1.

In the network shown below, find the voltage at node ‘a’.(a) 5.22∠104.5⁰(b) 5.22∠-104.5⁰(c) 6.22∠104.5⁰(d) 6.22∠-104.5⁰This question was posed to me by my college director while I was bunking the class.Question is taken from Nodal Analysis in chapter Steady State AC Analysis of Network Theory

Answer»

Right choice is (B) 5.22∠-104.5⁰

To EXPLAIN: Applying NODAL analysis at NODE ‘a’, (Va-10∠0^o)/j6+Va/(-j6)+(Va-Vb)/3=0. Applying nodal analysis at node ‘b’, (Vb-Va)/3+Vb/j4+Vb/j1=0. Solving the above equations we GET,Va = 5.22∠-104.5⁰V.



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