The expression of equivalent impedance (ZN) in the circuit shown below is?(a) (Z1+Z2)/Z1(b) (Z1+Z2)/Z2(c) Z1Z2/(Z1+Z2)(d) Z1+Z2This question was posed to me in semester exam.My query is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

The expression of equivalent impedance (ZN) in the circuit shown below

1.	The expression of equivalent impedance (ZN) in the circuit shown below is?(a) (Z1+Z2)/Z1(b) (Z1+Z2)/Z2(c) Z1Z2/(Z1+Z2)(d) Z1+Z2This question was posed to me in semester exam.My query is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory
Answer» Correct option is (c) Z1Z2/(Z1+Z2) The best EXPLANATION: The impedance between the points a and B with the source replaced by a SHORT circuit is NORTON’s equivalent impedance. The Norton’s equivalent impedance is ZN = Z1Z2/(Z1+Z2).

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The expression of equivalent impedance (ZN) in the circuit shown below is?(a) (Z1+Z2)/Z1(b) (Z1+Z2)/Z2(c) Z1Z2/(Z1+Z2)(d) Z1+Z2This question was posed to me in semester exam.My query is from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

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