1.

Determine the voltage at node ‘b’ in the circuit shown below.(a) -1.34∠-180⁰(b) 1.34∠-180⁰(c) -0.34∠-180⁰(d) 0.34∠-180⁰The question was asked in an interview for internship.My query is from Nodal Analysis topic in chapter Steady State AC Analysis of Network Theory

Answer»

Right CHOICE is (a) -1.34∠-180⁰

The explanation: Applying nodal analysis at node ‘a’, (Va-10∠0^o)/J6+Va/(-j6)+(Va-VB)/3=0. Applying nodal analysis at node ‘b’, (Vb-Va)/3+Vb/j4+Vb/j1=0. Solving the above EQUATIONS we get, Vb = -1.34∠-180⁰V.



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