Find the Norton’s current passing through ‘ab’ in the circuit shown below.(a) 4.16∠126.8⁰(b) 5.16∠126.8⁰(c) 5.16∠-126.8⁰(d) 4.16∠-126.8⁰I had been asked this question by my school teacher while I was bunking the class.I want to ask this question from Norton’s Theorem in portion Steady State AC Analysis of Network Theory

Find the Norton’s current passing through ‘ab’ in the circuit sh

1.	Find the Norton’s current passing through ‘ab’ in the circuit shown below.(a) 4.16∠126.8⁰(b) 5.16∠126.8⁰(c) 5.16∠-126.8⁰(d) 4.16∠-126.8⁰I had been asked this question by my school teacher while I was bunking the class.I want to ask this question from Norton’s Theorem in portion Steady State AC Analysis of Network Theory
Answer» Right answer is (d) 4.16∠-126.8⁰ Easy explanation: The NORTON’s current is EQUAL to the current passing through the SHORT circuit between the POINTS a and b. The Norton’s current is I=(10∠0^o)/(3∠90^o)+(5∠90^o)/(2∠-90^o) =4.16∠-126.8^oA.

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