Find the value of ‘y’ in the equation –(-1/j6)Va+(1/5+1/j5-1/j6)Vb=y obtained from the following circuit.(a) (10∠30^o)/5(b) -(10∠30^o)/5(c) (5∠30^o)/5(d) (-5∠30^o)/5The question was asked during an internship interview.The above asked question is from Nodal Analysis in portion Steady State AC Analysis of Network Theory

Find the value of ‘y’ in the equation –(-1/j6)Va+(1/5+1/j5-1/j6)

1.	Find the value of ‘y’ in the equation –(-1/j6)Va+(1/5+1/j5-1/j6)Vb=y obtained from the following circuit.(a) (10∠30^o)/5(b) -(10∠30^o)/5(c) (5∠30^o)/5(d) (-5∠30^o)/5The question was asked during an internship interview.The above asked question is from Nodal Analysis in portion Steady State AC Analysis of Network Theory
Answer» Right CHOICE is (b) -(10∠30^o)/5 The explanation is: We GOT Ybb=1/5+1/j5-1/j6 and Yab=–(-1/j6). The mutual ADMITTANCE between node b and a is the SUM of the admittances between nodes b and a. I2=-(10∠30^o)/5=y.

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