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Determine Norton’s equivalent current in the circuit shown below.(a) 5∠53.13⁰(b) 4∠53.13⁰(c) 4∠53.13⁰(d) 5∠-53.13⁰The question was posed to me in an online interview.Question is taken from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

Answer»

The CORRECT choice is (d) 5∠-53.13⁰

The EXPLANATION: The current through the terminals a and B is the NORTON’s EQUIVALENT current. The Norton’s equivalent current is I = (25∠0^o)/(3+j4) = 5∠-53.13⁰A.



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