1.

Determine the load current across j5Ω in the circuit shown below.(a) 3.66∠90⁰(b) 3.66∠-90⁰(c) 4.66∠90⁰(d) 4.66∠-90⁰I got this question by my school principal while I was bunking the class.This interesting question is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Answer»

Right option is (b) 3.66∠-90⁰

The EXPLANATION: The LOAD current is the ratio of thevenin’s EQUIVALENT voltage and thevenin’s equivalent IMPEDANCE. The load current IL = (42.86∠0^o)/(j6.71+j5) = 3.66∠-90^o A.



Discussion

No Comment Found

Related InterviewSolutions