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Find the voltage across (2+j5) Ω impedance considering 50∠0⁰ voltage source.(a) 30.16∠-9.28⁰(b) 30.16∠9.28⁰(c) 29.16∠-9.28⁰(d) 29.16∠9.28⁰I got this question in examination.My question is based upon Superposition Theorem topic in chapter Steady State AC Analysis of Network Theory |
Answer» RIGHT answer is (C) 29.16∠-9.28⁰ Easiest explanation: VOLTAGE ACROSS (2+j5) Ω impedance considering 50∠0⁰ voltage source is V1 = 5.42∠-77.47^o (2+j5) = 29.16∠-9.28^o V. |
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