum power to be transferred to the load is?(a) Source resistance equal to load resistance(b) Source resistance greater than load resistance(c) Source resistance greater than or equal to load resistance(d) Source resistance less than load resistanceThis question was posed to me in final exam.My doubt stems from Maximum Power Transfer Theorem in portion Steady State AC Analysis of Network Theory
Answer» Correct choice is (a) Source resistance equal to load resistance For EXPLANATION: The CONDITION for maximum POWER to be TRANSFERRED to the load is source resistance equal toload resistance. Maximum power transfer is desirable from the output amplifier to the speaker of an AUDIO sound system.

Discussion

8.	The condition for maximum voltage to be transferred to the load is?(a) Source resistance greater than load resistance(b) Source resistance less than load resistance(c) Source resistance equal to load resistance(d) Source resistance greater than or equal to load resistanceI have been asked this question in examination.The query is from Maximum Power Transfer Theorem in portion Steady State AC Analysis of Network Theory
Answer» Right ANSWER is (b) Source resistance LESS than LOAD resistance Explanation: Our aim is to FIND the necessary conditions so that the power delivered by the source to the load is maximum. The condition for maximum voltage to be TRANSFERRED to the load is source resistance less than load resistance.

Discussion

9.	Find the load current in the circuit shown below.(a) 3.19∠166.61⁰(b) 3.19∠-166.61⁰(c) 4.19∠166.61⁰(d) 4.19∠-166.61⁰The question was posed to me in examination.My question is from Norton’s Theorem in chapter Steady State AC Analysis of Network Theory
Answer» Right answer is (b) 3.19∠-166.61⁰ For explanation: The load CURRENT in the CIRCUIT is GIVEN by IL = I×(6∠-90^o)/(5+6∠-90^o) = 3.19∠-166.61^oA.

Discussion

10.	Find the Norton’s current in the circuit shown below.(a) 40∠30⁰(b) 40∠-30⁰(c) 30∠30⁰(d) 30∠-30⁰This question was posed to me in final exam.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory
Answer» Correct CHOICE is (c) 30∠30⁰ Best explanation: The NORTON’s current is equal to the current passing through the SHORT CIRCUIT between the points a and b. So the current passing through the short circuited terminals ‘a’ and ‘b’ is I = 30∠30⁰A.

Discussion

11.	Determine Norton’s equivalent impedance in the circuit shown below.(a) (5+j6) Ω(b) (5-j6) Ω(c) (6+j7) Ω(d) (6-j7) ΩI have been asked this question in an interview.My question comes from Norton’s Theorem topic in section Steady State AC Analysis of Network Theory
Answer» Correct answer is (a) (5+j6) Ω Easy EXPLANATION: The impedance seen from the TERMINALS when the source is reduced to ZERO is Z = (5+j6) Ω.

Discussion

12.	Find the Norton’s current passing through ‘ab’ in the circuit shown below.(a) 4.16∠126.8⁰(b) 5.16∠126.8⁰(c) 5.16∠-126.8⁰(d) 4.16∠-126.8⁰I had been asked this question by my school teacher while I was bunking the class.I want to ask this question from Norton’s Theorem in portion Steady State AC Analysis of Network Theory
Answer» Right answer is (d) 4.16∠-126.8⁰ Easy explanation: The NORTON’s current is EQUAL to the current passing through the SHORT circuit between the POINTS a and b. The Norton’s current is I=(10∠0^o)/(3∠90^o)+(5∠90^o)/(2∠-90^o) =4.16∠-126.8^oA.

Discussion

13.	Determine the Norton’s impedance seen from terminals ‘ab’.(a) 6∠90⁰(b) 7∠90⁰(c) 6∠-90⁰(d) 7∠-90⁰I have been asked this question in my homework.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory
Answer» Right choice is (c) 6∠-90⁰ The best EXPLANATION: The impedance between the POINTS a and b with the SOURCE replaced by a short circuit is Norton’s equivalent impedance. The Norton’s impedance is Zab=(J3)(-j2)/((j3)-(j2))=6∠-90^oΩ.

Discussion

14.	The Norton’s equivalent impedance in the circuit shown below.(a) 4.53∠9.92⁰(b) 4.53∠-9.92⁰(c) 5.53∠9.92⁰(d) 5.53∠-9.92⁰The question was posed to me by my school principal while I was bunking the class.My question is from Norton’s Theorem in portion Steady State AC Analysis of Network Theory
Answer» The correct choice is (a) 4.53∠9.92⁰ The best explanation: The NORTON’s EQUIVALENT impedance is Z = (3+j4)(4-j5)/((3+j4)+(4-j5))=4.53∠9.92^oΩ. The impedance between the POINTS a and b with the source REPLACED by a short circuit is Norton’s equivalent impedance.

Discussion

15.	Determine Norton’s equivalent current in the circuit shown below.(a) 5∠53.13⁰(b) 4∠53.13⁰(c) 4∠53.13⁰(d) 5∠-53.13⁰The question was posed to me in an online interview.Question is taken from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory
Answer» The CORRECT choice is (d) 5∠-53.13⁰ The EXPLANATION: The current through the terminals a and B is the NORTON’s EQUIVALENT current. The Norton’s equivalent current is I = (25∠0^o)/(3+j4) = 5∠-53.13⁰A.

Discussion

16.	The expression of equivalent impedance (ZN) in the circuit shown below is?(a) (Z1+Z2)/Z1(b) (Z1+Z2)/Z2(c) Z1Z2/(Z1+Z2)(d) Z1+Z2This question was posed to me in semester exam.My query is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory
Answer» Correct option is (c) Z1Z2/(Z1+Z2) The best EXPLANATION: The impedance between the points a and B with the source replaced by a SHORT circuit is NORTON’s equivalent impedance. The Norton’s equivalent impedance is ZN = Z1Z2/(Z1+Z2).

Discussion

17.	The expression of Norton’s current (IN) in the circuit shown below is?(a) V/Z1(b) V/Z2(c) V(Z2/(Z1+Z2))(d) VZ1/(Z1+Z2)The question was posed to me during a job interview.The doubt is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory
Answer» Right answer is (a) V/Z1 For explanation: The Norton’s EQUIVALENT FORM of any complex impedance circuit CONSISTS of an equivalent current SOURCE and an equivalent impedance. The expression of Norton’s current is IN = V/Z1.

Discussion

18.	Norton’s current is equal to the current passing through the ___________ circuited ___________ terminals.(a) short, input(b) short, output(c) open, output(d) open, inputThis question was addressed to me in an interview.I need to ask this question from Norton’s Theorem topic in section Steady State AC Analysis of Network Theory
Answer» Correct ANSWER is (b) SHORT, output Explanation: Norton’s current is EQUAL to the current passing through short CIRCUITED output terminals not the current through OPEN circuited output terminals.

Discussion

19.	Find the Thevenin’s impedance in the following circuit.(a) 11.3∠45⁰(b) 12.3∠45⁰(c) 11.3∠-45⁰(d) 12.3∠-45⁰This question was posed to me in an interview for internship.This intriguing question originated from Thevenin’s Theorem in portion Steady State AC Analysis of Network Theory
Answer» Correct option is (c) 11.3∠-45⁰ The BEST I can explain: The IMPEDANCE is equal to the impedance seen into the NETWORK across the output TERMINALS. Zab = 4 + (2+j6)(-j4)/(2+j2) = 11.3∠-45^o Ω.

Discussion

20.	Determine the thevenin’s voltage in the circuit shown below.(a) 18∠146.31⁰(b) 18∠-146.31⁰(c) 19∠146.31⁰(d) 19∠-146.31⁰I got this question in an online interview.This question is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory
Answer» The correct OPTION is (a) 18∠146.31⁰ The best I can explain: The voltage ACROSS (-j4) Ω RESISTOR is = (5∠90^o)/((2+j2)) (-j4) = 7.07∠-45^o V. The voltage across ‘AB’ = -10∠0^o+5∠90^o-7.07∠-45^o=18∠146.31^o V.

Discussion

21.	Find the Thevenin’s impedance across ‘ab’ terminals in the circuit shown below.(a) j4.71(b) j5.71(c) j6.71(d) j7.71I got this question in homework.Query is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory
Answer» CORRECT CHOICE is (C) j6.71 For explanation: The impedance is equal to the impedance seen into the network across the output terminals. Zab=j5 + (j4)(j3)/J7 = j6.71Ω.

Discussion

22.	Determine the load current across j5Ω in the circuit shown below.(a) 3.66∠90⁰(b) 3.66∠-90⁰(c) 4.66∠90⁰(d) 4.66∠-90⁰I got this question by my school principal while I was bunking the class.This interesting question is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory
Answer» Right option is (b) 3.66∠-90⁰ The EXPLANATION: The LOAD current is the ratio of thevenin’s EQUIVALENT voltage and thevenin’s equivalent IMPEDANCE. The load current IL = (42.86∠0^o)/(j6.71+j5) = 3.66∠-90^o A.

Discussion

23.	Find the thevenin’s impedance in the circuit shown below.(a) 4.83∠-1.13⁰(b) 5.83∠1.13⁰(c) 4.83∠1.13⁰(d) 5.83∠-1.13⁰I have been asked this question in my homework.My question is based upon Thevenin’s Theorem in portion Steady State AC Analysis of Network Theory
Answer» Correct choice is (a) 4.83∠-1.13⁰ Easiest EXPLANATION: The impedance is equal to the impedance SEEN into the network across the OUTPUT TERMINALS. ZTH = (j5-j4)+(3-j4)(4+j6)/(3-j4+4+j6) = 4.83∠-1.13⁰Ω.

Discussion

24.	Determine the Thevenin’s voltage across ‘ab’ terminals in the circuit shown below.(a) 41.86∠0⁰(b) 42.86∠0⁰(c) 43.86∠0⁰(d) 44.86∠0⁰The question was asked in an internship interview.My enquiry is from Thevenin’s Theorem in section Steady State AC Analysis of Network Theory
Answer» The correct CHOICE is (B) 42.86∠0⁰ Best explanation: The VOLTAGE ACROSS the points a and b is called thevenin’s equivalent voltage. Thevenin’s equivalent voltage Vab=100∠0^o×j3/(j3+j4) = 42.86∠0^o V.

Discussion

25.	In the circuit shown below, find the thevenin’s voltage across ‘ab’ terminals.(a) 48.5∠40.35⁰(b) 48.5∠-40.35⁰(c) 49.5∠-40.35⁰(d) 49.5∠40.35⁰The question was asked during an internship interview.I'm obligated to ask this question of Thevenin’s Theorem in section Steady State AC Analysis of Network Theory
Answer» Right OPTION is (d) 49.5∠40.35⁰ For explanation: THOUGH the thevenin’s equivalent circuit is not same as its original circuit, the output current and voltage are the same in both CASES. The thevenin’s voltage is equal to the voltage across (4+j6)Ω impedance. VTh =50∠0^o×(4+j6)/((4+j6)+(3-j4))=49.5∠40.35⁰V.

Discussion

26.	The value of ZTh in the circuit shown below is?(a) Z3+(Z1Z2/(Z1+Z2))(b) Z1+(Z3Z2/(Z3+Z2))(c) Z2+(Z1Z3/(Z1+Z3))(d) (Z1Z2/(Z1+Z2))I had been asked this question in an international level competition.This interesting question is from Thevenin’s Theorem topic in section Steady State AC Analysis of Network Theory
Answer» CORRECT OPTION is (a) Z3+(Z1Z2/(Z1+Z2)) To explain I would say: The thevenin’s equivalent form of any complex IMPEDANCE consists of an equivalent voltage SOURCE and an equivalent impedance. The thevenin’s impedance is ZTh = Z3+(Z1Z2/(Z1+Z2)).

Discussion

27.	Consider the circuit shown below. The expression of Thevenin’s voltage (VTh) is?(a) V(Z1/(Z1+Z2))(b) V(Z2/(Z1+Z2))(c) V(Z1)(d) V(Z2)I have been asked this question in an interview for internship.Enquiry is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory
Answer» The CORRECT option is (B) V(Z2/(Z1+Z2)) The explanation: THEVENIN’s theorem gives us a METHOD for SIMPLIFYING a given circuit. The thevenin’s voltage is VTh = V(Z2/(Z1+Z2)).

Discussion

28.	Find the voltage Vab in the circuit shown above using Superposition theorem.(a) 4∠0⁰(b) 50∠0⁰(c) 54∠0⁰(d) 46∠0⁰The question was posed to me by my school principal while I was bunking the class.Origin of the question is Superposition Theorem in chapter Steady State AC Analysis of Network Theory
Answer» Right ANSWER is (b) 50∠0⁰ To explain I WOULD SAY: The total voltage is the sum of the two voltages V1 and V2 => Vab = V1+V2 = 50∠0⁰V.

Discussion

29.	Determine the voltage across (2+j5) Ω impedance considering 20∠30⁰ voltage source.(a) 45.69∠-110.72⁰(b) 45.69∠110.72⁰(c) 46.69∠-110.72⁰(d) 46.69∠110.72⁰I got this question in an international level competition.The query is from Superposition Theorem topic in section Steady State AC Analysis of Network Theory
Answer» Correct ANSWER is (d) 46.69∠110.72⁰ The best I can explain: The voltage ACROSS (2+j5) Ω impedance CONSIDERING 20∠30⁰ voltage source is V2 = 8.68∠42.53^o (2+j5) = 46.69∠110.72⁰V.

Discussion

30.	Thevenin’s voltage is equal to the _____________ voltage across the _______________ terminals.(a) short circuit, input(b) short circuit, output(c) open circuit, output(d) open circuit, inputThis question was addressed to me in final exam.My enquiry is from Thevenin’s Theorem in chapter Steady State AC Analysis of Network Theory
Answer» Right option is (C) open circuit, OUTPUT The explanation: Thevenin’s voltage is equal to open circuit voltage across output terminals not the SHORT circuit voltage across output terminals.

Discussion

31.	Determine the voltage Vab considering the source 4∠0⁰A in the circuit shown above.(a) 46∠0⁰(b) 4∠0⁰(c) 54∠0⁰(d) 50∠0⁰The question was posed to me in examination.The doubt is from Superposition Theorem topic in section Steady State AC Analysis of Network Theory
Answer» The correct ANSWER is (b) 4∠0⁰ For EXPLANATION: Set the VOLTAGE source 50∠0⁰V to zero, and is short-circuited. So, the voltage DROP across ‘ab’ is zero.

Discussion

32.	Find the voltage across (2+j5) Ω impedance using Superposition theorem.(a) 40.85∠72.53⁰(b) 40.85∠-72.53⁰(c) 41.85∠72.53⁰(d) 41.85∠-72.53⁰The question was asked during an online exam.This intriguing question originated from Superposition Theorem in division Steady State AC Analysis of Network Theory
Answer» The correct OPTION is (a) 40.85∠72.53⁰ Explanation: The voltage across (2+j5) Ω impedance USING Superposition THEOREM is the SUM of the voltages V1 and V2. V = V1+V2 = 29.16∠-9.28^o+46.69∠110.72^o=40.85∠72.53^o V.

Discussion

33.	Determine the voltage Vab considering the source 50∠0⁰V.(a) 50∠0⁰(b) 4∠0⁰(c) 54∠0⁰(d) 46∠0⁰This question was posed to me at a job interview.I would like to ask this question from Superposition Theorem topic in section Steady State AC Analysis of Network Theory
Answer» Correct OPTION is (a) 50∠0⁰ To explain: Let source 50∠0⁰ act on the circuit and SET the source 4∠0⁰A EQUAL to zero. If the CURRENT source is zero, it becomes open-circuited. Then the voltage ACROSS ‘ab’ is 50∠0⁰.

Discussion

34.	Find the current through (2+j5) Ω impedance considering 20∠30⁰ voltage source.(a) 8.68∠-42.53⁰(b) 8.68∠42.53⁰(c) 7.68∠42.53⁰(d) 7.68∠-42.53⁰I got this question in a national level competition.The origin of the question is Superposition Theorem in portion Steady State AC Analysis of Network Theory
Answer» Correct CHOICE is (b) 8.68∠42.53⁰ The explanation is: The CURRENT through (2+j5) Ω impedance considering 20∠30⁰ voltage SOURCE is I2 = 20∠30^o×j4/(2+j9) = 8.68∠42.53^o A.

Discussion

35.	Determine the current through (2+j5) Ω impedance considering 50∠0⁰ voltage source.(a) 6.42∠77.47⁰(b) 6.42∠-77.47⁰(c) 5.42∠77.47⁰(d) 5.42∠-77.47⁰The question was asked during a job interview.I'm obligated to ask this question of Superposition Theorem in chapter Steady State AC Analysis of Network Theory
Answer» RIGHT CHOICE is (d) 5.42∠-77.47⁰ The explanation is: According to the SUPERPOSITION theorem the current due to the 50∠0^o source is I1 with the current source 20∠30⁰ A short-circuited. I1 = (50∠0^o)/(2+j4+j5) = 5.42∠-77.47^o A.

Discussion

36.	Superposition theorem is valid for only linear systems.(a) true(b) falseThe question was posed to me during an online interview.Question is taken from Superposition Theorem in division Steady State AC Analysis of Network Theory
Answer» Correct answer is (a) true To explain I would say: SUPERPOSITION THEOREM is valid for only linear SYSTEMS. Superposition theorem is not valid for non-linear systems. In a network containing complex impedance, all quantities MUST be treated as complex NUMBERS.

Discussion

37.	Find the voltage across (2+j5) Ω impedance considering 50∠0⁰ voltage source.(a) 30.16∠-9.28⁰(b) 30.16∠9.28⁰(c) 29.16∠-9.28⁰(d) 29.16∠9.28⁰I got this question in examination.My question is based upon Superposition Theorem topic in chapter Steady State AC Analysis of Network Theory
Answer» RIGHT answer is (C) 29.16∠-9.28⁰ Easiest explanation: VOLTAGE ACROSS (2+j5) Ω impedance considering 50∠0⁰ voltage source is V1 = 5.42∠-77.47^o (2+j5) = 29.16∠-9.28^o V.

Discussion

38.	Superposition theorem states that the response in any element is the ____________ of the responses that can be expected to flow if each source acts independently of other sources.(a) algebraic sum(b) vector sum(c) multiplication(d) subtractionThe question was asked in final exam.Question is from Superposition Theorem topic in chapter Steady State AC Analysis of Network Theory
Answer» The correct answer is (B) vector sum To elaborate: The superposition THEOREM is used to analyze ac circuits CONTAINING more than ONE SOURCE. Superposition theorem states that the response in any element is the vector sum of the responses that can be expected to flow if each source acts independently of other sources.

Discussion

39.	For the circuit shown below, find the voltage across the resistance RL if RL is infinite.(a) 3(b) 2(c) 1(d) 0The question was posed to me in exam.The origin of the question is Nodal Analysis in section Steady State AC Analysis of Network Theory
Answer» The correct CHOICE is (d) 0 Explanation: If RL is INFINITE, the voltage across it will be 0. So the voltage across the resistance RL if RL is infinite is zero.

Discussion

40.	Find the voltage Vab in the circuit shown below.(a) 21.66∠-45.02⁰(b) 20.66∠-45.02⁰(c) 21.66∠45.02⁰(d) 20.66∠45.02⁰I have been asked this question in class test.My doubt stems from Nodal Analysis in portion Steady State AC Analysis of Network Theory
Answer» Correct choice is (C) 21.66∠45.02⁰ Easiest explanation: Applying nodal analysis at node ‘a’, (Va-20∠0^o)/(3+2)+(Va-20∠90^o)/(j4+3)=0. On SOLVING, we GET Va = 21.66∠45.02⁰V.

Discussion

41.	In the following circuit. Find the power output of the source.(a) 27(b) 28(c) 29(d) 30I had been asked this question in exam.Query is from Nodal Analysis topic in section Steady State AC Analysis of Network Theory
Answer» Correct answer is (a) 27 The EXPLANATION: Total power delivered by the SOURCE is the PRODUCT of VOLTAGE and current and is given by power output of the source VIcosφ = 20 x 1.71cos142⁰ = 26.95W.

Discussion

42.	In the circuit shown below. Determine the power dissipated in 3Ω resistor.(a) 7.77(b) 8.77(c) 9.77(d) 10.77The question was asked by my school principal while I was bunking the class.The question is from Nodal Analysis topic in division Steady State AC Analysis of Network Theory
Answer» Correct choice is (b) 8.77 Best explanation: CURRENT in 3Ω RESISTOR I3 =(-20∠30^o+16.27∠18.91^o)/3=1.71∠-112^o. Power dissipated in 3Ω resistor P=I3^2 R=1.71^2×3=8.77W.

Discussion

43.	In the circuit shown below find the power dissipated by 2Ω resistor.(a) 16.24(b) 17.24(c) 18.24(d) 19.24This question was posed to me during an internship interview.My query is from Nodal Analysis in portion Steady State AC Analysis of Network Theory
Answer» Correct answer is (c) 18.24 To EXPLAIN I would SAY: Applying nodal analysis at node ‘a’, (Va-20∠30^o)/3+Va/(-j4)+Va/(2+j5)=0. On solving, Va = 16.27∠18.91⁰. CURRENT in 2Ω RESISTOR I2 = Va/(2+j5) = (16.27∠18.91^o)/(5.38∠68.19^o)=3.02∠-49.28^o. Power DISSIPATED in 2Ω resistor P=I2^2 R=3.02^2×2 = 18.24W.

Discussion

44.	In the circuit shown below we get a nodal equation as (1/3+1/j4-1/j6)Va—(-1/j6)Vb=x. Find the value of ‘x^‘‘.(a) (5∠0^o)/3(b) – (5∠0^o)/3(c) (10∠0^o)/3(d) – (10∠0^o)/3I had been asked this question in an internship interview.This question is from Nodal Analysis in chapter Steady State AC Analysis of Network Theory
Answer» CORRECT choice is (c) (10∠0^o)/3 For explanation: The general EQUATIONS are YaaVa+YabVb = I1, YbaVa+YbbVb = I2. We get Yaa=1/3+1/j4+1/(-j6) and the self ADMITTANCE at node a is the sum of admittances CONNECTED to node a. Yab=-(1/(-j6)). I1 = (10∠0^o)/3=x.

Discussion

45.	Find the value of ‘y’ in the equation –(-1/j6)Va+(1/5+1/j5-1/j6)Vb=y obtained from the following circuit.(a) (10∠30^o)/5(b) -(10∠30^o)/5(c) (5∠30^o)/5(d) (-5∠30^o)/5The question was asked during an internship interview.The above asked question is from Nodal Analysis in portion Steady State AC Analysis of Network Theory
Answer» Right CHOICE is (b) -(10∠30^o)/5 The explanation is: We GOT Ybb=1/5+1/j5-1/j6 and Yab=–(-1/j6). The mutual ADMITTANCE between node b and a is the SUM of the admittances between nodes b and a. I2=-(10∠30^o)/5=y.

Discussion

46.	Determine the voltage at node ‘b’ in the circuit shown below.(a) -1.34∠-180⁰(b) 1.34∠-180⁰(c) -0.34∠-180⁰(d) 0.34∠-180⁰The question was asked in an interview for internship.My query is from Nodal Analysis topic in chapter Steady State AC Analysis of Network Theory
Answer» Right CHOICE is (a) -1.34∠-180⁰ The explanation: Applying nodal analysis at node ‘a’, (Va-10∠0^o)/J6+Va/(-j6)+(Va-VB)/3=0. Applying nodal analysis at node ‘b’, (Vb-Va)/3+Vb/j4+Vb/j1=0. Solving the above EQUATIONS we get, Vb = -1.34∠-180⁰V.

Discussion

47.	If there are N nodes in a circuit, then the number of nodal equations that can be formed are?(a) N+1(b) N(c) N-1(d) N-2This question was posed to me in an online interview.This question is from Nodal Analysis topic in section Steady State AC Analysis of Network Theory
Answer» The CORRECT answer is (c) N-1 To EXPLAIN I WOULD say: If there are N nodes in a circuit, then the number of nodal EQUATIONS that can be formed are N-1. Number of nodal equations = N-1.

Discussion

48.	In the network shown below, find the voltage at node ‘a’.(a) 5.22∠104.5⁰(b) 5.22∠-104.5⁰(c) 6.22∠104.5⁰(d) 6.22∠-104.5⁰This question was posed to me by my college director while I was bunking the class.Question is taken from Nodal Analysis in chapter Steady State AC Analysis of Network Theory
Answer» Right choice is (B) 5.22∠-104.5⁰ To EXPLAIN: Applying NODAL analysis at NODE ‘a’, (Va-10∠0^o)/j6+Va/(-j6)+(Va-Vb)/3=0. Applying nodal analysis at node ‘b’, (Vb-Va)/3+Vb/j4+Vb/j1=0. Solving the above equations we GET,Va = 5.22∠-104.5⁰V.

Discussion

49.	Find the value V2 in the circuit shown below if the current through (3+j4) Ω is zero.(a) 16∠-262⁰(b) 17∠-262⁰(c) 18∠-262⁰(d) 19∠-262⁰The question was asked in a national level competition.I would like to ask this question from Mesh Analysis in section Steady State AC Analysis of Network Theory
Answer» CORRECT answer is (B) 17∠-262⁰ The explanation is: The three loop equations are (4+j3)I1 – (j3)I2 = 20∠0⁰. (-j3)I1 + (3+j2)I2 + (j5)I3 = 0. (j5)I2 + (5-j5)I3 = -V2. The CURRENT through (3+j4) Ω is zero, I2 = ∆2/∆ = 0

Discussion

50.	Find the common impedances Z12, Z13, Z21, Z23, Z31, Z32 respectively in the circuit shown below.(a) -j3Ω, 0Ω, -j3Ω, j5Ω, 0Ω, j5Ω(b) j3Ω, 0Ω, -j3Ω, j5Ω, 0Ω, j5Ω(c) j3Ω, 0Ω, -j3Ω, j5Ω, 0Ω,- j5Ω(d) j3Ω, 0Ω, -j3Ω, -j5Ω, 0Ω, j5ΩI had been asked this question during an online interview.I'm obligated to ask this question of Mesh Analysis topic in section Steady State AC Analysis of Network Theory
Answer» The CORRECT answer is (a) -j3Ω, 0Ω, -j3Ω, j5Ω, 0Ω, j5Ω To EXPLAIN: The COMMON IMPEDANCES Z12 and Z21 are Z12 = Z21 = -j3Ω. The common impedances Z13 and Z31 are Z13 = Z31 = 0Ω. The common impedances Z23 and Z32 are Z23 = Z32 = j5Ω.

Discussion

Explore topic-wise InterviewSolutions in .

If ZS=RS+jXS, ZL=RL, then condition for maximum power to be transferred is?(a) RL=|ZS|(b) RL=ZS(c) RL=-|ZS|(d) RL=-ZSThis question was addressed to me in exam.My question is based upon Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory

If the source ZS is complex, then the condition for the maximum power to be transferred is?(a) ZL=ZS(b) ZL=ZS(c) ZL=-ZS(d) ZL=-ZSI have been asked this question during an online exam.My enquiry is from Maximum Power Transfer Theorem in portion Steady State AC Analysis of Network Theory

Find the value of the maximum power in the circuit shown below.(a) 25(b) 50(c) 75(d) 100This question was addressed to me in my homework.My question is based upon Maximum Power Transfer Theorem topic in portion Steady State AC Analysis of Network Theory

In the circuit shown determine the value of load resistance when the load resistance draws maximum power?(a) 50(b) 25(c) 75(d) 100I got this question during a job interview.My question is from Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory

Find the load current in the circuit shown below.(a) 3.19∠166.61⁰(b) 3.19∠-166.61⁰(c) 4.19∠166.61⁰(d) 4.19∠-166.61⁰The question was posed to me in examination.My question is from Norton’s Theorem in chapter Steady State AC Analysis of Network Theory

Find the Norton’s current in the circuit shown below.(a) 40∠30⁰(b) 40∠-30⁰(c) 30∠30⁰(d) 30∠-30⁰This question was posed to me in final exam.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory

Determine Norton’s equivalent impedance in the circuit shown below.(a) (5+j6) Ω(b) (5-j6) Ω(c) (6+j7) Ω(d) (6-j7) ΩI have been asked this question in an interview.My question comes from Norton’s Theorem topic in section Steady State AC Analysis of Network Theory

Determine the Norton’s impedance seen from terminals ‘ab’.(a) 6∠90⁰(b) 7∠90⁰(c) 6∠-90⁰(d) 7∠-90⁰I have been asked this question in my homework.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory

Determine Norton’s equivalent current in the circuit shown below.(a) 5∠53.13⁰(b) 4∠53.13⁰(c) 4∠53.13⁰(d) 5∠-53.13⁰The question was posed to me in an online interview.Question is taken from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

The expression of equivalent impedance (ZN) in the circuit shown below is?(a) (Z1+Z2)/Z1(b) (Z1+Z2)/Z2(c) Z1Z2/(Z1+Z2)(d) Z1+Z2This question was posed to me in semester exam.My query is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

The expression of Norton’s current (IN) in the circuit shown below is?(a) V/Z1(b) V/Z2(c) V(Z2/(Z1+Z2))(d) VZ1/(Z1+Z2)The question was posed to me during a job interview.The doubt is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

Find the Thevenin’s impedance in the following circuit.(a) 11.3∠45⁰(b) 12.3∠45⁰(c) 11.3∠-45⁰(d) 12.3∠-45⁰This question was posed to me in an interview for internship.This intriguing question originated from Thevenin’s Theorem in portion Steady State AC Analysis of Network Theory

Determine the thevenin’s voltage in the circuit shown below.(a) 18∠146.31⁰(b) 18∠-146.31⁰(c) 19∠146.31⁰(d) 19∠-146.31⁰I got this question in an online interview.This question is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Find the Thevenin’s impedance across ‘ab’ terminals in the circuit shown below.(a) j4.71(b) j5.71(c) j6.71(d) j7.71I got this question in homework.Query is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Find the thevenin’s impedance in the circuit shown below.(a) 4.83∠-1.13⁰(b) 5.83∠1.13⁰(c) 4.83∠1.13⁰(d) 5.83∠-1.13⁰I have been asked this question in my homework.My question is based upon Thevenin’s Theorem in portion Steady State AC Analysis of Network Theory

Determine the Thevenin’s voltage across ‘ab’ terminals in the circuit shown below.(a) 41.86∠0⁰(b) 42.86∠0⁰(c) 43.86∠0⁰(d) 44.86∠0⁰The question was asked in an internship interview.My enquiry is from Thevenin’s Theorem in section Steady State AC Analysis of Network Theory

Consider the circuit shown below. The expression of Thevenin’s voltage (VTh) is?(a) V(Z1/(Z1+Z2))(b) V(Z2/(Z1+Z2))(c) V(Z1)(d) V(Z2)I have been asked this question in an interview for internship.Enquiry is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Determine the voltage Vab considering the source 4∠0⁰A in the circuit shown above.(a) 46∠0⁰(b) 4∠0⁰(c) 54∠0⁰(d) 50∠0⁰The question was posed to me in examination.The doubt is from Superposition Theorem topic in section Steady State AC Analysis of Network Theory

Determine the voltage Vab considering the source 50∠0⁰V.(a) 50∠0⁰(b) 4∠0⁰(c) 54∠0⁰(d) 46∠0⁰This question was posed to me at a job interview.I would like to ask this question from Superposition Theorem topic in section Steady State AC Analysis of Network Theory

Superposition theorem is valid for only linear systems.(a) true(b) falseThe question was posed to me during an online interview.Question is taken from Superposition Theorem in division Steady State AC Analysis of Network Theory

For the circuit shown below, find the voltage across the resistance RL if RL is infinite.(a) 3(b) 2(c) 1(d) 0The question was posed to me in exam.The origin of the question is Nodal Analysis in section Steady State AC Analysis of Network Theory

Find the voltage Vab in the circuit shown below.(a) 21.66∠-45.02⁰(b) 20.66∠-45.02⁰(c) 21.66∠45.02⁰(d) 20.66∠45.02⁰I have been asked this question in class test.My doubt stems from Nodal Analysis in portion Steady State AC Analysis of Network Theory

In the following circuit. Find the power output of the source.(a) 27(b) 28(c) 29(d) 30I had been asked this question in exam.Query is from Nodal Analysis topic in section Steady State AC Analysis of Network Theory

In the circuit shown below. Determine the power dissipated in 3Ω resistor.(a) 7.77(b) 8.77(c) 9.77(d) 10.77The question was asked by my school principal while I was bunking the class.The question is from Nodal Analysis topic in division Steady State AC Analysis of Network Theory

In the circuit shown below find the power dissipated by 2Ω resistor.(a) 16.24(b) 17.24(c) 18.24(d) 19.24This question was posed to me during an internship interview.My query is from Nodal Analysis in portion Steady State AC Analysis of Network Theory

Determine the voltage at node ‘b’ in the circuit shown below.(a) -1.34∠-180⁰(b) 1.34∠-180⁰(c) -0.34∠-180⁰(d) 0.34∠-180⁰The question was asked in an interview for internship.My query is from Nodal Analysis topic in chapter Steady State AC Analysis of Network Theory

If there are N nodes in a circuit, then the number of nodal equations that can be formed are?(a) N+1(b) N(c) N-1(d) N-2This question was posed to me in an online interview.This question is from Nodal Analysis topic in section Steady State AC Analysis of Network Theory

Explore topic-wise InterviewSolutions in .

If ZS=RS+jXS, ZL=RL, then condition for maximum power to be transferred is?(a) RL=|ZS|(b) RL=ZS(c) RL=-|ZS|(d) RL=-ZSThis question was addressed to me in exam.My question is based upon Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory

If the source ZS is complex, then the condition for the maximum power to be transferred is?(a) ZL=ZS(b) ZL=ZS*(c) ZL=-ZS(d) ZL=-ZS*I have been asked this question during an online exam.My enquiry is from Maximum Power Transfer Theorem in portion Steady State AC Analysis of Network Theory

Find the value of the maximum power in the circuit shown below.(a) 25(b) 50(c) 75(d) 100This question was addressed to me in my homework.My question is based upon Maximum Power Transfer Theorem topic in portion Steady State AC Analysis of Network Theory

In the circuit shown determine the value of load resistance when the load resistance draws maximum power?(a) 50(b) 25(c) 75(d) 100I got this question during a job interview.My question is from Maximum Power Transfer Theorem topic in division Steady State AC Analysis of Network Theory

Find the load current in the circuit shown below.(a) 3.19∠166.61⁰(b) 3.19∠-166.61⁰(c) 4.19∠166.61⁰(d) 4.19∠-166.61⁰The question was posed to me in examination.My question is from Norton’s Theorem in chapter Steady State AC Analysis of Network Theory

Find the Norton’s current in the circuit shown below.(a) 40∠30⁰(b) 40∠-30⁰(c) 30∠30⁰(d) 30∠-30⁰This question was posed to me in final exam.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory

Determine Norton’s equivalent impedance in the circuit shown below.(a) (5+j6) Ω(b) (5-j6) Ω(c) (6+j7) Ω(d) (6-j7) ΩI have been asked this question in an interview.My question comes from Norton’s Theorem topic in section Steady State AC Analysis of Network Theory

Determine the Norton’s impedance seen from terminals ‘ab’.(a) 6∠90⁰(b) 7∠90⁰(c) 6∠-90⁰(d) 7∠-90⁰I have been asked this question in my homework.This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory

Determine Norton’s equivalent current in the circuit shown below.(a) 5∠53.13⁰(b) 4∠53.13⁰(c) 4∠53.13⁰(d) 5∠-53.13⁰The question was posed to me in an online interview.Question is taken from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

The expression of equivalent impedance (ZN) in the circuit shown below is?(a) (Z1+Z2)/Z1(b) (Z1+Z2)/Z2(c) Z1Z2/(Z1+Z2)(d) Z1+Z2This question was posed to me in semester exam.My query is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

The expression of Norton’s current (IN) in the circuit shown below is?(a) V/Z1(b) V/Z2(c) V(Z2/(Z1+Z2))(d) VZ1/(Z1+Z2)The question was posed to me during a job interview.The doubt is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

Find the Thevenin’s impedance in the following circuit.(a) 11.3∠45⁰(b) 12.3∠45⁰(c) 11.3∠-45⁰(d) 12.3∠-45⁰This question was posed to me in an interview for internship.This intriguing question originated from Thevenin’s Theorem in portion Steady State AC Analysis of Network Theory

Determine the thevenin’s voltage in the circuit shown below.(a) 18∠146.31⁰(b) 18∠-146.31⁰(c) 19∠146.31⁰(d) 19∠-146.31⁰I got this question in an online interview.This question is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Find the Thevenin’s impedance across ‘ab’ terminals in the circuit shown below.(a) j4.71(b) j5.71(c) j6.71(d) j7.71I got this question in homework.Query is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Find the thevenin’s impedance in the circuit shown below.(a) 4.83∠-1.13⁰(b) 5.83∠1.13⁰(c) 4.83∠1.13⁰(d) 5.83∠-1.13⁰I have been asked this question in my homework.My question is based upon Thevenin’s Theorem in portion Steady State AC Analysis of Network Theory

Determine the Thevenin’s voltage across ‘ab’ terminals in the circuit shown below.(a) 41.86∠0⁰(b) 42.86∠0⁰(c) 43.86∠0⁰(d) 44.86∠0⁰The question was asked in an internship interview.My enquiry is from Thevenin’s Theorem in section Steady State AC Analysis of Network Theory

Consider the circuit shown below. The expression of Thevenin’s voltage (VTh) is?(a) V(Z1/(Z1+Z2))(b) V(Z2/(Z1+Z2))(c) V(Z1)(d) V(Z2)I have been asked this question in an interview for internship.Enquiry is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Determine the voltage Vab considering the source 4∠0⁰A in the circuit shown above.(a) 46∠0⁰(b) 4∠0⁰(c) 54∠0⁰(d) 50∠0⁰The question was posed to me in examination.The doubt is from Superposition Theorem topic in section Steady State AC Analysis of Network Theory

Determine the voltage Vab considering the source 50∠0⁰V.(a) 50∠0⁰(b) 4∠0⁰(c) 54∠0⁰(d) 46∠0⁰This question was posed to me at a job interview.I would like to ask this question from Superposition Theorem topic in section Steady State AC Analysis of Network Theory

Superposition theorem is valid for only linear systems.(a) true(b) falseThe question was posed to me during an online interview.Question is taken from Superposition Theorem in division Steady State AC Analysis of Network Theory

For the circuit shown below, find the voltage across the resistance RL if RL is infinite.(a) 3(b) 2(c) 1(d) 0The question was posed to me in exam.The origin of the question is Nodal Analysis in section Steady State AC Analysis of Network Theory

Find the voltage Vab in the circuit shown below.(a) 21.66∠-45.02⁰(b) 20.66∠-45.02⁰(c) 21.66∠45.02⁰(d) 20.66∠45.02⁰I have been asked this question in class test.My doubt stems from Nodal Analysis in portion Steady State AC Analysis of Network Theory

In the following circuit. Find the power output of the source.(a) 27(b) 28(c) 29(d) 30I had been asked this question in exam.Query is from Nodal Analysis topic in section Steady State AC Analysis of Network Theory

In the circuit shown below. Determine the power dissipated in 3Ω resistor.(a) 7.77(b) 8.77(c) 9.77(d) 10.77The question was asked by my school principal while I was bunking the class.The question is from Nodal Analysis topic in division Steady State AC Analysis of Network Theory

In the circuit shown below find the power dissipated by 2Ω resistor.(a) 16.24(b) 17.24(c) 18.24(d) 19.24This question was posed to me during an internship interview.My query is from Nodal Analysis in portion Steady State AC Analysis of Network Theory

Determine the voltage at node ‘b’ in the circuit shown below.(a) -1.34∠-180⁰(b) 1.34∠-180⁰(c) -0.34∠-180⁰(d) 0.34∠-180⁰The question was asked in an interview for internship.My query is from Nodal Analysis topic in chapter Steady State AC Analysis of Network Theory

If there are N nodes in a circuit, then the number of nodal equations that can be formed are?(a) N+1(b) N(c) N-1(d) N-2This question was posed to me in an online interview.This question is from Nodal Analysis topic in section Steady State AC Analysis of Network Theory

If the source ZS is complex, then the condition for the maximum power to be transferred is?(a) ZL=ZS(b) ZL=ZS(c) ZL=-ZS(d) ZL=-ZSI have been asked this question during an online exam.My enquiry is from Maximum Power Transfer Theorem in portion Steady State AC Analysis of Network Theory